math14 lesson 6 circle

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    CIRCLE

    (Lesson 6)

    Math 14Plane and Analytic Geometry

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    OBJECTIVES:

    At the end of the lesson, the student is expected to be

    able to: Determine the center and radius of the circle given

    an equation.

    Determine the general and standard form of

    equation of the circle given some geometric

    conditions.

    Convert general equation of a circle to the standard

    form and vice-versa Determine the equation of a circle defining family of

    circles

    Determine the radical axis

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    CIRCLEA circle is a locus of points that moves in a plane at

    a constant distance from a fixed point. The fixed point

    is called the center and the distance from the center

    to any point on the circle is called the radius.

    Parts of a Circle:

    Center - It is in the center of the circle and thedistance from this point to any other point on the

    circumference is the same.

    Radius - The distance from the centre to any point

    on the circle is called the radius. A diameter is twice

    the distance of a radius.

    Circumference - The distance around a circle is its

    circumference. It is also the perimeter of the circle

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    Chord- A chord is a straight line joining two points

    on the circumference. The longest chord in a circle

    is called a diameter. The diameter passed throughthe center.

    Segment - A segment of a circle is the region

    enclosed by a chord and an arc of the circle.

    Secant - A secant is a straight line cutting at two

    distinct points.

    Tangent - If a straight line and a circle have only

    one point of contact, then that line is called atangent. A tangent is always perpendicular to the

    radius drawn to the point of contact.

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    EQUATION OF THE CIRCLE

    P(x,y)

    C(h,k)

    y

    x

    x

    y

    k

    h

    r

    o

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    Let:

    C (h, k) - coordinates of the center of the circle

    r - radius of the circle

    P (x, y) - coordinates of any point along the circle

    From the figure: Distance CP = radius ( r )

    Recall the distance formula:

    Squaring both sides of the equation:

    r2 = (x h)2 + (y k)2

    The equation is also called the center-radius form or the

    Standard Form. (x h)2 + (y k)2 = r2

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    If the center of the circle is at the origin (0, 0):h = 0 k = 0

    C (h, k) C (0, 0)

    From: (x h)2 + (y k)2 = r2

    (x 0)2 + (y 0)2 = r2

    x2

    + y2

    = r2

    (Center at the origin)

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    From: (x h)2 + (y k)2 = r2 Standard Form

    Center at (h, k): (x2 2hx + h2) + (y2 2ky + k2) = r2

    x2 + y2 2hx 2ky + h2 + k2 - r2= 0

    Let: -2h = D

    -2k = E CONSTANTS

    h2 + k2 - r2 = F

    Therefore,

    x2 + y2 + Dx + Ey + F = 0 General Form

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    Examples:

    1. If the center of the circle is at C(3, 2) and theradius is 4 units, find the equation of the circle

    2. Find the equation of the circle with center (-1, 7)

    and tangent to the line 3x 4y + 6 = 0.

    3. Find the equation of the circle having (8, 1) and

    (4,-3) as ends of a diameter.

    4. Reduce to standard form and draw the circle

    whose equation is 4x2

    + 4y2

    4x 8y 31 = 0.5. Find the equation of the circle passing through the

    intersection of 2x-3y+6=0 and x+3y-6=0 with

    center at (3,-1).

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    Case II: Three noncollinear points determine a circle as

    shown in Figure 2. The three points are the three

    conditions in this case, knowing them gives threeconditions in D, E, and F in the general form of a circle.

    Note that one point (two coordinates) on a circle is a

    single condition, while each coordinate of the center

    is a condition. More generally, knowing that the centeris on the given line can be counted on as a condition

    to determine a circle; knowing h and k is equivalent to

    knowing that the center is on the lines x = h and y = k.

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    Case III: The equation of a tangent line, the point of

    tangency, and another point on the circle as shown

    in the Figure 3. The center is on the perpendicularto the tangent at the point of tangency. It is also on

    the perpendicular bisector of the segment joining

    any two points of the circle. These two lines

    determine the center of the circle; the radius is noweasily found.

    Case IV: Tangent line and a pair of points on a circledetermine two circles as shown in the Figure 4.

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    Figure 1 Figure 2

    Figure 3 Figure 4

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    Example:

    1. Find the equation of the circle if the circle is

    tangent to the line 4x 3y + 12=0 at (-3, 0) and

    also tangent to the line 3x + 4y 16 = 0 at (4, 1).

    2. Find the equation of the circle which passes

    through the points (1, -2), (5, 4) and (10, 5).

    3. Find the equation of the circle which passesthrough the points (2, 3) and (-1, 1) and has its

    center on the line x 3y 11 = 0.

    4. Find the equation(s) of the circle(s) tangent to

    3x-4y-4=0 at (0,-1) and containing the point (-1,-

    8)

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    Exercises:

    1. Find the equation of the circle passing through (7,

    5) and (3, 7) and with center on x-3y+3=0.2. Find the points of intersection of the circles

    x2 + y2 4x 4y + 4 = 0 and x2 + y2 + 2x 4y - 8 = 0.

    Draw the circles.

    3 Find the equation of the circle if it is tangent to the

    line x + y = 2 at point (4 -2) and the center is at the

    x-axis.

    4 A triangle has its sides on the lines x + 2y 5 = 0,2x y 10 = 0 and 2x + y + 2 = 0. Find the equation

    of the circle inscribed in the triangle.

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    5 Determine the equation of the circle circumscribing

    the triangle determined by the lines x + y = 8,

    2x + y = 14 and 3x + y = 22.6 A triangle has its sides on the lines x + 2y 5 = 0,

    2x y 10 = 0 and 2x + y + 2 = 0. Find the equation

    of the circle inscribed in the triangle.

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    FAMILIES OF CIRCLES

    Let x2+y2+D1x+E1y+F1=0 and x2+y2+D2x+E2y+F2=0 be the

    equation of two circles and taking k as the parameter,

    then the equation of the families of circles passing

    through the intersection of two circles is

    (x2+y2+D1x+E1y+F1) + k(x2+y2+D2x+E2y+F2) =0. Except for

    k=-1, it would become a linear equation (D1-D2)x + (E1-

    E2)y + (F

    1-F

    2) = 0, which is called a radical axisof the

    two given circles.

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    Example:

    1. Write the equation of the family of circles C3 all

    members of which pass through the intersection

    of the circles C1 and C2 represented by the

    equations C1: x2+y2-6x+2y+5=0 and C2: x

    2+y2-12x-

    2y+29=0. find the member of the family C3 that

    passes through the point (7, 0).2. Graph the circles C1 and C2 whose equations are

    C1: x2+y2-12x-9y+50=0 and C2: x

    2+y2-25=0. also

    graph the member C3 of the family of circles for

    which k=1.

    3. Draw the graph of the equations x2+y2-4x-6y-3=0

    and x2+y2-12x-14y+65=0. Then find the equation

    of the radical axis and draw the axis.

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    REFERENCES

    Analytic Geometry, 6th Edition, by Douglas F. Riddle

    Analytic Geometry, 7th Edition, by Gordon Fuller/Dalton Tarwater

    Analytic Geometry, by Quirino and Mijares