Find out the production per day of 24hrs in kg at 85% efficiency when machine gauge = 24, machine diameter = 30″ yarn count = 30Ne; RPM = 30; stitch length = 2.60 mm. Number of feeder = 54

Solution: Here data given, Efficiency = 85%Machine diameter = 30″ M/c gauge = 24 needles per inchYarn count = 30NeM/c rpm = 30Stitch length = 2.60 mmNumber of feeder = 54

Machine circumference = π × dNumber of needle = π × d × GLength of yarn in a course = π × d× G× Stitch lengthLength of yarn used to produce courses in a minute = π × d× G× Stitch length × m/c rpm= (π × 30× 24 × 2.6 × 30) mm/minute= 176342.4 mm/minute= 176.342 m/minute= 176.342 × 1.09 yards /minute= 192.21 yard/minute= pounds/minute= 0.0076 pounds/minute= 0.0076 × 60 × 24 pounds/day= 10.944 pounds/day= kg /day= 4.97 kg /dayNow with 54 feeders, the production will be, (4.97 × 54) = 268.38 kg/day

Production/m/c/day at 85% efficiency = 268.38 × 0.85 kg /day= 228.123 kg /day

Alternate solution:

Here data given, Efficiency = 85% Machine diameter = 30″ M/c gauge = 24 needles per inch Yarn count = 30NeM/c rpm = 30 Stitch length = 2.60 mm

Production in Kg/day =

= = 228.123 kg /day

For Practice…………….

1. Find out the production per hour in pounds at 70% efficiency when machine gauge = 32, machine diameter = 30″ yarn count = 40 Ne; RPM = 24; stitch length = 2.20 mm. [Number of feeder = 90]

2. What will be the production per shift (8 hrs) in kg at 95% efficiency when machine gauge = 24, machine diameter = 30″ yarn count = 30 Ne; RPM = 30; stitch length = 2.45 mm. [Number of feeder = 50]

3. Find out the stitch length of a fabric if that is produced from a machine 5 kg per day at 80% efficiency. And machine gauge = 24, machine diameter = 28″ yarn count = 27Ne; and machine RPM = 26. [Number of feeder = 60]

4. In a knitting factory, Fabric will be produced tomorrow from 28 Ne Yarn. It has 50 machines, all of them have 24 gauge, 30″ diameter, 60 feeders and stitch length should be = 3.00 mm. But 25 machines have an rpm of 24, and other 25 machines have an rpm of 28. What will be the production of that factory tomorrow?