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    Physic Report

    2011

    Written By :Funy Agustina / 14

    XI IPA 5SMA NEGERI 1

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    Emphasis

    Ia Activities

    1. Basic Theory

    Rigid body will perform translational motion when the force applied on the right thingsabout a point called the center of gravity. Center of gravity is the point where the object will

    be in rotational equilibrium (not experience rotation). At the time of rigid body having

    translational and rotational motion at once, then at that point the weight will act as the axis of

    rotation and the trajectory of motion of this weight point trajectory describes the motion

    translation.

    In almost all the problems of mechanics, g (acceleration of gravity) may be considered

    uniform in all parts of the body, because the relatively small body size than the distance that

    can cause a significant change in g. Thus the center of mass and center of gravity can be taken

    as the same point. For objects that have a severe form of an arbitrary location of the point

    sought by calculation. The calculation is based on the assumption that we can take some

    points from the objects that wish calculated is multiplied by the heavy emphasis on each point

    and then summed and divided by the total weight on each point. said center of gravity is also

    the center of mass near the earth's surface, but to place a certain height above the earth's

    center of gravity and center of mass to be distinguished.

    2. Purposes

    Finding that center of gravity (the center of mass) object area is located on the heavy line

    through experiment / observation.

    3. Tools and Materials

    The object area (thin, made of plate, wood or cardboard). These objects there is an

    irregular shape (equilateral triangle or isosceles triangle, square or rectangle,

    circle) is an arbitrary shape.

    Yarn smooth and strong.

    Measuring tool length / gauge / ruler.

    4. Procedure

    Prepare any object whose shape follows the thread and stative as a place to

    hang objects in a variety of free position (eg 5 different positions).

    By using a rope / yarn, we hang objects at a point A on the edges. If the object

    is at rest the center of gravity should be located straight below the hanging

    point A, so the emphasis lies on the line Aa (Aa line is an extension cord

    hanging objects).

    Ichtiar Melia Cahyanti /17 11 exact 5

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    Figure 5: Things The area

    Aa is the line of gravity of the object, Bb is the line of gravity of the object. Aa and Bb

    intersect at O.

    - Hang it on any other point on the edges. Example C, if the vertical line through O will

    also Cc ? Explain your answer along with reason!

    Answer: because the location of the center of gravity is always located at the intersectionof the two vertical lines for any object.

    - Based on data obtained in steps 1 and 2 (step on it), make a conclusion that led to the

    definition of the center of mass!

    Answer: The center of mass and center of gravity of an object have the same understanding, is

    a point where centered mass / weight of the object. The difference is the location of the center

    of mass of an object is not influenced by the gravitational field, so it's not always coincide

    with the location of point weight.

    5. Result of Experiment

    6. Conclusion

    Emphasis is also a center of mass near the earth's surface, but to place a certain height above

    the earth's center of gravity and center of mass to be distinguished.

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    Cc

    A

    Aa

    A Aa

    B

    Bb

    A

    Aa

    B

    Bb

    C

    O

    O

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    KESETIMBANGAN BENDA

    EQUILIBRIUM OBJECTS

    Objectives : To identify the location of the equilibrium thing

    Basic Theory :Objects that perform rotational motion caused by the torque. If the

    torque is done on a stationary object larger than the torque which inhibit, the object will rotate

    alias rotate. In this case the difference between the torque is done on the body by inhibiting

    the torque is called the total torque. So, really makes a rotating object is the total torque.

    Torque = force x arm style. When we give the torque on a body, we actually exert forces on

    the object, but that style is also multiplied by the long arm styles. Torque on an arbitrary point

    chosen as the axis equal to zero.

    =0

    Where, torsi=

    Things called rigid if the distance between any part of it was always the same. Each object

    can change shape (become rigid), if the object is subjected to torque. If the object shape

    changes, the distance between any part of it, of course, change is not rigid anymore.

    Tools and materials:

    Paralon

    Millimeter blog

    Pulleys

    Yarn

    Expenses

    Stative

    Procedure :

    1. Arrange the equipment as shown below

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    Gambar 3

    Try to tilt and right rod AB on graph paper Mark on graph paper points A, A ', B, B', C, C ', D, and D'. Graph paper mounted so that it

    records all those points.

    Deliver graph paper from the board.

    1. Weigh the burden and the rod A

    M1 = 50 gram / 0,5 kg W1 = 4,9 N

    M2 = 50 gram / 0,5 kg W2 = 4,9 N

    M3 = 90 gram / 0,9 kg W3 = 8,89 N

    M4 = 9 gram / 0,09 W4 = 0,88 N

    2. In the above graph paper, draw the forces T1, T2, W3, and WAB like the following

    picture:

    Try to keep the length of T1, T2, W3, and answered in accordance with their

    respective major vector in which T1 and T2 = W1 = W2

    Describe the forces T1 and T2 into horizontal and vertical components.

    Draw each arm styles (from point C) of T1, T2, and W3 that is li, LII, LIII.

    Fill in the following table

    No Fx (N) Fy (N) (Nm)

    1 Tax =5,5 Tay = 8,5 0 Nm

    2 Tbx =2,2 Tby =3,35 0,72 Nm

    3 Wx =1,3 Wb =8,8 0,52 Nm

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    Wab

    A

    B

    C D

    AB

    W3

    W2

    W1

    C

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    4 Wx = Wab =0,88 0,07 Nm

    Fx =7,7 Nm Fy = 21,53 Nm = 1,31 Nm

    Conclusion:

    To obtain the middle point of an object, we can look with a body weight of the point by

    drawing a line from the center of gravity.

    From the above trials, found that the object will be balanced when rotating and translating

    objects.

    =0F dan =0

    If the object has a resultant force = 0, then the object has not changed shape, mass, and

    volume.

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