maths and further maths a level transition pack
TRANSCRIPT
βLearning, in my opinion, is a great treasuryβ Saint Teresa of Avila, 1587
MATHS and
FURTHER MATHS
A Level
Transition Pack
Transition booklet
All of the topics in this booklet are on the Higher GCSE syllabus and are crucial to success in A-level Maths. It is
therefore essential that you revise, practise and develop your skills in these areas. You can use the links to the
website DrFrostMaths.com to help you β you will receive an email inviting you to register and set up a
password (if you havenβt already done so).
You should complete the booklet assessing your work as you go using the answers at the back of the booklet.
We expect to see full working out for each question β naturally any questions where the answer has just
been copied down will not be seen as completed.
The questions with * will be marked during your first lesson and will indicate to you which areas of Maths you
need to ask for help with before the baseline assessment, which will take place in the week commencing
27th September2021. Please complete these on a separate piece of paper with your name clearly written so
that you can hand this work to your teacher on the first lesson.
Extra help is available at www.pearsonactivelearn.com where you can log on using
Username: [email protected]
Password: sbsjAlevel20
This will give you access to the two textbooks that form the basis of the Y12 course and you are encouraged to
familiarise yourself with them.
Next to each exercise below (where applicable) there is a link to a video tutorial on DR Frost.
1. Simplify as far as possible a. 3π₯ β 2π¦ + 4π¦
b. 7 β 3π₯ + 2 + 4π₯ *
c. 5π₯ + 2π¦ β 4π¦ β π₯2
2. Factorise as fully as possible a. π₯2 + 5π₯
b. 2π¦2 + 6π¦
c. πππ β ππ3 *
d. ππ₯ + ππ¦ + ππ₯ + ππ¦
3. Multiply out the brackets and simplify a. 3π₯ + 2(π₯ + 1)
b. 5π₯ β 2π₯(π₯ β 1)
c. 3π₯(π₯ β 1) β 7π₯2 *
d. (π₯ β 3) (π₯ β 5)
e. (2π₯ + π¦) (π₯ β 3π¦)
4. Simplify the following
a. 6π¦
3π¦ b.
4ππ2π3
3π3π2π *
5. Simplify the following
a. 3π₯
2 Γ
2π
3π₯ * b.
5ππ2
2Γ
3
2π2π
6. Simplify the following
a. 2
π Γ·
π
2 b.
3(π₯β1)
π₯Γ·
6
π₯π¦ *
7. Write as a single fraction
a. π₯
2+
π₯ + 1
3 * b.
3(π₯β1)
π₯ β
6
π₯π¦
Expanding & Removing Brackets
https://youtu.be/QwAwH5qiA1Y
Simplifying Algebraic Fractions
https://youtu.be/PMXJGwzW1AM
Adding and subtracting Algebraic Fractions
https://youtu.be/PQWQQRRpUlQ
Section 1 β Algebraic Expressions
Solve the following equations, give your answers as fractions in mixed number form where necessary.
1. 2π₯ β 5 = 11
2. 12 = 2π₯ β 8
3. 3π₯
2= 5
4. 4 =π₯
2+ 5
5. π₯ + 3( π₯ + 1) = 2π₯
6. 1
3(π₯ + 2) =
1
5(3π₯ = 2)
7. 2π₯β1
3=
π₯
2 *
8. π₯+1
2+
π₯β1
3=
1
6
9.
Make x the subject of each of the following formulae
1. 2π₯ = π
2. 9π₯ = π + π
3. V2π₯ + π = π
4. 3(π₯ β 1) = π
5. π΅βπ΄π₯
π·= πΈ
6. π
π₯βπΆ= π *
7. π2
π₯β π = βπ
8. π = βπ β π₯
9. π‘ = β(π₯2 β π) β π *
10. π§π₯ = π(π₯ + π‘)
11. π₯(π β π) = ππ₯ + π
12. β(π₯2 + π2 ) = π2
Rearranging Formulae https://youtu.be/y-cGpOFCB3Q
Linear Equations in one variable https://youtu.be/l-za234E9F4 https://youtu.be/IHgy9iAk-wU
Section 2 β Linear Equations
Section 3 - Formulae
Solve the following pairs of simultaneous equations:
1. 2π₯ + 5π¦ = 24
4π₯ + 3π¦ = 20
2. 3π₯ β π¦ = 9 4π₯ β π¦ = β14 *
3. 5π₯ β 7π¦ = 27 3π₯ β 4π¦ = 16
Factorise each of the following quadratics
1. π₯2 + 7π₯ + 10
2. π₯2 + 8π₯ + 15
3. π₯2 β 8π₯ + 16
4. π₯2 β π₯ β 12
5. π₯2 β 5π₯ β 24 *
6. π₯2 β 49
7. π₯2 + 5π₯
Factorise each of the following quadratics
1. 2π₯2 + 5π₯ + 3
2. 3π₯2 + 7π₯ + 2
3. 3π₯2 β 11π₯ + 6
4. 3π₯2 β 5π₯ β 2
5. 2π₯2 + π₯ β 21
6. 12π₯2 + 4π₯ β 5
7. 6π₯2 β 27π₯ + 30 *
8. 4π₯2 β 25
Write each of the following in the form (π₯ + π)2 + π where π and π are constants to be determined:
1. π₯2 + 4π₯ + 7 *
2. π₯2 β 26π₯ β 1
3. π₯2 + 5π₯ β 5
4. π₯2 β π₯ + 1
Write each of the following in the form a(π₯ + π)2 + π where π, π and π are constants to be determined:
5. 2π₯2 β 4π₯ + 5 *
6. 3π₯2 β 12π₯ + 10 7. 5π₯2 + 25π₯ β 5
https://youtu.be /5p79yczPWQc
https://youtu.be/cbbEFYpeWV8
https://youtu.be/XWNropJ5pn0
https://youtu.be/sQooemMboCw
Section 4 β Simultaneous Equations (both linear)
Section 5 β Factorising Quadratics, x2 (multiplied by 1)
Section 6 β Factorising Quadratics, x2 (not multiplied by 1)
Section 7 β Completing the Square
Solve each of the following
1. π₯2 + 7π₯ + 12 = 0
2. π₯2 β 8π₯ + 12 = 0
3. π₯2 + 2π₯ β 15 = 0 *
4. 6π₯2 β 13π₯ + 6 = 0
5. 10π₯2 β π₯ β 3 = 0
6. 6π₯2 + 17π₯ β 3 = 0 7. 9π₯2 + 6π₯ = 0
8. 4π₯2 β 1 = 0
Solve the following quadratics, giving your solutions correct to 3 significant figures:
1. π₯2 + 7π₯ + 5 = 0
2. 10π₯2 + 3π₯ β 2 = 0
3. 5π₯2 β 9π₯ + 2 = 0 *
4. 6π₯2 β 5π₯ = 8
Solve each of the following equations
1. π₯ + 5 =14
π₯
2. 3
π₯β1+
3
π₯+1= 4 *
3. 2
π₯β1β
1
π₯+2=
β4
π₯+3
Quadratic Equations https://youtu.be/Idk4R_baULA
Hint: Form and solve a quadratic Equation
Use the formula:
π = βπ Β± βππ β πππ
ππ
https://youtu.be/q0vb8ybymKI
Section 8 β Solving Quadratic Equations β By Factorising
Section 9 β Solving Quadratic Equations - Formula
Section 10 β Equations with Quadratic Solutions
Solve the following pairs of simultaneous equations:π¦ = π₯2 β 4π₯ + 6 π¦ = 2π₯2 β 3π₯ + 4
1. π¦ = π₯ β 3 5. π¦ + 2π₯ = 3 π¦2 + π₯π¦ + 4π₯ = 7 * π¦2 + π₯π¦ = 13 β 16π₯
2. π₯ + π¦ = 5 6. 3π¦ β 2π₯ = 11 3π₯π¦ = 18 π₯π¦ = 2
)
In each diagram, find the value of:
1. * 2.
48π 23ππ
7ππ π₯ π₯
17ππ
Finding sides https://youtu.be/r6xuUjwyKek
Finding angles https://youtu.be/5brkGmejvqU
Example/ Advice.
- If both equations have the same letter as their subject (i.e. Q1) then put them equal to each
other, and then solve.
- Otherwise, substitute the linear equation into the non-linear equation, and then solve.
https://youtu.be/2_n1KKPzmm8
Section 11 β Simultaneous Equations (when one is non-linear)
Section 12 β Trigonometry (calculator allowed)
1. Simplify:
a) 2π2 Γ 4π5 b) π2 Γ π3 Γ π5 c) 12π7 Γ· 2π2 d) (π¦3)4 e) f) π€4π¦3 Γ· π€π¦2
2. Simplify
a) π8 Γ πβ6 b) (π€πβ4)3 * c) 2π2
3 Γ 4π1
4 d) π¦
12Γπ¦
13
π¦ e)
4π₯23 Γ 3π₯
β16
6π₯34
*
1. Simplify
a) β50 b) β98 c) β27 d) β363
e) β18 + β50 f) 2β8 + β72 * g) β3(2 + β3) h) (3β3 + 1)(2 - 5β3)
2. Express as simply as possible with a rational denominator
a) 1
β8 b)
β5
β15 c)
4β20
3β18 * d)
6ββ8
β2 e)
2
β3β
β6
β12 *
Laws of indices https://youtu.be/Z_WCKeO-liY
Fractional powers https://youtu.be/E-gq8eq105I
Negative powers https://youtu.be/RBPbRrHSCVs
Negative powers
Simplify https://youtu.be/LDH_VS1fwYE
Add/subtract https://youtu.be/O0Hm8oAgrPI
Multiply/divide https://youtu.be/XiuLvyXyRxY
Rationalise https://youtu.be/wiBovf97ihc
Section 13 - Indices
Section 14 - Surds
1. At a coffee shop Americanos cost Β£1.90. Cappuccinos cost Β£2.40. Maddie bought two Americanos
and some cappuccinos. She paid with a Β£20 note and received Β£9.00 change. How many
cappuccinos did she buy? *
2. Jamila has taken five out of six tests. The maximum mark in each test is 20. So far her average (mean) mark
is 12. Is it possible for her to increase her average mark to above 15 after she has taken the final test? *
3. Two work colleagues arrive on the ground floor of a building at 8.01 am for a meeting on the twentieth floor.
The twentieth floor is 60 m above ground level. One decides to take the stairs, the other the lift.
They both arrive on the twentieth floor at 8.07 am. In the meeting room they sketch graphs showing their height
above the ground in terms of time between 8.01 am and 8.07 am.
Which graph do you think shows the person who took the lift? Why ?
What assumptions might have been made in drawing these graphs? *
Problem Solving *
4. Calculate the shaded area in the diagram below: *
5. The diagram shows a square and a circle. The corners of the square are on the circle.
The perimeter of the square is 20 cm.
Find the exact value of the area of the circle. *
6. Find the value of x in the diagram below. *
Any students hoping to study Further Maths alongside Maths should also complete the following
questions, showing all steps of your method clearly.
1. Simplify these expressions as far as possible.
a. π₯2 βπ₯β6
π₯2+π₯β12 b.
π₯2β49
π₯2 βπ₯β30Γ·
π₯2+5π₯β14
π₯2β36
2. a. Show that the line x + y = 6 is a tangent to the circle x2 + y2 = 18.
a. Show the line and the circle on a diagram.
b. The tangent meets the x axis at P and the y axis at Q. Find the area of the triangle OPQ.
3. Expand and simplify (βa - 3βc)(5βa - βc)
4. a Write 4x2 + 24x + 11 in the form a(x + b)2 + c
b. Hence, or otherwise, write down the coordinates of the turning point of the graph of
y = 4x2 + 24x + 11.
5. Prove algebraically that the sum of the squares of three consecutive numbers less 2 is
always 3 times a square number.
6. The functions f and g are defined as g(x) = 3x and f(x) = 4x + 1 .
2-x
Given that x β 2, find the value(s) of x such that g(x) = f(x), giving your answer(s) to 2 decimal
places.
Further Maths
7.
8. A triangle has side lengths AB = 18 cm, BC = 15 cm and AC = 8 cm.
a. Find the size of the largest angle, giving your answer to 2 decimal places.
b. Find the area of the triangle, giving your answer to 2 decimal places.
9. a. Sketch the graph of y = sin x for - 180o β€ x β€ 360o , showing the points where the graph cuts the axes.
b. Hence find the exact values of x in the interval - 180o β€ x β€ 360o for which
sin π₯ = β1
2
10. Problem Solving challenge
Can you find the solution ?
Section 1
1a) 3π₯ + 2π¦ c) βπ₯2 + 5π₯ β 2π¦
2a) π₯(π₯ + 5) b) 2π¦(π¦ + 3) d) π(π₯ + π¦) + π(π₯ + π¦) = (π + π)(π₯ + π¦)
3a) 5π₯ + 2 b) 7π₯ β 2π₯2 d) π₯2 β 8π₯ + 15 e) 2π₯2 + 3π¦2 β 5π₯π¦
4a) 2
5a) b) 15π
4π
6a) 4
π2
7a) b) 3π₯π¦ β 3π¦ β 6
π₯π¦ or
3(π₯π¦ β π¦ β 2)
π₯π¦
Section 2
1. π₯ = 8 2. π₯ = 10 3. π₯ =10
3= 3
1
3 4. π₯ = β2
5. π₯ = β3
2= β1
1
2 6. π₯ = 4 8. π₯ = 0
Section 3
1. π₯ = π
2 2. π₯ =
π + π
9 3. π₯ =
πβπ
π2 4. π₯ =
π
3+ 1 or
π+3
3
5. π₯ =π΅βπΈπ·
π΄ or
πΈπ·βπ΅
βπ΄ 7. π₯ =
π2
πβπ 8. π₯ = π β π2
10. π₯ = ππ‘
π§βπ 11.
π
πβπβπ 12. π₯ = βπ4 β π2
Section 4
1. π₯ = 2 , π¦ = 4 3. π₯ = 4 , π¦ = β1
Section 5
1. (π₯ + 2)(π₯ + 5) 2. (π₯ + 3)(π₯ + 8) 3. (π₯ β 4)2 4. (π₯ β 4)(π₯ + 3)
6. (π₯ β 7)(π₯ + 7) 7. π₯(π₯ + 5)
Section 6
1. (2π₯ + 3)(π₯ + 1) 2. (3π₯ + 1)(π₯ + 2) 3. (3π₯ β 2)(π₯ β 3) 4. 3(2π₯ β 5)(π₯ β 2)
5. (3π₯ + 1)(π₯ β 2) 6. (2π₯ + 7)(π₯ β 3) 8. (2π₯ β 5)(2π₯ + 5)
Answers
Section 7
2. (π₯ β 13)2 β 170 3. (π₯ + 21
2)2 β 11
1
4 4. (π₯ β
1
2)2 +
3
4
6. 3(π₯ β 2)2 β 2 7. 5(π₯ + 21
2)
2β 36
1
4
Section 8
1. π₯ = β 4 ππ β 3 2. π₯ = 2 ππ 6 4. π₯ = 2
3 ππ
3
2
5. π₯ = 3
5 ππ β
1
2 6. π₯ =
1
6 ππ β 3 7. π₯ = 0 ππ β
2
3 8. π₯ =
1
2 ππ β
1
2
Section 9
1. π₯ = β 6.19 ππ β 0.807 2. π₯ = β 0.622 ππ 0.322 4. π₯ = β 0.811 ππ 1.64
Section 10
1. π₯ = β 7 ππ 2 3. π₯ = β7
5 ππ β 1
Section 11 β (with workings out for the questions 1-3)
1. π₯2 β 4π₯ + 6 = 3π₯ β 4 2. π₯ = π¦ + 3 β π¦2 + π¦(π¦ + 3) + 4(π¦ + 3) = 7
π₯2 β 7π₯ + 10 = 0 π¦2 + π¦2 + 3π¦ + 4π¦ + 12 = 7 (π₯ β 2)(π₯ β 5) = 0 2π¦2 + 7π¦ + 5 = 0 π₯ = 2 ππ 5 (2π¦ + 5)(π¦ + 1) = 0
β΄ π¦ = 2 ππ 11 π¦ = β5
2 ππ β 1
β΄ π₯ = 1
2 ππ 2
β π₯ = 2, π¦ = 2 ππ π₯ = 5, π¦ = 11 β π₯ =1
2, π¦ = β
5
2 ππ π₯ = 2, π¦ = β1
3. π₯ = 5 β π¦ β 3(5 β π¦)π¦ = 18
15π¦ β 3π¦2 = 18 3π¦2 β 15π¦ + 18 = 0 π¦2 β 5π¦ + 6 = 0 (π¦ β 3)(π¦ β 2) = 0 π¦ = 3 ππ 2
β΄ π₯ = 2 ππ 3
β π₯ = 2, π¦ = 3 ππ π₯ = 3, π¦ = 2
4. π₯ =1
2, π¦ = 3 ππ π₯ = 3, π¦ = 13 5. π₯ =
1
2, π¦ = 2 ππ π₯ = β4, π¦ = 11
6. π₯ =1
2, π¦ = 4 ππ π₯ = β6, π¦ = β
1
3
Section 12
2. π₯ = 73.07248694 = 73. 10 (3 π . π. )
Section 13
1a 8π7 1b) π10 1c) 6π5 1d) π¦12 1e) π€3π¦
2a) π2 2b) π€3πβ12 2c) 8π11
12 2d) π¦β1
6 2e) 2π₯β1
4
Section 14
1a) 5β2 1 b) 7β2 1 c) 3β3 1 d) 3β11
1 e) 8β2 1 f) 10β2 1g) 2β3 + 3 1 h) -43+β3