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    Unit IIDesign of DC Machines

    ByDr. R.KarthigaivelAssociate ProfessorDepartment of Electrical and ElectronicsEngineeringPSNA College of Engineering and Technology, DindigulTamil Nadu

    6040_b

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    C:\Users\god\Desktop\DEM\Karthi11\6.jpgParts of DC machine

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul

    Output Equation of DC Machines

    OutputEquationgivesarelationbetweenthemachineratinganditsarmaturedimensionsintermsofarmaturediameter,corelength,speed,specificelectricandspecificmagneticloadings.

    Let

    Pa=powerdevelopedbyarmatureinkW

    Pa=generatedemf×armaturecurrent×10-3

    Pa=E×Ia×10-3(1)

    Generatedemfinadcmachine,

    .EaZnpE.

    .(2)

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    .flux per pole in Wb

    Z total number of armature conductors

    n motor speed in rps(n=N/60)

    N speed in rpm

    a number of parallel paths

    Number of parallel path, a = 2(for wave winding)

    a = no. of poles=p(for lap winding)

    Substitute (2) in (1)

    310....aaIaZnpP.Let current in each conductor

    aIIaZ.(3)

    310)()(.....nZIpPZa.(4)

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    DLpBav...Specific magnetic loading,

    DLBpav...(5)

    Specific electric loading,

    DZIacZ..DacZIZ..(6)

    WhereD armature diameter

    L armature core length

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    Substitute (6), (5) in (4)310.....nDacDLBPava..32210....nLDacBav.kWinnLDCPoa..2Where

    Output co-efficient,

    3210...acBCavo.(7)

    (8)

    for motor

    .PPa.PPa.for generator

    Power developed by the armature{Pa= i/p -losses}

    {Pa= o/p + losses}

    {P = o/p}

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    Let

    Kfform factor

    Bavaverage gap density

    Bg(or)Bmmaximum gap density

    Form factor ,

    .

    .

    ...bBBKgavfWhere

    bpole arc

    pD.

    ..Pole pitch

    .Pole pitch

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    Main Dimensions

    a.Armature diameter (D)b.Armature core length (L)(i)Specific magnetic loading is related with D and L(ii)Specific electric loading is related with D(iii)The output coefficient depends on the value Bavand ac

    The choice of specific magnetic loading depends on :

    a. Teeth flux density

    b. Frequency of flux reversal

    c. size of the machine

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    Teethfluxdensity

    Fluxdensityintheairgapishigh,itmayincreaseahighfluxdensityinthearmatureteethbeyondthelimit.Thevalueoffluxdensityintheteethataminimumsectionshouldnotexceed2.2Wb/m2.

    Thehighvalueoffluxdensityintheteeth

    (i)Causesmoreironlosses

    (ii)Requireshighermmfforpassingthefluxthroughtheteeth.Itcanleadtoincreasedfieldcopperlossesandhighercostofcopper.

    Frequencyoffluxreversal

    f=(np/2)

    Higherfrequencyoffluxreversalresultsinincreasedironlossesinarmaturecoreandteeth.Thereforeweshoulduseasmallvalueoffluxdensityintheairgapfoeamachinehavinghigherfrequency.

    Sizeofmachine

    Ifsizeofthemachineincreases,thewidthofthetoothalsoincreasesduetoanincreaseindiameterofthearmature.Butthiswillnotcausethesaturationofmachinewhenthereisincreasedvalueofgapfluxdensity.

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    Choice of specific electric loading (or)

    Ampere conductors per metre (ac)

    TemperatureriseSpeedVoltageSizeofmachineArmaturereactioncommutation

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    11Theventilationofthemachineisbetterwhenamachinerotatesathighspeedandgraterlossescanbedissipated.Forahighspeedmachine,itispossibletouseahighvalueofac.

    .Heatdissipatedinthemachineincreaseswhenchoosingahighvalueofacduetouseofmorearmatureconductors..Ahighvalueofaccanbeusedformachinesusinginsulatingmaterialswhichcanwithstandatemperaturerise..Thechoiceofvalueforacdependsupontypeofenclosureandcoolingtechniquesemployedinthemachine.

    Temperature rise

    SpeedVoltage

    .Thechoiceofacvaluedependsonnumberofarmatureconductorswhichinturnsdependsonspaceavailabilityfortheprovisionofconductors..Inhighvoltagemachines,thethicknessofinsulationshouldbelarge,thereforethereislessspaceforconductorsresultsinlowvalueofac

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    Size of machine

    .Inlargesizemachinethereismorespaceforaccommodatingtheconductors.Soitcanbepossibletousehigherac.

    Armature Reaction

    .Forhigheracarmaturereactionwillbesevere.

    .Inordertopreventthis,thefieldshouldbemadestronger.Themmfrequiredforthefieldhavetobeincreasedtopreventdecreaseinflux..Thisincreasethecostofconductorsused

    Commutation

    aca(Z/D).Forhighvalueofac,eitherincreasetheconductorsordecreasethearmaturediameter..acareactancevoltageincoilainductanceinthecoil

    .Highvalueofacresultinincreasedreactancevoltagewhichdelaythecommutationcondition.(acliesbetween15000to50000)

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    13SeparationofDandLinDCmachines

    ThefactorswhichinfluencetherelativevalueofDandLindcmachinesarei.Machineproportionsii.Peripheralspeediii.Momentofinertiaiv.Voltagebetweenadjacentcommutatorsegments

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    14Machineproportions

    .Thedimensionsofthemachinearedecidedbythepolecriterion

    .Thecrosssectionofpolemayberectangularofsquare

    ..

    .Inasquaresection,widthofthepolebodyisequaltolengthofthemachine.But,thewidthofthepolebody(b)isabout0.45to0.55timesofpolepitch.L=b=(0.45to0.55).Inrectangularpoleconstruction,thelengthofthemachineisequaltotwicethewidthofpolebodyL=bto2b.Forsquarepolefaceconstruction,L=b(or)L/b=1

    .

    .)1.145.0(to.C:\Users\god\Desktop\DEM\Karthi11\7.jpg

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    Peripheralspeed

    Peripheralspeedofarmature,smnDVa/..Peripheralspeedofarmatureislimitingfactortothevalueofdiameter.Therefore,thePeripheralspeedofarmatureshouldnotexceedabout30m/sec.

    Moment of inertia.Machinesusedforcontrolsystems,asmallmomentofinertiaisdesirableanditcanbeobtainedbyselectinglowvalueofdiameterforarmatureconstruction..Ifmachinesaredesignedforimpactloadapplications,thenselectionofarmaturediametershouldbelarge.

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    Voltage between adjacent commutator segmentsThemaximumcorelengthofmachineisdecidedbymaximumallowableVoltagebetweenadjacentcommutatorsegments.

    Maximum Voltage between adjacent commutator segments,cagmcmTLVBE2.Where

    Bgm-maximum gap density under load condition

    L -Core length of machine

    Va-peripheral speed in m/sec

    Tc-number of turns/coil

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    A5kW,4pole,250V,1500rpmshuntgeneratorisdesignedtohaveasquarepoleface.Theloadingsare:averagefluxdensityinthegap=0.42Wb/m2andampereconductorspermetre=15000.findthemaindimensionsofthemachine.Assumefullloadefficiency=0.87andratioofpolearctopolepitch=0.66.

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    C:\Users\god\Desktop\DEM\Karthi11\8.jpgC:\Users\god\Desktop\DEM\Karthi11\8.jpg

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    19C:\Users\god\Desktop\DEM\Karthi11\8.jpgC:\Users\god\Desktop\DEM\Karthi11\8.jpgC:\Users\god\Desktop\DEM\Karthi11\9.jpgC:\Users\god\Desktop\DEM\Karthi11\8.jpg

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    20C:\Users\god\Desktop\DEM\Karthi11\9.jpgL = 0.1 mAns.D=0.193mL=0.1m

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    21Adesignisrequiredfora50kW,4pole,600rpm,dcshuntgenerator,thefullloadterminalvoltagebeing220V.Ifthemaximumgapdensityis0.83Wb/m2andthearmatureconductorspermetreare30000.calculatesuitabledimensionsofarmaturecoretogiveasquarepoleface.

    Assumethatthefullloadarmaturevoltagedropis3%oftheratedterminalvoltage,andthatthefieldcurrentis1%ofratedfullloadcurrent.Ratioofpolearctopolepitchis0.67.

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    C:\Users\god\Desktop\DEM\Karthi11\10.jpgC:\Users\god\Desktop\DEM\Karthi11\10.jpg

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    C:\Users\god\Desktop\DEM\Karthi11\10.jpgC:\Users\god\Desktop\DEM\Karthi11\11.jpg

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    C:\Users\god\Desktop\DEM\Karthi11\11.jpgC:\Users\god\Desktop\DEM\Karthi11\11.jpg

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    C:\Users\god\Desktop\DEM\Karthi11\11.jpgC:\Users\god\Desktop\DEM\Karthi11\12.jpg

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul26

    Selection of Number of PolesFactors which affect the Selection of suitable Number of Poles are(i)Frequency(ii)Weightofironpart(iii)Weightofcopper(iv)Lengthofcommutator(v)Labourcharges(vi)Flashoverbetweenbrushes(vii)Distortionoffieldform

    Frequency of flux reversal apoles airon losses

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    27C:\Users\god\Desktop\DEM\Karthi11\13.jpgWeightofironpart

    .Ifthenumberofpolesisdoubled,thenthefluxintheyokeishalved.

    .Tokeepyokefluxdensitysame,theweightofironinyokecanreducedinproportiontoincreaseinnumberofpoles..Increasingtheno.ofpolesincreasesthefrequencyoffluxreversalinthearmaturecorewhichresultsincreasecorelosses.

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    28Weight of copper

    The weight of copper can be divided intoi.Armature copperii.Field copperDue to increase in no. of poles decreases armature and field copper.

    Length of commutator

    Whenno.ofpolesincreasesitresultsinreductioninthelengthofcommutator.

    2 pole m/c4 pole m/c

    Current per parallel path

    Ia/2

    Ia/4

    Current per brush arm

    Ia

    2Ia/4=(Ia/2)

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    29Labour Charges

    Thelabourchargeswillincreaseastheno.ofpolesincreasesduetomorearmaturecoilstowind,insulateandsoldertocommutatoranddesignoffieldwindingsFlash over between brushesDistortion of field formpZIATza2..Forasmallerno.poles,ATaincreasesresultsindistortionoffieldformandreductioninfluxunderloadconditions..Toavoidthedistortionoffieldform,itisnecessarytoprovidecompensatingwindingforamachineshavingsmallno.ofpoles..Itcomplicatestheconstructionandincreasesthecostofmachine.

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    Advantages of having more number of polesIncreasing the number of poles, will reduces the following.Weight of iron parts.Weight of copper.Length of commutator.Distortion of field form

    Disadvantages of increasing number of poles.Frequency of flux reversal is more.High labour charge.Increase the flash over between brush arms

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    Guideline for selecting number of poles

    i.Frequency of flux reversalFrequency lies between 25 to 50 HzLower frequency is preferred for large machinesii.Thevalueofcurrentperparallelpathshouldbelimitedto200Aandcurrentperbrusharmshouldbelimited400A.

    2npf.Wave windingLap winding

    Current per parallel path

    Ia/2

    Ia/p

    Current per brush arm

    Ia

    2Ia/p

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    iii. The value of armature mmf per pole should not be excessivelylarge.Armature mmf/pole2.acATa.pDacATa2..Output (kW)

    ATa(amp turns/m)

    Upto100

    5000 or less

    100-500

    5000 to 7500

    500 -1500

    7500 to 10000

    Over 1500

    upto12500

    iv.Ifmorethanonechoiceofpolessatisfiestheabovethreeconditions,thenselectlargeno.ofpoles.Thisresultsinreductioninironandcopper.

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul33Findthesuitablediameter,corelengthandnumberofpolesofa400kW,550V,900rpmdcgeneratorhaving92%efficiency.Assumeanaveragefluxdensityintheairgapofabout0.6Wb/m2andampereconductorspermetretobe35000.C:\Users\god\Desktop\DEM\Karthi11\14.jpgC:\Users\god\Desktop\DEM\Karthi11\14.jpg

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul35C:\Users\god\Desktop\DEM\Karthi11\14.jpgC:\Users\god\Desktop\DEM\Karthi11\15.jpgC:\Users\god\Desktop\DEM\Karthi11\15.jpg

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul36C:\Users\god\Desktop\DEM\Karthi11\15.jpgC:\Users\god\Desktop\DEM\Karthi11\15.jpgC:\Users\god\Desktop\DEM\Karthi11\15.jpg

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    C:\Users\god\Desktop\DEM\Karthi11\16.jpgC:\Users\god\Desktop\DEM\Karthi11\16.jpgC:\Users\god\Desktop\DEM\Karthi11\16.jpg

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul38Findthemaindimensions,numberofpolesandlengthofairgapofa600kW,500V,900rpmgenerator.Assumeaveragegapdensityis0.6Wb/m2andampereconductorspermetre35000.Theratioofpolearctopolepitchis0.75andtheefficiencyis85%.

    The following are the design constraints : peripheral speed 40 m/s,frequency of flux reversal 50 Hz, current per brush arm400A, armature mmfper pole 7800 AT. The mmfrequired for airgap is 60 percent of armature mmfand gap contraction factor 1.15.

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul39C:\Users\god\Desktop\DEM\Karthi11\17.jpgC:\Users\god\Desktop\DEM\Karthi11\17.jpg

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul42C:\Users\god\Desktop\DEM\Karthi11\18.jpgC:\Users\god\Desktop\DEM\Karthi11\19.jpgC:\Users\god\Desktop\DEM\Karthi11\19.jpg

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul43C:\Users\god\Desktop\DEM\Karthi11\19.jpgC:\Users\god\Desktop\DEM\Karthi11\19.jpg

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    Magnetic circuit calculationsMagnetic circuit calculation involves two types of problemsi.Itisrequiredtodeterminethemmfneededtoestablishadesiredfluxatagivenpointinamagneticcircuit.ii.Thefluxorfluxdensityisunknownandisrequiredtobedeterminedforagivengeometryofthemagneticcircuitandspecifiedmmf.Themagneticcircuitissplitupintoconvenientpartswhichmaybeconnectedinseriesparallel.Thecalculationofmmfinthemagneticpartsaresimplewhereasincaseofairgapandtaperedteeth,thecalculationsarecomplex.

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul47MMF calculation of air gapLet

    lglength of air gap

    ysslot pitch

    Wsslot width

    Wttooth width

    L Length of core

    ndnumber of radial ventilating ducts

    Wdwidth of each duct

    H = atg= mmf per unit length

    Atg = atg×lgtotal mmf required in the air gap

    Bgor Bavaverage gap flux density or specific magnetic loading

    Wb/m2

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul48Reluctance of air gap with smooth armature surfaceC:\Users\god\Desktop\DEM\Karthi11\1.jpgThe reluctance of air gap for one slot pitchsgggLylAlS00....70104.....Permeability of free spaceA = Lys= area of cross section of air gap over one slot pitch

    AlAlSr...0..

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    49Reluctance of air gap for slotted armatureThe area of cross section of the air gap through which the flux passes isLys (or) LWt.

    Effective or contracted slot pitch

    tsssWWyy....)(000ssgsgggWyLlyLlAlS........C:\Users\god\Desktop\DEM\Karthi11\2.jpg

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul50ReluctanceofairgapwitheffectsofbothslotsandventilatingductsC:\Users\god\Desktop\DEM\Karthi11\5.jpgEffective or concentrated axial lengthddcdwnKLL...KcdCarter co-efficient for ductswhich depends on the ratio ofgdlwlengthgapwidthduct.sddcdgsgggywnKLlyLlAlS)(000........

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    51gap contraction factor for ducts is defined as)(tanRetanRecasesmoothductswithoutgapairofcelucductswithgapairofcelucKgd.LLwnKLLKLylwnKLlddcdgdsgddcdg......00/)(/..Nowconsidertheeffectofbothslotandventilatingducts,reluctanceofthiscasegivenbysgggyLlAlS.....00..

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    52Picture1Clarifications ?

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    Picture1Thank you

    53

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul54Design of Armature (Armature winding)

    i.Choice of armature windingii.Number of armature conductorsiii.Number of armature coilsiv.Number of armature slots

    Choice of armature winding(a)Labwinding.No.ofparallelpathisequaltoNo.ofpoles(a=p).Thecurrentineachparallelpathsis(1/p)timesofratedarmaturecurrent(b)Wavewinding.No.ofparallelpathsisequalto2..Theconductorshavetocarryhalfoftheratedarmaturecurrent

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    Dr. R.Karthigaivel, Associate Professor/EEE, PSNA CET, Dindigul55Number of armature conductors

    Generated emf (or) back emf,Total no.of armature conductors,aZnpE..npEaZ..E= V+Iarm(for generator)E= V-Iarm(for motor)rm-internal resistanceIarm-internal voltage drop

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    Number of armature coilsThemaximumvalueofvoltagebetweenadjacentsegmentsatloadshouldnotexceed30V.Singleturnhastwoconductors,sinceNo.ofcoilsforsingleturnwinding=(Z/2)

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