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UNIVERSAL PUBLIC SCHOOLSECOND TERMINAL EXAMINATION, 2012

Subject: Mathematics Maximum marks:100

Class:5th Allotted time:120 minutes

Q1. Match the items of A with relevant items of B. (More than one match may exist. ) 5X3=15

Column A Column B

(a) Even number (p) 31

(b) Odd number (q) 87

(c) Prime number (r) 28

(d) Composite number (s) ||-2|-4|

(e) Perfect number (t) 61

Q2. Fill in the blanks: 5X3=15

(a) G.C.D of co-prime numbers would be __________.

(b) LCM & HCF of X and Y are 23 and 1449 respectively. If X=161,Y=__________.

(c) BODMAS stands for _______________________________________________.(d) 4 greater than thrice of X is 6040.value of X is__________.

(e) (54+t) is divisible by 7.Minimum value of t to meet the requirement is_______. (t >0)

Q3. By using divisibility test criterion, examine whether 29700 is divisible by 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 13 and

25 or not. (Examine individually & show each and every step clearly.) 15

Q4. Find the least number of 4 digit which when divided by 4, 6, 8 and 10 leaves in each case a remainder 3. 5

Q5. Using concept of number line subtract (-3) from (-4). 4

Q6. If a=2, b=3, c= 4. Find the value of {2a+3b+4c-(a+2b+3c)} / {3a+4b+5c-(-a+c)} 3

Q7. Enlist all prime numbers which are greater than 30 and less than 50. 2.5

Q8. 787658376__5 is divisible by 9. Find the missing digit. State whether it is prime or composite. 2.5

Q9. Do as directed. (Attempt any five ) 5X6=30

(i) Find the prime factorization of 1260 and give the answer in exponential form.

(ii) Find the G.C.D. of 219, 2628, 2190 and 8833 using division method.

(iii) Simplify the expression (-18)+(-6)2-[(-7)X(-4)-{2-(3-5)}].(iv) An operation * for integers a and b is defined as a*b=(ab)+(a-b)+(a+b)+(a+4)

Compute: (a) (-3)*(-5)

(b) (+4)*(-8)

(v) Find out the sum of expressions x+xy2+y+ax2, 2ax2 - 2y+3x, -5xy2 ax2+2y and -5x+3y-2ax2.

(vi) Solve the linear equation (16x/2)-9-(4x/2)=7x-4x+4-2x-3.

(vii) The numerator of a rational number is 3 less than the denominator. If the numerator is increased by 8 and the

denominator is increased by 14, we get the same number. Find the number.

Q10. Price of sugar in a city varies as S=12+(D/40) per kg and that of milk varies as M=10+(D/50) per litre. A

person buys 20 kgs of sugar and 40 litre of milk daily. Terms are such that the customer has to pay the amount

which is multiple of 10 (just less than calculated by aforementioned relations). Find out the date on which dailyexpense of customer becomes 1000 Rs. 8

M= Rate of milk (Rs. per litre), S= Rate of sugar (Rs. Per kg), D= Additional days after 31st Dec 2012.