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    Pruebas del paquete listings

    1 \begin{displaymath}

    2 \oint_{S}\vec{E}\cdot d\vec{S}=\frac{q}{\

    epsilon_{0}}

    3 \end{displaymath}

    S

    E dS=q

    0

    1 \begin{trivlist}

    2 \item\input{\jobname.exa}

    3 \end{trivlist}

    Let H be a Hilbert space, C be a closed

    bounded convex subset ofH, T a nonex-

    pansive self map of C. Suppose that asn , an,k 0 for each k, and n =

    k=0(an,k+1 an,k)

    + 0. Then foreach x in C, Anx =

    k=0an,kT

    kx con-

    verges weakly to a fixed point ofT .

    The numbered equation

    uttu+u5+u |u|p2 = 0 inR3[0,[

    (1)

    is automatically numbered as equation 2.

    Let $H$ be a Hilbert space, $C$ be a closed bounde

    a nonexpansive self map of $C$. Suppose that as $n

    $a_{n,k}\rightarrow0$ for each $k$, and $\gamma_{na_{n,k+1}-a_{n,k}\right) {+}\rightarrow0$. Then

    $A_{n}x=\sum_{k=0}{\infty}a_{n,k}T{k}x$ converge

    $T$ .

    The numbered equation

    \begin{equation}

    u_{tt}-\Delta u+u{5}+u\left| u\right| {p-2}=0\

    {3}\times\left[ 0,\infty\right[ \label{eqn1}%

    \end{equation}

    is automatically numbered as equation \ref{eqn1}.

    1 Let $H$ be a Hilbert space, $C$ be a

    closed bounded convex subset of $H$,

    $T$

    2 a nonexpansive self map of $C$. Supposethat as $n\rightarrow\infty$,

    3 $a_{n,k}\rightarrow0$ for each $k$, and

    $\gamma_{n}=\sum_{k=0}{\infty}\left

    (

    4 a_{n,k+1}-a_{n,k}\right) {+}\rightarrow

    0$. Then for each $x$ in $C$,

    5 $A_{n}x=\sum_{k=0}{\infty}a_{n,k}T{k}x$

    converges weakly to a fixed pointof

    6 $T$ .

    7

    8 The numbered equation

    9 \begin{equation}

    10 u_{tt}-\Delta u+u{5}+u\left| u\right|

    {p-2}=0\text{ in }\mathbf{R}%

    11 {3}\times\left[ 0,\infty\right[ \label{eqn1} %

    12 \end{equation}

    13 is automatically numbered as equation \ref{eqn1}.

    Let H be a Hilbert space, C be a closedbounded convex subset ofH, T a nonex-

    pansive self map of C. Suppose that as

    n , an,k 0 for each k, and n =

    k=0(an,k+1 an,k)

    + 0. Then foreach x in C, Anx =

    k=0an,kT

    kx con-

    verges weakly to a fixed point ofT .

    The numbered equation

    uttu+u5+u |u|p2 = 0 inR3[0,[

    (2)

    is automatically numbered as equation 2.

    1

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    1 \begin{equation}

    2 \forall x \in \mathbf{R}:

    3 \qquad x{2} \geq 0

    4 \end{equation}

    x R : x2 0 (3)

    1 \begin{displaymath}

    2 x{2} \geq 0\qquad

    3 \textrm{para todo }x\in\mathbb{R}

    4 \end{displaymath}

    x2 0 para todo x R

    Codigo de este archivo

    \documentclass{article}

    \usepackage{amsmath}

    \usepackage{amsthm}

    \usepackage[latin1]{inputenc}

    \usepackage[normalbf,normalem]{ulem}

    \usepackage{titlesec}

    \usepackage{titletoc}

    \usepackage{amsbsy}

    \usepackage{multicol}

    \usepackage{fancyhdr}

    \usepackage{extramarks}

    \usepackage{amsfonts}

    \usepackage{amssymb}

    \usepackage{times}

    \usepackage[activeacute,spanish]{babel}

    \usepackage{color}

    \usepackage{verbatim}

    \usepackage{listings}

    \definecolor{gray97}{gray}{.97}

    \definecolor{gray85}{gray}{.95}

    \definecolor{gray75}{gray}{.75}

    \definecolor{gray45}{gray}{.45}

    \definecolor{yellow57}{rgb}{1.00,1.00,0.84}

    \lstset{ frame=Ltb,

    framerule=0pt,aboveskip=0.5cm,

    framextopmargin=3pt,

    framexbottommargin=3pt,

    framexleftmargin=0.4cm,

    framesep=0pt,

    2

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    rulesep=.4pt,

    backgroundcolor=\color{gray97},

    rulesepcolor=\color{black},

    %

    stringstyle=\ttfamily,

    showstringspaces = false,

    basicstyle=\small\ttfamily,

    commentstyle=\color{gray45},

    keywordstyle=\bfseries,

    %

    numbers=left,

    numbersep=15pt,

    numberstyle=\tiny,

    numberfirstline = false,

    breaklines=true,

    }

    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

    % minimizar fragmentado de listados

    \lstnewenvironment{listing}[1][]

    {\lstset{#1}\pagebreak[0]}{\pagebreak[0]}

    \lstdefinestyle{consola}

    {basicstyle=\scriptsize\bf\ttfamily,

    backgroundcolor=\color{blue57},

    }

    \lstdefinestyle{L}

    {language=TeX,}

    % y en la derecha la composicion.

    %

    % \begin{example}

    % \Large Esto es grande

    % \end{example}

    %

    % Esta parte procede de verbaim.sty de FMi

    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

    \makeatletter

    \newwrite\solution@stream

    \openout\solution@stream=\jobname.solutions

    \newcounter{problem}\newcommand*{\problemname}{Problem}

    \newcommand{\problem}[1]{%

    \refstepcounter{problem}%

    \problemname\theproblem:\enskip#1\par

    3

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    }

    \newcommand{\solution}[1]{%

    \protected@write\solution@stream{}{%

    \protect\print@solution{\theproblem}{#1}%

    }%

    }

    \newcommand*{\printsolutions}{%

    \closeout\solution@stream

    \makeatletter

    \InputIfFileExists{\jobname.solutions}{}{}%

    \makeatother

    }

    \newcommand*{\solutionname}{Solution}

    \newcommand{\print@solution}[2]{%

    \solutionname#1:\enskip#2\par

    }

    %\makeatother

    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

    %\makeatletter

    %\def\ThisFile{\yorname}%\let\OldInput\input

    %\renewcommand{\input}[1]{%

    % \renewcommand{\ThisFile}{#1}%

    % \OldInput{#1}%

    %}

    \newwrite\ejercicio@out

    \newenvironment{ejercicio}%

    {\begingroup% Lets Keep the Changes Local

    \@bsphack

    \immediate\openout \ejercicio@out \jobname.exa

    \let\do\@makeother\dospecials\catcode\M\active

    \def\verbatim@processline{%

    \immediate\write\ejercicio@out{\the\verbatim@line}}%\verbatim@start}%

    {\immediate\closeout\ejercicio@out\@esphack\endgroup%

    %

    % Y aqui lo que se ha anadido

    %

    4

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    \par\small\addvspace{3ex plus 1ex}\vskip -\parskip

    \noindent

    \makebox[0.45\linewidth][l]{%

    \begin{minipage}[t]{0.45\linewidth}

    \vspace*{-2ex}

    \setlength{\parindent}{0pt}

    \setlength{\parskip}{1ex plus 0.4ex minus 0.2ex}

    \begin{trivlist}

    \item\input{\jobname.exa}

    \end{trivlist}

    \end{minipage}}%

    \hfill%

    \makebox[0.5\linewidth][l]{%

    \begin{minipage}[t]{0.50\linewidth}

    \vspace*{-1ex}

    \verbatiminput{\jobname.exa}

    \end{minipage}}

    \par\addvspace{3ex plus 1ex}\vskip -\parskip

    }

    %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

    \newwrite\example@out

    \newenvironment{example}%

    {\begingroup% Lets Keep the Changes Local

    \@bsphack

    \immediate\openout \example@out \jobname.exa\let\do\@makeother\dospecials\catcode\M\active

    \def\verbatim@processline{%

    \immediate\write\example@out{\the\verbatim@line}}%

    \verbatim@start}%

    {\immediate\closeout\example@out\@esphack\endgroup%

    \makeatother

    %% Y aqui lo que se ha anadido

    %

    \par\small\addvspace{3ex plus 1ex}\vskip -\parskip

    \noindent

    \makebox[0.5\linewidth][l]{%

    \hspace*{+2ex}

    \setlength{\parindent}{0pt}\setlength{\parskip}{1ex plus 0.4ex minus 0.7ex}

    \begin{minipage}[t]{0.50\linewidth}

    % \vspace*{-1ex}

    \vspace*{-2ex}

    5

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    \lstinputlisting[style=L, basicstyle=\scriptsize\bf\ttfamily,

    backgroundcolor=\color{yellow57},]{\jobname.exa}

    %\verbatiminput{\jobname.exa}

    \end{minipage}}

    \hfill

    \hspace{10pt}%

    \makebox[0.45\linewidth][l]{%

    \begin{minipage}[t]{0.45\linewidth}

    \vspace*{-2ex}

    \setlength{\parindent}{0pt}

    \setlength{\parskip}{1ex plus 0.4ex minus 0.7ex}

    \begin{trivlist}

    \item\input{\jobname.exa}

    \end{trivlist}

    \end{minipage}}%

    \par\addvspace{3ex plus 1ex}\vskip -\parskip

    }

    \begin{document}

    Pruebas del paquete listings

    \begin{example}

    $$\oint_{S}\vec{E}\cdot d\vec{S}=\frac{q}{\epsilon_{0}} $$

    \end{example}

    \begin{lstlisting}[style=L]\begin{trivlist}

    \item\input{\jobname.exa}

    \end{trivlist}

    \end{lstlisting}

    \begin{ejercicio}

    Let $H$ be a Hilbert space, $C$ be a closed bounded convex subset of $H$,

    a nonexpansive self map of $C$. Suppose that as $n\rightarrow\infty$,

    $a_{n,k}\rightarrow0$ for each $k$, and $\gamma_{n}=\sum_{k=0}{\infty}\le

    a_{n,k+1}-a_{n,k}\right) {+}\rightarrow0$. Then for each $x$ in $C$,

    $A_{n}x=\sum_{k=0}{\infty}a_{n,k}T{k}x$ converges weakly to a fixed poin

    $T$ .

    The numbered equation\begin{equation}

    u_{tt}-\Delta u+u{5}+u\left| u\right| {p-2}=0\text{ in }\mathbf{R}%

    {3}\times\left[ 0,\infty\right[ \label{eqn1}%

    \end{equation}

    is automatically numbered as equation \ref{eqn1}.

    6

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    \end{ejercicio}

    \begin{example}

    Let $H$ be a Hilbert space, $C$ be a closed bounded convex subset of $H$,

    a nonexpansive self map of $C$. Suppose that as $n\rightarrow\infty$,

    $a_{n,k}\rightarrow0$ for each $k$, and $\gamma_{n}=\sum_{k=0}{\infty}\le

    a_{n,k+1}-a_{n,k}\right) {+}\rightarrow0$. Then for each $x$ in $C$,

    $A_{n}x=\sum_{k=0}{\infty}a_{n,k}T{k}x$ converges weakly to a fixed poin

    $T$ .

    The numbered equation

    \begin{equation}

    u_{tt}-\Delta u+u{5}+u\left| u\right| {p-2}=0\text{ in }\mathbf{R}%

    {3}\times\left[ 0,\infty\right[ \label{eqn1}%

    \end{equation}

    is automatically numbered as equation \ref{eqn1}.

    \end{example}

    \begin{example}

    \begin{equation}

    \forall x \in \mathbf{R}:

    \qquad x{2} \geq 0

    \end{equation}

    \end{example}

    \begin{example}

    \begin{displaymath}

    x{2} \geq 0\qquad

    \textrm{para todo }x\in\mathbb{R}

    \end{displaymath}\end{example}

    7