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  • 8/7/2019 Lecture3 Pol Mechnism

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    Electronic polarization

    343

    V RT!

    For calculating the effect of electronic polarization,

    We consider an idealized atomwith perfect spherical

    symmetry. I

    t has a point likecharge + ze in the nucleus, andThe exact opposite charge zehomogeneously distributed inthe volume of the atom, whichis

    with R= radius of the atom

    Ques: Density of electrons?

    Ques: Lorentz force = coulomb force =?

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    The density of electrons (Charge/Volume of atom) is then

    In the presence of an electric field E;

    Lorentz force: F1=-zeE acts on charges.

    The positive charge in the nucleus and the center of thenegative charges from the electron "cloud" will thusexperience forces in different direction and will become

    separated.We have the idealized situation shown in theimage in last slide.

    33

    4

    z e

    RV

    T!

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    The attractive force (between opposite charges)

    F2 is given by

    2 2

    0

    2

    30

    3 3

    3 3

    (charge of nucleus)(negative charge encolesd in sphere of radius d)

    4

    ( )

    4

    negative charge encolesd in sphere of radius d

    4 3 d= ze

    4 3 R

    Fd

    ze

    dR

    zed

    R

    TI

    TI

    T

    T

    !

    !

    !

    Q

    * Q= charge density x volume

    --

    -

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    Equating F1 and F2 we have equilibrium distance dE as

    Therefore the induced dipole moment is

    As polarization is dipole moment per unit volume so

    And Electronic Polarizability:

    3

    0

    3

    0

    4 and

    P4

    P NR E

    NR

    E

    TI

    G T

    I

    !

    !

    3

    04

    Ezed R EQ TI! !

    304

    E

    R Ed

    ze

    TI!

    3

    04

    .

    R

    E

    e

    TIE

    EQ

    !

    ! Where e is defined byElectronic polarizability.Ques: What is the Dimension

    of Polarizability?

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    P = NEeE = Io(Ir-1)E

    This gives

    Io(Ir-1) = NEe

    Here N is the number of dipoles per unit volume.

    There are a number of interesting points about the

    last result:1. We have justified the "law" of a linear relationship

    between E and P for the electronic polarizationmechanism (sometimes also called inducedpolarization).

    2. We can easily extend the result to a mixture of different atoms: All we have to do is to sum over therelative densities of each kind of atom.

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    3

    0

    3

    0

    4 and

    = 4

    P NR E

    NRE

    TI

    TI

    !

    !

    We can easily get an order of magnitude for .

    Taking a typical density ofN

    x 10

    25

    m

    3

    andR6 x 10 12 m, we obtain G8.14 x 105,

    and r=1. 000 0814

    Note:

    1. The values ofmolecular dipole moments are usually

    expressed in Debye units(3.3 x10-30 Cm). The Debye unit,

    abbreviated as D, equals 10-18 electrostatic units (e.s.u.).

    2. The permanent dipole moments of non-symmetricalmolecules generally lie between 0.5 and 5D.

    3. In the case ofpolymers and biopolymers one can meet

    much higher values ofdipole moments ~ hundreds or

    even thousands of Debye units.

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    2.Ionic polarization

    Consider a simple ioniccrystal, e.g. NaCl.

    Each Na+ - Cl pair is a naturaldipole, no matter how you pair up two atoms.

    The polarization of a givenvolume, however, is exactlyzero because for every dipolemoment there is a neighboring

    one with exactly the samemagnitude, but opposite sign.

    Note that the dipoles can notrotate; their direction is fixed.

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    In an electric field, theions feel forces in

    opposite directions.

    For a field acting asshown, the lattice distortsa little bit (hugelyexaggerated in thedrawing)

    The Na+ ions moved a bitto the right, the Cl ionsto the left.

    The dipole momentsbetween adjacent NaCl -

    pairs in field direction arenow different and there isa net dipole moment ina finite volume now.

    Ques: How large is d?

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    How large is d?

    The force F1 increasing the distance is given by

    F1 = q E

    with q = net charge of the ion.

    The restoring force F2: ford

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    Other relations

    2

    0

    2

    0

    r

    and

    NqP .

    Find out and

    q EYd

    E

    Yd

    Q

    I

    !

    Exercise:

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    Summary: Ionic polarization

    0

    qEd

    Yd!

    2

    02

    0

    r

    and

    q= .

    ind out and

    q E

    Yd

    E

    Yd

    Q

    I

    !

    Net Displacement:

    In the presence of E:

    Dipole moment:

    Polarization:

    00

    2

    0 Yd

    Nq

    E

    P

    IIG !!

    And r= (G+1)

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    Orientation Polarization In the case of Orientation polarization (sometime called Dipolar

    polarization) we have a material with built-in dipoles that areindependent of each other, i.e. they can rotate freely- in sharp contrastto ionic polarization.

    The prime example is liquid water, where every water molecule is a little dipole that can have any orientation

    with respect to the other molecules.

    Moreover, the orientation changes all the time because the molecules

    moves! (O

    rientation polarization for dielectric dipoles thus is pretty muchlimited to liquids)

    It is like a snapshot (2D) with a very, very short exposure time. A fewnanoseconds later the same piece of water may look totally different indetail, but pretty much the same in general.

    In a three-dimensional piece of water the blue and green circles would nothave to be in the same plane; but that is easy to imagine and is difficult to

    draw

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    Orientation polarization: visualize it

    in water Water molecules that form natural dipoles.

    because the negatively charged oxygen atom and the two positivelycharged H - atoms have different centers of charge.

    Each molecule carries a dipole moment which can be drawn as a vectorof constant length.

    If we only draw a vector denoting the dipole moment, we get - in two

    dimensions - a picture like this:

    The sum of all dipole moments will be zero, if the dipoles arerandomly oriented.

    If we now introduce a field E, the dipoles would have a tendency toturn into the field because that would lower their energy.

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    The dipoles are not sitting still, but moving around and rotating allthe time - because they contain thermalenergy and thus also someentropy.

    The electrical field induces average orientation in field direction. Most of the time an individual dipole points in all kinds of directions.

    The "real" picture (in the sense of a snapshot with a very short exposuretime) looks like this:

    The orientation of all dipoles is just a little bit shifted so that anaverage orientation in field direction results. In the picture, the effectis even exaggerated!

    With out FieldW

    ithF

    ield

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    Energy of a dipole in Electric field:

    Consider a Polar moleculewhich caries a permanent

    dipole moment (qd, like

    water molecule) is placed in an

    electric field E.

    The Potential energy is givenby;

    U= -.E=- Ecos()

    E

    +q(1)

    (2)-q

    d

    cos( )EUkT kT

    e e

    Q U

    !

    In thermal equilibrium the relative number of molecules with the potentialenergy Uis proportional to (Boltzmann statistics)

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    Number ofdipoles in a solid angle:

    Let n() be the number of dipoles per unit solid angle at

    , we have

    The number of dipoles in a solid angle d;

    co s ( )

    0( ) .

    E

    k Tn n eQ U

    U !

    0

    cosexp( )2 sin

    En d

    kT

    Q UT U U

    Note:Where d;! r.dS/r3

    Can be calculated

    as follows:

    ********************************************************************************************

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    Average Dipole Moment The average dipole moment in an electric field is the net moment

    of the assembly divided by the total numberof dipoles

    Therefore,

    00

    00

    exp( cos / )2 sin ( cos )

    exp( cos / )2 sin

    n E kT d

    n E kT d

    T

    T

    Q U T U Q U UQ

    Q U T U U "!

    cosE xk

    Q U !where and E akQ !

    L(a)L(a)is calledLangeven functionLangeven function

    cos

    0

    cos

    0

    1cos sin

    2 1

    1sin

    2[ ]1 1 1

    cot ( ),[ ]

    aE

    xk

    a

    aE

    xk

    a

    x x a a a

    a

    x a a a

    a

    e d e xdx

    ae d e dx

    xe e e eanha L a

    a e e e a a

    T Q U

    T Q U

    U U UQ

    QU U

    "! ! !

    ! ! ! !

    Coth(a)

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    ....453

    1

    )(

    3

    !

    aa

    aaCoth

    kT

    Ea

    where

    aPP

    aNN

    a

    so

    vv

    .

    )(.

    )(..

    )(.

    Q

    QQ

    QQ

    !

    !

    !

    !Where Ps is saturation polarization and

    Po is orientation Polarization.

    y=1/3a

    0 1 2 4 5 6 7 80.0

    0.2

    0.4

    0.6

    0.8

    1.0 y=1

    y=L(a)

    a

    y

    Langevin

    In Fig. the angeven unction L(a)L(a) is

    plotted against aa.

    L(a)L(a) has a limiting value 11, which was to

    be expected since this is the maximum o

    coscosUU..

    Case I: when a is very high : at Low Temp;

    a>>1 L(a)=1, Po = Ps

    Case II: when a is very ow: at high Temp;

    a

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    TkT

    Hence

    ENP

    and

    kT

    ENP

    oo

    voo

    v

    o

    1

    3

    3

    2

    2

    w!

    !

    !

    EQ

    E

    E

    QOrientation Polarization

    Orientation Polarizability

    OrDipolar Polarizability

    Note: Derivation shows that tendency o the extended ield toalign the dipoles is contracted by thermal motion resulting in a

    decreasing value o Po with increasing T

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    Total Polarizability of Polyatomic Gas:

    P = Pe+ Pi + Po

    P = NEe + NEi + NEo= 0 (r - 1) E

    Hence

    (r - 1) = =N./ 0

    Where is called Total Polarizabilty

    kie

    3

    2

    QEEE !

    Is knownas Langevin- DebyeEquation