llllllllllllllllllllllllllllll 5017 -...

15
llllllllllllllllllllllllllllll March 2014 5017 ([or Scheme I Candidates Oni'f) Second Year Higher Secondary Examination Part- Ill BIOLOGY Maximum : 60 Scores Genera/Instructions to Candidates : Time : 2 Hours Cool off time : 20 Minutes Preparatory Time : 5 Minutes • There is a 'cool off time' of 10 minutes each for Botany and Zoology in addition to the writing time of 1 hour each. Further there is '5 minutes' 'Preparatory Time' at the end of the Botany Examination and before the commencement of Zoology Examination. You are not allowed to write your answers nor to discuss. anything with others during the 'cool off time' and 'Preparatory time'. Use the 'cool off time' to get familiar with questions. and to plan your answers. Read questions carefully before answering. All questions are compulsory and only internal choice is allo'(Ved. • · When you select a question, all the sub-questions must be answered from the same question itself. Calculations, figures and graphs should be shown in the answer sheet itself. Malayalam version of the questions is also provided. • Give equations wherever necessary. Electronic devices except non programmable calculators are not allowed in the Examination Hall. · : cmmcwcnm1m n.J2,061m 10 m1ml8 oJI<mo 6161So' CQ5l ro1c002, o. <ll6YlJ n.J <llCfOnS1o n.J roic001 ®2,S60B2,cm®lm6m6cnJ '5 m1m1R"' gJ2"0 §?,@m(()O ffi86§§0J, (()J,Q):)mf) rn'@CfOCQJ oJlmlmcwo mscnmo<llmo n.JOSlg!. §?.®mro60Bcfb nfi)':P2,®J,cm®lm m2,mJ <ll..!l.188j60Bcib ruom5lc006mo. <ll..!lJ 88 j60B cf0c002, o §?,®m(()o nfj) ':P2, ®6Tno. 63(()2, <ll..!lJ 08 jffi ffiJ ffi §?.®m (() 6) Q:l ':P 6 ®8 <fO 6) ® (()6)Ei'fm'm SJ, ®m2, cfb §?.nJ <ll..!lJ 88 j60B§?,O ®CJ<ll<m <ll..!l.J08j ffilm) <m61cm 61<mro61Elfm'mSJ,<llc0061YS<mo6ffi. cfb6ffice£)' _o.Jk<m60Bcfb, · L(f)On.02,cfbcfb, nfj)cm1ru <m61cm §?.6n50m51 ro1c006Tno. 0 <ll..!l.J88_J60Bcfb Q:leJCWO§®m1eJ2,o @"@OJCfOjffi6§§ <nlOeJcnm" ffi)Q:lOJ8cfuj60Bcib 6)cfb8S2,c006Tno. <llln.JOL(f)Offi2,cfucib 63ySJ6)cfbCW6§§ 63(()6 gQeJ<lllc£g06Tn1c:fu §?.n.JcfuroGmru6 o n.J ro"lcfuS:lon.Oogl §?.n.J <ll cwou51c002,0JO® n.JoSl g!. -1-

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Page 1: llllllllllllllllllllllllllllll 5017 - ditto.wsditto.ws/wp-content/uploads/2014/03/HSE-II-Biology-March-2014.pdf• Malayalam version of the questions is also provided. ... Animals

llllllllllllllllllllllllllllll March 2014

5017

([or Scheme I Candidates Oni'f)

Second Year Higher Secondary Examination Part- Ill

BIOLOGY Maximum : 60 Scores

Genera/Instructions to Candidates :

Time : 2 Hours Cool off time : 20 Minutes

Preparatory Time : 5 Minutes

• There is a 'cool off time' of 10 minutes each for Botany and Zoology in addition to the writing time of 1 hour each. Further there is '5 minutes' 'Preparatory Time' at the end of the Botany Examination and before the commencement of Zoology Examination.

• You are not allowed to write your answers nor to discuss. anything with others during the 'cool off time' and 'Preparatory time'.

• Use the 'cool off time' to get familiar with questions.and to plan your answers. • Read questions carefully before answering. • All questions are compulsory and only internal choice is allo'(Ved. • · When you select a question, all the sub-questions must be answered from the

same question itself. • Calculations, figures and graphs should be shown in the answer sheet itself. • Malayalam version of the questions is also provided. • Give equations wherever necessary. • Electronic devices except non programmable calculators are not allowed in the

Examination Hall. · m1m<E~C!b61SY3ci0 :

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-1-

Page 2: llllllllllllllllllllllllllllll 5017 - ditto.wsditto.ws/wp-content/uploads/2014/03/HSE-II-Biology-March-2014.pdf• Malayalam version of the questions is also provided. ... Animals

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Maximum : 30 Scores

Time: 1 Hour

PART -A

BOTANY

Cool off Time : 10 Minutes

1. In flowering plants during double

fertilization two events take place

in the embryosac namely

and ___ _

2. Vidya got a plant which was

affected with a viral disease. Her

objective is to raise a disease

free plant from this infected plant

through tissue culture .

a) Which part of the plant should

be selected as the explant ?

b) State the reason for the

selection of this part as the

explant. (% +%=1 Score)

3. An article in the newspaper reports

that 'Refrigerants like

Chlorofluorocarbons (CFCs) pose

threat to the environment'. How

CFCs are harmful to the

environment? (2 Scores)

5017 ~2-

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CIDJ,cfu. (% o-~-%=1 Score)

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Page 3: llllllllllllllllllllllllllllll 5017 - ditto.wsditto.ws/wp-content/uploads/2014/03/HSE-II-Biology-March-2014.pdf• Malayalam version of the questions is also provided. ... Animals

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4. The species that invade a nude area

are called ___ species. In a

primary succession on rocks, the

group that invade first are usually

(1f2 +%=1 Score)

5. ______ are the enzymes

used for cutting the DNA molecule

into fragments. An example for this

type of enzyme is Eco R I. What

does Eco, Rand I stand for?

(% + 1 %=2 Scores)

6. Plant breeding involves techniques

for manipulating plants in order to

create the desired plant types. State

the steps involved in the production

of a new genetic variety of a crop.

(2 Scores)

5017

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(2 Scores)

Page 4: llllllllllllllllllllllllllllll 5017 - ditto.wsditto.ws/wp-content/uploads/2014/03/HSE-II-Biology-March-2014.pdf• Malayalam version of the questions is also provided. ... Animals

7. The rate of biomass production in

an ecosystem is called productivity.

They are of two types, gross primary

productivity and net primary

productivity. How these two

productivities are related ?

(1 Score}

8. Bt Cotton is regarded as an

important achievement of genetic

engineering. What does Bt stands

for? (1 Score)

9. From the following, select the two

having haploid chromosome

number.

a) egg

b) endosperm

c) zygote

d) pollen. (1 Score)

5017 -4-

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(1 Score)

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a) ®06mDo

(1 Score}

Page 5: llllllllllllllllllllllllllllll 5017 - ditto.wsditto.ws/wp-content/uploads/2014/03/HSE-II-Biology-March-2014.pdf• Malayalam version of the questions is also provided. ... Animals

111111111111 1111111111 11111111

1 0. The density of population in a given

habitat increase or decrease due

to different reasons. Name two

factors responsible for increase in

population in a given area.

(% + %=1 Score)

11. Animals that had their DNA

manipulated to possess and

express foreign DNA are called

transgenic animals. Write briefly

any three benefits of such

transgenic animals to human

beings. (3 Scores)

12. Now a days many farmers are

interested in organic farming.

What is meant by organic farming ?

Can you suggest any two

advantages of organic

farming? (1 + 1 =2 Scores)

5017 -5-

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(% +%=1 Score)

11. ~m)\~c00~16)e.J DNA mJlam oJ6oe&m

m1tm6~~ DNA ~cfb6)cOOJ~§lc006cfuCQJ6o

LoJcfuSl~c006 cB:>CQJ6o 6).DJCf?Pam ®OOJ6)(Q)

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Offi@®tfu 1 e.J6 o CllJ tm6 LoJ cg w J ~ m

60B dO .DJ6(06c001 nti)l:?6®6cfu.

(3 Scores)

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cfuJ611'Sl c006 tm6 6'f'li. nti) mno 61Tl 63om wo

m1ca,u n..oom1o(J)u ? gQ®1@<m Offi@®

(1 +1=2 Scores)

Page 6: llllllllllllllllllllllllllllll 5017 - ditto.wsditto.ws/wp-content/uploads/2014/03/HSE-II-Biology-March-2014.pdf• Malayalam version of the questions is also provided. ... Animals

13. Adaptations are the attributes of the

organism that enables it to survive

and reproduce in its habitat. Give

the adaptations of

a) Cactus plant in desert

b) Kangaroo rat in desert

c) Seals in polar region. (3Scores)

14. Sunflower is pollinated by insects

while rice is pollinated by wind.

a) How these plants are adapted

to their respective type of

pollination method ?

(Hint-any 4 points)

b) Plants can be self or cross

pollinated. Write any two

mechanisms existing in nature

to promote cross pollination.

(4+ 1 =5 Scores)

OR

5017

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13. m1 m <31 ~ OJ 8 rru cru.o eJ ®m1 rlf3 63 ffi6

g16i oJl c00u mm cm1 g16i oJl cOO 8 m6 o rru (l1j) 8

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C151 ®m) ntD 6)(l1j) ~ 80 ?

a) mro6csJm1CQ}l6)eJ cfb:)~m) 6>..!2.151

b) ffiffi6C5~m1CQ}l6)eJ c£bo(f)8ffi6 nmen c) lill60J ln.J<8B<:m60T3~6>eJ rruie.J6c£bcm

(3Scores)

14. OUJ ro jcfb8(l1))1 cw1 rlf3 c£b i S615T3 ~ o 6> m g!1 rlf3

c£b8Rbo n.Jffi8(1)6mo ms®m6ffi16.

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<m7>ffi6<8CW::>g16jffi::>m>1 gQ'D 6>..!2.151

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cfbcm nm 15'6 ®6c£b.

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CW6~~ nffi6>®an1eJ6o rosrrs6 roicm1

cfbcm nm 15'6 ®6 c£b.

( 4+ 1 =5 Scores)

Page 7: llllllllllllllllllllllllllllll 5017 - ditto.wsditto.ws/wp-content/uploads/2014/03/HSE-II-Biology-March-2014.pdf• Malayalam version of the questions is also provided. ... Animals

111111111111111111111111111111

5017

a) The diagram given below shows

the transverse section of a

young anther. Identify the parts

a, b, c and d. (2 Scores}

b) The developmental stages of

male gametes in plants consist

of microsporogenesis and male

gametophyte. Arrange the

following terms in their correct

developmental sequence.

Pollen grain

Sporogenous tissue

anther

microspore tetrad

pollen mother cell

male gamete. (3 Scores}

-7-

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~b 1--+-~~-/----;~--Q

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(2 Scores)

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®6c£h.

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(3 Scores}

Page 8: llllllllllllllllllllllllllllll 5017 - ditto.wsditto.ws/wp-content/uploads/2014/03/HSE-II-Biology-March-2014.pdf• Malayalam version of the questions is also provided. ... Animals

15. A list of different organisms in an

ecosystem are given below.

Arrange them in 181, 2nd, 3rd and

4th trophic level.

i) Phytoplankton

ii) Man

iii) Fish

iv) Zooplankton. (% X4=2 Scores)

16. Use of a thermostable DNA

5017

polymerase from the bacterium,

Thermus aquaticus, made it

possible to generate billion copies

of DNA in a very short time using

a process.

a) Name the process.

b) Name the three important steps

involved in this process.

{% + 1 ¥2=2 Scores)

-8-

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i) 6) 6)ni) (gfP<;kP~ s61i0

ii) mm6n.<.l:ljd0

iii) Q}((ffi) jo

iv) <TUJ<;hpffu's61i0 (% X4=2 Scores)

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6TIJ8~a\lwcw1®l m1cmJ,o eJI51~ <ID8n.J

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226fl58ci%)8cf0 cfu~<WJ,O.

a) gQ'D Ln.Jlcf:b1wwz,6ls (gn.J6)ffimD ?

b) gQ'D ln.Jlcfu1Wm516le.J ln.JW8ffi6l<;tj§

illJCffi6 o.e.J§6WUO Offi6l<ID~Jo ?

(% +1%=2 Scores)

Page 9: llllllllllllllllllllllllllllll 5017 - ditto.wsditto.ws/wp-content/uploads/2014/03/HSE-II-Biology-March-2014.pdf• Malayalam version of the questions is also provided. ... Animals

llllllllllllllllllllllllllllll -

PART-S Maximum : 30 Scores

Time: 1 Hour · ZOOLOGY

Cool off Time : 10 Minutes

1. Observe the diagram, and answer

the questions :

a) Identify A and B.

b) What is the function of C?

c) In which of the marked part

reduction division takes place ?

What is the significance of it ?

1 . .!llll em o m1 roi cth9:fL.g,l m> 8 6> <:? CJ:l o cw 6 em

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a) A, 8 nB)rrni <50(f)6mcf0 ®lro1..g:Jo1

Wc?,c&.,.

b) C CW66>S w&amo nB)(Y(f) ?

C) (ID7)S(Q)8~6lc;tjS6 Q m5J c6lt66)6 rrnM1 en'&

nffiCID6 (50(f)(OI0)6 6lOJ..g:J06ffi 'o1M

dh91cm cu51o..n~cm' mst66)6rrn®?

nB)<Iln06TT>®16l~ ln.J8UJ8ffijo ?

(3 Scores) (3 Scores)

5017 -9-

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111111111111 IIIII IIIII 11111111

2. Classify the diseases given in the

box as two groups based on their

causative organisms. Specify the

type of causative organism for each

group. (2 Scores)

T~hoid,

(g (\):) (J) 60B 6) ~ 5 (ffi() (lJ ~ cili:) (\) 6m Q):) m>

(g (0:) CD 86m2, cO£)~ 6)5 (ffi()S ((lli) :)ffi((510)1 co1l

m 6TY56 ciliJ§ 60Bgpm>1 ®1 m1 c0£l6 cili. 63:::J(gffi:::J

ciliJ3nm6o cili8m6mm8cw (g(\):)(J):)6m6

c0£lcf6 0@®6 oJl c5:::JCD((510)1 co'n6lc;:856 \ffi6

%)6lrm~6®6cili. (2 Scores)

Malaria, Pneumonia, /

Diphtheria,

Amoebiasis

3. One of your neighbour is suffering 3. m1 ool3 §6 6)5 63ffi6 ®0 m> co1l c££):) (\) mu,

grJmcgm l m1 CQ) 60B ~1 co1l 6l.DJ :::Jo1_gJl af&,

Lffi)ClJ60B~6>5 ~co'nc;B:::JBmo, 6l.DJ01m>

cg OJ B m, o11 cO£l o %) rm1 ru ((3'f() m6 cs OJ

from itching, fluid discharge, slight

pain and swelling in genital region.

a) What do you think the disease

he is suffering from ?

b) What measures are to be taken

to prevent such diseases ?

(2 Scores)

5017 -1Q-

6lc;:856\ffi6.

a) ((3Y()CW8~ 6>5 (gffi:::JCDo %)OoKl6)6ffi(l"(}'

ml60B cJ6 ciliffi6 ®6 \ffi6 ?

b) gQ 60T3 6> m cw 6 ~ § <Z m 0 w 60T3 cJ6 ® 5

m>:::JcTO %)6lmD~8o ciliffi6 ®216 cilicf6

o.ffi56c0£l6ffio ? (2 Scores)

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I IIIII II!!' 111111111111111111

4. Explain the phenomenon shown in

the following figure and the reason

for difference in the production of

recombinants in Cross A and Cross B

as explained by Morgan. (3 Scores)

Cross A

y w y•w•

Parental CJ!C3'il~•===c:.n

m "''~-.·. ·· CD y w Yel.low ,wh ite

, cw:=vr===G:J /ItO'" "'·'·*·"'" .o:I,., ........... W

F, generation

5017

y w cm:=:w=~-,.D::l

cm:;::n=====r:co

Par ental type(98. 7%)

y \V w ·l@i ~·:()::) .

, . .... · , .~ ..• ~;, ... . .. :uif . .'.@>

ycllow.whllc

\Vlld type

Recombinant types(l.3%)

y w• I ·· @ @

OR

4. ® 8 6) ~:? cB:>86mlgJl ro1 c006 em ..!l.llL ®0)'"6)1 ~

cru~ _i2_{l c;t:ll-Bdl ro1 cMJ6 em L nJ cm1 @ o cru o o.Jl0llBQ)0cMJ6cfr>W60 'A'' 'B' omcmi <8LcB:>Ocru6cB:>§l~ ~6TlSOcB:>6Cffi 'oi<8cB:>Oo 6DJlmcWc:fu~1~' OJj®jOcruo ruro60JO m6~~ c:fuOro6mo <Bmorow6)qq oJ10llBi c:fuffi6mo (ID(Jffi6cruro1-3] OJ jcOOnmoc006 c:fu.

Gametes

(3Scores)

<¥ xCross B

Parental type(62.8%)

w 111 cw ·· !Pli· (D i• ·< .. .'l ., .. ·,, .j ,,, it .......... ~

White,m!niaturc

w (' :: M

'p; J4 L d . 5o; &

Recombinant types{37 .2%)

, .. ,. w~ - - - .-·n1 I · · ·M ·.- _ .... , . - -~ - - -!~

(t#_ . 4:it<#kotl'Pi~¢. . . ··:~

miniature

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Difference in chromosome number

of some human beings A, B, C and

D are given below :

A) 22 pairs of Autosomes

B) 22 pairs of Autosomes + XO

C) 22 pairs of Autosomes +

1 Autosome

D) 22 pairs of Autosomes + XXY

a) Identify the person who suffers

from Klinefelter's syndrome.

Write its symptoms.

b) Differentiate between

aneuploidy and polyploidy.

(3 Scores)

5. "Prediction of the sequence of

amino acids from the nucleotide

sequence in mRNA is very easy,

but the exact prediction of the

nucleotide sequence in mRNA from

the sequence of amino acids coded

by mRNA is difficult."

5017

a) Which properties of the genetic

code is the reason for the above

condition? Explain.

b) Which are the stop codons in

DNA replication ? (3 Scores)

-12-

111111111111111111111111111111

A, B, C, D omrmi mm6ct!ljro161e.J

C8lcB:.::>mC8cru::>o mmJCSl~ OJj®j::>cruo

®::>611:? 61cB:.::>S6 M'm1 ro1 G006 rm6 0

A) 22 C88l6::>cw1 63::>C8§::>C8cru::>m6ce:.ci0

B) 22 (]g)68CU51 63JC8§8C8(TU8f1t1cB:.ciO + xo C) 22 C88l6::>ru51 63::>C8§::>C8cru::>mJ,ce:.cfO + 1

638C8§::>C8cru::>o

D) 22 C88l6::>ru51 63JC838C8cru::>~ce:.cf0 + XXY

a) '~~ 'cn.5kmC8LCW::>o

6DJ::>u.5l~ OJjcMl551 o.ffi®? mro®161cm

eJ cfu9:16m6N3 cfO om 1:?6 ®6 ce:. 0

b) '®OffiJ1C8g_d::>cillcw1', 'C8o..J::>g£1C8gJ::>

mYru51' g;QOJ ®11ID1e.J6~ OJj®j::>cruo

ommD'? (3 Scores)

5. "m RNA cWle.J6§§ m~g;e1<BW::>616>8 CW16>cm lc£bmic£bffi6m@'m1am m1cm6o, ~6frS::>cB:.6 em mro m1 <Bm::> ar®m51 CW6 ce:,

§6 6> s l ce:. mi ce:. ro 6m o l o..J OJ .!2..11 GOO 6 OJ:)cffi OJ§@(() om§6~Q.'l:)6ffiuo

om em::> am m RNA w ::>am <B ce:. ::> cw 6 @..DJ~ 6>~S6 em mrom1 <Bm::> ar®cru1 CW6 ce:.~@S lcB:.m"lce:.ro6mM'm1am m1rm6o, mro®1m6 ce:.::>ro6mm::>w m~g;e1cgw::; 6>6>8CW6cfu~6)S lc£bmice:.ro6mo ~®j Q) 8 W1 om 1:?6 ® 6 OJ 8 cffi 6DJ6 BD1 ffi6

§861'l)o''

a) ' 8l6 m1 <ID ce:. <B ce:. ::> cw16> ~ ' o.ffi ® 6 (l()j@80J6N3§861'l) m6ce:.g£1am o..JO 6W®1 ro1 G006 em mro ru cmo ~6 cfu8(()6ffio ? oJl(J()Bffi8c006cfbo

b) 'DNA oJlne.JsmM'm1am' ~§§ '(]~:}~u (]cfu:}(](U):)6ffi6cfuci0 l

o.ffi61®5?Jpo ? (3 Scores)

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11111111111111111 11 1! 11 1111

6. Diagrammatic representation of ·central dogma' is given below: Observe the diagram carefully and redraw it making appropriate corrections. (1 Score)

translation mRNA

7. The meaning of 'antibiotics' is 'against life', whereas with reference to human beings they are 'pro life' . Substantiate the statement with suitable example. (2 Scores)

8. Observe the diagram and answer the questions :

5017

a) Identify the process shown in the figure and define it.

b) Identify the structure B. Write any one function of it in the process shown in the diagram.

(2Scores)

B-®re e @

6. '61<m\ffiLSaiTl <ZCW8cm' 61<!2> <mJ_nllc;rll c006 rm <Z ro6l.J 8 ..!2.11L cmo ®8 61"9 61c£h8S6 mm1 ro1 c006 rm6. _nll l em o <m J cfuti! m 8 CQ)l mlroi~-e,l <Zm>8~-ed cm1ffi6CO'®e.J6c£hcm 0Jffi6@m1 n.Jc£hcDC0'®1 (lJ(O~cfu.

(1 Score)

transcription ) Protein

-13-

7 • ffi'@ ~16Yll (g m> 8 31 cOOU om rm (lJ 8 c001 mffiL.Oo ·~irumu nffi®1ffi' nffi(ffi86ffiu, O{Drm8aiT> ffiffi6nS1j@ffi <mo6YllmD1 -:3J)s<Zcm-ID8~o mm® ·~rum mmm6cfuJel ffi8m>®' ffi'©GlT)'. <Zm>8gyil-ed ~B8nDffi6ffi <mn.o1cmo ~'U l n.JC'Q?80J ffi6)<!2> <TU8WJ cfuffi1 c006 cfu.

(2 Scores)

8. _nllLcmo m1roidM{].~~i, cmrm1m1c006rm <Z.!l.J8Bj6m3c/O~ ~@mffi6)ffi':P6®6c£h.

a) _nllLcmmm1am cfu86TD1-Wm1c006rm LnJLcfu1m> nffi61CIDmi' <m1ro1~o16Wfl5) m1 mru..!2.11 c:006 c£b.

b) '8' <1ffi on & 0 (f)o <m1 ro1-:3,d o1srmf, .!li1L <m mm1 am c£b 8 6m1 _gJl ro1 c00 6 em Ln.JLcfu1m>mflarn mm<m161~ 63ro6 wma:mo nffi196®6cfb. (2 Scores)

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9. Prepare a pamphlet for an

awareness programme in your

school about the measures to

prevent and control a lcohol and

drug abuse in adolescents.

(2 Scores)

10. Expand the fol lowing abbreviations

which are commonly used in

reproductive health :

\A"'­a, . Kl

b) .ZiFT. (1 Score)

11 . "i\Jature prov ides all for the need of

man but not for his greed."

a) Do you agree with this statement?

Justify your answer.

b) Distinguish between two types

of biodiversity conservations.

(3 Scores)

12. "Gopalan argues that if father is of

'A' blood group, mother is of 'B'

blood group. Their children can only

be 'A' group, B group or 'AB' group."

5017

a) Do you agree with Gopalan's

Argument ?

b) Give reason for your answer.

(2 Scores)

-14-

llllllllllllllllllllllllllllll

9. CWJ,OJ8c00~6)eJ rllBj<mm1~~CW6o , rllCW cOOJ,rll COJ, cm1 ~~CW6o B6COJ,o.J ~CQ)::>(J)o ®SCWJ,cm®1m6o, ffilcwLm)lcOOJ,cm®1mJ,o ~ OJ 6ft51 nffi s 6 ~ c00 6ft5 m ::> «>(f) 6013 6) ~ cfbJ,01~" m16013~6>s m5'cOOJ~cun ms W®J, em ~ 6YlJ 8 WOJ ro'OcOOco6ffi o.J co1 o.J ::> s1~ ~OJ6f@1 63COJ, 'nJ::>o6>eJR' m1roam1

cOOJ,cfb . (2 Scores)

10. ' Ol6>Lo.J8CW~io16>nDro'O<mm1ro'O' rro8W::> (() 6ffi ~ nJ ~ CQ) ::>(1)1 cOOJ, ffi) ..!lJ6 (06 6)c00':PJ, Mmu ®86>':P ®cm1co1cOOJ,ffi)J,. !m?>®16>~

o.J~ ffi EiJ,lrlCO~ o.Jo %) ':PJ, ®J, c£b.

a) ART

b) ZIFT. (1 Score)

11. ' \o.Jcfb~®1 mmJ,oS:1jm" ro®OJCR>jrll6~~

6>®~::>o mafOce:,J,cmJ,, %Jcm8rn'O !m?>®j::> l(J)nD~ffiJ,~~®~."

a) g;Q'D lo...l<lJ?::>rum~cw::>s m16013ci0 ~cw8grJjc006cm6~6ft5::> ? m16013~6>s ~cmmcoo rro::>w~ce:,co1c006cfb .

b) C06ft5J, ®COM"m1el6~~ 1 6>6>~0J 6) 6) OJ <Lil w j ffi) 0 (() dh9:16ffi 6013 cJO ®am1eJJ,~~ OJj®j::>rroo OJj&IDrll::>

cOOJ,cfb. (3 Scores)

12 . "!m?>::;?dOO 'A' CO&IDl(f)J<J::!!>O, !m?)QID 'B'

co &ID l (f)~ CJ:j6 o ro® cw ::> rn'O m c00 cJ0 ' A'

l(J)~~c;tj::> , 'B' l(J)~~c;tj::> 'AB' l(J)~~c;tP rll::>L®o ro®CQ)]c6lc006o %Jcm::>6Tli' ~(J)::>o.J::>

eJ6>~ OJ::>Bo"

a) ml6!5Bci0 ~(J)::>o.J::>eJ6>~ OJ8B~Mm::>S

~CQ):)grJj c006 ffi)6 ~6ft5::> ?

b) m16013~6>s ~mmcomm1m ce:,::>co6ffi

6>rll':PJ,®6cfb. (2 Scores)

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llllllllllllllllllllll llllliil 13. Given below is the diagrammatic

representation of the operation of Natural Selection on different traits.

a) Identify the type of natural selection A, B and C with explanation of each.

b) Define Hardy-Weinberg Principle. (4 Scores)

. /

5017

~ · +:··· ·· - ~ ;; >:-..

!l<········ :• ·.<•. · ~ .. ' . ~l~ctit?I}:; . b i3 .0 ·~ ~ ~= z

-15-

13. OJj®j~ g?6ffi1®cfu ()1)j@~OJ06T3§?,61S lo.J~®1 m1ffiBD~ffi6TDo ()1)~1<;tjlcOOJ,ITn C8ffi6ll~.!lill®o ®:::J6/\j) 6/cfu~SJ,(m)1m1 cOOJ,CffiJ,.

a) A, B, C o.GJrm1 ru nffi®J,®ffio Lo.J~®1 m1ffiBD:::>ffi6TD61(m) IT04.,!Lll ~cOOJ,ITnJ, ? 63~C8ffi~ffi)J,o oJI(J()G Q):::JcOOJ,cfu.

b) • nD~mru5l o.11 cm6ill &0 Ln.J1cmm5l?-Jl&.' mlffiQdill1cOOJ,cfu. (4 :t;~:, .)f\-'~-'::)

(.4)

(C)