inf 5460 electronic noise – estimates and countermeasures
TRANSCRIPT
INF 5460Electronic noise –Estimates and countermeasures
Lecture 10 (Mot 7)
Modelling system noise
• Modelling of noise must include:– Sensors
– Bias and coupling network
– Amplifiers
• We use our standard method: 1. Determine the total noise at output: Eno2. Determine the system gain: Kt 3. Divide Eno with Kt: Eni²=Eno²/Kt²
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A general voltage noise model
• Equivalent noise voltage at the input –general expression:
– A, B, C and D are functions of resistors, capacitors, coils etc and not functions of currents or voltages.
2222222222CSnnSni EDZICEBEAE
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A general current noise model• Equivalent noise
current at the input –general expression:
• Neither J, K, L nor M are functions of voltage or current.
• It is irrelevant whether one calculates the equivalent input noise voltage or current.
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2222
2
22222
C
Cn
S
nnsni
Z
EMIL
Z
EKIJI
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Effect of parallel load resistance 1/2• Input (i.e. without Rp):
• Output (i.e. with Rp).
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2
2
2
S
S
no
so
E
V
E
V
N
S
S
PS
p
so VRR
RV
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2
P
SP
SS
PS
Pno E
RR
RE
RR
RE
2
2
2
2
2
2
2
2
2
2
2
2
p
p
ss
s
p
sp
ss
ps
p
s
ps
p
no
so
ut
ut
ER
RE
V
ERR
RE
RR
R
VRR
R
E
V
N
S
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Effect of parallel load resistance 2/2
When Rs=Rp then Es=Ep and we get that (S/N)ut= ½(Vs²/Es²)= ½(S/N)inn. Rp equally reduces Vs and Es but
contribute in addition with its own noise. When Rs≫Rp
decreases (S/N)ut towards zero, while when Rs≪Rp will (S/N)ut increase towards (S/N)inn which is the best that can be achieved.
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2
2
2
2
2
2
2
2
2
2
2
p
p
ss
s
p
sp
ss
ps
p
s
ps
p
no
so
ut
ut
ER
RE
V
ERR
RE
RR
R
VRR
R
E
V
N
S
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Calculation with amplifier noise
1. Noise at output
2. System gain
3. Equivalent input noise
We compare with our well-known equation:
• Terms in front of En: If Rp≪Rs
we have that En will contribute a lot. If Rs=Rp the contribution from En will be equal to 4En². If Rp ≫ Rs contributes En with only En²
• Inp²RS² is a new term. This is the thermal noise in Rp.
22222
2
22 |||| SpnpSpnn
pS
p
Sno RRIRRIERR
REE
pS
p
tRR
RK
2222
2
2
2
22
Snpnn
p
pS
S
t
noni RIIE
R
RRE
K
EE
2222
2
22
Snns
t
noni RIEE
K
EE
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Increased Rp & Vb1)
Rp must be made as high as possible. If a certain voltage is required over RS or a certain current through RS we may change the bias voltage accordingly.
Example: RS=1k, Rp=1.5k and VB=2.5V. If we change to new values Rp=199k and VB=200V the voltage over the sensor and the current through the sensor remains the same but the noise is significantly reduced.
2)
Alternatively, maybe it is possible to use a coil instead of Rp?
222
2
22 1 SSnS
nni ERILj
REE
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1k sensor requiring 1V and 1mA
Green: 1.5k, 2.5V
Blue: 199k, 200V1.5k, 2.5V 49k, 50V
AC gain -4.4dB -0.2dB
Noise gain 0.60 0.98
Noise out 3.2nV/Hz 4.0nV/Hz
Noise eq. input 5.3nV/Hz 4.1nV/Hz
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Bias impedance: R and L• 1MHz signal frequency
• Load R or L
• Simulations:
– Transient
– AC
– Noise
• (HP-filter on output to get same DC)
At 1MHz R 4k L 200µH
Gain 0.80 0.78
V(onoise) 3.6nV/Hz 3.2nV/Hz
V(inoise) 4.6nV/Hz 4.1nV/Hz
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Effect of shunt capacitances
Here we have replaced the resistance Rp with a capacitor Cp
1)
2)
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1
1
1
1
1
222
222
222
2
2
22
2
22
pS
Snn
ps
S
p
S
p
S
nn
p
S
p
Sno
CR
RIE
CRE
CjR
CjR
IE
CjR
CjEE
1
1
1
1
222
2
pS
p
S
p
tCR
CjR
CjK
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3)
We compare with our well-known expression:
En² is multiplied by (RS²Cp²²+1). Note ! RS²Cp²² will often be substantially less than 1.
Only the En² contribution increases. NB! Cp is no noise source! Cp is not the input capacitance of the amplifier. This is included in En, In and Kt.
2222222
2
22 1 SnpSnS
t
noni RICREE
K
EE
2222
2
22
Snns
t
noni RIEE
K
EE
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Noise in a resonant circuit1) Noise at output
Calculation of parts:
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2
22 ||||||
||
pp
pP
pP
CLSnn
CLS
CL
Sno XXRIEXXR
XXEE
Sppsp
p
p
pp
S
p
pS
CLS
CL
RCLRLj
Lj
Lj
LCR
LjCjR
XXR
XX
pp
pp
22
11
1
11
1
||
||
ppSSp
pS
p
pS
CLSLCRRLj
LRj
CjLjR
XXRpp 211
1||||
2
22
2
22
11
1
11
1
p
pS
nn
p
pS
Sno
CjLjR
IE
LjCjR
EE
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2) Signal gain
3) Equivalent input noise
•
The In-coefficient is independent of frequency
The En-coefficient will have a weight larger than 1 except at resonance. At the resonance (²CpLp=1) is the reactance element 0 and the coefficient equal to 1. We will then end up with our well-known expression (without Cpand Lp).
Lp and Cp does not contribute itself but affects others.
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2
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1
||
||
p
pS
CLS
CL
t
jLjCR
XXR
XXK
pp
pp
2
2
22
22
2
22
11
11
11
p
pS
p
pS
n
p
ppS
nS
t
noni
CjLjR
LjCjR
ILj
LCREE
K
EE
22
22
221
1 Sn
p
ppS
nS RILj
LCREE
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The gain (top figure) is largest at resonance frequency. That is also the case for the noise output (in the middle). However, the equivalent noise at the input (bottom) is lowest at the resonance. This means that the signal is amplified more than the increase in noise at resonance.
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Summary• Resistance in parallel:
• Capacitor in parallel:
• Coil in parallel:
• Xs in the series and Xp in parallel:
Xs and Xp are combinations of capacitances and coils in series and/or parallel (No resistances!)
• XLC is a coil and a capacitor in parallel:
2222
2
22 1 Snpnn
P
SSni RIIE
R
REE
22222222 1 SnnpSSni RIECREE
222
22
222 1 Snn
SSni RIE
L
REE
222
2
22 1 nSSn
p
SSSni IXRE
X
XREE
LC
Lj
CjLj
CjLj
X LC 211
1
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When we can not reduce the noise…• Large SNR and DR is achieved either by
reducing the noise or increasing the signal. Is it any potential for increasing the maximum signal range?
• Make the signal range approach the supply voltage range– The signal range in traditional amplifiers is
only a limited region of the voltage supply region a)
– Rail-to-rail amplifiers approach the full supply voltage range. However these amplifiers are much more complex. b)
• Use differential amplifiers– Differential amplifiers has twice the signal
range (and better CMRR) but the component noise increases (from 2 and upwards).
Rail-to-rail diff in/out amplifier
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Rail-to-rail test bench
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Rail-to-rail amplifier
• Vout_cm=1.65, Vin_cm=0-3.3V
• Vin_cm=1.65, Vout_cm=0-3.3V
• AC (Vout_cm=Vin_cm=1.65V)
• Noise (Vout_cm=Vin_cm=1.65V)
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NCM-eye• Goal: Measure resistance in
rock
• Two ASICs designed for 200°C operation temperature
• Measurement setup:– 100-200V AC is set up over the
rock region to be inspected
– Sensor front ends width very high input impedance (10-100G) measure the local voltage level
– Voltage differences between neighbour pairs are found
– Resulting values are converted into a digital format and feed into common buses
Very high input impedance preamp• GBW=10MHz
• Zin = 1-100G
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