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88MAMATHTHWWOORRKKBBOOOOKK
LCM = 60
112 43
3.141622%
.625
A=hb
30x + 22y
6.25mm=
X118 3
>32x - 14y
34.66
GCF = 812 = 2 x 2 x 3
I = P x R x T
831-256
=<6.25mm <
=LCM = 60A=hb 32x - 1
4y
.625
30x + 22y
>
34.66
22%
GCF = 812 = 2 x 2 x 33.1416
I = P x R x T
831-256 112 43
=18 X
13
EMP4055i
MathWORKBOOK
AuthorBeverly Nance
Project ManagerE. Rohne Rudder
TypesettingPagecrafters, Inc.
Cover ArtE. Rohne Rudder
Managing EditorKathleen Hilmes
Copyright © 1993Milliken Publishing Company
All rights reserved.
8Finally, a new workbook for eighth grade math!
Basic skills are reviewed and expanded as students work through 58pages of activities. Each page gives an example and step–by–stepsolution of the problem presented. Some of the many skills coveredinclude a review of addition, subtraction, multiplication, and division,plus challenges in decimal fractions, exponential and scientificnotation, primes, probability, percents, and basic geometric principles.Six answer pages are provided.
The purchase of this book entitles the individual purchaser to reproducecopies by duplicating master or by any photocopy process for single class-room use. The reproduction of any part of this book for commercial resale orfor use by an entire school or school system is strictly prohibited. Storage ofany part of this book in any type of electronic retrieval system is prohibitedunless purchaser receives written authorization from the publisher.
Find each sum.
46 + 54 + 62 + 38 =
85 + 15 + 37 + 13 =
127 + 43 + 130 + 30 =
17 + 23 + 35 + 25 =
250 + 350 + 25 + 175 =
© Milliken Publishing Company 1 MP4055
Addition and subtraction of whole numbers
194055281
324+ 1820043, 210
827 724 8245 4537 6331365 599 3605 2009 5224
+ 942 + 307 + 2913 + 5432 + 8445
1234 246 13579 20406 15795678 802 79135 1030 2631
+ 9012 + 468 + 35793 + 99999 + 4682
21300– 895512,345
Find each difference.
4829 2056 8000 7248 5040– 3718 –1264 – 4654 – 3585 – 3999
6213 4000 8219 2467 3579– 5876 – 805 – 7878 – 908 – 2468
12345 9876 50604 7000 48113– 6789 – 6789 – 3080 – 4778 – 36251
Find each quotient.
Find each product.
© Milliken Publishing Company 2 MP4055
17 561) 29 899) 35 875) 48 960)
246 135× 82 × 791
1350 2863 1792 8921× 405 × 823 × 544 × 345
5628 5701 9287 8040× 500 × 803 × 123 × 506
358 17542) 256 82176) 987 42441)
Multiplication and division of wholenumbers
358× 493222
143217542
17 R 2432 568) 32
248
224
24
Simplify each expression.
2 + 8 ÷ 4 – 2 =
8 – 5 ÷ 5 + 5 =
Find each sum.
6 x 3 + 2 ÷ 2= 9 ÷ 3 + 6 – 1 = 17 + 2 x 5 ÷ 5 = 24 ÷ 8 + 3 – 2 =
© Milliken Publishing Company 3 MP4055
41 – 6 ÷ 6 + 5 = 36 ÷ 12 + 8 – 4 = 52 ÷ 4 x 2 + 1 = 12 x 3 – 4 + 5 =
2 + 3 (5 – 2) = 6 + 4 (8 + 2) = 5 (3 – 2) + 1 = 6 (8 ÷ 8) + 7 =
7 – 2 (5 – 5) = 18 + 3 (4 – 2) = 24 ÷ 2 (1 – 0) = 16 – 3 (8 ÷ 4) =
8 + 12 ÷ 2 – 4 x 3 + 1 =
8 + 6 –12 + 1 =
14 – 12 + 1 =
2 + 1 =
3
18 – 5 x 3 + 6 = 17 + 5 x 2 – 2 = 8 + 8 ÷ 8 – 8 = 25 – 6 ÷ 3 + 3 =
Order of operations (multiplicationand division)
Simplify each expression.
5 + 4 [3 + 4(8 – 6)] =
© Milliken Publishing Company 4 MP4055
21 + 4[8 x 3 – 16] = 58 – 5 [6 + 8 ÷ 4] = 6 [5 + 3 x 2] – 12 =
2 + 3 [5 + 8 (6 – 2)] = 78 – 2 [24 – 2(8 – 5)] =
28 + 7[16 – 2 (4 + 3)] = 146 – 5 [8 (6 – 4) – 12] =
16 – 2 [5 + 3 ÷ 3] = 18 + 7 [6 – 4 ÷ 4] = 37 – 3 [4 x 2 – 5] =
More order of operations (inside out)
2 + 3 [5 + 2 (8 – 5)] =
2 + 3 [5 + 2 (3)] =
2 + 3 [5 + 6] =
2 + 3 [11] =
2 + 33 = 35
Find the difference.
20.4 16.23 8.4 12.25 2.803– 8.6 – 4.5 – 2.39 – 6.47 – 1.04
42.56 6.984 8 8.35 2.45– 13.24 – 4.279 – 4.35 – 4 – 1.46
Find each sum.
2 + 4.8 + .2 + 3 =
3.4 + 2.6 + 5 + 2.4 =
6.5 + 8.2 + 2.3 + .5 =
9 + .4 + 8 + .3 + 2.3 =
2.85 + .05 + 2.1 + 4 =
© Milliken Publishing Company 5 MP4055
Addition and subtraction of decimals
23.5
.4+ 6.0211.92
8.40– 2.35
6.05
0.456 23.4 2.35 10.2 7.21.234 7.25 4 1.35 5.68
+ 2.345 + 18.07 + 5.6 + .4 + 4
Simplify each expression.
21.4 – (3.2 + 8.4) 18.4 + (6.35 – 2.42)
17.56 + (18.42 – 6) 29.35 – (4.38 + 2.9)
(8.2 + 3.5) – (4.6 + 2.5) + 2.1
Find each product.
3 x 1.5 =
5 x .25 =
2 x .37 =
10 x .04 =
8 x 1.11 =
© Milliken Publishing Company 6 MP4055
Multiplication and division of decimals
3.45x 1.2
690345
4.140
2.8 .45 1.23 .456 24.3x .7 x .6 x .9 x .2 x .3
2.9 .47 2.31 .123 12.04x .17 x 2.6 x .12 x .04 x .05
Find the quotient.
.4 16.8) 4 16.8) .04 16.8) .004 .168)
2.5 6.25) .25 6.25) 25 6.25) .025 6.25)
1.2 9.6) .15 7.5) .11 .099) 8 .048)
3.2 960) .21 8.4) 14 1.96) .35 70)
.123 2.46) 2.04 .612) 311 6.22) .481 .962)
12.06.4 4.824)
© Milliken Publishing Company 7 MP4055
Round to nearest whole number.
7.4 ≈ 8.6 ≈ 17.11 ≈ 21.51 ≈
1.45 ≈ .09 ≈ 2.145 ≈ .96 ≈
Round to nearest hundreth.
2.456 ≈ .045 ≈ 1.181 ≈ 2.009 ≈
Round to nearest thousandth.
.0456 ≈ .1234 ≈ .2345 ≈ .0604 ≈
Round to nearest tenth.
.24 ≈ .17 ≈ 2.43 ≈ .48 ≈
Write <, >, or = to make a true statement.
2.005 2.5
3.14 3.41
8 7.895
2.115 2.151
4.92 4.29
12.46 14.2 6.35 5.63 3.405 3.045
8.002 8.02 .88 .8 .119 .1109
3.801 3.108 .707 .7 .003 .02
16.16 17 18.05 15.88 2.3 .32
Comparing decimals
2.45 < 2.5
3 > 2.999
Rounding decimals
6.23 ≈ 6.2 6.28 ≈ 6.3
Write in exponential notation.
3 • 3 • 3 =
5 • 5 • 5 • 5=
1 • 1 • 1 • 1 • 1 =
2 • 2 • 2 =
(2.4) (2.4) (2.4) =
10 • 10 • 10 • 10 = 9 • 9 • 9 = 7 • 7 • 7 • 7 • 7 =
(3.2) ( 3.2) = 8 • 8 • 8 • 8 = 6 • 6 • 6 • 6 • 6 • 6 =
Evaluate each expression.
22 = 5
2= 7
2= 1
2= 9
2=
33= 4
3= 2
3= 8
3= 5
3=
44= 2
4= 1
4= 3
4= 5
4=
102= 10
4= 10
1= 10
0= 10
3=
35= 2
6= 1
10= 4
2= 5
5=
Write the missing exponent.
23
• 24= 2 ■■ 8
2• 8
5= 8 ■■ 7
4• 7
5= 7 ■■
53
• 5 ■■ = 54
4■■ • 43= 4
56
8• 6
3= 6 ■■
35
• 37= 3 ■■ 9
1• 9 ■■ = 9
810
3• 10
4= 10 ■■
(2.5) (2.5) (2.5) (2.5)(2.5) (2.5) = (2.5) ■■
© Milliken Publishing Company 8 MP4055
Using exponents
2 • 2 • 2 • 2 • 2 = 25
32= 3 • 3 = 9
42
• 43 = (4 • 4) (4 • 4 • 4) = 4
5
© Milliken Publishing Company 9 MP4055
Evaluate.
2.4 x 102=
3.71 x 103=
5.06 x 101=
8.371 x 103=
7.008 x 102=
9.23 x 103= 8.405 x 10
1=
6.204 x 104= 2.3 x 10
5=
1.49 x 106= 3.755 x 10
3=
5 x 106= 8.1 x 10
5=
7.42 x 104= 9 x 10
8=
Write in scientific notation.
405 = 8400 =
2468 = 700,000 =
8,040,000 = 42,000 =
1005 = 27 =
550,000 = 4,000,000 =
80,808 = 1450 =
9000 = 6002 =
50,000 = 12345 =
18 = 246 =
908 = 325,000 =
5.23 x 103= 5230
24,680 = 2.468 x 104
Scientific notation
Complete the Prime Factor Treesto find each GCF.
© Milliken Publishing Company 10 MP4055
GCF = 6
12 18
2 96 3
2 33 2
2• 2•3 2•3 •3
Use Prime Factor Trees to find GCF
81
3
54
3
GCF =
GCF =
120
2
48
3
120
2
48
3
GCF =
220
2
340
2
GCF =
GCF =
8
2
20
2
175
5
225
5
GCF =
72
2
90
2
GCF =
GCF =
170
2
130
2
The following word problemsrequire you to find a least commonmultiple (LCM). Use either method(A) or method (B).
1. What is the length of the side of the smallest possible square formed byplacing rectangles side by side that are 3 inches by 4 inches?
2. Jane and Mark are cycling to the shore but Jane rides at a rate of 15 mph, and Mark rides at a rate of 12 mph. What is the minimum distance they will ride if they each travel the same distance in a whole number of hours?
3. Rhonda earned $75 per week for 4 weeks. If Jane only earns $50 per week how many weeks will she have to work before she will have the same amount of money?
4. Paul can mow 12 lawns per week for 3 weeks. Robbie mows 6 lawns in 1 week. How many weeks will Robbie have to work before he’s mowed the same number of lawns as Paul?
5. What is the length of the side of the smallest possible square formed by placing rectangles side by side that are 5 cm by 6 cm?
6. Tara read 8 books/month for 3 months. How many books will John have to read for each of 4 months if they are to read the same number of books?
7. Harold earned $150/week for 8 weeks. Sarah earned $90/week for 10 weeks. What is the least common multiple of both their salaries?
8. Bob types 40 words per min. for 5 minutes. Julie types 50 words per min. How long before she will have typed the same number of words?
© Milliken Publishing Company 11 MP4055
Find the LCM of 15 and 20
Method (A): 15, 30, 45, 6020, 40, 60
15
3
20
2
LCM = 2 x 2 x 3 x 5 = 60
LCM = 60
Method (B):
5 2 5
1520
= 8090
= 2128
=
936
= 1751
= 3240
=
4860
= 3857
= 1230
=
112
= 2 13
= 3 14
= 4 15
= 5 16
=
135
= 2 47
= 3 59
= 4 34
= 5 23
=
1025
= 20 58
= 30 57
= 40 12
= 50 35
=
1934
= 7 23
= 6 12
= 8 19
= 1113
=
Reduce each fraction to lowest terms.
© Milliken Publishing Company 12 MP4055
I. Reduce:
II. Change mixed number to improper fraction:
III. Find missing number to form equivalent fraction:
Change each mixed number to an improper fraction.
12
=6
23
=10 3
=1520 9
=1618
57
=21
79
=28 3
=2432 5
=3050
910
=30
611
=18 19
=3848 4
=120160
Find the missing number to form equivalent fractions.
68 ÷
÷2
2 =
34
35
7=
21+ 5
7=
26
7
3
4=
32:3 × 8
4 × 8=
32
24
© Milliken Publishing Company 13 MP4055
724
,5
18,
812
58
,7
20,
624
78
,1230
,1115
135
, 127
, 134
1
2,
2
3,
1
8:
3
24<
12
24<
16
24
Write > or < to make a true statement.
23
35
49
78
29
311
56
45
311
29
57
68
712
811
613
45
417
316
720
516
23
1823
38
211
2730
710
85100
1621
3250
1520
2122
1314
Write in order from least to greatest.
< <
< <
< <
< <
1834
2056
3 54 6
<. ..<
© Milliken Publishing Company 14 MP4055
23
79
58
+56
+13
+ 45
125
57
184
56
+ 234
+ 35
12+11
29
35
5 73
10
+149
+ 623
+ 547
412
635
1238
3 23
5 1745
+ 514
+ 4 29
+ 2114
Add the following fractions and mixednumbers and reduce answer
28
+ 58
+ 18
=
3 211
+ 5 711
+ 6 =
3 521
+ 6 421
+ 1 321
=
Write each sum in simplest form.
33
4= 3
9
12
+5
6= +
10
12
319
12= 4
7
12
© Milliken Publishing Company 15 MP4055
Write each difference in simplestform.
Subtraction of fractional and mixed numbers
32
3 = 3
8
12 = 2
20
12
– 13
4 = 1
9
12 = 1
9
12
111
12
1112
–9
12=
1720
–5
20=
1278
– 538
=
1921
1112
910
– 37
– 23
– 45
3 56
71415
12 1924
–145
– 2 14
– 5 23
18 23
16 59
27 38
–4 78
– 8 78
– 14 910
84 28 331
42
– 635
–19 – 16 511
© Milliken Publishing Company 16 MP4055
Write each product in simplest form. Multiplication of fractions
25
× 103
× 64
=
59
× 23
× 910
=
712
× 45
× 214
=
2 × 314
= 512
× 89
=
312
× 4 = 16 × 134
=
212
× 312
= 513
× 418
=
21
3 × 3
3
4 =
7
3×
15
4=
35
4= × 8
3
4
Multiplication of mixed numbers
5
1
2
3×
4
5×
10
6=
1 × 4 × 2
3 × 1 × 3=
8
9
23
× 3 × 412
= 56
× 12 × 11
10=
315
× 10 × 25
= 46
× 24 × 14
12=
2
3
1
1
12
÷ 34
=
25
÷ 13
=
37
÷ 65
=
2 ÷ 34
= 56
÷ 2 =
212
÷ 3 = 512
÷ 14
=
335
÷ 217
= 423
÷ 123
=
6 ÷ 8 = 325
÷ 10 =
Division of fractions
Division of mixed numbers
© Milliken Publishing Company 17 MP4055
Write each quotient in simplest form.
34
÷
38
+
12
÷
14
=
56
÷
13
+
18
÷
14
=
2
÷ 34
+ 3( ÷ 9) = 2
12
÷
24
+ 3
14
÷
23
=
Find the quotients and add to find their sum.
21
2 ÷ 5 =
5
2×
1
5 =
1
2
2
3 ÷
4
5 =
2
3×
5
4 =
10
12 =
5
6
Evaluate each expression given
a = 2, b = 3, c = 4, d = 12.
Complete each table.
© Milliken Publishing Company 18 MP4055
d e f d ÷ f + 2 e
24 7 6
16 3 4
30 12 5
8 2 2
a b 3 a + b 4 b – a
1 2
5 2
2 4
9 10
c d c d – 2 2 c ÷ d
1 2
6 4
8 2
9 3
a b c 2 a + b c – a c
1 5 2
3 8 4
2 9 1
5 8 3
Evaluate the following expression givena = 2, b = 3, c = 4.
a b +
2 (3) +
– b + 5 a
– 3 + 5 (2)
6 + 2 – 3 + 10
c
a
4
2
15
a + c =
a b =
4a + 1 =
6a ÷ d =
b – a =
d ÷ b =
5b – 3 =
a b c =
x + 19 = 26 y – 24 = 30 a – 4 = 9 m + 17 = 26
d – 7 = 30 c – 4 = 12 b + 9 = 81 n + 72 = 78
t + 2 = 20 v – 13 = 6 w – 13 = 4 z + 5 = 20
e + 7 = 9 r – 12 = 6 p – 3 = 4 g + 6 = 6
© Milliken Publishing Company 19 MP4055
Solve the following equations.When finished, add all answers. The sum should total 310!
Solve the equation for the variable
x + 85 = 91
– 85 – 85
x = 6
y – 14 = 60
+ 14 + 14
y = 74
2 × = 42y5
= 6a5
= 4 7b = 21
R24
= 6 5t = 185 2m = 100n82
= 6
c7
= 18 9d = 180w3
= 5 4v = 28
8f = 16 12g = 36j4
= 5k5
= 2
© Milliken Publishing Company 20 MP4055
Solve the following equations. When finished, add all the answers. The sum should total 1000!
Solve the equation for the variable
3 ×3
=
213
y7
= 3
× = 7 7y7
= 7 3( )
y = 21
WORD PROBLEMS
1. Jake hit 3 more home runs than Rhajon. Jake hit a total of 11 homeruns. How many homers did Rhajon hit?
2. Sallie is 4 inches shorter than Marie. Sallie is 61 inches tall. How tall is Marie?
3. Josie ate 360 fewer calories than Mark. Josie ate a total of 1250 calories. How many did Mark eat?
4. Miguel drove 75 miles further than James. Miguel drove 350 miles. How far did James drive?
5. Rochelle types 23 words per minute faster than Wanda. If Rochelle types 88 words per minute, how fast does Wanda type?
6. Amy’s salary is $2450 less than Joan’s salary. If Amy’s salary is $15,500, how much is Joan’s salary?
7. Josè scored 13 points higher on the final exam than Frank. Frank earneda score of 77. What was Josè’s score?
8. Barbara ran the marathon in 3h. 27 min. which was 14 minutes slowerthan Julie. What was Julie’s time?
9. There are 36 cookies in a package of Mrs. Buttermaker Cookies. Thereare 14 more cookies in a package of Blue Ribbon Cookies. How many cookies are in the Blue Ribbon package?
10. Last fall Sal read 13 books which was 6 less than the number of bookshe read last summer. How many books did he read over the summer?
© Milliken Publishing Company 21 MP4055
© Milliken Publishing Company 22 MP4055
WORD PROBLEMS
1. Becky earns $14.25 per hour which is 3 times more than Joe’s hourlywage. How much does Joe make per hour?
2. Marty drove 1/3 of the distance between St. Louis and Kansas City. He drove 84 miles. How far is St. Louis from Kansas City?
3. Jennifer’s weight is 3/4 the weight of Sam. Jennifer weighs 120 lbs. How much does Sam weigh?
4. Fred scored twice the number of points in the basketball game as John. Fred scored 26 points. How many did John score?
5. Krista tripled her yearly salary. Her new salary is $24,600. What was her old salary?
6. The cupcakes were divided evenly among the 27 students. Each student got two cupcakes. How many cupcakes were there originally?
7. Loretta cycled twice as far as Julio. Julio cycled 23 miles. How far didLoretta cycle?
8. The cost of the party was divided evenly among 18 people. The total cost was $99.00. How much did each person chip in?
9. Michael drove 3 times as fast as Marla. Michael drove 57 mph. How fast did Marla drive?
10. Hughie’s yearly salary was divided evenly over 12 months. Each month he received $800. How much was his yearly salary?
Solve each equation and checkyour solution.
© Milliken Publishing Company 23 MP4055
Solving two-step equations
1.“Undo” addition/subtraction
2.“Undo”multiplication/division
2 × + 3 = 7– 3 = – 3
2 × = 4
2 ×2
=
42
∴ × = 2
Check:×3
– 1 = 4 153
– 1 = 4
+ 1 = + 1
3 ×3
= 3 5( ) 5 – 1 = 4
× = 15 4 = 4
4 × + 5 = 21 ×4
+ 5 = 21 3 × – 2 = 7
×3
+ 2 = 7 9 × + 1 = 19 ×5
– 4 = 2
8 × – 2 = 22 ×7
+ 4 = 8 2 × – 42 = 44
×3
+ 3 = 3 5 × – 5 = 5 ×11
– 2 = 4
✔
Length (l) 8 9 6
Width (w) 5 7 5
Perimeter (p)
© Milliken Publishing Company 24 MP4055
Substitute data into formula: e.g.
area of circle = π x (radius)2
a = π r2
If r = 3 cm
a = 3.14 (3)2 = 3.14(9)
= 28.26 cm2
FORMULAS
Complete each chart by substituting data into eachformula.
Radius (r) 2 4 1.5
Area (a)
Radius (r) 2 3.5 5
Circumference (c)
Length (l) 7 12 14.5
Width (w) 5 3 6
Area (a)
a = π r2
c = 2 π r
p = 2(l + w) a = l x w
Rate (R) 55 40 62
Time (t) 3 8 7
Distance (d)
Distance (d) 300 480 85
Gallons (g) 6 16 5
Mileage (m)
d = R x t m = dg
13 + –18 + –5 = –13 + 16 + –5 =
–24 + 20 + 6 =
26 + –12 + –4 =
–42 + 38 + –4 =
56 + 8 + –10 =
246 + –138 + –56 =
–6 + –8 + 2 + 4 =
5 + –4 + 6 + –6 =
–9 + 7 + 2 + 3 =
6 + –3 + –8 + 1 =
–5 + –5 + 6 + –7 =
–560 + 450 =
–246 + –424 =
–2000 + –455 =
2465 + –3460 =
–3000 + –467 =
40 + –32 + 6 =
–13 + 15 + –30 =
32 + –48 + 14 =
52 + –34 + 9 =
20 + 42 + 13 =
346 + –129 + 48 =
3 + –2 + 5 + 0 =
–3 + 4 + 3 + –4 =
–4 + 5 + –6 + 8 =
–7 + 8 + 2 + 5 =
3 + 4 + –3 + –5 =
–840 + 760 =
832 + –832 =
6000 + –4500 =
8888 + –6468 =
4642 + –5000 =
–40 + 80 + –30 =
–6 + 8 + 9 =
–25 + 50 + 75 =
–29 + –13 + –6 =
–124 + 68 + –56 =
2 + –3 + –4 + 5 =
–7 + 9 + –1 + –2 =
6 + –5 + –4 + –3 =
4 + –5 + –5 + 4 =
7 + 6 + –2 + –3 =
450 + –230 =
–345 + 500 =
–4000 + 842 =
–2830 + 1460 =
–4256 + 5642 =
© Milliken Publishing Company 25 MP4055
Find the sum.
2 + –3 + 5 =
–5 + 6 + –7 =
10 + –7 + 6 =
–3 + 1 + –5 =
1 2 3 4 5 60–5 –4 –3 –2 –1
+3
–2
–7
Addition of integers
3 + –2 + 4 + –7
–6
+4
© Milliken Publishing Company 26 MP4055
Subtraction of integers(Add the opposite)Find the difference.
8 – 5 =
–9 – 4 =
10 – –6 =
–7– –2 =
12 – –3 =
–20 – 20 = 101 – –303 =
32 – 40 =
–13 – –14 =
100 – –46 =
250 – –75 =
–200 – 48 =
–40 – –60 =
8 – –4 =
76 – –82 =
2 – 49 =
13 – –14 =
–202 – 404 =
14 – 464 =
126 – 300 =
76 – 84 =
99 – 88 =
32 – –5 =
0 – –4 =
37 – 100 =
–62 – –41 =
72 – –27 =
82 – –5 =
–20 – –20 =
–50 – 55 =
50 – –50 =
3 – –58 =
–242 – –50 =
–28 – –36 =
7 – 58 =
146 – 530 =
–43 – –43 =
24 – 16 = 24 + –16 = 8
24 – –16 = 24 + 16 = 40
–24 – 16 = –24 + –16 = –40
–24 – –16 = –24 + 16 = –8
© Milliken Publishing Company 27 MP4055
Find the product. Multiplication of integers
–24 x –2 =
–4 x 3 =
–7 x –7 =
–41 x 2 =
–2 x –19 =
2 x –2 x 4 = –3 x –2 x –1 =–3 x 4 x –5 =
3 x 2 x 3 = –2 x 4 x –4 =4 x 2 x –1 =
–1 x –2 x –3 = 4 x 5 x 6 =5 x 6 x –2 =
–3 x 4 x –2 = 5 x 10 x –10 =6 x –2 x 4 =
–5 x –5 x 5 = 4 x –3 x –3 =2 x –30 x –1 =
4 x 5 x 2 = –6 x 5 x 2 =–2 x –3 x –11 =
–2 x –1 x –1 = 4 x –3 x 6 =–3 x –4 x 8 =
–2 x 3 x –4 x –1 = 5 x –2 x 1 x –1 =
–2 x 5 x –2 x –4 = –1 x –1 x –1 x –2 =
3 x 3 x –1 x –1 x 1 = –2 x 3 x 4 x –1 =
–2 x –2 x –2 x –2 x –2 = –1 x –1 x 2 x 3 x –1 =
–3 x 2 x 2 x 2 x –3 = –2 x –5 x 2 x 3 x 5 =
1 x 2 x 3 x 4 x 5 = 7 x –6 x 5 x –4 x 3 =
2 x –3 x –2 x –3 x 2 = –3 x 2 x 3 x –2 x 3 =
2 x 1 x 3 x –2 x –3 x –1 = 1 x –4 x –1 x 1 x –4 x –4 =
–3 x –2 x 4 = 24
“Even” number of signs produces apositive product.
–3 x –2 x –4 = –24
“Odd” number of signs produces anegative product.
Find the quotient.
8 ÷ 4 =
–4 ÷ 2 =
–1 ÷ –1 =
6 ÷ –3 =
–9 ÷ –3 =
© Milliken Publishing Company 28 MP4055
Division of integers
24 ÷ –6 = –4
Division involving one negative numberwill produce a negative quotient.
–24 ÷ –6 = 4
Division involving two negative numberswill produce a positive quotient.
–10 ÷ –2 =
0 ÷ 4 =
14 ÷ –2 =
16 ÷ 8 =
–18 ÷ –2 =
–20 ÷ –4 =
–28 ÷ 7 =
–54 ÷ –9 =
–68 ÷ 17 =
62 ÷ –31 =
100 ÷ –20 =
150 ÷ –50 =
400 ÷ –20 =
–320 ÷ –160 =
1000 ÷ –50 =
–1500 ÷ –150 =
–12 ÷ –2 =
–6 ÷ –2 =
–11 ÷ 1 =
15 ÷ –5 =
17 ÷ –17 =
20 ÷ –5 =
22 ÷ –11 =
–35 ÷ 7 =
63 ÷ –7 =
72 ÷ –9 =
–64 ÷ –16 =
–100 ÷ 25 =
–300 ÷ –75 =
–600 ÷ –40 =
–450 ÷ 9 =
–2400 ÷ –60 =
–2000 ÷ –1000 =
–3 ÷ 1 =
–8 ÷ 2 =
–14 ÷ 7 =
–16 ÷ –2 =
18 ÷ –9 =
–21 ÷ –7 =
–20 ÷ –2 =
–42 ÷ –21 =
–65 ÷ –13 =
75 ÷ 25 =
81 ÷ –9 =
–100 ÷ –50 =
225 ÷ –15 =
121 ÷ 11 =
490 ÷ 70 =
–3000 ÷ 600 =
4500 ÷ –900 =
0 ÷ –2 =
7 ÷ –1 =
–13 ÷ –1 =
–15 ÷ 3 =
16 ÷ –4 =
–18 ÷ 3 =
24 ÷ –8 =
56 ÷ –7 =
66 ÷ –11 =
–58 ÷ 2 =
–85 ÷ –17 =
100 ÷ –10 =
–275 ÷ 25 =
–625 ÷ 5 =
–630 ÷ 90 =
2500 ÷ 50 =
8500 ÷ 1700 =
5 ÷ –5 =
12 + –3 x –6 = –18 x 2 + 3 = 16 ÷ –4 + 3 =
28 – 3 x –2 = –64 + –8 ÷ –4 = –30 x –2 – 4 =
63 ÷ –9 – 5 = 13 – 4 x –5 = 27 + –8 x 6 =
18 – 3 ÷ –3 = –65 ÷ 13 – 5 = 14 x –5 – 8 =
Evaluate.
–3 + 2 x –5 =
© Milliken Publishing Company 29 MP4055
Order of operations
–2 + 3 x –5 –2 + –15 = –17
–20 ÷ 4 + –13–5 + –13 = –18
Evaluate.
4 + 2[–5 x 2 + 1] =
© Milliken Publishing Company 30 MP4055
More order of operations
–2 + 3[–4 x 5 – 6]
–2 + 3[–20 – 6]
–2 + 3[–26]
–2 + –78 = –80
3 + 5[2 + 3 x –2] = –1 + 2[5 x 2 – 3] = 8 – 2[6 ÷ 3 – 2] =
–10 – 4[2 + 3 ÷ –3] = 20 + 2[3 ÷ 3 – 1] = 2[5 x 2 – –6] + 1 =
5[8 ÷ 4 – 1] – 2 = 6 – 3[2 + 3 x –4] = –17 + –2[4 x 5 – 2] =
12 – 3[4 + 8 ÷ –4] = 5[20 ÷ –5 – 1] – 1 = –2 + –3[6 + 8 x 2] =
10zy
+ 3 × – y =
2x + 3y – z = 2y – 4x + 72 =
3z + 4x – 5z = xy + yz + 2x =
zy
+ 2 × =
If x = –4, y = 2, z = –6evaluate each of the following expressions.
© Milliken Publishing Company 31 MP4055
Given a = 2, b = –3, evaluate the expression
5b + a
5 (–3) + 2
–15 + 2
–13
×y + 2y× + z =
x + y = y – z = 4z + x = –2y + 5x =
2x + 3y = xy + 2 = 6y – 4z =
© Milliken Publishing Company 32 MP4055
INTEGER WORD PROBLEMS
Write and solve a linear equation for each problem.
1. If x is increased by 14, the sum is 12. What is x?
2. If y is decreased by 17, the difference is 3. What is y?
3. If w is multiplied by 7, the product is –63. What is w?
4. If t is divided by –3, the quotient is 42. What is t?
5. –16 is 5 more than q. What is q?
6. 24 less than c is 13. What is c?
7. –3 times m is –105. What is m?
8. A number divided by 9 results in a quotient of –117. What is thenumber?
9. When a certain number is increased by 57, the result is 38. What is the number?
10. A certain number is 14 less than –9. What is the number?
© Milliken Publishing Company 33 MP4055
WORD PROBLEMS USING RATIONAL NUMBERS
1. William gained 4 lbs., lost 3 lbs., gained 6 lbs. and finally lost 11 lbs. What was his net weight change?
2. Jackie’s average of 84 increased by 2 points, then fell by 4 points, then increased by 9 points, and finally fell by 1 point. What was her final average?
3. The average temperature on Monday was 5 degrees below 0. It rose7 degrees on Tuesay, fell 8 degrees on Wednesday and rose 4 degrees on Thursday. What was Thurday’s average temperature?
4. In the first quarter of Saturday’s football game, Wayne gained 7 yards, lost 3 yards, lost another 5 yards, then gained 15 yards. What was his net gain or loss in the first quarter?
5. The stock market rose 1-1/4 points on Monday, fell 3/4 of a point on Tuesday, rose 1/2 point on Wednesday, rose 7/8 of a point of Thursday, and fell 1-1/2 points on Friday. What was the net change for the week?
6. The submarine dove 75 feet, rose 25 feet, then dove 140 feet and finally ascended 85 feet. What was the net change in depth?
7. Cindy lost 1-3/4 lbs., gained 2-2/3 lbs., gained 1-1/2 lbs., then finally lost 3-1/2 lbs. What was her net change in weight?
8. Maureen climbed to an altitude of 1500 feet above sea level. She then descended 750 feet, climbed 850 feet, and then descended 620 feet where she finally decided to stop. At what altitude did she rest?
9. The temperature at the ski resort was 22° C when the ski lifts opened. During the course of the day it fell 3.8° C, rose 2.9°C, rose another 5.3° C, and finally fell 4.7°C. What was the temperature at the close of the day?
–158
+ – 2 34
= 2 712
+ – 3 13
= – 2.45 – 3.1 = 4.2 + – 3.14 =
2.5 – – 3.4 = 3 12
+ –114
= 78
+ – 35
= – 2.9 + – 5 =
23
–– 5
6= 3.4 + – 5.6 = –1 – .46 = –12
3+ 1
6=
–3.4 – 5 = 49
+–23
= 125
+ – 2 14
= 1.4 + – 5 =
© Milliken Publishing Company 34 MP4055
Combining rational numbers
–78
+34
= –.3 – –.5 =
–78
+68
= –.3 + .5 =
–18
.2
Simplify each expression.
2 + – 3 + – 4 = 5 + – 8 + 7 = – 6 + 8 + –10 =
21 + – 8 + – 2 = –13 + – 4 + 9 = 17 + – 2 + 6 =
24 ÷ – 6 + 3 = 2 × – 4 – 4 = 3 + 8 × – 3 =
– 6 + 8 + – 3 = 8 + 6 + –1 = 8 – 3 – – 4 =
– 3 =
16 =
– 21 =
– 2 + 0 = 3 + –1 = – 5 + – 3 = 8 + – 2 =
8 – – 3 = 3 × – 5 = 11 + – 7 = 8 – – 9 =
4 + – 8 = – 6 + – 2 = 8 ÷ – 2 = 24 ÷ 6 =
– 20 + 6 = –18 ÷ – 3 = 6 + – 8 = – 2 + –1 =
8 + – 2 0 + – 7 4 – 1 17 + – 2
© Milliken Publishing Company 35 MP4055
Absolute valueDetermine absolute value.– 2 = 2
6 + – 10 = – 4 = 4
– 2 × – 3 = 6 = 6
1.
2.
3.
Comparing rational numbers
–46 < 2 –18 > –50
–3 12
–4
–2 1.2
–3 34
–2 12
–3.2 2 37
36
– 49
.4
–10 –212
–3.2 –.32 –3 12
–2.5 23
–.6
–2.3 –2.31 –3 12
–3 14
2.45 –3 2 14
–125
© Milliken Publishing Company 36 MP4055
Write > or < in each .
Put numbers in order from least to greatest.
________ < _______ < _______ < ______
________ < _______ < _______ < ______
________ < _______ < _______ < ______
________ < _______ < _______ < ______
________ < _______ < _______ < ______
3 –3.2 –3 45
–.2
–1.4 1.04 –.14 114
2 35
–2.4 –2 12
2
13
–.45 25
–.3
–4 12
4.2 –4.3 4 13
23 –5 –1 2
– 5 < – 1 < 2 < 23
Ordering rational numbers
Solving one-step equations
× + – 8 = 2
+ 8 + 8
× + 0 = 10
× = 10
–2 × = 16
–2 × = 16
–2 – 2
× = – 8
© Milliken Publishing Company 37 MP4055
Solve for x.
× + – 9 = 7 × – 2 = –18 ×–3
= 6 5 × = – 35
× + 12 = 7 × – – 3 = 4 –7 × = – 63 ×7
= – 4
× – 15 = – 3 × + – 6 = 14 12 × = – 48 ×–3
= – 4
–3 × = – 51 × – 13 = – 27 ×6
= –18 × + – 6 = – 50
Add 8 to each sideof equal sign:
Divide each side ofequal sign by –2:
Solve for x.
© Milliken Publishing Company 38 MP4055
Solving two-step equations
2 × + – 3 = –15
→ + 3 = + 3
2 × + 0 = – 12
2 × = – 12
→ 2 = 2
× = – 6
×5
+ 2 = – 4
–3 × + 5 = 65 4 × – 6 = – 26 ×–2
– 4 = 6
×3
+ – 4 = – 7 –7 × – 3 = 18 6 × + 16 = – 2
–12 × + –4 = 8 ×–9
– 7 = – 6 –8 × + 6 = – 50
Add 3 toeach sideof equalsign.
Divideeach sideof equalsign by 2.
2 –4 = 5 – 2 = 3 – 1 = 7 – 4 =
10 – 2 = 4 – 5 = 6 – 2 = 8 – 9 =
9 – 8 = 6 – 6 = 2 – 5 = 4 – 2 =
Write each decimal as a power of 10.
.1 = ________
.00001 = ________
1000 = ________
.001 = ________
100 = ________
.000001 = ________
© Milliken Publishing Company 39 MP4055
Negative exponents
Write each power with a positive exponent.
Write each power with a negative exponent.
19 2 = 1
73 = 14 2 = 1
31 =
154 = 1
26 = 16 4 = 1
83 =
110 2 = 1
79 = 13 4 = 1
2 5 =
A. .01 =1
100=
110 2 = 10−2
B. 15 4 = 5−4
C. 3−2 =132
Write in scientific notation.
.004 =
.0012 =
.0204 =
© Milliken Publishing Company 40 MP4055
Using scientific notation
.0003 = 3 x 10–4
2000 = 2 x 103
Using a decimal
3.2 x 10–4 = .00032
4600 = .048 .15 =
.00005 = 3200 = .0003 =
270 = .018 = .123 =
Write the equivalent decimal.
2.84 x 10–2 = 3.2 x 10–3 = 4.8 x 102 =
1.2 x 103 = 5 x 10–4 = 1.04 x 10–1 =
5.6 x 10–3 = 2 x 102 = 4.1 x 10–2 =
6 x 10–3 = 5 x 103 = 1.8 x 10–1 =
4.56 x 10–2 = 7.1 x 10–1 = 2.9 x 102 =
23
34
56
78
215
18
49
37
910
89
38
45
56
23
12
35
67
49
511
67
29
311
34
715
23
813
617
34
513
611
23
56
98
76
118
107
© Milliken Publishing Company 41 MP4055
Using cross-products
23
34
46
56
2024
1822
14
37
28
38
1540
1236
25
37
615
27
39
13
511
1824
1216
23
49
2030
38
2156
49
58
48
1016
34
1428
36
78
1416
59
Write > or < in each . Which is bigger: 34
or 58
?
2434
2058
>
3 54 8
>. ..
Circle which two ratios are equal in each group.
© Milliken Publishing Company 42 MP4055
Determine the unit price of eachitem. Circle the “better buy.”
Find the “unit price”
Item: MilkPrice: $2.56 per gallonQuantity: 1 gallon or 128 oz.Unit Price per ounce =
Item Price Quantity Unit Price
Milk (A) $1.28 64 oz.
Milk (B) $ .48 16 oz.
Item Price Quantity Unit Price
Apples (A) $3.20 1 lb.
Apples (B) $1.76 1/2 lb.
Item Price Quantity Unit Price
Pizza (A) $1.20 3 slices.
Pizza (B) $1.50 5 slices.
Item Price Quantity Unit Price
Jelly (A) $ .45 6 oz.
Jelly (B) $ .56 8 oz.
Item Price Quantity Unit Price
Ice crm.(A) $.90 2 scps.
Ice crm.(B) $1.05 3 scps.
Item Price Quantity Unit Price
Soap (A) $1.92 64 oz.
Soap (B) $1.68 48 oz.
Item Price Quantity Unit Price
Bologna (A) $1.20 1/4 lb.
Bologna (B) $2.40 1/2 lb.
Item Price Quantity Unit Price
Pencils (A) $1.50 1 doz.
Pencils (B) $1.20 8
Item Price Quantity Unit Price
Gum (A) $.75 5 sticks
Gum (B) $1.04 8 sticks
$2.56128 oz.
= $.02 per ounce
© Milliken Publishing Company 43 MP4055
Solving proportions
×4
= 2432
–32
= 15y
1112
= w18
710
= m50
t9
= 45
3n
= 49
815
= 3c
v4
= 56
7d
= 89
420
= e5
f24
= 68
312
= 8g
68
= 3p
w3
=8
14
14w = 24
w =157
Solve for the variable.
© Milliken Publishing Company 44 MP4055
How far is it from New York to St. Louis?
Use the scale: 1" = 500 mi.
NY to St. Louis = 2"
Determine the actual distancebetween each pair of cities.Use the scale.
×2
=500
1
× = 1000 miles
1. New York to Miami 9. Seattle to Chicago2. Boston to Washington, D.C. 10. Denver to Washington, D.C.3. St. Louis to San Francisco 11. St. Louis to Denver4. Dallas to Seattle 12. San Francisco to Washington, D.C.5. Chicago to Denver 13. Boston to Chicago6. Boston to Dallas 14. Miami to Seattle7. New York to San Francisco 15. New York to Dallas8. Miami to St. Louis
St. Louis •
Boston •New York•
Washington,D.C.
•Chicago •
Dallas •
Denver•
Seattle•
SanFrancisco
•
Miami•
×100
×100
Reduced Decimal PercentFraction
© Milliken Publishing Company 45 MP4055
Complete the chart, filling in all equivalent values.
Example:
34
75100
12
20100
15100
38
25100
710
.65
.05
30%
6%
60%
ReducedDecimal PercentFraction
.75 75%
Write an equation for each question and solve.
What is 35% of 80?
12 is what % of 60?
15 is 40% of what?
What is 47% of 60?
8 is what % of 32?
24 is 30% of what?
What is 95% of 240?
48 is what % of 64?
34 is 17% of what?
3 is what % of 2?
© Milliken Publishing Company 46 MP4055
What is 20% of 30?
x = .20 (30)
x = 6
Write an equation for each question, substituting x for the word“what.” Solve for x.
8 is 25% of what?
8 = .25 (x)
8.25
=.25 .25
32 = ×
(x)
(x)
© Milliken Publishing Company 47 MP4055
WORD PROBLEMS
1. A VCR costs $325. The sales tax is 8% of the price. What is the total priceof the VCR including tax?
2. A coat was originally priced at $280. The department store had a 25%off sale. What was the sale price of the coat?
3. The bicycle which originally sold for $400 was on sale for $320. Whatpercent was the bicycle marked down?
4. Last year, Ms Stewart earned $64,000. This year she got a raise and now makes $67,200. What percent increase did Ms Stewart receive?
5. Sam weighs 160 lbs. but wants to weigh 152 lbs. What percent of his weight does he want to lose?
6. Terry used to be 125 cm. tall. She is now 7% taller. How tall is she now?
7. Franklin has an average of 75 and wants to raise it to 90. What % increase would this be?
8. The sale price of a radio is $81. It was marked down 10%. What was theoriginal price?
9. Tommy bought a sweater at a moonlight madness sale for $20. It used to be $100. What % savings did he receive?
10. Jeri got a promotion and a 14% increase. Her old salary was $24,000.What is her new salary?
Old Price New Price Increase % Increase
$50 $70$100 $125
$64 $96$75 $90
$250 $300$400 $440
$2500 $3250$5000 $5050
$10,000 $20,000
Old Price New Price Decrease % Decrease
$50 $30
$100 $75
$64 $32
$12 $9
$450 $405
$500 $490
$2800 $2772
$4600 $3680
$20,000 $19,400
© Milliken Publishing Company 48 MP4055
What % did the price of the sweater increase?
Old Price = $40
New Price = $50
Increase = $10
% Increase = IncreaseOld Price
=10 40
= 25%
Determine increase and %or decrease and %.
© Milliken Publishing Company 49 MP4055
25% OFF SALE!
Original Price of Sweater = $40
$40 x .25 = $10 = Discount
$40 – $10 = $30 = Sale Price
Original Price % Discount Savings Sale Price
$50 20%$75 40%$64 25%$87 10%
$124 30%$156 8%$79 50%
$2000 5%$850 20%
$250 15%
$450 45%
$600 33%
$4600 18%
$27 20%
$30 25%
$950 12%
$10,000 40%
$25,000 15%
$64,000 8%
$100,000 19%
Determine savings and sale price.
© Milliken Publishing Company 50 MP4055
Percents using ratios
What is 30% of 50? (write a proportion)
Solve using a proportion
What is 20% of 50?
15 is what % of 60?
17 is 50% of what?
What is 5% of 650?
37 is what % of 370?
48 is 40% of what?
What is 7% of 92?
600 is what % of 500?
24 is 30% of what?
What is 150% of 84?
×=
× =
× =
50.
30
100
100 30 50
100 1500
( )
35100
(Hint: Always write the % as a
fraction with denominator “100.”
e.g. 35% =
© Milliken Publishing Company 51 MP4055
Given 3, 8, 7, 1, 0, 3, 6
Mean =
Median = 0, 1, 3, 3, 6, 7, 8 = 3
Mode = 3
Find the Mean, Median, Modefor each set of data.
Test Scores Hourly Wages Heights
78, 92, 90, 78, 96 $6.50, $20.00, $32.00 72", 60", 58", 62", 60", 72"
$29.00, $6.50, $10.00, 60", 76"
$15.00
Mean Mean Mean
Median Median Median
Mode Mode Mode
Weights Homeruns Driving Speeds
194, 206, 128, 102, 128, 7, 10, 7, 24, 3, 7, 6, 24, 55, 45, 55, 60, 60, 70, 55,
240, 100, 128, 128, 206 7, 11, 26 55, 62, 68, 75, 60
Mean Mean Mean
Median Median Median
Mode Mode Mode
Ages Hours of Sleep Phone Calls
14, 15, 13, 13, 15, 12, 17, 2, 8, 10, 8, 7, 10, 6, 4, 7, 3, 10, 1, 0, 2, 5, 5, 3, 2, 7,
15, 15, 12, 15, 12, 14 7, 10, 7, 7, 9, 3 8, 3, 4, 3, 4
Mean Mean Mean
Median Median Median
Mode Mode Mode
3 + 8 + 7 + 1 + 0 + 3 + 67
= 4
© Milliken Publishing Company 52 MP4055
Using the 3 graphs answer the following exercises.
1. How many schools are in Summit?
2. Compare Jamestown and Fox. How many more schools are inJamestown?
3. Powell Schools represent what %of the total number of schools?
4. How many districts have less than20 schools?
5. How many students attend FoxDistrict?
6. How many more students does Summerville have than James-town?
7. How many districts have morethan 3000 students?
8. Summit has what % of the totalstudent population.
9. What was the population of Hope HS in 1965? in 1970? in 1980?
10. During what 5 year period was itsfastest rate of growth?
Number of Schools
50
40
30
20
10
0
SUMMIT
POWELL
SUMMERVILLE
JAMESTOWN
FOX
18
28
48
32
14
Fox
Jamestown
Summerville
Powell
Summit
Each represents 1000
Number of Students
2500
2000
1500
1000
500
1960
Population Growth of Hope H. S.
1965 1970 1975 1980 1985 1990
© Milliken Publishing Company 53 MP4055
+ = +
+ = + =
= =
= =
= =
4 2 4 2
4 9 2 3 5
3 4 3 2 6
9 4 3 2 1
16
4
4
22
– –
( )
– –
NUMBERS WITH PERFECT SQUARE ROOTS
Simplify each radical.
49 100
81 25
36 64
Simplify each radical. Then add or subtract.
121 100 225 4 16 49
81 9 64 625 169 144
100 25 900 400 196 256
–
– –
–
+ +
+
+ +
Simplify each radical. Then multiply by the coefficient.
5 9 7 4 11 16 4 4
6 49 10 225 8 81 100 64
Simplify each radical. Then multiply or divide.
4 9 16 1 25 25 49 4
64
16
100
25
121
49
225
81
• • • •
© Milliken Publishing Company 54 MP4055
REDUCING RADICALS
Reduce to simplest form.
98 = 49 • 2
= 49 • 2
= 7 2
3 48 = 3 16 • 3
= 3 16 • 3
= 3 (4) • 3
= 12 • 3
45 32 50 28
200 242 162 75
1000 72 44 80
12 8
18 6
20 27
2 24 6 125 3 98
9 18 5 40 15 27
7 450 2 90 8 54
4 1350 2 363 5 147
7 7 7 12 18 20
300 – 27 75 + 27 98 – 32 12 – 3
200 + 128 6 + 24 63 – 7 8 + 18
72 – 50 150 – 24 121 + 100 242 + 8
243 + 192 175 – 28 3 + 27 48 – 27
© Milliken Publishing Company 55 MP4055
Combining square roots
Only radicals that are “exactly” alike can be added:
28 + 63
4 • 7 + 9 • 7
2 7 + 3 7
5 7
Simplify the sums and differences.
24 + 54
© Milliken Publishing Company 56 MP4055
More combining square roots
All square root radicals can be multiplied or divided.
Simplify products and quotients.
3 • 27 = 3 • 27 = 81 = 92 • 8
24
6=
246
= 4 = 2
5 • 125 273
6 • 6 88
3 • 2 155
5 • 7 168
7 • 14 328
2 • 32 1004
11 • 3 555
13 • 4 7525
PYTHAGOREAN THEOREM
Find the missing side of eachtriangle using the PythagoreanTheorem.
© Milliken Publishing Company 57 MP4055
bc
a
4c
3
a2 + b2 = c2
a2 + b2 = c2
32 + 42 = c2
9 + 16 = c2
25 = c2
5 = c
12
5 3
5c b 6 8
c
13
a
5
26
24b
c 3
3
35
c
15
8
c 8 10
a
15
12
a6
12
a
25
20 a
Example:4 155 ft. 3 inch 7 ft. 6 inch 7 qt. 1 pt.
– 2 ft. 7 inch + 4 ft. 9 inch +2 qt. 1 pt.2 ft. 8 inch
3 gal. 1 qt. 18 yds. 2 ft. 17 m 56 cm–1 gal. 3 qt. + 37 yds. 1 ft. –4 m 85 cm
5 qt. 11 oz. 15 mi. 370 ft. 85 cm 43 mm– 2 qt. 3 oz. – 8 mi. 2000 ft. + 17 cm 65 mm
18 lbs. 7 oz. 5 qt. 7 c 6 oz.+ 5 lbs. 9 oz. – 3 qt. 1 cup –5 c 7 oz.
UNITS OF MEASURE
Write the equivalent measure.
24 inch = ______ ft.
12 feet = ______ yd.
8 qts. = ______ gal.
32 oz. = ______ cups
6 c. = ______ pints
© Milliken Publishing Company 58 MP4055
Equivalent measures
12 inch = 1 foot 8 oz. = 1 cup
3 feet = 1 yard 2 c. = 1 pint
36 inches = 1 yard 2 p.t = 1 quart
5280 feet = 1 mile 4 qt. = 1 gal.
1000 mm = 1 m 16 oz. = 1 lb.
100 cm = 1 m
10mm = 1 cm
Add or subtract. (Reduce measure)
© Milliken Publishing Company 59 MP4055
Answer Keypage 1
200150330100800
2134 1630 14,763 11,978 20,00015,924 1516 128,507 121,435 8892
1111 792 3346 3663 1041337 3195 341 1559 1111
5556 3087 47,524 2222 11,862
page 8
page 510
13.417.5
209
4.035 48.72 11.95 11.95 16.88
11.8 11.73 6.01 5.78 1.76329.32 2.705 3.65 4.35 .99
9.8 22.3329.98 22.07
6.7
page 220,172 106,785
546,750 2,356,249 974,848 3,077,7452,814,000 4,577,903 1,142,301 4,068,240
33 31 25 2049 321 43
page 32
1219 8 19 49 25 1 26
45 7 27 3711 46 6 137 24 12 10
page 64.5
1.25.74.4
8.881.96 .27 1.107 .0912 7.29.493 1.222 .2772 00492 .602
42 4.2 420 422.5 25 .25 250
8 50 .9 .006300 40 .14 20020 .3 .02 2
page 7<<><>< > >< > >> > << > >
7 9 17 221 0 2 1
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2.46 .05 1.18 2.01
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page 4494 53 28
53 18 54113 4242 126
3
4
5
3
3
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7 7
1 2 11
12 7 7
6
3
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3.2 8 6
4 25 49 1 81
27 64 8 512 125
256 16 1 81 625
100 10,000 10 1 1000
243 64 1 16 3125
2 8 7
5 4 6
3 9 10
2.5
( )
( )
( )
9
© Milliken Publishing Company 60 MP4055
page 9240
371050.68371700.89230 84.05
62,040 230,0001,490,000 37555,000,000 810,000
74,200 900,000,000
page 16
page 17
page 14
page 15
page 104 25
27 624 1020
page 11126066
306
36004 min.
page 13> << >> < < <> > < >> > < >
page 12
34
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© Milliken Publishing Company 61 MP4055
page 263
–1316–515
–40 404–8 371 4
146 –63325 –21
–248 9920 8712 0
158 –105–47 10027 61
–606 –192–450 8–174 –51
–8 –38411 0
page 18669114
1224
5, 7 0,117, 3 22, 3
10, 14 14, 837, 31 25, 6
10 1826 1011 3019 8
page 197 54 13 9
37 16 72 618 19 17 152 18 7 0
page 28–2–21
–235 3 –4 –70 –11 –2 13
–7 –3 8 –52 –1 –2 –49 –4 3 –65 –2 10 –3
–4 –5 2 –86 –9 5 –6
–4 –8 3 –29–2 4 –9 5–5 –4 2 –10–3 4 –15 –11
–20 15 11 –1252 –50 7 –7
–20 40 –5 5010 2 –5 56 –3 0 –1
page 254
–69
–7–10 –2 1410 2 –2811 10 –2
100 –8 27–48 54 75
–112 52 2650 –8 6
–1 1 0–6 3 3–2 –4 88 –11 –1
220 –110 –80155 –670 0
–3158 –2455 1,500–1370 –955 2,4201386 –3467 –358
page 29–1330 –33 –134 –62 56
–12 33 –2119 –10 –78
page 2748
–1249
–823860 –16 –6–8 18 32
–60 –6 120–48 24 –50060 125 36
–66 40 –6096 –2 –72
–24 10–80 2
9 24–32 –672 300
120 2.520–72 108–36 64
page 2412.56 50.24 7.065 12.56 21.98 31.4
26 32 22 35 36 87165 320 434 50 30 17
page 2021 30 20 3
144 37 50 492126 20 15 7
2 3 20 10
page 30–14–17 13 8–14 20 33
3 36 –536 –26 –68
page 31–2 8 –28 –24–2 –6 –11 364 92 –15
–4 –44 –28
page 234 64 3
15 2 303 28 430 2 66
page 218
65”161027565
$17,9503h. 13 min.
5019
page 22$4.75
252160 lbs.
13$8,200
5446 min.
$5.5019 mph
$9,600
© Milliken Publishing Company 62 MP4055
page 32–220–9
–126–213735
–1,053–19–23
page 33Lost 4
90–2˚
14 yds.+3/8
–105 ft.–1 1/12 lb.
+980 ft.21.7˚
page 34page 39
page 45
page 43
page 353
16212 2 8 6
11 15 4 174 8 4 4
14 6 2 36 7 3 155 4 8
11 8 211 12 211 13 9
page 3716 –16 –18 –7–5 1 9 –2812 20 –4 1217 –14 –108 –44
page 38–30–20 –5 –20–9 –3 –3–1 –9 7
page 40
.0284 .0032 4801200 .0005 .104.0056 200 .041
.006 5.000 .18.0456 .71 290
page 42$.02 per oz.$.03 per oz.$.20 per oz. $.03 per oz.$.22 per oz. $.035 per oz.
$.40/slice $4.80 lb.$.30/slice $4.80 lb.$.075/oz. $.125 each
$.07/oz. $.15 each$.45/scoop $.15/stick$.35/scoop $.13/stick
page 441 – 1250 9 – 1937.52 – 375 10 – 1687.53 – 1875 11 – 8754 – 2000 12 – 2687.55 – 1000 13 – 10006 – 1875 14 – 30007 – 2875 15 – 1687.58 – 1187.5
page 36><< < < <> < < >> < > >
page 41<<> > > <> < > << > < << < < <
© Milliken Publishing Company 63 MP4055
page 462820
37.528.2
2580
22875
200150
page 5010
25%34
32.510%1206.44
120%80
126
page 471 $3512 $2103 20%4 5%5 5%6 133.75 cm7 20%8 $909 80%
10 $27,360.
page 4820 4025 2532 5015 2050 2040 10
750 3050 1
10,000 100
20 4025 2532 503 25
45 1010 228 1
920 20600 3
page 49$10.00 $40.00$30.00 $45.00$16.00 $48.00$ 8.70 $78.30$37.20 $86.80$12.48 $143.52$39.50 $39.50
$100.00 $1900.00$170.00 $680.00
$37.50 $212.50$202.50 $247.50$198.00 $402.00$828.00 $3772.00
$5.40 $21.60$7.50 $22.50
$114.00 $836.00$4000.00 $6000.00$3750.00 $21,250.00$5120.00 $58,880.00
$19,000.00 $81,000.00
page 53
page 54
page 5186.8 $17.00 65”
90 $15.00 61”78 $6.50 60”
156 12.63 60128 7 60128 7 55
14 7 414 7 315 7 3
page 521 182 183 20%4 25 approximately 15006 approximately 17507 38 approximately 11.76%9 approximately 750, 875, 1800
10 1973 – 1978
© Milliken Publishing Company 64 MP4055
page 55 page 56 page 57
page 5824243
(ex) 12’ 3” 10 qt.1 gal. 2 qts. 56 yds. 12m 71cm3 qts. 1 cup 6 mi. 3650 ft. 112 cm 8mm24 lbs. 1 qt. 3 cups 1 cup 7 oz.
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P.O. Box 802Dayton, OH 45401-0802
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a
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