insa toulouse 1a mecanique du point examen mai 2010 correction

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  • 8/9/2019 INSA Toulouse 1A Mecanique Du Point Examen Mai 2010 Correction

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    WF1tour

    F

    WF1tour

    F0 2

    WF1tour =

    2

    0F .d =

    2

    0 b sin(b.).R.d = [ R. cos(b.) ]20 = R. (1 cos(2.b))

    b = 1, 2, 3... WF1tour

    Fi.e. rot

    F= 0

    )

    b h m M [0, /2]

    = ddt

    t = 0 = 0

    O,ex, ey, ez O, er, e, ek ere

    e e ez t = 0R = N+ F N

    F e

    er e ek

    P = m.g.ez = m.g. (cos.er sin. ek)R = Fe + N.ek

    aM/ a/ac er e ek

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    OM= r.er aM/ =d2

    dt2

    OM= d2rdt2 .er

    a/ =d2 OO

    dt2

    =0

    +

    d/dt

    OM

    =0

    +/

    / OM

    a/ = .ez (.ez r.er)

    a/ = r.2.ez (ez er)

    a/ = r.2.ez (sin( ).e)

    a/ = r.2. sin.ez e sin( ) = sin

    a/ = r.2. sin.e = r.2. sin. (cos.ek + sin.er)

    ac = 2./ vM/ = 2..drdt . (ez er)

    ac = 2..drdt. sin( ).e = 2..

    drdt. sin.e

    F Fe Fc = m.aM/ Fm.a/ m.ac = m.aM/(m.g. cos.er m.g. sin. ek) + (Fe + N.ek) + m.r.2. sin. cos.ek + m.r.2 sin

    2 .er

    2.m..drdt . sin.e

    = m.d

    2rdt2 .er

    er, e, ek

    m.g. cos + m.r.2 sin2 = m.d2rdt2

    F 2.m.drdt .. sin = 0m.g. sin + N+ m.r.2. sin. cos= 0

    r(t)

    r(t)

    =g cos

    2. sin2 [cosh(.t. sin) 1]

    d2rdt2

    2. sin2 .r = g. cos

    r = . sin

    d2rdt2

    2.r = 0

    r(t) = A.e.t + B.e

    .t

    r(t) = Cte

    Cte = g. cos2

    r(t) = A.e.t + B.e

    .t g. cos2

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    t = 0 r = 0 0 = A + B g. cos2

    t = 0 v = 0 0 = AB v(t) = drdt = A..e

    .t B. .e.t

    0=A + B g. cos20= AB

    A = B = g. cos22

    r(t) = g. cos2 .e

    .t+e.t

    2

    g. cos2

    r(t) = g. cos2 . cosh(.t) g. cos2

    r(t) = g. cos2 sin2

    . [cosh( sin.t) 1]

    F

    F = 2.m.drdt.. sin

    F = 2.m. sin. g. cos2 sin2

    . sin. sinh( sin.t)F = 2.m.g. cos sinh( sin.t).e

    er

    N= m.g. sinm.r.2 cos sinN= m.g. sinm.2 cos sin. g. cos2 sin2 . [cosh( sin.t) 1]

    N= m.g. sin2

    sin m.g cos2

    sin[cosh( sin.t) 1]

    N= m.g. sin2 m.g. cos2 . cosh( sin.t)+m.g. cos2

    sin

    N= m.gm.g. cos2 . cosh( sin.t)sin

    N= m.gsin

    .

    1 cos2 . cosh( sin.t)

    cosh(x) = ex+ex2x = 0 [0, /2[ N

    t N = 0N

    N 0

    = /2 N= m.g ek ez

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