lectures 18-19 (ch. 30) inductance and self-inductunce
DESCRIPTION
Lectures 18-19 (Ch. 30) Inductance and Self-inductunce. Mutual inductunce Tesla coil Inductors and self-inductance Toroid and long solenoid Inductors in series and parallel Energy stored in the inductor, energy density 7. LR circuit 8. LC circuit 9. LCR circuit. Mutual inductance. - PowerPoint PPT PresentationTRANSCRIPT
Lectures 18-19 (Ch. 30)Inductance and Self-inductunce
1. Mutual inductunce2. Tesla coil3. Inductors and self-inductance4. Toroid and long solenoid5. Inductors in series and parallel6. Energy stored in the inductor, energy density7. LR circuit8. LC circuit9. LCR circuit
Mutual inductanceVirce verse: if current in coil 2 is changing, the changing flux through coil 1 induces emf in coil 1.
dt
diM
i
NM
iMNdt
dN
1212
1
2221
12122
222
1
22
2
11
1212
i
N
i
NM
MMM
dt
diM
i
NM
iMNdt
dN
2121
2
1112
21211
111
Units of M
sH
m
V
C
NE
m
V
q
FE
m
Vs
Cm
NsTBvqF
sA
Vs
A
mTH
henryHA
WbM
iM
1
][,
111
1
111
)(11
1][,
2
2
Joseph Henry (1797-1878)
Typical magnitudes: 1μH-1mH
Examples where mutual inductance is useful
Tesla coil
Nikola Tesla (1856 –1943)[B]=1T to his honor
?
,,.1
2
2110
1
2110
1
1101101
1121
2212
l
NNAMwhy
l
NNAM
l
iNinB
ABi
NMrr
Estimate.
kVmHMKtake
Kl
NNAM
coreticferromagneWith
Vs
AH
dt
diM
HmA
mTmM
ts
AiNNmcmAml
m
m
50,251000
,
501021025
255.0
101010104
102,10,1000,1010,5.0
1
01
211
6621
3237
6221
23211
cos
.3
.2
1
2120
2
1
2120
21212
l
NNAM
axisesbetweenangleanisandrrif
l
NNAM
ABrrif
Example: M=?
Mutual inductance may induce unwanted emf in nearby circuits. Coaxial cables are used to avoid it.
Self-inductance
i
NL
dt
diL
LiNdt
dN
,
,
Thin ToroidThin solenoid with approximately equal inner and outer radius.
r
ANL
r
NiB
BAi
NL
2
2
,
2
Long solenoid
l
ANL
l
NiB
ABi
NL
2
max
max
maxmax,
Example. Toroidal solenoid with a rectangular area.
a
bhNL
a
bNih
r
drNih
r
NiB
Bhdrdi
NL
b
a
ln2
ln22
,2
,
2
dt
diLV
dt
diL
ab
Inductors in circuits
Energy stored in inductor
2
22
2
0
LIU
LILidiW
LididtPdWdt
diiLIVP
L
I
in
abin
222
22 QVCV
C
QUC Compare to
Magnetic energy density
Let’s consider a thin toroidal
solenoid, but the result turns out to be correct for a general case
rAr
AINu
r
ANL
LIU
rA
U
volume
Uu
B
L
LLB
222
2,
2
2
22
22
2
222
)2(
2
2
2
22
222
Bu
NrAr
rABNu
N
rBI
r
NIB
B
B
Energy is stored in B inside the inductor
Compare to:
Energy is stored in E inside the capacitor
2
2EuE
Example. Find U of a toroidal solenoid with rectangular area
4
ln
2
2,
2
.2
4
ln
ln2
,2
.1
22
2
22
22
ab
hNIU
rdrhdV
r
NIB
Bu
dVuU
ab
hNIU
a
bhNL
LIU
L
B
volune
BL
L
L
LR circuit, storing energy in the inductor
t
L
t
edt
diL
RIeIi
t
R
Ri
R
Ldt
Ri
diL
R
Ri
dt
didt
diLiR
),1(
))(
ln(
,)(
)(
0
εL
Energy conservation law
dt
dURii
LiU
dt
dU
dt
dLi
dt
diLi
dt
diLiRii
dt
diLiR
L
LL
2
22
2
2,
2
1
,,0
Power output of the battery =power dissipated in the resistor + the rate at which the energy is stored in inductor
General solution Initial conditions (t=0)
L
i 0
t
L
t
edt
diL
RIeIi
),1(
0
L
RIi
Steady state (t→∞)
LR circuit, delivering energy from inductor
ttt
L
t
i
I
i
I
eRIeeIL
dt
diL
Ieit
I
i
R
Ldt
i
di
L
Ri
dt
di
dt
diLiR
,,ln
,
,0
Ridt
dURi
dt
Lid
Ridt
idiL
dt
diLiR
L 222
2
,)2/(
0,0
εL
t
ε
The rate of energy decrease in inductor is equal to the power input to the resistor.
Oscillations in LC circuit
Oscillations in LC circuit
,0,,02
2
LC
q
dt
qd
dt
dqi
dt
diL
C
q
conditionsinitialthebydefinedareQand
tQi
tQq
)sin(
)cos(
LCqq
1,0 22
Compare to mechanical oscillator
x0
F
m
kxx
kxxm
,0
,
2
LCm
k
CkLm
Limv
C
qkx
ivqx
1,
1,
22,
22
,2222
conditionsinitialbydefinedareXand
tXv
tXx
)sin(
)cos(
General solution
LCqq
1,0 22
tqi
tqq
qQtqtQq
ti
tiqtq
sin
cos
)0(cos
00)0(
0)0(,)0(.1
0
0
0
0
q
i
t
t
conditionsinitialbydefinedareQand
2
T
2
T
ti
q
tii
iQiQti
tQtQi
tQtQq
Qtq
tQi
tQq
solutiongeneral
ititq
sin
cos
)0(
cos)2/sin(
sin)2/cos(
2/0cos)0(
)sin(
)cos(
)0(,0)0(.2
0
0
00
0
q
i
t
t2
T
2
T
2
202
02
20
20222
02
0
0
0
0
0
0
0
00
)()()(
tantan
sin
cos
)sin(
)cos(
)0(,)0(:.3
iq
iqQQiq
q
iar
q
i
Qi
tQi
tQq
itiqtqconditionsinitialArbitrary
Energy conservation law
0)2
()2(
0
,0
22
Li
dt
d
C
q
dt
d
dt
diLi
dt
dq
C
qdt
dqi
dt
diL
C
q
222222
2220
20
22 LI
C
QLi
C
qconst
Li
C
q
t
UL UC
q-Q Q
UC ULUC+UL=const
T/22
T
0)2/cos()4/cos()3
1012.322
.2
005.0)0(cos
00)0(
0)0(,)0(.1
00
620
2
maxmax
0
0
qTqq
JC
q
C
QUU
mCqQtqtQq
ti
tiqtq
CL
Example. In LC circuit C=0.4 mF, L=0.09H.The initial charge on the capacitor is 0.005mC and the initial current is zero. Find: (a) Maximum charge in the capacitor (b) Maximum energy stored in the inductor; (c) the charge at the moment t=T/4, where T is a period of oscillations.
mVC
q
dt
diLV
TtmVC
Lti
C
LCtiV
LCtiI
QC
QV
4)2
4/,4.2)0()0(
)0(,)1
Example. In LC circuit C=250 ϻF, L=60mH.The initial current is 1.55 mA and the initial charge is zero. 1) Find the maximum voltage across the capacitor . At which moment of time (closest to an initial moment) it is reached? 2) What is a voltage across an inductor when a charge on the capacitor is 1 ϻ C?
2
T
q
Cdt
diCLq
dt
diL
C
qd
LLLJ
iL
C
qc
mCqb
AiAT
Tiiia
ef
ef
108)
111,1025.2
22)
4.0)3()
1.0)3(,1.0)
2()
2()
3()
11
11
21
2
20
20
2111
Example. In LC circuit C=18 ϻF, two inductors are placed in parallel: L1=L2=1.5H and mutual inductance is negligible.The initial charge on the capacitor is 0.4mC and the initial current through the capacitor is 0.2A. Find: (a) the current in each inductor at the instant t=3π/ω, where ω is an eigen frequency of oscillations; (b) what is the charge at the same instant? (c) the maximum energy stored in the capacitor;(d) the charge on the capacitor when the current in each inductor is changing at a rate of 3.4 A/s.
LCR circuit
0
,0
C
qqRqL
dt
dqiiR
dt
diL
C
q
LCL
Rqqq
1,
2,02 0
20
teq ~ 02 20
2 Characteristic equation
C
LR
L
R
LC
4
4
10
,)(
22
222
02
220
22202,1
Critical damping
a) Underdamped oscillations:
tQetQ
tttQti
ttQtq
i
)(
)],sin()cos()[()(
)cos()()(2,1
2220
4R
C
L
2,0
)(
)(
210
2211
21
2,1
21
21
if
eCeCti
eCeCtq
numbersrealare
tt
tt
2220
4R
C
Lc) Overdamped oscillations:
t
t
eCtCCti
etCCtq
RC
L
2
1
])([)(
)()(
4
221
21
2,1
2220
b) Critically damped oscillations: 2220
4R
C
L
Example. The capacitor is initially uncharged. The switch starts in the open position and is then flipped to position 1 for 0.5s. It is then flipped to position 2 and left there.1) What is a current through the coil at the moment t=0.5s (i.e. just before the switch was flipped to position 2)?2) If the resistance is very small, how much electrical energy will be dissipated in it?3) Sketch a graph showing the reading of the ammeter as a function of time after the switch is in position 2, assuming that r is small.
1 2
r
25Ω
10mH50V
AIsti
smsH
R
L
AV
RIeIi
t
2)5.0(
5.04.025
10
225
50),1()1
2
mJLI
UU Ldis 202
)22
3)
10µF
A
Induced oscillations in LRC circuit, resonance
~
)(
2tan,
])2()[(
sin2
cos)(
]sin)sin(cos)[cos(
)cos()sin(2)cos()(
)cos(
)sin(
)cos(
cos2
,,2
,1
,
0cos
20
222220
22
220
220
2
20
0
fQ
fQ
fQ
ttf
tftQtQ
tQq
tQq
tQq
tfqqq
Lf
L
R
LCdt
dqi
tRidt
diL
C
q
Q
0At the resonance condition: an amplitude greatly insreases0
0