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DO HELIUM ADSORBER PRESSURE VESSEL & VACUUM VESSEL ENGINEERING NOTES D-ZERO ENGINEERlNG NOTE # 3823.115-EN-524 April 12, 2000 Author: Russ Rucinski PPDIETI'ID-Zero Upgrade project

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  • DO HELIUM ADSORBER

    PRESSURE VESSEL & VACUUM VESSEL

    ENGINEERING NOTES

    D-ZERO ENGINEERlNG NOTE # 3823.115-EN-524

    April 12, 2000

    Author: Russ Rucinski PPDIETI'ID-Zero Upgrade project

  • PRESSURE VESSEL ENGINERING NOTE

    PER CHAPTER 5031

    Prepared by: STEj?1i AN IE 11c.J>fl/)EPreparation date:~7~1~/~6./~q~~___________ E.£)&'""E.CI 8'1' ~ RLJS~ ~Uc.&""'&'5J Kl

    1. Description and Identification Fill in the la~el information below:

    IThis vessel conforms to Fermilab ES&H Manual 'Chapter 5031

    Vessel Title HEL1U M Absc«BE( wI LiGIJ//) NzJI\

  • Lab Property Number(s): NbW£ --~~~--------------------~---------------------

    Lab Location Code:. RPIS -32'5 (bAS) (obtain from safety officer) Purpose of Vessel (s): Hf'LJUM l'U~IFYI N6 $YSlfM FO~ uP6gabE

    'NII,/e-. .. 5.'2. f-V INtJt:/l:. ''1.'' ,.;:j;jett '" go"Vessel Capacity/Size:o",.i@.. :. 1..3 .t:

  • List the numbers of all pertinent drawings and the location of the originals.

    Drawing # Location of Original

    25lpJ.37S- ME-.JJQ51./9 . dCaWfr

    2. Design Verification

    Does the vessel (s) have a U stamp? 'fes X No If "Yes" I fill

    out data below and skip page 3; if "~O", fill out page 3 and skip this

    page.

    Staple photo of U stamp plate below.

    Copy nu" label details to the side •....TIUtJoI..""·...,A'" iiHa:-r ~£1'A1.. tl.4T"E MR. /uc S.M~II.A...E I t.Jl'"

    - MJ\~.p . S\uJ\ ,3~5 ~L at JOo of Jk.t \ \ 5 P\L Q-t- JeO of

    M'i\. bt~. Mf-t. T?t?lP. sha.\\ - 32.0 D F ai 3lD5 ps; J\

  • -----

    3. System yent;~g Ver;fica~ Provide the system schematic in the Appendix.

    Is it possible to isolate the relief valves by a valve from the vessel?

    Yes__ NoL

    If ·Yes·, the system muSt conform to code rules. Provide an'~

    explanation on the appended schematic. (An isolatable vessel,

    nOt conforming to code rule is non-compliant under this

    chapter.)

    Is the relief cracking pressure set at or bel~the K.A.W.P.?

    Yes. X No Act.ual set.t.ing P?r...~w PSI

    (A ·No· response violat.es this chapter.)

    Is the pressure drop of the relief system at. maxi.,m ant.icipat.ed flow such t.hat. )(ssel pressure n~: ~;~ses abqVe the following? (UG 125)

    Yes No L~!l~~ of KAWi)(one relief) 11 of KANP (multiple reliefs) 121% of KANP (unexpected heat. source)

    Provide test or calculat.ional proof in the Appendix. (Non-conforminqpr~ssure rises is non-compliant. under this Chapt.er.)

    Lilt of reliefl and ,acting,:

    MAnufacture;: Model' Set Pressure FlOW BAt.e

    \02q '5c£M. A It. \ II-kc.~1" P(:l.If-/\M.-1 F \ ~E:. C:.pv ~ ""'jAil2 31 !> cot", Alr~ => ..,..-J ACi

  • 6. Exceotionai, Existing, Used and Unmanned Area Vessels

    Is this vessel or ~n~ part thereof in the above categories? Yes_____ No__~___ .

    If "Yes", follow the Engineering Note requirements for documentation and append to Note.

    5031TA-IOFermilab ES&H Manual Rev.8/9S

  • By: Jason Lambin Edited: Russ Rucinski

    Rev: A. Valdez 12114/99. RAR 1-7-00

    RELIEF SUMMARY

    Outer LN1.Jacket Relief

    Cases (see Appendix A)

    1. Loss of vacuum

    2. Gas Generation from warm Ghe load

    3. Under Fire Conditions

    Outer LNz Jacket Relief Devices (see Appendix B)

    AGCO relief valve set pressure =60 psig

    I" Fike rupture disc burst pressure =100 psig

    Outer LNz Jacket (see Appendix C)

    %MAWP at relieving flow

    Required Capacity

    121 scfm Air

    762 scfrn Air

    281 scfrn Air

    Actual Capacity

    237 scfrn Air @ 60 psig (stamped) 363 scfrn Air @ 100 psig

    1029 scfrn Air @ 100 psig

    107%MAWP

  • By: Jason Lambin Edited: Russ Rucinsld

    Rev: A. Valdez 12114/99

    RELIEF SUMMARY

    Inner Ghe Vessel Relief

    Cases (see Appendix A) Required Capacity

    1. Loss of vacuum 0.1 scfm Air

    2. GHe flows at maximum rate through relief 570 scfm Air

    3. Under Fire Conditions 41 scfm Air

    Inner Ghe Relief Devices Actual Capacity (see Appendix. B)

    AGCO relief valve 658 scfm Air @ 340 psig (stamped) set pressure = 350 psig

    1" Filee rupture disc 4609 scfm Air @ 500 psig burst pressure = 500 psig

    Inner Ghe Vessel (see Appendix C)

    %MAWP at relieving flow 101% MAWP

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    .) ESTIMATED WE IGIlTS

    EMPTY DOUBLE WALL VACUUM VESSEL I'll THOu1 LI D ,)200 LU~ .LID ASSEMBLY WITHOUT ATTACHMENTS BELOW - 1250 LBS.HEAT EXCHANGER IDa LBS.CHARCOAL ADSORBER BOO LBSMISCELLANEOUS PIPING. VALVlS. 150 IBS.

    ASS[UIJI y. 5500 1'052.) DESIGN SPEClrlCATIONS ARE

    HELIUM FLOW RATE-50 9 /5INCOMING HELIUM PRESSURE-300 PSIG LN. CONSUMPTION RATE-1'.7 GPH CHARCOAL ADSORGER MAWP·350 PSIG JACKET MAWP.IOO PSIG

  • - - -

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    gISFiP2-~ SERIAL tr. ITAG HYDRO (1)

    ANDERSON GREENWOOD I CROSBY

    FUNCfIONAL TEST REPORT

    DIRECT SPRING VALVES (I)

    uauua.:

    S 5{ I:lOS (){)Ol}. {)() I VAI~;

    '-/ -J-q _cL 9 (lA1J(lI! • (I'1NAL):

    AIO()- 03 BELWWS OR IBACK O-RING TEST PRESSURE

    ASSY ISET NAMEPLA.TE I.> SPECIFIED RESEAT LEAK TEST@FlNAL TECH fDQ PSIG, TECII (·1" CDTP 54 PSIG(3) 5.L1 PSIG(4) (.) f\

    IJ{J, vA I /\ JA 1) t.]l. IQ;),(,:, ( ,_. ___,,_..______ 0_ " l!:WEaA11ON WILL DlI11AL 10INDICATE CDMI'UmON AND VDlACA11ON. CUSTOt.fEtl WlTNESS TESTMEDtuM T )IUlFEIl1O APPLICABLE DOCUMENT FOIt TESf PItOCEOOIUl. PIUlSSURE DlI'SIO, UNUSS DnIEIlWlSE DlDlCATED. SIONA1URE DATE AIR t.I ~fha;J-1HYDIlOSTAncTESfCONDlJCTED PElt ASME, CUSTOMER (CUm Oil NlA. LIQUIDISET EMPIRICALLY, ENTEIT RDlG'SCITEW SIm\NOS (J'IJllNSINOTCII1!S). 11I\JlI8LES PER MINIJIl! (AIR). CUBIC CENnMETERS PER MINt/fE (UQUlD), ACCEPTABLE "O'~'TEAM) !!TF'I\M ""'~·I R•• I. (O!I99)

  • ))\ .....iYfa~lLd llidt a rds f-I1S

  • F.-lei Certificate of Conformance """"'~~"lJ'~R for Rupture Disc Devices

    Il10_Blue Springs, Missouri 64015 U.S.A. (816) 229~3405 • Telefax (816) 228~9277

    GEIfERAL SPECIFICATIONS Customer: NATIONAL ACCELERATOR LAB P.O. Number: 521393 Qty. Shipped: 4 Nominal Size: 1 IN Type: CPV BT Bolted type Mfg. Lot Number: 9915695 Dwg. Number: N/A Bolt Torque: N/A Flange Rating: 150 ANSI capacity: Specified Manufacturing Range Type: Maximum Stamped Mfg. RaDge KR: 3.25

    . ' .. ',""

    N/A

    P.O. Qty: 4

    Code or Specification Requirement: ASME VIll, Div.l, 98Ed Min. Net Flow Area: .694 Sq.In. Customer Part Number: N/A . Customer TWIt Number: N/A

    .'". MA~ SPBCD'ICATIOIfS" '.,;... ',:.,...... ," ."",co,'":,,,",:·

    ~gm12gns:nt aud. Milts:rial Mat'l 1&t rig. Top Ring Material 316 SST 481644 Seal Material Aluminum 87A068 Vacuum SuPPOrt Material 316 SST 490084

    SPECIFICATIONS AT SPECIFIED TEMPERATURE All Burst Pressures are listed in PSIG @ 72 Desuees F Specified Burst Pressure: Nominal: 100.00 Min: N/A Max: N/A

    Many!actuDn& BWl&e IMin: BY12turr: Tolerance Min: 86.36 Max: 100.00 88.16 Max: 97.44 Stamped Burst Pressure: 92.80 Min: N/A Max: N/A

    BORST TEST RESULTS ......

    Avera~e Burst Pressure: 92.80 Burst Tests: N/A

    SPECIFICATIONS ATAVBIEl!fT TBMPBRATDRB*+;);;~:,::, ....Am1tIellt teaaoentare fa debed .. ISOto 90 deD'Mtl p~ fl0.0 to 32.2dure.. 0;1

    All Burst Pressures are listed in PSrG @ 72 D -- F Man:ufw::wrin& Ran&e IMin: R:u,12Wrr: Iglerancc Min: N/A Max: N/A NJA Max: N/A

    Stam.J)ed Burst Pressure: N/A Min: NJA Max: N/A BtlRST'TB8T RESULTS

    Average Burst Pressure: 92.80 Test Media: AIR Burst Tests: 92.20 94.20 92.00

    SPECIAL NOTES

    Rupture discs are manufactured at ambient temperature to burst within manufacturing range values derived from Fike Temperature Compensation data unless actual temperature tests are performed. We certify these components meet applicable specifications, drawings and requirements: of your purchase order. Evidence of compliance is maintained on me in our records, available for i

    Jun-14-99 @ 10:42 AM Date

    Q044E Page 1 of 1

    I

  • Itkl Certificate of Conformance DMSI~!~:~~2 for Rupture Disc Devices Blue Springs, Missouri 64015 U.S.A. (816) 229-3405 • Telefax (816) 228-9277

    GENERAL SPECIFICATIONS Customer: NATIONAL ACCELERATOR LAB P.O. Number: Qty. Shipped: 4 Nominal Size: 1 IN Type: CPVBT Mfg. Lot Number: 9915696 Dwg. Number: N/A Bolt Torque: N/A Flange Rating: 300 ANSI

    521393 Bolted type

    Capacity: Specified Manufacturing Range Type: Maxtmum. Stamped Mf'1_ Ran,e Ka: 3.25

    N/A

    P.O. Qty: 4

    Code or Specification Requirement: ASME VIll, Div.I, 98Ed Min. Net Flow Area: .694 Sq.In. Customer Part Number: N/A Customer TaJ{ Number: N/A

    MATERUL SPECD'ICATIONS ....c.. ", ..

    ~2mR2nent and Miltl:rjal Mat'l Lot No, Top Ring Material 316 SST 481644 Seal Material 316 SST 460934 Vacuum Sut>t>ort Material 316 SST 480590

    SPECIFICATIONS AT SPECIFIED TEMPERATURE All Burst Pressures are listed in PSIO @ 72 Deli!Tees F Specified Burst Pressure: Nominal: 500.00 Min: N/A Max: N/A

    Manuia~tyIing RaniS: IMin: BURtuIS: I21erance Min: 444.45 Max: 500.00 452.83 Max: 500.50 Stamped Burst Pressure: 476.67 Min: NJA Max: N/A

    BURST TEST RESULTS Averajte Burst Pressure: 476.67 Burst Tests: N/A

    SPECIFICATIONS AT AMBIENT TEMPERATURE* ·Amblent temoen.t1U'e is deftDed ulSO to 90 dene•• It; rl0;0 to 3:&.:& deue•• C~l

    All Burst Pressures are listed in PSIO l@. 72 Deli!TeCs F Manl.1ia~tyring Ranie IMin: Rl.1Ril.1D: Tolcmnsoc Min: N/A Max: N/A N/A Max: NLA

    Stamt>ed Burst Pressure: NJA Min: N/A Max: N/A BURST TEST RESULTS

    AveraJ{e Burst Pressure: 476.67 Test Media: AIR Burst Tests: 477.00 478.00 475.00 i

    SPECIAL NOTES

    Jun-14-99 ® 10:42 AM Date

    Rupture discs are manufactured at ambient temperature to burst within manufacturing range values derived from Fike Temperature Compensation data unless actual temperature tests are performed. We certify these components meet applicable specifications, drawings and requirements of your purchase order. Evidence of compliance is maintained on me in our records, available for review upon request.

    Q044E Page 1 of 1

  • Appendix A : Relief Sizing 1 By: Jason Lambin

    Edited: Russ Rucinski Revised: A. Valdez 12114/99, RAR InlOO

    OUTER NITROGEN JACKET RELIEF

    Cases to be considered:

    1.) Loss of Vacuum. CGA

    .fJ Operational case; Gas generation caused by maximwn heat input

    3.) Fire Case, CGA

    ~ Maximwn filling rate: Not applicable since the liquid nitrogen supply sources have delivery pressures less than the MA WP of the vessel

    CASE 1) Loss of vacuwn, CGA S1.3-1995-par. 5.2.2.

    ~________________~~~~Lo~ssofvacuum

    7 Q = (590-T) FGUA A 4(1660- T) I

    Where: QA = Flow capacity in SCFMAir T = TUI at flow rating pressure, in OR F = Cv 12"

    S = !E.{Dl _Dl)= 1f(23.35)( Ift)2 =O.51ft2 Foc the area between thejac:ketand the vessel c 4 J v. 12"

    s~ = nRl[l+ K2(2- KlI= 1r(6.375~)2[1+(·2:!...)2(2_(2:!...1\] =l.32ftl For the beads of the He vessel6.375" 6.375" 'j

    http:1f(23.35http:1l'(12.75

  • 2 Appendix A : Relief Sizing By: Jason Lambin

    Edited: Russ Rucinski Revised: A. Valdez 12/14/99, RAR InlOO

    So the total inner surface are is:

    ST =23.03+ 1.1l+0.56+ 2 *1.32+ 2 *0.51 =28.36ft2 Now for the outer surface area we divide the outer vesseL in three sections. The formula is as follows:

    SOT = StQp +ScyiintUr + Shead Where:

    s.......... =1If)y L y =1r(48.5")(lOn(lft)2 = 106.86ft2

    .- 12"

    S =1r D2 =j 48.S" 11ft)2 == 12.82ft2

    to, -+ '"l 4 lZ'

    SA =1/Rl [l + Kl(2- K)J= 1f(24.2.5.)l[1+(~)1 / 2-(~1\] =1.5.70ftl , 24.2.5 \ 24.2.5 Y

    So the total outer surface area is:

    SOT = 12.82+ 106.86+ 15.70 = 135.38ft2

    Now we can calculate the mean smface area

    S = S17 +Sro = 135.38+28.38 =81.88ft2 - 2 2

    FIND T: Shell design pressure =115 PSIA

    Flow rating pressure = 1.10(115 PSIA) =126.5 PSIA

    Corresponding Tsar: 102 K: 184 OR

    FIND G,: From Table 1, eGA S-1.3-1995

    http:135.38+28.38http:1.1l+0.56

  • 3 Appendix A : Relief Sizing By: Jason Lambin

    Edited: Russ Rucinski Revised: A. Valdez 12114/99, RAR IntOO

    FIND U: Must use larger U calculated with the insulating space filled:

    1.) With GHe at 100 of and 1 ATM (14.7 PSIA), or 2.) With GN2 at 100 of and 1 ATM (14.7 PSIA), or 3.) With air at 100 of and 1 ATM (14.7 PSIA)

    Where:

    kU=

    x

    Where: k= thermal conductivity of the medium koHe= 0.152 W/m*K koN2= 0.0259 W/m*K kair =0.0263 W/m*K (interpolated from Table A.4 in

    Incropera and DeWitt's Introduction to Hear Transfer) x= Thickness of insulation effective for convection and radiatioo, Vz"

    GHe will give the highest U :

    U =!!..= 0.152W/m*K =11.97 ,W x 0.0127m m- *K

    and using the tmits conversion factor

    1 W =0.17615 BTU m 2 * K hr* jt2*O F

    U =2.11 BTU GHe hr* jt2*O F

    Find F: Correction Factor F to be determined by CGA S-1.3, Section 5.1.4

    Involves a 5 step process

    Step 1: Assume F =1.0

    590-184= (1.0)(10.2)(2.11)(81.88) =121.2S'CFMairQA 4(1660-184)

    Conven mis to a mass flow rate in Ibm/he

    W= QAEC ~M 18.35 zr

    http:1.0)(10.2)(2.11)(81.88

  • 4 Appendix A : Relief Sizing By: lason Lambin

    Edited: Russ Rucinski Revised: A. Valdez 12114/99. RAR IntOO

    Where: C= Gas constant (Table 4) M= Molecular weight Z= Compressibility factor at specified temperature and pressure

    k = Cp = 1.041 =lAO C v 0.742

    From Table 4, C=356

    M=28.014

    P 115 -= =0.233

    493.13

    T 184-=-=0.808 Tc 227.6

    From general compressibility chart, Z=O.84

    356(l21.2SCFM) 28.014 =1000.9 lbm LNw 18.35 (0.84)(184) hr 2

    T =590- 59O- Ts , [O~L]

    e

    Where: T.= 184 oR D = 1.315 inches L= 5 feet Cp is to be taken at the ave temp = (590+ 184)12 =387 OR

    c =1.05~(0.239BTU/Ibm *0 F ) =0.251 BTU p g * K 1.0J/ g * K Ibm *"F

    Substituting and solving.

  • 5 Appendix A : Relief Sizing By: Jason Lambin

    Edited: Russ Rucinski Revised: A. Valdez 12114/99, RAR In/OO

    Where: f = friction factor, assume equal to 0.02 I =equivalent pipe length, in feet, say 18 ft W= required mass flow rate, 1000 IbnJltr v =specific volume at flow rating pressure and average temperature, in ft3nb d =inner diameter, in inches, 1.097

    P =8.6 ATM (126.5 PSIA)

    T • ...,= 387 OR (215 K)

    v=1.16 jt3 lb

    Substituting into the equation, the pressure drop is found to be 0.4psi

    Pj= 126.1 psia

    Step 4: Find Vi for P,=8.6 ATM and T;=I90 OR (105.6 K)

    Find v for P=8.6ATM and T=l84 OR (102 K)

    jt3v=O.454

    lb

    Step S: Solve for F

    F = ~ ZziT~ = ~ PPvi =Vi 126.1(.469) 126.5(.454)

    F=1.0

    -

  • 6 Appendix A : Relief Sizing By: Jason Lambin

    Edited: Russ Rucinski Revised: A. Valdez 12114/99. RAR InlOO

    Now go back to original equation and solve for QA.

    Q = 590-T Fo.uA [CGA S-1.3. Section 5.2.2] A 4(1660-T) I

    Where: T=I84 OR F=l.O Gi=IO.2 U=2.11 BTU/hr*ft2*oF A=81.88 ft2

    Loss of vacuum CGA case:

    0 4=121 SCFMmr

    Case 2.) Operationally, consider the maximum heat input to the nitrogen jacket. One could imagine this

    to occur only when beginning flow through the adsorber and the upstream heat exchanger is warm. Warm

    Ghe enters into the top of the adsorber and boils the liquid nitrogen in the jacket.

    Conservative assumptions are:

    I.) Heat transfer is not limited by convection coefficients.

    2.) Incoming flow rate is 120 gls (Normally only one Mycom-60gls is used)

    3.) AU the heat transferred goes into boiling liquid nitrogen and not into wanning the nitrogen above

    saturation temperature. 4.) Neglect flow through the nonnaJ vent line.

    Relief rhGH~ =120g/s

    Vent

    Then:

    .' Qmax Q ("":"A 1..)With mN2 =-h- and max = rrlQJl GH~ flNl

    It.. =15801/g at 300 K and 305 PSIG h2 =540.81/g at 100 K and 305 PSIG

    Qmax =(120g/s)(1580-541)1/g = 124,680W

  • 7 Appendix A : ReHef Sizing

    By: Jason Lambin Edited: Russ Rucinski

    Revised: A. Valdez 12114/99, RAR InlOO

    . = 124,680JIs= 794 Is so mNz 157 Jig g

    Then we convert this to equivalent scfin air.

    794g / s • 2.2Ib", • 3600s = 6290lb / hr l000g 1hr '"

    18.35W ~zrQAE = - Ref. CGA S-13 5.1.4 C M

    Where: C= Gas constant (Table 4) M= Molecular weight Z= Compressibility factor at specified temperature and pressure W=62901blhr

    k =C p =1.041 = 1.40

    . Cv 0.742

    From Table 4, C=3S6

    M=28.014

    _p = 115 =0.233 493.13

    T 184-=--=0.808 Tc 227.6

    From general compressibility chart, Z=O.84

    Q _ 18.35(6290) (.84)(184) '(E - (356) 28.014

    0&=762 SCFMAir

    -

  • Appendix A : Relief Sizing 8 By: Jason Lambin

    Edited: Russ Rucinski Revised: A. Valdez 12114199, RAR 117/00

    Case 3.) Under Fire Conditions Per CGA S-1.3-1995 5.3

    Per 5.3.1 paragraph b. the vessel being sufficiently isolated from engulfment office. the required capactiy calculated by par 5.3.3 can be reduced to 30%.

    Where: F =1.07 Correction factor calculated in Appendix E Gi = 10.2 Gas Factor for insulated containers from table 1 U = 2.32 Btu Overall heat transfer. Calculated in Appendix E

    hr* fit *oR

    A = 81.88ft 2 Arithmetic mean area calculated on Case 1.

    Qa =(0.30)(1.06)(10.2)(1.61)(81.88)°·82 =281scfm-air

  • 9 Appendix A: Relief Sizing By: Jason Lambin

    Edited: Russ Rucinski Revised: A. Valdez 12114/99

    HELIUM RELIEF

    Cases to be considered:

    L) Loss of Vacuum, CGA 2.) Operational Maximum supply rate, closed outlets 3.) Fire Conditions, CGA

    CASE 1) Loss of vacuum

    = .0085PV .JMQ [Per CGA $-1.3, Section 5.2.1] A C Z

    Where: p= MAWP 365 psia V= 5.2 (Volume of the container in cubic feet) C= 377, from Table 4 M= 4 (Molecular weight) Z= as follows:

    ~= 365 =10.4 Pc 35.2

    T 144-=-=15.1 Tc 9.5

    From general compressibility chart. Z=1.1

    Q = .0085(365)(5.2) .J 4 = .0816 A 377 1.1

    Loss of vacuum case:

    0&=0.082 SCFMair

  • 10 Appendix A: Relief Sizing By: Jason Lambin

    Edited: Russ Rucinski Revised: A. Valdez 12114/99

    Case 2) Operational error that needs to be considered. For the worst case, consider the helium purifier to be off-line. An operator opens the inlet valve and fails to open the outlet valve. The operalOr then closes the bypass valve so the relief sees Full Mycom flow.

    Assume that the relief valves on the source (Mycom) also sel at 350 psig ~ work and the Mycom compressor is capable of delivering this mass flow at this pressure. Assume botff Mycoms are on. (Normally only one Mycom is on. one is spare)

    According 10 AIRCO's Industrial Gases Data Book:

    1 kg He =213.2 SCFGHe

    Q = 120g/s* 213.2SCF * 60s =1535s(.:fin GHe lOOOg 1min

    Q.. =QG,.[~~ )= Ordk[t;)= 570scfin

    Case 3) Under Fire conditions Per CGA S-1.3-1995 5.3.1

    Q =O.00035PWca Where:

    P = 365 psi (MAWP) Wc= Water Capacity in Ibm

    Then:

    Q" =.00035(365)(324.3) =41.4scfm

    FIRE CASE:

    !h=41.4 SCFMair

  • Appendix B - Flow Capacity of Relief Devices By: Jason Lambin Edited: Russ Rucinski

    Liquid Nitrogen Jacket Relief Valve, SV-261l·N

    Stamped capacity =237 scfm air at 60 psig =75 psia From sizing formulas in AGCO series 80 catalog, we see flow is directly proportional to the inlet pressure. Scaling the stamped capacity up for vessel MAWP =115 psia,

    Capacity at 115 psia =363 SCFMair

    Liquid Nitrogen Jacket Rupture Disc, RD 2612·N

    Use equations in Fike technical bulletin,

    We have Sonic flow:

    a = QSA ~T+460 ~29 in2 11.4Po 520 M

    We are interested in air flow at standard conditions so the second two terms reduce to unity. Rearranging to solve for Q;

    For a I" rupture disc, a =0.785 in2• So at the burst pressure. Po=115 PSIA, QSA capacity is:

    QSA =11.4 * 115 psia *0.785 in2 =1029 SCFMair

    Adsorber Relief Valve, SV-2603-H

    Stamped capacity at 350 psig (MA WP= 365 psia) =658 SCFMair

    Adsorber rupture disc, RD-l609·H

    Burst pressure is nominally 500 psig =515 psia. so at burst pressure. Po=515 PSIA, QSA capacity is:

    QSA = 11.4 *515 psia *0.785 in: =4609 SCFMair

  • o

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    «» Fermilab

    Oct. 14, 1999 Russ Rucinski

    PPD-10060- Helium adsorber vessel, Heat exchanger, and piping

    EXHmITB

    Pressure Testine Pennit"

    Type of Test: [ 1 Hydrostatic [..Jl Pneumatic - Gas Nitrogen

    Test Pressure: 441 psig + vacuum =456 psid (125% of MAWP) Maximum Allowable Working Pressure: 350 psig + vacuum - 365 p'sid

    Items to be Tested: 1) ASME coded pressure vessel. 12" sch.40 pipe x 6 foot long with heads and overall volume-5.2 cubic feet. 2) ASME coded parallel plate heat exchanger 5" SQuare x 6

    feet long. 3) Ap,proximately 30 feet of pipe varying 1" to 2" pipe size that is connected to items 1 & 2. 4;} GIt5 surP'L"f Ft.e~ t-\~s I.... C.C.UPEP ItJ ""TeST. tpV:

    Location of Test: South parking lot or other outdoor location near D-Zero Ass'y Building

    Date and Time: October or November 1999 Ocr. -z.q I\C\~

    Hazards Involved: 210.000 ft lbs of stored energy (eguivalent to a 50 ton shielding block

    potentially dropping 2.1'feet. Replacement value =$120K. Risk of explosive type release of energy.

    Safety Precautions Taken: Personnel will be protected by a substantial barrier. The majority

    of the pressurized components will be enclosed in the vacuum vessel container which will act as secondary containment should there be a problem. The net volume of the Vacuum container is 21 times larger than the volume being pressurized. The gas volume, if passed controllably

    (ie. small leak) into the vacuum container will result in the initial pressure of 456psia/21 = 22 psia - 7 psig. This can safely be relieved by the 2" IPS oarallel plate relief on the vacuum

    container. There will be a 15 to 20 foot clear area around the vessel.

    -

    • Must be signed by division/section safety officer and division/section head prior to conducting test. It is the responsibility of the lest coordinator to obtain signatures. Fermilab ES&'H Manual 5034TA·l

    Rev. 4/92

  • 2 Special Conditions or Requirements: The vessel and heat exchanger are ASME code

    stamped to a MA WP of 365 psid. ASME coded components are pressure tested hydrostatically

    to 150% MA WP or pnuematically to 125% MAWP at the manufacturer. so risk of failure of

    these components is reduced. This pressure test is to test the high pressure piping attached to

    these components as an assembly. Hydrostatic testing is not an option due to the vessel being filled with charcoal adsorption material.

    Procedure:

    Equipmept; A 450 to 485 psig relief on the GN2 source is reguired. Relief size must be equal or greater than the source line size. Source may be a GN2 cylinder (only one required) set up with a suitable regulator, gage and valves for isolation and bleeding. Source is to be secured

    and located where accessible to test personnel behind the barrier.

    Prepare system for pressure. test: Remove the 350 psig relief valve and 500 psig rupture disc

    and CAP port. Close valves to· all gages thAt would hAve their nmge exceeded. Pump down the

    vacuum vessel and isola.te it. Monitor the vacuum rate of rise (microns/hour) prior to the test.

    Test: Set up the safety preCAutions. Put up SAfety rope. Record vacuum vessel pressure. 2 "1Oft.fI:,. /If C;ftIX

    Pressurize to 25 psig and look for gross leaks. Now staying behind barrier, pressurize to 350

    psig and hold for 3 to 5 min. Pressurize to 400 psig and hold for 3 to 5 minutes. Take to full pressure - 441 psig +/·5 psig. Hold for 5·10 minutes. Bleed down all pressure. Record

    VAcuum pressure. If no leilk: is suSl)eCted. pressure testing phASe is complete.

    Final leak check: Connect A helium leak detector to the vacuum vesseL Pressurize the helium side of the system with gAS helium and wcuch the leak detector to confmn no leaks in piping or components contained within vacuum space.

    Test Coordinator: Russell A. Rucins

    Division/Section Safety Officer..,..........,-;:.fh'...;;;...;;..-"--___

    Division/Section Head ~""rT~f-.ij'7'9::>'-::;f'-~---.::~1v).t:'tJi?f:r:. !C~ Results _______-1::______________________

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  • EXHIBIT A-I

    Vacuum Vessel Engineering Note (per Fermilab ES&H Manual Chapter 5033) .

    Prepared By STEPHANI E' Hf Date l/"lqq Div/Sec PPO IE;IT I!lhTeO\ Rus'S 'J:IUC."""'''''I

    Reviewed By ~ ID"* J1'Z9BDate "J.11.11~Div/Sec tea b I c.. Sa.

    Div/Sec Head Date pz/atS Div/Sec_-=-(A__f/...t::.7?____ --~~~--------------

    1. Identification and Verification of Compliance

    Fill in the Fermilab Engineering Conformance Label information below:

    This vessel conforms to Fermilab ES&H Manual Chapter 5033

    Vessel Title HEL IV"" YURlFIE'R vAc..UlJM VES~£L Vessel Number PPD"V' too~o (P"""IDUiL"f Rf) o Ii OO'7) Vessel Drawing Number 311./0, l.Zz. - Me: - Z733L/f 't.lTQHA\. MAWP .,10 pStS i . ... e::~Ta."..I"~ MAwP Fu,"",, \JAc..IJ\J/oA Working Tempera:ure Range - 32() of to _..u(0",,0"""-____ of Designer/Manufacturer---!..F..=Eu.!

  • Laboratory location code R. P' 5 - 3 Z5 (PAS) Laboratory property number tolo... E Purpose ofvessel Va~ uu-m-':""':\j~t~-s-e--:\---'~f'-,-c-'Gr-U-:-e..---::Iy....-(-,...,..." e r u

    Fermilab ES&H Manual 5033TA-7 Rev. 3/96

  • List all pertinent drawings

    Drawing No.: Location of Original:

    J1IJ.lll- ME - 2. 133l/1 bAS HIGH BAY

    2. Design Verification

    Provide design calculations in the Note Appendix.

    3. System Venting Verification

    Can this vessel be pressurized eithefnternali¥Jor externally? [x] Yes [] No I/yes, to what pressure? 2.. PsI .8~ A L.EA"- v",\~"'LN1\ot-i"'I-i..'"\

    List all reliefs and· settings. Provide a schematic of the relief system components and appropriate calculations or test results to prove that the vessel will not be subjected to pressures greater than 110% beyond the maximum allowable internal or external pressure.

    Manufacturer Relief Pressure Setting Flow Rate Size PAbou.ec.. ~ '2. psi 2"EeJ;.M ll-AS PLA-rc ']04 SdM

    4. Operating Procedure Section

    Is an operating procedure necess~ for the safe operation of this vessel?

    Yes No X (If "Yes", it must be appended)

    Is a testin,& procedure necessary for the safe acceptance testing (proof testing) of this vessel? [] Yes ~ No ~VT rtat1p.

    I/yes, the written procedure must be approved by the Division Head prior to testing and supplied with this Engineering Note.

    s v .. '2.,=»,-8-v' :1.1 \/U 1AH,.Jtft"f. '$"'~. e..",t,.., G:IJ

    Fermilab ES&H Manual 5033TA-8 Rev. 3/96

    http:PAbou.ec

  • ---

    5. Welding InfonnatiQn

    Has the vessel been fabricated in a Fennilab shop? D

  • -

    By: Russ Rucinski

    3/13/2000

    VACUUM JACKET RELIEF SUMMARY

    PPDV-I0060

    Cases Required Capacity

    1. Discharge Area based on water capacity of inner vessels. eGA 0.11 in"2

    2. Max. LN2 delivery, ruptured pipe 512 scfm Air

    3. Max. Ghe 120 gis, ruptured pipe 570 scfm Air (Ref. Appendix A, case 2, PV note)

    Jacket Relief Device Actual Capacity (see T. Nguyen cales.)

    2" Lift plate relief and 2" piping Min. Area =Apipe =3.65 in"2

    2" Lift plate, 704 scfm Air @ 2 psig set pressure = 2 psig

    (2324 scfm air when vessel @11O% Mawp)

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  • ) ) ) Thang Nguyen

    1/17100

    FIRS,!" c;~~~s.: 1 2" LIFTPLATE CAPACITY CALC. AT20 P61g (R~~r to hand ~/c(J/~~icm she~ts for ref~-'t!flg~) ~~§l!fTI~ !~o:it ~~ Li~ fi1o:ite. reli~ve. ~re~!Jr~ !~ at 29 ps!g. Finq m~ ~l~ r~!~ q~~i ~~ynQ!~~ TUfTI~e.r f!e.. and ~re!S~!Jr~ ~ro~ AP

    I 1

    Given: Po= 20 psig ,... =Viscosity

    Pe=

    :34.67Ipsia14.67 pSia ,p =Density

    d= 2.157 in K = Resistance factor -, . .I60F f = friction factor

    M=

    ! =1 -[

    2~lgram 2a= 5.411§!lin

    ~ := g~~ ! ~I ~.~ P~ • m~ ~Q~~Qro,~ * {~~IfTI}AO.~ i Or

    Qsa =a * 11.4Po (The other two terms became one after substitution)

    a2~38.98I~CFlI I· :SISCFS ···I(SmndarJ/S)Qsa= Re =22700 • q * r I (d • m) I

    p. = 9. 1~04 Lbmlft3

    ,...;:: 0.018 centiJ>oise

    ,... = ~~~~)E~Q4 Lbnlitt·-s I

    Re= 11.21E+081

    ~p =43.~ ! ~ P ci/(d5' K= 2.20~11 f= 0.019

    AP= 8.961111J>~ig

    DESIRED PRESSURE IN TANK = 34~~IP~i9cAiclJLATET~ffK-PRESSURE-~ 28.96111 psig-- -- --. --1-- ---- -- -1--' ------ -- ---, - -.-- - - - ,

    . I . _ DIFFERENCE BETWEEN DESIRED AND CALC. = -5.53889l1:>.sig

    Page 1 of 4 -J

  • ) ) ) Thang Nguyen

    1/17100

    SECQ~[) ~~~~S: I i 1 2" LIFT PLATE CAPACITY ,ALC. AT25 PSIG (Re.fe.r fO h~ncl CJ!JlcLl'~tign sheets for r~(eri!nce) Assume that th~ Li~ Pla!e relieve pr~~~urfil is at 2§ ~i9! Fin~!he. flow r~!~ 9~~! Aeyn0lcls f.1uf1lb~r ~e, an~ pre~~r~ ~rop AP

    Glv~n: I I Po = 25 psig 39.67 psia I I· j.l Viscosity Pe = 14.67 psia I p = Density

    d = 2.157 in IiiK=Aesistance factor t =1 60 F I f =friction factor

    M = 29 gram I ·a =1 5.4119 in2

    ! ::= g~! l11·~ p~ .. [(!I! ~~~~~r~·5 .. (~~1f1l)A~.5Or

    Qsa =a .. 11.4Po I (The other two terms became one after substi.tution) ---.. -. ...... ... - - ..._. - ..... 1 ...., ..-. I I

    Qsa= 2447.47ISCFM 40.791SCFS i(standard ft3/s)

    Ae =2279'l* q * r I (d .. m) I

    p = Q.?()~g ~~rTlI~3 j.l = Q.()1 ~ cl3ntip~~~ j.l = 5.60E-04 Lbmlft • s

    Re = I 1.58E+08

    ~p = ~~.~ ~ K P q2l(~5, I

    K= 2.2081 f= 0.019

    AP= 13.41006lp~ig

    DESIRED PRESSURE IN TANK = 34'~II?~gCALCULATETANlfiiRESSURE-= ~~~~~~ p'~!g--·-~·---ri~---·- T--------r DIFFERENCE BETWEEN DESIRED AND CALC. = 3.9100581psig

    OJPage 2 of4

  • ) ) )

    Thang Nguyen 1/17/00

    T~I~~ ~~~~~; 1 I -1 2" LIEf PLATE CAPA,,'TY CALC. Al22 PilG I (Refer to ha"ct calctll~~ion sh~ets for ref~rf!"ce) I· Assume that me Lift plEit~ reli~ve pre~~ur~ is at gg p.§ig.

    Fil1cj th~ fl~\N ~Ei~~ Q~Eii fleynolcjs l1u!1l!>~r fie I. ancj pr~~lJr~ cj~op aP

    Given: II I I Po - ??'psig ~~.§7 psiEi If.!. = Viscosity Pe -I· 14.671'psia p - Density

    d = 2.1 ~7 il'l I· K= Resistance factor t =1 60. F .. f =friction factor

    M= 2~ 9~am

    a = 5.4119 in2

    ~ :: 9~~ !V·4P~ * [(t, t ~~)l~~o.ro.·~ * (~~1~)I\O.5Or

    Q~~ :: ~ ~ ~ ~ .~~~ I(The. Q!h!lr~o !~~!1l~ ~~Einll:l one Eifter sU!>liititution) I

    2262.38ISCFM 37.711SCFSg~= (~tanc1§lrd fe/~)

    ~~ = ~~?~g * q * ~ I (d * !!I)l

    e='1 ()·1~Q?g ~!>rnI!!3

    J.I. = ()·()1~ (;~l'Iti~Q!~~

    f.!. =1 ~.~OE-04 Lbmlft * s

    Re = I 1.35E+08

    aP =43.5 f K P g2/id5 ---- -1 - K= 2.2081 t= 0.019

    aP= 10.59829I~ig

    DESIRED PRESSURE IN TANK ;: 34~I~~!gCALCUt:ATETANKPRESSURE-;: ~.59~~ ~~ig--------ri- --- -- T--------'T

    DIFFERENCE BETWEEN DESIRED AND CALC. = .1.901713Ipsl9.

    -.J)

    Page 3 of4

  • 1/17/00

    ) ) ) Thang Nguyen

    FO~~TIi G.~~~~ l 2" LlFrpL~TECAPA{t/IT{tf'LC. ~ri1 PSIG (Rf!ff!! to f!~f!I ~/c~/~ticm shfilf!ts for ~f!ff!.~tJlrce) AS~LJmf! melt th~ Lift ~IClte rf!lif!ve ~r~~l!rE3 i~ at 2~ ps.ig. fiflQ ~tl~ flo.~ rCl~ qS.Cl! 8f!yno.!d~ n_uml:>~r 8~! iClrl(i ~rf!s.s.LJr~ QrtlP L\f'

    Given: I j . .- ..Po. = ?~ ps.ig ~7.~7IPSiCl I f! = Viscosity

    Pe = 14.67 pSia p = Density d = ~.1§? il1 I K =Resistance factor t = 60 F f = friction factorI

    M = 2~ grClm I

    a = 5.4119 in2 I

    ! :: 9~! ! 1t~ Po. .. [(t "!' ~~~)I~~OrO.5 .. (~~1rn)"'O.~Or

    Qsa =a" 11.4Po (The other two terms became one after substituti.on)

    Qaa= --~~4~o81~F~ - ..-~~.;3 ~F~-·-1(~tandaTd J .. i3/S) 8~ ~ ~?~ .. q .. ~! (~I" In)

    I

    p = Q:1~§~ ~!>~3 f! = 9·()~ ~ ~flti~Qis.f! f! §.~~-()4 Lbmlft • s

    Re = I 1.43E+08

    ~~::: ~~~~ 1~ Pg'l. !(~r K=. I g.?Q~lf = 0.019

    L\P= 11.4868lps.ig

    DESIRED PRESSURE IN TANK = 34'~I~igCALCULATETANlfpRESSURE-= 34.4868 ps.ig. -. -0.· -1",- ..__ .- -r-- ... _-- ·-l-DIFFERENCE BETWEEN DESIRED AND CALC. = -o.013203~

    o Page 4 of 4

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    ~U'SS RUC.,"':)S((:..I OATE REVISION OATE

    \-\'-\ -00

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  • ----

    Fermilab

    WIlI.IJUIl QUAI.lI' [CATION 'J'UST RECORn

    Weldor's Name L. Nelson Ident. Ne. 47 Dato 9-16-82 W!llding Process (os) (;'rAtl Type Manua~ Tes t in Acco rdancc wi til WPS No. ..........;E55::.!......:1!:.:5~O~O~3~___________

    Material Spec. Spec/Grade No. SA53 B to S.pec/Grade 51\53 D P No. 1 to P No. __1_____ Thick•• 322" Dia • ....,¥G_"___ Filler Motal Spoc. No. A 5.18 Class. No. En 7052 F No.~Backing ~N~O~__________________________________________~________

    Position ________________ Wold Progression ____ .. ___________60 ~I~lpw=a=r~d~ Gas Typo . Argon Composition ______~__ ploctrical Cnnractoristica: Current IlC Polari ty Straight Othor Tb1ckncss RAnge 9uII]1 r1Nt; O.06? - 0,641

    FOR INPORMATION ONLY

    Piller Metal Diameter and Trade Name Linde 6S 1/16, 3/32" Submerged Arc Flux Trade Name __________~n~/~a____________________~--

    . t Gas Metal Arc Welding Shield Gas Trade Name.. __~n~/~a_'______________~__

    \ ;GUIDED BEND TEST RESULTS

    Speciaen No.

    1

    ~

    3 4

    Type

    Root 1"ace, Root

    Face

    Figure No.

    0If-462.3a "",-10"'. ""a _OW-462.3a

    ON-462.3a

    Results

    Acceptable

    A~ep1:.ilD.l.e· .

    ,Accstabl.e Ac:ceptabl.e

    RADIOGRAPHIC TEST RESULTS (FOR ALTERNATIVE' QUALIPICATION BY RADIOGRAPHY)

    Radiographic Results ______~__n~/~aL-_______________________________

    To.t Conducted. by IFR §ngineering Tes~ No. 47445-We certify that tho statements in this record are correct and that the tost welds were prepared, welded and tested in accordace with the ~~quirements of Section IX of the ASME Code.

    http:ON-462.3ahttp:OW-462.3ahttp:0If-462.3a