isabel borja nile 2011
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CLIL Project. Professional English for Clinical Microbiology Answer key Unit 2. Isabel Borja NILE 2011. Answer key Lesson 2.1 – Identification of Bacteria. Activity 1.a. Steps in identification:. Activity 1.b. Steps in identification:. Activity 2. - PowerPoint PPT PresentationTRANSCRIPT
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Isabel BorjaNILE 2011
Professional English Professional English forfor
Clinical MicrobiologyClinical Microbiology
Answer key Unit 2Answer key Unit 2
CLIL Project
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Answer keyLesson 2.1 – Identification of
Bacteria
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Activity 1.a
Steps that are always compulsory Steps that depend on purpose
- Preliminary identification- Speciation
- Serological identification- Genetic identification
Steps in identification:
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Activity 1.bSteps in identification:
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Activity 2Preliminary identification: cultural and morphologic characteristics
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Activity 3.a
Text frame:
The name of the test is Haemolysis.We have to use blood agar to observe this feature. When it appears, this means that bacteria lyse red blood cells in blood agar. Macroscopically, colonies may present three appearances:1. A yellow halo around the colonies, which means lysis of RBC is complete and we call this beta-haemolysis.2. A green halo around the colonies, which means lysis of RBC is incomplete and we call this alfa-haemolysis.3. No halo around the colonies, which means there is no lysis of RBC and we call this gamma-haemolysis .It is an important observation for Streptococci.
Haemolysis
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Haemolysis
Identify in the image below the three kind of haemolysis:
Gamma haemolysis
Alfa haemolysis Beta haemolysis
Activity 3.a
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Activity 3.bCatalase test
Text frame:
The name of the test is Catalase.This enzyme breaks down hydrogen peroxide into water and oxygen. We demonstrate this by emulsifying a colony in a drop of hydrogen peroxide. If there is the enzyme, bubbles will appear.Catalase may exist in aerobic bacteria that produce hydrogen peroxide as a result of oxygen metabolism.We may obtain false positives if we use a metal wire loop to pick up the colony or a colony from a blood agar plate.The test is important to differentiate GPC: Staphylococci are positive and Streptococci are negative.
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Catalase test
Questions:
(i) Complete the chemical reaction that involves catalase:
catalase2 H2O2 2 H2O + O2
(ii) How shall we report the catalase test on the image and why.
Catalase positive. Because we may see bubbles produced by gaseous oxygen
released in the chemical reaction.
Activity 3.b
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Activity 3.cOxidase test
Text frame:
The name of the test is Oxidase.This enzyme takes part in aerobic respiration helping oxygen to accept hydrogen and produce water. We demonstrate its presence by mixing a colony with a drop of Kovac´s oxidase reagent. This is used by bacteria as hydrogen acceptor instead of oxygen. The reduced reagent develops a blue-purple colour.Oxidase may exist in aerobic bacteria.We may obtain false positives if we use a metal wire loop to pick up the colony or a colony from media containing some dye.The test is important to differentiate GNB: Pseudomonas are positive and Enterobacteriae are negative.
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Oxidase test
Questions:
Compare both images:
Image 1 - Swab method: oxidase + Image 2 –
Oxidase +
(i) Deduct how the oxidase test in image 2 has been performed and the name of the method.
Kovac´s reagent has been added directly to the plate. We may call this method: plate method.
(ii) Do we need to take any precaution when using this second method?We cannot use the plate method with media that contain dyes
because we may obtain a false positive because of the dye.
Activity 3.c
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Answer keyLesson 2.2 – Biochemical Tests
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Activity 1
ENZYME
SUBSTRAT FINAL PRODUCT Colour A Colour B
INDICATOR
Fundamentals:
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Urease Urea NH3 + CO2
Yellow Red Phenol Red
Lysine DecarboxilaseLysine Cadaverine + CO2
YellYellow Red
Phenol Red
B) Urease Test
A) Lysine Decarboxilase Test
Activity 2.a
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L-Tryptophan Indol + Pyruvic acid + NH3
Activity 2.a
Yellow
Tryptophanase
Violet
Kovac´s Indole reagent
ONPG ONP + Galactose Colourless Yellow
β-galactosidase
C) Indol Production Test
D) ONPG Test
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Activity 2.bTaking biochemical tests to pieces
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Activity 3COMMERCIAL
KITS
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Answer keyLesson 2.3 – Variability of Bacteria
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Activity 1LIMITS FOR VARIABILITY:
1.- When percentages are 98 or 99, that is over 85% and it means that almost all the isolated cultures will give the same result and we may consider the species is positive to the test, but even so, we will find some strain will be negative. These tests have high significance because statistically they have quite sure results.
2.- On the other hand we have some percentages that are not so clear. Percentages around 85% may be considered as positive reactions of the species, but accepting this means that nearly 15% are negative strains. The one that has only 65% will be considered indeterminate for the referred test and that means that the test in this case has no significance.
3.- The most puzzling situation here is that of E. coli for Indol test: 50% means that half the isolated strains will be positive and half negative. The most indeterminate result we could ever have. For percentages under 50% we may apply the same reasoning as before for percentages about 65%.
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Activity 2.a
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Activity 2.b
BIOCHEMICAL TESTS
Nosignificance
Indeterminate
Highsignificance
Positive reaction
Negative reaction
<<< 85 %
< 85 %
≥ 85 %
Making it clear:
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Activity 3Functional matrix:
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Answer keyLesson 2.4 – Susceptibility Tests
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Activity 1
Resistant
Susceptible
Fundamentals of disc diffusion test:
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Activity 2 Kirby-Bauer Method
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Activity 3.aInterpreting diameters:
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Activity 3.bInterpreting diameters:
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Activity 4Using breakpoint tables:
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Activity 5Using breakpoint tables: life test
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