honors geometry section 5.2 use perpendicular bisectors

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Honors Geometry Section 5.2 Use Perpendicular Bisectors

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Page 1: Honors Geometry Section 5.2 Use Perpendicular Bisectors

Honors Geometry

Section 5.2

Use Perpendicular Bisectors

Page 2: Honors Geometry Section 5.2 Use Perpendicular Bisectors

Perpendicular Bisector

• A segment, ray, line, or plane that is perpendicular to a segment at its midpoint.

Page 3: Honors Geometry Section 5.2 Use Perpendicular Bisectors

Equidistant

•A point that is the same distance from each figure.

•Points on the perpendicular bisector of a segment are equidistant from the segment’s endpoints.

Page 4: Honors Geometry Section 5.2 Use Perpendicular Bisectors

THEOREM 5.2 Perpendicular Bisector Theorem

In a plane, if a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.

If is the bisector of , then CA = CB.

Page 5: Honors Geometry Section 5.2 Use Perpendicular Bisectors

THEOREM 5.3 Converse: Perpendicular Bisector Theorem

In a plane, if a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment.

If DA = DB, then D lies on the bisector of .

Page 6: Honors Geometry Section 5.2 Use Perpendicular Bisectors

EXAMPLE 1 Use the Perpendicular Bisector Theorem

AD = CD Perpendicular Bisector Theorem

3x + 145x =

7x =

BD is the perpendicular bisector of AC . Find AD.

AD = 5x = 5(7) = 35.

ALGEBRA

Page 7: Honors Geometry Section 5.2 Use Perpendicular Bisectors

EXAMPLE 2 Use perpendicular bisectors

SOLUTION

a. WX bisects YZ , so XY = XZ.

Because W is on the perpendicular bisector of YZ, WY = WZ by Theorem 5.2.

The diagram shows that VY = VZ = 25.

In the diagram, is the perpendicular bisector of

a. What segment lengths in the diagram are equal?

Page 8: Honors Geometry Section 5.2 Use Perpendicular Bisectors

EXAMPLE 2 Use perpendicular bisectors

b. Is V on WX ?

b. Because VY = VZ, V is equidistant from Y and Z. So, by the Converse of the Perpendicular Bisector Theorem, V is on the perpendicular bisector of YZ , which is WX .

In the diagram, is the perpendicular bisector of

Page 9: Honors Geometry Section 5.2 Use Perpendicular Bisectors

Concurrent• When three or more lines, rays, or

segments intersect in the same point.

Point of Concurrency• The point of intersection of the lines,

rays, or segments.

Page 10: Honors Geometry Section 5.2 Use Perpendicular Bisectors

THEOREM 5.4 Concurrency of Perpendicular Bisectors of a Triangle

The perpendicular bisectors of a triangle intersect at a point that is equidistant from the vertices of the triangle.

If are perpendicular bisectors, then PA = PB = PC.

Page 11: Honors Geometry Section 5.2 Use Perpendicular Bisectors

EXAMPLE 3Use the concurrency of perpendicular bisectors

FROZEN YOGURT

Three snack carts sell frozen yogurt from points A, B, and C outside a city. Each of the three carts is the same distance from the frozen yogurt distributor.

Find a location for the distributor that is equidistant from the three carts.

Page 12: Honors Geometry Section 5.2 Use Perpendicular Bisectors

EXAMPLE 3Use the concurrency of perpendicular bisectors

Theorem 5.4 shows you that you can find a point equidistant from three points by using the perpendicular bisectors of the triangle formed by those points.

Page 13: Honors Geometry Section 5.2 Use Perpendicular Bisectors

EXAMPLE 3Use the concurrency of perpendicular bisectors

Copy the positions of points A, B, and C and connect those points to draw ∆ABC. Then use a ruler and protractor to draw the three perpendicular bisectors of ∆ABC. The point of concurrency D is the location of the distributor.

Page 14: Honors Geometry Section 5.2 Use Perpendicular Bisectors

• The point of concurrency of the three perpendicular bisectors of a triangle.

• The circumcenter P is equidistant from the three vertices, so P is the center of a circle that passes through all three vertices.

Circumcenter

Page 15: Honors Geometry Section 5.2 Use Perpendicular Bisectors

• The location of P depends on the type of triangle.