homology representations of the...
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Homology Representations of the SymmetricGroups1
Netanel Friedenberg
October 8, 2014
1This material is based upon work supported by the National ScienceFoundation under agreement No. DMS-1055897. Any opinions, findings andconclusions or recommendations expressed in this material are those of theauthors and do not necessarily reflect the views of the National ScienceFoundation
Group Actions
An action of a group G on a set A is a group homomorphismϕ : G → SA, or
a multiplication G × A→ A, (g , x) 7→ gx such that ∀x ∈ Aand ∀g , h ∈ G
1Gx = x and(gh)x = g(hx).
Group Actions
An action of a group G on a set A is a group homomorphismϕ : G → SA, or
a multiplication G × A→ A, (g , x) 7→ gx such that ∀x ∈ Aand ∀g , h ∈ G
1Gx = x and(gh)x = g(hx).
Group Actions
An action of a group G on a set A is a group homomorphismϕ : G → SA, or
a multiplication G × A→ A, (g , x) 7→ gx such that ∀x ∈ Aand ∀g , h ∈ G
1Gx = x and(gh)x = g(hx).
Group Representations
Representation of G : A group homomorphismX : G → GLd(C).
Equivalently, G -module: A vector space V , with amultiplication G × V → V , (g , v) 7→ v, such that(∀v,w ∈ V )(∀c , d ∈ C)(∀g , h ∈ G ),
1Gv = v.(gh)v = g(hv).g(cv + dw) = c(gv) + d(gw).
Group Representations
Representation of G : A group homomorphismX : G → GLd(C).
Equivalently, G -module: A vector space V , with amultiplication G × V → V , (g , v) 7→ v, such that(∀v,w ∈ V )(∀c , d ∈ C)(∀g , h ∈ G ),
1Gv = v.(gh)v = g(hv).g(cv + dw) = c(gv) + d(gw).
Group Representations
Representation of G : A group homomorphismX : G → GLd(C).
Equivalently, G -module: A vector space V , with amultiplication G × V → V , (g , v) 7→ v, such that(∀v,w ∈ V )(∀c , d ∈ C)(∀g , h ∈ G ),
1Gv = v.(gh)v = g(hv).g(cv + dw) = c(gv) + d(gw).
An Example: Permutation Representations
Say G acts on A. The permutation representation associated withthis action is:
Vector space V = CA.
Multiplication: g(r1a1 + · · ·+ rmam) = r1(ga1) + · · ·+ rm(gam)(ri ∈ C, ai ∈ A, g ∈ G ).
An Example: Permutation Representations
Say G acts on A. The permutation representation associated withthis action is:
Vector space V = CA.
Multiplication: g(r1a1 + · · ·+ rmam) = r1(ga1) + · · ·+ rm(gam)(ri ∈ C, ai ∈ A, g ∈ G ).
An Example: Permutation Representations
Say G acts on A. The permutation representation associated withthis action is:
Vector space V = CA.
Multiplication: g(r1a1 + · · ·+ rmam) = r1(ga1) + · · ·+ rm(gam)(ri ∈ C, ai ∈ A, g ∈ G ).
Homology
Chain complex: (C·, ∂·) a sequence
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
of vector spaces Ck (“chain spaces”) and lineartransformations ∂k : Ck → Ck−1 (“boundary maps”) suchthat ∂k ◦ ∂k+1 = 0 (∀k ∈ Z).
Often omit subscripts: ∂2 = 0.
∂k ◦ ∂k+1 = 0 ⇐⇒ Im(∂k+1) ⊂ Ker(∂k).
Homology spaces: Hk :=Ker(∂k)
Im(∂k+1)
Homology
Chain complex: (C·, ∂·) a sequence
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
of vector spaces Ck (“chain spaces”) and lineartransformations ∂k : Ck → Ck−1 (“boundary maps”) suchthat ∂k ◦ ∂k+1 = 0 (∀k ∈ Z).
Often omit subscripts: ∂2 = 0.
∂k ◦ ∂k+1 = 0 ⇐⇒ Im(∂k+1) ⊂ Ker(∂k).
Homology spaces: Hk :=Ker(∂k)
Im(∂k+1)
Homology
Chain complex: (C·, ∂·) a sequence
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
of vector spaces Ck (“chain spaces”) and lineartransformations ∂k : Ck → Ck−1 (“boundary maps”) suchthat ∂k ◦ ∂k+1 = 0 (∀k ∈ Z).
Often omit subscripts: ∂2 = 0.
∂k ◦ ∂k+1 = 0 ⇐⇒ Im(∂k+1) ⊂ Ker(∂k).
Homology spaces: Hk :=Ker(∂k)
Im(∂k+1)
Homology
Chain complex: (C·, ∂·) a sequence
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
of vector spaces Ck (“chain spaces”) and lineartransformations ∂k : Ck → Ck−1 (“boundary maps”) suchthat ∂k ◦ ∂k+1 = 0 (∀k ∈ Z).
Often omit subscripts: ∂2 = 0.
∂k ◦ ∂k+1 = 0 ⇐⇒ Im(∂k+1) ⊂ Ker(∂k).
Homology spaces: Hk :=Ker(∂k)
Im(∂k+1)
Example: Homology of a triangle
We assign a chain complex to the boundary of triangle ∆ABC :
Let C1 = span(AB,BC ,CA), C0 = span(A,B,C ), andC−1 = span(∅).
Boundary map: “oriented boundary”. That is,
∂1(AB) = B − A, ∂1(BC ) = C − B, ∂1(CA) = A− C ,∂0(A) = ∂0(B) = ∂0(C ) = 1 · ∅,∂−1(∅) = 0.
Example: Homology of a triangle
We assign a chain complex to the boundary of triangle ∆ABC :
Let C1 = span(AB,BC ,CA), C0 = span(A,B,C ), andC−1 = span(∅).
Boundary map: “oriented boundary”. That is,
∂1(AB) = B − A, ∂1(BC ) = C − B, ∂1(CA) = A− C ,∂0(A) = ∂0(B) = ∂0(C ) = 1 · ∅,∂−1(∅) = 0.
Example: Homology of a triangle
We assign a chain complex to the boundary of triangle ∆ABC :
Let C1 = span(AB,BC ,CA), C0 = span(A,B,C ), andC−1 = span(∅).
Boundary map: “oriented boundary”. That is,
∂1(AB) = B − A, ∂1(BC ) = C − B, ∂1(CA) = A− C ,∂0(A) = ∂0(B) = ∂0(C ) = 1 · ∅,∂−1(∅) = 0.
Example: Homology of a triangle
We assign a chain complex to the boundary of triangle ∆ABC :
Let C1 = span(AB,BC ,CA), C0 = span(A,B,C ), andC−1 = span(∅).
Boundary map: “oriented boundary”. That is,
∂1(AB) = B − A, ∂1(BC ) = C − B, ∂1(CA) = A− C ,
∂0(A) = ∂0(B) = ∂0(C ) = 1 · ∅,∂−1(∅) = 0.
Example: Homology of a triangle
We assign a chain complex to the boundary of triangle ∆ABC :
Let C1 = span(AB,BC ,CA), C0 = span(A,B,C ), andC−1 = span(∅).
Boundary map: “oriented boundary”. That is,
∂1(AB) = B − A, ∂1(BC ) = C − B, ∂1(CA) = A− C ,∂0(A) = ∂0(B) = ∂0(C ) = 1 · ∅,
∂−1(∅) = 0.
Example: Homology of a triangle
We assign a chain complex to the boundary of triangle ∆ABC :
Let C1 = span(AB,BC ,CA), C0 = span(A,B,C ), andC−1 = span(∅).
Boundary map: “oriented boundary”. That is,
∂1(AB) = B − A, ∂1(BC ) = C − B, ∂1(CA) = A− C ,∂0(A) = ∂0(B) = ∂0(C ) = 1 · ∅,∂−1(∅) = 0.
Example: Homology of a triangle
It is easy to check that in this case we have
ker(∂1) = span(AB + BC + CA)Im(∂1) = {aA + bB + cC ∈ C0|a + b + c = 0} = ker(∂0)Im(∂0) = C−1 = ker(∂−1)
So the homology spaces are H1∼= C, H0
∼= 0, and H−1 ∼= 0.
Generalization: Simplicial homology of a simplicial complex.
Further generalization (via category theory): Simplicial sets.
Example: Homology of a triangle
It is easy to check that in this case we have
ker(∂1) = span(AB + BC + CA)Im(∂1) = {aA + bB + cC ∈ C0|a + b + c = 0} = ker(∂0)Im(∂0) = C−1 = ker(∂−1)
So the homology spaces are H1∼= C, H0
∼= 0, and H−1 ∼= 0.
Generalization: Simplicial homology of a simplicial complex.
Further generalization (via category theory): Simplicial sets.
Example: Homology of a triangle
It is easy to check that in this case we have
ker(∂1) = span(AB + BC + CA)Im(∂1) = {aA + bB + cC ∈ C0|a + b + c = 0} = ker(∂0)Im(∂0) = C−1 = ker(∂−1)
So the homology spaces are H1∼= C, H0
∼= 0, and H−1 ∼= 0.
Generalization: Simplicial homology of a simplicial complex.
Further generalization (via category theory): Simplicial sets.
Example: Homology of a triangle
It is easy to check that in this case we have
ker(∂1) = span(AB + BC + CA)Im(∂1) = {aA + bB + cC ∈ C0|a + b + c = 0} = ker(∂0)Im(∂0) = C−1 = ker(∂−1)
So the homology spaces are H1∼= C, H0
∼= 0, and H−1 ∼= 0.
Generalization: Simplicial homology of a simplicial complex.
Further generalization (via category theory): Simplicial sets.
Homology Representations
Say G is a group and
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
is a chain complex where the chain spaces are also G -modules.
Suppose further: multiplication by group elements commuteswith boundary maps.
That is, ∂(gv) = g∂(v).
Then the homology spaces become G -modules in a naturalway.
Homology Representations
Say G is a group and
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
is a chain complex where the chain spaces are also G -modules.
Suppose further: multiplication by group elements commuteswith boundary maps.
That is, ∂(gv) = g∂(v).
Then the homology spaces become G -modules in a naturalway.
Homology Representations
Say G is a group and
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
is a chain complex where the chain spaces are also G -modules.
Suppose further: multiplication by group elements commuteswith boundary maps.
That is, ∂(gv) = g∂(v).
Then the homology spaces become G -modules in a naturalway.
Homology Representations
Say G is a group and
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
is a chain complex where the chain spaces are also G -modules.
Suppose further: multiplication by group elements commuteswith boundary maps.
That is, ∂(gv) = g∂(v).
Then the homology spaces become G -modules in a naturalway.
Example: Homology of a triangle
Chain complex from before, based on the triangle.S{A,B,C} ∼= S3 acts on the triangle by permuting its vertices.
So S3 acts on the chain spaces.
H1 = span(AB + BC + CA). While it seems that S3 actstrivially, we are concerned with orientation, so, for example,BA = −AB.
It turns out thatg(AB + BC + CA) = sign(g)(AB + BC + CA), where
sign(g) =
{1 if g is an even permutation
−1 if g is an odd permutation.
Example: Homology of a triangle
Chain complex from before, based on the triangle.S{A,B,C} ∼= S3 acts on the triangle by permuting its vertices.
So S3 acts on the chain spaces.
H1 = span(AB + BC + CA). While it seems that S3 actstrivially, we are concerned with orientation, so, for example,BA = −AB.
It turns out thatg(AB + BC + CA) = sign(g)(AB + BC + CA), where
sign(g) =
{1 if g is an even permutation
−1 if g is an odd permutation.
Example: Homology of a triangle
Chain complex from before, based on the triangle.S{A,B,C} ∼= S3 acts on the triangle by permuting its vertices.
So S3 acts on the chain spaces.
H1 = span(AB + BC + CA). While it seems that S3 actstrivially, we are concerned with orientation, so, for example,BA = −AB.
It turns out thatg(AB + BC + CA) = sign(g)(AB + BC + CA), where
sign(g) =
{1 if g is an even permutation
−1 if g is an odd permutation.
Example: Homology of a triangle
Chain complex from before, based on the triangle.S{A,B,C} ∼= S3 acts on the triangle by permuting its vertices.
So S3 acts on the chain spaces.
H1 = span(AB + BC + CA). While it seems that S3 actstrivially, we are concerned with orientation, so, for example,BA = −AB.
It turns out thatg(AB + BC + CA) = sign(g)(AB + BC + CA), where
sign(g) =
{1 if g is an even permutation
−1 if g is an odd permutation.
N-Complexes
In a paper in 1996, Kapranov introduced the notion of anN-complex.
An N-complex (C·, ∂·) is a sequence
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
of vector spaces Ck and linear transformations∂k : Ck → Ck−1 such that ∂N = 0.
So a 2-complex is a chain complex.
Choose k ∈ Z, 1 ≤ i < N. Then
· · · ∂ i
−→ Ck+N−i∂N−i
−→ Ck∂ i
−→ Ck−i∂N−i
−→ · · ·
is a chain complex. The homology at Ck is
Hk,i =ker(∂ i : Ck → Ck−i )
Im(∂N−i : Ck+N−i → Ck)
N-Complexes
In a paper in 1996, Kapranov introduced the notion of anN-complex.
An N-complex (C·, ∂·) is a sequence
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
of vector spaces Ck and linear transformations∂k : Ck → Ck−1 such that ∂N = 0.
So a 2-complex is a chain complex.
Choose k ∈ Z, 1 ≤ i < N. Then
· · · ∂ i
−→ Ck+N−i∂N−i
−→ Ck∂ i
−→ Ck−i∂N−i
−→ · · ·
is a chain complex. The homology at Ck is
Hk,i =ker(∂ i : Ck → Ck−i )
Im(∂N−i : Ck+N−i → Ck)
N-Complexes
In a paper in 1996, Kapranov introduced the notion of anN-complex.
An N-complex (C·, ∂·) is a sequence
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
of vector spaces Ck and linear transformations∂k : Ck → Ck−1 such that ∂N = 0.
So a 2-complex is a chain complex.
Choose k ∈ Z, 1 ≤ i < N. Then
· · · ∂ i
−→ Ck+N−i∂N−i
−→ Ck∂ i
−→ Ck−i∂N−i
−→ · · ·
is a chain complex. The homology at Ck is
Hk,i =ker(∂ i : Ck → Ck−i )
Im(∂N−i : Ck+N−i → Ck)
N-Complexes
In a paper in 1996, Kapranov introduced the notion of anN-complex.
An N-complex (C·, ∂·) is a sequence
· · · ∂n+1−→ Cn∂n−→ Cn−1
∂n−1−→ · · · ∂1−→ C0∂0−→ C−1
∂−1−→ · · ·
of vector spaces Ck and linear transformations∂k : Ck → Ck−1 such that ∂N = 0.
So a 2-complex is a chain complex.
Choose k ∈ Z, 1 ≤ i < N. Then
· · · ∂ i
−→ Ck+N−i∂N−i
−→ Ck∂ i
−→ Ck−i∂N−i
−→ · · ·
is a chain complex. The homology at Ck is
Hk,i =ker(∂ i : Ck → Ck−i )
Im(∂N−i : Ck+N−i → Ck)
N-Complexes
Kapranov shows that given a simplicial set, and ω an Nth rootof unity, using powers of ω as weights in the sums defining theboundary maps yields an N-complex associated to thesimplicial set.
In fact, the usual chain complex associated to the simplicialset is just the case N = 2, ω = −1.
N-Complexes
Kapranov shows that given a simplicial set, and ω an Nth rootof unity, using powers of ω as weights in the sums defining theboundary maps yields an N-complex associated to thesimplicial set.
In fact, the usual chain complex associated to the simplicialset is just the case N = 2, ω = −1.
Word Complexes
Inspired by Kapranov’s work, we constructed the followingN-complexes. Fix ω, an Nth root of unity, and n ∈ N
Wk , spanned by k-tuples from {1, . . . , n}.Boundary map:
∂k((a1, . . . , ak)) =k∑
i=1
ωi−1(a1, . . . , ai , . . . , ak) (ai indicates
that ai has been removed from the list).
(W·, ∂·) is an N-complex, the (total) word complex.
Ik , subspace of Wk spanned by k-tuples with no repeats.Then (I·, ∂·) is also an N-complex, the injective word complex.
Word Complexes
Inspired by Kapranov’s work, we constructed the followingN-complexes. Fix ω, an Nth root of unity, and n ∈ N
Wk , spanned by k-tuples from {1, . . . , n}.
Boundary map:
∂k((a1, . . . , ak)) =k∑
i=1
ωi−1(a1, . . . , ai , . . . , ak) (ai indicates
that ai has been removed from the list).
(W·, ∂·) is an N-complex, the (total) word complex.
Ik , subspace of Wk spanned by k-tuples with no repeats.Then (I·, ∂·) is also an N-complex, the injective word complex.
Word Complexes
Inspired by Kapranov’s work, we constructed the followingN-complexes. Fix ω, an Nth root of unity, and n ∈ N
Wk , spanned by k-tuples from {1, . . . , n}.Boundary map:
∂k((a1, . . . , ak)) =k∑
i=1
ωi−1(a1, . . . , ai , . . . , ak) (ai indicates
that ai has been removed from the list).
(W·, ∂·) is an N-complex, the (total) word complex.
Ik , subspace of Wk spanned by k-tuples with no repeats.Then (I·, ∂·) is also an N-complex, the injective word complex.
Word Complexes
Inspired by Kapranov’s work, we constructed the followingN-complexes. Fix ω, an Nth root of unity, and n ∈ N
Wk , spanned by k-tuples from {1, . . . , n}.Boundary map:
∂k((a1, . . . , ak)) =k∑
i=1
ωi−1(a1, . . . , ai , . . . , ak) (ai indicates
that ai has been removed from the list).
(W·, ∂·) is an N-complex, the (total) word complex.
Ik , subspace of Wk spanned by k-tuples with no repeats.Then (I·, ∂·) is also an N-complex, the injective word complex.
Word Complexes
Inspired by Kapranov’s work, we constructed the followingN-complexes. Fix ω, an Nth root of unity, and n ∈ N
Wk , spanned by k-tuples from {1, . . . , n}.Boundary map:
∂k((a1, . . . , ak)) =k∑
i=1
ωi−1(a1, . . . , ai , . . . , ak) (ai indicates
that ai has been removed from the list).
(W·, ∂·) is an N-complex, the (total) word complex.
Ik , subspace of Wk spanned by k-tuples with no repeats.Then (I·, ∂·) is also an N-complex, the injective word complex.
Word Complexes
Sn acts on the collection of (injective) k-tuples of thenumbers 1, . . . , n: Wk and Ik are permutation modules for Sn.
This action of Sn commutes with the boundary maps ∂k , soHk,i (W ) and Hk,i (I ) are Sn-modules as well.
Word Complexes
Sn acts on the collection of (injective) k-tuples of thenumbers 1, . . . , n: Wk and Ik are permutation modules for Sn.
This action of Sn commutes with the boundary maps ∂k , soHk,i (W ) and Hk,i (I ) are Sn-modules as well.
Total Word Complex
Theorem:
The complex (W·, ∂·) has trivial homology. That is, forall k and all 0 < i < N, Hk,i (W ) = 0.
Total Word Complex
Theorem: The complex (W·, ∂·) has trivial homology. That is, forall k and all 0 < i < N, Hk,i (W ) = 0.
Injective Word Complex
Conjecture: For the injective word complex, all of the homology is“concentrated towards the top”.
Specifically, we conjecture thatfor any of the chain complexes
· · · ∂ i
−→ Ik+N−i∂N−i
−→ Ik∂ i
−→ Ik−i∂N−i
−→ · · · ,
all of the homology spaces except the top one are the zero space,unless the sequence starts
In∂−→ In−1
∂N−1
−→ · · · ,
in which case the top two homology spaces may be nontrivial.
Injective Word Complex
Conjecture: For the injective word complex, all of the homology is“concentrated towards the top”. Specifically, we conjecture thatfor any of the chain complexes
· · · ∂ i
−→ Ik+N−i∂N−i
−→ Ik∂ i
−→ Ik−i∂N−i
−→ · · · ,
all of the homology spaces except the top one are the zero space,unless the sequence starts
In∂−→ In−1
∂N−1
−→ · · · ,
in which case the top two homology spaces may be nontrivial.
Injective Word Complex
Theorem: If the homology is concentrated as conjectured, then thecollection of these homology modules for all n breaks up naturallyinto sequences of representations (Xn)∞n=1 (where each Xn is arepresentation of Sn) that are what Stanley, in his EnumerativeCombinatorics, calls elementary sequences. Moreover, the caseN = 2, ω = −1 gives exactly the sequence of representations thathe gives as an example there.
Current Work
We are currently trying to use methods of algebraic discreteMorse theory as well as methods involving spectral sequencesto prove our conjecture about the concentration of thehomology of the injective word complex.
We are also using the zig-zag lemma, applied to the triple I ,W , and the quotient complex W /I , to convert the conjectureto an equivalent conjecture about W /I , the “non-injectiveword complex”, which seems to behave better with respect tothe manipulations necessary for the algebraic discrete Morsetheory, and opens up more possibilities for the use of spectralsequences.
Current Work
We are currently trying to use methods of algebraic discreteMorse theory as well as methods involving spectral sequencesto prove our conjecture about the concentration of thehomology of the injective word complex.
We are also using the zig-zag lemma, applied to the triple I ,W , and the quotient complex W /I , to convert the conjectureto an equivalent conjecture about W /I , the “non-injectiveword complex”, which seems to behave better with respect tothe manipulations necessary for the algebraic discrete Morsetheory, and opens up more possibilities for the use of spectralsequences.
Current Work
We are currently trying to use methods of algebraic discreteMorse theory as well as methods involving spectral sequencesto prove our conjecture about the concentration of thehomology of the injective word complex.
We are also using the zig-zag lemma, applied to the triple I ,W , and the quotient complex W /I , to convert the conjectureto an equivalent conjecture about W /I , the “non-injectiveword complex”, which seems to behave better with respect tothe manipulations necessary for the algebraic discrete Morsetheory, and opens up more possibilities for the use of spectralsequences.