i introductory material a. mathematical concepts scientific notation and significant figures
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I Introductory MaterialA. Mathematical Concepts
Scientific Notation andSignificant Figures
• Scientific Notation – A method devised to express very small and very large numbers.
– Based on powers of 10 e.g 123 billion is 123,000,000,000 expressed in scientific notation = 1.23 x 10 11
– 1.23 is called the coefficient•It must be greater than 1 and less than 10
– 10 11 is called the base. It is a power of 10. In this example the power of 10 is the 11
• Significant Figures– Tells how well known a measurement is.
– Using Significant Figures is a way to express the error in a measurement.
– The more significant figures the more accurate the measurement.
– The last number listed is the value that is uncertain•e.g.
– 2.3 value known to units, estimated to tenths
– 2.34 value known to tenths, estimated to hundredths
• Determining the number of Significant Figures– All non - zero numbers are significant– Zeros within a number are significant
•Both 40.05 and 3201 have 4 significant figures
– Zeros used to set the decimal point are NOT significant.•0.00235
– 3 significant figures
•47,000– 2 significant figures
» If you want it to have more, use scientific notation: 4.7000 x 104 denotes 5 significant figures
» Other possibility: 47,000. is sometimes used to denote 5 significant figures.
• Types of Numbers– Exact
•Numbers from counting•Conversions in the same system of measurement
•Defined conversions between different systems of measurement
•Have an infinite number of significant figures
– Inexact•Numbers from measurements•Conversions between different systems of measurement
•Have a finite number of significant figures
• Working with Significant Figures– When doing calculations, you can not gain or lose precision. The answer can only be as good as the least precise number
– Multiplication and Division•The number of significant figures in the answer depends on the number with the least number of significant digits.
•Determine the number of significant figures in: (16.300)(0.00235)/1.6300 – can only have 3 digits in the answer.
Determine the correct answer for:
(4.10)(3.023 x 109)/(1.5)
1. 8.26 x 109
2. 8.3 x 109
3. 8.263 x 109
4. 8.2628 x 109
– Addition and subtraction•The number of significant figures in the answer depends on the number with the least number of significant decimal places.
•Determine the answer: 4.72 + 0.653 + 9.2– 9.2 is only known to the tenths place, so the answer can only be known to the tenths place
4.72 0.653 9.214.573
14.6
What is the sum of 9 x 103 + 7.2 x 102?
A) 1 x 104
B) 9.7 x 103
C) 1.0 x 104
D) 9.72 x 103
9 x 103 known only to the thousands place
7.2 x 102 known to the tens place, so answer can only be known to the thousands place.
9000 720 9720 rounds to 1000010 000How many significant digits do you
have?210. x 103 = 1.0 x 104
• Rounding– When the answer contains too many digits, (more than the number of significant digits) the answer must be rounded to the correct number of significant digits.
– General Rules: If the digit after the last significant digit is•0 - 4, the significant digit stays the same
– 15.635 to the tenths place is 15.6
•6 - 9, the significant digit goes up– 15.625 to the units place is 16
•5, the significant digit goes to an even number– 15.625 to the hundredths place is 15.62 – While 15.635 to the hundredths place is 15.64– The reason for this is that in a series of calculations any error will be averaged out.
Error Analysis• Types of Error
– Determinate Error (ED)• Source of the error is known and can be determined.
• e.g. a watch that is ten minutes fast• Determinate error will most often effect accuracy
• It is the difference between the true value and the measured value
– Indeterminate Error (EI)• Source of the error is unknown or not controllable
• e.g. the vibration in a balance table• Indeterminate error will most often effect precision
• Can be expressed as:– Standard deviation – Variance– Coefficient of Variation– Tolerances
– Total Error• Sum of all the determinate and indeterminate error
• If the true value is known, this can be expressed as the percent relative error: %ER
• Describing Indeterminate Error– Population
• Complete set of individual data points in a study– The female population of the United states
– Sample• A specific subset of the population that is assumed to be representative of the whole– The female population of Newark, De.
– Members of the Data Set• Individual items (xi) within the sample of a known number (N) of items
% ER X
XtrueXtrue
x 100
• Measuring the Central Tendency of a Population or Sample– Mean
•Average value of all the members in the set•A population mean is the true or expected value; it is represented by the symbol µ
•A sample mean is the calculated average of the sample population; it is represented by the symbol x
•When a sample is used, we assume that x is a good approximation of µ
– Median•The middle value of all the members in the set
– Mode•The value that appears with the greatest frequency in the set
• Measuring the Spread of Data– Range
• Difference between the highest (largest) value and the lowest (smallest) value in the set
• Range = xHi - xLo
– Standard deviation( for population; s for sample)• Measure of how closely the individual values are clustered around the mean
– Variance• Square of the standard deviation• Variance = s2
s
X
Xi
2
i 1
n
n 1
– Accuracy•Closeness of population mean and sample mean
– Precision•Closeness of individual data points to each other
•Measured by range or standard deviation
• Determining and Describing Indeterminate Error (Uncertainty Statistics)– Standard deviationPopulation Sample
– Where xi is the data point, x is the sample mean, n is the number of data points
– Variance• s2
X
Xi
2
i 1
n
n
s
X
Xi
2
i 1
n
n 1
– Relative standard deviation(RSD) and Coefficient of Variation (CV)•Coefficient of Variation is a measure of the dispersion of a distribution
•It allows us to compare populations or samples that have different mean values
– Standard deviation of the mean,sm
RSD s
X
CV s
X x 100
sm s
n
• Ways of Representing DataData Table
• Ways of Representing DataData Table
DATA118.2
120.7
119.4
121.3
118.6
119.7
120.2
114.8
121.2
119.3
Collection of 10 data points
Histograma tabulation of the frequency of each measurement
• How do you decide if all you data should be used or is some can be ignored?
• Sort the data from low to highDATA
114.8
118.2
118.6
119.3
119.4
119.7
120.2
120.7
121.2
121.3
Look at the Range of the data:114.4 - 121.3Difference = 6.5
Apply Q TestLook at the gap between the smallest two numbers (Low Gap) and the largest two numbers (High Gap).Low Gap = 118.2 - 114.8 = 3.4High Gap = 121.3 - 121.2 = 0.1
1. Calculate the Gap to Range Ratio
Qcalc GapRange
Qcalc Low3.4
6.50.523
Qcalc High 0.1
6.50.015
2. Compare Qcalc to Q from the table (90% confidence)
Q Number of data points
0.76 4
0.64 5
0.56 6
0.51 7
0.47 8
0.44 9
0.41 10
If Qcalc < Qtable data CAN NOT be rejected
Qlo = 0.523Qhi = 0.016Qtable = 0.41 for 10 data points
So: Qlo > Qtable so can reject 114.8
Always make sure you mention the method used to reject data
Calculate mean, deviation and RSD
x = 119.8; s = 1.1; RSD = 0.009
118.2
118.6
119.3
119.4
119.7
120.2
120.7
121.2
121.3
Data now consists of 9 points.
x = 119.8
s
X
Xi
2
i 1
n
n 1
1.6
1.2
0.5
0.4
0.1
-0.4
-0.9
-1.4
-1.5
X - Xi(X - Xi)2
2.56
1.44
0.25
0.16
0.01
0.16
0.81
1.96
2.25
s
9.6
8ÊÊÊÊ1.095ÊÊ1.1
RSD s
X
Ê1.1
119.8ÊÊ0.009
x = 119.8
s = 1.1
RSD = s/ x = 0.009
119.8 ± 1.1119.8 ± 1 68.3 % of data in this range
119.8 ± 2
119.8 ± 3
95.8 % of data in this range99.7 % of data in this range
Confidence Limit• How certain you are that the true value [population mean] (µ) lies within a range around the sample mean(x)
• Confidence Limits are usually calculated at 90%, 95% or 99%
• Confidence Limits are calculated using the Student t table
DF Confidence
Limit
90% 95% 99%
1 6.31 12.7 63.7
2 2.92 4.3 9.92
3 2.35 3.18 5.84
4 2.13 2.78 4.60
5 2.02 2.57 4.03
6 1.94 2.45 3.71
7 1.90 2.36 3.50
8 1.86 2.31 3.36
10 1.81 2.23 3.17
15 1.75 2.13 2.95
20 1.73 2.09 2.85
40 1.68 2.02 2.70
inf 1.65 1.96 2.58
DF = degrees of freedomIt is equal to n - 1Where n is the number of data points
To calculate the Confidence Limit
CL() X t s
n
From our data, for the 9 data pointsx = 119.8; s = 1.1; DF = 8, t = 2.31
CL() 119.8 (2.31)(1.1)
9CL() 119.8 0.8
at 95% confidence:
119.0 120.6