Highland Science Department

Percentage Yield

Highland Science Department

Percentage Yield

Percentage Yield: a comparison of the mass of product actually obtained in an experiment to the amount theoretically possible.

Highland Science Department

Percentage Yield

Percentage Yield: a comparison of the mass of product actually obtained in an experiment to the amount theoretically possible.

-it's rare to produce the same amount of product as predicted by the balanced chemical equation

Highland Science Department

Percentage Yield

Percentage Yield: a comparison of the mass of product actually obtained in an experiment to the amount theoretically possible.

-it's rare to produce the same amount of product as predicted by the balanced chemical equation

Reasons: -side reactions-reaction does not go to completion-loss of product during separation

Highland Science Department

Percentage Yield

% yield = actual yield x 100% theoretical yield

Highland Science Department

Percentage Yielde.g. 1. If 189 g of lead (II) sulfide was actually obtained in a reaction for which the theoretical yield was 239 g, calculate the percentage yield.

Highland Science Department

Percentage Yielde.g. 1. If 189 g of lead (II) sulfide was actually obtained in a reaction for which the theoretical yield was 239 g, calculate the percentage yield.

G: actual yield of PbS = 189 gtheoretical yield of PbS = 239 g

U: % yieldS: % yield = actual yield x 100%

theoretical yield

Highland Science Department

Percentage Yielde.g. 1. If 189 g of lead (II) sulfide was actually obtained in a reaction for which the theoretical yield was 239 g, calculate the percentage yield.

G: actual yield of PbS = 189 gtheoretical yield of PbS = 239 g

U: % yieldS: % yield = actual yield x 100%

theoretical yieldS: % yield = 189 g x 100%

239 g= 79.1 %

Highland Science Department

Percentage Yielde.g. 2. If 8.30 g of sodium and 14.0 g of chlorine are heated together, a total of 19.5 g of sodium chloride is isolated. Determine the percentage yield of sodium chloride.

Highland Science Department

Percentage Yielde.g. 2. If 8.30 g of sodium and 14.0 g of chlorine are heated together, a total of 19.5 g of sodium chloride is isolated. Determine the percentage yield of sodium chloride.G: 2Na(s) + Cl2(g) 2NaCl(s) MM Cl2

mass of Na = 8.30 g Cl = 2 x 35.4 = 70.8 gmass of Cl2 = 19.5 g MM NaClactual yield of NaCl = 19.5 g Na = 1 x 23.0 = 23.0

Cl = 1 x 35.4 = 35.458.4 g

Highland Science Department

Percentage Yielde.g. 2. If 8.30 g of sodium and 14.0 g of chlorine are heated together, a total of 19.5 g of sodium chloride is isolated. Determine the percentage yield of sodium chloride.G: 2Na(s) + Cl2(g) 2NaCl(s) M.M. Cl2

mass of Na = 8.30 g Cl = 2 x 35.4 = 70.8 gmass of Cl2 = 19.5 g M.M. NaClactual yield of NaCl = 19.5 g Na = 1 x 23.0 = 23.0

Cl = 1 x 35.4 = 35.4U: percentage yield 58.4 g

S: 1: limiting reactant = mass ÷ lowest #M.M.

2: limiting limiting NaCl NaClreactant reactant moles massmass moles

3: % yield = actual mass x 100%theoretical mass

Highland Science Department

Percentage Yielde.g. 2. If 8.30 g of sodium and 14.0 g of chlorine are heated together, a total of 19.5 g of sodium chloride is isolated. Determine the percentage yield of sodium chloride.S: Na amount = 8.30g = 0.361 mol

Cl2 amount = 14.0g = 0.198 mol

Highland Science Department

Percentage Yielde.g. 2. If 8.30 g of sodium and 14.0 g of chlorine are heated together, a total of 19.5 g of sodium chloride is isolated. Determine the percentage yield of sodium chloride.S: Na amount = 8.30g = 0.361 mol = 1.82

0.198 mol

Cl2 amount = 14.0g = 0.198 mol = 10.198 mol

Highland Science Department

Percentage Yielde.g. 2. If 8.30 g of sodium and 14.0 g of chlorine are heated together, a total of 19.5 g of sodium chloride is isolated. Determine the percentage yield of sodium chloride.S: Na amount = 8.30g = 0.361 mol = 1.82 < 2

0.198 mol limiting

Cl2 amount = 14.0g = 0.198 mol = 1 = 1 excess0.198 mol

Highland Science Department

Percentage Yielde.g. 2. If 8.30 g of sodium and 14.0 g of chlorine are heated together, a total of 19.5 g of sodium chloride is isolated. Determine the percentage yield of sodium chloride.S: Na amount = 8.30g = 0.361 mol = 1.82 < 2

0.198 mol limiting

Cl2 amount = 14.0g = 0.198 mol = 1 = 1 excess0.198 mol

theoretical = 8.30 g Namass NaCl

= 8.30 x 58.4 g NaCl23.0

= 21.1 g

Highland Science Department

Percentage Yielde.g. 2. If 8.30 g of sodium and 14.0 g of chlorine are heated together, a total of 19.5 g of sodium chloride is isolated. Determine the percentage yield of sodium chloride.S: Na amount = 8.30g = 0.361 mol = 1.82 < 2

0.198 mol limiting

Cl2 amount = 14.0g = 0.198 mol = 1 = 1 excess0.198 mol

theoretical = 8.30 g Namass NaCl

= 8.30 x 58.4 g NaCl23.0

= 21.1 g% yield = 19.5 g x 100%

21.1 g= 92.4 %