ii design of dc machines
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Unit IIDesign of DC Machines
ByDr. R.KarthigaivelAssociate ProfessorDepartment of Electrical and ElectronicsEngineeringPSNA College of Engineering and Technology, DindigulTamil Nadu
6040_b
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C:\Users\god\Desktop\DEM\Karthi11\6.jpgParts of DC machine
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Output Equation of DC Machines
OutputEquationgivesarelationbetweenthemachineratinganditsarmaturedimensionsintermsofarmaturediameter,corelength,speed,specificelectricandspecificmagneticloadings.
Let
Pa=powerdevelopedbyarmatureinkW
Pa=generatedemf×armaturecurrent×10-3
Pa=E×Ia×10-3(1)
Generatedemfinadcmachine,
.EaZnpE.
.(2)
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.flux per pole in Wb
Z total number of armature conductors
n motor speed in rps(n=N/60)
N speed in rpm
a number of parallel paths
Number of parallel path, a = 2(for wave winding)
a = no. of poles=p(for lap winding)
Substitute (2) in (1)
310....aaIaZnpP.Let current in each conductor
aIIaZ.(3)
310)()(.....nZIpPZa.(4)
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DLpBav...Specific magnetic loading,
DLBpav...(5)
Specific electric loading,
DZIacZ..DacZIZ..(6)
WhereD armature diameter
L armature core length
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Substitute (6), (5) in (4)310.....nDacDLBPava..32210....nLDacBav.kWinnLDCPoa..2Where
Output co-efficient,
3210...acBCavo.(7)
(8)
for motor
.PPa.PPa.for generator
Power developed by the armature{Pa= i/p -losses}
{Pa= o/p + losses}
{P = o/p}
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Let
Kfform factor
Bavaverage gap density
Bg(or)Bmmaximum gap density
Form factor ,
.
.
...bBBKgavfWhere
bpole arc
pD.
..Pole pitch
.Pole pitch
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Main Dimensions
a.Armature diameter (D)b.Armature core length (L)(i)Specific magnetic loading is related with D and L(ii)Specific electric loading is related with D(iii)The output coefficient depends on the value Bavand ac
The choice of specific magnetic loading depends on :
a. Teeth flux density
b. Frequency of flux reversal
c. size of the machine
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Teethfluxdensity
Fluxdensityintheairgapishigh,itmayincreaseahighfluxdensityinthearmatureteethbeyondthelimit.Thevalueoffluxdensityintheteethataminimumsectionshouldnotexceed2.2Wb/m2.
Thehighvalueoffluxdensityintheteeth
(i)Causesmoreironlosses
(ii)Requireshighermmfforpassingthefluxthroughtheteeth.Itcanleadtoincreasedfieldcopperlossesandhighercostofcopper.
Frequencyoffluxreversal
f=(np/2)
Higherfrequencyoffluxreversalresultsinincreasedironlossesinarmaturecoreandteeth.Thereforeweshoulduseasmallvalueoffluxdensityintheairgapfoeamachinehavinghigherfrequency.
Sizeofmachine
Ifsizeofthemachineincreases,thewidthofthetoothalsoincreasesduetoanincreaseindiameterofthearmature.Butthiswillnotcausethesaturationofmachinewhenthereisincreasedvalueofgapfluxdensity.
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Choice of specific electric loading (or)
Ampere conductors per metre (ac)
TemperatureriseSpeedVoltageSizeofmachineArmaturereactioncommutation
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11Theventilationofthemachineisbetterwhenamachinerotatesathighspeedandgraterlossescanbedissipated.Forahighspeedmachine,itispossibletouseahighvalueofac.
.Heatdissipatedinthemachineincreaseswhenchoosingahighvalueofacduetouseofmorearmatureconductors..Ahighvalueofaccanbeusedformachinesusinginsulatingmaterialswhichcanwithstandatemperaturerise..Thechoiceofvalueforacdependsupontypeofenclosureandcoolingtechniquesemployedinthemachine.
Temperature rise
SpeedVoltage
.Thechoiceofacvaluedependsonnumberofarmatureconductorswhichinturnsdependsonspaceavailabilityfortheprovisionofconductors..Inhighvoltagemachines,thethicknessofinsulationshouldbelarge,thereforethereislessspaceforconductorsresultsinlowvalueofac
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Size of machine
.Inlargesizemachinethereismorespaceforaccommodatingtheconductors.Soitcanbepossibletousehigherac.
Armature Reaction
.Forhigheracarmaturereactionwillbesevere.
.Inordertopreventthis,thefieldshouldbemadestronger.Themmfrequiredforthefieldhavetobeincreasedtopreventdecreaseinflux..Thisincreasethecostofconductorsused
Commutation
aca(Z/D).Forhighvalueofac,eitherincreasetheconductorsordecreasethearmaturediameter..acareactancevoltageincoilainductanceinthecoil
.Highvalueofacresultinincreasedreactancevoltagewhichdelaythecommutationcondition.(acliesbetween15000to50000)
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13SeparationofDandLinDCmachines
ThefactorswhichinfluencetherelativevalueofDandLindcmachinesarei.Machineproportionsii.Peripheralspeediii.Momentofinertiaiv.Voltagebetweenadjacentcommutatorsegments
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14Machineproportions
.Thedimensionsofthemachinearedecidedbythepolecriterion
.Thecrosssectionofpolemayberectangularofsquare
..
.Inasquaresection,widthofthepolebodyisequaltolengthofthemachine.But,thewidthofthepolebody(b)isabout0.45to0.55timesofpolepitch.L=b=(0.45to0.55).Inrectangularpoleconstruction,thelengthofthemachineisequaltotwicethewidthofpolebodyL=bto2b.Forsquarepolefaceconstruction,L=b(or)L/b=1
.
.)1.145.0(to.C:\Users\god\Desktop\DEM\Karthi11\7.jpg
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Peripheralspeed
Peripheralspeedofarmature,smnDVa/..Peripheralspeedofarmatureislimitingfactortothevalueofdiameter.Therefore,thePeripheralspeedofarmatureshouldnotexceedabout30m/sec.
Moment of inertia.Machinesusedforcontrolsystems,asmallmomentofinertiaisdesirableanditcanbeobtainedbyselectinglowvalueofdiameterforarmatureconstruction..Ifmachinesaredesignedforimpactloadapplications,thenselectionofarmaturediametershouldbelarge.
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Voltage between adjacent commutator segmentsThemaximumcorelengthofmachineisdecidedbymaximumallowableVoltagebetweenadjacentcommutatorsegments.
Maximum Voltage between adjacent commutator segments,cagmcmTLVBE2.Where
Bgm-maximum gap density under load condition
L -Core length of machine
Va-peripheral speed in m/sec
Tc-number of turns/coil
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A5kW,4pole,250V,1500rpmshuntgeneratorisdesignedtohaveasquarepoleface.Theloadingsare:averagefluxdensityinthegap=0.42Wb/m2andampereconductorspermetre=15000.findthemaindimensionsofthemachine.Assumefullloadefficiency=0.87andratioofpolearctopolepitch=0.66.
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20C:\Users\god\Desktop\DEM\Karthi11\9.jpgL = 0.1 mAns.D=0.193mL=0.1m
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21Adesignisrequiredfora50kW,4pole,600rpm,dcshuntgenerator,thefullloadterminalvoltagebeing220V.Ifthemaximumgapdensityis0.83Wb/m2andthearmatureconductorspermetreare30000.calculatesuitabledimensionsofarmaturecoretogiveasquarepoleface.
Assumethatthefullloadarmaturevoltagedropis3%oftheratedterminalvoltage,andthatthefieldcurrentis1%ofratedfullloadcurrent.Ratioofpolearctopolepitchis0.67.
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Selection of Number of PolesFactors which affect the Selection of suitable Number of Poles are(i)Frequency(ii)Weightofironpart(iii)Weightofcopper(iv)Lengthofcommutator(v)Labourcharges(vi)Flashoverbetweenbrushes(vii)Distortionoffieldform
Frequency of flux reversal apoles airon losses
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27C:\Users\god\Desktop\DEM\Karthi11\13.jpgWeightofironpart
.Ifthenumberofpolesisdoubled,thenthefluxintheyokeishalved.
.Tokeepyokefluxdensitysame,theweightofironinyokecanreducedinproportiontoincreaseinnumberofpoles..Increasingtheno.ofpolesincreasesthefrequencyoffluxreversalinthearmaturecorewhichresultsincreasecorelosses.
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28Weight of copper
The weight of copper can be divided intoi.Armature copperii.Field copperDue to increase in no. of poles decreases armature and field copper.
Length of commutator
Whenno.ofpolesincreasesitresultsinreductioninthelengthofcommutator.
2 pole m/c4 pole m/c
Current per parallel path
Ia/2
Ia/4
Current per brush arm
Ia
2Ia/4=(Ia/2)
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29Labour Charges
Thelabourchargeswillincreaseastheno.ofpolesincreasesduetomorearmaturecoilstowind,insulateandsoldertocommutatoranddesignoffieldwindingsFlash over between brushesDistortion of field formpZIATza2..Forasmallerno.poles,ATaincreasesresultsindistortionoffieldformandreductioninfluxunderloadconditions..Toavoidthedistortionoffieldform,itisnecessarytoprovidecompensatingwindingforamachineshavingsmallno.ofpoles..Itcomplicatestheconstructionandincreasesthecostofmachine.
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Advantages of having more number of polesIncreasing the number of poles, will reduces the following.Weight of iron parts.Weight of copper.Length of commutator.Distortion of field form
Disadvantages of increasing number of poles.Frequency of flux reversal is more.High labour charge.Increase the flash over between brush arms
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Guideline for selecting number of poles
i.Frequency of flux reversalFrequency lies between 25 to 50 HzLower frequency is preferred for large machinesii.Thevalueofcurrentperparallelpathshouldbelimitedto200Aandcurrentperbrusharmshouldbelimited400A.
2npf.Wave windingLap winding
Current per parallel path
Ia/2
Ia/p
Current per brush arm
Ia
2Ia/p
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iii. The value of armature mmf per pole should not be excessivelylarge.Armature mmf/pole2.acATa.pDacATa2..Output (kW)
ATa(amp turns/m)
Upto100
5000 or less
100-500
5000 to 7500
500 -1500
7500 to 10000
Over 1500
upto12500
iv.Ifmorethanonechoiceofpolessatisfiestheabovethreeconditions,thenselectlargeno.ofpoles.Thisresultsinreductioninironandcopper.
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Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul33Findthesuitablediameter,corelengthandnumberofpolesofa400kW,550V,900rpmdcgeneratorhaving92%efficiency.Assumeanaveragefluxdensityintheairgapofabout0.6Wb/m2andampereconductorspermetretobe35000.C:\Users\god\Desktop\DEM\Karthi11\14.jpgC:\Users\god\Desktop\DEM\Karthi11\14.jpg
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Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul38Findthemaindimensions,numberofpolesandlengthofairgapofa600kW,500V,900rpmgenerator.Assumeaveragegapdensityis0.6Wb/m2andampereconductorspermetre35000.Theratioofpolearctopolepitchis0.75andtheefficiencyis85%.
The following are the design constraints : peripheral speed 40 m/s,frequency of flux reversal 50 Hz, current per brush arm400A, armature mmfper pole 7800 AT. The mmfrequired for airgap is 60 percent of armature mmfand gap contraction factor 1.15.
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Magnetic circuit calculationsMagnetic circuit calculation involves two types of problemsi.Itisrequiredtodeterminethemmfneededtoestablishadesiredfluxatagivenpointinamagneticcircuit.ii.Thefluxorfluxdensityisunknownandisrequiredtobedeterminedforagivengeometryofthemagneticcircuitandspecifiedmmf.Themagneticcircuitissplitupintoconvenientpartswhichmaybeconnectedinseriesparallel.Thecalculationofmmfinthemagneticpartsaresimplewhereasincaseofairgapandtaperedteeth,thecalculationsarecomplex.
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Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul47MMF calculation of air gapLet
lglength of air gap
ysslot pitch
Wsslot width
Wttooth width
L Length of core
ndnumber of radial ventilating ducts
Wdwidth of each duct
H = atg= mmf per unit length
Atg = atg×lgtotal mmf required in the air gap
Bgor Bavaverage gap flux density or specific magnetic loading
Wb/m2
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Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul48Reluctance of air gap with smooth armature surfaceC:\Users\god\Desktop\DEM\Karthi11\1.jpgThe reluctance of air gap for one slot pitchsgggLylAlS00....70104.....Permeability of free spaceA = Lys= area of cross section of air gap over one slot pitch
AlAlSr...0..
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49Reluctance of air gap for slotted armatureThe area of cross section of the air gap through which the flux passes isLys (or) LWt.
Effective or contracted slot pitch
tsssWWyy....)(000ssgsgggWyLlyLlAlS........C:\Users\god\Desktop\DEM\Karthi11\2.jpg
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Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul50ReluctanceofairgapwitheffectsofbothslotsandventilatingductsC:\Users\god\Desktop\DEM\Karthi11\5.jpgEffective or concentrated axial lengthddcdwnKLL...KcdCarter co-efficient for ductswhich depends on the ratio ofgdlwlengthgapwidthduct.sddcdgsgggywnKLlyLlAlS)(000........
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51gap contraction factor for ducts is defined as)(tanRetanRecasesmoothductswithoutgapairofcelucductswithgapairofcelucKgd.LLwnKLLKLylwnKLlddcdgdsgddcdg......00/)(/..Nowconsidertheeffectofbothslotandventilatingducts,reluctanceofthiscasegivenbysgggyLlAlS.....00..
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52Picture1Clarifications ?
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Picture1Thank you
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Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul54Design of Armature (Armature winding)
i.Choice of armature windingii.Number of armature conductorsiii.Number of armature coilsiv.Number of armature slots
Choice of armature winding(a)Labwinding.No.ofparallelpathisequaltoNo.ofpoles(a=p).Thecurrentineachparallelpathsis(1/p)timesofratedarmaturecurrent(b)Wavewinding.No.ofparallelpathsisequalto2..Theconductorshavetocarryhalfoftheratedarmaturecurrent
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Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul55Number of armature conductors
Generated emf (or) back emf,Total no.of armature conductors,aZnpE..npEaZ..E= V+Iarm(for generator)E= V-Iarm(for motor)rm-internal resistanceIarm-internal voltage drop
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Number of armature coilsThemaximumvalueofvoltagebetweenadjacentsegmentsatloadshouldnotexceed30V.Singleturnhastwoconductors,sinceNo.ofcoilsforsingleturnwinding=(Z/2)
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