)4HW (

Example (1):

Givens:

= 230 GPa

=

=

= 4.6 GPa

=

=

= 92 GPa

=

=

= 1.769 GPa

= 0.25

= 0.3

= 0.6

= 0.4

, , , :Calculate

= . + . = (0.4*230) + (0.6*4.6) = 94.76 GPa

=

=

= 7.565 GPa

= . + . = (0.3*0.6) + (0.25*0.4) = 0.28

=

=

= 2.911 GPa

Example (2):

Calculate: , , , for a unidirectional lamina for the

following material combinations: = 0.45 and = 0.55

1. E-glass and polyester (isophthalic)

From table 2.1:

E-glass has the following properties:

= 72.345 GPa

= 0.22

= 3.45 GPa

From table 2.4:

Polyester has the following properties:

= 3.4 GPa

= 0.38

= 75.9 GPa

= . + . = (0.55*72.345) + (0.45*3.4) = 41.32

=

=

= 7.145 GPa

= . + . = (0.38*0.55) + (0.22*0.45) = 0.308

=

=

= 6.047 GPa

2. S-glass and epoxy9310:

From table 2.1:

S-glass has the following properties:

= 85 GPa

= 0.22

= 4.8 GPa

From table 2.4:

Epoxy9310 has the following properties:

= 3.12 GPa

= 0.38

= 75.8 GPa

= . + . = (0.55*85) + (0.45*3.12) = 48.154

=

=

= 6.635 GPa

= . + . = (0.38*0.55) + (0.22*0.45) = 0.308

=

=

= 8.297 GPa

3. Carbon T300 and vinyl esler:

From table 2.1:

Carbon T300 has the following properties:

= 230 GPa

= 0.2

= 3.53 GPa

From table 2.4:

Vinyl esler has the following properties:

= 3.4 GPa

= 0.38

= 82.7 GPa

= . + . = (0.55*230) + (0.45*3.4) = 128.03

=

=

= 7.421 GPa

= . + . = (0.38*0.55) + (0.2*0.45) = 0.299

=

=

= 6.202 GPa

Example (3):

Select a matrix, fiber and fiber volume fraction to obtain

material with and

for different fibers and matrices we find that to By using matlab

get these conditions we use:

D-glass as fiber and Bismaleiraide as a matrix

Matlab code:

clear;clc;close all; Vm = 0.24; Vf = 1-Vm; Ef = 55; Em = 3.583; E1 = (Vf*Ef)+(Vm*Em) E2 = (Em*Ef)/((Vf*Em)+(Vm*Ef)) F = E1/E2

Output:

E1 = 42.6599

E2 = 12.3761

F = 3.4470 =