ibo 2012 singapore part a

Question1Partially correct

Mark 0,25 out of 1,00

Text Question

Mitochondria key associated with the following functions:

a.thermogenesis / thermogenesisb.apoptosis / apoptosisc.production of ATP / energy production ATParchei moleculesd.fatty acid metabolism / metabolism of fatty Auxerre

Select which of the following cases PARXA strong presence mitochondria, intermediate and absence of mitochondria.

Intestine epithelia / Intestinal epitheliumAnswer 1

Red muscle fibers / fibers red - skeletal muscleAnswer 2

Brown fat cell / brown adipose tissue to produce heatAnswer 3

Sperm cell / SpermAnswer 4

Feedback

The correct answer is:

Intestine epithelia / Intestinal epithelium- Interim,

Red muscle fibers / fibers red - skeletal muscle- Entonsi,

Brown fat cell / brown adipose tissue to produce heat- Intense,

Sperm cell / Sperm- Interim.



Mitochondria key associated with the following functions:

a.thermogenesis / thermogenesisb.apoptosis / apoptosisc.production of ATP / energy production ATParchei moleculesd.fatty acid metabolism / metabolism of fatty Auxerre

Assign basic (basic) functions (function) of mitochondria (a through d) observed in the corresponding cells.

Feedback


Intestine epithelia / Intestinal epithelium- B,

Red muscle fibers / fibers red - skeletal muscle- C,

Brown fat cell / brown adipose tissue to produce heat- A,

Intestine epithelia / Intestinal epithelium- C,

Sperm cell / Sperm- C.Question3True


Arrange this series of molecules DNA, from lowest to highest, as regards their melting temperature (Tm).

a.5'-AAGTTCTCTGAA the 3rd-' 3'-TTCAAGAGACTT-5 '

b.5'-AGTCGTCAATGCGG-three ' -3'-on the 5th TCAGCAGTTACGCC '

c.5'-GGACCTCTCAGG the 3rd-' 3'-CCTGGAGAGTCC-5 '

Feedback


Mediocre Tm- C,

Higher Tm- B,

Chamilotero Tm- A.Question4Partially correct


There are several mechanisms by which a cell can be driven to suicide - a phenomenon known as "apoptosis".One of the mechanisms triggered by the active oxygen radicals.The outer membrane of mitochondria normally expressed on the surface of the protein Bcl-2.Another protein, Apaf-1 binds to Bcl-2.Active oxygen radicals induce the release of Apaf-1 from Bcl-2 and a third protein, Bax, penetrates the mitochondrial membrane, releasing cytochrome c.The liberated forms of cytochrome c form a complex with Apaf-1 and caspase 9.This complex then activates several proteases that digest (hydrolyze) cellular proteins.

What will be the fate of a cell exposed to reactive oxygen species in the following circumstances?

I. The cell expresses a mutant form of Apaf-1 which can be joined to (continuously) with the Bcl-on the 2nd.II.The cell does not express all the Bcl-two.III.The cell overexpressing a form of Bcl-2 which only targets the plasma membrane.IV.Added to the cell a chemical that prolongs the half-life of Bcl-2.

Assign the following situations in which a cell ends with the aforementioned conditions (I to IV).

a.The cell resistant to apoptosis.b.The cell is pushed in apoptosis.C.The fate of the cell can not be predicted.

Feedback


IV- C,

I- A,

II- B,

III- B.

Question5True


Text Question

Below is a cross section of the root.

They designed the three paths of ions and water absorption: apoplastic, diachymotopiako, symplastiko path.Assign paths with the numbers I, II, III you see in the above figure.

diachymotopiako pathAnswer 1

apoplastic pathwayAnswer 2

symplastiko pathAnswer 3



To match the description or outcome (A - J) with the corresponding term (1-9).

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8- J,

6- I,

1- E,

5- G,

7- C,

4- H,

2- A,

9- D,

3- B.



Text Question

The process of gas exchange in animals include various respiratory organs (a - d).For each animal (frog, salmon, crayfish, lizard, worm, dragonfly), matching to the appropriate bodies to adult animals:

a.Lungs / lungs

b.Gills / gills

c.Skin / skin

d.Trachea / windpipe

Feedback


Crayfish- B,

Dragonfly- D,

Frog- A, c,

Lizard- A,

Worm- C,

Salmon- B.

Question8True


Text Question

The amount of saliva secreted by a mammal related to how chewing needed.Pair the animals with saliva (saliva secreted / day in liters) producing.

wolf / wolf

horse / horse

cattle / cow

human / man

Feedback


man- 0.75 - 1.5,

cow- 130 to 180,

wolf- Smaller than 0.75,

horse- From 10 to 12.

Question9True


Text Question

European freshwater eels usually employ oxygen with gills but can spend long periods out of water by employing atmospheric oxygen from their skin.The graphic below shows the size of the blood saturation of the oxygen and the oxygen supply through various organs when eel was out of water (in arbitrary units).

Assign the following statements (I to IV) with corresponding lines (A - D) shown above.

I. Total saturation blood oxygen

II.Providing oxygen through gills

III.Providing oxygen through skin

IV.Providing oxygen through swim bladder

CAnswer 1

DAnswer 2

AAnswer 3

BAnswer 4



Text Question

The anatomical features of animals are adapted to different diets (a - d).

a.carnivores / carnivores

b.omnivores / omnivores

c.non-ruminant herbivores / herbivore non-ruminant

d.ruminant herbivores / ruminant herbivores

Assign different diets (a - d) with appropriate dental features (I - IV).

I. lack upper incisors, the presence of dental plaque, only sideways movement of premolars and molars.

II.canines are extremely well developed and used for mangling flesh

III.striations observed in molars by continuous grinding of food

IV.cutters used for snacking, premolars / molars angled to the position and the jaws are moved cyclically.

Feedback


III- B,

IV- C,

II- A,

I- D.



Text Question

The anatomical features of animals are adapted to different diets (a - d).

a.carnivores / carnivores

b.omnivores / omnivores

c.non-ruminant herbivores / herbivore non-ruminant

d.ruminant herbivores / ruminant herbivores

The ratio of surface area of the gastrointestinal tract (GI) and whole body differs between herbivores, omnivores and carnivores.Assign different diets (a - d) with the corresponding GI size / body size.

Feedback


2:1- C,

0.6:1- A,

1.2:1- B,

3:1- D.Question12Incorrect


Text Question

To assign the adjustments of the digestive system (a - c) with the following anatomical descriptions.

Anatomical descriptionsI.Simple stomach, very limited use of plants in the dietII.Simple stomach, inability to use plants in dietIII.Very developed stomach with many bags, capable of breaking down plant matter

Digestive adjustmentsa.Intensive anaerobic respiration after the food leaves the stomach and intestineb.Intensive anaerobic respiration before the food reaches the stomach and intestinec.Inability to digest certain substances in seeds, fruits and greens.

Feedback


III- B,

I- C,

II- A.



Text Question

The fish are well adapted to living in water (eg surface, middle bottom) of the water mass and specific habitats (eg seabed covered with grass, puddles rocks).The speed depends partially on the morphology of their body.Assign fish (A - H, which are not drawn to scale) with the analog habitat (Part of the water column / housing).

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Middle / Medium- D,

Surface- F,

Sea grass beds / Bottom of algae- G,

Bottom / Bottom- C,

Middle / Medium- H,

Rock crevices / cracks rocks- B,

Bottom / Bottom- E,

Bottom / Bottom- A.

Question14Incorrect


Text Question

The fish are well adapted to living in water (eg surface, middle bottom) of the water mass and specific habitats (eg seabed covered with grass, puddles rocks).The speed depends partially on the morphology of their body.Assign both faster and two slower fish (A - H, which are not drawn to scale).Feedback


Express- H,

Argon- A,

Argon- G,

Express- D.



Text Question

Match the following characteristics with the right organizations.

Features / Specifications:I.lung bags, grabbers (nails) sometimes consisting of three parts, but now reduced to just two gizzard.II.limited side undergoes metamorphosis during ontogeny.III.rear ends covered with scales, respiratory organs using ventilated airbags, moving over (jaw) and mandible (jaw).IV.minutes, tubular secretory organs that result between medium and posterior intestine, the body composed of three parts (guilds: all metameric together), a pair of antennae.V.specialized epithelial muscle cells, knidokyttara, ciliary body symmetry.VI.uses cysts of Lorenzini to determine the electric field and temperature differences, cartilaginous skeleton airway.

Organisms / Organizations:A.white shark (Carcharodon carcharias)b.housefly (Musca domestica)C.bird kokkinonouris (Phoenicurus Phoenicurus)d.corals spherical form (Faviidae)E.European garden spider (araneus diadematus)F.common frog (Rana temporaria)Feedback


IV- B,

III- C,

V- D,

I- E,

VI- A,

II- F.



Text Question

The following illustration shows one of the known hypotheses about the origin and evolution of plastids.

The procedures that facilitated the evolution represented by numbers (1-4) in the diagram above: (1) the primary endosymbiosis, (2) for the loss of primary plastids, (3) and (4) for additional endosymbiosis.These procedures resulted in the presence or absence of specific plastid in different taxa.Assign the taxa (a - d) with corresponding types of plastids, which are described in the following answers.

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3 chloroplast membranes- B,

Rodoplastis with 4 films- C,

Chloroplast membranes with 2- A,

Rodoplastis with two films- D.



Text Question

The researchers systematically cladistic perform comparisons between groups to separate derivatives and similar features main characters.To do this, use an external reference group, which relates quite to that study.

Treaty: The outside group is less related to each member of the study group than the members of the study group to another.

Prerequisite: Basic characteristics precede the divergence (separation of classes) of the two groups are bonds.

Given these theoretical proposals, some researchers studied a group and the information collected are shown in the following table.

Fill in kladogramma which best describes the relationship between the A1 to A6, matching numbers 1-2 by the A1-A6 in kladogramma shown below.

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6- A5,

3- A3,

1- A1,

2- A4,

5- A2,

4- A6

Question18True


Text Question

To study the cross section of the root in the figure below.

To assign passwords (1-18) given in the table below with the labeled parts (A to H) in the above form.

HAnswer 1

FAnswer 2

BAnswer 3

GAnswer 4

EAnswer 5

AAnswer 6

DAnswer 7

CAnswer 8



Text Question

Assign plant structures (1-10) with the corresponding functions (A - J).

8Answer 1

6Answer 2

4Answer 3

7Answer 4

10Answer 5

1Answer 6

9Answer 7

5Answer 8

2Answer 9

3Answer 10

Feedback


8- J,

6- I,

4- A,

7- D,

10- E,

1- G,

9- F,

5- C,

2- H,

3- B.

Question20Incorrect


Text Question

Which of the following sequences phases of the cell cycle is characteristic of eukaryotes; [G: gap, S: composition, M: mitosis]

Select one or more:

a.G1 _ G0 _ G1 _ S _ G2 _ M

b.G1 _ S _ G2 _ G0 _ Mc.G1 _ G0 _ G1 _ G2 _ S _ M

d.G1 _ G0 _ G2 _ S _ M

e.G0 _ G1 _ S _ G2 _ M

Feedback

The correct answer is: G0 _ G1 _ S _ G2 _ M, G1 _ G0 _ G1 _ S _ G2 _ M.



Text Question

About the G2 phase, chose what of the following statements you think is wrong:

Select one or more:

a.Homologous chromosomes are pulled by the spindle (microtubules) in their respective poles.b.Homologous chromosomes are aligned at the equator.c.Homologous chromosomes have not been copied yet.

d.Homologous chromosomes are the haploid or n state.Feedback

The correct answer is: Homologous chromosomes align at the equator., Homologous chromosomes are pulled by the spindle (microtubules) in their respective poles., Homologous chromosomes have not been copied yet., Homologous chromosomes are the haploid or n state ..

Question22True


Text Question

The bacteria in nature prefer to adhere to surfaces and to form shapes called "biofilm."During the adhesion step, prior to approaching the surface of adhesion, the bacteria encounter a zone where grown repulsive forces approaching the surface.Which bacteria are more likely to have an advantage in order to overcome this repulsion zone?

Select one:

a.A Bacterium

b.Bacterium Bc.Bacterium C

Feedback

The correct answer is: B. Bacterium

Question23True


Text Question

The bacteria in nature prefer to adhere to surfaces and to form shapes called "biofilm."During the adhesion step, prior to approaching the surface of adhesion, the bacteria encounter a zone where grown repulsive forces approaching the surface.

Once the bacteria overcome the repulsion zone and closer to the surface, the strength of adhesion to the surface of the three bacteria are likely to vary.Place the three bacteria in the correct order, depending on the strength of their attachment.

Select one:

a.A> B> C

b.B> C> A

c.C> A> B

d.C> B> AFeedback

The correct answer is: C> B> A.



Text Question

The bacteria in nature prefer to adhere to surfaces and to form shapes called "biofilm."During the adhesion step, prior to approaching the surface of adhesion, the bacteria encounter a zone where grown repulsive forces approaching the surface.

A small pond with stagnant water rich in organic content, but soon the concentration of nutrients was diluted with rainwater.All three bacteria were affected by this change and tried to survive the best way possible under these conditions.Select from the following statements, as many think that is wrong.

Select one or more:

a.A bacterium allows faster diffusion of the relevant components within its cell.b.The bacterium C has a capsule that allows it to efficiently absorb more nutrients.

c.The bacterium of the whip extends to take up nutrients from the water level.

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The correct answer is: A bacterium allows faster diffusion of the relevant components within its cell., The bacterium of the whip extends to take up nutrients from the water level., The bacterium has a capsule C which allows it to absorb nutrients more effectively ..



Text Question

A lab technician stained with different stains unknown bacteria before noticed.The dyes used are known to have designed, lipopolysaccharide, nuclear envelope, DNA, cytoplasm and ribosomes.What stains are likely to stain positive, regardless of the type of bacteria present in the sample;

Select one or more:

a.nuclear envelope

b.DNA

c.cytoplasmd.ribosomes

e.lipopolysaccharides

Feedback

The correct answer is: DNA, cytoplasm, ribosomes.



Text Question

Study the following graph and determine what / which of the following statements is correct / s.

Select one or more:

a.The plants are grown (accumulated biomass) when bright development environment is greater than the photon flux shown at A.b.Point B is showing the amount of light where the rate of photosynthesis equals respiration rate.

c.Point A is a point fotokoresmou.

d.It is a curve produced photosynthetic O2.e.The rate of cellular respiration is greater than the rate of photosynthesis when the plants grow in low light than the value shown at point A.

f.The C is the maximum photosynthetic rate.g.Plants stop growing when they grow under irradiation greater than that indicated by point B.

Feedback

The correct answer is: C is the maximum photosynthetic rate., The rate of cellular respiration is greater than the rate of photosynthesis when the plants grow in low light than the value indicated by the point A, Plants grown (accumulate biomass) when bright development environment is greater than the photon flux shown at A..

Question27True


Text Question

Read the following response curves to light for photosynthesis sheet in C4 and C3 plants.To select / the right / s statement / s.

Select one or more:

a.Figure A shows the characteristics of plant C4.b.The C3 plants have a competitive advantage over C4 plants in full sunlight (full sunlight) due to reduction of photorespiration.

c.The C3 plants have a competitive advantage over C4 at low temperatures and low light due to the higher quantum efficiency.Feedback

The correct answer is: Figure A shows the characteristics of plant C4., The C3 plants have a competitive advantage over C4 at low temperatures and low light due to the higher quantum efficiency ..

Question28True


Text Question

Below are some statements related to photosynthesis.To determine which / what the / the following statement / statements is true / correct.

Select one or more:

a.The key initial role of light at the beginning of the light phase of photosynthesis is the production of free oxygen.

b.The photophosphorylation comprises producing ATP during the light phase of photosynthesis.c.It is now believed the specialized enzymes needed for CO2 capture in sugar found in the chloroplast stroma.d.In a plant cell, ATP synthase complexes are found only in thylakoid membranes.e.Photosystem II is necessary for the cyclic phosphorylation.

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The correct answer is: The photophosphorylation involves ATP production during the light phase of photosynthesis., Currently believed specialized enzymes that are essential for the capture of CO2 to sugars found in the stroma of the chloroplast ..

Question29Incorrect


Text Question

Place the following Plants A to C in evolutionary order, starting from the most primitive to the most advanced sample (on the order of answers is: primitive, intermediate, contemporary).

Select one:

a.B -> C -> A

b.B -> A -> C

c.A -> C -> B

d.A -> B -> Ce.C -> A -> B

Feedback

The correct answer is: B -> C -> A.

Question30True


Text Question

Below are data respiration rate, heart rate and body temperature of four different mammals, A to D.

Classify mammals A D according to the surface area in relation to the volume (from high to low).

Select one:

a.A> D> C> B

b.A> D> B> C

c.A> C> B> Dd.D> C> B> A

e.C> B> A> D

Feedback

The correct answer is: A> C> B> D.

Question31Incorrect


Text Question

Below are data respiration rate, heart rate and body temperature of four different mammals, A to D.

To classify mammals A to D according to the total blood volume in the body (from largest to smallest).

Select one:

a.C> B> A> D

b.A> C> B> Dc.A> D> B> C

d.A> D> C> B

e.D> B> C> A

Feedback

The correct answer is: D> B> C> A.



Text Question

Evaluate the following statements concerning the respiratory processes of amphibians, reptiles, birds and mammals.To choose the correct answers between the agencies and the following tasks:

I. negative pressure is used to transfer air into the lungs

II.The lungs completely filled with air during the respiratory cycle.

Select one or more:

a.Birds -> Ib.Mammals -> Ic.Mammals -> II

d.Reptiles -> I

e.Birds -> II

f.Amphibians -> IIg.Reptiles -> IIh.Amphibians -> I

Feedback

The correct answer is: Reptiles -> I Birds -> I Birds -> II Mammals -> I.



Text Question

The process of gas exchange in animals include the circulatory system (open and closed).For each animal (frog, Salmon, crayfish, lizards, Worm, Dragonfly) to choose those who have an open circulatory system.

Select one or more:

a.Dragonflyb.Crayfish

c.Lizard

d.Frog

e.Wormf.Salmon

Feedback

The correct answer is: lobster, Dragonfly.



Text Question

The urine production is the result of the continuous filtration of plasma from the kidneys.Please choose as many of the following statements do you think is correct.

Select one or more:

a.The kidneys produce antidiuretic hormone ADH.

b.The kidneys help control the total volume of blood in circulation.c.The ammonia (NH3) generated in the proximal threaded sections during acidosis.

d.The rate of filtration in glomerulus affected by the concentration of sodium in the blood.

e.The kidneys help maintain stable pH apekkrinontas ydrogonoionta epanarrofontas and bicarbonate ions.f.The kidneys cooperate with the lungs in the control of pH of the plasma.g.Animals excrete very concentrated urine, such as rats desert, have relatively small brackets Henle.

h.The kidneys have a direct effect on blood pressure.i.Brackets Henle withdraw water, ions and nutrients from the blood.

j.The kidneys excrete volatile acids produced by the metabolism.Feedback

The correct answer is: The kidneys have a direct influence on blood pressure. The kidneys help to control the total volume of blood in circulation. The kidneys and lungs cooperate in controlling the pH of the plasma. Ammonia (NH3) produced in proximal threaded sections against acidosis. the rate of filtration in glomerulus affected by the concentration of sodium in the blood ..



Text Question

The allergy is due to hypersensitivity of the immune system as a result of excessive exposure to antigens.Conversely, although the psefdallergia similar to allergy, there is no immune stage in its development.

The pathological processes listed below as comments:

a.The overall levels of IgE antibodies in serum is elevated.

b.Specifically detect IgE antibodies in serum.

c.Released histamine is the main essence of the process of inflammation.

d.To show the reaction requires a minimum amount of antigen.

To choose which comments apply to the presence of allergy.

Select one or more:

a.db.a

c.bd.cFeedback

The correct answer is: a, b, c, d.

Question36True


Text Question

The allergy is due to hypersensitivity of the immune system as a result of excessive exposure to antigens.Conversely, although the psefdallergia similar to allergy, there is no immune stage in its development.

The pathological processes listed below as comments:

a.The overall levels of IgE antibodies in serum is elevated.

b.Specifically detect IgE antibodies in serum.

c.Released histamine is the main essence of the process of inflammation.

d.To show the reaction requires a minimum amount of antigen.

To choose which comments apply to the presence psefdallergias.

Select one:

a.a

b.d

c.cd.b

Feedback

The correct answer is: c.

Question37True


Text Question

The age of the animal fossils can be determined using carbon isotopes14C in their bones.How accumulates14C in the bones?

Select one:

a.converting CO2 into organic compounds in bone

b.the accumulation of CO2 and deposition in bone

c.with consumption and assimilation of organic compounds on boneFeedback

The correct answer is: with consumption and assimilation of organic compounds in the bones.

Question38Incorrect


Text Question

In all vertebrate species, there are always some items that circumstances can "fly" (eg fish, frogs, lizards and squirrels).They have the ability to 'real' flight but use their body parts as gliders or parachutes to slow their descent.

Animals act as gliders minimize resistance (D) air (drag) and use updrafts (L) to create better climb / drag (L / D ratio).In contrast, animals that use the method of parachute, maximize D because they usually do not have sufficient area to increase L. When the animal is normal anemopteriki descent, forces act on it (see figure below).The resistance (R) which generates the stretched body in air produces L. There also drag (D) in the opposite direction of flight, while there is also the effect of the weight of the animal (mg).The path to the ground makes an angle (i).

To assign the correct animal, (a or b), with the expected values L / D and No.

Select one or more:

a.T> 45 -> ab.L / D ac.L / D b

d.T> 45 -> b

Feedback

The correct answer is: L / D b, T> 45 -> b.



Text Question

In all vertebrate species, there are always some items that circumstances can "fly" (eg fish, frogs, lizards and squirrels).They have the ability to 'real' flight but use their body parts as gliders or parachutes to slow their descent.

In the 'flying' lizards, the patageio is a leather strand that connects the front and rear ends.The Russell and Dijkstra (2001) compared the patageia and associated aerodynamic surfaces of two species of lizards,Draco Volans('Flying' Dragon) andPtychozoon kuhli('Flying' Gecko).

To choose which of the following conclusions are correct, that can be drawn from the study on the morphological adaptations of lizards for air movement.

Select one or more:

a.Although the average weight of D. volans is smaller than that of P. kuhli, the body surface per unit mass is very similar.

b.Ancillary structures increase the aerodynamic surface contribute much more to D. volans than in P. kuhli.c.The similar size that contributes patageio is higher in D. volans than in P. kuhli, faced this drawback (the P. Kuhli) in the presence of auxiliary fins and folds.d.The total area of the body is very similar in both species.

e.The comparison of the area of the mass patageiou shows that the P. kuhli patageia are larger than the patageia D. volans having equivalent mass.

Feedback

The correct answer is: Although the average weight of D. volans is smaller than that of P. kuhli, the body surface per unit mass is very similar., The total area of the body is very similar in both species., The proportional size contributed by patageio is higher in D. volans than in P. kuhli, faced this drawback (the P. Kuhli) in the presence of auxiliary fins and folds ..

Question40True


Text Question

Male crabs fiddler, using large claws (chelipeds) to send messages, the moving (eg females).A student studied the interaction of male-female crabs, using two mirrors that reflect images of the same male, but of different sizes, which was initiating the claws of females.Combinations of mirrors used in the experiment were: 10x: 3x (Edit-treatment I), 3x: 1x (Treatment II) and 10x: 1x (Treatment III).Ten male crabs Kinousa the callipers, occurred in 20 females in three trials for each treatment.Recorded the percentage of females (Graph A) and the time it took each female crab to approach each reflection (Chart B) for each treatment and the information whether the male was left-handed or right-handed.

Choose from the following / s right / d conclusion / conclusions that can be drawn about the interactions of male and female crabs.

Select one or more:

a.In mate choice is important if the males are left-handed or right-handed

b.Males that move faster the claws attract more females

c.An obvious difference in the size of the caliper helps females to be more decisived.The average time it takes females to make a choice between different arsenic Processing II and III

e.Females generally prefer older malesFeedback

The correct answer is: Females generally prefer older males, a clear difference in the size of the caliper helps females to be more decisive.



Text Question

The Cormorants (Phalacrocorax carbo) feed on fish.Submerged in water and use vision to hunt fish, and this is why my water clarity is critical.Usually, they are solitary hunters but when the water is cloudy, you can create a group in which many Cormorants cooperate.

To select / the process / processes playing / play a role in developing a cooperative hunting strategy Cormorants.

Select one or more:

a.trial and error / trial and error

b.social learning / social learningc.imprinting / mapping the genome

d.Conditioning / Agilitye.Habituation / habitf.Competition / Competition

Feedback

The correct answer is: social learning / social learning, trial and error / trial and error.

Question42True


Text Question

The diagram below the Dittman et al.(1999) shows the behavior of adult salmon, Oncorhynchus kisutch, reared in a hatchery, and exposed to synthetic flavoring, beta-phenylethyl alcohol (PEA) which was placed in one of the two tubes that lead to the arena, ie the tank in which they are salmon.Salmon exposed to PEA during different stages of their development: alevin (Stage I), parr (Stage II) and smolt (Stage III) at the hatchery before adulthood and experimentation.The control fish (control) was not exposed to PEA.

To choose the / a correct / s conclusion / conclusions can be drawn.

Select one:

a.There is a critical period in the olfactory imprinting in salmon.b.Chemical signals play a secondary role in the repatriation of salmon.

c.Salmon initially exposed to PEA had no preference left or right input tube REA

d.The age of the salmon is the most important factor that allows the salmon to return to their place of hatching.

Feedback

The correct answer is: There is a critical period in the olfactory imprinting in salmon ..

Question43True


Text Question

The Bateson and Punnett (1908) studied the color of the flowers and the shape of pollen in sweet pea (Lathyrus odoratus, associated with sweet pea Pisum sativum studied by Mendel).Crossed a pure (homozygous) purple plant with elongated pollen grains with a pure (homozygous) plant red round pollen grains and complete the following table for the offspring of F2 generation:

Indicate the likely explanation for the observed differences between expected guests.

Select one:

a.Maternal inheritance / Mother inheritance

b.Dominant epitasis / prevailing epistasis

c.Linkage / Insiderd.Complimentary epistasis / Supplementary Stewardship

Feedback

The correct answer is: Linkage / Insider.

Question44True


Text Question

The DNA sequence of the genome of Atlantic salmon (Salmo salar), which includes 28 pairs of autosomes and one pair of sex chromosomes (XY) has recently been analyzed.The technique used for DNA microinjection successfully transferred an intergenic structure containing the growth hormone gene at the stage of the zygote embryo salmon.Transgenic individuals obtained 4 (paternal atoms F0), 2 males and 2 females.The intergenic structure of growth hormone is subject to review by an amplifier specialist for the liver, and all four transgenic individuals have high levels of growth hormone in plasma, leading to an acceleration in the pace of growth.It was confirmed that the transgene was integrated structure in a single copy in the genome.Through beam will obtain stable lines of transgenic salmon with an increased growth rate.To create the F1 generation, both male and female transgenic parent individuals F0 intersect with gender of persons corresponding wild type (nontransgenic) salmon.

When you check the ratio of males versus females in the F2 generation would find that there are always more females (70%) than males (30%) subjects regardless of whether the presence of the transgenic portion is zero, in heterozygous or homozygous individuals the F2 generation.Do the instructions / the right / s explanation / explanations for these results.

Select one:

a.Apart from the sex chromosomes, environmental factors are likely to have a secondary role in fylokathorismo.b.The transgenic portion of growth hormone has been transferred to another locus in the sex chromosomes, which leads to sex reversal in some males.

c.The integration of the transgenic growth hormone structure is no longer stable.

d.The epigenetic silencing (not expression) in some people has stifled the expression of the transgene portion of growth hormone.

Feedback

The correct answer is: Apart from the sex chromosomes, environmental factors are likely to have a minor role in fylokathorismo ..

Question45True


Text Question

The hens with short wings and legs are called "creepers".When creepers are mated with normal birds produce creepers and normal birds at equal frequencies.When mated with creepers creepers creepers and produce normal birds 2:1 ratio.The intersection of normal birds leads to the production of only normal offspring.

What is the simplest genetic basis for chickens and creepers normal chickens? Indicate the / the right / s answer / answers.

Select one or more:

a.creepers -> homozygous dominant

b.normal -> homozygous recessivec.creepers -> heterozygousd.creepers -> homozygous recessive

e.normal -> homozygous dominant

f.normal -> eterozygo

Feedback

The correct answer is: normal -> homozygous recessive, creepers -> heterozygous.

Question46True


Text Question

The hens with short wings and legs are called "creepers".When creepers are mated with normal birds produce creepers and normal birds at equal frequencies.When mated with creepers creepers creepers and produce normal birds 2:1 ratio.The intersection of normal birds leads to the production of only normal offspring.

To indicate the correct phenotype have hens with 2 creeper alleles.

Select one:

a.Normal / Normal

b.Short wings / Short wings

c.Lethal / Deadlyd.Short wings and legs / Short wings and legs

e.Short legs / feet Close

Feedback

The correct answer is: Lethal / Deadly.

Question47Incorrect


Text Question

In a specific fruit plant, several genes control the production of anthocyanin.In the absence of anthocyanin, leaves seedling show coloring only with green chlorophyll.One locus (defined chromosomal location) called Colourless 1 (C1) appear to function as an intermediary loci for at least two other proteins (the ChsA and ChsJ) encoding two enzymes in the pathway of synthesis of anthocyanin (see figure below).The path to the anthocyanin hampered residual homozygous genotypes as shown for the region ChsA in Fig.To assume that the following conditions apply: (i) applicable independence for installation and for the three loci and (ii) homozygosity for recessive alleles at any of the three loci causes the production of green seedlings.

To indicate the expected phenotypic ratios of progeny for the two crosses, mentioned below.

Note: the following answers concerning respectively "beam type" -> "Share progeny (green to purple)"

Select one or more:

a.ChsA chsA ChsJ chsJ C1c1XchsA chsA chsJ chsJ c1c1 -> 3:1

b.ChsA chsA ChsJ chsJ C1c1XchsA chsA chsJ chsJ c1c1 -> 1:1

c.ChsA chsA ChsJ chsJ C1C1XChsA chsA ChsJ chsJ C1C1 -> 1:7

d.ChsA chsA ChsJ chsJ C1c1XchsA chsA chsJ chsJ c1c1 -> 15:1

e.ChsA chsA ChsJ chsJ C1C1XChsA chsA ChsJ chsJ C1C1 -> 9:7

f.ChsA chsA ChsJ chsJ C1c1XchsA chsA chsJ chsJ c1c1 -> 9:7g.ChsA chsA ChsJ chsJ C1C1XChsA chsA ChsJ chsJ C1C1 -> 1:1

h.ChsA chsA ChsJ chsJ C1C1XChsA chsA ChsJ chsJ C1C1 -> 15:1

i.ChsA chsA ChsJ chsJ C1c1XchsA chsA chsJ chsJ c1c1 -> 1:7

j.ChsA chsA ChsJ chsJ C1C1XChsA chsA ChsJ chsJ C1C1 -> 3:1

Feedback

The correct answer is: ChsA chsA ChsJ chsJ C1C1XChsA chsA ChsJ chsJ C1C1 -> 9:7, ChsA chsA ChsJ chsJ C1c1XchsA chsA chsJ chsJ c1c1 -> 1:7.

Question48Incorrect


Text Question

The marsupial moles (classNotoryctemorphia) living in sandy desert areas of South Australia, Western Australia and the northern region.They dig tunnels in the sand, filling the tunnel behind them and giving the impression that "swim" through the sand.His eyes marsupial mole is completely covered by skin, have a diameter of about 1 mm and no lens or daughter.The optic nerve is too weakened.Do the instructions / the right / s proposal / recommendations (a - c).

Select one:

a.The immensely weakened optic nerve is a residual-vestigial (atrophic) structure.

b.The absence of the lens is homologous to the absence of the flies ommatidion cave.c.His eyes marsupial mole is where the eyes of kangaroos.

Feedback

The correct answer is: The eyes of the marsupial mole is depending on the eyes of kangaroos ..

Question49True


Text Question

We studied the banding pattern / littorinid footsteps of snails on the rocky shores of Singapore, a vertical cliff (see A) and a sloping rock (see B).Two taxonomic groups found on vertical rock and an additional third type found in sloping rock.The dispersion of snails was recorded in July, September and December 2002, when the average surface temperature of the rocks was 42 C, 34 C and 27 C respectively.

Do the instructions / the right / correct conclusions on the dispersion patterns of snails.

Select one or more:

a.The preferred area for habitat Echinolittorina malaccana kind is smaller than the corresponding species in Littoraria sloping rock.b.The kind Echinolittorina vidua is less heat resistant than the sympatry of species E. Malaccana.

c.The upper limits of the zone type Echinolittorina malaccana the vertical rock was constant regardless of the sampling period.d.The species Echinolittorina vidua and Littoraria have similar zones dispersion.

e.The sampling period does not affect the dispersion pattern of the two groups of snails on the vertical rock.

Feedback

The correct answer is: The upper limits of the zone of the kind Echinolittorina malaccana the vertical rock was constant irrespective of the sampling period. The preferred zone for habitat Echinolittorina malaccana kind is smaller than the corresponding species in Littoraria sloping rock ..

Question50Incorrect


Text Question

We studied the banding pattern / littorinid footsteps of snails on the rocky shores of Singapore, a vertical cliff (see A) and a sloping rock (see B).Two taxonomic groups found on vertical rock and an additional third type found in sloping rock.The dispersion of snails was recorded in July, September and December 2002, when the average surface temperature of the rocks was 42 C, 34 C and 27 C respectively.

Snails collected from the field and extracts six tissue samples from each of the three groups were separately incubated classification at different temperatures.Calculated activity of transaminase glutamate oxaloacetate transaminase (GOT) and the results of the enzymatic assays are presented in the following graph.

To indicate the correct taxonomic group (EM, EV or LL) reflecting the graph shown below:

Select one:

a.Taxon / Phylogenetic group: EM

b.Taxon / Phylogenetic group: EV

c.Taxon / Phylogenetic group: LLFeedback

The correct answer is: Taxon / Phylogenetic group: EM.



Text Question

The ecology of a group of beetles was studied in West Africa by Krell-Westerwalbesloh et al.(2004).The community of beetles were divided into four categories: (i) the slide (rollers), (ii) the Tiller (tunnellers), (iii) the residents (dwellers) and (iv) the mandatory kleptoparasitistes (obligatory kleptoparasites).The slide quickly make balls of dung / feces (less than 1 hour), the flow away from the source and depositing in or on the earth to witness the exclusive use of manure.The Tillers build nests just below the source of manure / feces and carry into the nest, where they form these balls (within hours).Residents feed and reproduce in the pile of manure.The mandatory portions kleptoparasitistes use manure / faeces monopolized by other groups, egstealing balls manure make the slide or portions of the pile manure around the nest grubber.Recorded abundance (see Table) and Airworthiness (see Figure) of these beetles (data from 15 samples) at six different times of day.

Do the instructions / the right / correct conclusions can be drawn from the study.

Select one or more:

a.There is intense competition in the community of beetles.b.The actual habitat and habits of each group are similar to the respective base their habits and habitats (habitat without the presence of competition).

c.The four groups of beetles can not coexist as all exploit the same resource in similar ways.

d.The results of this study support the principle of competitive exclusion and provide evidence for the division (sharing) of natural resources.

e.One or more of the groups will eventually sidelined / s and remove it / them from the community.

f.The slide dominate the community of beetles.

Feedback

The correct answer is: There is intense competition in the community of beetles., The Scroll dominate the community of beetles., The results of this study support the principle of competitive exclusion and provide evidence for the division (sharing) of natural resources ..

Question52Incorrect


Text Question

Mount St.Helens state in southeastern Washington (USA) erupted catastrophically on May 18, 1980.The explosion resulted in a terrain with low availability of nutrient media, intense droughts and frequent movements of the surface.They settled permanently grids at various points over the ridge around the crater to watch the rebound after the explosion.The following chart shows the number of species and the coverage ratio to one of these points from 1981 to 1998.

Do the instructions / the right / correct conclusions can be drawn from the diagram.

Select one or more:

a.The total cover of the vegetation in this area has grown relatively slowly due to unfavorable conditions in volcanic deposits.

b.Neither space nor light is a limitation to the plants resources in this environment.

c.The explosion killed all the vegetation above the ridge.

d.In study has created a stable plant community 20 species, suggesting the peak stage in the process of ecological succession.

e.Only a few additional species invaded after 1982.

f.The secondary succession (recurrence after vegetation destruction) occurred rapidly after the explosion.Feedback

The correct answer is: The explosion killed whole vegetation over the ridge. Neither the space nor the light is a limitation to the plants resources in this environment., Only a few additional species broke after 1982. Total coverage of the vegetation in this area has grown relatively slowly due to unfavorable conditions in the volcanic deposits ..



Text Question

The following schematic diagram shows a simulation of a marine community, which was performed to study the relationships between populations.

Based on / in the diagram above, indicate the / the right / wrong statements.

Select one or more:

a.All animals in this community have three germ layers and is defterostomia.

b.In their natural environment, the density of mussels is greater in the middle intertidal zone than in the lower intertidal zone.c.The sexes of animals represented here are echinoderms, mollusks and arthropods.

d.At the end of the study, the community is falling apart and only one population increases the ecological habitat.e.Demonstrated the competitive exclusion of other populations of mussels.

f.In their natural environment, the starfish is a staple.g.The community, in this natural state, contains four species of the Kingdom Animalia.h.The physical conditions include biotic interactions such as inter-specific (between species) competition and predation.i.The mussels occupy the fundamental habitat including both middle intertidal zone and the lower intertidal zone.

Feedback

The correct answer is: The community, in this natural state, contains four species of the Kingdom Animalia., The tribes of animals represented here are echinoderms, mollusks and arthropods., In their natural environment, the starfish is a key species., In their natural environment, the density of mussels is greater in the middle intertidal zone than in the lower intertidal zone., At the end of the study, the community collapses and only one population increases the ecological habitat. demonstrates the competitive exclusion of remaining populations of mussels., mussels occupy the fundamental habitat including both middle intertidal zone and the lower intertidal zone., Physical conditions include biotic interactions such as inter-specific (between species) competition and predation ..



Text Question

Growth in most intertidal organisms generally decreases with a vertical direction towards the coast.The Lim and Green (1991) studied a population of the Baltic clam Macoma balthica (an ordinary two-door), two levels of coast in Hudson Bay, Canada.The annual growth rings of shells are distinct in both subpopulations (see the following diagram) and the mussels of the two zones do not differ genetically.The Baltic mussel normally buries himself and generally hiding from predators.Is the vector of trimatodon.Subsidiaries sporocysts pests are found mainly in the gonads of mussels, and cause partial or complete disappearance of the gonads.Seabird, the final host of trimatodon there in large numbers in the upper shore during low tide (tide of retreat).Measured the number of metacercariae (the next stage in the life cycle of the parasite) egkystontai that the inner surface of the shell and nested erpomenon mussels.

Select one or more:

a.Environmental factors may play an important role in determining the growth rate of mussels in subpopulations than heredity.

b.The creep behavior of mussels could enhance the integration life cycle of the parasite.

c.Increased exposure of mussels in the upper shore on seabirds, which are the definitive host of trimatodon, could be held responsible for the difference in parasite load between the two sub-populations.

d.Mussels that are buried in the sand generally have more metakerkidikes (metacercaria) cysts regardless of the level of the coast.

e.A relatively larger size of mussel accepted the parasite further up the coast.f.The growth rate of Macoma balthica in Hudson Bay agrees with the generally observed for most intertidal organisms, such as lower intertidal organisms grow faster than those in the upper coast.

g.High parasitic load promotes physical development, reduced reproductive performance due to castration of the host of the trematodes.

Feedback

The correct answer is: A relatively larger size of mussel accepted the parasite further up the coast., The creep behavior of mussels could enhance the integration life cycle of the parasite., Increased exposure of mussels in the upper shore on seabirds, which are definitive host of trimatodon, could be held responsible for the difference in parasite load between the two sub-populations., high parasitic load promotes physical development, reduced reproductive performance due to castration of the host of the trematodes., Environmental factors may play an important role in determining the growth rate of mussels in subpopulations of that heredity ..



Text Question

The following table presents the genetic code of amino acids.

Some viruses (e.g. tobacco mosaic (TMV) RNA with sequences which contain a "defective" codon. In TMV, at 95% of the time the ribosome host will terminate protein synthesis of the polypeptide at this codon but the remainder will overtake.

The following sequences show part of an mRNA of TMV.Pointed to (the) sequence (sequences) that may lead to the production of two polypeptides, in part given, choosing them as correct (they will not be chosen are those which will not produce two peptides).

Select one or more:

a.5'-AUG-UCU-UAU-UGG-CAU-GAU-GGU-UGU-CUU-UUC-ACC-CGG-GGG-AAA-UAA-3 '

b.5'-AUG-CAU-GUU-CUU-UUC-UCU-UAU-UGU-GGU-UGU-ACC-CGG-GGG-UUC-UAA-3 '

c.5'-AUG-CAU-GAU-GGU-UGU-ACC-CGG-GGG-UAG-CUU-UUC-UCU-UAU-UGC-UAA-3 '

d.5'-AUG-ACC-CGG-GGG-UUU-CUU-UUC-UAG-UAU-GAU-CAU-GAA-GGU-UGU-UAA-3 'e.5'-AUG-CUU-UUC-UCU-UAU-UAG-CAU-GAU-GGU-UGU-ACC-CGG-GGG-CCC-UAA-3 'f.5'-AUG-UCU-UGU-CUU-UUC-ACC-CGG-GGG-UAG-UAU-UAC-CAU-GAU-GGU-UAA-3 'Feedback

The correct answer is: 5'-AUG-UCU-UGU-CUU-UUC-ACC-CGG-GGG-UAG-UAU-UAC-CAU-GAU-GGU-UAA-3 ', 5'-AUG-ACC-CGG- GGG-UUU-CUU-UUC-UAG-UAU-GAU-CAU-GAA-GGU-UGU-UAA-3 ', 5'-AUG-CUU-UUC-UCU-UAU-UAG-CAU-GAU-GGU-UGU- ACC-CGG-GGG-CCC-UAA-3 ', 5'-AUG-CAU-GAU-GGU-UGU-ACC-CGG-GGG-UAG-CUU-UUC-UCU-UAU-UGC-UAA-3'.

Question56True


Text Question

How many chromatin filaments present in a normal human body cell is in G2 phase?

Answer:

INCLUDEPICTURE "http://e-school.biologia.gr/theme/image.php/fusion/core/1386199438/i/grade_correct" \* MERGEFORMATINET Feedback

The correct answer is: 92

Question57Incorrect


Text Question

Some combinations of alleles can lead to a particular mental disorder in humans.The Table shows the enzymatic activity of different genotypes (indicated as percentages of normal activity).

All individuals who are homozygous or heterozygous for any combination of 5/1 alleles listed above exhibit the classic symptoms of the disease.Individuals heterozygous Y424C and between each of the first four alleles (ie example individuals Y424C/R231X or Y424C / P292L etc.) show milder symptoms.Homozygous individuals R158Q/R158Q exhibit the classic symptoms of the disease, while the homozygous and heterozygous R271Q/R271Q R271Q/Y424C atoms exhibit milder symptoms.What is the enzyme activity in individuals with genotypic combinations marked with an X (R271Q/E290K);

Hint: write a number that you think corresponds to the enzyme activity, eg24Answer:

INCLUDEPICTURE "http://e-school.biologia.gr/theme/image.php/fusion/core/1386199438/i/grade_incorrect" \* MERGEFORMATINET Feedback


Question58Incorrect


Text Question


All individuals who are homozygous or heterozygous for any combination of 5/1 alleles listed above exhibit the classic symptoms of the disease.Individuals heterozygous Y424C and between each of the first four alleles (ie example individuals Y424C/R231X or Y424C / P292L etc.) show milder symptoms.Homozygous individuals R158Q/R158Q exhibit the classic symptoms of the disease, while the homozygous and heterozygous R271Q/R271Q R271Q/Y424C atoms exhibit milder symptoms.What is the enzyme activity in individuals with genotypic combinations marked with a Y (Y424C / R158Q);

Hint: write a number that you think corresponds to the enzyme activity, eg24Answer:



Question59Incorrect


Text Question


If genetic traits are inherited independently to calculate the expected values for each phenotype and check the random distribution by calculating the value of X2.

Hint: write a number that corresponds to the value of X2, eg134Answer:



Question60True


Text Question

In the pituitary, certain peptides derived from the propeptide-opiomelanocortin (POMC) that are used as buffers.The propeptide is proteolytically cleaved (A - E) in various products.Each polypeptide is shown below, has the amino terminus on the left and the carboxy terminus on the right.

To write the minimum number of enzymes needed by a cell to produce b-MSH from POMC.

Hint: write a number, eg5Answer:



Question61Incorrect


Text Question

In the pituitary, certain peptides derived from the propeptide-opiomelanocortin (POMC) that are used as buffers.The propeptide is proteolytically cleaved (A - E) in various products.Each polypeptide is shown below, has the amino terminus on the left and the carboxy terminus on the right.

Write down the minimum number of enzymes needed by a cell to produce a-MSH from POMC.

Hint: write a number, eg5Answer:



Question62True


Text Question


If genetic traits are inherited independently, what phenotypic ratio would expect to see?

Hint: write the phenotypic ratio of the form: 5:4:3:2

Answer:


The correct answer is: 9:3:3:1

Question63Incorrect


Text Question


If genetic traits are inherited independently to fill the expected values for each phenotype.

Hint: write the expected values, starting from top to bottom of the table and distinguishing values with a comma, eg12, 15, 16, 17, 50Answer:


The correct answer is: 240, 80, 80, 27, 427

Question64Incorrect


Text Question

The DNA sequence of the genome of Atlantic salmon (Salmo salar), which includes 28 pairs of autosomes and one pair of sex chromosomes (XY) has recently been analyzed.The technique used for DNA microinjection successfully transferred an intergenic structure containing the growth hormone gene at the stage of the zygote embryo salmon.Transgenic individuals obtained 4 (paternal atoms F0), 2 males and 2 females.The intergenic structure of growth hormone is subject to review by an amplifier specialist for the liver, and all four transgenic individuals have high levels of growth hormone in plasma, leading to an acceleration in the pace of growth.It was confirmed that the transgene was integrated structure in a single copy in the genome.Through beam will obtain stable lines of transgenic salmon with an increased growth rate.To create the F1 generation, both male and female transgenic parent individuals F0 intersect with gender of persons corresponding wild type (nontransgenic) salmon.

For the introduction of Fon the 2ndgeneration is requested to make a crossbreed between siblings to get transgenic homozygous individuals will carry the transgene structure of growth hormone.What would be the expected genotypic ratio expressed as a%?

Hint: Write the percentages percent (%) reported in the order in omozyo, heterozygous, wild-type writing numbers separated by commas, eg15, 45, 40Answer:


The correct answer is: 25, 50, 25

Question65Incorrect


Text Question

The black hair of Guinea Pig due to a dominant gene B and the white of the recessive allele b.To assume that people II1 and II4 are not carriers of the recessive allele.

What is the probability of the individual II3 be heterozygous?

Hint: the answer given by a fraction, eg4/3Answer:


The correct answer is: 2/3

Question66Incorrect


Text Question

The black hair of Guinea Pig due to a dominant gene B and the white of the recessive allele b.To assume that people II1 and II4 are not carriers of the recessive allele.

What is the probability that a particular offspring of crossover III1 x III2 have white hair?

Hint: the answer given by a fraction, eg4/3Answer:


The correct answer is: 1/12

Question67Incorrect


Text Question


AAll individuals who are homozygous or heterozygous for any combination of 5/1 alleles listed above exhibit the classic symptoms of the disease.Individuals heterozygous Y424C and between each of the first four alleles (ie example individuals Y424C/R231X or Y424C / P292L etc.) show milder symptoms.Homozygous individuals R158Q/R158Q exhibit the classic symptoms of the disease, while the homozygous and heterozygous R271Q/R271Q R271Q/Y424C atoms exhibit milder symptoms.What is the critical variation sets / distinguish individuals with classic symptoms of people with mild symptoms(Critical variation / range is somewhere betweenReply

INCLUDEPICTURE "http://e-school.biologia.gr/theme/image.php/fusion/core/1386199438/i/grade_incorrect" \* MERGEFORMATINET % To _____% of normal activity / normal activity)?

Hint: write two numbers separated by a dash, to show the variation, eg26-28.Feedback

The correct answer is: 10-25

Question68True


Text Question





After analysis of the above information, identified (recognized) the external team.

Hint: write with a capital letter and a number one of A1-A6, whatever you think right.Answer:


The correct answer is: A1

Question69True


Text Question





Identified (recognized) characters (a - f) that appear on both the internal and the external team.

Hint: write a small letter a of a - f, we thought right.Answer:


The correct answer is: f

Question70True


Text Question





Identified (recognized) the main characters are presented to all members of the internal team only.



The correct answer is: e

Question71Incorrect


Text Question





Identified (recognized) the last point of divergence in kladogramma formed using the appropriate character.



The correct answer is: b

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HTMLCheckbox"Attribute VB_Control = "DefaultOcxName26, 154, 103, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName251, 153, 104, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName242, 152, 105, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName231, 151, 106, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName213, 150, 107, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName202, 149, 108, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName191, 148, 109, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName181, 147, 110, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName161, 146, 111, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName151, 145, 112, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName141, 144, 113, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName136, 143, 114, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName114, 142, 115, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName104, 141, 116, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName93, 140, 117, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName86, 139, 118, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName65, 138, 119, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName53, 137, 120, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName41, 136, 121, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName35, 135, 122, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName214, 134, 123, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName118, 133, 124, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName134, 132, 125, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName133, 131, 126, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName132, 130, 127, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName131, 129, 128, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName130, 128, 129, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName128, 127, 130, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName127, 126, 131, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName126, 125, 132, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName125, 124, 133, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName124, 123, 134, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName122, 122, 135, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName121, 121, 136, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName120, 120, 137, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName1191, 119, 138, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName117, 118, 139, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName116, 117, 140, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName115, 116, 141, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName113, 115, 142, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName1121, 114, 143, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName111, 113, 144, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName110, 112, 145, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName108, 111, 146, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName107, 110, 147, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName106, 109, 148, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName105, 108, 149, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName103, 107, 150, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName102, 106, 151, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName101, 105, 152, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName100, 104, 153, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName99, 103, 154, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName98, 102, 155, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName97, 101, 156, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName96, 100, 157, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName95, 99, 158, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName94, 98, 159, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName92, 97, 160, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName91, 96, 161, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName90, 95, 162, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName89, 94, 163, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName88, 93, 164, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName87, 92, 165, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName85, 91, 166, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName84, 90, 167, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName83, 89, 168, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName82, 88, 169, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName81, 87, 170, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName80, 86, 171, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName79, 85, 172, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName78, 84, 173, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName76, 83, 174, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName751, 82, 175, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName74, 81, 176, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName73, 80, 177, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName72, 79, 178, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName70, 78, 179, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName69, 77, 180, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName68, 76, 181, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName67, 75, 182, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName661, 74, 183, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName64, 73, 184, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName63, 72, 185, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName62, 71, 186, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName61, 70, 187, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName60, 69, 188, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName58, 68, 189, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName57, 67, 190, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName56, 66, 191, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName551, 65, 192, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName54, 64, 193, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName52, 63, 194, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName51, 62, 195, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName50, 61, 196, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName48, 60, 197, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName471, 59, 198, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName461, 58, 199, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName45, 57, 200, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName44, 56, 201, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName43, 55, 202, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName42, 54, 203, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName40, 53, 204, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName39, 52, 205, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName38, 51, 206, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName37, 50, 207, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName36, 49, 208, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName341, 48, 209, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName33, 47, 210, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName32, 46, 211, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName30, 45, 212, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName29, 44, 213, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName28, 43, 214, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName27, 42, 215, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName25, 41, 216, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName241, 40, 217, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName23, 39, 218, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName212, 38, 219, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName201, 37, 220, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName19, 36, 221, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName18, 35, 222, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName16, 34, 223, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName15, 33, 224, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName14, 32, 225, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName13, 31, 226, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName12, 30, 227, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName10, 28, 229, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName9, 27, 230, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName8, 26, 231, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName7, 25, 232, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName6, 24, 233, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName5, 23, 234, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName410, 22, 235, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName312, 21, 236, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName210, 20, 237, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName135, 19, 238, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName75, 18, 239, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName66, 17, 240, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName55, 16, 241, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName46, 15, 242, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName310, 14, 243, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName211, 13, 244, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName119, 12, 245, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName47, 11, 246, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName34, 10, 247, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName24, 9, 248, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName112, 8, 249, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName20, 7, 250, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName31, 6, 251, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName21, 5, 252, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName11, 4, 253, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName4, 3, 254, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName3, 2, 255, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName2, 1, 256, MSForms, HTMLSelect"Attribute VB_Control = "DefaultOcxName1, 0, 257, MSForms, HTMLSelect"

_1456349165.unknownAttribute VB_Name = "ThisDocument"Attribute VB_Base = "1Normal.ThisDocument"Attribute VB_GlobalNameSpace = FalseAttribute VB_Creatable = FalseAttribute VB_PredeclaredId = TrueAttribute VB_Exposed = TrueAttribute VB_TemplateDerived = TrueAttribute VB_Customizable = TrueAttribute VB_Control = "DefaultOcxName462, 232, 25, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName441, 231, 26, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName421, 230, 27, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName401, 229, 28, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName381, 228, 29, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName361, 227, 30, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName342, 226, 31, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName321, 225, 32, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName302, 224, 33, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName283, 223, 34, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName262, 222, 35, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName244, 221, 36, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName222, 220, 37, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName205, 219, 38, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName184, 218, 39, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName164, 217, 40, MSForms, HTMLText"Attribute VB_Control = "DefaultOcxName144, 216, 41, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName1310, 215, 42, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName1211, 214, 43, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName1113, 213, 44, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName1011, 212, 45, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName912, 211, 46, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName710, 210, 47, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName612, 209, 48, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName511, 208, 49, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName413, 207, 50, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName315, 206, 51, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName220, 205, 52, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName145, 204, 53, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName233, 203, 54, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName221, 202, 55, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName217, 201, 56, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName204, 200, 57, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName193, 199, 58, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName183, 198, 59, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName171, 197, 60, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName163, 196, 61, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName153, 195, 62, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName138, 194, 63, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName1210, 193, 64, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName1112, 192, 65, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName1010, 191, 66, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName911, 190, 67, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName811, 189, 68, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName611, 188, 69, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName510, 187, 70, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName411, 186, 71, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName313, 185, 72, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName218, 184, 73, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName139, 183, 74, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName301, 182, 75, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName291, 181, 76, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName282, 180, 77, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName261, 179, 78, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName252, 178, 79, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName243, 177, 80, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName232, 176, 81, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName22, 175, 82, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName203, 174, 83, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName192, 173, 84, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName182, 172, 85, MSForms, HTMLOption"Attribute VB_Control = "DefaultOcxName162, 171, 86, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName152, 170, 87, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName142, 169, 88, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName137, 168, 89, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName123, 167, 90, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName1111, 166, 91, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName109, 165, 92, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName910, 164, 93, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName810, 163, 94, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName71, 162, 95, MSForms, HTMLCheckbox"Attribute VB_Control = "DefaultOcxName59, 161, 96, MSForms, HTMLOption"Attribute VB_Control = "DefaultO

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