Kites team Structurelecture2

TRUSSES1-Axial loads only 2-Loads applies at

end points only 3 -Elements are

joined by pins only

1-Determine the force in each member of the truss?

0 1

0 2

0 3

2tan tan

3

tan 0 43

X X X

Y Y Y

A Y

Y

X

X Y

F A B P

F A B

M B L Ph

B h

B L

B B

2-Determine the force in each member of the truss and indicate whether the the

members are in tension or compression?

1 1

2 2

2 23

2 3 22 2

0

0

0

0 ( )

0 ( )

0 ( )

X X X

Y Y Y Y Y

A Y Y

F A P A P

PhF A B A B

LPh

M Ph B L BL

Ph PhF F Tension

L LF P F P Tension

F L h LF F F Compression

Lh L

3-Determine the force in each member of the truss and indicate whether the the

members are in tension or compression?

0

600

0

400

400*3 600*4 *6 0

600

200

X

X

Y

Y Y

C Y

Y

Y

F

C N

F

A C

M A

A N

C N

At joint A

At joint C

At joint D

1 2

2

2

1

30

5

4600 0

5

600*5750 ( )

43

750 450 ( )5

X

Y

F F F

F F

F N Compression

F N Tension

4

5

0

600 ( )

0

200 ( )

X

Y

F

F N Compression

F

F N Compression

3 3

0

3450 600 250 ( )

5

XF

F F N Tension

4-Determine the force in each member of the truss and indicate whether the the

members are in tension or compression?

At joint B

At joint C

At joint A

0

500 sin 45 0 707.1 ( )

0

45 0 500 ( )

X

BC BC

Y

BC BA BA

F

N F N F N Compression

F

F Cos N F F N Tension

0

707.1 45 0 500 ( )

0

707.1 45 0 500

X

CA CA

Y

Y Y

F

F Cos N F N Tension

F

C Sin N C N

0

500 0 500

0

500 0 500

X

X X

Y

Y Y

F

N A A N

F

N A A N

*

1 1 3 2

1 1 3 2 2 2

2 22 2

2 2

2 2

1 3

13

0

0

0

0

0

( )

0

X

Y

Y

Y

C Y

Y

F

P F F FCos

LP F F F

h L

F

hD P F

h L

h LF P D

h

M D L Ph F h

P h D LF

h

6-Determine the force in each member of the truss and indicate whether the the

members are in tension or compression?

1

Method of  joints : we willbegainbyanalzingthe

equilibrium of  joint D , and then proceed to

analyze joints C and D

1tan 26.57

2

At joint D

0

600 26.57 0

1341.64 ( )

0

X

DC

DC

Y

F

F Sin

F N Compression

F

/

/

1341.64 26.57 0

1200 ( )

At joint C

0

26.57 0 0

0

1341.64 ( )

At joint E

0

900 45 0

1272.79 ( )

0

1200 1272.79 45 0

DE

DE

X

CE CE

Y

CB

X

EB

EB

Y

EA

EA

Cos F

F N Tension

F

F Cos F

F

F N Compression

F

F Sin

F N Compression

F

Cos F

F

2100 ( )

Note , the equilibrium analysis of joint Acan be used to

determine the components of supports reaction atA 

N Tension