management aptitude test 13 nov

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MANAGEMENT APTITUDE TEST

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MANAGEMENT APTITUDE TEST

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If the length of the largest straight rod that can be put inside a cuboid is 10 m, then the surface area ofthe cuboid cannot be more than

• The largest such size will be close to cube. So we will solve for cube.

• Thus 10 = sqrt (3) * A, where A = side

• A = 10/(sqrt(3)) = 5.77 approx.

• Thus surface area = 6 * square of 5.77

• =200 answer.


A & B start walking in opposite directions. A covers 3 km, B covers 4 km. A turns right and walks 4 km

while B turns left andwalks 3 km.,How far is each from

the starting point?


Solution

• From the start each of them is distant as under :

• Solve by using pythogorus rules

• Sqrt ( 3^2 +4^2) = sqrt (9+16) = sqrt (25)

• = 5 answer.


a queue of children, Goti is fifth from the left and

Monu is sixth from the right. When they interchange their seats among

themselves, Goti becomes thirteenth from the left., what will be

Monu’s position from the right?


Solution

• From Monu, we have 5 persons in the right and 12 in the left. Thus there are 12+5+1 = 18 persons in all. Monu now shifts to the place where Goti was sitting earlier. Thus his place is 18 – 4 = 14th from the right (because Goti was 5th from left).


Which is the logical conclusion?

• Statement.:

• A : All goats are parrots.

• B : All parrots are crows.

• Conclusions:

• I : All crows are goats.

• II: All goats are crows.


Solution

• As we can see that all goats are parrots, who are crows thus all goalts are crows.

• Thus conclusion no. 2 is the valid conclusion. Answer

GOATS

PARROTS

CROWS


WHICH IS THE RIGHT CONCLUSION ?

• Statements:

• Some kites are horses.

• All horses are dogs.

• Conclusions

• A. All dogs are horses.

• B. Some dogs are horses.


SOLUTION

• THERE IS SOME COMMON AREA IN KITES AND HORSES. ALL HORSES ARE DOGS, BUT REVERSE IS NOT TRUE. Thus Some dogs are horses is the only right logic.

KITESHORSE

DOG


ASSUMPTION - INFERENCE

• A highly cohesive work group is a prerequisite for high team performance. Sociologists point that the association between group cohesion and success is owing to the support individual team members give to one another and their acceptance of the groups goals and activities.

• READ THE ASSUMPTIONS AND FIND THE BEST ONE :


WHICH STATEMENT WILL WEAKEN THE INFERENCE OF THE PREVIOUS STATEMENT

• (a) A group of Japanese researchers found that successful work teams were headed by dominant leaders.

• (b) University researchers found that there was a significant correlation between team productivity and the extent to which the team members understood and complied with the groups objectives.

• (c) American researchers found that successful team members tended to rate their fellow members more favourably

• (d) Industrial psychologists in UK found that work groups who tended to participate in after hours social activities were more productive


ANSWER

• Statement No. A. will weaken the inference.


WHICH IS VALID ASSUMPTION?

• If a person reads a lot, he will increase his• vocabulary. • (A) Strong vocabulary is important for writing

and speaking• (B) People should read books containing

unfamiliar words• (C) The books to be read should be entertaining• (a) A only (b) B only• (c)Conly (d)A,BandC


SOLUTION

• Although all the statements are correct – because reading unfamiliar books will help you in preparing vocabulary and reading entertaining books will help you in building vocabulary. But these statements are not assumptions (they are not implicit). Only statement A is implied therefore this is valid assumption. Answer.


Which is valid conclusion?

• Kap humiliated Sachin in the presence of his colleagues.

• Conclusions:

• I. Kap did not like Sachin.

• II. Sachin was not popular with his colleagues.

Solution:

Only Ist statement is valid conclusion .


Sentence improvement

• If’ they cooperate together by dividing up the work they shall be over with the work faster.

• (a) if they cooperate together by dividing the work

• (b) if they cooperate by dividing up the work• (c) if they cooperate by dividing the work• (d) if they cooperate together by division of

work


Solution

• Cooperation does not require together and dividing doesnot require up therefore the answer is C.



• The war victims needed nurses to bandage their wounds badly.

• (a) The war victims needed nurses to bandage their

• wounds badly• (b) The victims of war needed nurses to

bandage their wounds badly• (c) The war victims badly needed nurses to

bandage their wounds• (d) The war victims needed nurses badly

for bandaging their wounds


Solution

• C is the best choice.



• British Airspace has been focusing on building European links.

• (a) concentrating on creating european links

• (b) focusipg on forging european links

• (c) stressing on building european connectivity

• (d) stressing on building European links


Solution

• Concentrating is better option in comparison to focussing and creating is better option in comparison to building. So A option is the best option.


Which is the best analogy?

• PLANT : PARASITE::• (a) Transient: Permanent• (b) Wild : Prey• (c) Flora : Fauna• (d) Sailor : Pirate• Solution : • Parasites damages plants, similarly pirates

damage / loot the sailor. So answer is D.



• MINER QUARRY::• (a) Carpenter: Saw• (c) Poet: Sonnet• (b) Painter: Brush• (d) Sculptor : Atelier• Solution: miner works in a quarry (mine). • Similarly sculptor works in atelier, thus

best option is d.



• CHATTER;TALK::

• (a) Scurry: Move

• (c) Limp : Walk

• (b) Sleep : Drowse

• d) Chant : Sing

• Solution : Talk is milder version of Chatter. Similarly move is milder version of scurry. Thus answer is A.



• TRAITOR: COUNTRY• (a) Potentate : Kingdom• (b) Bureaucrat: Government• (c) Apostate : Religion• (d) Tailor : Law• Solution: • Traitor gives treachery to the country,

similarly apostate does to his religion. So answer is C.



• MONEY : BANK

• (a) Fear : Tremble (c) Sound: Music

• (b) Arrows : Quiver (d) Coin: Mint

• Solution :

• Money is kept in bank similarly, arrows are kept in quiver. So answer is B.



• GREENHOUSE : PLANT::• (a) Incubator: Infant• (b) Hen house : Chicken• (c) Hive : Bee

• Solution: Greenhouse is a place where plants are nurtured. Similarly incubator is a place where infant is nurtured. So answer is A.



• INSINUATE : CHARGE::

• (a) Say: Deny (c) Hint :Affirm

• (b) Refer: Reject (d) Charge : Pardon

• Solution:

• (c ) insinuate is a mild charge. Hint is to give a mild affirmation.


Which is the best option?

• NUCLEUS: CELL::

• (a) Rind : Melon (c) Stalk: Corn

• (b) Web: Spider (d) Yolk: Egg

• Solution

• (d) is the best option.


Comprehension – what is the basic focus of the writer?

• It is the avant-garde of the litigant spirit that is most unsettling. If one can blame the Government for a lightning strike and a corporation for a wind gust, it is easy to imagine tracking almost any mishap to some distant agency. Should owners of property on which there is a public passage way prohibit barefoot pedestrians or else assume liability for every stubbed toe? Must the manufacturer of a knife clearly label it as dangerous or else be vulnerable to damages for a kitchen worker’s sliced finger? Could the designer of a dam be blamed if a voluntary swimmer in a lake thus created?


Solution

• The main theme of the author is to talk about issues which may create litigation and the author is critical of (unnecessary) litigation spirit.


Describe ozymandias?

• I met a traveller from an antique land.• Who said: “Two vast and trunldess legs of stone• Stand in the desert. Near them on the sand,• Half sunk, a shattered visage lies, whose frown• And wrinkied lip and sneer of cold command• Tell that its sculptor well those passions read• which yet survive, stamped on those lifeless things,• The band that mocked them and heart that fed.• And on the pedestral these words appear:• ‘My name is Ozymandias, king of kings:• Lock on my works, ye mighty, and despair!’• Nothing beside remains, round the decay.


Solution

• He believes that he is very mighty. He is suffering from megalomania.


Fill in the blank

• The orator was so soporific that the audience became ______

• (a) elated (b) drowsy

• (c) affable(d) riotous

• Solution:

• Soporific = which creates sleep. Thus (B) is the best option.


Fill in the blank

• The columnist was very gentle when he mentioned his friends, but he was bitter and even ______ when he discussed people who irritated him.

• (a) acerbic (b) remorseful

• (c) stoical (d) laconic

• Solution:

• (a) matches with bitter here.


Fill in the blank

• A - - -- - analysis of these substances will show that they differ - - -

• (a) random— minutely (b) detailed— essentially

• (c) careful— completely (d) final— Structurally

• Solution .

• (c ) is the best option.


Fill in the blank..

• As - - - head of the organisation, he attended social functions and civil meetings, but had no - - - in the formulation of company policy.

• (a) hypothetical— vote (b) titular— voice (c) nominal— competition (d) former— pride

• Solution : (b) is the best option.


Fill in the blank

• The perpetual spinning of particles is much like that of a top, with one significant difference, unlike the top, the particles have no need to be wound up, for --- - - - is one of their -- - - - - properties.

• (a) revolution— radical (b) rotation— intrinsic (c) motion— intangible (d) acceleration— hypothetical

• Solution:• (b) is the best option.


What is the sum of digits of number (10^500 - 123456789)

1. 44472. 4457

3. 44674. 4465

5. 4456


• Look at options and solve it. As we deduct 123456789, the last few values left are 999876543211. as we can see that these values have been reduced by 123456789 so their reduction is by 45. thus 45 – 1 (which is there is 10) = 44 should be additive identity. Only option 4456 gives the answer. (4456+44 gives 4500,which is round number). Thus answer is 4456.


A, B, C purchase 100, 150 & 250 toffees from wholesaler for a total

of Rs. 300, Rs. 375 & Rs. 500 respectively. In this process

wholesaler earned p% & q% profit from A & C where p=3q. How much

profit did the wholesaler make in this transaction with B?

• 1. 67% 2. 33% 3. 25%

• 4. 100% 5. None of these


Solution

• Let us assume p = 30 and q = 10 • Sale price of first (assume cost 100) =130• Sale price of c = 110 • 130 – 110 = 20 which is 2Q• Solution : • Sale price of 100 tofees = 3 per tofee• That of 250 tofees = 2 per tofees• Difference = 3-2 = 1 rupee = 2Q• P = 3q or P – q = 2q. • Thus q = .5. cost of one toffee = 1.5 per tofee


Solution continued . .

• Cost of b toffee

• = 150 * 1.5 = 225.

• Sale price = 375

• Profit = 375 – 225 = 150 or rupee 1 per tofee.

• 150/225*100 = 66.7% answer.


A shopkeeper give one scientific calculator free with five mobile phones, which in other words is

giving 20% discount on the sale of mobile phones. Then what is the percentage of

difference between two scientific calculator and a mobile?

(1) ±42% (2) ± 52%(3) ± 60% (4) ± 62%

(5) ±70%


Solution

• Let us assume that one mobile costs Rs. 100. thus 5 mobile costs Rs. 500 we can give discount of 20% which is 100. Thus the final price is 400

• Price of one calculator is Rs. 100 (equal to the discount). We take 2 calculator as = 200. The final price of one mobile is Rs. 80. thus difference is 120. 120/200 *100 = 60% answer.


11 hockey players are to be selected out of 16 players. Team must have 1 goal keeper, 5

defenders & 4 forwards. Out of 16,2 are goal keeper, 9 forward & remaining are defenders. Find now many ways can a team he selected?

2256 252256 108 112 308


Solution

• There are 2 goal keepers out of whom 1 has to be selected so we have 2 options here.

• We have to select not 4 but 5 forwards out of 9, so solution: 9c5 = 126

• We have to select 5 defenders out of 5, so we have only one choice.

• Thus total choices: 2X 126X1 = 252 answer.


There are 2 trains moving in opposite direction. They are of

equal length. Their speeds are also 90 KM per hour each. They 1

minute to cross each other. What is the length of each of these trains?


Solution

• Speed of 1 train : 90• Speed in meters / per second = 90*5/18• =25 meters per second. • The combined speed is 50 meters per

second. • Thus the two trains have taken 60

seconds and have travelled : 60*50=3000• Thus length of one train = 1500 meters.

(each).


Ram Kap and goti start business with equal capital. Ram double the money every month. Kap trible the

capital every quarter and goti quadruple the capital every 6

month. What is their profit sharing ratio at the end of the year?


Solution

• Their capital ratio comes to :

• 4095:120:84 answer.


3/4 th of 68 is less than2/3 of 114 by?

• ¾ *68 = 3*17 = 51

• 2/3 *114 = 2*38 =76

• Their difference is 25 answer.


LCM and HCF of 2 numbers are 84 and 21 respectively. If the ratio of the two numbers is 1:4, the larger

number is ? • The two numbers are X and 4X.

• Let take factorisation of 84 and 21.

• Factorisation of 84 = 2*2*3*7

• Since HCF is 21, the numbers are 21 and 84 answer.


1/3rd of a number is 3 more than 1/4th of the number, what is the

number?

• Let us assume the number to be X.

• X/3 – X/4 = 3

• (4X – 3X ) / 12 = 3

• X = 36 Answer.


If 1/8th of a pencil is black, half of the remaining is yellow and

remaining 3.5 CM is blue, what is the total length of the pencil?

• Let us assume the length of the pencil to be 16 CM . 2CM is black. 7 CM is yellow. 7CM is blue. Thus if 7CM is blue, total length is 16, if 3.5 CM is blue, the total length is 16/7*3.5 = 8 CM Answer.


What is the next number in the sequence: 5,25,50,250,500?

• Let us first multiply a number by 5 and then multiply by 2 and so on. Thus we are able to get 2500 as the next number.


What is the value of (1/4)^-(1/2)?

• Let us first solve or – sign. We get 4^(1/2)

• We know the answer now = 2*2 =4 so the answer is 2


How many 5 digit multiples of 11 are there, If the 5 digits are

3,4,5,6,7?

• We have only 5 digits, which we can interchange. The total of these numbers is 25. for 11 to divide the difference of the alternate groups of numbers must be either 0 or 11. (25-11) = 14, dividing it in 2 parts, we get 7,7. thus alternate totals must be 7 and 18.

• Thus possible numbers are: 53647. We can inter-change 5,6,7 and also 3 and 4.

• Thus 3! *2! = 12 is the answer.


What will be the remainder when we divide 9^6+7 by 8?

• we can solve it as (1^6 +7)/ 8

• (because when we divide 9 by 8, the remainder is 1.).

• Thus the remainder is 0. Answer.


In a bill the accountant transposed rupee for paise and vice versa. The

actual invoice amount was 5.42 more than 6 times of the bill. What

were the original invoice & bill amount?

• Options: (a) 44.06 and 6.44 (b) 18.25 and 25.18

• Solution try options and solve it?


Solution

• 6.44 * 6 = 38.64

• Add 5.42 in this.

• We get + 44.06. Thus this is the right answer.


6 workers can make 270 units per minutes (together) How many units

can be made by10 workers for every 4 minutes.

• 270/6 *10 *4 = 1800


Sumit buys every year Bank s cash certificates of value exceeding the last year’s purchase by Rs. 300. After 20 years, he finds that the

total value of the certificates purchased by him is Rs. 83,000. Find the value of the certificates

purchased by him in the 13th year.


Solution

• Sum = n/2 (2a + (n-1)d)

• =20/2 (2a + 19*300) = 83000

• 2a + 5700 = 8300

• 2a = 2600

• A = 1300.

• Thus 13th investment was : (A + 12 D)

• = 1300 + (12*300) = 4900 answer.


BM started from his house one morning in a hurry. While moving out he looked at the mirror image of a wall clock. The clock had no number on its dial. It took him 10 minute to reach his office and then only he realised

his mistake as he could recollect that the time he saw while leaving home was exactly one hour behind that shown by the clock at ilie office. What was the time by the clock in

his office?Options: 5:25, 5:35,6:25, 6:35

answer: 6.35 answer.


In a showroom there is ‘Buy 2 Get Some Free” offer. The number of free shirts (of same type) is to be decided by tossing a

coin, on which numbers 2 and 3 are written on its sides. The number of free shirts is equal to the number that appears after tossing the coin. By how much percent

more than the cost price the selling price of a shirt is kept so that the showroom dealer

must not incure any loses?


Solution

• Let us assume that the cost of one shirt is 100.

• Expected value = 2 *.5 + 3*.5 = 2.5

• Thus when he sells for 200, his cost is 450. he gets 225 per shirt.

• He must keep at least 125% above the cost to ensure no profit no loss.


What is the maximum number of soaps that can be produced in a

day?• A factozy uses two

machines, M1 and M2 to manufacture three types of soap, P, Q & R. The efficiency of the two machines with respect to the three types of soap is given in the table below. The numbers indicate the time taken (in min.) by the two machines to manul.lcture one unit each of the three types of soap.


Solution

• Let us assume that machine works for 12 hours. Machine M1 will make P (because the required is minimum) and M2 will make Q. Thus total production is :

• (12*60)/8 = 90

• (12*60)/9 = 80

• Thus they will make total 170 soaps.


If X is 90% of Y. what % of X is Y?

• Let us assume Y = 100

• X = 90

• Thus y = 100/90 *100 = 111% answer.


If X is 90% of Y. Y is 90% of Z what % of X is Z?

• Let us start with Z. Z is 100, Y is 90. Now being being 90, X is 90% of Y, thus X is 81.

• Z is 100/81*100 = 123.45 % of X. answer.


At what rate percent per annum will a sum of money doubles

itself in 12 years?(SI)

• This is a question on simple interest (SI)

• We have 100 rupees now and we want 100 more in next 12 years. Thus annual interested expected is 100/12=8.33 approx. per annum answer.


At what rate percent per annum will a sum of money doubles

itself in 12 years?(CI)

• This is a question of compound interest.

• Let us assume that the amount is X.

• 100 (1+R)^12 = 200

• (1+R)^12 = 2

• Therefore the rate is 5.9% per annum.


the simple interest on a certain sum is 9/16 of the sum. Find

the rate percent and time, if both are equal.

• Let us assume that sum is 16. interest will be 9.

• PRT / 100 = I (p=principal,R=rate,T=time).

• 16*R^2 / 100 = 9 (R = T)

• R^2 = 900/16

• R = 30 / 4 or 7.5% per annum answer.


A sum when reckoned at simple interest at 3 per annum

amounts to Rs.364.80 after 4 years. Find the sum.

• Let us assume that the amount was Rs. 100.

• As per question : 100*3*4/100 = 12 or the amount becomes 112.

• Thus sum was 100/112 *364.8=325 (approx.)


Amount = Rs 1110, Time = 100 days, Rate = 5% p.a. what is

simple interest?

• 1110*100/365 *5/100

• =15.2 Rupees.


A is 20% more that B and B is 10% more than C. A is what % more

than C?

• Let us assume C = 100. B is 110. thus A is 120/100 *110 = 132.

• A = 132, C = 100.

• Thus A is 32% more than C. Answer.


Goti spends 30% of his pocket money and has $210 left. How

much did he get as pocket money?

• Money left out is 70%.

• 100/70 *210 = 300$


The average age of the boys in a class of 20 boys is 15.6

years. What will be the average age if 5 new boys come

whose average age is 15.4 years?

• Average = Total / Number

• Total of 20 = 312. total of 5 = 77

• Total of 25 = 389

• New average = 389/25= 15.56 answer.


A sum of Rs.10,000 deposited at compound interest becomes double after 5 years. After 20 years, how

much will it become?

• Let us assume that money doubles in 5 years, from 1 we get 2 in 5 years, 4 in 10 years, and 8 in 15 years, and 16 in 20 years. Thus this amount will become 160000 in 20 years.


A sum of Rs.5000 was taken as a loan. This is to be paid in two equal installments. If the rate of interest is

20% compounded annually, then what is the value of each

instalment?

• Let us assume that there are 2 instalments of X amounts. Thus discounting them will give 5000.

• X /(1.2 )+ X / 1.44 = 5000


Solution

• X /(1.2 )+ X / 1.44 = 5000

• 2.64X = 5000*1.2*1.44

• X = (5000*1.2*1.44)/2.64

• =3272.7 ANSWER.


—If a certain sum is doubled in 8

years on simple interest,then in how many years will it be

four times?

• Let us assume that Rs 100 becomes 200 in 8 years. Thus this money generates 100/8 = 12.5 per annum of interest

• We have to generate interest of Rs. 300 on Rs. 100 years. Thus years will be : 300/12.5 = 24 years. Answer.


A testator bequeathed by will 2/5 of his estate to his son,

‘’60% of the remainder to his daughter and the remainder to‘his widow, the son got Rs.750 more than the daughter. Howmuch did the widow receive?

• Let us assume that the total amount was Rs. 500. Son got 200 and daughter got 180. thus the difference was only 20.


• If the difference is 20, the total amount

• is

• 500/20 * 750

• 18750 is the total amount.

• Share of widow : 18750*3/5 *40/100

• Thus the widow got. Rs. 4500 answer.


A’s mother is sister of B and has a daughter C. How, can A be related

to B from among the following?

• (a) Niece (b) Uncle

• (C) Daughter (d) Father

• (a)


Anil, introducing a girl in a party, said, She is the wife of the

grandson of my mother. How is Anil related to the

girl?

• Father in law.


A man said to a woman, Your mother’s husband’s sister is my

aunt. How is the woman related to the man?

(a) Grand daughter (b) Daughter(c)Sister(d) Aunt

• Sister


Showing a lady in the park, . Sumit said, ‘She is the daughter of my grandfather’s only son’. How is

Sumitrelated to that lady?(a) Father (b) SonBrother (d) Mother

• Brother


Puzzle

• (a) A x B means A is the brother of B.• (b) A + B means A is the mother of B.• (c) A ÷ B means A is the son of B.• (d) A — B means A is the husband of B.• Which of the following would mean M is

the father of N: (a) M ÷ N +0• (b) M x 0- N (c)M+0 ÷ N• (d)M-0+N


Solution

• Option D gives you correct answer.


Puzzle test….

• (1) In a family of six persons : A, B, C, D, E and F there are two married couples.

• (2) D is grand mother of A and mother of B.

• (3) C is the wife of B and mother of F.

• (4) F is the grand daughter of E. What is C to A?


Solution

• Grandmother is D, Grand father is E

• Grandson / grand daughter are A and F.

• Thus C is mother of A. answer.


Proper course of action?

• The exodus from villages, to cities is detrimental to both.

• Courses of Action:• I. Rural postings must be made

mandatory.• I!. There should be fewer trains linking

cities to smaller places.• III. Employment generation scheme should

be launched in rural areas.


Solution

• Only III is the proper course of action.


Which information is sufficient to answer the question?

• Has Smith ever won an award for literature?

• A. Smith won the only award existed during his time

• B. During smith’s time, writing was looked down upon let alone merit an award.


Solution

• Both the statements are not sufficient to answer the question.


Which is an appropriate course of action?

• Every year, at the beginning or at the end of the monsoons we have some cases of conjectivities, but this year,it seems to be a major epidemic witnessed after nearly four years.

Courses of action:• I. Precautionary measures should be taken

after four years to check this epidemic.• II. People should be advised to drink boiled

water


Solution

• Both the course of actions are appropriate and should be immediately taken up.


Which is the most logical idea?

• If an ant were as big as a horse, could it move mountains?

• No. A giant ant . . . . . (select from a,b,c,d)

• (a) Would be a structural failure.

• (b) Would never be able to move mountains.

• (c) Would be a mere curiosity.

• (d) Would never be able to hunt for food.


Solution

• A giant Ant would not be able to move mountains because it is just a curoisity (we are not sure about what could it do). Other options are not logical – as logically we cannot say that it is structural failure or it cannot hunt for food or it cannot move mountains.


Puzzle test…

• Nine cricket fans are watching a match in a stadium. Seated in one row, they are J, K, L, M, N, 0, P, Q and R. L is at the right of M and at third place at the right of N. K is at one end of the row. Q is immediately next to 0 and P. 0 is at the third place at the left of K. J is right next to left of 0.

• Who is sitting in the centre of the row?• (a)L (b)O• (c)J (d)Q


Solution …

• NRMLJOPQK

• J IS IN THE CENTRE


A and B start walking in opposite directions. A covers 3 km and B

covers 4 km. Then A turns right and walks 4 km while B turns left and walks 3 km. How far is each from

the starting point?

• A is 3 KM in one direction and 4 KM in right. Applying pythogorus, we find that A is 5 KM from the starting point. Similarly B is also 5 KM from the starting point. Ans.


Ram walks 10 m south from his house, turns left and walks

25 m, again turns left and walks 40 m, then turns right and. walks 5 m

to reach to school. In which direction the schoolis from his house?

• Draw a map and get the answer = north-east.


In a class of 35 students Kiran is placed 7th from the bottom

whereas Sohan is placed 9th from the top. Mohan is placed exactly in between the two. What is Kiran’s

position from Mohan?

• 10th

• From 9th to the top and 7th to the bottom, we have 21 candidates (35-(6+8) ). Mohan is just in the centre. So from Mohan, Kiran is at 10th place. Answer.


A watch reads 4 If the minute hand points towards the East, in which

direction does the hour hand point?

• The hour hand is towards South West.


Puzzle

• Goti and I started walking towards each other from two places lOO m apart. After walking 30m, Goti turns left and goes lO m, then he turns right and goes 20m then turns right again and comes back to the road and starts walking. If we walk with the same speed, what is the distance between us at this point of time


Solution

• (Goti walks 70 meters in all), so I walk 70 meters towards Goti’s starting point and now I am 30 meters from that. Goti takes only 30+20 meters on the road. Thus Goti is 50 meters from my starting point. Thus there is a gap of 20 meters between me and Goti. Answer.


Sum of 1st to 30th terms of a series in arithmetic

progèssion is 150. if the first term is A, what is 30th term of the series?

• Sum = 30/2 (2a + (29)D) = 150• 2a + 29d =150*2/30 = or 29 D = 10 – 2A • 30th term = A + 29D• 29 D = 10 – 2A, putting the value, we get the answer

= 10 – A answer


Question on number system

• Convert 252 into binary system

• 252 / 2 = 126 / 2 = 63/2 = 31/2 = 15/2 = 7/2 = 3/2 =1 (starting from last remainder to the first)

• 11111100 answer.

• Convert it again to decimal system:

• 1*2^7+1*2^6+1*2^5+1*2^4+1*2^3+1*2^2+0*2^1+0*2^0 = 128+64+32+16+8+4 = 252


Multiply 12 to 13 ( note - both are octal numbers, your outcomes must

also be in octal numbers)?

• Let us first convert them into decimal numbers: 12= 1*8^1 + 2*8^0 =10

• 13 = 1*8^1 + 3*8^0 =11• Now multiply 10 to 11 = 110• Now convert it into octal number: • 110/8 = 13 / 8 • =156 • Test = now convert 156 to decimal number


Convert 156 (octal) to decimal number …..

• 1*8^2 + 5*8^1 + 6*8^0

• =64+40+6

• =110 answer.


Multiply 5 (base 16) to 12 (base 7) and get the outcome in binary?

• (5*16^0 ) * (1*7^1 +2*7^0)

• 5 *9 = 45

• 45/2 = 22/2 = 11/2 = 5/2 =2/2 1

• =101101 answer.


78.8% of a common medicine for stomach-upsets is absolute alcohol;

3.3% of it is mentha oil; 0.07% spear mint oil; and 0.177%

chloroform. How much of each of these compounds is there in a pack

of 30 ml?solution

alchol = 23.6 ml, 1 ml of menthol oil and so. On.


What is the sum of cubes of the first 5 natural numbers?

• Formula

• = [N (N+1)/2 ]^2

• = [5*6 / 2 ]^2

• =225 answer.


What is the sum of squares of the first 13 natural numbers?

• Formula

• =[n(n+1)(2n+1) ] /6

• =(13*14*27)/6

• =819 answer.


In a Class of 80 pupils, the number of boys is three-fifths the number of girls. Determine the number of girls

in the class.

• Let the number of girls be X

• X + 3/5X = 80

• 8/5 X = 80

• X = 80 *5/8

• X = 50 (the number of girls is 50, boys are 30) answer.


The difference between two numbers is 30. On dividing the

greater by the smller the quotient is 3. Find the numbers.

• Let the smaller number be X.

• 3X – X = 30

• 2X =30; X = 15,

• Thus 2 numbers are 15 and 45 answer.


Gunpowder contains 75% nitre and 10% sulphur. The rest of it is

charcoal. What is the amount of charcoal in 9 kg of gunpowder.

• Charcoal is (100 – 75 – 10) = 15%

• 9 KG = 9000 Grams

• 9000*15/100

• =1350 grams answer.


Question on profit

• At what percentage alove the Cost price must an article be marked so as to gain 33% after allowing the customer a discount of 5%?

• (a) 48% (b) 43%

• (c) 40% (d) 38%

• (e) None of the above


Solution …

• Let the cost be 100

• Final price being realised 133

• It is after discount, so price before discount (marked price) is :

• 133*100/95 =140 , so 40 is the answer.


A vertical pole PO is standing at the centre 0 of a square ABCD. If AC

subtends an angle 90° at point P of the pole then the angle subtended

by a side of the squareat Pis

(a) 35° (b) 45°(c) 30° (d) 60°

(e) None of the above


Solution

• When diagonal (in a square) makes angle of 90 degree in a pyrimidical shape, then sides make angles of 60 degree. (rule).

• So answer is 60 degrees.


Find the per cent of pure gold in 22 carat gold, if 24 carat gold is cent

per cent pure gold.

• 22/24 *100

• =91.67 % answer.


In the diagram the two circles pass through each other’s centre. If the radius of each circle is 2, what is

the perimeter of the region marked B?


Solution

• Permieter of one circle is 2/3 now because, it is being cut by other circle.

• Thus 2/3 + 2/3 of perimeters added :

• 2 * 2/3 * (formula of perimeter = 2pi *r)

• =(8 * pi * r) /3 answer.


What is angle C?


Solution

• Angle O is double the angle A. Thus it is 100 degree. Thus C is (180 -100)/2 = 40 degrees answer.


What is angle a?


Solution

• Angles from D and C are equal . • 180 – 60 – 37 – x• =83 – x• Let us sum up for two angles: • (180+180 ) = 360• 83-x + 83 – x + 180+2X = 360• 2Y +2X = 180 let us assume Y = 53 • 2X = 72 or X = 36 answer (solve by options,

so angle A = 53 ) answer.


ABOUT AFTERSCHO☺OL

Afterschoool conducts three year integrated PGPSE (after class 12th along with IAS / CA / CS) and 18 month PGPSE (Post Graduate Programme in Social Entrepreneurship) along with preparation for CS / CFP / CFA /CMA / FRM. This course is also available online also. It also conducts workshops on social entrepreneurship in schools and colleges all over India – start social entrepreneurship club in your institution today with the help from afterschoool and help us in developing society.


Why such a programme?

• To promote people to take up entrepreneurship and help develop the society

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• To enable people to take up social development as their mission

• To enable people to promote spirituality and positive thinking in the world


Who are our supporters?

• Afterschoolians, our past beneficiaries, entrepreneurs and social entrepreneurs are supporting us.

• You can also support us – not necessarily by money – but by being promotor of our concept and our ideas.


About AFTERSCHO☺OL PGPSE – the best programme for developing great

entrepreneurs• Most flexible, adaptive but rigorous programme• Available in distance learning mode• Case study focused- latest cases • Industry oriented practical curriculum• Designed to make you entrepreneurs – not just

an employee• Option to take up part time job – so earn while

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Workshops from AFTERSCHO☺OL

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relevance


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with the time• Placement for those who are interested• Admissions open throughout the year • Latest and most advanced technologies, books and study

material


Components • Pedagogy curriculum and approach based on IIM Ahmedabad and ISB

Hyderabad (the founder is alumnus from IIMA & ISB Hyderabad)• Meditation, spiritualisation, and self development • EsGotitial softwares for business• Business plan, Research projects• Participation in conferences / seminars• Workshops on leadership, team building etc. • Written submissions of research projects/articles / papers• Interview of entrepreneurs, writing biographies of entrepreneurs• Editing of journals / newsletters• Consultancy / research projects • Assignments, communication skill workshops• Participation in conferences and seminars• Group discussions, mock interviews, self development diaryng • Mind Power Training & writing workshop (by Dr. T.K.Jain)


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• AFTERSCHO☺OL will shortly open its branches in important cities in India including Delhi, Kota, Mumbai, Gurgaon and other important cities. Afterschooolians will be responsible for managing and developing these branches – and for promoting social entrepreneurs.


Case Studies

• We want to write case studies on social entrepreneurs, first generation entrepreneurs, ethical entrepreneurs. Please help us in this process. Help us to be in touch with entrepreneurs, so that we may develop entrepreneurs.


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• Share to learn more• Interact to develop yourself• Fear is your worst enemy• Make mistakes to learn • Study & discuss in a group• Criticism is the healthy route to mutual support

and help • Ask fundamental questions : why, when, how &

where?• Embrace change – and compete with yourself

only


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society

management aptitude test 13 nov

Technology

work b

work c

work d

b start

right conclusion

b people

work groups

answer statement