last lecture chemical weathering: main driver is acidic water when common rock forming minerals are...
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Last Lecture• Chemical weathering: main driver is acidic water• When common rock forming minerals are weathered the
typical reaction results in some loss of cations and the production of clays
• Because silicate mineral weathering consumes CO2, weathering can influence global climate
alpha
Quantifying Physical Weathering Rates
Cosmogenic Radionuclides:
neutron
CRNs produced in rock and soil• We know how fast• Can give age / erosion rate
Heimsath et al., 1999Coastal California
Heimsath et al. 2000SE Australia
Does soil production vary with soil depth?
Heimsath et al. 2001Oregon Coast Range
Wilkinson et al. 2005Blue Mountains, Australia
Does soil production vary with soil depth?
YES!
Evidence for both peaked and exponential soil production functions depending on where you are
h
Wep
p = Production rate
W = Production rate when there is no soil
= A length that tells you how
much the production rate decreases with increasing soil thickness
h = Soil thickness
Place W in mm/yr
in m Reference
Australia (1) 0.143 0.238 Heimsath et al., Quat. Int., 2001
California 0.077 0.435 Heimsath et al. Geomorph. 1999
Oregon 0.268 0.333 Heimsath et al. ESPL 2001
Australia (2) 0.053 0.5 Heimsath et al., Geology 2000
This is what the soil production function looks like
• Natural erosion rates can on sloping lands range from 1 metre per million years to several mm per year (1 mm/yr = 1km/million years)
• Disturbance (e.g., humans) can raise rates by 100 times or more!
• Soil can be stripped in decades
Human Disturbance
• If you strip the soil, how long does it take to recover?
• Mass balance: The rate of change of soil thickness is equal to the rate of soil production minus the rate of erosion:
Epdt
dh
Human Disturbance
• Take a very simple situation. You strip away all the soil, and then you manage to reduce the erosion rate to zero:
Epdt
dh
Time it takes soil to recover
0
• Take a very simple situation. You strip away all the soil, and then you manage to reduce the erosion rate to zero:
• And remember, soil production is a function of depth:
Epdt
dh
Time it takes soil to recover
0
h
Wep
• So putting these two together you get:
• It turns out you can solve this equation, to find out how long it takes for the soil to reach some thickness h:
h
Wedt
dh
1 h
eW
t
Time it takes soil to recover
H = 0.2m
h = 0.5m
1230 yrs
4296 yrs
1530 yrs
7990 yrs
2460 yrs
8590 yrs
3060 yrs
16000 yrs
So soil conservation is important because once it is gone, it is gone for a very long time!
How long does it take?
Late Holocene (last 4ka) uplift/subsidence rates (mm/yr)
Late Holocene surface change
Shennan and Horton (2001), J. Quat Sci., 17, 511-526.
Late Holocene surface change
• Fastest rate of soil production measured ->0.1-0.2 mm/yr)
• We shouldn’t expect the same background erosion rates all over the UK
So
• Fastest rate of soil production measured ->0.1-0.2 mm/yr)
• We shouldn’t expect the same background erosion rates all over the UK
Soil mantled landscape Bedrock landscape
• Relative balance between erosion and production of soil
http://static.panoramio.com/photos/original/147837.jpg
Transport limited Weathering limited
Weathering can make sediment available for transport: then what?
Mobile Soil
Bedrock/Saprolite
Soil Production
Erosion
Soil Mantled Landscape: Soil Production > Erosion
Infiltration rates
• Also:– Tropical rainforest in Australia: 1350 mm/hr– Oregon Coast Range 5400 mm/hr
Understanding saturation on hillslopes
• Important for hydrology
• Also for slope stability
Why are these the bits that are saturated?Water collects, but soil is thicker.Can we make predictions????
Predicting saturation
If you cant get this right, you’ve got no chance of predicting basin response to storms because of this
Some simple
box models:
It rains
Imagine this as a box
Coming in:Rain
Going out:Overland flowEvaporation
Groundwater flowDeep flow
Nothing coming inFrom the right becauseIt is a drainage divide
Going in, coming out
• Coming in:p*LWhere p is precipitation rate and L is
length of box
• Going out:r*LWhere r is the return flow rate
Going in, coming out
• Going outet*LWhere et is
evapotranspiration rate
qSSF*dSSF
Where q is the Darcy velocity and d is the depth of shallow subsurface flow
Okay, lets do things in volumes per time
• Coming in:p*AWhere p is precipitation rate and L is
length of box
• Going out:r*AWhere r is the return flow rate
Okay, lets do things in volumes per time• Going outet*AWhere et is evapotranspiration rate
qSSF*b*dSSF
Where q is the Darcy velocity and d is the depth of shallow subsurface flow
If there is no change in the amount of water in the box, what goes in must come out
p*A=et*A+r*A+ qSSF*b*dSSF
This is a bit ugly. Lets name something the water supply, call it ‘w’, and let it be equal to the precipitation minus the evapotranspiration and return flow:w = p-et-r
If there is no change in the amount of water in the box, what goes in must come out
w*A = qSSF*b*dSSF
Okay, all this equation says is that the water supplied to the hillslope must equal the water leaving the hillslope from Horton overland flow and shallow subsurface flow
w*A = qSSF*b*dSSF
But wait! We know qSSF = K*sin(q)*cos(q)
If there is no change in the amount of water in the box, what goes in must come out
q = K(h/L)h/L=sin(q)
So q = K sin(q)
Implications
How much water can a hillslope transport before overland flow occurs?
Max water supply rate is:
A
bKdw soil )cos()sin(max
How much water can a hillslope transport before overland flow occurs?
Increase K Increase w
Increase dsoil
Increase w
Increase q Increase w (up to a point)
Increase A Decrease w
wmax = K*sin(q)*cos(q)*b*dSoil/A
Some numbersA/b (in metres)
– divergent slope ~1-10– Planar slope ~10-200– Convergent slope ~100-100,000
• Soil thickness: 0-3m
• K in cm/hr– Silt: 0.01– Sand: 40
Creep vs. Overland flowZone where creep dominates(Convex)
Zone where overland flow dominates(Concave)
Exfiltration and overland flow
Creep processes lead to hillslopes with different curvature than overland flow.
Resolution of forces acting on a slope
W
N
t
S
a
W: weight of materialN: normal force acting perpendicular to slope t: shear force acting parallel to slopeS: shear strength (resistance to shear)a: slope angle
•Friction/shear strength depends on the normal force!•Pore water reduces both normal force and frictional resistance to sliding
Landslides
Driving and resisting forces
Shear tries to get the block to slide downhill
This is resisted by friction
Resisting stress
• Friction resists sliding• The friction is a function of the effective
normal stress• R = seff*tan(f)• tan(f) is the friction slope
Resisting stress
• Effective normal stress: buoyant weight of the soil mass– Wbuoyant = Wsoil –Wwater
seff = cos(q)*(Wsoil-Wwater)
So, balance the forces:
• At the limit of stability, friction and cohesion just balance shear stress:
t = Cr + seff*tan(f)
There is something called the ‘factor of safety’. It is the ratio between resisting forces and forces compelling the soil to move downslope:
FS = (Cr + seff*tan(f))/t
So, balance the forces:
FS = (Cr + seff*tan(f))/t
or
The depth of water in soil at the failure point is equal to:
)sin()cos(
)tan()(cos)( 2
ss
wwssr
dg
ddgCFS
)tan()(cos
)cos()sin()tan()(cos2
2
w
ssssrw g
dgdgCd
Rainfall rate for failure
Can solve for the depth of water at a given supply rate in the soil
bK
wAdw )cos()sin(
)tan()(cos
)cos()sin()tan()(cos2
2
w
ssssrw g
dgdgCd
Rainfall rate for failureThis is the supply rate at failure
Now you can get a good idea of how much rain you need to get one of these:
)tan(
)sin()tan()cos()cos()tan(
w
ssr
Ag
dgCKbw
But wait…
Supply rate that fills soil:
wA
bKds )cos()sin(
Must be larger than the supply rate to cause failure
)tan(
)sin()tan()cos()cos()tan(
w
ssr
Ag
dgCKbw
A few typical values
Typical root cohesion: 500-15000N/m2
Typical tan(f): 0.8rw = 1000 kg/m3
rs = 1500-1900 kg/m3
• K in cm/hr– Silt: 0.01– Sand: 40
Can the hillslope fail at all?
• If the slope is still stabile once it fills with water, it won’t fail at all.
• This is the equation for the factor of safety if the soil is saturated (that is dw = ds)
)sin(
)tan()cos()(
)sin()cos(
s
ws
ss
r
dg
CFS
Conclusions• 4 runoff mechanisms• Slope stability: depends
on gradient, amount of water, cohesion, and soil thickness
• You should familiarize yourself with the stability equations (we use them in practicals!
Reading:
Get it here: http://eps.berkeley.edu/development/view_person.php?uid=1164&page=81