law of probability and chi-square analysisclasspages.warnerpacific.edu/bdupriest/bio 250/law...
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Law of Probability and Chi-Square Analysis
Bio 250 Genetics
Dr. Ramos
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Independent Assortment
• Mendel’s dihybrid crosses.
• Extensive genetic diversity.
The separation of the allele from the mother from the allele from the father occurs during the first division of meiosis and is called segregation.
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Independent Assortment
• Number of possible gamete = 2n
• n= haploid number
Calculate the number of possible gametes in humans…
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Laws of Probability
• Genetic ratios expressed as probabilities
¾ tall: ¼ dwarf
• Probability ranges from 0.0 to 1.0
• Product law = probability of possible outcomes when two events that occur independently but at the same time.
• Sum law = probability where the possible outcome of two events are independent but can be accomplished in more than one way.
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Forked-Line Method
• Trihybrid crosses
– 3 pairs of contrasting traits
– Segregation and independent assortment
– Punnet square with 64 separate boxes!!
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Laws of Probability
• Probability in a small vs. large group
– Smaller groups – a larger deviation from predicted ratio due to chance.
– Impact of deviation due to chance diminishes as the sample size increases.
– Random fluctuation
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III. Statistics and chi-square
• How do you know if your data fits your
hypothesis? (3:1, 9:3:3:1, etc.)
• For example, suppose you get the following
data in a monohybrid cross:
Phenotype Data Expected (3:1)
A 760 750
a 240 250
Total 1000 1000
Is the difference between your data and the expected ratio due to chance deviation or is it significant?
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Two points about chance deviation
1. Outcomes of segregation, independent
assortment, and fertilization, like coin tossing,
are subject to random fluctuations.
2. As sample size increases, the average deviation
from the expected fraction or ratio should
decrease. Therefore, a larger sample size
reduces the impact of chance deviation on the
final outcome.
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The null hypothesis
The assumption that the data will fit a given ratio, such as 3:1 is the null hypothesis. It assumes that there is no real difference between the measured values and the predicted values. Use statistical analysis to evaluate the validity of the null hypothesis.
•If rejected, the deviation from the expected is NOT due to chance alone and you must reexamine your assumptions. •If failed to be rejected, then observed deviations can be attributed to chance.
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Process of using chi-square analysis
to test goodness of fit
• Establish a null hypothesis: 1:1, 3:1, etc.
• Plug data into the chi-square formula.
• Determine if null hypothesis is either (a) rejected or
(b) not rejected.
• If rejected, propose alternate hypothesis.
• Chi-square analysis factors in (a) deviation from
expected result and (b) sample size to give measure
of goodness of fit of the data.
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Chi-square formula
• Once X2 is determined, it is converted to a probability
value (p) using the degrees of freedom (df) = n- 1
where n = the number of different categories for the
outcome.
X2
(o e)2
e
where o = observed value for a given category, e = expected value for a given category, and sigma is the sum of the calculated values for each category of the ratio
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Chi-square - Example 1
53.0
250
250240
750
750760
2
222
2
e
eo
Phenotype Expected Observed
A 750 760
a 250 240
1000 1000
Null Hypothesis: Data fit a 3:1 ratio.
degrees of freedom = (number of categories - 1) = 2 - 1 = 1
Use Fig. 3.12 to determine p - on next slide
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X2 Table and Graph
Unlikely: Reject hypothesis
Likely: Do not reject Hypothesis
likely unlikely
0.50 > p > 0.20
Figure 3.12
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Interpretation of p
• 0.05 is a commonly-accepted cut-off point.
• p > 0.05 means that the probability is greater than 5%
that the observed deviation is due to chance alone;
therefore the null hypothesis is not rejected.
• p < 0.05 means that the probability is less than 5%
that observed deviation is due to chance alone;
therefore null hypothesis is rejected. Reassess
assumptions, propose a new hypothesis.
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Conclusions:
• X2 less than 3.84 means that we accept the Null
Hypothesis (3:1 ratio).
• In our example, p = 0.48 (p > 0.05) means that we
accept the Null Hypothesis (3:1 ratio).
• This means we expect the data to vary from
expectations this much or more 48% of the time.
Conversely, 52% of the repeats would show less
deviation as a result of chance than initially observed.
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Glossary Sheet
• Terms you should know from this lecture:
• Terms you should know for the next lecture:
Incomplete dominance Lethal allele
Codominance Epistasis
X-linkage Sex-limited inheritance
Sex-influenced inheritance Penetrance
Expressivity Position effect