laboratory exercises in medical chemistry...
TRANSCRIPT
Laboratory Exercises in Medical Chemistry I
1
st year, General Medicine
Faculty of Medicine in Pilsen
Charles University
Name: Confirmation of the attendance at the labs
(stamp, tutor's signature)
Study group:
Date:
Date of report delivery:
Report accepted returned for revision
Programme
a) Reactions of inorganic compounds
- reaction of Ag+ ions with dilute solution of HCl
- reaction of Fe3+
ions with a solution of potassium ferrocyanide
- reaction of Fe3+
ions with SCN- ions
- reaction of Cu2+
ions with ammonia
- reaction of Ca2+
ions with oxalic acid
- reaction of carbonates with dilute solution of HCl
b) Qualitative analysis of cations and anions
- demonstration of the procedure for identification of Ni2+
cation
- demonstration of the procedure for identification of SO42-
anion
- identification of the cation and the anion in an unknown sample
There is a rack with clean test tubes on your working place. In addition, there is an empty rack
intended to be used for placing dirty test tubes. After the work is done, take the rack with test tubes
you have used, and pour out the content according to instruction of laboratory assistants (there are
extra bottles for collecting the waste in the laboratory). Moreover, they will specify, where to put
empty dirty test tubes.
A lab coat is required to be worn over your clothes, when working in a lab!
After the work is done, clean your working place so that it is the same as it was in the beginning!
Before you leave the lab, ask laboratory assistant for a stamp and your tutor for signature!
1
a) Reactions of inorganic compounds
For each of the following exercises, you need ONE clean test tube. It does not matter on the exact measurement
of volumes. You can pour the solutions into test tubes directly from bottles in appropriate small volume
(about 1 ml, i.e. approx. 1 cm of the column height of liquid in a test tube). Do not pipette the solutions!
1. Reaction of Ag+ ions with diluted solution of HCl
Pour into a test tube about 1 ml of solution with Ag+ ions.
CAUTION: contamination of the skin with Ag+ ions causes unremovable black spots
( ! not only pouring the solution on your skin is risky, touching on dirty glass as well ! )
Add about 1 ml of dilute solution of HCl into the test tube and watch the reaction.
Describe the changes observed:
Chemical equation in ionic form Colour of the precipitate
2. Reaction of Fe3+
ions with a solution of potassium ferrocyanide
Pour into a test tube about 1 ml of solution with Fe3+
ions.
Add several drops of potassium ferrocyanide solution into the test tube and watch the reaction.
Describe the changes observed:
Chemical equation in ionic form Colour of the solution
What is the traditional name for a dye produced by reaction of Fe3+
ions with ferrocyanides?
2. Reaction of Fe3+
ions with SCN- ions
Pour into a test tube about 1 ml of solution with Fe3+
ions. Add several drops of a solution with SCN-.
Describe the changes observed:
Potassium ferrocyanide – formula:
Colour of the solution containing Fe3+
ions:
2
4. Reaction of Cu2+
ions with ammonia
Pour into a test tube about 1 ml of solution with Cu2+
ions.
Add about 1 ml of dilute solution of ammonia into the test tube and watch the reaction.
Describe the changes observed:
Chemical equation in ionic form Colour of the solution
5. Reaction of Ca2+
ions with oxalic acid
Free Ca2+
ions play many roles in body fluids. Ca2+
ions are very important in the process of blood
clotting (hemocoagulation). Removal of Ca2+
can prevent blood clotting in vitro. This can be used in
clinical medicine. Ca2+
ions can be removed from the solution (bound) by the use of organic acids
with more carboxylic groups, e.g. oxalic acid or citric acid.
oxalic acid – structural formula
citric acid – structural formula
Let's try the reaction of Ca2+
ions with oxalic acid. Pour into a test tube about 1 ml of Ca2+
solution.
Add about 1 ml of oxalic acid solution into the test tube and watch the reaction.
Describe the changes observed:
Chemical equation in ionic form Colour of the precipitate
6. Reaction of carbonates with diluted solution of HCl
Pour into a test tube about 1 ml of sodium carbonate solution. Add about 1 ml of dilute solution of
HCl into the test tube and watch the reaction.
Describe the changes observed:
Chemical equation Gas, that is released
Colour of the solution containing Cu2+
ions:
3
b) Qualitative analysis of cations and anions
All the reactions you will perform will be in aqueous environment, where are the soluble inorganic
salts usually dissociated into ions.
In your practical exercises, you will work only with solutions, where is single "simple" inorganic
compound disolved, in other words – just one cation and just one anion. This information very
simplifies the analysis. When you successfully identify one cation, you can stop. It is not necessary tio
continue, no other cation is in the sample. Similarly for the anion. There can be often many cations
and many aniont in real samples. In such cases (mixture of several compounds), the analysis is more
difficult.
Classification of cations – hydrogene sulfide system
Cations are classified into 5 groups according to the results of so called "group reactions".You have to
use group reagents for that purpose. It is necessary to work systematically – to begin from the very
beginning – to test the presence of group I cations.
In case of positive result you know that one of the cations of this analytical group is in the sample.
Now it is time to use so called selective or specific reactions to distinguish among cations belonging
into this group.
Negative result excludes this group of cations. Only after exclusion of the group, you may continue
and test the presence of cations from the next group in order.
Not understanding the principle, on which the whole system of classification is based, is the most
usual cause for being unsuccessful in analysis of unknown sample. You can test the group reaction for
"higher" analytical group only after you exclude the presence of cations of all previous groups! Cation
of the group I can positively react with group reagents for "higher" groups!
You have to keep the order of reactions tested on your sample, i.e. you have to begin always with
tests for group I and in case of negative result to continue to the next group in order. Once the group
reaction is positive, identification of the group is done. Now you have to direct your attention only on
cations belonging into this group.
Group I – insoluble chlorides Ag+ Pb
2+
Group reagent: dilute solution of HCl
Add a dilute solution of HCl to the sample. Formation of precipitate means the presence of cation
from this group. If no precipitate forms, you can exclude this group and you have to continue with test
for presence of cations of the group II.
AgCl white precipitate
PbCl2 white precipitate
Both cations, Ag+ and Pb
2+, give white precipitate of insoluble chloride. How can we distinguish
between them?
1st option
Ag+ and Pb
2+ cations form precipitates of chromates that very differ in colour.
Ag2CrO4 reddish-brown precipitate
PbCrO4 yellow precipitate
The procedure: Pour the original solution in a new test tube and add appropriate volume of K2CrO4.
aqueous solution of sodium chloride – what ions are present?
4
2nd
option
Silver chloride is soluble in ammonia, lead chloride is insoluble.
The procedure: Add enough of dilute ammonia solution to the precipitate in the test tube (about
double volume than the volume you already have in the test tube). Mix thoroughly. If the precipitate
disappears, it was AgCl, and we have identified Ag+ cation. In the opposite case, the cation is Pb
2+.
Group II – insoluble sulfides that precipitate from acidic environment
This group has two subgroups: II. A Hg2+
Cu2+
Cd2+
II. B As3+
Sb3+
Sn2+
Group reagent: dilute solution of HCl and hydrogensulfide water
Acidify the sample by addition of small volume of dilute HCl solution. Go to the fume chamber and
add hydrogen sulfide water. Formation of precipitate of insoluble sulfide means presence of a cation
of this group.
group II.A HgS black precipitate
CuS black precipitate
CdS yellow precipitate
group II.B As2S3 yellow precipitate
Sb2S3 orange precipitate
SnS brown precipitate
Distinguishing between subroups
Precipitates of sulfides of II.A group cations are insoluble in ammonium polysulfide (NH4)2Sx.
Precipitates of sulfides of II.B group cations are soluble in ammonium polysulfide (NH4)2Sx.
There is a bottle with (NH4)2Sx in a fume chamber. Be very careful in testing the solubility in case of
yellow precipitate (the only way to distinguish between Cd2+
and As3+
).
Do NOT take the test tube out from the fume chamber! When the experiment is done, pour the content of the test tube into a bottle for collection of waste
inside the fume chamber and put the ampty test tube into a basket there
Ions in subgroups can be distinguished according to the colour of precipitates of sulfides. Hg2+
ions
and Cu2+
ions can be distinguished form each other according to the colour of original solution. Hg2+
ions are colourless Cu2+
ions form in aqueous solutions blue complexes [Cu(H2O)4]2+
. The blue colour
can be deepened by addition of ammonia.
Group III.A – insoluble hydroxides Fe3+
Cr3+
Al3+
Group reagent: solution of NH4Cl and dilute ammonia (NH3)
Optimal pH for precipitation is around 9, the reagent acts as a buffer and mantaines this wanted pH.
Add NH4Cl soloution to the sample in a test tube first and then add dilute solution of ammonia.
Formation of precipitate means presence of cation from this group.
Fe(OH)3 brown precipitate
Cr(OH)3 grayish-green precipitate
Al(OH)3 white (colourless) gelatinous precipitate
Use the colour of original solution to distinguish between cations of this group. Fe3+
ions are yellow in
solution, Cr3+
ions are deep green and Al3+
ions colourless.
5
Presence of Fe3+
ions can be confirmed by two nice reactions. Use original solution of the sample, add
ammonium thiocyanate (deep red colour similar to blood is formed) or potassium ferrocyanide (deep
blue colour is formed, so called "Prussian blue").
[Fe(SCN)]2+
red solution
{Fe[Fe(CN)6]}- blue solution
Group III.B – sulfides that precipitate in alkaline pH Fe2+
Co2+
Ni2+
Zn2+
Group reagent: dilute ammonia and solution of (NH4)2S
Ions of group III.B precipitates as sulfides insoluble in alkaline environment. First add small volume
of ammonia and then the precipitation reagent – amonnium sulfide (work inside fume chamber).
Formation of precipitate means presence of cation from this group.
FeS black precipitate
CoS black precipitate
NiS black precipitate
ZnS white precipitate
Do NOT take the test tube out from the fume chamber! When the experiment is done, pour the content of the test tube into a bottle for collection of waste
inside the fume chamber and put the ampty test tube into a basket there.
You should easily identify Zn2+
ions, that gives whitesulfide and are colourless in original solution
(all the other cations in this group are obviously coloured). The appeearance of other three sulfides is
similar (black precipitate), so we have to continue in investigation.
Fe2+
ions are light green in colour and give striking colour raction with potassium ferricynide (deep
blue colour - "Prussian blue").
{Fe[Fe(CN)6]}- blue solution
Co2+
ions are pink in hydrated form.
Ni2+
ions are easy to identify, their aqueous solutions are clearly green. Addition of few drops of
ammonia changes the colour to blue.
[Ni(NH3)6]2+
blue solution
Group IV – insoluble carbonates Ba2+
Sr2+
Ca2+
Mg2+
Group reagent: dilute solution of ammonia and a solution of (NH4)2CO3
First add small volume of ammonia and then the precipitation reagent – amonnium carbonate
(NH4)2CO3. Formation of precipitate means presence of cation from this group.
BaCO3 white precipitate
SrCO3 white precipitate
CaCO3 white precipitate
MgCO3 white precipitate (after being boiled)
Ca2+
precipitates after addition of oxalic acid. The other cations do not react.
(COO)2Ca white precipitate
To distinguish between Ba2+
and Sr2+
use the flame test. There is a working place with lab burner in
the laboraotry. Ba2+
ions turn colour of the flame to green, Sr2+
to crimson (red).
6
Group V - ions of alkali metals and ammonium ion Li+ Na
+ K
+ NH4
+
Group reagent: – (no group reagent)
Cation is classified to be from fifth group of cations by excluding all the previous groups. It is quite
difficult to identify cations of group V.
Distinguishing among Li+, Na
+ and K
+ can be done by the flame test. Li
+ ions colour the flame to
crimson (red). (caution – very similar colour is caused by Sr2+
). Na+ ions colour the flame to yellow
and K+ ion to violet.
NH4+ ions can be detected by Nessler's reagent (alkaline solution of Hg[HgI4]). This reaction is very
sensitive, even very diluted solutions react. Pour about 1 ml of unknown sample into a test tube, add
small volume of dilute solution of NaOH and few drops of the reagent. Record the formation of brown
precipitate, in case of dilute solutions of yellow colour.
Classification of cations into analytical groups
Group Reagent Cation Colour of the precipitate Original solution Notes
I HCl Ag
+ AgCl (white) colourless reddish-brown Ag2CrO4
Pb2+ PbCl2 (white) colourless yellow PbCrO4
II.A
HCl
+
H2S
Hg2+ HgS (black) colourless
precipitates of sulfides are
insoluble in ammonium
polysulfide
Cu2+ CuS (black) light blue
Cd2+ CdS (yellow) colourless
II.B
As3+ As2S3 (yellow) colourless
precipitates of sulfides are
soluble in ammonium
polysulfide
Sb3+ Sb2S3 (orange) colourless
Sn2+ SnS (brown) colourless
III.A
NH4Cl
+
NH3
Fe3+ Fe(OH)3 (brown) yellow reaction with [Fe(CN)6]
4-, SCN
-
Cr3+ Cr(OH)3 (grayish-green) green
Al3+ Al(OH)3 (colourless gelatinous) colourless
III.B
NH3
+
(NH4)2S
Fe2+ FeS (black) greenish-yellow reaction with [Fe(CN)6]
3-
Co2+ CoS (black) pink
Ni2+ NiS (black) green
Zn2+ ZnS (white) colourless
IV
NH3
+
(NH4)2CO3
Ba2+ BaCO3 (white) colourless flame test: green
Sr2+ SrCO3 (white) colourless flame test: crimson (red)
Ca2+ CaCO3 (white) colourless reaction with oxalic acid
Mg2+ MgCO3 (white) after boiling colourless
V –
Li+ – colourless flame test: crimson (red)
Na+ – colourless flame test: yellow
K+ – colourless flame test: violet
NH4+ – colourless Nessler's reagent
7
Classification of anions
To succeed in identification of anion, you have to work systematically. Classification into analytical
groups is based on results of precipitation reactions with two reagents: AgNO3 and Ba(NO3)2. The
strategy is very different from the one used for cations. In case of anion, it is simpler:
Take two test tubes. Into both of them, pour about 1 ml unknown sample. Add about 1 ml of AgNO3
solution in one of them, add about 1 ml of Ba(NO3)2 solution in the other one. You can directly
identify the analytical group according to the results of these two reactions (only for groups IV, V.A
and V.B you have to do one more step – to test the solubility of the precipitate formed).
Group I SO42-
reaction with: Ag+ no reaction
Ba2+
white precipitate
You can confirm the result by the reaction with Pb2+
ions. White precipitate of PbSO4 is formed.
Group II PO43-
CrO42-
OH-
reaction with: Ag+ coloured precipitate
Ba2+
white or yellow precipitate
These anions give deeply coloured, water insoluble silver salts - yellow Ag3PO4, reddish-brown
Ag2CrO4 and dark brown AgOH that immediately decomposes to Ag2O. Precipitates of barium salts
are white or yellow.
Group III SO32-
CO32-
reaction with: Ag+ white precipitate
Ba2+
white precipitate
In this group, white precipitates are formed with both reagents, only the precipitate of Ag2CO3 is dirty
yellow. Precipitates of silver salts are easily soluble in both dilute HNO3 and ammonia.
The result of group reactions is not reliable for distinguishing between these two anions. It is
necessary to conduct one more test. Sulfites have reducing properties, carbonates not. Use iodine
solution for detection of reducing properties. Sulfites reduce the brown iodine solution into colourless
iodide ions. Carbonates do not react.
Procedure: Pour into a test tube about 1 ml of sample to be tested, add dropwise iodine solution (use
the dropper) and watch the reaction.
Group IV NO2- S
2-
reaction with: Ag+ white or black precipitate
Ba2+
no reaction
Sulfides can be easily recognized because of black, very insoluble precipitate of Ag2S. You have to be
more careful in case of nitites. Very similar white precipitates are are formed in case of many other
anions of the groups V. A and V. B. To distinguish among them, note that precipitate of AgNO2 is
soluble in dilute solution of nitric acid (HNO3).
Group V.A Cl- [Fe(CN)6]
3-
reaction with: Ag+ white or brown precipitate (insoluble in HNO3, soluble in ammonia)
Ba2+
no reaction
You should easily identify ferricyanides. Original solution is light yellow, precipitate of silver salt is
brown. Moreover, for definite confirmation, you can use the reaction with Fe2+
ions (formation of
"Prussian blue"). White precipitate of AgCl must be tested for solubility, to distinguish from
precipitates formed from NO2- and anions of group V.B. AgCl is insoluble in dilute HNO3, but soluble
in ammonia.
8
Group V.B Br- I
- SCN
- [Fe(CN)6]
4-
reaction with: Ag+ white or yellow precipitate (insoluble in HNO3, insoluble in ammonia)
Ba2+
no reaction
You can record light yellow colour of AgI. Ferrocyanides ([Fe(CN)6]4-
) are light yellow in solution.
Distinguishing among anions of this group
The easiest way how to distinguish among these anions, is to use solution of FeCl3. Bromides do not
react, iodides are oxidized to iodine (solution in a test tube turns brown), thiocyanates give deep red
solution of [Fe(SCN)]2+
and ferrocyanides form deep blue colour ("Prussian blue").
Group VI NO3- MnO4
-
reaction with: Ag+ no reaction
Ba2+
no reaction
Distinguishing between these two anions is easy accordind to the colour of original solution. Nitrates
(NO3-) are colourless, permanganates (MnO4
-) are deep violet, pink when diluted.
Classification of anions into analytical groups
Group Anion
Colour and solubility of precipitate formed with
Notes
AgNO3 Ba(NO3)2
I SO42-
– white with Pb2+
- white precipitate PbSO4
II
PO43- yellow white
CrO42- reddish-brown yellow with Pb
2+ - yellow precipitate PbCrO4
OH- brown white
III SO3
2- white white reduces brown I2 to colourless I-
CO32- white white
IV NO2
- white soluble
in HNO3
–
S2- black –
V.A Cl
- white insoluble
in HNO3
soluble in NH3
–
[Fe(CN)6]3- brown – with Fe
2+ --> "Prussian blue"
V.B
Br- white
insoluble
in HNO3
insoluble
in NH3
– with Fe3+
- no reaction
I-
light
yellow – with Fe
3+ --> formation of brown I2
SCN- white – with Fe
3+ --> red colour
[Fe(CN)6]4-
white – with Fe3+
-->"Prussian blue"
VI NO3
- – – original solution colourless
MnO4- – – original solution deep violet
It is difficult to distinguish among NO2-, Cl
- a Br
-. These three anions are precipitated only as
insoluble silver salts. In all three cases, the result is white precipitate. To distinguish among them, it is
necessary to divide the precipitate of silver salt into two test tubes and check the solubility of it in
dilute nitric acid (HNO3) and in dilute ammonia (NH3) – see the table.
9
Where to find the solutions needed?
Working place: group reagents for cation classification: HCl
NH4Cl
(NH4)2CO3
group reagents for anion classification: AgNO3
Ba(NO3)2
for solubility tests of precipitates: dilute solution of ammonia (NH3)
dilute solution of nitric acid (HNO3)
solution of iron (III) chloride (FeCl3)
Fume chamber: hydrogensulfide water H2S
ammonium polysulfide (NH4)2Sx
ammonium sulfide (NH4)2S
Place with shared solutions: potassium chromate (K2CrO4)
ammonium thiocyanate (NH4SCN)
potassium ferrocyanide (K4[Fe(CN)6])
potassium ferrocyanide (K3[Fe(CN)6])
oxalic acid
Nessler's reagent
solution of Pb2+
solution of iodine
Do NOT take anything away from the place with reagents! What is there is shared with others!
The correct way: Come with your test tube. Add what you need at this place.
Do NOT take anything out from the fume chamber!
The correct way: Come with your test tube to the fume chamber. Conduct an experiment. Remember
the result. Pour the content of the test tube into the bottle for waste and place empty test tube into a
basket located inside the fume chamber.
A. Demonstration of the procedure for identification of Ni2+
cation and SO42-
anion
The following part of the manual shows the procedure of identification on "known samples" What
will be demonstrated, are the steps resulting in identification of Ni2+
cation and SO42-
anion.
There is a sample marked Ni2+
and a sample marked SO42-
on your working place. Now you have the
opportunity to try all the procedure on these samples.
Demonstration of the procedure for identification of Ni2+
In the procedure of cation identification, it is necessary to keep the order of group reactions tested
(i.e. begin with group I and continue towards "higher" groups, until the reaction is positive). After
identification of the group, you do NOT continue in testing of reactions for "higher" groups! Now, the
only step missing to fulfill the final goal, is to distinguish among cations belonging into the identified
group. As an unknown sample, you will use "Ni2+
".
10
1. Reagent for group I cations: dilute solution of HCl
Pour into a test tube about 1 ml of unknown sample solution (Ni2+
in this case). Add small volume of
dilute solution of HCl.
Describe the changes observed:
Positive reaction would be manifested by formation of precipitates of insoluble chlorides. Negative
result excludes presence of cations of this group. We have to continue and test the group reaction for
group II of cations.
2. Reagent for group II cations: dilute solution of HCl and hydrogensulfide water
Pour into a test tube about 1 ml of unknown sample solution (Ni2+
in this case). Add small volume of
dilute solution of HCl. Go to the fume chamber with this test tube and add hydrogensulfide water.
Describe the changes observed:
Positive reaction would be manifested by formation of coloured precipitates of insoluble sulfides. For
cations of group II.A, precipitates would be insoluble in ammonium polysulfide (NH4)2Sx. For cations
of group II.B, precipitates would be soluble in ammonium polysulfide. Negative result excludes
presence of cations of this group. We have to continue and test the group reaction for group III.A of
cations.
3. Reagent for group III.A cations: solution of NH4Cl and dilute ammonia solution
Pour into a test tube about 1 ml of unknown sample solution (Ni2+
in this case). Add small volume of
NH4Cl solution. For the precipitation, optimal pH is around 9. Ammonia itself would be more
alkaline, we need to add NH4Cl first. Then you can add about 1 ml of dilute ammonia solution.
Describe the changes observed:
Positive reaction would be manifested by formation of precipitates of insoluble hydroxides. Negative
result excludes presence of cations of this group. We have to continue and test the group reaction for
group III.B of cations.
4. Reagent for group III.B cations: solution of (NH4)2S and dilute ammonia solution
Pour into a test tube about 1 ml of unknown sample solution (Ni2+
in this case). Add small volume of
dilute ammonia solution.
Describe the changes observed:
Go to the fume chamber with this test tube and add ammonium sulfide. Record positive reaction –
formation of coloured precipitate of the sulfide.
Chemical equation in ionic form Colour of the precipitate
Conclusion: Our cation belongs to the group III.B. What it could be: Fe2+
, Co2+
, Ni2+
or Zn2+
.
11
One of these can be excluded because of the colour of sulfide precipitate. Which one?
What is helpful now? Colour of analysed sample.
Colour:
According to the colour of the original sample solution, you can easily identify Ni2+
cations. For
confirmation, you can test the reaction of the sample with ammonia. Pour into a test tube about 1 ml
of original unknown sample solution (Ni2+
in this case). Add dilute solution of ammonia (NH3).
Describe the changes observed:
Chemical equation in ionic form
Demonstration of the procedure for identification of SO42-
As an unknown sample, you will use "SO42-
". Similarly to cations, also anions can be classified into
several groups on the basis of the results of the reactions with group reagents. For anions it is
relatively easy, there are only two: AgNO3 and Ba(NO3)2.
Prepare two test tubes. Into both of them, pour about 1 ml unknown sample (SO42-
in this case).
Colour of the sample:
1) reaction with Ag+
Take one of the test tubes prepared and add about 1 ml of AgNO3 solution.
Describe the changes observed:
2) reaction with Ba2+
Take the second test tube prepared and add about 1 ml of Ba(NO3)2 solution.
Describe the changes observed:
Chemical equation in ionic form Colour of the precipitate
It is very easy in this case. Combination of the results of reactions with Ag+ and Ba
2+ clearly points to
the Group I of anions. There is a single anion: SO42-
.
12
B. Analysis of unknown sample
There is a test tube marked with number of your sample in a rack on the working place. The test tube contains unknown
sample to be identified. First, try to identify the cation, and the anion after that. Be responsible, volume of the sample you
have is limited. And it must be enough to perform all the tests needed for definite identification. Do not put anything into
the original test tubes with sample. For individual tests, put a small volume of the sample into new clean test tube!
No new sample available at all!
It may happen that either cation or anion (or both) cause the sample to be coloured.
Sample number: Colour of the sample:
CAUTION: Colour of the solution caused by presence of coloured cations may influence appearance of precipitates
formed in identification of anions and vice versa, e.g. tested reaction for anion identification should give white precipitate,
but this precipitate may look "bluish" because of the presence of blue cation! This should be taken into account!
Describe the systematic procedure leading to definite identification of cation present in the unknown sample.
(all the test performed, including results; chemical equations in ionic form)
Cation Formula Name in words Analytical group
Describe the systematic procedure leading to definite identification of anion present in the unknown sample.
(all the test performed, including results; chemical equations in ionic form)
Anion Formula Name in words Analytical group
CONCLUSION
Analysed unknown sample is a solution of: (give the inorganic compound)
Formula
Name in words