math 110 practice final exam - sga.utm.edu

14
Math 110 Practice Final Exam 1. Evaluate using the Piecewise Function: () = { โˆ’3 2 + 4 โˆ’ 7 โ‰ค โˆ’5 5 โˆ’5 < โ‰ค 3 |2 โˆ’ 1| >3 a. (2) = โˆ’5 b. (โˆ’5) = 5 c. (โˆ’6) = 13 d. (8) = 15 2. Given the Piecewise Function, Identify an open point of the graph. () = { 2 โˆ’ 12 < โˆ’2 +4 โˆ’2 โ‰ค < 2 โˆ’6 + 3 โ‰ฅ2 a. (โˆ’2, โˆ’2) b. (2, โˆ’9) c. (โˆ’2, 16) d. (2, 6) 3. Find the new function given the set of equations: ( + 2)() () = โˆ’ + 1 () = 2 +1 โ„Ž() = ( + 1) 2 a. 2 +2 b. 2 โˆ’+2 c. 2 โˆ’ 2 + 3 d. +2 4. Find the Difference Quotient of the function: = (+โ„Ž)โˆ’() โ„Ž () = โˆ’5 2 +2 a. โˆ’10โ„Ž b. โˆ’10 โˆ’ 5โ„Ž c. โˆ’5 d. โˆ’10โ„Ž โˆ’ 5โ„Ž 2

Upload: others

Post on 26-Mar-2022

18 views

Category:

Documents


0 download

TRANSCRIPT

Page 1: Math 110 Practice Final Exam - sga.utm.edu

Math 110 Practice Final Exam

1. Evaluate using the Piecewise Function:

๐‘“(๐‘ฅ) = {โˆ’3๐‘ฅ2 + 4๐‘ฅ โˆ’ 7 ๐‘ฅ โ‰ค โˆ’5

5 โˆ’5 < ๐‘ฅ โ‰ค 3|2๐‘ฅ โˆ’ 1| ๐‘ฅ > 3

a. ๐‘“(2) = โˆ’5 b. ๐‘“(โˆ’5) = 5

c. ๐‘“(โˆ’6) = 13 d. ๐‘“(8) = 15

2. Given the Piecewise Function, Identify an open point of the graph.

๐‘“(๐‘ฅ) = {2๐‘ฅ โˆ’ 12 ๐‘ฅ < โˆ’2

๐‘ฅ + 4 โˆ’2 โ‰ค ๐‘ฅ < 2โˆ’6๐‘ฅ + 3 ๐‘ฅ โ‰ฅ 2

a. (โˆ’2, โˆ’2) b. (2, โˆ’9)

c. (โˆ’2, 16) d. (2, 6)

3. Find the new function given the set of equations: (๐‘” + 2๐‘“)(๐‘ฅ)

๐‘“(๐‘ฅ) = โˆ’๐‘ฅ + 1 ๐‘”(๐‘ฅ) = ๐‘ฅ2 + 1 โ„Ž(๐‘ฅ) = (๐‘ฅ + 1)2

a. ๐‘ฅ2 + 2 b. ๐‘ฅ2 โˆ’ ๐‘ฅ + 2

c. ๐‘ฅ2 โˆ’ 2๐‘ฅ + 3 d. ๐‘ฅ + 2

4. Find the Difference Quotient of the function: ๐ท๐‘„ =๐‘“(๐‘ฅ+โ„Ž)โˆ’๐‘“(๐‘ฅ)

โ„Ž

๐‘“(๐‘ฅ) = โˆ’5๐‘ฅ2 + 2

a. โˆ’10โ„Ž b. โˆ’10๐‘ฅ โˆ’ 5โ„Ž

c. โˆ’5๐‘ฅ d. โˆ’10๐‘ฅโ„Ž โˆ’ 5โ„Ž2

Page 2: Math 110 Practice Final Exam - sga.utm.edu

5. Use the given Table of Values to identify the correct Evaluation.

๐‘ฅ ๐‘“(๐‘ฅ) ๐‘”(๐‘ฅ) 1 3 8 3 1 9 8 9 1 9 8 3

a. (๐‘“ โˆ˜ ๐‘”)(8) = 1 b. (๐‘“ โˆ˜ ๐‘”)(9) = 3

c. (๐‘” โˆ˜ ๐‘“)(3) = 8 d. (๐‘” โˆ˜ ๐‘“)(9) = 9

6. Find the Composite function given the set of equations: (โ„Ž โˆ˜ ๐‘“)(๐‘ฅ)

๐‘“(๐‘ฅ) = 3๐‘ฅ โˆ’ 4 ๐‘”(๐‘ฅ) = 2๐‘ฅ2 โˆ’ 5 โ„Ž(๐‘ฅ) = 3(๐‘ฅ โˆ’ 1)2

a. 27๐‘ฅ2 โˆ’ 75 b. 27๐‘ฅ2 โˆ’ 90๐‘ฅ + 75

c. 18๐‘ฅ2 โˆ’ 17 d. 18๐‘ฅ2 โˆ’ 27๐‘ฅ + 45

7. Given the Graph, identify the correct evaluation:

a. (๐‘“ โˆ˜ ๐‘”)(4) = 4 b. (๐‘” โˆ˜ ๐‘“)(4) = 4

c. (๐‘“ โˆ˜ ๐‘“)(4) = 4 d. (๐‘” โˆ˜ ๐‘”)(4) = 4

Page 3: Math 110 Practice Final Exam - sga.utm.edu

8. Given the table of data, determine if the table can represent a One-to-One Function.

๐‘ฅ (Semester)

๐‘ฆ (Percent Passing)

F2012 48

S2013 55

F2013 52

S2014 46

F2014 51

a. No, ๐‘ฅ repeats b. Yes, ๐‘ฅ & ๐‘ฆ are unique

c. No, ๐‘ฆ repeats d. Yes, ๐‘ฅ & ๐‘ฆ both repeat

9. Consider the One-to-One function, Identify the correct statement about itโ€™s inverse.

๐น(๐‘ฅ) = {(2,1), (3,2), (4,3), (5,4), (1,7)}

a. ๐‘“โˆ’1(2) = 3 b. ๐‘“โˆ’1(1) = 0

c. ๐‘“โˆ’1(4) = 7 d. ๐‘“โˆ’1(2) = 1

10. Consider the One-to-One graph of ๐‘“(๐‘ฅ), Identify the correct evaluation for its inverse.

a. ๐‘“โˆ’1(โˆ’1) = 2 b. ๐‘“โˆ’1(0) = โˆ’1

c. ๐‘“โˆ’1(1) = 0 d. ๐‘“โˆ’1(โˆ’3) = 4

Page 4: Math 110 Practice Final Exam - sga.utm.edu

11. Solve the Rational Equation: 4

๐‘ฅโˆ’1+

7

๐‘ฅ+2=

3๐‘ฅโˆ’7

(๐‘ฅโˆ’1)(๐‘ฅ+2)

a. ๐‘ฅ = 2 b. ๐‘ฅ = โˆ’1

c. ๐‘ฅ = 1 d. ๐‘๐‘œ ๐‘†๐‘œ๐‘™๐‘ข๐‘ก๐‘–๐‘œ๐‘›

12. Find the Vertical Asymptotes: ๐‘“(๐‘ฅ) =(๐‘ฅ+6)(๐‘ฅโˆ’2)

(๐‘ฅโˆ’3)(๐‘ฅ+4)

a. โˆ’6 ๐‘Ž๐‘›๐‘‘ 2 b. 6 ๐‘Ž๐‘›๐‘‘ โˆ’ 2

c. โˆ’3 ๐‘Ž๐‘›๐‘‘ 4 d. 3 ๐‘Ž๐‘›๐‘‘ โˆ’ 4

13. Identify the Domain: ๐‘“(๐‘ฅ) =(๐‘ฅโˆ’2)(๐‘ฅ+2)

(๐‘ฅโˆ’2)(๐‘ฅโˆ’1)

a. (โˆ’โˆž, โˆ’2) โˆช (โˆ’2, โˆ’1) โˆช (โˆ’1, โˆž) b. (โˆ’โˆž, 1) โˆช (1, 2) โˆช (2, โˆž)

c. (โˆ’โˆž, โˆ’1) โˆช (โˆ’1, โˆž) d. (โˆ’โˆž, โˆ’2) โˆช (โˆ’1, โˆž)

14. Which Rational Function has 2 Holes and 1 Vertical Asymptote?

a. ๐‘“(๐‘ฅ) =(๐‘ฅ+3)(๐‘ฅโˆ’1)(๐‘ฅ+1)

(๐‘ฅโˆ’1)(๐‘ฅ+3)(๐‘ฅ+2) b. ๐‘“(๐‘ฅ) =

(๐‘ฅ+2)(๐‘ฅโˆ’7)(๐‘ฅ+3)

(๐‘ฅ+2)(๐‘ฅโˆ’5)(๐‘ฅโˆ’1)

c. ๐‘“(๐‘ฅ) =(๐‘ฅโˆ’2)(๐‘ฅ+1)(๐‘ฅ+5)

(๐‘ฅโˆ’5)(๐‘ฅ+2) d. ๐‘“(๐‘ฅ) =

(๐‘ฅ+5)(๐‘ฅโˆ’3)(๐‘ฅ+1)

(๐‘ฅโˆ’3)(๐‘ฅ+1)

15. Find the x-intercept values: ๐‘“(๐‘ฅ) =๐‘ฅ2โˆ’5๐‘ฅ+6

๐‘ฅ2โˆ’4๐‘ฅโˆ’5

a. โˆ’3 ๐‘Ž๐‘›๐‘‘ โˆ’ 2 b. โˆ’5 ๐‘Ž๐‘›๐‘‘ 1

c. โˆ’1 ๐‘Ž๐‘›๐‘‘ 5 d. 2 ๐‘Ž๐‘›๐‘‘ 3

16. Find the y-intercept value: ๐‘“(๐‘ฅ) =๐‘ฅ2+4

๐‘ฅโˆ’2

a. โˆ’2 b. 2

c. โˆ’1 d. 1

2

Page 5: Math 110 Practice Final Exam - sga.utm.edu

17. Find the equation of the Horizontal Asymptote: ๐‘“(๐‘ฅ) =3๐‘ฅ2+4๐‘ฅโˆ’9

2๐‘ฅ3โˆ’2๐‘ฅ2+5๐‘ฅโˆ’1

a. ๐‘ฆ =3

2 b. ๐‘ฆ = 1

c. ๐‘ฆ = 0 d. ๐‘๐‘œ ๐ป๐‘œ๐‘Ÿ๐‘–๐‘ง๐‘œ๐‘›๐‘ก๐‘Ž๐‘™ ๐ด๐‘ ๐‘ฆ๐‘š๐‘๐‘ก๐‘œ๐‘ก๐‘’

18. Find the equation of the Oblique Asymptote: ๐‘“(๐‘ฅ) =โˆ’3๐‘ฅ3+๐‘ฅ2+2๐‘ฅโˆ’6

๐‘ฅ2โˆ’2๐‘ฅ+1

a. ๐‘ฆ = โˆ’3๐‘ฅ โˆ’ 5 b. ๐‘ฆ = โˆ’3๐‘ฅ + 7

c. ๐‘ฆ = 3๐‘ฅ โˆ’ 7 d. ๐‘๐‘œ ๐‘‚๐‘๐‘™๐‘–๐‘ž๐‘ข๐‘’ ๐ด๐‘ ๐‘ฆ๐‘š๐‘๐‘ก๐‘œ๐‘ก๐‘’

19. Identify the equation based on the graph:

a. ๐‘“(๐‘ฅ) =(๐‘ฅ+1)(๐‘ฅโˆ’7)(๐‘ฅ+2)

(๐‘ฅ+1)(๐‘ฅโˆ’3) b. ๐‘“(๐‘ฅ) =

(๐‘ฅโˆ’1)(๐‘ฅ+7)(๐‘ฅ+2)

(๐‘ฅ+2)(๐‘ฅโˆ’3)

c. ๐‘“(๐‘ฅ) =(๐‘ฅโˆ’1)(๐‘ฅโˆ’7)(๐‘ฅโˆ’2)

(๐‘ฅโˆ’2)(๐‘ฅ+3) d. ๐‘“(๐‘ฅ) =

(๐‘ฅ+1)(๐‘ฅโˆ’7)(๐‘ฅ+2)

(๐‘ฅ+2)(๐‘ฅโˆ’3)

20. Solve: ๐‘ฅ + 3 = โˆš14๐‘ฅ โˆ’ 6

a. โˆ’3 ๐‘Ž๐‘›๐‘‘ โˆ’ 5 b. 3 ๐‘Ž๐‘›๐‘‘ 5

c. 3 d. ๐‘๐‘œ ๐‘†๐‘œ๐‘™๐‘ข๐‘ก๐‘–๐‘œ๐‘›

21. Solve: |2๐‘ฅ โˆ’ 9| = 7

a. 1 & 8 b. 8 & โˆ’ 8

c. 1 & โˆ’ 1 d. โˆ’1 & โˆ’ 8

Page 6: Math 110 Practice Final Exam - sga.utm.edu

22. Solve:

4|2๐‘ฅ โˆ’ 9| + 7 = 3

a. 4 & 5 b. 4 & โˆ’ 5

c. โˆ’4 & โˆ’ 5 d. ๐‘๐‘œ ๐‘†๐‘œ๐‘™๐‘ข๐‘ก๐‘–๐‘œ๐‘›

23. George has $5000 to invest in an account which compounds weekly at 3.8%. If he needs

$7250, how long will he need to leave his money invested? ๐ด = ๐‘ƒ (1 +๐‘Ÿ

๐‘›)

๐‘›๐‘ก ๐‘œ๐‘Ÿ ๐ด = ๐‘ƒ๐‘’๐‘Ÿ๐‘ก

a. 508.6 ๐‘ฆ๐‘’๐‘Ž๐‘Ÿ๐‘  b. 9.7 ๐‘ฆ๐‘’๐‘Ž๐‘Ÿ๐‘ 

c. 39.3 ๐‘ฆ๐‘’๐‘Ž๐‘Ÿ๐‘  d. 17.5 ๐‘ฆ๐‘’๐‘Ž๐‘Ÿ๐‘ 

24. The bank currently offers monthly interest at 5.4%, and George has $1200 to invest. How much

money will be in his account at the end of 6 years? ๐ด = ๐‘ƒ (1 +๐‘Ÿ

๐‘›)

๐‘›๐‘ก ๐‘œ๐‘Ÿ ๐ด = ๐‘ƒ๐‘’๐‘Ÿ๐‘ก

a. $1658 b. $1578

c. $1868 d. $1388

25. Solve:

log2(3๐‘ฅ + 25) + 4 = 8

a. 3 b. 0

c. โˆ’3 d. ๐‘๐‘œ ๐‘†๐‘œ๐‘™๐‘ข๐‘ก๐‘–๐‘œ๐‘›

26. Solve:

log(๐‘ฅ โˆ’ 7) + log(2๐‘ฅ + 3) = log (19)

a. โˆ’3

2 ๐‘Ž๐‘›๐‘‘ 7 b. โˆ’

5

2 ๐‘Ž๐‘›๐‘‘ 8

c. 7 d. 8

Page 7: Math 110 Practice Final Exam - sga.utm.edu

27. Given the Hydronium concentration, find the correct ๐‘๐ป of the substance.

๐‘๐ป = โˆ’ log[๐ป3๐‘‚+]

๐บ๐‘–๐‘ฃ๐‘’๐‘› [๐ป3๐‘‚+] = 3.7 ร— 10โˆ’4.83

a. 3.74 b. 4.83

c. 4.26 d. 5.68

28. A sound has a decibel level of 132. If it takes 5 machines to produce this loudness, find the

intensity of 1 machine.

๐ท = 10 โˆ™ log (5 โˆ™ ๐ผ

10โˆ’12)

๐‘๐‘œ๐‘ก๐‘–๐‘๐‘’: 5 times the intensity is because we needed 5 machines to produce the loudness.

a. 3.1698 b. 15.8489

c. 1.58 ร— 1013 d. 12.6990

29. An organism in a polluted water sample is recognized as active. Measurement #1 showed 187

organisms as active. 3 hours later, Measurement #2 showed 123 organisms as active. Find the

rate of decay for this population in this polluted environment.

๐‘ฆ = ๐‘๐‘’๐‘Ÿ๐‘ก

a. โˆ’0.2193 b. โˆ’0.5207

c. โˆ’0.1396 d. โˆ’0.6578

30. We want a colony to double in 36 months. What rate of growth should we hope to have?

๐‘ฆ = ๐‘๐‘’๐‘Ÿ๐‘ก

a. 0.1980 b. 0.1792

c. 0.0167 d. 0.0193

Page 8: Math 110 Practice Final Exam - sga.utm.edu

31. Identify the graph which shows the correct intersection of the lines.

{3๐‘ฅ โˆ’ 2๐‘ฆ = 52๐‘ฅ + 3๐‘ฆ = 7

a.

b.

c.

d.

32. Find the point of intersection for the given system of linear equations.

{3๐‘ฅ โˆ’ 4๐‘ฆ = 1

2๐‘ฅ + 3๐‘ฆ = 12

a. (โˆ’1, โˆ’1) b. (5, โˆ’1)

c. (6, 0) d. (3, 2)

Page 9: Math 110 Practice Final Exam - sga.utm.edu

33. Identify the system of nonlinear equations which creates the graph.

a. {3๐‘ฅ2 + 2๐‘ฆ2 = 5

๐‘ฅ2 โˆ’ 3๐‘ฆ2 = 3 b. {

3๐‘ฅ2 โˆ’ 2๐‘ฆ2 = 5

๐‘ฅ2 + 3๐‘ฆ2 = 3

c. {3๐‘ฅ2 โˆ’ 2๐‘ฆ = 5

๐‘ฅ + 3๐‘ฆ2 = 3 d. {

3๐‘ฅ2 โˆ’ 2๐‘ฆ2 = โˆ’5

๐‘ฅ2 โˆ’ 3๐‘ฆ2 = 3

34. Solve the nonlinear system of equations. Find all real points of intersection.

{๐‘ฅ2 + ๐‘ฆ2 = 12

โˆ’๐‘ฅ2 + ๐‘ฆ = 0

a. (โˆš3, 3), (โˆ’โˆš3, 3) b. (3, โˆ’4), (โˆ’3, โˆ’4)

c. (3, โˆš3), (3, โˆ’โˆš3), (โˆ’4, 2), (4, 2) d. (โˆš3, 3), (โˆ’โˆš3, 3), (2, โˆ’4), (โˆ’2, 4)

35. Write the Augmented matrix as a system of equations.

[3 1 โˆ’2 โ‹ฎ 71 โˆ’1 โˆ’3 โ‹ฎ 52 2 0 โ‹ฎ โˆ’3

]

a. {3๐‘ฅ2 + ๐‘ฅ โˆ’ 2 = 7๐‘ฅ2 โˆ’ ๐‘ฅ โˆ’ 3 = 52๐‘ฅ2 + 2๐‘ฅ = โˆ’3

b. {

3๐‘ฅ + ๐‘ฆ โˆ’ 2๐‘ง = 7๐‘ฅ โˆ’ ๐‘ฆ โˆ’ 3๐‘ง = 5

2๐‘ฅ + 2๐‘ฆ + ๐‘ง = โˆ’3

c. {

3๐‘ฅ + ๐‘ฆ โˆ’ 2๐‘ง = 7๐‘ค๐‘ฅ โˆ’ ๐‘ฆ โˆ’ 3๐‘ง = 5๐‘ค2๐‘ฅ + 2๐‘ฆ = โˆ’3๐‘ค

d. {

3๐‘ฅ + ๐‘ฆ โˆ’ 2๐‘ง = 7๐‘ฅ โˆ’ ๐‘ฆ โˆ’ 3๐‘ง = 52๐‘ฅ + 2๐‘ฆ = โˆ’3

Page 10: Math 110 Practice Final Exam - sga.utm.edu

36. Solve the system of equations.

{

8๐‘ฅ + 2๐‘ฆ โˆ’ 5๐‘ง = โˆ’13๐‘ฅ + 2๐‘ฆ + 3๐‘ง = โˆ’4โˆ’5๐‘ฅ + 4๐‘ฆ + ๐‘ง = 8

a. (1, 1, โˆ’1) b. (โˆ’1, 1, 1)

c. (โˆ’1, 1, โˆ’1) d. (1, โˆ’1, 1)

37. Identify the type of system:

{4๐‘ฅ + 1๐‘ฆ = 5

8๐‘ฅ + 2๐‘ฆ = 10

a. Dependent b. Inverse

c. Consistent d. Inconsistent

38. Given the reduced matrix, write the solution:

[1 0 1 โ‹ฎ 10 1 1 โ‹ฎ 00 0 0 โ‹ฎ 4

]

a. (1 โˆ’ ๐‘ง, โˆ’๐‘ง, ๐‘ง) b. (1, 0, 4)

c. (1 โˆ’ ๐‘ง, โˆ’๐‘ง, 4) d. ๐‘๐‘œ ๐‘†๐‘œ๐‘™๐‘ข๐‘ก๐‘–๐‘œ๐‘›

39. Given the reduced matrix, write the solution:

[1 0 3 40 1 โˆ’1 00 0 0 0

]

a. (โˆ’3๐‘ง + 4, ๐‘ง, ๐‘ง) b. (4

3, 1, ๐‘ง)

c. (3๐‘ง, โˆ’1๐‘ง, 4๐‘ง) d. (๐‘ง, ๐‘ง, ๐‘ง)

Page 11: Math 110 Practice Final Exam - sga.utm.edu

40. The table shown represents 3 peopleโ€™s trips to the concession stand at a baseball game. Use the

information to determine the price of one hotdog.

Hotdogs Cokes Pretzels Total spent

Sally 4 6 2 $26.80

Bink 6 3 1 $22.80

Roana 2 4 8 $28.80

a. $1.88 b. $2.28

c. $2.15 d. $2.35

41. A volleyball team paid $5 for a pair of socks and $17 for a pair of shorts. Last year, the total bill

was $315. This year, they purchased the same number of socks and shorts, but the total was

$342. Socks are now $6 a pair and shorts are $18 a pair. How many pairs of shorts did the team

buy? (Hint: try to set up a table like the one above)

a. 12 b. 15

c. 21 d. 8

42. Identify the system of inequalities that creates the feasible region shown:

a. {

๐‘ฅ + 3๐‘ฆ โ‰ค 198๐‘ฅ + ๐‘ฆ โ‰ค 73

โˆ’๐‘ฅ + 7๐‘ฆ โ‰ค โˆ’16๐‘ฅ โ‰ฅ 2

b. {

โˆ’๐‘ฅ โˆ’ 3๐‘ฆ โ‰ค 198๐‘ฅ + ๐‘ฆ โ‰ฅ 73

๐‘ฅ โˆ’ 7๐‘ฆ โ‰ค โˆ’16๐‘ฅ โ‰ฅ 2

c. {

โˆ’๐‘ฅ + 3๐‘ฆ โ‰ค 198๐‘ฅ + ๐‘ฆ โ‰ค 73

โˆ’๐‘ฅ โˆ’ 7๐‘ฆ โ‰ค โˆ’16๐‘ฅ โ‰ฅ 2

d. {

โˆ’๐‘ฅ + 3๐‘ฆ โ‰ค 198๐‘ฅ + ๐‘ฆ โ‰ฅ 73

โˆ’๐‘ฅ โˆ’ 7๐‘ฆ โ‰ฅ โˆ’16๐‘ฅ โ‰ฅ 2

Page 12: Math 110 Practice Final Exam - sga.utm.edu

43. Use the optimizing function to Minimize the feasible region created by the system:

{๐‘ฆ โ‰ค 5๐‘ฅ โ‰ฅ 2

โˆ’๐‘ฅ + ๐‘ฆ โ‰ฅ โˆ’1

๐‘ง = 8๐‘ฅ โˆ’ 2๐‘ฆ

a. 22 b. 38

c. 14 d. 6

44. The matrix simplification is not possible because _____.

[1 5 42 9 7

] + [8 91 30 2

]

a. Adding inverse matrices is wrong and causes mass destruction of sanity.

b. Addition is only possible when both matrices are perfectly square.

c. The number of rows of the first matrix do not match the number columns of the second matrix.

d. Both matrices must be exactly the same size in order to add them together.

45. Simplify the Matrix Expression:

2 [3 41 โˆ’1

] [32

]

a. [6 122 โˆ’2

] b. [342

]

c. [24 12] d. Not Compatible

46. The inverse of this matrix is impossible to compute because ______.

[3 โˆ’42 6

โˆ’1 5]

a. All entries must be positive values. b. The matrix must be square.

c. This matrix is too big. d. All entries must be 0 ๐‘œ๐‘Ÿ 1 ๐‘œ๐‘Ÿ โˆ’ 1.

Page 13: Math 110 Practice Final Exam - sga.utm.edu

47. Compute the inverse of the matrix:

๐ด = [1 0 00 โˆ’1 0

โˆ’1 0 1]

a. [1 0 00 โˆ’1 01 0 1

] b. [โˆ’1 0 00 1 01 0 โˆ’1

]

c. [1 0 00 โˆ’1 01 0 โˆ’1

] d. [1 0 00 1 0

โˆ’1 0 โˆ’1]

48. Given the matrix equation, solve for ๐‘‹: ๐ด๐‘ฅ = ๐‘

a. ๐‘ฅ = ๐‘/๐ด b. ๐‘ฅ = ๐ดโˆ’1๐‘

c. ๐‘ฅ = ๐‘โˆ’1๐ด d. ๐‘ฅ = ๐‘๐ดโˆ’1

49. Given the matrix equation, solve for ๐‘‹:

๐ด = ๐‘‹๐ถ when ๐ด = [5 72 3

] ๐‘Ž๐‘›๐‘‘ ๐ถ = [2 31 1

]

a. [2 โˆ’10 1

] b. [2 11 0

] c. [1 21 1

] d. [โˆ’1 21 โˆ’1

]

50. Write the system of equations as a Matrix Equation:

{5๐‘ฅ โˆ’ 3๐‘ฆ + 7๐‘ง = 12

๐‘ฅ โˆ’ ๐‘ฆ = 2๐‘ฆ + 8๐‘ง = 9

a. [5 โˆ’3 7 121 โˆ’1 0 20 1 8 9

] b. [5 โˆ’3 71 โˆ’1 00 1 8

] [๐‘ฅ๐‘ฆ๐‘ง

] = [1229

]

c. [๐‘ฅ๐‘ฆ๐‘ง

] = [5 โˆ’3 71 โˆ’1 00 1 8

] [1229

] d. [๐‘ฅ๐‘ฆ๐‘ง

] = [5 โˆ’3 71 โˆ’1 00 1 8

]

โˆ’1

[1229

]

Page 14: Math 110 Practice Final Exam - sga.utm.edu

Answer Key:

1 D

2 D

3 C

4 B

5 C

6 B

7 C

8 B

9 A

10 D

11 B

12 D

13 B

14 A

15 D

16 A

17 C

18 A

19 D

20 B

21 A

22 D

23 B

24 A

25 C

26 D

27 C

28 A

29 C

30 D

31 C

32 D

33 B

34 A

35 D

36 C

37 A

38 D

39 A

40 D

41 B

42 C

43 D

44 D

45 B

46 B

47 A

48 B

49 B

50 B