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Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

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Page 1: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Introduction to Motors

Kurt HeinzmannDEKA Research & Development Corp.

Christopher MikusBAE Systems

January 2005

Page 2: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Introduction to Motors

Topics

1. Manufacturers' torque curves and specification sheets

2. How to manage motor temperature rise 3. Gear ratio 4. Review of motors from the Kit of Parts 5. Which motor for which application on a robot?

Page 3: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Note• These slides have been edited since the

presentation on 7 Jan 2005.– Distinction has been made between torque

constant Kt and voltage constant Ke, because, although in an ideal motor,

K = Kt = Ke, Kt and Ke differ significantly in a gearmotor. Some of the motors in the kit are gearmotors.

– New material was added• Advice balloons• Comparison of motors in the Kit• Clarification of gear ratio selection

Page 4: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Steps• Assumptions and approximations• Power• Power loss in the mechanism• Power required at the motor• Power loss in the motor • Basic motor theory• Important motor parameters• Power loss in the motor• Power loss in other electrical components• Gear ratios• Comparison• Batteries

Page 5: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Assumptions and Approximations

• Steady operation– We will not discuss acceleration requirements

• Linear systems– We will represent nonlinear phenomena as linear

• Simple motor analysis– Study only two power loss parameters

• Loss due to electrical resistance• Loss due to friction and damping, combined in one fixed

value

Page 6: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Example: Simplify. Assume fixed free current(combine the effects of friction and damping)

Example motor

y = 0.11x + 0.53

0.0

0.5

1.0

1.5

2.0

2.5

3.0

0 2 4 6 8 10 12 14

Voltage, V

Ifree

, A

Current

Linear (Current)Free current

per data

sheet

Page 7: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Power• Power is a measure of how fast work gets done.• POWER = EFFORT x FLOW

“EFFORT”– force– torque– pressure– voltage– thinking

“FLOW”–travel speed–rotating speed–flow of fluid–flow of electrons–doing

Page 8: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Power Loss in the Mechanism

• Some power from the motor is lost due to friction in the mechanism– Gears, belts, cables– Bearings, guides– Tires, balls, or other deformable items– Damage– Contamination

• Power loss is heat

Cooling a hot motor with snow or cold spray is not a suggested solution to heat generation. Changing the temperature of a motor’s

components too quickly can cause permanent damage. Design your robot well to

prevent motor overheating

Page 9: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Power required at the motor• Power at the motor = power required at the point of use +

power lost in the mechanism• Power loss is heat

Page 10: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Power loss in the motor• Power is lost in the motor due to friction,

damping, and electrical resistance• Power loss is heat

Design your robot’s drive train such that it won’t bind under stress and

add excessive friction to your system. Reduce friction and loading by

properly supporting axles with bearings and pillow

blocks. Reduce side loading by supporting

both ends of axles and drive shafts.

Page 11: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Basic Motor Theory

• Torque is rotating EFFORT, speed is rotating motion (“FLOW”)– Torque = force x radius

• Voltage is electrical EFFORT, current is FLOW of electrons

• Power = EFFORT x FLOW– Mechanical power P(out) = torque x speed– Electrical power P(in) = voltage x current

• Shaft power = power in – power loss– Power loss is sum of electrical loss and mechanical loss

Page 12: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Basic Motor Theory

Important motor parameters

• Stall torque ( stall )

• Stall current ( istall )

• Free speed ( free )

• Free current ( ifree )

Page 13: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Basic Motor TheoryImportant motor parameters

•Torque loss (loss)– We will derive this from free current– Unit: newtons (N)

• Resistance (R)– Ohm’s law

– Unit: ohm ()

• Torque constant ( Kt )–Torque is proportional to current

– Units: (Nm/A)ampere

newton-metres

volts _ radian/second

• Voltage constant ( Ke ) –Motor internal voltage is proportional to speed– Units: V/(rad/s)

Page 14: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Units, ConversionsInternational System (SI) of units

Item

Symbol used here Comment SI unit

Abbrev-iation

Alternate unit Conversion

Force Mechanical effort newton N lb. 4.45 N = 1lb.Distance Mechanical displacement metre m In. 0.0254 m = 1 in.Speed Travelling speed metre/second m/s mph 0.45 m/s = 1 mph

Torque Turning effort newton metre Nm lb-inAngle Angular displacement radian rad degree 2 rad = 360°

Speed Rotating speed radian/second rad/s rpm 0.105 rad/s = 1 rpmTime Don’t have much second s min., h 3600 s = 1 h

Voltage V Electrical effort volt V

Current i Electrical flow ampere APower P Rate of work watt W hp 746 W = 1 hp

Resistance R Cause of power loss as heat ohm Energy Work joule (Nm) J ft-lb

Pressure Fluid effort pascal (N/m2) Pa psi 6900 Pa = 1 psi

Flow Fluid flow (at stated pressure) cubic metre/s m3/s CFM 0.00047 m3/s = 1 CFM

Prefixes: m = milli- = one thousandth (mm, mNm) k = kilo- = one thousand (km, kW)

Page 15: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Why use SI units?

• Easier than U.S. Customary units• Electrical power gets converted to mechanical

power.– If you express electrical power and mechanical power in

watts, you know what’s happening at both ends of the motor.

– Would you like to convert volts-times-amperes to horsepower?

• Advice: Convert to SI units before doing any other calculation.

• Consolation: you can always convert back.

Page 16: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Basic Motor Theory

Page 17: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Direct Current (DC), Permanent-Magnet

(PM), Brush-Commutated Motor

FIRST rules do not allow you to modify

the internal components of a motor. Read the

current year's rules to understand how

you may modify gear boxes if at all.

Page 18: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Basic Motor Theory

Page 19: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Given: stall, istall, free, ifree and V,

Find: Kt, Ke, loss(free), and R.

Important motor parameters

Some motors have an internal circuit breaker, which will stop the motor, or PTC thermistor*,

which will stop or slow the motor by increasing its electrical resistance, if the motor gets too hot. After the motor cools, it runs normally again.

Examples: Window motor

Sliding door motor *PTC thermistor - resistor with a positive temperature coefficient

Page 20: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Find torque constant Kt and voltage constant Ke

Page 21: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Find torque loss loss(free)

Page 22: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Find resistance R

Page 23: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Calculate current, speed, power and efficiency

Page 24: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

From data sheet:

From equation 3a:

From equation 3b:

From equation 4:

From equation 5:

stall = 0.65 Nm

istall = 148 A

free = 2513 rad/s

ifree = 1.5 A

loss(free)

= 0.0044 Nm/A x 1.5 A = 0.0066 NmR = 12 V /148 A = 0.081

Example Motor

Kt = 0.65 Nm / (148.0-1.5) A = 0.0044 Nm/A

Ke = (12 V -1.5 A*0.081 )/ 2513 rad/s = 0.0047 V/(rad/s)

Page 25: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Equations 6 - 11 allow us to calculate the following

performance curves as a function of torque (with constant voltage):

• current (6)• speed (7)• output power (8) • input power (9)• power loss (10)• efficiency (11)

Page 26: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Example Motor - Current

Example motor

0

20

40

60

80

100

120

140

160

0.00 0.10 0.20 0.30 0.40 0.50 0.60 0.70

Torque (Nm)

Spe

ed (r

ad/s

); P

ower

(W)

148 A

Page 27: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Example Motor - Speed

Example motor

0

500

1000

1500

2000

2500

0.00 0.10 0.20 0.30 0.40 0.50 0.60 0.70

Torque (Nm)

Spe

ed (r

ad/s

); P

ower

(W)

Page 28: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Example Motor - Power output

Example motor

0

500

1000

1500

2000

0.00 0.10 0.20 0.30 0.40 0.50 0.60 0.70

Torque (Nm)

Sp

eed

(ra

d/s

); P

ow

er (

W)

407 W

Page 29: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Example Motor - Input Power

Example motor

0

500

1000

1500

2000

0.00 0.10 0.20 0.30 0.40 0.50 0.60 0.70

Torque (Nm)

Spe

ed (r

ad/s

); P

ower

(W)

Output power, W

Input power, W

407 W

1800 W

Page 30: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Example Motor - Power loss

Example motor

1800 W

0

500

1000

1500

2000

0.00 0.10 0.20 0.30 0.40 0.50 0.60 0.70

Torque (Nm)

Spe

ed (r

ad/s

); P

ower

(W)

Output power, W

Power loss, W

Input power, W

407 W

Best operation is to the left of where these lines cross.

Page 31: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Example Motor - Efficiency

Example motor

0

10

20

30

40

50

60

70

80

90

100

0.00 0.10 0.20 0.30 0.40 0.50 0.60 0.70

Torque (Nm)

Spe

ed (r

ad/s

); P

ower

(W)

76%

Page 32: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Example motor

1800 W

0

500

1000

1500

2000

2500

0.00 0.10 0.20 0.30 0.40 0.50 0.60 0.70

Torque (Nm)

Spe

ed (r

ad/s

); P

ower

(W)

0

50

100

150

200

250

Cur

rent

(A);

Eff

icie

ncy

(%)

Output power, WSpeed, rad/sPower loss, WCurrent, AEfficiency

148 A

76%

407 W133 W

Motor performance based on data sheet

Page 33: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Real World: Power loss

14 AWG wire: 3.0 m/ft.12 AWG wire: 1.9 m/ft.10 AWG wire: 1.2 m/ft. 6 AWG wire: 0.5 m/ft. (Copper at 65 °C)

Page 34: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Example motor, stalled for approximately 2 s

0

20

40

60

80

100

120

140

160

-1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

Time, s

Cu

rre

nt,

A;

Te

mp

era

ture

, °C

;

Re

sis

tan

ce

, mO

hm

0

2

4

6

8

10

12

14

16

Vo

lta

ge

, VMotor winding temperature measurement

Current

Motor terminal voltage

Battery voltage

~ Smoke ~

•This circuit was not properly protected (wrong circuit breaker)•Measuring thermocouple was inserted near windings (windings got hotter than thermocouple)•Brushes got hotter than windings

Example motor, stalled for approximately 2 s

Page 35: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

•Motor resistance increased from 67 m to 96 m (43%) in two seconds•Battery resistance = 18 m •Resistance of wires (5 ft. of 14 AWG), connectors, breakers, etc. = 25 m •Total circuit resistance increased to about twice the initial motor resistance

Example motor, stalled for approximately 2 s

0

20

40

60

80

100

120

140

160

-1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

Time, s

Tem

per

atu

re, °

C;

Res

ista

nce

, mO

hm

Motor winding temperature measurement

Total circuit resistance

Motor resistance

Resistance of wires, connectors, breakers, etc.

Battery resistance

~ Smoke ~Example motor, stalled for approximately 2 s

Page 36: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Example motor

0

500

1000

1500

2000

2500

0.00 0.10 0.20 0.30 0.40 0.50 0.60 0.70

Torque, Nm

Sp

ee

d (

rad

/s);

P

ow

er

(W)

0

50

100

150

200

250

Cu

rre

nt

(A);

Eff

icie

nc

y (

%)

Output power, W

Speed, rad/s

Power loss, W

Current, A

Efficiency

68%

278 W126 W

1240 W

95 A

SYSTEM

DATA SHEET

Performance of the system compared with motor performance based on data sheet

Page 37: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

CIM motor (a.k.a. Chiaphua, a.k.a. Atwood)

Be aware that a motor may have other names.

Page 38: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Stall torque stall = 347 oz-in = 2.4 Nm

Free speed free = 5342 rpm = 560 rad/s

Free current ifree = 2.4 A

Stall current istall = 114 A

CIM motor data and curves

Page 39: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

CIM motor

0

200

400

600

800

1000

1200

1400

0 0.5 1 1.5 2 2.5

Torque, Nm

Sp

eed

(ra

d/s

); P

ow

er (

W)

0

20

40

60

80

100

120

140

Cu

rren

t (A

); E

ffic

ien

cy (

%)

Output power, W

Speed, rad/s

Power loss, W

Current, A

Efficiency

CIM motor performance curves

You will need to operate within the limits of the circuit breakers supplied

with the kit! (20 A, 30 A, or 40 A)

Page 40: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Comparison of power available from example motor and CIM motor

0

50

100

150

200

250

300

350

400

450

0 0.5 1 1.5 2 2.5

Torque, Nm

Ou

tpu

t p

ow

er,

W

Example motor

CIM motor

Comparison of power available from example motor and CIM motor

Page 41: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Simple strategy

• Calculate (or read from data sheet) the motor resistance R

• Increase R by 50% - 100%

• Calculate power curve

• Operate at half of new peak power

Page 42: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Comparison of power available from example motor and CIM motor

0

500

1000

1500

2000

2500

0 0.2 0.4 0.6 0.8 1 1.2 1.4

Torque, Nm

Sp

eed

, ra

d/s

0

50

100

150

200

250

300

350

400

450

500

Ou

tpu

t po

wer

, W

Speed, Example motor

Speed, CIM motor

Example motor, R increased by 75%

CIM motor, R increased by 75%

<--- Stay to the left of the peak power point

Performance curves re-calculated with R increased by 75%

Page 43: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

"Gear" ratio: Mechanical power transmission

efficiency is important

• Spur gears: 90% per pair

• Worm and gear: 10%-60%

• Nut on a screw (not ball nut): 10%-60%

• Twist cables: 30%-90%

• Chain: 85%-95%

• Wire rope (cables): up to 98%

• Rack and pinion 50%-80%

Page 44: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Gear ratioExample: out = 1.5 Nm; out = 100 rad/s

Pmotor = Pout / g (12)

Page 45: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Gear ratio exampleOutput power = 1.5 Nm • 100 rad/s = 150 W

Try:Spur gears (assume 90% efficiency per stage)

Power required at motor Pmotor = Pout / g

one stage: Pmotor = 150 W / 0.9 = 167 W

two stages: Pmotor = 150 W / 0.9 /0.9 = 185 W

three stages: Pmotor = 150 W / 0.9 /0.9 /0.9 = 206 W

four stages: Pmotor = 150 W /0.9/0.9/0.9/0.9 = 229 W

Page 46: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Gear ratio exampleEstimate torque by inspection, then calculate an approximate gear ratio to determine how many gear stages are required.

Rule of thumb for spur gears: max. ratio per stage = 5:1

Comparison of power available from example motor and CIM motor

0

500

1000

1500

2000

2500

0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8

Torque, Nm

Sp

eed

, ra

d/s

0

100

200

300

400

500

Ou

tpu

t po

wer

, W

Speed, Example motorSpeed, CIM motorExample motor, R increased by 75%CIM motor, R increased by 75%4 stages3 stages2 stages1 stage

0.4 Nm?

0.1 Nm?

Page 47: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Gear ratioExample motor

Page 48: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Gear ratio - example motorChoosing operating point for example motor

0

500

1000

1500

2000

2500

0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8

Torque, Nm

Sp

ee

d,

rad

/s

0

100

200

300

400

500

Ou

tpu

t p

ow

er,

W

Speed, Example motor

Power, example motor, R increased by 75%

Operating point

Tw o stages: 185 W

1850 rad/s

Check: gear ratio Ng = motor/out = 1850 / 100 = 18.5:1 = 4.3 • 4.3Operating point looks good (comfortably to the left of the peak power point)

Page 49: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Gear ratioCIM motor

Page 50: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Gear ratio - CIM motorChoosing operating point for CIM motor

0

500

1000

1500

2000

2500

0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8

Torque, Nm

Sp

eed

, ra

d/s

0

100

200

300

400

500

Ou

tpu

t p

ow

er,

W

Speed, CIM motor

Power, CIM motor, R increased by 75%

Operating point

One stage: 167 W

0.43

Nm

388 rad/s

Gear ratio Ng = motor/out = 388 / 100 = 3.9:1Moderately heavy load for this motor (near peak power)

Page 51: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Gear ratio example

• Calculate current– Should not exceed breaker current

• Choose motors based on– Power– Gearing required– Possibility of stalling and heating– Weight– All motor tasks

Page 52: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Summary of motors in the 2005 Kit of Parts

Sorted by peak output power

SupplierNumber on motor Motor name Description

Reference Voltage on data sheet

Gear ratio

Stall torque (as from data sheet)

Stall torque (Nm)

Stall current (A)

Free speed (rpm)

Free speed (rad/s)

Free current (A)

Peak power, 10.5 V supply (W)

Fisher-Price

74550-0642 Power Wheels Motor only 12 647 mNm 0.647 148 24000 2513 1.5 312

CIM FR801-001 (Chiaphua, Atwood)

Keyed output shaft, ccw 12 346.9 oz-in 2.45 114 5342 559 2.3 261

Fisher-Price

74550-0642 Power Wheels Motor and gearbox 12 181 77 148 133 13.9 2.5 203

Globe 409A586 2WD/4WD transfer mtr.

Motor only 12 35 oz in 0.247 21.5 9390 983 0.4 46

Taigene 16638628 Sliding (van) door

Worm Gearmotor 10.5

34 Nm cw, 30 Nm ccw 30 44 75 7.9 2.7 44

Globe 409A587 2WD/4WD transfer mtr.

Planetary Gearmotor 12 117 13 21.5 80 8.4 0.58 24

Nippon-Denso

E6DF-14A365-BB

Window Lift Worm Gearmotor 12.6 9.2 Nm 9.2 24.8 92 9.6 2.8 16

Jideco Window Lift Worm Gearmotor 12 8.33 Nm 8.33 21 85 8.9 3 14

Mabuchi RS454SH W/spur gear ccw

Spur pinion on shaft 12 620 g-cm 0.061 5.2 4700 492 0.22 5.7

Page 53: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Comparison of motors in the 2005 Kit of Parts

Speed and torque at peak power with 10.5 V supply

1

10

100

1000

10000

100000

0.01 0.1 1 10 100

Torque, Nm

Sp

ee

d, r

ad

/s

5 W

10 W

20 W

50 W

100 W

200 W

500 W

Mabuchi

Jideco

Nippon

Globe with gearhead

TaigeneFisher-Price with gearbox

Fisher-Price motor alone

CIM

Globe motor alone

Page 54: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Keep batteries charged.Battery voltage and breaker panel voltage with pulse load:

Discharge current: 50 A (shared between two 30 A breakers); duty cycle: 10 s on, 10 s off.Battery nominal capacity @ 20 hour discharge rate: 18 Ah

0

2

4

6

8

10

12

14

16

0 5 10 15

Time, minutes

Dis

char

ged

capa

city

, Ah;

Vol

tage

, V

Battery voltage

Discharged capacity

Panel voltage6.3 Ah

Page 55: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Keep batteries charged.Battery DC resistance during pulsed discharge.

Pulse: 50 A for 10 s, 0 A for 10 sResistance calculated from voltage drop and pulse current, at 1 s intervals throughout the pulse.

0

20

40

60

80

100

120

140

160

0.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0

Discharged capacity, Ah

DC

resi

stan

ce, m

illio

hms

0

2

4

6

8

10

12

14

16

Bat

tery

ope

n ci

rcui

t vol

tage

, V

Battery resistance

Panel plus wire resistance

Battery open-circuit voltage 1 second

2 s

3 s4 s

5 s

10 s

Page 56: Introduction to Motors Kurt Heinzmann DEKA Research & Development Corp. Christopher Mikus BAE Systems January 2005

Conclusion

• Proper planning up front will keep you alive in the heat of the battle.

• Wisely choose the role that a motor will play on your robot. Remember that most of these motors were originally designed for applications other than a competition robot.

• Test the conditions in which a motor is used and

calculate conditions when possible. If you operate below the limits recommended here, your motors are likely to be be trouble-free.

• Good Luck