l20 – register set. the 430 register set not exactly a dual ported register set, but a dual drive...
DESCRIPTION
The MSP 430 datapath There are two busses driving data to the ALU There is also a MDB There is also a MAB Registers are 16 bit R0,R1,R2 and R3 are special purpose register The PC, the SP, SR, and constant Any can be used as arguments in instructions and all are connected to the internal busses 9/2/2012 – ECE 3561 Lect 9 Copyright Joanne DeGroat, ECE, OSU3TRANSCRIPT
L20 – Register Set
The 430 Register Set Not exactly a dual ported register set, but a
dual drive register set.
Ref: text Unit 10, 17, 20
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The MSP 430 datapath There are two busses driving data to
the ALU There is also a MDB There is also a MAB Registers are 16 bit R0,R1,R2 and R3 are special purpose
register The PC, the SP, SR, and constant Any can be used as arguments in
instructions and all are connected to the internal busses
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Register line structure – dual ported Diagram
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The register design 430 DP The register cell structure is somewhat less
complicated as there is only one source for a new value.
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Still need the bus driver The bus driver is still needed to drive the bus. They are the same as before, but they are now
16 bits each.
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The bus drivers The code LIBRARY IEEE; USE IEEE.STD_LOGIC_1164.all; ENTITY busdr8 IS PORT (drive : IN std_logic; data : IN std_logic_vector(7 downto 0); intbus : OUT std_logic_vector(7 downto 0)); END busdr8;
ARCHITECTURE one OF busdr8 IS BEGIN PROCESS (drive,data) BEGIN IF (drive='1') THEN intbus <= data; ELSE intbus <= "ZZZZZZZZ"; END IF; END PROCESS; END one;
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Quartis result The synthesis result Resources – tri-state pins
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Next assignment The next assignment is to create a bus driver,
a 4-to-16 demultiplexer, and a 16-bit register cell.
Write the VHDL code for it. You can write a simple test bench to test it
logically it you want, but most likely will wait until the register set is done to do the logic simulation.
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Have a bus driver that works!! LIBRARY IEEE; USE IEEE.STD_LOGIC_1164.all; ENTITY busdr8 IS PORT (drive : IN std_logic; data : IN std_logic_vector(7 downto 0); intbus : OUT std_logic_vector(7 downto 0)); END busdr8;
ARCHITECTURE one OF busdr8 IS BEGIN PROCESS (drive,data) BEGIN IF (drive='1') THEN intbus <= data; ELSE intbus <= "ZZZZZZZZ"; END IF; END PROCESS; END one;
The new approach
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Put together for four of them LIBRARY IEEE; USE IEEE.STD_LOGIC_1164.all; ENTITY m4drv IS PORT (intbus : INOUT std_logic_vector(7 downto 0); data1,data2,data3,data4 : IN std_logic_vector(7 downto 0); dr1,dr2,dr3,dr4 : IN std_logic); END m4drv; ARCHITECTURE one OF m4drv IS COMPONENT busdr8 IS PORT (drive : IN std_logic; data : IN std_logic_vector(7 downto 0); intbus : OUT std_logic_vector(7 downto 0)); END COMPONENT; FOR all : busdr8 USE ENTITY work.busdr8(one); --internal signals BEGIN u1 : busdr8 PORT MAP (dr1,data1,intbus); u2 : busdr8 PORT MAP (dr2,data2,intbus); u3 : busdr8 PORT MAP (dr3,data3,intbus); u4 : busdr8 PORT MAP (dr4,data4,intbus); END one;
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Results for bus driver Now have no fixed 0’s
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Prior results The prior results, although they looked like they
worked, didn’t. ARCHITECTURE one OF mdrv IS COMPONENT busdr IS PORT (drive : IN std_logic; data : IN std_logic; intbus : OUT std_logic); END COMPONENT; FOR all : busdr USE ENTITY work.busdr(one); --internal signals SIGNAL dr1,dr2,dr3 : std_logic; SIGNAL data1,data2,data3 : std_logic; BEGIN u1 : busdr PORT MAP (dr1,data1,intbus); u2 : busdr PORT MAP (dr2,data2,intbus); u3 : busdr PORT MAP (dr3,data3,intbus); END one;
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The 4-to-16 multiplexer Specification
Input – 4 bit binary number Output – 16 lines numbered o0 to o15 operation
is such that only 1 of the outputs is active, indicating the value of the 4-bit binary input.
Input and output type – can be std_logic or std_logic_vector.
Recommend using direct output generation by writing the logic equation for each output line directly from the 4-bit input.
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The 16-bit register cell Write a VHDL ENTITY and
ARCHITECTURE for a 16-bit register unit. Inputs – latch – std_logic din – std_logic_vector Output dout – std_logic-vector
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An 8 bit register This is code for an 8-bit register – 8 F/Fs LIBRARY IEEE; USE IEEE.STD_LOGIC_1164.all; ENTITY reg8 IS PORT (datain : IN std_logic_vector(7 downto 0); load : IN std_logic; dataout : OUT std_logic_vector(7 downto 0)); END reg8;
ARCHITECTURE one OF reg8 IS
BEGIN PROCESS (datain,load) BEGIN IF (load='1' AND load'event) -- IF (rising_edge(load)) THEN dataout <= datain; END IF; END PROCESS; END one;
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Another use of the register cell The register cell will also be used for the
input latching for the inputs to the ALU. The bus driver will also be used for the output
driver of the ALU result onto its bus.
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The objective Dual ported register set
2 data busses Can load or drive either
bus No timing – only control
To insure this unit will synthesize need to do it subcomponent by subcomponent and structurally.
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Reg 0
Reg 1
Reg 2
Reg 15
A BUS
BBUS
AregNo Aload Adrive
BregNo Bload Bdrive
Why dual ported? Traditional processor architecture Accumulator based operation RISC
Reduced Instruction Set Computer Basis – all operations take 1 cycle Can’t achieve with an accumulator architecture Have to fetch 2nd argument
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RISC Requirements Need to fetch both operands at once in one
cycle Dedicated instructions
Load Store Functional
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Reg 0
Reg 1
Reg 2
Reg 15
A BUS BBUS
AregNo Aload
Adrive
BregNo Bload Bdrive
Ainput Binput
ALU
A_ALUload
A_ALUdrive
B_ALUload
B_ALUdrive
oper
C N Z
Cin
Synthesis results Results in just registers Resources – 8 registers on FPGA
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2-to-1 multiplexer 8-bit The code LIBRARY IEEE; USE IEEE.STD_LOGIC_1164.all; ENTITY mux2to1x8 IS PORT (linput,rinput : IN std_logic_vector(7 downto 0); sel : IN std_logic; dataout : OUT std_logic_vector(7 downto 0)); END mux2to1x8;
ARCHITECTURE one OF mux2to1x8 IS BEGIN dataout <= linput when sel='0' ELSE rinput; END one;
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Synthesis Results for mux 8-bit 2-to-1 mulitplexer Resources – 8 combinational LUTs
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A register line Combine the register, the bus drivers (one for ABUS,
one for Bbus), and a 2-to-1 mux for selecting which bus to have for input. LIBRARY IEEE; USE IEEE.STD_LOGIC_1164.all; ENTITY reg_line_str IS PORT (ABUS,BBUS : INOUT std_logic_vector (7 downto 0); aload,bload : IN std_logic; adrive,bdrive : IN std_logic; sel : IN std_logic); END reg_line_str;
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The code ARCHITECTURE one OF reg_line_str IS COMPONENT reg8 IS PORT (datain : IN std_logic_vector(7 downto 0); load : IN std_logic; dataout : OUT std_logic_vector(7 downto 0)); END COMPONENT; FOR all : reg8 USE ENTITY work.reg8(one); COMPONENT busdr8 IS PORT (drive : IN std_logic; data : IN std_logic_vector(7 downto 0); intbus : OUT std_logic_vector(7 downto 0)); END COMPONENT; FOR all : busdr8 USE ENTITY work.busdr8(one); COMPONENT mux2to1x8 IS PORT (linput,rinput : IN std_logic_vector(7 downto
0); sel : IN std_logic; dataout : OUT std_logic_vector(7 downto 0)); END COMPONENT; FOR all : mux2to1x8 USE ENTITY
work.mux2to1x8(one);
-- INTERNAL SIGNALS SIGNAL muxout,regout : std_logic_vector (7 downto 0); SIGNAL muxsel,rload : std_logic; BEGIN m1 : mux2to1x8 PORT MAP
(ABUS,BBUS,muxsel,muxout);
muxsel <= Aload AND sel;
r1 : reg8 PORT MAP (muxout,rload,regout);
rload <= (Aload OR Bload) AND sel;
abd : busdr8 PORT MAP (adrive,regout,ABUS); bbd : busdr8 PORT MAP (bdrive,regout,BBUS); END one;
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The results Synthesis results for a single dual ported
register.
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Decoder to build a register set Need to activate the correct register from a register set. LIBRARY IEEE; USE IEEE.STD_LOGIC_1164.all; ENTITY decoder2to4 IS PORT (addr : IN std_logic_vector(1 downto 0); sel_line : OUT std_logic_vector(3 downto 0)); END decoder2to4;
ARCHITECTURE one OF decoder2to4 IS BEGIN sel_line(0) <= NOT addr(1) AND NOT addr(0); sel_line(1) <= NOT addr(1) AND addr(0); sel_line(2) <= addr(1) AND NOT addr(0); sel_line(3) <= addr(1) AND addr(0); END one;
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Decoder synthesis Synthesis gives Resources – pins and 4 combinaltional LUTs
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A full register set A full register set would have at least 8
registers. Here will start with 2 registers.
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The code Have all the reference unit code. The first time abbreviated ENTITY interface
– only the busses. LIBRARY IEEE; USE IEEE.STD_LOGIC_1164.all; ENTITY reg_set_2 IS PORT (ABUS,BBUS : INOUT std_logic_vector(7 downto 0)); END reg_set_2;
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The 2 register architecture ARCHITECTURE one OF reg_set_2 IS -- this architecture is to confirm the build up of bus units COMPONENT reg_line_str IS PORT (ABUS,BBUS : INOUT std_logic_vector (7 downto 0); aload,bload : IN std_logic; adrive,bdrive : IN std_logic; sel : IN std_logic); END COMPONENT; FOR all : reg_line_str USE ENTITY work.reg_line_str(one); -- now delcare signals for test setup SIGNAL aload1,bload1,adrive1,bdrive1,sel1 : std_logic; SIGNAL aload2,bload2,adrive2,bdrive2,sel2 : std_logic; BEGIN r1 : reg_line_str PORT MAP (ABUS,BBUS,aload1,bload1,adrive1,bdrive1,sel1); r2 : reg_line_str PORT MAP (ABUS,BBUS,aload2,bload2,adrive2,bdrive2,sel2); END one;
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Quartis results After synthesis Report usage only shows pins – you have to
traverse into each unit to get resources. Can see these by running cursor over the unit in the RTL viewer.
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Usage summary by using cursor For each register line
32 buffers (regular) 2 combination ANDs 1 combination OR 8 DFF 16 Tri-state buffers 8 muxes
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Expanding register line unit Pushing down by double clicking in unit box The same unit from before
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Now moving control signals Move the control signals to the ENTITY.
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The last step Adding a decoder to generate the selects This time a 1-to-2 decoder Then a bunch of errors popped up so back up.
Do the implementation one step at a time Add the regno signal to the ENTITY
WORKED FINE Add the decoder COMPONENT – re-synthesize
WORKED FINE Add and instantiation for the decoder
WORKED FINE Finally link the decoder output to the select lines with
concurrent signal assignment statements. It then started generating errors so starting a new approach.
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Build up from drivers The architecture – Diagram not complete
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The units The tri-state bus drivers
4 of them 8-bits each in a hierarchical unit The registers
4 of them as instantiated units Mux2to1x8 – a byte width 2 to 1 multiplexer used to select which
input to have available to load into register, the ABUS or the BBUS
Decoders 2 to 4 – takes the 2 bit register number and generates the correct select line – used for selecting which register to load from the ABUS or BBUS and which register to drive. Note that the system can drive just register. It is capable of two operations each cycle.
Glue logic – generated the load and drive signals.
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Results for the design Resources
Pins – 24 ABUS – 8 BBUS – 8 aload,bload,adrive,bdrive – 4 aregno,bregno – 2 each – 4
Registers – 32 (4 registers 8-bits each) Combinational LUTs – 60
Average fanout – 3.31
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Synthesis results Quartis produced graphic
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Pushing down Decoder register and mux
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Next step The next step is the VHDL simulation of the
register set to be sure its behavior is as desired.
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Lecture summary Have seen how to create a 4 register location
register-set.
The next assignment is to use the code here (which is also on the web page) to generate a 8 location register. Simply build upon this code.
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