matlab code of chapter 4

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Matlab code %matlab code of composite structure %chapter four code %michromechanics composite material %calculation of material properties %inputs: Em,Ef,Vm,Vf,Gm,Gf,alpha m, alpha f, neu f, neu m _______________________________________________ Ef=230; Em=4.6; Vf=0.4; Vm=0.6; Gm=1.769; Gf=92; alpham=30*10^-6; alphaf=15*10^-6; neuf=0.25; neum=0.3; E1=(Ef*Vf)+(Em*Vm) E2=(Em*Ef)/((Vf*Em)+(Vm*Ef)) alpha1=((Ef*Vf*alphaf)+(Em*Vm*alpham))/E1 alpha2=(alphaf*Vf)+(alpham*Vm) G12=(Gm*Gf)/((Gf*Vm)+(Gm*Vf)) neu12=(neuf*Vf)+(neum*Vm)

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Page 1: Matlab code of chapter 4

Matlab code

%matlab code of composite structure

%chapter four code

%michromechanics composite material

%calculation of material properties

%inputs: Em,Ef,Vm,Vf,Gm,Gf,alpha m, alpha f, neu

f, neu m

_______________________________________________

Ef=230;

Em=4.6;

Vf=0.4;

Vm=0.6;

Gm=1.769;

Gf=92;

alpham=30*10^-6;

alphaf=15*10^-6;

neuf=0.25;

neum=0.3;

E1=(Ef*Vf)+(Em*Vm)

E2=(Em*Ef)/((Vf*Em)+(Vm*Ef))

alpha1=((Ef*Vf*alphaf)+(Em*Vm*alpham))/E1

alpha2=(alphaf*Vf)+(alpham*Vm)

G12=(Gm*Gf)/((Gf*Vm)+(Gm*Vf))

neu12=(neuf*Vf)+(neum*Vm)

Page 2: Matlab code of chapter 4

Example 4.5

We will use the data of this example

Ef=230 Gpa

Em= 4.6 Gpa

Gm= 1.769 GPA

Gf= 92 Gpa

alpham=30*10^-6

alphaf=15*10^-6

results:

G12 2.911 Gpa

E1 94.76

E2 7.565

υ 12 0.28 Alpha 1 1.5437e-05

Alpha 2 2.4000e-05

MAtlab code results :

E1 94.7600

E2 7.5658

G12 2.9110

υ 12 0.2800

Alpha 1 1.5437e-05

Alpha 2 2.4000e-05

So the code is work correctly

Page 3: Matlab code of chapter 4