holt algebra 1 8-5 factoring special products factor the difference of two squares. objectives
TRANSCRIPT
Holt Algebra 1
8-5 Factoring Special Products
Factor the difference of two squares.
Objectives
Holt Algebra 1
8-5 Factoring Special Products
The difference of two squares has the form a2 – b2. The difference of two squares can be written as the product (a + b)(a – b). You can use this pattern to factor some polynomials.
A polynomial is a difference of two squares if:
•There are two terms, one subtracted from the other.
• Both terms are perfect squares.
4x2 – 9
2x 2x 3 3
Holt Algebra 1
8-5 Factoring Special Products
Holt Algebra 1
8-5 Factoring Special Products
Recognize a difference of two squares:
the coefficients of variable terms are perfect squares
powers on variable terms are even,
and constants are perfect squares.
Reading Math
Holt Algebra 1
8-5 Factoring Special Products
Example 3A: Recognizing and Factoring the Difference of Two Squares
Determine whether each binomial is a difference of two squares. If so, factor. If not, explain.
3p2 – 9q4
3p2 – 9q4
3q2 3q2 3p2 is not a perfect square.
3p2 – 9q4 is not the difference of two squares because 3p2 is not a perfect square.
Holt Algebra 1
8-5 Factoring Special Products
Example 3B: Recognizing and Factoring the Difference of Two Squares
Determine whether each binomial is a difference of two squares. If so, factor. If not, explain.
100x2 – 4y2
Write the polynomial as (a + b)(a – b).
a = 10x, b = 2y
The polynomial is a difference of two squares.
100x2 – 4y2
2y 2y10x 10x
(10x)2 – (2y)2 (10x + 2y)(10x – 2y)
100x2 – 4y2 = (10x + 2y)(10x – 2y)
Holt Algebra 1
8-5 Factoring Special Products
Example 3C: Recognizing and Factoring the Difference of Two Squares
Determine whether each binomial is a difference of two squares. If so, factor. If not, explain.
x4 – 25y6
Write the polynomial as (a + b)(a – b).
a = x2, b = 5y3
The polynomial is a difference of two squares.
(x2)2 – (5y3)2
(x2 + 5y3)(x2 – 5y3)
x4 – 25y6 = (x2 + 5y3)(x2 – 5y3)
5y3 5y3x2 x2
x4 – 25y6
Holt Algebra 1
8-5 Factoring Special Products
Check It Out! Example 3a
Determine whether each binomial is a difference of two squares. If so, factor. If not, explain.
1 – 4x2
Write the polynomial as (a + b)(a – b).
a = 1, b = 2x
The polynomial is a difference of two squares.
(1) – (2x)2 (1 + 2x)(1 – 2x)
1 – 4x2 = (1 + 2x)(1 – 2x)
2x 2x1 1
1 – 4x2
Holt Algebra 1
8-5 Factoring Special Products
Check It Out! Example 3b
Determine whether each binomial is a difference of two squares. If so, factor. If not, explain.
p8 – 49q6
Write the polynomial as (a + b)(a – b).
a = p4, b = 7q3
The polynomial is a difference of two squares.
(p4)2 – (7q3)2 (p4 + 7q3)(p4 – 7q3)
p8 – 49q6 = (p4 + 7q3)(p4 – 7q3)
7q3 7q3●p4 p4●
p8 – 49q6
Holt Algebra 1
8-5 Factoring Special Products
Check It Out! Example 3c
Determine whether each binomial is a difference of two squares. If so, factor. If not, explain.
16x2 – 4y5
4x 4x 4y5 is not a perfect square.
16x2 – 4y5 is not the difference of two squares because 4y5 is not a perfect square.
16x2 – 4y5
Holt Algebra 1
8-5 Factoring Special Products
Lesson Quiz: Part II
Determine whether the binomial is a difference of two squares. If so, factor. If not, explain.
5. 9x2 – 144y4
6. 30x2 – 64y2
7. 121x2 – 4y8
(3x + 12y2)(3x – 12y2)
(11x + 2y4)(11x – 2y4)
Not a difference of two squares; 30x2 is not a perfect square