magnetic properties of materials - nicholas research group

18
Magnetism – HT10 - RJ Nicholas 1 Magnetic Properties of Materials 1. Magnetisation of materials due to a set of isolated atoms (or ions) a) Diamagnetism - magnetic moment of filled shells of atoms. Induced moment opposes applied field b) Paramagnetism - unfilled shells have a finite magnetic moment (orbital angular momentum) which aligns along the magnetic field direction. 2. Collective magnetisation - magnetic moments of adjacent atoms interact with each other to create a spontaneous alignment - Ferromagnetism, Ferrimagnetism, Antiferromagnetism Some useful background Definition of the fields: B is the magnetic flux density (units Tesla) H is the magnetic field strength (units Am -1 ) M is the magnetisation (the magnetic dipole moment per unit volume, units Am -1 ) B = μ 0 (H + M) = μ 0 μ r H = μ 0 H (1 + χ) All materials Relative permeability susceptibility linear materials only 0 field in linear non when = H H M χ

Upload: others

Post on 12-Sep-2021

5 views

Category:

Documents


0 download

TRANSCRIPT

Page 1: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 1

Magnetic Properties of Materials1. Magnetisation of materials due to a set of isolated atoms

(or ions)a) Diamagnetism - magnetic moment of filled shells of

atoms. Induced moment opposes applied fieldb) Paramagnetism - unfilled shells have a finite magnetic

moment (orbital angular momentum) which aligns along the magnetic field direction.

2. Collective magnetisation - magnetic moments of adjacent atoms interact with each other to create a spontaneous alignment - Ferromagnetism, Ferrimagnetism, Antiferromagnetism

Some useful backgroundDefinition of the fields:B is the magnetic flux density (units Tesla)H is the magnetic field strength (units Am-1)M is the magnetisation (the magnetic dipole moment per

unit volume, units Am-1)B = μ0 (H + M) = μ0 μr H = μ0 H (1 + χ)

All materialsRelative

permeabilitysusceptibility

linear materials only

0fieldinlinearnonwhen

→∂∂=−

HHMχ

Page 2: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 2

Magnetic Energy

Energy in Magnetic Field = ½B.H = ½μ0 (H + M).H

= ½μ0 H2 + ½M.H

Energy of a magnetic moment m in magnetic flux

energy to align one dipole = - m.B = -mzBz

Energy density due to magnetisation

of a material: E = M.B

Magnetic moment from a current loop:

Magnetic Flux density B is:

M is magnetic dipole moment/unit volume

im IA= =∫I dS

0 0 0 ( )NV

μ μ μ= + = +imB H H M

dm= IdS

Page 3: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 3

Langevin DiamagnetismElectrons in an atom precess in a magnetic field at the Larmor frequency:

Act as a current loop which shields the applied field

I = charge/revolutions per unit time =

Area of loop = π<ρ2> = π(<x2> + <y2>) = 2/3 π<r2>

Hence magnetic moment induced/atom mi

meB2

⎟⎠⎞

⎜⎝⎛−

meBZe22

1)(π

22

6r

mBZe−=

22

00

6r

mNZe

BNmi μμχ −==For N atoms susceptibility

(per unit vol or per mole)

Magnetic Levitation - An example of magnetic energy density

Energy due to magnetisation = -m.BMagnetic moment = VχB/ μ0 so

force = -mdB/dx = - Vχ(B dB/dx)/ μ0 = - ½∇B2 Vχ/ μ0

force = gradient of Field energy density ½ B2 Vχ

Levitation occurs when force balances gravitationalforce = Vρg, therefore:-½∇B2 = ρg μ0 / χTypical values of χ are of order 10-5 - 10-6

Page 4: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 4

ParamagnetismUnfilled shells.

Magnetic moment of an atom or ion is:μ = -gμBJ, where J is the total angular momentum

J = L + S and μB is the Bohr magneton (e /2m)

A magnetic field along z axis splits energy levels so:

U = - μ.B = mJ gμBB

mJ runs from J to -J

Spin ½ systemN ions with mJ = ±½ , g = 2, then U = ± μBB,ratio of populations is given by Boltzman factor so we can write:

Upper state N2 has moment -μB , so writing x = μBB/kT

)exp()exp(

)exp(

)exp()exp(

)exp(

2

1

kTB

kTB

kTB

NN

kTB

kTB

kTB

NN

BB

B

BB

B

μμ

μ

μμ

μ

−+

−=

−+=

xNeeeeNNNM Bxx

xx

BB tanh)( 21 μμμ =+−=−= −

Page 5: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 5

Magnetisation

Magnetisation saturates at high fields and low temperatures

Low field, higher temperature limit tanh x → x

Curie’s Law:

Compare with Pauli paramagnetism

TkBNM

B

BB

μμ tanh=

TkN

HM

B

B2

0μμχ ==

FB

B

TkN2

3 20μμ=

General Result for mJ … J → -J

2 1 2 1 1 1( ) coth( ) ( ) coth( )2 22 2BJ JM NgJ y yJ JJ J

μ + +⎡ ⎤= −⎢ ⎥⎣ ⎦

( ) 2 2

0

10,3

13

as ,

BB

B

sat B

gJ BJas y M NgJJ kT

J J gM CNH kT T

y M Ng J

μμ

μχ μ

μ

+→ =

+= = =

→ ∞ =

Curie’s Law

Page 6: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 6

Saturation behaviour

• Curie Law at low field

• Saturation at high field

Apply a magnetic field to split up energy levels and observe transitions between them

For a simple spin system ω = gμBB - selection rule is ΔmJ

= 1 (conservation of angular momentum)When ions interact with the crystal environment or each

other then extra splittings can occur.

Magnetic Resonance

Magnetic Field

Ene

rgy

Page 7: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 7

Magnetic Resonance ExperimentExperiment uses microwaves (10 -

100 GHz), with waveguides and resonant cavities

Resonance Spectrum

Relate toCrystal fieldsplittings

Page 8: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 8

Nuclear Magnetic Resonance

Similar to spin resonance of electrons, but from spin of nuclei. Energy is smaller due to the much smaller value of μBN

Resonance condition is ω = gμN(B + ΔB)ΔB is the chemical shift due to magnetic flux from orbital

motion of electrons in the atom.

Diamagnetic magnetic moment induced in a single atom

302

2

30 .

6 rr

mBZe

rmB μμ −==Δ

N.M.R. and M.R.I.

Chemical sensitivity is used in monitoring many biochemical and biological processes

NMR

Scan magnetic field with a field gradient in order to achieve chemically sensitive imaging

MRI

Page 9: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 9

Magnetic Cooling (adiabatic demagnetisation)

Cool a solid containing alot of magnetic ions in a magnetic field. Energy levels are split by U = ± μBBi

Population ratio is

Remove magnetic field quickly while keeping population of spins the same - Adiabatically

⎟⎟⎠

⎞⎜⎜⎝

⎛−=

+

i

iB

kTB

NN μ2exp

iB

i

fB

f

BkT

BkT

μμ=

Tf is limited by small interactions between ions which split energy levels at B = 0

Interactions between magnetic ionsDipole - dipole interactionsNeighbouring atoms exert a force on each other which tries to

align dipoles m. Interaction energy is U = -m.B.Magnetic flux B is μ0(m/4πr3 - 3(m.r)r/4πr5) so

U = -m.B ~ - μ0 m1.m2/4πr3 = - μ0 μB2/4πr3

r is separation of atoms (approx. 0.3nm) giving U = 4 x 10-25 J = 0.025 K

If all atomic dipoles are aligned the magnetisation is:M = NμB giving a total magnetic flux B = μ0 NμB ~ 1Tso: U = 0.9 x 10-23 J ~ 0.7 K

Page 10: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 10

Collective Magnetism -Ferro-, Antiferro- and Ferrimagnetism

Oldest piece of Condensed Matter physics known about and exploited is ferromagnetism.

Why do spins align at temperatures as high as 1000 K ??It is definitely not due to magnetic dipole-dipole

interactions.

The strong interaction is due to the action of the Pauli exclusion principle which produces:

Exchange Interactions

Consider two adjacent atoms and two electrons with a total wavefunction ψ (r1,r2;s1,s2)

Pauli exclusion principle: ψ (r1,r2;s1,s2) = - ψ (r2,r1;s2,s1)If r1 = r2 and s1 = s2 then ψ = 0

Electrons with same spin ‘repel’ each other and form symmetric and antisymmetric wavefunctions [φa(r1) = φ3d(r1-ra)]

ψs (1,2) = [φa(r1) φb(r2) + φa(r2) φb(r1)]χs(↑↓)

ψt (1,2) = [φa(r1) φb(r2) - φa(r2) φb(r1)]χt(↑↑)

Energy difference between singlet and triplet is dependent on alignment of the spins U = -2Js1.s2

Exchange Interaction

Page 11: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 11

energy difference given by the ‘exchange integral’

Comes from electrostatic (Coulomb) interactions

23

13*

10

2

120

2* )2()2(

42

4)1()1(2 rdrd

re

reJ baba φφ

πεπεφφ ⎥

⎤⎢⎣

⎡−= ∫

Positive termelectron-electron

coupling

Negative termelectron-ion

coupling

J > 0Electron spins alignFerromagnetic coupling

J < 0Electron spins antiparallel

Anti-ferromagnetsCovalent bonding

Molecular Field ModelEnergy of one spin in an external magnetic flux B0

which can be considered as due to an effective flux Beff

Spins are aligned by the combination of the external flux B and the internal magnetisation.

. .

. .

ij B

ij B

U J g

J g

μ

μ

= − +

= − +

∑i j 0 i

i j 0 i

S S B S

S S B S

eff 0 0

2 20

B B M ,2

where M ij

j iB

B

JNg S and

N g

μ λ

μ λμ μ

= +

= − =∑

Page 12: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 12

Curie - Weiss LawAssuming Curie’s Law to hold for the total fields

Curie - Weiss Law shows that at around Tc there will be a spontaneous magnetisation

λμχ

λμ

λμμ

CTTT

CBM

CTCBM

TMBC

TCB

M

cc

eff

=−

==

−=

+==

,

)(

0

0

00

000

Saturation Magnetisation

Around Tc the spins begin to align.

No simple analytical solution, but graph shows numerical result is reasonable description of experiment

TkMNM

yBNgJM

B

BB

JB

00

00

tanh

1/2spin For

,)(

μμμμ

μμμ

=

=

Page 13: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 13

Typical values of Tc are 1000K, so if z = 8 we find

J = ~ 0.02 eV,

At saturation (all spins aligned) M = NμB giving:

Beff = μ0λM = μ0NμBTc/C = kBTc/ μB ~ 1500 T

This is not a real Magnetic Field

Bferromagnet = μ0 NμB ~ 1T

neighboursnearestofNo.isz,2

so

2and,2

1spinfor 220

20

B

ijc

B

ijij

B

B

kzJ

CT

gN

J

kNC

==

==∑

λ

μμλμμ

Result is a non-integer average magnetic moment per electron e.g.

Metal Ms (μB / atom) gJIron 2.2 Fe3+ 5 Tc = 1043Cobalt 1.7 Co2+ 6 Tc = 1388Nickel 0.6 Ni2+ 6 Tc = 627Gd 6.8 Gd3+ 7 Tc = 292Dy 10.2 Dy3+ 10 Tc = 88

Rare-earths have very narrow bands so result is given by free ion result

Page 14: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 14

Exchange interaction shifts energy levels of electrons by less than typical band widths in metals, so we have to remember that just as in Pauli paramagnetism not all of the spins can be aligned.

Band model of Ferromagnetism

Domains

One thing is missing from our explanation:Real magnetic materials need an external magnetic field to

be applied in order to produce strong or permanent magnetisation - depends on crystal orientation

Page 15: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 15

Why do Domains form?Magnetisation of a single crystal costs a large amount of

energy of magnetisation =Balanced by anisotropy energy - spins only like to align

along particular crystal directions - energy cost is K per electron spin

dM.B0∫

Domains in real crystalsSingle ‘whisker’

of ironLarger crystal of

NickelDomains can be ‘pinned’ by the presence of impurities, which make it easy for the domain boundary to sit in one place

Causes the difference between ‘soft’ and ‘hard’magnetic materials

Page 16: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 16

Domain boundaries - Bloch Wall

Energy is minimised by changing the spin slowly in N steps by a small angle θ = π/N.

Energy cost calculated from exchange energy

U = -Σ2Js1.s2

ΔU =2NJS2(1-cos(θ))= 2NJS2(1-(1 - θ2/2)) = JS2 π2/N

Anisotropy energy cost = KN/2

Total = JS2 π2/N + KN/2,

Minimum when N = (2JS2 π2/K)½, e.g. 300 in Fe

Antiferromagnetism

What if exchange integral J < 0?

Adjacent spins line up antiparallel.

This causes antiferromagnetism

An example is MnO

Can model this with a molecular field model with twomolecular fields corresponding to spin up and spin down

Result gives: χ = C/(T + θ)

Page 17: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 17

A A A AB B B

Aeff 0 0 B

Beff 0 0 A

2 20

B B M ,

B B M

4 ijj i

B

J

N g

μ λμ λ

λμ μ

= −

= −

=∑

Sum these two equations

( )

0

0 0

0 0

0 0

,2

2 2

2 2

22

AA eff A B

A B

B A

CM B M M MT

C CM B MT TC CM B MT T

C C C BM B MCT T T

μ

λμ μ

λμ μ

λμ μλ

= = +

= −

= −

= − =+

Page 18: Magnetic Properties of Materials - NICHOLAS RESEARCH GROUP

Magnetism – HT10 - RJ Nicholas 18

Summary of Collective Magnetism

Some crystals can have ions with both J > 0 and J < 0This causes Ferrimagnetism. Best known example is ferrite

Fe3O4 (Fe2+O,Fe3+2O3).

Moment = (2 x 5/2 - 2) μB /formula unit