lectures 11 & 12: magnetic fields and the motion of charged particles chapters 26-28 (tipler)...
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Lectures 11 & 12: Magnetic Fields and the Motion of Charged Particles
Chapters 26-28 (Tipler)
Electromagnetism
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Learning ObjectivesTo introduce the concepts of magnetic fields
•Current
•Magnetic force on a moving charge
•Magnetic field lines
•Magnetic flux
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The Nature of Electric Current
Recognizable effects of current flow are:
•heating
•magnetic
•electrolytic
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The Nature of Electric Current
Recognizable effects of current flow are:
•heating
•magnetic
•electrolytic
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Definition of Current
Suppose a conductor carries a current I
Rate of flow of charge Q past a given cross-section is defined by:
dt
dQI =
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The SI unit of current is the ampere: one ampere is defined to be one coulomb per second.
André Marie Ampére (1775-1836)
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The Current in a Conductor
ne
Area A
vd
In a time t, volume “swept” out is: Avdt
Charge contained in this volume is:
( )etAvnQ de Δ=Δ
Therefore: eAvnIt
Qde==
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The current per unit cross section is called the current density J:
deevnA
IJ ==
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Magnetic Field
•A moving charge (current) creates a magnetic field in the surrounding space
•The magnetic field exerts a force Fm on any other moving charge (or current) that is present in the field
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The Magnetic Force on a Moving Charge
Experimentally:
A particle of charge +q moving with velocity v in a magnetic field B, experiences a (magnetic) force Fm:
qFm ∝ vFm ∝ θsin ∝mFFm is to v & B
θsinBqvFm =
Fm
θ
B
v
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BvqF m ∧=
In vector form
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€
rF m = q
r v ×
r B
The unit of B is: N C-1 m-1 s
N C ms-1
This is given a special name tesla (T), in honour of Nikola Tesla
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If 1 C of charge moving at 1 m/s perpendicular to a magnetic field experiences a force of 1 Newton, the magnetic field is 1 tesla.
Earth’s magnetic field 5 10-5 TPoles of a large electromagnet 2 TSurface of a neutron star 108 T
Nikola Tesla (1856-1943) a Slovenian born American electrical engineer
Gauss (G) is another unit in
common use: 1G = 10-4 T
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In regions where both E and B fields are present, the total force is the vector sum of the electric and magnetic forces:
( )BvEqF ∧+=
in direction of E to v and B
Lorentz Equation
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The Earth’s magnetic field at a particular region is represented by
k70sinBj70cosBB OO −=A proton is moving in this magnetic field with a velocity
jsm10v 7 =Obtain an expression for the direction and magnitude of magnetic force acting on the proton.
Worked Exercise
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BvqF m ∧=
€
F = q vyˆ j ( )∧ By
ˆ j + Bzˆ k ( )
= qv yByˆ j ∧ ˆ j ( ) + qvyBz
ˆ j ∧ ˆ k ( )
= qvyBzˆ i
= −3 ×10−17 N ˆ i
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Magnetic Field Lines
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Magnetic Field Lines
NOTE: unlike electric field lines, magnetic field lines are ALWAYS
continuous (no magnetic monopoles) and they do not point in the direction of the force on the moving charge in a magnetic field – they ARE NOT lines of force.
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Magnetic Field Lines
•the tangent to a field line at a point P gives the direction of B at that point
•the number of field lines drawn per unit cross sectional area is proportional to the magnitude of B
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Magnetic Flux
The magnetic flux B passing through the small area A shown is defined by:
€
φB = Bcosθ × ΔA = B • ΔA
€
φB = B • d Asurface
∫
A
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€
φB = B.dAclosed surface
∫ = 0
Gauss’s flux law for magnetism:
€
φE = E .dAclosed surface
∫ = Q
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Review and Summary•A magnetic field B is defined in terms of the force Fm acting on a test particle with charge q and moving through the field with velocity v:
€
F m = qv × BThe SI unit for B is the tesla (T)
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Review and Summary
•Compare this with the definition of the electric field E
FE = qE
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Review and Summary
Gauss’s Law for Magnetism
The net magnetic flux through any closed surface is zero
€
φB = B.d Asurface
∫ = 0
As a result, magnetic field lines always close on themselves
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Class Exercise
False
1. True or False: The magnetic force does not accelerate a moving charged particle because the force is perpendicular to the velocity of the particle.
2. What is the force acting on an electron with velocity
in a magnetic field
€
v = 2ˆ i − 3ˆ j ( ) ×106 m/s
€
B = 0.8ˆ i + 0.6 ˆ j − 0.4 ˆ k ( )T
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€
F = Fx2 + Fy
2 + Fz2
F = 0.621 pN
1 pN = 10-12 N
€
rF = −0.192ˆ i − 0.128 ˆ j − 0.576 ˆ k pN
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Last lecture:Magnetic force on moving charges
€
F m = qv × BMagnetic flux and Gauss’s flux law
€
φB = B.dAclosed surface
∫ = 0
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BvqF m ∧=A few special cases:
v parallel to Bv perpendicular to Bv makes an angle θ to B
Today’s lecture:
Magnetic force on a current, torque on a current loop.
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BvF ∧=q(a) v parallel to B F = 0
(b) v B F to the plane containing B and v qvBF =
r
mvqvB
2
=
€
ω =2πf = 2π1
T=
qB
m
qB
mvr =€
2πr
v= T
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x x x x xx x x x xx x x x x
The direction of B field in sketches
Into the paper,away from you
Out of the paper,towards you
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(c) v makes an angle θ with B
(i) a uniform circular motion in which it has the speed vsinθ in a plane perpendicular to the direction of B
(ii) a steady speed of magnitude vcosθ along the direction of B
Helical Motion
B
vθ
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The Force on a Current-carrying Conductor
Single Charge BqvF dq =N, the number of charge carriers in volume Al, is: N = nAl
n = charge number density
Total force F:
BnAlqvNFF dq ==( )( ) JAlBlBAnqvF d ==
IlBF =
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In General
BlIF ∧=magnetic force on a straight wire segment
The direction of l is defined as the direction of the current I
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If the conductor is not straight, consider individual segments and use
BlIdFd ∧=magnetic force on an infinitesimal wire segment
x
x
x
x
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B
I
b
F1
The Torque on a Current-Carrying Loop (26-3 Tipler)
l
-F1
F2 -F2
b parallel to yl in the x-z plane,makes an angle to xF1, points in y direction-F1, points in -y,net torque from F1 and -F1 is zero.
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The Torque on a Current-Carrying Loop (26-3 Tipler)
φτ sin2 lF ×=φsinlBIb×=φsinBIA=
Fr ∧=τ
O F2
-F2
F2 passes through O, so torque from F2 is zero.
Torque from -F2The direction of the torque??
r
Pointing out towards you
Will the loop accelerate towards you?
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The Torque on a Current-Carrying Coil
φτ sin2 lF ×=φsinlBIb×=
φsinBIA=
A
BAI ∧=τ
l
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The Torque on a Current-Carrying Coil
BAI ∧=τThis result is true for loops of any shape
Define AI=μ
B∧=μτMagnetic Dipole Moment
The torque tends to align μ and B
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€
τ =BIAsinφ
€
τ =BIAsinφ
Unstable equilibrium= 180 degrees
Stable equilibrium= 0
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I
Comparison between Magnetic and Electric Dipole Moments
Magnetic Dipole
μB∧=μτ
B
-q
+q
p
Electric Dipole
E
Ep∧=τ
EpU .−=Electric Dipole Potential EnergyMagnetic Dipole Potential Energy
BU .μ−=
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Electric dipole,
Molecules behave like electric dipoles
Why do we bother with magnetic dipoles?
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v
L
Magnetic Dipole Moment of an Electron in an Atom
2rI πμ ×=
€
I =e
T r
ev
π2=
2
evr=μ
Angular Momentum L = mer x v
€
μ =evr
2
me
me
=e
2me
L
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Magnetic Dipole Moment of an Electron in an Atom
Lm
e
e2−=μ
Q.M. L is quantised. Fundamental unit is:
€
L = h
eB m
e
2
h=μ
Fundamental Unit of Magnetic Moment
)T (J mA 10274.9 -1224−×=
Bohr Magneton
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All atoms have orbiting electrons,Why only some have a non-zero magnetic moment??
Next lecture:Connecting B to current I