guia resuelta primer parcial analisis

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    =23

    1

    2+ 1 +

    1

    2+

    5

    12 2

    1

    4

    1

    13

    2

    6+

    1

    4+

    2

    3

    =

    2

    3

    6 + 12 + 6 + 5

    24

    12 12 4 + 3 + 812 =

    2

    3

    7

    12

    1

    4

    5

    12

    =

    2

    3+

    7

    121

    4+

    5

    12

    =8 + 7 3 + 5

    12

    =17

    12

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    =25 2

    1

    2+ 1 1

    5+

    3

    101

    4

    =2

    5 2

    5 + 10 2 + 310

    14

    =2

    5 2

    63

    3

    51

    4

    =2

    56

    5+

    24

    1

    2

    = 45

    +1

    2

    =8 + 5

    10

    = 310

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    ab

    n=

    b

    a

    n

    (a)nm = m

    an

    1

    4

    4 36

    22=

    1

    4

    1

    6

    22

    =

    1

    41

    2

    62

    2=

    1

    4

    1

    362

    =

    9 1

    36

    2

    =

    836

    2

    9

    2

    =

    9

    22

    = 814

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    8 1

    2

    2+

    6 12

    2 12=

    7

    2

    2+

    7

    2

    2 12

    =

    49

    4 +

    49

    4

    12

    =

    2 49

    4

    = 2 494

    = 7

    2

    2

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    = 34+7

    312

    = 311

    312

    = 31112

    = 31

    =

    3

    1

    1=

    1

    3

    =

    5 4 106+2

    2

    8 105=

    5

    210

    4

    105

    =

    5

    2 105(4) =

    5

    2 109

    =

    1

    5

    2

    10 108= 1

    4

    108

    = 1

    2 10 82=

    1

    2 104=

    1

    20000=

    =

    4

    813

    +

    49

    16+

    3

    64

    27

    2+

    5

    1

    32

    426

    23 + 3

    72

    + 12

    = 33 +7

    4+

    4

    3

    2+

    1

    2

    4+ 24 + 34

    = 27 +7

    4+

    16

    9 +

    1

    16+ 81

    = 108 +16

    9 +

    28 + 1 + 1

    16

    = 108 +16

    9 +

    158

    30

    16

    = 72 108 + 16 8 + 15 9

    72

    = 8039

    72

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    = 25 + 9 + 4

    81 +38

    3

    27+

    3

    33 3

    = 34 + 3 23

    + 3 3

    3

    = 37 3 2

    3 + 3 3

    3

    = 109

    3 + 3 3

    3

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    2

    2

    33

    2

    = 2

    4 9

    3

    6

    = 2

    5

    3

    =

    10

    3

    2 2

    3+ 32 = 4332 =8 96 = 176

    2 +23

    32

    = 2 1 = 3

    2 +2

    3

    32

    =

    6 + 23

    32

    =

    (4) (1)2

    = 2

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    a

    b

    a+

    b

    n+ 1 n

    =

    n+ 1 n

    n+ 1 +

    n

    n+ 1 +

    n

    =

    n+ 1

    2+

    n+ 1 n

    n+ 1 n (n)2n+ 1 +

    n

    = n+ 1 n

    n+ 1 +

    n

    =

    1n+ 1 + n

    n3 + 3n2 +n

    n2 + 1 =

    n (n2 + 3n+ 1)n n+ 1

    n

    =

    n2 + 3n+ 1

    n+ 1n

    n

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    2x = 1 12x = 2

    x = 2

    2

    x = 1

    5x = 7 25x = 9

    x = 9

    5

    x = 95

    6x+ 1 + 4 = 7x 3

    6x 7x = 3 513x = 8x =

    8

    13

    9x 3 = 2 (2x+ 4)

    9x 3 = 4x+ 89x+ 4x = 8 + 313x = 11

    x = 11

    13

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    (1 x) 3 = (1 +x) 23 3x = 2 + 2x

    3x 2x = 2 35x = 1

    x = 1

    5

    2x+ 3

    2 (x 1) = 6x 23(x 1)

    (2x+ 3) (3) = (6x 2) 26x 9 = 12x 4

    18x = 5

    x = 5

    18

    2 (x 1)

    3

    (x 1

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    2 +

    34

    x4 10x2 + 1 =x2(x2 10) + 1

    2 + 32 = 2 + 223 + 3 = 5 + 26

    x=

    2 +

    3

    x4 10x2 + 1 = x2(x2 10) + 1=

    2

    6 + 5

    2

    6 + 5 10

    + 1

    =

    2

    6 + 5

    2

    6 5

    + 1

    = 2

    62

    52 + 1

    = 24 25 + 1= 0

    x2

    x=

    2 +

    3

    (a+b) (a b) = a2 b2

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    R

    a

    b

    c

    R

    a < b a+c < b+c

    a < b

    c >0 a c < b c

    a < b

    c b c

    0

    2x 2 + 1 2x 3 x 3

    2

    x (,32

    )

    2x 2 + 1 2x 3 x 3

    2

    x (, 32

    ]

    2x+ 6x >10 11 8x > 1 x > 18 x

    1

    8, +

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    2 x

    x

    2 x >0

    2 x 0

    2> 0 + x x 4 2> 4(2 x) 2> 8 4x 4x >8 2 4x >6 x > 6

    4=

    3

    2

    x 2

    2

    2 x

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    2

    2 x>4 x

    3

    2, 2

    A(x)B(x)

    A(x)B(x) >0

    A(x)> 0

    B(x)> 0

    A(x)< 0

    B(x)< 0

    A(x)B(x)

    0

    B(x)< 0

    A(x)< 0

    B(x)> 0

    A(x) B(x)

    0

    4

    2

    2 x>4 2

    2 x 4> 0

    2 4(2 x)2 x >0

    4x 22 x >0

    0

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    4x 6> 0 2 x >0

    4x >6 x 32

    x

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    x+ 2 < 0 x 3> 0

    x < 2 x >3

    x

    x+ 2 > 0 x 3< 0

    x > 2 x 1 x 3x+ 1

    1> 0

    (x 3) (x+ 1)x+ 1

    >0

    4x+ 1

    >0

    x+ 1 > 0 x < 1 x (, 1)

    x (, 1)

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    52

    < 47

    < 611

    0

    r >0

    log(x+ 102)

    x= 0

    2 + log(x)

    x >0

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    log(a b) = log(a) + log(b)

    loga

    b

    = log(a) log(b)

    log ab =b log(a)

    10log(x) =x

    log

    4x2

    = log(1) = 0

    (x 2) log(4) = 0x 2 = 0x= 2

    log

    25x3

    = log

    1

    8

    = log(1) log(8) = log(8)

    (5x 3) log(2) = log(23

    ) = 3 log(2) (5x 3)log(2) = 3log(2)5x= 0x= 0

    10log(x+7) = 10100 x+ 7 = 10100 x= 10100 7

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    10log(x23x+1)=100=1

    x2 3x+ 1 =1x(x 3) = 0x= 0

    x= 3

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    P = (x, y) R

    x

    P

    y

    P

    y

    x

    P

    o= (0, 0)

    Sy(P) = (x, y)Sx(P) = (x, y)So(P) = (x, y)

    P = (1, 3)

    P

    P

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    V(x) =x(30 2x)(40 2x)

    R

    V(x)

    V(x)

    xR

    x1530 2x0

    30 2x

    x 0

    V

    V

    = 30 2x >0

    0< x 0

    V

    (0, 15)

    V(x)

    x= 0

    x= 15

    x = 6

    x

    6

    x

    V(x)

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    0

    500

    1000

    1500

    000

    500

    000

    500

    y

    2 4 6 8 10 12 14x

    V(x)

    x = 0

    x = 15

    x= 6

    x y=V(x)

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    x

    y

    x

    y

    X= base

    y= altura

    x

    y

    20 2x+ 2y = 20

    y= 10 x

    (f)

    x

    y >10

    20

    x 10

    y 0

    (f) = (0, 10)

    0

    2

    4

    6

    8

    10

    y

    2 4 6 8 10x

    y= 10 x

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    x = lado

    x = lado

    h 2=x+y

    2

    2

    A(x) =

    x x2

    =x2

    2

    A

    (A) = (0, +)

    A(x)

    x

    0

    2

    4

    6

    8

    10

    y

    1 2 3 4x

    x y

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    x

    (x R)((x, y)

    (f) (x, y)

    (f) y = y

    (f)

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    (, 0)

    (0, +)

    x= 0

    (f) = [2, 2]

    (1, 0) (1, 2)

    (2, 1) (0, 1)

    x= 0

    1

    x =1

    x = 1

    1

    (, 0) (1, +)

    (0, 1)

    x= 1

    x= 0

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    x

    y

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    f(x) =mx+b

    m

    b

    f(0)

    y

    m >0

    m

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    f(x) =34 x+174

    (x0, f(x0)) (x1, f(x1)) (f) f

    m

    m=f(x1) f(x0)

    x1 x0 m= 2 53 1=

    34=

    3

    4

    m

    b

    (1, 3)

    (80, 3)

    (f)

    m= 3 3

    80 (1)= 0 b= 3

    f(x) = 3

    (0, 4)

    (3, 0)

    (f)

    f(x) =mx+b f(0) =b

    f(0)

    (0, 4)

    (f)

    f(0) = 4

    b= 4

    m

    0 = 3m+ 4 m= 43

    f(x) = 4

    3x+ 4

    b

    f(a) = 0

    0 =a m+b

    a m= b

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    a = 0

    b = 0

    f(x) = m x m R m= 0

    f(x) = 0

    a = 0

    m= b

    a b= 0

    m = 0

    b

    f(x)

    f(x) = 0

    ab

    R

    f(0) =17

    4

    b

    f(0) = 3

    b

    f(2) = 34 (2) + 4 =8

    3+ 4 =

    20

    3

    m = 34 m = 0 m = 43

    f(x) = 0 m= 0

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    f(x)

    -3 1

    5

    f(x)

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    f(x)

    4

    2

    2

    4

    6

    y

    4 3 2 1 1 2 3 4x

    f(x)

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    f(x) =m x+b= x+b 3 = 2 +b b= 1

    f(x) =x+ 1

    b= f(x)

    m

    x

    b= 5

    0

    1 = 5

    f(x) = 5

    b= f(x) m x= 4 (2) 3 f(x) = 2x+ 2

    f(x) =x+b

    b

    f(x)

    4

    2

    0

    2

    4

    y

    4 2 2 4x

    y=x+ 1

    x= 1

    m >0

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    f(x)

    10

    8

    6

    4

    2

    0

    2

    4

    6

    8

    10

    y

    4 2 2 4x

    f(x) = 5

    m= 0

    f(x)

    4

    2

    0

    2

    4

    y

    4 2 2 4x

    f(x) = 2x+ 2

    x= 1

    m

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    f(x)

    f(x) =x+b

    b > 0

    b0

    0

    x= 0

    y

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    g(0) = 32

    g(100) = 212

    g

    g(x) =mx+b

    b= 32

    m=212 32

    100 0 =

    95

    180

    100

    g(x) =9

    5x+ 32

    h(x)

    h(32) = 0 h(212) = 100

    m = 100 0212 32=

    9

    5

    b=h(x) m x

    x= 32

    b= 0 59 32 = 160

    9

    h(x) =59

    x 1609

    g(x)

    h(x)

    g(x)

    h(x)

    g (h (x)) = g

    5

    9x 160

    9

    =9

    5 5

    9

    x

    160

    9 + 32= x 160

    5 + 32

    = x 32 + 32= x

    f(x) 1f(x)

    f1(x) f(x)

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    h (g (x)) = h

    9

    5x+ 32

    =

    5

    9

    9

    5x+ 32

    160

    9

    = x+ 32 5 160= x+ 160 160= x

    g (h (x)) =h (g (x)) =x

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    f(x) =ax2 +bx+c

    a,b,c R

    a = 0

    a >0

    f(x) =x(x 4) 4 =x2 4x 4

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    f(x) =ax2

    +bx+c

    f(x) =a (x xv)2 +yv

    f(x) =a (x r1) (x r2)

    D= b2 4ac

    d >0 f R

    d= 0 f

    d 0

    a

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    xv = 0 yv =f(xv) = 0

    2 = 0

    a= 1> 0

    f(x)

    4

    2

    0

    2

    4

    y

    4 2 2 4x

    xv = 0 yv = 0 r1= r2= 0 (f) = [0, +) xv

    xv

    = 0 y

    v = f(x

    v) = 0

    a =

    1 < 0

    f(x)

    4

    2

    0

    2

    4

    y

    4 2 2 4x

    xv = 0 yv = 0 a= 1< 0 (f) = (, 0] xv

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    xv = 0 yv = f(0) =3 a = 1 > 0

    x2 3 = 0 x2 = 3 x=

    3

    xv yv

    f(x)

    4

    2

    0

    2

    4

    y

    4 2 2 4x

    xv = 0 yv = 3 r1= 3 r2= 3 a= 1< 0 (f) = [3, +)

    yv y

    D >0

    D= b2 4ac

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    a

    xv yv a= 1 xv = 5

    yv = 0

    f(x)

    5

    4

    3

    2

    1

    1

    2

    y

    2 4 6 8x

    xv = 5 yv = 0 r1= r2= 0 a= 1 (f) = (, 0]

    xv x

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    a= 2< 0

    xv = 0 yv = 0 r1=r2= 0

    f(x)

    (, xv) = (, 0) (0, +)

    f(x) 0x R r1=r2=xv = 0

    xv f(x) x= 0

    r1 = 0 r2 = 3 a =2

    xv

    xv =r1+r2

    2

    xv =3

    2

    yv =f(xv) = 2 32

    3

    2 3

    =

    9

    2

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    f(x)

    , 32

    32

    , +

    f(x)

    f = (, 0) (3, +) f

    f

    f+ = (0, 3)

    f

    xv =

    32

    f

    f(x) = 2

    x 12

    2

    r1= 0 r2=1

    2

    a= 2

    xv = b2a

    = 12 (2)=

    1

    4

    yv = 18

    +1

    4=

    1

    8

    f(x)

    , 1

    4

    14

    , +

    f = (, 0) 12 , + f+= 0, 12 f(x)

    xv =

    14

    f(x) = (x+ 1)2 = (x (1))2

    r1 = r2 =

    1

    a= 1> 0

    xv =

    1

    yv = 0

    f(x)

    (1, +)

    (, 1)

    f

    a >0

    f+ =R{1}

    f

    0

    f(x)

    x= xv = 1

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    r1= 3 r2= 5 a= 20

    xv =

    3+52

    = 1

    f

    (, 1))

    (1, +)

    f+ = (3, 5) f= (, 3) (5, +) f

    x= xv = 1

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    a= 5< 0

    f

    xv

    xv = b2a

    = 102

    (

    5)

    = 1

    yv f(x) xv

    f(xv) =f(1) = 5 12 + 10 1 = 5

    5

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    f(x) =x3

    8

    6

    42

    0

    2

    4

    6

    8

    y

    3 2 1 1 2 3x

    f(x) = (x 2)3

    10

    8

    6

    4

    2

    0

    2

    4

    6

    8

    10

    y

    1 1 2 3 4x

    f(x) =x3

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    f(x) =x3 1

    10

    8

    6

    4

    2

    0

    2

    4

    6

    8

    10

    y

    4 3 2 1 1 2 3 4x

    f(x) =x3

    f(x) =x4

    5

    10

    15

    20

    y

    3 2 1 1 2 3x

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    f(x) =ax+b

    cx+d

    adbc = 0

    adbc = 0

    c = 0

    c = 0

    f(x) =ax+b

    cx+d=A+

    B

    x e

    A= a

    c

    e= dc

    B = bcadc2

    B >0

    (f)

    ++

    b < 0

    +

    +

    (f) = R {e}

    x = e

    B

    x1 x2

    P =

    (x1, f(x1)) Q= (x2, f(x2))

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    B >0

    B >0 ++ b < 0

    +

    +

    (f) = R {e} x= e

    f

    x= e

    y= A

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    y = 0

    x = 0

    x1 =1 x2 = 1

    P = (1, 4) Q = (1, 4)

    f)

    ++

    (f) = R{0}

    x10 x1 < x2

    f(x1)< f(x2)

    (x1, x2) (f)

    f(x) = 4

    x

    10

    8

    6

    4

    2

    0

    2

    4

    6

    8

    10

    y

    10 8 6 4 2 2 4 6 8 10x

    f

    (, 0) (0, +)

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    y = 0

    x = 0

    x1 =1 x2 = 1

    P = (1, 4) Q = (1, 4)

    f)

    +

    +

    (f) = R{0}

    x10 x1 < x2

    f(x1)< f(x2)

    (x1, x2)

    (f)

    f(x) = 4

    x

    10

    8

    6

    4

    20

    2

    4

    6

    8

    10

    y

    10 8 6 4 2 2 4 6 8 10x

    f

    (, 0) (0, +)

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    y = 0

    x1= 2 x2= 4 P = (2, 4)

    Q= (4, 4)

    f)

    ++

    (f) = R{3}

    x10 x1 < x2

    f(x1)> f(x2)

    (x1, x2) (f)

    f(x) = 4

    x3

    10

    8

    6

    4

    2

    02

    4

    6

    8

    10

    y

    10 5 5 10 15x

    f

    (, 3) (3, +)

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    y = 2

    x = 3

    x1 = 1 x2 = 4

    P = (1, 0)

    Q = (4, 6)

    f)

    ++

    (f) = R{3}

    x10 x1 < x2

    f(x1)> f(x2)

    (x1, x2) (f)

    f(x) = 4

    x3+ 2

    10

    8

    6

    4

    2

    02

    4

    6

    8

    10

    y

    10 5 5 10 15x

    f

    (, 3) (3, +)

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    y = 4

    x = 2

    x1 = 1 x2 = 3

    P = (1, 1)

    Q = (3, 17)

    f)

    ++

    (f) = R{2}

    x10 x1 < x2

    f(x1)> f(x2)

    (x1, x2) (f)

    f(x) = 4x+5

    x2

    20

    10

    0

    10

    20

    y

    10 5 5 10x

    f

    (, 3) (3, +)

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    y = 3

    x =1

    x1 =2 x2 = 0

    P = (2, 4) Q = (0, 2)

    f)

    +

    +

    (f) = R

    {1}

    x10 x1 < x2

    f(x1)> f(x2)

    (x1, x2) (f)

    f(x) = 3x+2

    x+1

    10

    8

    6

    4

    2

    02

    4

    6

    8

    10

    y

    4 3 2 1 1 2 3x

    f

    (, 1) (1, +)

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    f(x) =

    x

    1

    0

    1

    2

    3

    y

    1 1 2 3 4 5x

    (f) = R 0

    f(x) = x

    3

    2

    1

    0

    1

    y

    1 1 2 3 4 5x

    (f) = R 0

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    f(x) =

    x+ 3

    1

    0

    1

    2

    3

    y

    4 2 2 4x

    (f) = R 3

    f(x) = |x 2|

    1

    1

    2

    3

    4

    5

    6

    y

    4 2 2 4 6 8x

    (f) = R

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    (f) =R x2 0x R x2 + 4 0 x Rx2 + 4

    0

    x 8

    0 x 8

    f= [8, +)

    x

    f x2 9 0 x2 9 |x| 3

    f= (, 3] [3, +)

    x

    f

    x (x 1) 0

    x 0

    x 1 0

    x 1

    x 0

    x 1 0

    x 0

    f= (, 0] [1, +)

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    ff(1) =f(f(1)) =f(2 (1)2 +5(1) =

    f(3) = 3

    f h(1) = f(h(1)) = f(4) =

    32 20 = 12

    g f(1) f(1) = 3 / (g) = R {3}

    h g(2) =h(g(2)) =h 15

    = 2 1

    5 6 = 230

    5 = 28

    5

    f g(x) = f

    1

    x+ 3

    = 2

    1

    x+ 3

    2+ 5 1

    x+ 3

    = 2

    (x+ 3)2+

    5

    x+ 3

    =

    2 + 5

    (x+ 3)

    (x+ 3)2

    = 5x+ 17

    (x+ 3)2

    g h(x) = 1(2x2 + 5x) + 3

    = 1

    2x2 + 5x+ 3

    ((f g) h) (x) =

    (f g) (h(x))= 2 + 5 ((2x 6) + 3)

    ((2x 6) + 3)2

    = 10x 13

    (2x 3)2

    f h(x) = 2(2x 6)2 + 5(2x +)= 2(4x2 24x+ 36) + 10x 30= 8x2 38x+ 42

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    f f(x) = 2 2x2 + 5x2 + 5x= 2(4x4 + 20x3 + 25x2) + 5x

    8x4 + 40x3 + 50x2 + 5x

    f g(x) =g f(x)

    (f (g h)) (x) = f(g h (x))= f(g(h (x)))

    = (f

    g) (h (x))

    = ((f g) h) (x)

    f g h t(x)

    (((f g) h) p) (x)

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    f : R R m = 0

    x

    y

    f

    y = 3x 5 y+ 53

    =x

    f1(x) =

    x+ 5

    3

    f

    f1(x) =1

    3x+

    5

    3

    x 0

    f(x) = 2x2 1

    f :RR f

    f : [0, +

    )

    R

    1

    f

    m m = 1m

    13

    y0 f f1(y0)

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    y= 2x

    2

    1

    2

    1

    0

    1

    2

    3

    4

    y

    1 2 3 4 5x

    f= [0, +)

    f= [1, +)

    y= 2x2 1 x2 = y+ 12

    |x| =

    y+ 1

    2

    x 0 |x| =x x= y+ 12 f1(x) =

    x+ 1

    2

    f1 : [1, +) R 0 f1 (x) =

    x+ 1

    2

    f= [5, +) x+ 5 0 +

    x [5, +)

    f = (, 3]

    x

    y

    f(x)

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    y = 3 x+ 5 x+ 5 = 3 y x+ 5 = (3 y)2 x= (3 y)2 5 x= y2 6y+ 4 f1(x) =x2 6x+ 4

    f1 : (, 3] R f1(x) =x2 6x+ 4

    f : R R f1(x) = 3x

    f

    f= [3, +)

    xv = 3 a = 1 > 0 xv

    f(xv) = 5

    (f)

    f= [5, +) =

    (f1)

    x

    y

    f

    y= x2 6x+ 4 (x 3)2 5

    (x 3)2 =y + 5 |x 3| =

    y+ 5

    x 3 |x 3| =x 3 x 3 =

    y+ 5

    x= 3 + y+ 5 f1(x) = 3 + x+ 5

    f1 : [5, +) = R

    f1(x) = 3 +

    x+ 5

    f(x)

    f=

    (, 3] x 3

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    f= [

    5, +

    )

    y= x2 6x+ 4 (x 3)2 5

    (x 3)2 =y + 5 |x 3| =

    y+ 5

    x 3 |x 3| = (x 3) 0 x 3 =

    y+ 5

    x= 3

    y+ 5

    f1(x) = 3

    x+ 5

    f1 : [5, +) = R

    f1(x) = 3 x+ 5

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    x >0

    (x >0) xx

    =

    x

    xx

    x>0=

    x2x

    =

    x2

    x =

    x

    f

    1

    x

    =

    1x

    + 1

    1x

    + 1

    =

    1x

    + 11+xx

    =

    1+x

    x

    x+1x

    =x+ 1

    x x

    x+ 1

    = x

    x

    x+ 1

    x+ 1

    = x

    x f(x)

    =

    x f(x)

    f1x = x f(x)

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    f(x) = 2x

    2

    1

    0

    1

    2

    3

    4

    5

    6

    y

    3 2 1 1 2 3 4 5x

    f

    f= R

    f= R >0

    f(x) = 12x

    2

    1

    0

    1

    2

    3

    4

    5

    6

    y

    3 2 1 1 2 3 4 5x

    f

    f= R

    f= R >0

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    f(x) = 3x

    2

    1

    0

    1

    2

    3

    4

    5

    6

    y

    3 2 1 1 2 3 4 5x

    f

    f= R

    f= R >0

    f(x) =

    13

    x

    2

    1

    0

    1

    2

    3

    4

    5

    6

    y

    3 2 1 1 2 3 4 5x

    f

    f= R

    f= R >0

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    r >0, r = 1 R

    rx : R R>0

    logr(x) :R>0 R

    (x, y)

    (rx)

    (y, x)

    (logr(x))

    f(x) = log2(x)

    4

    2

    2

    4

    6

    y

    2 2 4 6 8x

    f

    f= R>0 f= R

    f(x) = log 1

    2(x)

    4

    2

    2

    4

    6

    y

    2 2 4 6 8x

    f

    f= R>0 f= R

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    f(x) = log

    3(x)

    4

    2

    2

    4

    6

    y

    2 2 4 6 8x

    f

    f= R>0 f= R

    f(x) = log 1

    3(x)

    4

    2

    2

    4

    6

    y

    2 2 4 6 8x

    f

    f= R>0 f= R

    log 12

    (x) = log2(x)

    log 13

    (x) = log3(x)

    x

    1

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    (ln(x)) = R>0 x

    2x >0 x >0

    (f) = R>0

    x/f(x) = 1

    2x= e x= e2

    f

    {x: 3x2 + 2x >0}

    a >0

    3x2 + 2x >0 x (, r1) (r2, +)

    3x2 + 2x= 3x

    x

    2

    3

    r1 = 2

    3 r2= 0

    (f) =

    , 2

    3

    (0, +)

    e ln 2, 7182

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    f(x) = 1 3x2 + 2x= e 3x2 + 2x e= 0 x=2

    4 + 12e

    6

    x=2 2

    1 + 3e

    6

    x=1

    1 + 3e

    3

    f(x) = 1 x=1 1 + 3e3

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    f : R>0 R y = ln(2x) ey = 2x x = 12 ey

    f1 : R R>0 f1(x) = 12

    ex

    (f) = R

    f

    f(1) = ln(5) =f(1)

    f

    (f) := [0, +)

    x2 + 4

    ln(x)

    f(x)

    [0, +)

    (f) = [ln(4), +)

    y = ln x2 + 4 ey =x2 + 4 x2 =ey 4 |x| = ey 4

    x 0 |x| =x x= ey 4

    f1 : [ln(4), +) [0, +) f1 (x) =

    ex 4

    f1 (x)

    (f)

    f= f1

    (f) = (, 1)(1, +)

    (f) = (1, +)

    (f) = R

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    y= ln

    x2 1 ey + 1 =x2 |x| = ey + 1

    x >0 |x| =x x= ey + 1

    f1 : R (1, +) f1(x) =

    ex + 1

    (f) = R

    0 (f) = [6, +

    )

    y = 2x + 5 y 5 = 2

    x

    x= ln(y 5)ln(2)

    x=

    ln(y 5)ln(2)

    2 x= ln

    2(y 5)ln2(2)

    f1 : [6, +) R

    f1(x) =ln2(x 5)

    ln2(2)

    (f1)

    f1(x)

    (f1) = (5, +)

    f1(x)

    f

    f

    (f) = R

    (f) = R0

    y= ex+3 ln(y) =x+ 3 x= ln(y) 3

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    f1 : R0 R f1(x) = ln(x) 3

    (f) = R>0 f (f) =

    R>1

    y = ex2 x2 = ln(y)

    (x >0) x= ln(y)

    f1 : R>1 R>0 f1(x) =

    ln(x)

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    sin(x ) = sin(x)

    2

    cos(2x+) = cos(2x)

    sin

    x+

    2

    = cos(x)

    1

    f(x) = sin(x )

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    f(x) = cos(2x)

    f(x) = cos(2x+)

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    f(x) = sin(x+

    2)

    2

    2

    2

    3 2

    2-

    -

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    sin(x)

    2

    sin(x) = 1

    2

    [0, 2)

    S[0,2)

    S=

    x0+ 2k : x0 S[0,2) k Z

    [0, 2)

    sin(x) =1

    2 x=

    6 x=

    6 =

    5

    6

    S[0,2)=

    6,5

    6

    S= 6+ 2k : k Z 5

    6+ 2k : k

    Z

    x R|cos(x)| 1

    [0, 2)

    x= 0 x=

    S= {2k : k Z} {+ 2k : k Z}

    R

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    x R

    sin(x+ y) = sin(x)cos(y) + cos(x) sin(y)

    sin(x y) = sin(x)cos(y) cos(x) sin(y)

    cos(x+y) = cos(x)cos(y) sin(x)sin(y)

    cos(x y) = cos(x) cos(y) + sin(x)sin(y)

    sin(x+x) = sin(x)cos(x) + cos(x) sin(x)

    = 2 sin(x)cos(x)

    sin(2x) = 2 sin(x) cos(x) x R

    x R

    cos(x+y) =cos(x)cos(y) sin(x)sin(y)

    cos

    x+

    4

    = cos(x)cos

    4

    sin(x)sin

    4

    = cos(x)

    2

    2 sin(x)

    2

    2

    =

    2

    2 (cos(x) sin(x))

    cos

    x+

    4

    =

    2

    2 (cos(x) sin(x)) x R

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    cos(x)

    (cos(x)) = [0, ]

    sin(x)

    2

    , 2

    arc cos(x) : [1, 1] [0, ]

    arcsin(x) : [1, 1]

    2,

    2

    cos(x) arc cos(x)

    sin(x) arcsin(x)

    x= sin

    4

    =

    2

    2

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    x= cos () = 1

    (x [1, 1]) arc cos(x) 0

    cos2(x) = 1 sin2(x)

    sin (arcsin (x)) = x

    sin2 (x) = (sin(x))2

    cos(arccos(x)) =

    cos2 (arcsin (x))

    =

    1 sin2 (arcsin (x))

    =

    1 (sin (arcsin (x)))2

    =

    1 x2

    (x

    (arcsin(x)) cos (arcsin (x)) =

    1 x2

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    f(x)

    x= 3

    x 1

    x= 1

    x= 4

    f(3) = 3 + 2 = 1 f(1) = 1 f(4) = 3 4 4 = 8

    y= f(x)

    y

    (0, y)

    f(x)

    y

    (

    ,

    1)

    (1, +

    )

    y

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    f(x)

    f(x)

    x= 3

    x= 1

    x= 4

    x 4

    f(3) = 13 + 2 = 1 f(1) = 1

    1 + 2=

    1

    3 f(4) =

    1

    4 + 2=

    1

    6

    y= f(x)

    y

    (0, y)

    f(x)

    y 11,

    12 (0, +)

    y

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    x

    0 x 100,000

    100,000

    x

    100,000

    200,000

    x 200,000

    f(x)

    f(x) =

    0

    0 x 100000x100000

    1000 1

    2 100000< x 200000

    50 + x

    2000001000

    x >200000

    50

    f(x)

    200000

    200000

    $200000

    $50

    $530

    50 +x 200000

    1000 = 530

    x 200000 = 1000 480 x = 200000 + 480000 x = 680000

    $680000

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    f(x)

    f

    (1, 2)

    (2, 0)

    m= 2 01 2= 2

    3 f(x) = 2

    3x+b

    0 =f(2) = 43

    + b b= 43

    f(x) = 23

    x+4

    3

    g(x)

    2

    2

    g(x) =a (x 2) (x+ 2)

    g(1) = 2

    2 =a(3)(1) = 3a a= 23

    g(x)) = 23 (x 2) (x+ 2)

    x/f(x)> g(x)

    a g(x)

    |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||

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    f(x)> g(x) x (, 1) (2, +)

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    a2 b2 = (a b) (a+b)

    cosh2(x) sinh2(x) = (cosh(x) sinh(x)) (cosh(x) + sinh(x))= ex +ex

    2 e

    x

    ex

    2ex +ex

    2 + e

    x

    ex

    2

    =

    2ex

    2

    2ex

    2

    = ex ex= ex+(x) =e0 = 1

    cosh2(x) sinh2(x) = 1

    x R

    cosh(x) = sinh(x) cosh2(x) = sinh2(x) cosh2(x) sinh2(x) = 0

    x

    R cosh2(x)

    sinh2(x) = 1

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    x= 0

    f(1) = 3, 55Kg

    4, 55 = 2 3, 55 f(2) = 4, 55Kg

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    ab

    cd

    = ab d

    c

    f(n+ 1)f(n)

    = 23(n+1)

    4(n+ 1) + 14n+ 1

    23n

    = 23n+3

    4n+ 54n+ 1

    23n

    = 8(4n+ 1)

    4n+ 5

    = 8

    4n+ 1

    4n+ 5

    f(n+ 1)f(n)

    = 84n+ 14n+ 5

    f(2)

    f(1)= 8 5

    9=

    40

    9

    f(3)

    f(2)= 8 9

    13=

    72

    13

    f(4)

    f(3)= 8

    13

    17=

    104

    17

    f(5)

    f(6)= 8 17

    21=

    136

    21

    f(6)

    f(5)= 8 21

    25=

    168

    25

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    (1, +)

    (, 2]

    |x|

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    x2 0

    2x

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    1< 4

    x

    x 4

    x

    x (0, +)

    x (3, 3)

    3< x 2< 3 1< x

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    2 x 4 3 x 6 2 x 6

    x < 3

    x > 1

    1 < x < 3 = (1, 3)

    (, 3) (1, +) = (1, 3)

    1< x

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    1< x

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    12;23;34;45 ;56

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    3

    p N

    q N /

    3 =p

    q

    p

    q

    pq

    3 = p2

    q2

    3 |p 3 | q

    |

    |

    p

    q

    3

    p

    3

    q

    p2 = 3q2 3|p2 3|p

    3

    p

    p

    3|p

    3

    3 | q

    3|p p= 3t

    t N 3q2 =p2 = (3t)2 = 9t2 q2 = 3t2 3| q2

    3| q

    3 / Q

    p

    q

    p

    q

    p

    q

    32

    24

    12

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    3, 141592<

    3, 14< 3, 141Q

    <

    0, 001 = 3, 140592 < 0, 001 = 3, 140592 >3, 14

    3, 14< 0, 001<

    0, 001 RQ

    x / Q

    y Q x y / Q

    z Q

    x y= x Q

    x= yQ

    + zQ

    Q

    / Q 0, 001 Q 0, 001 / Q

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    n 1 n N 1n 1 n N 1 A

    1 A

    1 = max(A) = sup(A)

    sup(A)

    max(A)

    1

    A

    n N, n > 0 1

    n > 0

    0

    A

    0 = nf(A)

    n

    1n

    0 = nf(A)

    > 0 a A/ 0 a < 0 +

    a

    A

    a = 1

    n n N

    1

    > 0

    n0 N n0 > 1 1n0 <

    a= 1n0

    A

    0 a

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    12

    1

    2 n

    n+ 1 n+ 1 2n n 1

    12

    B

    12 B

    1

    B

    1 nn+ 1

    n+ 1 n

    1 = sup(B)

    >0 b B / 1 < b 1

    1 < nn+ 1

    = n+ 1 1

    n+ 1 =

    n+ 1

    n+ 1 1

    n+ 1= 1 1

    n+ 1

    < 1

    n+ 1

    > 1n+ 1

    n+ 1 > 1

    n0 >

    1 1

    R

    b = n0

    n0+1

    1 < b

    1 = sup(B)

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    1 /

    B

    1 B n N / 1 = nn+ 1

    n+ 1 =n 0 = 1

    1

    B

    B

    nf(C) = 0

    0 / Csup(C) = 7

    7 / C

    1 = nf(N) =mn(N)

    0

    E

    0 E

    0 = mn(E)

    E

    n 1n2

    n 1> M n > M 1

    M >0

    n= [M] + 1

    n 1

    n2 > M

    E

    mn(F) = 1

    max(F) = 4

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    G=

    6 1

    10n : n N

    10n 1 110n

    1 110n

    1 6 110n

    5

    G

    5 G

    5 = mn(G)

    6 1

    10n 6 6

    G

    > 0 n N /n > 1

    1n

    n N 10n > n 110n

    < 1

    n<

    n N / 110n

    < ( >0)

    110n

    > ( >0)

    6

    1

    10n >6

    (

    >0)

    6 = sup(G)( >0)

    H= (1, 3)

    I= (, 3)(3, +)

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    2n 1n+ 2

    2 2n 1 2n+ 4 1 4

    1, 99 = 2

    = 0, 01

    1, 99< p=2n 1

    n+ 2 2 < 2n 1

    n+ 2 2n+ 4 (n+ 2) 5

    n+ 2 > 5

    n > 5 2

    t < 2

    t= 2

    >0

    n > 5

    2

    p= 2n1

    n+2

    n=

    5

    1, 99 = 2 0, 01

    n= 5

    0, 01= 500

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    25001500+1

    = 999502

    1, 990039 > 1, 99

    t 0/t= 2

    t 0/t= 2

    n=

    5

    p=2n 1

    n+ 2

    > t

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    n= 1001 1

    n= 0, 000999< 0, 001

    x >0 1

    x>0

    R

    n N/n > 1x 1

    n< x

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    A B

    a A, a B

    c R

    B c bb B c aa A

    a B

    {

    } {

    }

    nf(B) nf(A) sup(A) sup(B)

    A= (1, 2) B= (0, 2)

    A= (1, 2) B= (0, 3)

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    A

    a =

    1> 0

    (r1, r2) r1 r2

    x2 3x+ 2 = (x 1) (x 2) r1 = 1 r2= 2

    A= (1, 2)

    nf(A) = 1

    sup(A) = 2

    A

    f(x) = 3x2 3x+ 2

    f(x) x= 32

    f32

    = 0, 25

    f(0) = 2

    B

    B

    x (0, 2) y (0,25, 2)

    B= (0,25, 2)

    nf(B) = 0, 25

    sup(B) = 2

    B

    C

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    C= [

    0,25, +

    ]

    nf(C) = mn(C) =

    0, 25

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    a1 =1

    2 a2=

    2

    3 a3=

    3

    4 a4=

    2

    5 a5=

    5

    6

    b1= 1 b2= 2

    32 b3=

    22

    53 b4 =

    23

    73 b5=

    24

    93

    c1 = 1 c2 = 14

    c3=1

    6 c4= 1

    24 c5 =

    1

    120

    (n N) n!

    n! =n

    (n

    1)

    (n

    2)

    (n

    3)

    2

    1

    5! = 5 4 3 2 1 = 120

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    d1=cos()

    1 = 1

    d2=cos(2)

    2 =

    1

    2

    d3 = cos(3)

    3 = 1

    3

    d4=cos(4)

    4 =

    1

    4

    d5 = cos(5)5

    = 15

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    an cn

    cn= 1n2

    + 1=

    2

    n+ 2

    cn :

    23

    ; 12

    ; 25

    ; 13

    ; 27

    ; 14

    ; etc

    an

    an = bn cn = 1 + (1)n

    2 2n+ 2

    =1 + (1)n

    n+ 2

    an=1+(1)n

    n+2 a100=

    1

    2

    51

    102

    151

    a200 = lmn

    an= 0

    an=(1)n+1 a100= 1 a200 = 1

    an=n+1n

    a100 =

    101100

    a200=

    201200

    lmn

    an= 0

    1; 1

    2; 1

    3; etc

    bn=1 + (1)n+1

    n+ 1 : 1, 0,

    1

    2, 0,

    1

    3, 0,

    1

    4, 0,etc

    n+ 1

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    cn

    1, 2, 3, 4, 5,etc

    cn=(1)n + 1

    2 n

    2 : 0, 1, 0, 2, 0, 3, 0, 4, 0, 5,etc

    an = bn+cn=1 + (1)n+1

    n+ 1 +

    (1)n + 12

    n2

    an=1 + (1)n+1

    n+ 1 +

    (1)n + 12

    n2

    a100= 50 a200 = 100

    a1 = 1

    a2 = 2a1 = 2

    a3 = 2a2 = 4

    a4 = 2a3 = 8

    an = 2n1 a100= 299a200 = 2199 lm

    nan = +

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    n N

    an > 10 an>1000

    an> 10 an > 1000

    M > 0R

    n0 M an> Mn n0

    an

    an=n 5

    22 57

    4

    an> M

    n 52

    2> M+

    57

    4

    n 52

    2> M+

    57

    4

    n3

    n 5

    2 > 0

    an> M n 52

    >

    M+

    57

    4

    n > 52

    +

    M+

    57

    4

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    n

    3

    an> M n > 52

    +

    M+

    57

    4

    n0

    M= 10

    n0 =

    52

    +

    10 + 574

    + 1 = 8

    n 8

    an>10

    M= 1000 n0 = 52+ 1000 + 574

    + 1 = 35

    n 35

    an>1000

    an+1 an = 2n+1 2n =

    2n(2 1) = 2n >0 an+1> an(n N)

    n0 an0 > M

    M

    an > M 2n > M+ 100 n > ln(M+ 100)ln(2)

    M= 10

    n0 =

    ln(110)

    ln(2)

    + 1 = 7

    n 7

    an>10

    M= 1000

    n0 = ln(1100)ln(2)

    + 1 = 11

    n 11

    an>1000

    1, 9 an 2, 1 0, 1 an 2 0, 1

    |an 2| 110 1n+1 110 110

    110

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    |an 2| n 1 1

    = 1

    10

    n0 = 1

    ( 110 ) 1 = 9

    (n 9) |an 2| 110

    1, 9 an 2, 1

    = 1

    1000

    n0= 1

    ( 11000 )1 = 999

    (n 999) |an 2| 11000

    1, 9999 an 2, 001

    |sin(n)| 1

    1n 1

    10

    1n 1

    1000

    n0 = 10 n0= 1000

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    14

    < an 1 < 14 34

    < an< 54

    an

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    lmn

    an = lmn

    n2

    4n+ 2 3n 1

    n2

    n

    2

    5 + 4n2

    5

    =

    lmn

    an = lmn

    n+

    n2 5n

    n

    1 + 3n

    1

    = +

    lmn

    an= lmn

    n3

    1 + 2

    n3n2 1 1n2 = lmn0

    n3

    n4

    1

    1 + 2

    n31 1n21= 0

    lmn

    an = lmn

    n2

    n2

    22 1

    n23 + 2

    n2

    3

    =

    23

    lmn

    an = lmn

    n2

    44 + 3

    n2

    n

    2

    3 + 4000n2

    3

    =4

    3

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    lmn

    an = lmn

    n (1)n

    1 1n

    + 1

    2

    = 12

    an=

    bn n+ 2n+1

    2

    2(n2 +1)

    2n2 + 1 cn

    lmn

    n+ 2n+1

    2

    = lmn

    2 n+ 2n+ 1

    = lmn

    2 nn

    1 + 2n

    1 + 1

    n

    = 2

    lmn

    2(n2

    +1)

    2n2 + 1

    = 2 2n2

    2n2

    1 + 1

    2n2

    1

    = 2

    bn= n+2

    (n+12 )

    an

    cn = 2(n2+1)

    2n2+1

    an

    lmn

    an= 2

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    lmn bn= 2

    ??? lmn b2n1 = 2 an bn

    lmn cn= 2 ???

    lmn c2n = 2

    an cn

    an

    an

    lmn

    bn= 2 lmn

    b2n1= 2

    > 0

    n0

    N/ n

    n0 |bn 2| < n n0 2n 1 n |b2n1 2| <

    lmn

    b2n1 = 2

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    (

    n

    n2)

    |an

    2

    |<

    lmn

    an = 2

    12

    an =

    1 + r + r2 + r3 + r4 + + rn

    r= 12

    an

    an = 1 +r+r2 +r3 +r4 + +rn

    r an = +r2

    +r

    3

    +r

    4

    + +rn

    +r

    n+1

    an r an = 1 rn+1

    an(1 r) = 1 rn+1

    an

    an=1 rn+1

    1 r =1

    2

    an

    an= 2

    12n

    lmn

    an = lmn

    2 12n

    = 2

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    lmn

    an = lmn

    n2 +n 2 n

    n2 +n 2 +nn2 +n 2 +n

    = lmn

    n2 +n 2 n2n2 +n 2 +n

    = lmn

    n1

    1 2n

    n

    1 + 1n 2

    n2+ 1

    2

    =1

    2

    lmn

    an = lmn

    n2 + 1

    n2 3 + 3

    n2 + 1 + n2 3 + 3n2 + 1 +

    n2 3 + 3

    = lmn

    (n2 + 1) (n2 n+ 3)n2 + 1 +

    n2 3 + 3

    = lmn n

    11 2nn

    1 + 1n2

    +

    1 1n

    + 3n2

    2

    =12

    lmn

    an = lmn

    n

    2

    n2

    2 1n2

    3 + 2n2

    23

    +nn

    323 1

    n

    2 + 3n

    =

    2

    3+

    3

    2

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    lmn

    an = lmn

    n

    n+ 2 n

    n+ 2 +

    n

    n+ 2 +

    n

    = lmn

    n (n+ 2 n)

    n+ 2 +

    n

    = lmn

    2

    n

    n

    1 + 2n

    + 1

    2

    = 1

    lmn

    an = lmn

    n

    n+ 2 n

    n+ 2 +

    n

    n+ 2 +

    n

    = lmn

    n(n+ 2 n)

    n

    1 + 2n

    + 1

    = lmn

    +n2n

    21 + 2

    n+ 1

    2

    = +

    lmn

    an = lmn

    n

    n+ 1 + n

    n+ 1 n2

    = lmn

    n

    2 n+1n + 1n

    21 + 1

    n+ 1

    n2

    = lmn

    1

    n(1+ 1n)n2

    0

    + 1

    1 + 1n

    + 1n2

    1

    = 1

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    an bn

    cn

    cn = an bn

    a := lmn an b := lmn bn

    c:= lmn cn

    an bn

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    an=bn= n

    lmn

    an bn = lmn

    n n= 0

    an= 2n bn=n

    lmn

    an bn = lmn

    2n n= lmn

    n= +

    an bn +

    (+) (+)

    an=bn= n

    lmn

    anbn

    = lmn

    1 = 1

    an=n

    2

    bn = n

    lmnan

    bn = lmnn= +

    an bn +

    an=bn=

    1n

    lmn

    anbn

    = lmn

    1 = 1

    an=

    1n

    bn= 1n2

    lmn

    anbn

    = lmn

    n2

    n = +

    an bn

    00

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    an=e

    n

    bn= 1n

    lmn

    abnn = lmn

    en

    1n =e1 =

    1

    e

    an=e

    n

    bn = 1n2

    lmn

    abnn = lmn

    en

    1n2 =e

    1n =e0 = 1

    an bn

    00

    an=

    1n

    bn = n

    lmn

    an bn = lmn

    1

    n n= 1

    an=

    1n

    bn= n

    2

    lmn an bn = lmn1

    n n2

    = +

    an bn

    0

    an= 1n

    bn = en

    lmn

    bann = lmn

    (en)1n =e1 =e

    an= 1n2 bn=en

    lmn

    bann = lmn

    (en)1n2 = lm

    ne

    1n =e0 = 1

    an bn

    0

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    +

    lmn

    an= +

    an > 0

    an> 0n

    lmn(an+bn) = lmn

    +

    an1 +01

    an bn 1

    = +

    L 0

    an L

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    lmn

    anbn

    = lmn

    0

    1

    bn

    an0

    = 0

    an>0

    N

    abnn = ebnln(an)

    lmn

    e

    +bn ln(

    0+an )

    = 0

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    lmn

    an = lmn

    01

    n

    sin(n)

    = 0

    lmn

    an = lmn

    (1)n(n+ 2 n)(

    n+ 2 +

    n)

    n+ 2 +

    n

    n+ 2 +

    n

    = lmn

    (1)n (n+ 2 n)n+ 2 +

    n

    = lmn

    (1)n

    2n+ 2 +

    n

    0

    = 0

    an (1)n 1n

    an

    lmn an=

    an a2nn1 a2n1n1

    an ank

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    lmn

    an= 0

    rn n 0 |r| 1, r R

    lmn

    an= 0

    rn n 0 |r|

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    lmn

    an = lmn

    n

    5n

    2

    5

    n+ 1

    = lmn

    5 n

    2

    5

    n+ 1

    1= 5

    lmn

    an = lmn

    n

    n4 + 11

    2

    = lmn

    n

    n4

    1 + 1

    n4

    12

    = lmn nn1

    4

    n1 + 1n41

    12

    = 1

    (1 + (1)n)n

    2n

    an = 0 2nn

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    2n

    n

    an a2n1 0 a2n1n 0 a2nn +

    an L R an

    an

    an

    an

    an

    an +

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    lmn

    an= + (M >0) n0 N n n0 an> M

    M = 1

    n0 N n n0 an > 1 an0 = 0 an0+1= 0 an

    lmn

    an= +

    an

    bn =

    2n

    n +

    an

    lmn

    bn = L lmn

    bn+1=L

    bn b1 b2 b3 b4 b5 b6 bn+1 b2 b3 b4 b5 b6 b7

    R +

    bn bn+1 bn(n

    N)

    bn+1 bn 2n+1

    n+ 1 2

    n

    n

    2 n+ 1n

    = 1 +1

    n

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    lmn

    an = lmn

    3 9n + cos(n)2 9n + sin(n)

    = lmn

    9n

    9n

    3 +

    0cos(n)

    9n

    2 + sin(n)9n0

    = 3

    2

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    bn

    1 + 1

    e

    bn

    1

    lmn

    1 +

    3n+ 1

    3n 5 1n

    = lmn

    1 +

    3n+ 1 3n+ 53n 5

    n

    = lmn

    1 + 13n5

    6

    3n5

    6

    e

    2

    63n 5 n

    = e2

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    1

    1

    1

    4

    3+

    n +

    lmn

    1 + 3

    3n+ 12n+1

    = lmn

    1 + 13n+13 3n+1

    3

    e

    2

    3n+ 1

    3 n

    = e2

    lmn

    1 + 1

    n2

    n2

    e

    0

    1n

    =e0 = 1

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    lmn

    1 + 1n17

    n

    17

    e

    0

    17

    =e17

    +

    lmn

    an= +

    lmn

    1 +

    2n+ 6

    3n2 5n2+2

    2n+1

    = lmn

    1 + 13n25

    2n+6

    +

    3n252n+6

    e

    2n+63n25n2+22n+1

    13

    =e13

    =0ann 0 lmn (1 +an)

    1an =e

    lmn

    sin(n)

    n2 n= lm

    n

    1

    n

    0

    sin(n)

    = 0

    lmn

    1 +sin(n)

    n2

    1( sin(n)

    n2 )

    e

    sin(n)

    n2 n0

    =e0 = 1

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    cos2(x) = 1 sin2(x)

    lmn

    cos2

    1

    n

    1sin2( 1n) = lm

    n

    1

    1 cos2

    1

    n

    1 sin2( 1n)

    1

    =

    1 sin2

    1

    n

    1 sin2( 1n)

    e

    1

    = e1

    bn =

    Cos(n)5n3+1

    lmn bn= 0

    bn= 0 n N

    lmn

    bn(2n2 + 3) = lm

    ncos(n)

    0

    2n2 + 3

    5n3 + 1= 0

    lmn

    an= lmn

    (1 +bn)

    1bn

    e

    bn(2n2+3)0

    lmn

    an=e0 = 1

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    lmn

    an+1an = lmn n+ 12n+2 2

    n+1

    n =

    1 n+ 1

    n 2

    n+1

    2 2n+1 =1

    2 1 lm

    nan= +

    lmn

    an+1an = lmn (n+ 1) 2n+1(n+ 1)! n!n2n

    = lmn

    n+ 1

    n+ 1n!

    n!2

    n

    2n

    2n

    = lmn

    0

    2n

    = 0< 1

    lmn

    an= 0

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    lmn

    |an+1||an| =l lmn

    n

    |an| =m y l= m

    lmn

    |an+1||an| = lmn

    (n+ 1)!

    n! = lm

    nn+ 1 = + >1

    lmn

    n

    n! = +

    (r >0 R), lmn

    rn

    n! = 0

    lmnan+1an = lmn r

    n+1

    (n+ 1)!n!rn

    = lmn

    r

    n+ 1= 0< 1

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    lmn

    |an+1||an| = lmn

    22(n+1)+1

    (2(n+ 1))! (2n)!

    22n+1

    = lmn

    22n+3

    (2n+ 2)! (2n)!

    22n+1

    = lmn

    4 22n+1(2n+ 2)(2n+ 1) (2n)!

    (2n)!

    22n+1

    = lmn

    4

    (2n+ 2)(2n+ 1)= 0< 1

    lmn

    an= 0

    lmn

    n|an| = lmn

    12

    + 2n

    =12

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    lmn

    |an+1||an| = lmn

    n+ 1!

    (n+ 1)n+1 n

    n

    n!

    = lmn

    nn

    (n+ 1)n = lm

    n

    n

    n+ 1

    n= lm

    n

    n+ 1 1

    n+ 1

    n= lm

    n

    1 1

    n+ 1

    n

    = lmn

    1 1n+ 1

    n+1

    e1

    1

    n

    n+1

    = e1

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    bn

    lmn

    n

    |bn| = lmn

    1 +

    1

    n

    n=e >1

    lmn

    1

    an= +

    an

    1

    anan>0n

    > bn an< 1

    bn n0

    lmn

    an= 0

    +

    lmn

    an= +

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    a4n =

    cos(4n) +

    sin(2n) = 1 n N lmn

    a4n= 1

    a4n+1 = cos ((4n+ 1) ) + sin

    (4n+ 1)

    2

    = cos(4n+) + sin

    2n+

    2

    = cos(pi) +sin

    2 = 1 + 1 = 0 ( n N) lmn

    a4n+1 = 0

    lmn an

    a2n =

    =1n(1)

    6n+1

    + 4 = 3 ( n N) lm

    na2n= 3

    a2n1 =

    =1n

    (1)3(2n1)impar +1 4 = 3 ( n N) lmn a2n1 = 3

    lmn an

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    cos(2n) = 1 ( n N) cos((2n 1)) = 1 ( n N)

    a2n= 6n+ 1

    10n 2 n N lmn a2n= 0

    a2n1 = 3(2n 1) + 15(2n 1) 2=

    (6n 2)(10n 7)( n N)

    lmn

    a2n1= 1

    lmn an

    an

    a5n

    a5n+1

    a5n = 5n

    5n n 1

    a5n+1= 2 +

    1

    5n+ 1n2

    lmn an

    cos(2n) = 1 ( n N)cos ((2n 1) ) = cos (2n ) = 1 ( n N)a2n =

    1 +

    1

    2n

    2nne

    a2n1 =

    1 12n 1

    2n1n e1

    lmn an

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    L= lmn an =L ank

    bn

    lmn

    bn=L

    lmn

    bn = L L= 0

    L >0

    lmn

    bn=L

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    an+1an

    = 2 > 1 an+1 > an an

    (nN)

    (n N)

    (n N)

    an = 2

    n1 (n N)

    a1= 1 = 211 = 20 = 1

    an= 2

    n1

    an+1 = 2

    n

    an+1= 2an= 2(2n1) = 2(n1)+1 = 2n

    (n N) (n N)an = 2n1

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    an

    an

    0< a1=1

    3

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    n= 6

    an

    0< an < 1n N

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    a1 =

    13

    0< a1

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    L= lmn

    an+1 lmn

    1

    2(an)

    L (1 an)1L =12

    L(1 L)

    L= 12

    L(1 L) 2L= L L2

    L+L2 = 0 L(L+ 1) = 0

    L 0

    L= 0

    lmn an

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    an a1 =

    1; a2 = 1

    2; a3 =

    13

    ; a4 = 1

    4

    an = 1nn

    N

    a1 = 1 =

    11

    an =

    1n

    an+1= 1

    1 +

    1

    an

    =H.I1

    1 +

    1

    1n

    = 1

    1 +n

    = 1

    n+ 1an+1=

    1

    n+ 1

    an= 1

    nn N lm

    nan= 0

    an a1 = 1; a2 =

    3; a3 =

    3

    30 an

    >0

    2n+1

    5n

    >

    0

    an L 0

    L= lmn

    an+1= lmn

    Lan

    2

    52n+ 15n

    =

    2

    5L

    L= 0

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    c1 = 1000 10 %

    c2 = c1+c1 10

    10 0 =c1+c1 1

    10=c1

    1 +

    1

    10

    =c1 11

    10

    K

    10 %

    1110

    10 %

    K

    x %

    1 + x

    100

    K

    1 x100

    cn

    c1= 1000 c2= 1000

    1110

    10 %

    c3= 1000 1110

    910 10 %c4= 1000 11102 910 10 %

    c5= 1000

    1110

    2 910

    2

    10 %

    c6= 1000

    1110

    3 910

    2

    10 %

    c7= 1000

    1110

    3 910

    3

    10 %

    an

    an

    cn=

    1000 99

    100

    n12

    1000 99100

    n2 1 11

    10

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    cn n 2n n 2n 1

    c2n1= 1000

    99

    100

    n1

    c2n = 1000

    99

    100

    n1

    11

    10

    99100

    = 0, 99 < 1

    cn

    c2n

    c2n1

    cn lm

    nc2n = L

    lmn

    c2n1=L lmn

    cn=L

    lmn

    cn= 0

    cn L 0

    cn

    9 %

    1 9100

    = 91100

    L

    L

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    c1= 1000 c2= 1000

    1110

    10 %

    c3= 1000

    1110

    91100

    9 %

    c4= 1000

    1110

    2 91100

    10 %

    c5= 1000

    1110

    2 91100

    2

    9 %

    c6= 1000

    1110

    3 91100

    2

    10 %

    c7= 1000 1110

    3

    91100

    3

    9 %

    cn

    cn =

    1000 1001

    1000

    n12

    1000 10011000

    n21 11

    10

    c2n1= 1000

    1001

    1000

    n1

    c2n= 1000

    1001

    1000

    n1

    11

    10

    10011000

    = 1, 001> 1

    cn c2n c2n1

    +

    lmn cn= +

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    an 0

    an lmn an = L 0

    L >0

    1 = lmn

    Lan+1

    anL

    = lmn

    1n+ 1

    n

    r= r 0

    L= 0

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    an = 3n2 + 1

    n 0

    an

    bn

    n

    n

    bn=

    n+12 +1n+1

    2

    = 1 + 2n+1

    11+ 2

    n+1

    bn

    b2n1 = 1 +1

    nn 1

    b2n= 11 + 2

    2n+1

    n 1

    bn lm

    nb2n = L

    lmn

    b2n1 = L lmn

    bn = L

    lmn

    bn = 1

    L

    L

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    an>0n N

    an lm

    nan = L

    +

    M = lmn bn = lmn3an

    2an+ 1 = lmnan

    3

    an

    2 + 1an

    L

    = 3

    2+

    1

    L

    L

    R

    32

    L= +

    L R M < 3

    2

    M

    2

    L= + M

    32

    M

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    lmn

    3n

    n+ 1 = lm

    nn 3

    n

    1 + 1n0

    = 3

    an bn cn lmn an = lmn cn = L

    lmn bn=L

    an=n5

    6n

    lmn

    an= 0

    lmn

    n

    |an| = lmn

    n

    n5

    n

    6n= lm

    n

    nn1

    56

    =1

    6

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    f(an

    f(an) an f

    f

    an f

    1

    4

    lmn

    an = 1+

    1

    f(x)

    4x

    an

    f(x)

    f(an) 4

    +

    1

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    lmn

    n

    7notn

    1 2

    n

    n2= lm

    n7

    1 1n2

    n2

    e1

    2

    = 7e2 = 7e2

    0, 94< 1

    lmn

    5 3an= 0

    bn = 5

    lmn

    3an= 5

    cn =13

    lmn

    an =5

    3

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    xn 3

    1

    lmn

    xn=L R 1< L 3

    L

    1

    xn >1n N

    x1>1 xn

    L= 1

    L

    1< L 3

    1

    2xn

    lmn

    1 2xnL

    = 1 2L

    1< L 3 13 1

    L

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    an a

    a= 0

    lmn

    an = lmn

    n2

    6

    a+ 3bn2

    + 2n12

    n6

    n

    4

    5 3n3

    + 4n4

    = lmn

    +n2

    a=0

    a+0

    3bn2 +0

    2n 112 5 3

    n30

    + 4n40

    5

    =

    a = 0

    lm

    nan=

    a

    4

    a

    b

    a = 0 a= 0

    an= 3bn4 + 2n5n4 3n+ 4

    lmn

    an = lmn

    n4

    3b+ 2n12

    n4

    n

    4 5 3n3

    + 4n4

    = lmn3b+

    0 2n7

    5

    3

    n30 + 4

    n40

    =3b

    5

    4

    3b5

    = 4 3b= 20 b= 203

    a= 0

    b= 20

    3

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    n N xn+1 xn

    xn+1 xn 14

    +x2n xn

    x2n xn+1

    4 0

    xn 122

    0

    xn

    xn

    L

    a

    L

    an+1 an L

    L= lmn

    xn+1 = lmn

    1

    4+

    L2x2n =

    1

    4+L2

    L

    L2

    L+1

    4= 0

    12

    L=1

    2

    0< a 1

    2 n N 0< an 12

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    x1 = a

    0< x1

    12