lecture on vehicle dynamics 2
TRANSCRIPT
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0
P P’
s
s ∆s
t) t+∆t
t
s
∆
∆Kecepatan rata-rata =
dt
ds
t
s
v t
=
∆
∆
= →∆ 0lim
Kecepatan sesaat
m/det atau ft/det
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t
v
∆
∆Percepatan rata-rata =
0
P P’
s
v v+∆v
(t) t+∆t
Percepatan sesaat
m/det2 atau ft/det22
2
0lim
dt
sd dt
dv
t va
t
=
=
∆∆=
→∆
:
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)(t f a =
C D
dt t f dv
dt adv
)(
=
=
∫∫ =⇒ dt t f dv )(
∫
∫∫
=−⇒
=
t
t v
dt t f vv
dt t f v
dv
00
0
)(
)(0
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)(s f a =
dss f dvv
dsadvv
)(=
=
∫
∫∫
=−
=⇒
s
s
s
s
v
dss f vv
dss f v
dvv
0
00
)(
)(
2
02
12
2
1
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)(v f a =
v=k(t) ⇒
:
)(
)(
v f
dvdt
dt
dvv f
=
=
)(
)(
v f
vdvdx
dx
dvvv f
=
=
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a = 0 t ,
v
konstan==
vdt
ds
s
, s0
s
vt ss
vt ss
dt v
s
ds
t s
+=
=−
= ∫∫
0
0
00
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a
konstan== adt
dv
v
at vvat vv
dt a
v
dvt v
+=
=−
= ∫∫
0
0
00
, v0
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at vdt
dsv +== 0
s0 s,
2
21
00
2
21
00
0
0 )
0
at t vss
at t vss
dt at v
s
dst s
++=
+=−
+= ∫∫ (
adsvdv
ads
dv
v
=
==konstan
)(2
)()(
0
2
0
2
0
2
0
2
21
00
ssavv
ssavv
dsav
vdv
s
s
v
−+=
−=−
=
∫∫
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A B
, s A s B
, s B – s A B
A s B/A.
0
s B
s
s A s B/A
A B
, B A
:
⇔−= A B A B sss /
⇔−= A B A B vvv /
⇔−= A B A B aaa /
A B A B sss / +=
A B A B vvv / +=
A B A B aaa / +=
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222
222
222
;;
;;
z y x
z y x
z y x
z y x
aaaa
za ya xa
z y xdt
d
vvvv
zv yv xv
z y xdt d
z y xr
z y x
++=
===
++==
++=
===
++==
++=
++=
:Percepatan
:Kecepatan
:Posisi
&&&&&&
&&&&&&
&&&
&&&
k jiv
a
k jirv
kir
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1 1
: x = t 3
– 6t 2
– 15t + 40 x t .
(). ,
(). ,
(). ,(). t 4
t 6 .
22
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3 3
.
v0,
a = - kv.
(). v t ,
(). x t ,
(). v x.
!
24
ol i
p iston
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4 4
25 /.
,
30
1,2 /2. ,
5
!
25