lesson 4: solving for unknown angles using equations

11
NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4 Lesson 4: Solving for Unknown Angles Using Equations 44 This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015 This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License. Lesson 4: Solving for Unknown Angles Using Equations Student Outcomes Students solve for unknown angles in word problems and in diagrams involving all learned angle facts. Classwork Opening Exercise (5 minutes) Opening Exercise The complement of an angle is four times the measurement of the angle. Find the measurement of the angle and its complement. + = = ( )= ( ) = Complementary โˆ s The measurement of the angle is ยฐ. The measurement of the complement of the angle is ยฐ. In the following examples and exercises, students set up and solve an equation for the unknown angle based on the relevant angle relationships in the diagram. Encourage students to list the appropriate angle fact abbreviation for any step that depends on an angle relationship. Example 1 (4 minutes) Two options are provided here for Example 1. The second is more challenging than the first. Example 1 Find the measurements of โˆ  and โˆ . + + = + = + โˆ’ = โˆ’ = ( )= ( ) = Vert. โˆ s The measurement of โˆ : ()ยฐ = ยฐ The measurement of โˆ : ()ยฐ = ยฐ Scaffolding: As in earlier lessons, tasks such as the Opening Exercise can be scaffolded into parts as follows: Explain the angle relationships in the diagram. Write the equation. Explain how the equation represents the diagram, including particular parts. Solve the equation. Interpret the solution, and determine if it is reasonable.

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Page 1: Lesson 4: Solving for Unknown Angles Using Equations

NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4

Lesson 4: Solving for Unknown Angles Using Equations

44

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015

This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Lesson 4: Solving for Unknown Angles Using Equations

Student Outcomes

Students solve for unknown angles in word problems and in diagrams involving all learned angle facts.

Classwork

Opening Exercise (5 minutes)

Opening Exercise

The complement of an angle is four times the measurement of the angle. Find the measurement

of the angle and its complement.

๐’™ + ๐Ÿ’๐’™ = ๐Ÿ—๐ŸŽ

๐Ÿ“๐’™ = ๐Ÿ—๐ŸŽ

(๐Ÿ

๐Ÿ“) ๐Ÿ“๐’™ = (

๐Ÿ

๐Ÿ“) ๐Ÿ—๐ŸŽ

๐’™ = ๐Ÿ๐Ÿ–

Complementary โˆ s

The measurement of the angle is ๐Ÿ๐Ÿ–ยฐ.

The measurement of the complement of the angle is ๐Ÿ•๐Ÿยฐ.

In the following examples and exercises, students set up and solve an equation for the

unknown angle based on the relevant angle relationships in the diagram. Encourage

students to list the appropriate angle fact abbreviation for any step that depends on an

angle relationship.

Example 1 (4 minutes)

Two options are provided here for Example 1. The second is more challenging than the first.

Example 1

Find the measurements of โˆ ๐‘ญ๐‘จ๐‘ฌ and โˆ ๐‘ช๐‘จ๐‘ซ.

๐Ÿ๐’™ + ๐Ÿ”๐’™ + ๐Ÿ—๐ŸŽ = ๐Ÿ๐Ÿ•๐ŸŽ

๐Ÿ–๐’™ + ๐Ÿ—๐ŸŽ = ๐Ÿ๐Ÿ•๐ŸŽ

๐Ÿ–๐’™ + ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ—๐ŸŽ = ๐Ÿ๐Ÿ•๐ŸŽ โˆ’ ๐Ÿ—๐ŸŽ

๐Ÿ–๐’™ = ๐Ÿ–๐ŸŽ

(๐Ÿ

๐Ÿ–) ๐Ÿ–๐’™ = (

๐Ÿ

๐Ÿ–) ๐Ÿ–๐ŸŽ

๐’™ = ๐Ÿ๐ŸŽ

Vert. โˆ s

The measurement of โˆ ๐‘ญ๐‘จ๐‘ฌ: ๐Ÿ(๐Ÿ๐ŸŽ)ยฐ = ๐Ÿ๐ŸŽยฐ

The measurement of โˆ ๐‘ช๐‘จ๐‘ซ: ๐Ÿ”(๐Ÿ๐ŸŽ)ยฐ = ๐Ÿ”๐ŸŽยฐ

Scaffolding:

As in earlier lessons, tasks such as the Opening Exercise can be scaffolded into parts as follows:

Explain the angle

relationships in the

diagram. Write the

equation. Explain how the

equation represents the

diagram, including

particular parts. Solve the

equation. Interpret the

solution, and determine if

it is reasonable.

Page 2: Lesson 4: Solving for Unknown Angles Using Equations

NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4

Lesson 4: Solving for Unknown Angles Using Equations

45

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015

This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

3xยฐ

(x+64)ยฐ

Two lines meet at a point. List the relevant angle relationship in the diagram. Set up

and solve an equation to find the value of ๐’™. Find the measurement of one of the

vertical angles.

Students use information in the figure and a protractor to solve for ๐‘ฅ.

i) Students measure a 64ยฐ angle as shown; the remaining portion of the angle must

be ๐‘ฅยฐ (โˆ s add).

ii) Students can use their protractors to find the measurement of ๐‘ฅยฐ and use this

measurement to partition the other angle in the vertical pair.

As a check, students should substitute the measured ๐‘ฅ value into each expression and

evaluate; each angle of the vertical pair should be equal to the other. Students can also use

their protractor to measure each angle of the vertical angle pair.

With a modified figure, students can write an algebraic equation that they have the skills to solve.

๐Ÿ๐’™ = ๐Ÿ”๐Ÿ’

(๐Ÿ

๐Ÿ) ๐Ÿ๐’™ = (

๐Ÿ

๐Ÿ) ๐Ÿ”๐Ÿ’

๐’™ = ๐Ÿ‘๐Ÿ

Vert. โˆ s

Measurement of each angle in the vertical pair: ๐Ÿ‘(๐Ÿ‘๐Ÿ)ยฐ = ๐Ÿ—๐Ÿ”ยฐ

Extension:

๐Ÿ‘๐’™ = ๐’™ + ๐Ÿ”๐Ÿ’

๐Ÿ‘๐’™ โˆ’ ๐’™ = ๐’™ โˆ’ ๐’™ + ๐Ÿ”๐Ÿ’

๐Ÿ๐’™ = ๐Ÿ”๐Ÿ’

(๐Ÿ

๐Ÿ) ๐Ÿ๐’™ = (

๐Ÿ

๐Ÿ) ๐Ÿ”๐Ÿ’

๐’™ = ๐Ÿ‘๐Ÿ

vert. โˆ s

Measurement of each angle in the vertical pair: ๐Ÿ‘(๐Ÿ‘๐Ÿ)ยฐ = ๐Ÿ—๐Ÿ”ยฐ

MP.7

64ยฐxยฐ

xยฐ

xยฐ

xยฐ

Page 3: Lesson 4: Solving for Unknown Angles Using Equations

NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4

Lesson 4: Solving for Unknown Angles Using Equations

46

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015

This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Exercise 1 (4 minutes)

Exercise 1

Set up and solve an equation to find the value of ๐’™. List the relevant angle relationship in the diagram. Find the

measurement of one of the vertical angles.

Students use information in the figure and a protractor to solve for ๐‘ฅ.

i) Measure a 132ยฐ angle as shown; the remaining portion of

the original angle must be ๐‘ฅยฐ (โˆ s add).

ii) Partition the other angle in the vertical pair into equal angles

of ๐‘ฅยฐ.

Students should perform a check (as in Example 1) before solving an

equation that matches the modified figure.

Extension:

๐Ÿ’๐’™ = ๐Ÿ๐Ÿ‘๐Ÿ

(๐Ÿ

๐Ÿ’) ๐Ÿ’๐’™ = (

๐Ÿ

๐Ÿ’) ๐Ÿ๐Ÿ‘๐Ÿ

๐’™ = ๐Ÿ‘๐Ÿ‘

vert. โˆ s

Measurement of each vertical angle: ๐Ÿ“(๐Ÿ‘๐Ÿ‘)ยฐ = ๐Ÿ๐Ÿ”๐Ÿ“ยฐ

Note: Students can check their answers for any question by measuring each unknown angle with a protractor, as all

diagrams are drawn to scale.

Example 2 (4 minutes)

Example 2

Three lines meet at a point. List the relevant angle relationships in the diagram. Set up and solve an equation to find the

value of ๐’ƒ.

Let ๐’ƒ = ๐’„.

๐’„ + ๐Ÿ‘๐Ÿ• + ๐Ÿ’๐Ÿ‘ = ๐Ÿ๐Ÿ–๐ŸŽ

๐’„ + ๐Ÿ–๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ

๐’„ + ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ–๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ–๐ŸŽ

๐’„ = ๐Ÿ๐ŸŽ๐ŸŽ

โˆ s on a line

Since ๐’ƒ = ๐’„, ๐’ƒ = ๐Ÿ๐ŸŽ๐ŸŽ.

5xยฐ

(x+132)ยฐ

37ยฐ

bยฐ

43ยฐ๐’„หš

Page 4: Lesson 4: Solving for Unknown Angles Using Equations

NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4

Lesson 4: Solving for Unknown Angles Using Equations

47

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015

This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Exercise 2 (4 minutes)

Students set up and solve an equation for the unknown angle based on the relevant angle relationships in the diagram.

List the appropriate angle fact abbreviation in the initial equation.

Exercise 2

Two lines meet at a point that is also the endpoint of two rays. List the relevant angle

relationships in the diagram. Set up and solve an equation to find the value of ๐’ƒ.

๐’ƒ + ๐Ÿ—๐Ÿ“ = ๐Ÿ—๐ŸŽ + ๐Ÿ–๐ŸŽ

๐’ƒ + ๐Ÿ—๐Ÿ“ = ๐Ÿ๐Ÿ•๐ŸŽ

๐’ƒ + ๐Ÿ—๐Ÿ“ โˆ’ ๐Ÿ—๐Ÿ“ = ๐Ÿ๐Ÿ•๐ŸŽ โˆ’ ๐Ÿ—๐Ÿ“

๐’ƒ = ๐Ÿ•๐Ÿ“

Vert. โˆ ๐’”

Example 3 (6 minutes)

Students set up and solve an equation for the unknown angle based on the relevant angle relationship in the question.

In this case, suggest that students use the words angle and supplement as placeholders in their equations. Students can

use a tape diagram to solve for the unknown angles.

Example 3

The measurement of an angle is ๐Ÿ

๐Ÿ‘ the measurement of its supplement. Find the measurements of the angle and its

supplement.

๐š๐ง๐ ๐ฅ๐ž =๐Ÿ

๐Ÿ‘(๐ฌ๐ฎ๐ฉ๐ฉ๐ฅ๐ž๐ฆ๐ž๐ง๐ญ)

๐š๐ง๐ ๐ฅ๐ž =๐Ÿ

๐Ÿ‘(๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐š๐ง๐ ๐ฅ๐ž)

Using a tape diagram:

The measurements of the two supplementary angles that satisfy these criteria are ๐Ÿ•๐Ÿยฐ and ๐Ÿ๐ŸŽ๐Ÿ–ยฐ.

The tape diagram model is an ideal strategy for this question. If students are not familiar with the tape diagram model,

use a Guess and Check table with them. Here is an example of such a table with two entries for guesses that did not

result in a correct answer.

Guess ๐Ÿ

๐Ÿ‘(๐†๐ฎ๐ž๐ฌ๐ฌ) Sum (should be ๐Ÿ๐Ÿ–๐ŸŽยฐ)

60 2

3(60) = 40 60 + 40 = 100; not the answer

90 2

3(90) = 60 90 + 60 = 150; not the answer

95ยฐ

80ยฐbยฐ

๐Ÿ๐Ÿ–๐ŸŽ

angle

supplement

๐Ÿ“ units = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ unit = ๐Ÿ‘๐Ÿ”

๐Ÿ units = ๐Ÿ•๐Ÿ

๐Ÿ‘ units = ๐Ÿ๐ŸŽ๐Ÿ–

Page 5: Lesson 4: Solving for Unknown Angles Using Equations

NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4

Lesson 4: Solving for Unknown Angles Using Equations

48

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015

This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

๐Ÿ—๐ŸŽ

angle

complement

Exercise 3 (5 minutes)

Students set up and solve an equation for the unknown angle based on the relevant angle relationship in the question.

In this case, suggest that students use the words angle and complement as placeholders in their equations. Students can

use a tape diagram to solve for the unknown angles.

Exercise 3

The measurement of an angle is ๐Ÿ

๐Ÿ’ the measurement of its complement. Find the measurements of the two

complementary angles.

๐š๐ง๐ ๐ฅ๐ž =๐Ÿ

๐Ÿ’(๐œ๐จ๐ฆ๐ฉ๐ฅ๐ž๐ฆ๐ž๐ง๐ญ)

๐š๐ง๐ ๐ฅ๐ž =๐Ÿ

๐Ÿ’(๐Ÿ—๐ŸŽ โˆ’ ๐š๐ง๐ ๐ฅ๐ž)

Using a tape diagram:

Example 4 (4 minutes)

Example 4

Three lines meet at a point that is also the endpoint of a ray. List the relevant angle relationships in the diagram. Set up

and solve an equation to find the value of ๐’›.

Let ๐’™ยฐ be the measurement of the indicated angle.

๐’™ + ๐Ÿ—๐ŸŽ + ๐Ÿ๐Ÿ— = ๐Ÿ๐Ÿ–๐ŸŽ

๐’™ + ๐Ÿ๐Ÿ๐Ÿ— = ๐Ÿ๐Ÿ–๐ŸŽ

๐’™ + ๐Ÿ๐Ÿ๐Ÿ— โˆ’ ๐Ÿ๐Ÿ๐Ÿ— = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ๐Ÿ๐Ÿ—

๐’™ = ๐Ÿ”๐Ÿ

โˆ s on a line

๐’› = ๐’™ + ๐Ÿ—๐ŸŽ

๐’› = ๐Ÿ”๐Ÿ + ๐Ÿ—๐ŸŽ

๐’› = ๐Ÿ๐Ÿ“๐Ÿ

โˆ s add

๐Ÿ“ units = ๐Ÿ—๐ŸŽ

๐Ÿ unit = ๐Ÿ๐Ÿ–

๐Ÿ’ units = ๐Ÿ•๐Ÿ

The measurements of the two complementary

angles that satisfy these criteria are ๐Ÿ๐Ÿ–ยฐ and ๐Ÿ•๐Ÿยฐ.

zยฐ

29ยฐ๐’™ยฐ

Page 6: Lesson 4: Solving for Unknown Angles Using Equations

NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4

Lesson 4: Solving for Unknown Angles Using Equations

49

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015

This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Exercise 4 (4 minutes)

Exercise 4

Two lines meet at a point that is also the vertex of an angle. Set up and solve an equation to find the value of ๐’™. Find the

measurements of โˆ ๐‘ฎ๐‘จ๐‘ญ and โˆ ๐‘ฉ๐‘จ๐‘ช.

Let ๐’šยฐ be the measurement of the indicated angle.

๐’š = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ (๐Ÿ—๐ŸŽ + ๐Ÿ‘๐Ÿ”)

๐’š = ๐Ÿ“๐Ÿ’

โˆ s on a line

๐Ÿ’๐’™ + ๐’š + ๐Ÿ“๐’™ = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ’๐’™ + ๐Ÿ“๐Ÿ’ + ๐Ÿ“๐’™ = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ—๐’™ + ๐Ÿ“๐Ÿ’ = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ—๐’™ + ๐Ÿ“๐Ÿ’ โˆ’ ๐Ÿ“๐Ÿ’ = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ“๐Ÿ’

๐Ÿ—๐’™ = ๐Ÿ๐Ÿ๐Ÿ”

(๐Ÿ

๐Ÿ—) ๐Ÿ—๐’™ = (

๐Ÿ

๐Ÿ—) ๐Ÿ๐Ÿ๐Ÿ”

๐’™ = ๐Ÿ๐Ÿ’

โˆ s on a line

The measurement of โˆ ๐‘ฎ๐‘จ๐‘ญ: ๐Ÿ’(๐Ÿ๐Ÿ’)ยฐ = ๐Ÿ“๐Ÿ”ยฐ

The measurement of โˆ ๐‘ฉ๐‘จ๐‘ช: ๐Ÿ“(๐Ÿ๐Ÿ’)ยฐ = ๐Ÿ•๐ŸŽยฐ

Closing (1 minute)

In every unknown angle problem, it is important to identify the angle relationship(s) correctly in order to set

up an equation that yields the unknown value.

Check your answer by substituting and/or measuring to be sure it is correct.

Exit Ticket (4 minutes)

5xยฐ

36ยฐ

4xยฐ

B

AC D

E

FG

๐’šยฐ

Lesson Summary

Steps to Solving for Unknown Angles

Identify the angle relationship(s).

Set up an equation that will yield the unknown value.

Solve the equation for the unknown value.

Substitute the answer to determine the measurement of the angle(s).

Check and verify your answer by measuring the angle with a protractor.

Page 7: Lesson 4: Solving for Unknown Angles Using Equations

NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4

Lesson 4: Solving for Unknown Angles Using Equations

50

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015

This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Name Date

Lesson 4: Solving for Unknown Angles Using Equations

Exit Ticket

Lines ๐ต๐ถ and ๐ธ๐น meet at ๐ด. Rays ๐ด๐บ and ๐ด๐ท form a right angle. Set up and solve an equation to find the values of

๐‘ฅ and ๐‘ค.

50ยฐ

60ยฐ

xยฐA

C

B

D

F

E

G

wยฐ

Page 8: Lesson 4: Solving for Unknown Angles Using Equations

NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4

Lesson 4: Solving for Unknown Angles Using Equations

51

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015

This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

Exit Ticket Sample Solutions

Lines ๐‘ฉ๐‘ช and ๐‘ฌ๐‘ญ meet at ๐‘จ. Rays ๐‘จ๐‘ฎ and ๐‘จ๐‘ซ form a right angle. Set up and solve an equation to find the values of ๐’™

and ๐’˜.

โˆ ๐‘ฉ๐‘จ๐‘ฌ = ๐Ÿ”๐ŸŽ

โˆ ๐‘ฉ๐‘จ๐‘ฎ = ๐Ÿ๐ŸŽ

Vert. โˆ s

โˆ s add

๐’™ + โˆ ๐‘ฉ๐‘จ๐‘ฎ = ๐Ÿ—๐ŸŽ

๐’™ + ๐Ÿ๐ŸŽ = ๐Ÿ—๐ŸŽ

๐’™ + ๐Ÿ๐ŸŽ โˆ’ ๐Ÿ๐ŸŽ = ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ๐ŸŽ

๐’™ = ๐Ÿ–๐ŸŽ

Complementary โˆ s

๐’™ + ๐’˜ + ๐Ÿ”๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ–๐ŸŽ + ๐’˜ + ๐Ÿ”๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ๐Ÿ’๐ŸŽ + ๐’˜ = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ๐Ÿ’๐ŸŽ + ๐’˜ โˆ’ ๐Ÿ๐Ÿ’๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ๐Ÿ’๐ŸŽ

๐’˜ = ๐Ÿ’๐ŸŽ

โˆ s on a line

Problem Set Sample Solutions

Set up and solve an equation for the unknown angle based on the relevant angle relationships in the diagram. Add

labels to diagrams as needed to facilitate their solutions. List the appropriate angle fact abbreviation for any step that

depends on an angle relationship.

1. Four rays have a common endpoint on a line. Set up and solve an equation to find the value

of ๐’„.

๐Ÿ“๐Ÿ— + ๐’… = ๐Ÿ—๐ŸŽ

๐Ÿ“๐Ÿ— โˆ’ ๐Ÿ“๐Ÿ— + ๐’… = ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ“๐Ÿ—

๐’… = ๐Ÿ‘๐Ÿ

Complementary โˆ s

๐’… + ๐’„ + ๐Ÿ๐Ÿ’๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ‘๐Ÿ + ๐’„ + ๐Ÿ๐Ÿ’๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ

๐’„ + ๐Ÿ๐Ÿ•๐Ÿ = ๐Ÿ๐Ÿ–๐ŸŽ

๐’„ + ๐Ÿ๐Ÿ•๐Ÿ โˆ’ ๐Ÿ๐Ÿ•๐Ÿ = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ๐Ÿ•๐Ÿ

๐’„ = ๐Ÿ—

โˆ s on a line

59ยฐ

140ยฐ

cยฐ

dยฐ

Scaffolding:

Some students may need to

use the corner of a piece of

paper to confirm which rays

form the right angle:

59 + ๐‘‘ = 90 or

59 + ๐‘‘ + ๐‘ = 90.

50ยฐ

60ยฐ

xยฐA

C

B

D

F

E

G

wยฐ

Page 9: Lesson 4: Solving for Unknown Angles Using Equations

NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4

Lesson 4: Solving for Unknown Angles Using Equations

52

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015

This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

2. Lines ๐‘ฉ๐‘ช and ๐‘ฌ๐‘ญ meet at ๐‘จ. Set up and solve an equation to find the value of ๐’™. Find the measurements of โˆ ๐‘ฌ๐‘จ๐‘ฏ

and โˆ ๐‘ฏ๐‘จ๐‘ช.

โˆ ๐‘ฉ๐‘จ๐‘ฌ + ๐Ÿ“๐Ÿ• = ๐Ÿ—๐ŸŽ

โˆ ๐‘ฉ๐‘จ๐‘ฌ + ๐Ÿ“๐Ÿ• โˆ’ ๐Ÿ“๐Ÿ• = ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ“๐Ÿ•

โˆ ๐‘ฉ๐‘จ๐‘ฌ = ๐Ÿ‘๐Ÿ‘

Complementary โˆ s

โˆ ๐‘ฉ๐‘จ๐‘ฌ + ๐Ÿ‘๐’™ + ๐Ÿ’๐’™ = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ‘๐Ÿ‘ + ๐Ÿ‘๐’™ + ๐Ÿ’๐’™ = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ‘๐Ÿ‘ + ๐Ÿ•๐’™ = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ‘๐Ÿ‘ โˆ’ ๐Ÿ‘๐Ÿ‘ + ๐Ÿ•๐’™ = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ‘๐Ÿ‘

๐Ÿ•๐’™ = ๐Ÿ๐Ÿ’๐Ÿ•

(๐Ÿ

๐Ÿ•) ๐Ÿ•๐’™ = (

๐Ÿ

๐Ÿ•) ๐Ÿ๐Ÿ’๐Ÿ•

๐’™ = ๐Ÿ๐Ÿ

โˆ s on a line

The measurement of โˆ ๐‘ฌ๐‘จ๐‘ฏ: ๐Ÿ‘(๐Ÿ๐Ÿ)ยฐ = ๐Ÿ”๐Ÿ‘ยฐ

The measurement of โˆ ๐‘ฏ๐‘จ๐‘ช: ๐Ÿ’(๐Ÿ๐Ÿ)ยฐ = ๐Ÿ–๐Ÿ’ยฐ

3. Five rays share a common endpoint. Set up and solve an equation to find the value of ๐’™. Find the measurements of

โˆ ๐‘ซ๐‘จ๐‘ฎ and โˆ ๐‘ฎ๐‘จ๐‘ฏ.

๐Ÿ๐’™ + ๐Ÿ‘๐Ÿ”. ๐Ÿ“ + ๐Ÿ‘๐Ÿ”. ๐Ÿ“ + ๐Ÿ๐’™ + ๐Ÿ‘๐’™ = ๐Ÿ‘๐Ÿ”๐ŸŽ

๐Ÿ•๐’™ + ๐Ÿ•๐Ÿ‘ = ๐Ÿ‘๐Ÿ”๐ŸŽ

๐Ÿ•๐’™ + ๐Ÿ•๐Ÿ‘ โˆ’ ๐Ÿ•๐Ÿ‘ = ๐Ÿ‘๐Ÿ”๐ŸŽ โˆ’ ๐Ÿ•๐Ÿ‘

๐Ÿ•๐’™ = ๐Ÿ๐Ÿ–๐Ÿ•

(๐Ÿ

๐Ÿ•) ๐Ÿ•๐’™ = (

๐Ÿ

๐Ÿ•) ๐Ÿ๐Ÿ–๐Ÿ•

๐’™ = ๐Ÿ’๐Ÿ

โˆ s at a point

The measurement of โˆ ๐‘ฌ๐‘จ๐‘ญ: ๐Ÿ(๐Ÿ’๐Ÿ)ยฐ = ๐Ÿ–๐Ÿยฐ

The measurement of โˆ ๐‘ฎ๐‘จ๐‘ฏ: ๐Ÿ‘(๐Ÿ’๐Ÿ)ยฐ = ๐Ÿ๐Ÿ๐Ÿ‘ยฐ

4. Four lines meet at a point which is also the endpoint of three rays. Set up and solve an equation to find the values

of ๐’™ and ๐’š.

๐Ÿ๐’š + ๐Ÿ๐Ÿ + ๐Ÿ๐Ÿ“ + ๐Ÿ—๐ŸŽ = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ๐’š + ๐Ÿ๐Ÿ๐Ÿ• = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ๐’š + ๐Ÿ๐Ÿ๐Ÿ• โˆ’ ๐Ÿ๐Ÿ๐Ÿ• = ๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐Ÿ๐Ÿ๐Ÿ•

๐Ÿ๐’š = ๐Ÿ”๐Ÿ‘

(๐Ÿ

๐Ÿ) ๐Ÿ๐’š = (

๐Ÿ

๐Ÿ) ๐Ÿ”๐Ÿ‘

๐’š = ๐Ÿ‘๐Ÿ. ๐Ÿ“

โˆ s on a line

๐Ÿ‘๐’™ = ๐Ÿ๐’š

๐Ÿ‘๐’™ = ๐Ÿ(๐Ÿ‘๐Ÿ. ๐Ÿ“)

๐Ÿ‘๐’™ = ๐Ÿ”๐Ÿ‘

(๐Ÿ

๐Ÿ‘) ๐Ÿ‘๐’™ = (

๐Ÿ

๐Ÿ‘) ๐Ÿ”๐Ÿ‘

๐’™ = ๐Ÿ๐Ÿ

Vert. โˆ s

H

B

C

D

E

F

A

3xยฐ

4xยฐ

57ยฐ

Scaffolding:

Students struggling to organize their solution may benefit from prompts such as the following:

Write an equation to

model this situation.

Explain how your equation

describes the situation.

Solve and interpret the

solution. Is it reasonable?

Page 10: Lesson 4: Solving for Unknown Angles Using Equations

NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4

Lesson 4: Solving for Unknown Angles Using Equations

53

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015

This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

5. Two lines meet at a point that is also the vertex of a right angle. Set up and solve an equation to find the value of ๐’™.

Find the measurements of โˆ ๐‘ช๐‘จ๐‘ฌ and โˆ ๐‘ฉ๐‘จ๐‘ฎ.

โˆ ๐‘ซ๐‘จ๐‘ฉ = ๐Ÿ’๐’™

โˆ ๐‘ซ๐‘จ๐‘ฎ = ๐Ÿ—๐ŸŽ + ๐Ÿ๐Ÿ“ = ๐Ÿ๐ŸŽ๐Ÿ“

๐Ÿ’๐’™ + ๐Ÿ‘๐’™ = ๐Ÿ๐ŸŽ๐Ÿ“

๐Ÿ•๐’™ = ๐Ÿ๐ŸŽ๐Ÿ“

(๐Ÿ

๐Ÿ•) ๐Ÿ•๐’™ = (

๐Ÿ

๐Ÿ•) ๐Ÿ๐ŸŽ๐Ÿ“

๐’™ = ๐Ÿ๐Ÿ“

vert. โˆ s

โˆ s add

โˆ s add

The measurement of โˆ ๐‘ช๐‘จ๐‘ฌ: ๐Ÿ’(๐Ÿ๐Ÿ“)ยฐ = ๐Ÿ”๐ŸŽยฐ

The measurement of โˆ ๐‘ฉ๐‘จ๐‘ฎ: ๐Ÿ‘(๐Ÿ๐Ÿ“)ยฐ = ๐Ÿ’๐Ÿ“ยฐ

6. Five angles are at a point. The measurement of each angle is one of five consecutive, positive whole numbers.

a. Determine the measurements of all five angles.

๐’™ + (๐’™ + ๐Ÿ) + (๐’™ + ๐Ÿ) + (๐’™ + ๐Ÿ‘) + (๐’™ + ๐Ÿ’) = ๐Ÿ‘๐Ÿ”๐ŸŽ

๐Ÿ“๐’™ + ๐Ÿ๐ŸŽ = ๐Ÿ‘๐Ÿ”๐ŸŽ

๐Ÿ“๐’™ + ๐Ÿ๐ŸŽ โˆ’ ๐Ÿ๐ŸŽ = ๐Ÿ‘๐Ÿ”๐ŸŽ โˆ’ ๐Ÿ๐ŸŽ

๐Ÿ“๐’™ = ๐Ÿ‘๐Ÿ“๐ŸŽ

(๐Ÿ

๐Ÿ“) ๐Ÿ“๐’™ = (

๐Ÿ

๐Ÿ“) ๐Ÿ‘๐Ÿ“๐ŸŽ

๐’™ = ๐Ÿ•๐ŸŽ

Angle measures are ๐Ÿ•๐ŸŽยฐ, ๐Ÿ•๐Ÿยฐ, ๐Ÿ•๐Ÿยฐ, ๐Ÿ•๐Ÿ‘ยฐ, and ๐Ÿ•๐Ÿ’ยฐ.

b. Compare the expressions you used for the five angles and their combined expression. Explain how they are

equivalent and how they reveal different information about this situation.

By the commutative and associative laws, ๐’™ + (๐’™ + ๐Ÿ) + (๐’™ + ๐Ÿ) + (๐’™ + ๐Ÿ‘) + (๐’™ + ๐Ÿ’) is equal to (๐’™ + ๐’™ + ๐’™ + ๐’™ + ๐’™) + (๐Ÿ + ๐Ÿ + ๐Ÿ‘ + ๐Ÿ’), which is equal to ๐Ÿ“๐’™ + ๐Ÿ๐ŸŽ. The first expression, ๐’™ + (๐’™ + ๐Ÿ) + (๐’™ + ๐Ÿ) + (๐’™ + ๐Ÿ‘) + (๐’™ + ๐Ÿ’), shows the sum of five unknown numbers where the second is

๐Ÿ degree more than the first, the third is ๐Ÿ degree more than the second, and so on. The expression ๐Ÿ“๐’™ + ๐Ÿ๐ŸŽ

shows the sum of five times an unknown number with ๐Ÿ๐ŸŽ.

7. Let ๐’™ยฐ be the measurement of an angle. The ratio of the measurement of the complement of the angle to the

measurement of the supplement of the angle is ๐Ÿ: ๐Ÿ‘. The measurement of the complement of the angle and the

measurement of the supplement of the angle have a sum of ๐Ÿ๐Ÿ–๐ŸŽยฐ. Use a tape diagram to find the measurement of

this angle.

(๐Ÿ—๐ŸŽ โˆ’ ๐’™): (๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐’™) = ๐Ÿ: ๐Ÿ‘

The measurement of the angle that satisfies these criteria is ๐Ÿ’๐Ÿ“ยฐ.

15ยฐ

3xยฐ

4xยฐA

C

B

D

F

E

G

๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ unit

๐Ÿ‘ units

MP.2 &

MP.7

๐Ÿ’ units = ๐Ÿ๐Ÿ–๐ŸŽ

๐Ÿ unit = ๐Ÿ’๐Ÿ“

๐Ÿ‘ units = ๐Ÿ๐Ÿ‘๐Ÿ“

Page 11: Lesson 4: Solving for Unknown Angles Using Equations

NYS COMMON CORE MATHEMATICS CURRICULUM 7โ€ข6 Lesson 4

Lesson 4: Solving for Unknown Angles Using Equations

54

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka-math.org This file derived from G7-M6-TE-1.3.0-10.2015

This work is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.

8. Two lines meet at a point. Set up and solve an equation to find the value of ๐’™. Find the measurement of one of the

vertical angles.

A solution can include a modified diagram (as shown) and the supporting

algebra work:

๐Ÿ‘๐’™ = ๐Ÿ๐Ÿ๐Ÿ•

(๐Ÿ

๐Ÿ‘) ๐Ÿ‘๐’™ = (

๐Ÿ

๐Ÿ‘) ๐Ÿ๐Ÿ๐Ÿ•

๐’™ = ๐Ÿ‘๐Ÿ—

vert. โˆ s

Each vertical angle: ๐Ÿ’(๐Ÿ‘๐Ÿ—)ยฐ = ๐Ÿ๐Ÿ“๐Ÿ”ยฐ

Solutions may also include the full equation and solution:

๐Ÿ’๐’™ = ๐’™ + ๐Ÿ๐Ÿ๐Ÿ•

๐Ÿ’๐’™ โˆ’ ๐’™ = ๐’™ โˆ’ ๐’™ + ๐Ÿ๐Ÿ๐Ÿ•

๐Ÿ‘๐’™ = ๐Ÿ๐Ÿ๐Ÿ•

(๐Ÿ

๐Ÿ‘) ๐Ÿ‘๐’™ = (

๐Ÿ

๐Ÿ‘) ๐Ÿ๐Ÿ๐Ÿ•

๐’™ = ๐Ÿ‘๐Ÿ—

9. The difference between three times the measurement of the complement of an angle and the measurement of the

supplement of that angle is ๐Ÿ๐ŸŽยฐ. What is the measurement of the angle?

๐Ÿ‘(๐Ÿ—๐ŸŽ โˆ’ ๐’™) โˆ’ (๐Ÿ๐Ÿ–๐ŸŽ โˆ’ ๐’™) = ๐Ÿ๐ŸŽ

๐Ÿ๐Ÿ•๐ŸŽ โˆ’ ๐Ÿ‘๐’™ โˆ’ ๐Ÿ๐Ÿ–๐ŸŽ + ๐’™ = ๐Ÿ๐ŸŽ

๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ๐’™ = ๐Ÿ๐ŸŽ

๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ—๐ŸŽ โˆ’ ๐Ÿ๐’™ = ๐Ÿ๐ŸŽ โˆ’ ๐Ÿ—๐ŸŽ

โˆ’๐Ÿ๐’™ = โˆ’๐Ÿ•๐ŸŽ

(โˆ’๐Ÿ

๐Ÿ) (โˆ’๐Ÿ๐’™) = (โˆ’

๐Ÿ

๐Ÿ) (โˆ’๐Ÿ•๐ŸŽ)

๐’™ = ๐Ÿ‘๐Ÿ“

The measurement of the angle is ๐Ÿ‘๐Ÿ“ยฐ.

4xยฐ

(x+117)ยฐ

xยฐxยฐ

xยฐ

xยฐ

117ยฐ

xยฐ