lecture 11: chapter 7, secs. 2-3 binomial and normal
TRANSCRIPT
![Page 1: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/1.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture 1
Lecture 11: Chapter 7, Secs. 2-3Binomial and Normal Random VariablesoDefinitionoWhat if Events are Dependent?oCenter, Spread, Shape of Counts, ProportionsoNormal ApproximationoNormal Random Variables
![Page 2: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/2.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.2
Looking Back: Review
o 4 Stages of Statisticsn Data Production (discussed in Lectures 1-3)n Displaying and Summarizing (Lectures 3-8)n Probability
o Finding Probabilities (discussed in Lectures 9-10)o Random Variables (introduced in Lecture 10)
n Binomialn Normal
o Sampling Distributionsn Statistical Inference
![Page 3: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/3.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.3
Definition (Review)n Discrete Random Variable: one whose
possible values are finite or countably infinite (like the numbers 1, 2, 3, …)
Looking Ahead: To perform inference about categorical variables, need to understand behavior of sample proportion. A first step is to understand behavior of sample counts. We will eventually shift from discrete counts to a normal approximation, which is continuous.
![Page 4: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/4.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.4
Definition Binomial Random Variable counts sampled
individuals falling into particular category;n Sample size n is fixedn Each selection independent of othersn Just 2 possible values for each individualn Each has same probability p of falling in
category of interest
![Page 5: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/5.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.6
Example: A Simple Binomial Random Variable
o Background: The random variable X is the count of tails in two flips of a coin.
o Questions: Why is X binomial? What are n and p? o Responses:
n Sample size n fixed? n Each selection independent of others? n Just 2 possible values for each?n Each has same probability p?
Practice: 7.24 p.307
![Page 6: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/6.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.8
Example: A Simple Binomial Random Variable
o Background: The random variable X is the count of tails in two flips of a coin.
o Question: How do we display X?o Response:
Looking Back: We already discussed and displayed this random variable when learning about probability distributions.
Practice: 7.32a p.308
![Page 7: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/7.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.10
Example: Determining if R.V. is Binomial
o Background: Consider following R.V.:n Pick card from deck of 52, replace, pick another.
X=no. of cards picked until you get ace.o Question: Is X binomial?o Response:
Practice: 7.25b p.307
![Page 8: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/8.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.12
Example: Determining if R.V. is Binomial
o Background: Consider following R.V.:n Pick 16 cards without replacement from deck of
52. X=no. of red cards picked.o Question: Is X binomial?o Response:
Practice: 7.25d p.307
![Page 9: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/9.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.14
Example: Determining if R.V. is Binomial
o Background: Consider following R.V.:n Pick 16 cards with replacement from deck of 52.
W=no. of clubs, X=no. of diamonds, Y=no. of hearts, Z=no. of spades. Goal is to report how frequently each suit is picked.
o Question: Are W, X, Y, Z binomial?o Response:
Practice: 7.25a p.307
![Page 10: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/10.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.16
Example: Determining if R.V. is Binomial
o Background: Consider following R.V.:n Pick with replacement from German deck of 32
(doesn’t include numbers 2-6), then from deck of 52, back to deck of 32, etc. for 16 selections altogether. X=no. of aces picked.
o Question: Is X binomial?o Response:
![Page 11: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/11.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.18
Example: Determining if R.V. is Binomial
o Background: Consider following R.V.:n Pick 16 cards with replacement from deck of 52.
X=no. of hearts picked.o Question: Is X binomial?o Response:
n fixed n = 16 n selections independent (with replacement)n just 2 possible values (heart or not)n same p = 0.25 for all selectionsà____
Practice: 7.25c p.307
![Page 12: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/12.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.19
Requirement of IndependenceSnag:n Binomial theory requires independencen Actual sampling done without replacement
so selections are dependentResolution: When sampling without
replacement, selections are approximately independent if population is at least 10n.
![Page 13: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/13.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.21
Example: A Binomial Probability Problem
o Background: The proportion of Americans who are left-handed is 0.10. Of 46 presidents, 8 have been left-handed (proportion 0.17).
o Question: How can we establish if being left-handed predisposes someone to be president?
o Response: Determine if 8 out of 46 (0.17) is _______________ when sampling at random from a population where 0.10 fall in the category of interest.
Practice: 7.74 p.338
![Page 14: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/14.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.22
Solving Binomial Probability Problemsn Use binomial formula or tables
Only practical for small sample sizesn Use software
Won’t take this approach until latern Use normal approximation for count X
Not quite: more interested in proportionsn Use normal approximation for proportion
Need mean and standard deviation…
![Page 15: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/15.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.24
Example: Mean of Binomial Count, Proportion
o Background: Based on long-run observed outcomes, probability of being left-handed is approx. 0.1. Randomly sample 100 people.
o Questions: On average, what should be then count of lefties?n proportion of lefties?
o Responses: On average, we should getn count of lefties _____n proportion of lefties _____
Practice: 7.27 p.308
![Page 16: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/16.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.25
Mean and S.D. of Counts, ProportionsCount X binomial with parameters n, p has:n Meann Standard deviationSample proportion has:n Meann Standard deviation
Looking Back: Formulas for s.d. require independence: population at least 10n.
![Page 17: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/17.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.27
Example: Standard Deviation of Sample Count
o Background: Probability of being left-handed is approx. 0.1. Randomly sample 100 people. Sample count has mean 100(0.1)= 10, standard deviation
o Question: How do we interpret these?o Response: On average, expect
sample count =____ lefties. Counts vary; typical distance from 10 is ____.
Practice: 7.29c-d p.308
![Page 18: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/18.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.29
Example: S.D. of Sample Proportion
o Background: Probability of being left-handed is approx. 01. Randomly sample 100 people. Sample proportion has mean 0.l, standard deviation
o Question: How do we interpret these?o Response: On average, expect
sample proportion = ____ lefties. Proportions vary; typical distance from 0.1 is
____Practice: 7.29g-h p.308
![Page 19: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/19.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.31
Example: Role of Sample Size in Spread
o Background: Consider proportion of tails in various sample sizes n of coinflips.
o Questions: What is the standard deviation forn n=1? n=4? n=16?
o Responses: n n=1: s.d.=n n=4: s.d.=n n=16: s.d.=
A Closer Look: Due to n in the denominator of formula for standard deviation, spread of sample proportion____________ as n increases.
Practice: 7.34b p.309
![Page 20: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/20.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.32
Shape of Distribution of Count, ProportionBinomial count X or proportion for
repeated random samples has shape approximately normal if samples are large enough to offset underlying skewness. (Central Limit Theorem)
For a given sample size n, shapes are identical for count and proportion.
![Page 21: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/21.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.34
Example: Underlying Coinflip Distribution
o Background: Distribution of count or proportion of tails in n=1 coinflip (p=0.5):
o Question: What are the distributions’ shapes?o Response:
Practice: 7.32a p.308
![Page 22: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/22.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.36
Example: Distribution for 4 Coinflipso Background: Distribution of count or proportion of tails in n=4
coinflips (p=0.5):
o Question: What are the distributions’ shapes?o Response:
Practice: 7.32b p.308
![Page 23: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/23.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.37
Shift from Counts to Proportionsn Binomial Theory begins with countsn Inference will be about proportions
![Page 24: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/24.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.39
Example: Distribution of for 16 Coinflips
o Background: Distribution of proportion of tails in n=16coinflips (p=0.5):
o Question: What is the shape?o Response:
Practice: 7.34c p.309
![Page 25: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/25.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.41
Example:Underlying Distribution of Lefties
o Background: Distribution of proportion of lefties (p=0.1) for samples of n=1:
o Question: What is the shape?o Response:
![Page 26: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/26.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.43
Example: Dist of of Lefties for n= 16
o Background: Distribution of proportion of lefties (p=0.1) for n=16:
o Question: What is the shape?o Response:
Practice: 7.32c p.309
![Page 27: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/27.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.45
Example: Dist of of Lefties for n=100
o Background: Distribution of proportion of lefties (p=0.1) for n=100:
o Question: What is the shape?o Response:
Practice: 7.35a,b p.309
![Page 28: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/28.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.46
Rule of Thumb: Sample Proportion Approximately Normal
Distribution of is approximately normal if sample size n is large enough relative to shape, determined by population proportion p.
Require and
Together, these require us to have larger n for p close to 0 or 1 (underlying distribution skewed right or left).
![Page 29: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/29.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.48
Example: Applying Rule of Thumb
o Background: Consider distribution of sample proportion for various n and p:
n=4, p=0.5; n=20, p=0.5; n=20, p=0.1; n=20, p=0.9; n=100, p=0.o Question: Is shape approximately normal?o Response: Normal?
n n=4, p=0.5 n n=20, p=0.5 n n=20, p=0.1 n n=20, p=0.9 n n=100, p=0.1 [np=100(0.1)=10, n(1-p)=100(0.9)=90 both ³ 10]
________ [np=4(0.5)=2<10]________ [np=20(0.5)=10=n(1-p)]No [________________________]No [________________________]________
Practice: 7.38 p.310
![Page 30: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/30.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.50
Example: Solving the Left-handed Problem
o Background: The proportion of Americans who are lefties is 0.1. Consider P( ³8/46=0.17) for a sample of 46 presidents.
o Question: Can we use a normal approximation to find the probability that at least 8 of 46 (0.17) are left-handed?
o Response:
Probability
0.
0.
Actual (binomial) probability is 0.084
Approximated (normal) probability is 0.047.
0.1 0.170.17 Practice: 7.35b p.309
![Page 31: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/31.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.52
Example: From Count to Proportion and Vice Versa
o Background: Consider these reports:n In a sample of 87 assaults on police, 23 used weapons.n 0.44 in sample of 25 bankruptcies were due to med. bills
o Question: In each case, what are n, X, and ?o Response:
n First has n = ____, X = ____, = _____ n Second has n = ____, = _____, X = __________
Practice: 7.29a-b p.308
![Page 32: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/32.jpg)
Looking Back: Review o 4 Stages of Statistics
n Data Production (discussed in Lectures 1-3)n Displaying and Summarizing (Lectures 3-8)n Probability
o Finding Probabilities (discussed in Lectures 9-10)o Random Variables (introduced in Lecture 10)
n Binomial (just discussed in Lecture 11)n Normal
o Sampling Distributionsn Statistical Inference
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.53
![Page 33: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/33.jpg)
Role of Normal Distribution in Inference n Goal: Perform inference about unknown
population proportion, based on sample proportion
n Strategy: Determine behavior of sample proportion in random samples with known population proportion
n Key Result: Sample proportion follows normal curve for large enough samples.
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.54
Looking Ahead: Similar approach will be taken with means.
![Page 34: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/34.jpg)
Discrete vs. Continuous Distributions n Binomial Count X
o discrete (distinct possible values like numbers 1, 2, 3, …)
n Sample Proportion o also discrete (distinct values like count)
n Normal Approx. to Sample Proportion o continuous (follows normal curve)o Mean p, standard deviation
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.55
![Page 35: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/35.jpg)
Sample Proportions Approx. Normal (Review)
n Proportion of tails in n=16 coinflips (p=0.5) has
n Proportion of lefties (p=0.1) in n=100 people has
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.56
, shape approx normal
, shape approx normal
![Page 36: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/36.jpg)
Example: Variable Typeso Background: Variables in survey excerpt:
o Question: Identify type (cat, discrete quan, continuous quan)n Age? Breakfast? Comp (daily min. on computer)? Credits?
o Response:n Age: n Breakfast: n Comp (daily time in min. on computer): n Credits:
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.58Practice: 7.43 p.330
![Page 37: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/37.jpg)
Probability Histogram for Discrete R.V.Histogram for male shoe size X represents
probability by area of barsn P(X £ 9) (on left) n P(X < 9) (on right)
For discrete R.V., strict inequality or not matters.©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.59
![Page 38: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/38.jpg)
Definition Density curve: smooth curve showing prob. dist. of
continuous R.V. Area under curve shows prob. that R.V. takes value in given interval.
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.60
Looking Ahead: Most commonly used density curve is normal z but to perform inference we also use t, F, and chi-square curves.
![Page 39: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/39.jpg)
Density Curve for Continuous R.V.Density curve for male foot length X represents
probability by area under curve.
Continuous RV: strict inequality or not doesn’t matter.
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.62
A Closer Look: Shoe sizes are discrete; foot lengths are continuous.
![Page 40: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/40.jpg)
68-95-99.7 Rule for Normal Data (Review)Values of a normal data set haveo 68% within 1 standard deviation of meano 95% within 2 standard deviations of meano 99.7% within 3 standard deviations of mean
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.64
![Page 41: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/41.jpg)
68-95-99.7 Rule: Normal Random VariableSample at random from normal population; for sampled value X
(a R.V.), probability iso 68% that X is within 1 standard deviation of meano 95% that X is within 2 standard deviations of meano 99.7% that X is within 3 standard deviations of mean
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.65
![Page 42: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/42.jpg)
Example: 68-95-99.7 Rule for Normal R.V.o Background: IQ for randomly chosen adult is normal R.V. X with
. o Question: What does Rule tell us about distribution of X ?o Response: We can sketch distribution of X:
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.68Practice: 7.47 p.331
![Page 43: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/43.jpg)
Example: Finding Probabilities with Ruleo Background: IQ for randomly chosen adult is normal R.V. X
with . o Question: Prob. of IQ between 70 and 130 = ?
o Response:
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.70Practice: 7.48a p.331
![Page 44: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/44.jpg)
Example: Finding Probabilities with Ruleo Background: IQ for randomly chosen adult is normal R.V. X
with . o Question: Prob. of IQ less than 70 = ?o Response:
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.72Practice: 7.49a p.331
![Page 45: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/45.jpg)
Example: Finding Probabilities with Ruleo Background: IQ for randomly chosen adult is normal R.V. X
with . o Question: Prob. of IQ less than 100 = ?o Response:
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.74
![Page 46: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/46.jpg)
Example: Finding Values of X with Ruleo Background: IQ for randomly chosen adult is normal R.V. X
with . o Question: Prob. is 0.997 that IQ is between…?o Response:
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.76Practice: 7.48c p.331
![Page 47: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/47.jpg)
Example: Finding Values of X with Ruleo Background: IQ for randomly chosen adult is normal R.V. X
with . o Question: Prob. is 0.025 that IQ is above…?
o Response:
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.78Practice: 7.48d p.331
![Page 48: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/48.jpg)
Example: Using Rule to Evaluate Probabilitieso Background: Foot length of randomly chosen adult male is
normal R.V. X with (in.) o Question: How unusual is foot less than 6.5 inches?o Response:
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.80Practice: 7.49b p.331
![Page 49: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/49.jpg)
Example: Using Rule to Estimate Probabilitieso Background: Foot length of randomly chosen adult male is
normal R.V. X with (in.) o Question: How unusual is foot more than 13 inches?o Response:
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.82Practice: 7.49c-d p.331
![Page 50: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/50.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.83
Lecture Summary(Binomial Random Variables)
o Definition; 4 requirements for binomialo R.V.s that do or don’t conform to requirementso Relaxing requirement of independenceo Binomial counts, proportions
n Meann Standard deviationn Shape
o Normal approximation to binomial
![Page 51: Lecture 11: Chapter 7, Secs. 2-3 Binomial and Normal](https://reader034.vdocuments.us/reader034/viewer/2022043020/626bca6186a6e62ec1289248/html5/thumbnails/51.jpg)
©2011 Brooks/Cole, Cengage Learning
Elementary Statistics: Looking at the Big Picture L11.84
Lecture Summary(Normal Random Variables)
o Relevance of normal distributiono Continuous random variables; density curveso 68-95-99.7 Rule for normal R.V.s