gual bilni classes sbi po pre. 2019 · " cat " gmat " gre " ssc " bank...
TRANSCRIPT
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SBI PO (PRE) – 2019
Direction (1-5): What approximate value will come in place of the
question mark (?) in the following question? (You are not expected
to calculate the exact value)
funsZ’k ¼1&5½ % fuEu iz’u eas iz’u fpUg ¼\½ ds LFkku ij D;k vuqekfur eku
vk,xk\ ¼vkils lVhd eku dh x.kuk djus dh vis{kk ugha gSa½
1. 8.02 – (? – 9.01) + (10.92)2 = 120
(a) 0 (b) 18 (c) 21 (d) 24 (e) 23
2. 13.96 × 9.09 + 200.02 = ?
(a) 226 (b) 242 (c) 256 (d) 351 (e) 248
3. 6% of [(198.99)+(15.99)2] = ?
(a) 30 (b) 17 (c) 27 (d) 24 (e) 3
4. 1 1 1
14.96 3.94 ?− + = 0
(a) 5 (b) 8 (c) 10 (d) 12 (e) 3
5. ( )2
6.02 120.89 144.06− + = ?
(a) 35 (b) 42 (c) 37 (d) 40 (e) 33
6. Cost price of A is twice the cost price of B. If the selling price of B is
Rs. 3600 and it is sold at the profit of 20%, then find the cost price
of A.
A dk ykxr ewY; B ds ykxr ewY; ls nksxquk gSA ;fn B dk fcØh ewY;
3600 :i;s gS vkSj ml ij 20% ykHk izkIr gksrk gS] rks A dk ykxr ewY;
Kkr djsaaA
(a) Rs.3000 (b) Rs.6000 (c) Rs.8000
(d) Rs.2000 (e) Rs.10000
7. The cost price of the two chairs is same. Difference between their
selling prices is Rs. 90. On selling one chair, a person got a profit of
12% and on selling another he got a profit of 18%. Find the cost
price of each chair.
nks dqflZ;ksa dk ykxr ewY; cjkcj gSA mudh fcØh dh dherksa ds chp dk
varj :- 90 gSA ,d dqlhZ cspus ij ,d O;fDr dks 12% dk ykHk izkIr gksrk
gS ,oa nwljh dqlhZ dks cspus ij mls 18% dk ykHk izkIr gksrk gSA izR;sd
dqlhZ dh ykxr ewY; Kkr dhft,A
(a) Rs. 1200 (b) Rs. 1500 (c) Rs. 1800
(d) Rs. 2400 (e) Rs. 1000
8. 1500 rupees is invested in a scheme A at R% p.a. simple interest.
Another amount (1500 - x) is invested in scheme B at 2R % p.a.
simple interest. After 4 years, interest earned from scheme A is
25% less than that of scheme B. Find x.
1500 :i;s dh jkf’k dks Ldhe A esa R% dk lk/kkj.k C;kt dh nj ij fuos’k
fd;k x;k nwljh jkf’k (1500-x) dks Ldhe esa 2R% dh lk- C;kt dh nj
ij fuos’k fd;k x;k ;fn 4 lky ckn A dk C;kt B ds C;kt ls 25% de
gS rks x dk eku D;k gksxk\
(a) 500 (b) 600 (c) 900 (d) 1000 (e) 1200
9. Ratio of age A after two years to the present age of B is 5: 6 and ratio
of age of A 8 years hence to the age of B 6 year hence is 6: 7. Find
B’s present age.
nks o"kZ ckn A dh vk;q vkSj B dh orZeku vk;q dk vuqikr 5%6 gS vkSj 8
lky ckn A dh vk;q vkSj 6 lky ckn B dh vk;q dk vuqikr 6%7 gSA rks B
dh orZeku vk;q Kkr djsaA
(a) 30 (b) 34 (c) 36 (d) 28 (e) 24
10. 4 years ago, the ratio of ages of A and B was 9 : 11 and 6 years hence,
the ratio of ages of A and B will be 7 : 8. Find the present age of B.
4 lky igys A vkSj B dh vk;q dk vuqikr 9 % 11 vkSj 6 o"kZ ckn] A vkSj
B dh vk;q dk vuqikr 7 % 8 gksxkA orZeku esa B dh vk;q Kkr dhft,A
(a) 22 years (b) 24 years (c) 26 years
(d) 37 years (e) None of these
11. 4 years hence the sum of ages of A and B will be 16 years more than
the sum of the present ages of B and C. 4 years ago the sum of A’s
age and C’s age was 32 years, then what is the present age of C?
4 o"kZ ckn] A vkSj B dh vk;q dk ;ksx B vkSj C dh orZeku vk;q ds ;ksx ls
16 o"kZ vf/kd gksxkA ;fn 4 o"kZ igys A vkSj C dh dqy vk;q 32 o"kZ Fkh] rks
C dh orZeku vk;q D;k gS\
(a) 18 years (b) 14 years (c) 10 years
(d) 16 years (e) 12 years
12. A started business with Rs. 600 and B with Rs. 900. After 5 months
B left and C joined with capital Rs. 600 less than B. If at the end of
year profit of C was Rs 3500, then find the total profit at the end of
year.
A us 600 :i;s vkSj B us 900 :i;s ls ,d O;olk; 'kq: fd;kA 5 eghus
ckn B us bl O;olk; dks NksM+ fn;k vkSj C, B ls de 600 :i;s de ds
lkFk bl O;olk; ls tqM+ x;kA ;fn o"kZ ds var esa C dk ykHk 3500 :i;s
FkkA rks o"kZ ds var esa dqy ykHk Kkr djsaA
(a) Rs. 46000 (b) Rs. 36000 (c) Rs. 28000
(d) Rs. 23000 (e) None of these
13. A container contains a mixture of milk and water in which water is
24%. 50% of the mixture is taken out in which water is 78 litre less
than the milk. Find the initial quantity of water in that container?
,d crZu A esa nw/k vkSj ikuh gS ftlesa ikuh 24% gS 50% feJ.k dks fudky
fy;k tkrk gS ;fn cps feJ.k esa ikuh rFkk nw/k dh ek=k dk vUrj 78 yh-
gS rks crkvks izkjEHk esa ikuh dh ek=k fdruh gS\
(a) 171 lit (b) 152 lit (c) 72 lit (d) 108 lit (e) 114 lit
14. 40 men can complete a work in 48 days. If 64 men started working
and after X days, 32 more men joined the work. If the remaining
work is completed in 2
163
days, then find the value of X.
40 O;fDr ,d dke dks 48 fnuksa esa iwjk dj ldrs gSaA ;fn 64 O;fDr dk;Z
djuk 'kq: djrs gS vkSj X fnuksa ds ckn 32 yksx vkSj dk;Z djus esa 'kkfey
gksrs gSA ;fn 'ks"k dke 2
163fnuksa esa iwjk dj fn;k tkrk gS] rks] X dk eku
Kkr djsa\
(a) 2 (b) 5 (c) 8 (d) 4 (e) 6
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15. Train A crosses a vertical pole at the speed of 15 m/s in 20 seconds.
Speed of train A is 3 m/s less than the speed of train B and length
of train B is 30 meter less than length of train A. Find the time taken
by Train B to cross 270 meter long platform.
Vªsu A 20 lsdaM esa 15 ehVj@lsdaM dh nj ij ,d Å/okZ/kj [kaHks dks ikj
djrh gSA Vªsu A dh xfr Vªsu B dh xfr ls 3 ehVj@lsdaM de gS vkSj Vªsu
B dh yackbZ Vªsu A dh yackbZ ls 30 ehVj de gSA Vªsu B }kjk 270 ehVj yacs
IysVQkeZ dks ikj djus esa yxus okyk le; Kkr djsaA
(a) 20 seconds (b) 15 seconds (c) 30 seconds
(d) 45 seconds (e) 40 seconds
16. The ratio of speed of a boat in still water to speed of the current is
10 : 1. If ratio of the time taken by the boat to travel D km
downstream to the time taken to travel (D – 45) km upstream is 3 :
2. Find the value of D.
fLFkj ikuh esa ,d uko dh xfr ,oa /kkjk dh xfr dk vuqikr 10 % 1 gSA
;fn /kkjk ds cgko ds lkFk D fdeh dh ;k=k djus esa fy, x, le; vkSj
/kkjk ds izokg ds foijhr (D - 45) fdeh ;k=k djus ds chp fy, x, le;
dk vuqikr 3 % 2 gS] rks D dk eku Kkr djsaA
(a) 88 (b) 54 (c) 110 (d) 99 (e) 66
Direction(17-21): In the following question, two equations are
given in variables X and Y. You have to solve these equations and
determine the relation between X and Y.
funsZ’k ¼17&21½% fuEufyf[kr iz’u esa pj X vkSj Y esa nks lehdj.k fn, x;s
gSaA bu lehdj.kksa dks gy dhft;s] ,oe X vkSj Y ds chp lEcU/k Kkr
dhft;sA
17. A) 5x + 2y = 31
B) 3x + 7y = 36
(a) X > Y (b) X ≥ Y (c) X < Y
(d) X ≤ Y (e) X = Y or No relation can be established
18. A) x2 – 7x + 12 = 0
B) y2 – 9y + 20 = 0
(a) X > Y (b) X ≥ Y (c) X < Y
(d) X ≤ Y (e) X = Y or No relation can be established
19. A) (x + 1)2 = 122
B) y2 + 2y – 143 = 0
(a) X > Y (b) X ≥ Y (c) X < Y
(d) X ≤ Y (e) X = Y or No relation can be established
20. 6x2 + 5x + 1 = 0
4y2 + 4y + 1 = 0
(a) If X > Y (b) If X < Y (c) If X ≥ Y
(d) If X ≤ Y (e) If X = Y or no relation can be established
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21. x2 – 16x + 64 = 0
Y2 = 64
(a) If X > Y (b) If X < Y (c) If X ≥ Y
(d) If X ≤ Y (e) If X=Y or No relation can be established
22. Cost of gardening the circular field C at Rs.10 per meter square is
Rs.3465. Side of the square field S is equals to the diameter of the
circular field C. find the perimeter of square field.
xksykdkj {ks= C dks 10 :i;s izfr ehVj oxZ dh nj ij ckxokuh djus dh
ykxr 3465 :i;s gSA oxkZdkj {ks= S dh Hkqtk] xksykdkj {ks= C ds O;kl ds
cjkcj gSA oxkZdkj {ks= dk ifjeki Kkr djsaA
(a) 108 (b) 84 m (c) 78 m
(d) 112 m (e) None of these
Direction(23-27): Find the missing term in given series.
funsZ’k ¼23&27½% nh xbZ J`a[kyk esa yqIr 'kCn Kkr dhft,A
23. 15, 8, 9, 15, 32, ?
(a) 82.5 (b) 81.5 (c) 84.5 (d) 80.5 (e) 86
24. 18, 24, 36, 56, 86,?
(a) 128 (b) 118 (c) 124 (d) 130 (e) 126
25. 222, 110, 54, 26, ?
(a) 8 (b) 11 (c) 13 (d) 9 (e) 12
26. 2, 1, 1, 1.5, 3, ?
(a) 4.5 (b) 6 (c) 7.5 (d) 8 (e) 7.2
27. 26, 63, 124, 215, ?
(a) 315 (b) 421 (c) 342 (d) 426 (e) 388
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Direction(28-32): Study the following pie-chart and table
carefully to answer the questions that follow.
funsZ’k ¼28&32½ % fuEufyf[kr iz’uksa dk mŸkj nsus ds fy, fuEufyf[kr
rkfydk ,oa ikbZ pkVZ dk /;kuiwoZd v/;;u djsaA
Percentage of visitors (male and female) in a museum on the given
3 days-Friday, Saturday and Sunday is depicted in the pie chart
given below.
laxzgky; esa rhu fnuksa&’kqØokj] 'kfuokj vkSj jfookj esa vk, vkxarqdksa ¼iq:"k
vkSj efgyk½ dk izfr’kr uhps fn, x, ikbZ pkVZ esa n’kkZ;k x;k gSA
Total number of visitors on the given three days = 400
fn;s x, rhu fnuksa esa dqy vkxarqdksa dh la[;k 400 gSA
Percentage of visitors
Ratio of male visitors to female visitors on the given three days is
depicted in the table given below:
fuEufyf[kr rkfydk esa rhu fnuksa eas vkus okys iq:"k ,oa efgyk vkxarqdksa ds
e/; dk vuqikr n’kkZ;k x;k gS%
Days Male : Female
Friday 2 : 3
Saturday 7 : 5
Sunday 5 : 4
28. On Tuesday, the number of female visitors was 1/5 more than that
of Saturday. If the respective ratio between the number of male
visitors and that of female visitors on Tuesday is 11 : 6, then what
was the total number of visitors (male and female) on Tuesday?
Ekaxyokj ds fnu efgyk vkxarqdksa dh la[;k 'kfuokj ds fnu efgyk vkxarqdks
dh la[;k ls 1@5 T;knk FkhA ;fn eaxyokj ds fnu iq:"k vkxarqdksa ,oa
efgyk vkxarqdksa dk vuqikr Øe’k% 11 % 6 Fkk] rks eaxyokj ds fnu vkxarqdksa
¼iq:"k ,oa efgyk½ dh la[;k D;k gS\
(a) 208 (b) 170 (c) 182 (d) 130 (e) 156
29. What is the total number of male visitors on the given 3 days
together?
fn;s x;s rhuksa fnuksa esa iq:"k vkxarqdksa dh dqy la[;k D;k gS\
(a) 220 (b) 230 (c) 200 (d) 210 (e) 190
30. Out of the total number of visitors on Saturday, 35% were adults.
The cost for 1 adult’s ticket is double that for one child’s ticket. If
the total amount collected from selling tickets on Saturday was
Rs.8100. What is the cost of 1 adult’s ticket?
'kfuokj dks vk, dqy vkxarqdksa esa ls 35% o;Ld gSA ,d o;Ld ds fVdV
dh dher ,d cPps dh fVdV dh dher ls nksxquh gSA ;fn 'kfuokj dks
csph xbZ fVdVksa ls dqy 8100 :i, izkIr gksrs gSA rks ,d o;Ld ds fVdV
dh dhe fdruh gS\
(a) Rs.200 (b) Rs.160 (c) Rs.120 (d) Rs.100 (e) Rs.50
31. What is the central angle corresponding to the number of visitors
(male and female) on Sunday (in degrees)?
jfookj ¼fMxzh esa½ dks vkxarqdksa ¼iq:"k vkSj efgyk½ dh la[;k ds laca/k esa
dsanzh; dks.k fdruk gS\
(a) 172.8° (b) 165.6° (c) 162° (d) 154° (e) 198°
32. The number of female visitors on Friday was what percentage of
the number of female visitors on Sunday?
'kqØokj dks efgyk vkxarqdksa dh la[;k jfookj dks efgyk vkxarqdksa dh la[;k
dh fdruh izfr’kr Fkh\
(a) 70% (b) 85% (c) 80% (d) 65% (e) 75%
Direction(33-37): The bar graph shows the total number of male
and female lives in four different towns and table shows the
number of males and females whose ages are above 40 years. Read
the data carefully and answer the questions below:
funsZ’k ¼33&37½ % ckj xzkQ pkj vyx&vyx dLcksa esa jgus okys iq:"kksa vkSj
efgykvksa dh dqy la[;k dks n’kkZrk gS vkSj rkfydk esa mu iq:"kksa vkSj
efgykvksa dh la[;k dks n’kkZrh gS ftudh vk;q 40 o"kZ ls vf/kd gSA tkudkjh
dks /;kuiwoZd i<+s vkSj uhps fn, x, iz’uksa ds mŸkj nsa%
Name of the town Number of males and females whose ages are above 40 years
A 50
B 70
C 110 D 120
33. Find the average number of those males and females whose ages
are below and equals to 40 years of town A, C and D.
mu iq:"kksa vkSj efgykvksa dh vkSlr la[;k Kkr djsa ftudh vk;q 'kgj A,
C vkSj D es 40 lky ls de ;k mlds cjkcj gSA
(a) 180 (b) 160 (c) 190 (d) 200 (e) 210
34. Find the ratio of the those number of males and females whose ages
are above 40 years in town A and B to those males and females
whose ages are below and equals to 40 years in town D.
og iq:"k vkSj efgyk,a ftudh vk;q 'kgj A vkSj B esa 40 o"kZ ls vf/kd gS]
vkSj og iq:"k vkSj efgyk,a ftudh vk;q 'kgj D esa 40 o"kZ ls de vkSj
mlds cjkcj gS] dh la[;k dk vuqikr Kkr djsaA
(a) 1: 1 (b) 3: 5 (c) 2: 5 (d) 4: 7 (e) 1: 3
35. If 40% of population in town B whose ages are below and equals to
40 years are male and 40% of population in town D whose ages are
below and equals to 40 years are female. Find the difference
between the females of town B and D whose ages are below and
equals to 40 years.
;fn 'kgj B esa 40% tula[;k ftudh vk;q 40 o"kZ ls de vkSj mlds cjkcj
gS] iq:"k gS vkSj 'kgj D esa 40% tula[;k ftudh vk;q 40 o"kZ ls de vkSj
mlds cjkcj efgyk,¡ gSA 'kgj B vkSj D dh mu efgykvksa ds chp varj Kkr
djs ftudh vk;q 40 o"kZ ls de vkSj mlds cjkcj gSaA
(a) 46 (b) 52 (c) 49 (d) 58 (e) 39
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36. Number of males and females in town A whose ages are below and
equals to 40 years is what percent less than those number of males
and females in town D whose ages are below and equals to 40 years.
'kgj A esa iq:"kksa vkSj efgykvksa dh la[;k ftudh vk;q 40 o"kZ ls de ;k
mlds cjkcj gS] 'kgj D esa mu iq:"kksa vkSj efgykvksa dh la[;k dh rqyuk esa
fdrus izfr’kr de gS ftudh vk;q 40 lky ls de ;k mlds cjkcj gSA
(a) 10% (b) 12% (c) 7% (d) 5% (e) 17%
37. If in another town E, total males and females are 10% more than
the total males and females in town A and those males and females
whose ages are above 40 years is 20% more than those males and
females whose ages are above 40 years in town C. Find the number
of those males and females in town E whose ages are below and
equals to 40 years.
;fn ,d 'kgj E esa] dqy iq:"k vkSj efgyk,a] 'kgj A ds dqy iq:"kksa vkSj
efgykvksa dh rqyuk esa 10% vf/kd gS vkSj os iq:"k vkSj efgyk,a ftudh mez
40 lky ls vf/kd gS] mu iq:"kksa vkSj efgykvksa dh rqyuk essaa 20% vf/kd gS
ftudh vk;q 'kgj C esa 40 ls vf/kd gSA 'kgj E esa mu iq:"kksa vkSj efgykvksa
dh la[;k Kkr djsa ftudh vk;q 40 o"kZ ls de vkSj mlds cjkcj gSaA
(a) 132 (b) 128 (c) 142 (d) 124 (e) 138
Directions (38-42): Study the given information carefully and
answer the question that follow.
3 pizza shops A, B and C sells veg pizza and non veg pizza.
Respective ratio between number of vegetarian and non-
vegetarian pizzas sold by pizza shop A was 9 : 7 and that sold by
pizza shop B was 3 : 4. The no. of pizzas (Veg + non veg) sold by
pizza shop C was 108 and respective ratio between number of
vegetarian and non-vegetarian pizza sold by pizza shop C was 7 : 5
Total number of pizza sold by all three pizza shop was 376. Number
of veg pizza sold by pizza shop A was 20% more than the veg pizza
sold by pizza shop B.
funsZ’k ¼38&42½ % nh xbZ lwpuk dks /;ku ls i<+s vkSj mldk mŸkj nsA
rhu fiTtk nqdku] A, B rFkk C }kjk ost fiTtk rFkk ukWu ost fiTtk csps
tkrs gSA A,B ds }kjk csps x;s ost rFkk ukWu ost fiTtk dk vuqikr Øe’k%
9%7 rFkk 3%4 gSA C ds }kjk dqy 108 fiTtk ¼ost rFkk ukWu ost½ csps tkrs
gS C ds }kjk csps x;s ost rFkk ukWu ostu fiTtk dk vuqikr 7%5 gS rhuks
nqdku }kjk dqy 376 fiTtk csps x;sA A ds }kjk csps x;s ost fiTtk] B ds
}kjk csps x;s ost fiTtk ls 20% T;knk gSA
38. If cost of each veg pizza and each non-veg pizza sold by shop B is Rs
200 and Rs 300 respectively then find the total amount obtained by
shop B (in Rs).
;fn B ds izR;sd ost fiTtk rFkk ukWuost fiTtk dk ewY; Øe’k% 200 vkSj
300 gS rks B ds }kjk csps x;s fiTtk ls fdruk ewY; izkIr gqvkA
(a) 40,000 (b) 36000 (c) 48000
(d) 32000 (e) 44000
39. What is the ratio of veg pizza sold by shop A & C together to the
non-veg pizza sold by shop B & C together.
A vkSj C ds }kjk csps x;s ost fiTtk rFkk B ,oa C ds }kjk csps x;s ukWuost
fiTtk ds lkFk D;k vuqikr gSA
(a) 27 : 25 (b) 27 : 29 (c) 29 : 27
(d) 25 : 27 (e) 23 : 25
40. What is the average of veg pizza sold by all shops?
lHkh nqdku }kjk csps x;s ost fiTtk dk vkSlr D;k gksxk\
(a) 61 (b) 68 (c) 62 (d) 60 (e) 65
41. Total veg pizzas sold by Shop A and C are what percent of total non-
veg pizza sold by shop B & C?
A vkSj C ds }kjk csps x;s ost fiTtk B rFkk C ds }kjk csps x;s ost fiTtk
dk fdruk izfr’kr gS\
(a) 113% (b) 108% (c) 109% (d) 112% (e) 116%
42. If Veg pizza sold by shop B is increased by 1
33 %3
and non-veg
pizza sold by shop A is increased by 75% then what is the sum of
veg pizza sold by B and non-veg pizza sold by A after increment.
;fn B ds }kjk csps x;s ost fiTtk 1
33 %3
rFkk A ds }kjk csps x;s ukWuost
fiTtk 75% c<+ tkrs gS rks B ds ost rFkk A ds ukWuost fiTtk dk dqy ;ksx
fdruk gksxk\
(a) 178 (b) 186 (c) 198 (d) 200 (e) 182
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1. (b)
8.02 – (? – 9.01) + (10.92)2 = 120
⇒ 8 – ? + 9 + (11)2 = 120
⇒ 8 – ? + 9 + 121 = 120
⇒ ? = 138 – 120
⇒ ? = 18
2. (b)
? = 14 × 3 + 200
⇒ ? = 42 + 200
⇒ ? = 242
3. (c)
6% of [(198.99)+(15.99)2]= ?
? = 6
10× [199 + (16)2]
? = 6
10× [199 + 256]
? = 6
10× 455
? = 27.30
? ≈ 27
4. (a)
1 1 1
- +14.96 3.94 ?
= 0
1 1 1
= -? 4 15
1 15- 4
=? 60
1 11
=? 60
? = 60
11≈ 5
5. (c)
(6.02)2 - 120.89 144.06+ = ?
? = (6)2 - 121 144+
? = 36 – 11 + 12
? = 37
6. (b)
Given, selling price of B = 1.20 × cost price of B
⇒ Cost price of B = 3600 ÷ 1.20 = Rs.3000
Cost Price of A = 2 × Cost price of B
Hence, the cost price of A = 2 × Rs.3000 = Rs.6000.
7. (b)
Let CP of the Article 100x Rs.
So SP of first Article at 12% gain= 112x Rs.
And SP of second Article at 18% gain = 118x Rs.
118x – 112x= 90
6x = 90
X= 15
So CP of the Article = 100x =1500 Rs.
8. (a)
Interest earned from scheme A = 1500×R ×4
100= 60R
Interest earned from scheme B
= ( ) ( )1500- x ×2R ×4 2R 1500- x
=100 25
60R = ( )2R 1500- x3
×4 25
1500 – x = 1000
X = 500
9. (c)
Let the age of A be x years and age of B be y years,
❖ Neon Approach (Thought Process):
(10.92)2 and 120 is approximately same
Then x = 8 + 9 = 17 ~ 18
❖ Neon Approach (Thought Process):
Aryan Ratio :
CP of A = 3600
6× 5× 2 = 6000
❖ Neon Approach (Thought Process):
∴ Option (a) and (d) impossible gS D;ksafd ;g cgqr
de gSA
∴ CP of A 7200 ls de gksxk ,slk dsoy option (b) gSA
❖ Neon Approach (Thought Process):
Aryan Ratio :
CP of each chair = 90
6× 100 = 1500
❖ Neon Approach (Thought Process):
Ratio of interest of A and B = 3 : 4
If Rate of interest of B is same then
A : B
3 : 2
500× ×500
1500 1000 x = 1500 – 1000
= 500
Solutions
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A + 2
B=
5
6
6A + 12 = 5B
6A – 5B = - 12 ---------- (i)
A + 8 6
=B + 6 7
7A + 56 = 6B + 36
7A – 6B = - 20 ----------- (ii)
On solving eq. (i) and (ii), we get
A = 28 and B = 36
10. (c)
Let the ages of A and B be 9X and 11X, then
9 10 7
11 10 8
x
x
+=
+
⇒ 72X + 80 = 77X + 70
⇒ X = 2
Hence, the present age of B = 11X + 4 = 22 + 4 = 26 years
11. (d)
Present age of A and C:
A + C = 40 ............(i)
After 4 years, sum of ages of A and B will be 16 years more than
the sum of the present ages of B and C.
A + 4 + B + 4 = B + C + 16
A - C = 8 ............(ii)
On solving eq(i) and eq(ii).
2A = 48
A = 24
Then, the present age of C:
24 + C = 40
C = 16 Years
12. (d)
Ratio of the equivalent capitals of A, B and C for 1 month
= 600 × 12 : 900 × 5 : 300 × 7 = 24 : 15 : 7
7 ≡ Rs. 3500
⇒ 1 ≡ Rs. 500
The total profit at the end of year = 24 + 15 + 7 = 46 ≡ 46 × Rs.
500 = Rs. 23000
13. (e)
Let the quantity of mixture be 100x lit
Quantity of milk= 76x lit
And quantity of water= 24x lit
Quantity of water taken= 12x lit
Quantity of milk taken= 38x lit
26x=78
x=3 lit
required quantity of water = 24×3 = 72 lit
14. (b)
Total work = 48× 40 = 1920 units
Now,
1920 = 64 × X + (64 + 32) × (50/3)
⇒ 1920 = 64X + 1600
⇒ 64X = 320
⇒ X = 5
❖ Neon Approach (Thought Process):
A (2 year hence) : B (Present)
5 : 6
A (8 year hence) : B (6 year hence)
6 : 7
difference is same
B’s Present Age = 6
1× 6 = 36
❖ Neon Approach (Thought Process):
B dh Present Age esa 6 tksM+us ij og 7 dk Multiple
gksxh ,slk dsoy option (c) gSA
❖ Neon Approach (Thought Process):
A : B
-4 +6
9 : 11 A : B 7 : 8 = 1 × 2
14 : 16 = 2
Present age of B =10
5× 11 + 4 = 26 year
❖ Neon Approach (Thought Process):
B dh present age esa 6 tksM+us ij og 8 dk Multiple
gksxh ,slk dsoy option (c) gSA
❖ Neon Approach (Thought Process):
Present age of A and B is 8 year more than B and C
A – C = 8
A + C = 32 + 8 = 40
A = 24
C = 16
❖ Neon Approach (Thought Process):
The ratio of Milk and water = 19 : 6
Aryan Ratio :
Initial quantity of water = 78
6.5× 6 = 72
❖ Neon Approach (Thought Process):
40 × 48 =( )
64×x 96×50=
y 3 1- y
y =1
6or x = 5 days
❖ Neon Approach (Thought Process):
40 × 48 = 96 × D
D = 20
Remaining day = 20 - 2 1
16 33 3=
96 × 10
3= 64 × D
D = 5 days
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15. (c)
Let the length of Train A be L meters, then According to
question,
L
15= 20
⇒ L = 300 m
∴ Length of train A is 300 m
So, length of train B = 300 – 30 m = 270 meters
Speed of train B = 15 + 3 = 18 m/s
When B crosses a 270 m long platform,
Time = 270 270
18
+seconds = 30 seconds
Hence, the required time = 30 seconds.
16. (d)
Let ratio of speed of a boat in still water to speed of the current
is 10x : x, then
( )
( )
D/ 10+1 x 3=
D- 45/ 10-1 x 2
⇒ 18D = 33D – 33 × 45
⇒ 15D = 33 × 45
⇒ D = 99
17. (a)
A) (5x + 2y = 31) × 3
B) (3x + 7y = 36) × 5
15x + 6y = 93 ..... (i)
15x+35y= 180 .... (ii)
On solving both equations, we get
x = 5 and y = 3
so, X > Y
❖ Neon Approach (Thought Process):
∴ x days work = (8×48) – 64 = 320
∴ x = 320
64= 5
❖ Neon Approach (Thought Process):
down stream : upstream
Speed 11 : 9
Time 3 : 2
Distance 33 : 18
D =45
15× 33 = 99 km
❖ Neon Approach (Thought Process):
5x + 2y = 31 …...(1)
3x + 7y = 36 ……(2)
Subtract equation (2) - equation (1)
5y – 2x = 5
x = 2.5 (y - 1)
y always +ve then
x > y
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18. (d)
A) x2 – 7x + 12 = 0
⇒ x(x – 4) – 3(x – 4) = 0
⇒ (x – 4)(x – 3) = 0
So, x = 3, 4
B) y2 – 9y + 20 = 0
⇒ y(y – 5) – 4(x – 5) = 0
⇒ (y – 5)(y – 4) = 0
So, y= 4, 5
Hence, X ≤ Y
19. (e)
A) (x + 1)2 = 122
⇒ (x + 1)2 – 122 = 0
⇒ (x + 1 – 12)(x + 1 + 12) = 0
⇒ (x – 11)(x + 13) = 0
x = 11, –13
B) y2 + 2y – 143 = 0
⇒ y2 + 13y – 11y – 143 = 0
⇒ y(y + 13) – 11(y + 13) = 0
⇒ (y + 13)(y – 11) = 0
y = 11, – 13
So, no relation can be established.
20. (c)
6x2 + 5x + 1 = 0
⇒ 6x2 + (3 + 2)x + 1 = 0
⇒ 3x(2x + 1) + (2x + 1) = 0
⇒ (3x + 1)(2x + 1) = 0
⇒ x = –1/3, –1/2
4y2 + 4y + 1 = 0
⇒4y2 + (2 + 2)y + 1 = 0
⇒ (2y + 1)2 = 0
⇒ y = –1/2
So, X ≥ Y
21. (c)
x2 – 16x + 64 = 0
⇒ (x – 8)2 =0
⇒ x = 8
Y2 = 64
⇒ Y = ± 8
So, X ≥ Y
22. (b)
Let r meter be the radius of circular field C, then
Area of circular field C × 10 = 3465
⇒ πr2 × 10 = 3465
⇒ r2 = 441
4
⇒ r = 21
2m
Side of square field S = 2 × r = 21m
Perimeter of square field = 4 × 21 = 84 meters
23. (a)
15 × 0.5 + 0.5 = 8
8 × 1 + 1 = 9
9 × 1.5 + 1.5 = 15
15 × 2 + 2 = 32
32 × 2.5 + 2.5 = 82.5
24. (a)
The pattern of the series is:
25. (e)
222 ÷ 2 - 1 = 110
110 ÷ 2 - 1 = 54
54 ÷ 2 - 1 = 26
❖ Neon Approach (Thought Process):
+ + - -
- - + +
+ - - +
- - + -
x2 – 7y + 12 = 0 y2 – 9y + 20 = 0
x = +4 y = +5 x < y
x = +3 y = +4
❖ Neon Approach (Thought Process):
+ + - -
- - + +
+ - - +
- - + -
(x+1)2 = 122 y2 + 2y - 143 = 0
x = + y = +
We can find the Answer with the sign
So relation cannot establish.
❖ Neon Approach (Thought Process):
+ + - -
- - + +
+ - - +
- - + -
6x2 + 5y + 1 = 0 7y2 + 4y + 1 = 0
x = 3
6− y =
2
4− Ans. x > y
x = 2
6− y =
2
4−
❖ Neon Approach (Thought Process):
+ + - -
- - + +
+ - - +
- - + -
22 – 16x + 64 = 0 y2 = 64
x = 8 y = + 8 Ans. x > y
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26 ÷ 2 - 1 = 12
26. (c)
The pattern of the series is:
2 × 0.5 = 1
1 × 1 = 1
1 × 1.5 = 1.5
1.5 × 2 = 3
3 × 2.5 = 7.5
27. (c)
26 = 33 – 1,
63 = 43 – 1,
124 = 53 – 1,
215 = 63 – 1,
342 = 73 – 1
28. (b)
Day Male Female Total
Friday 40 60 100
Saturday 70 50 120
Sunday 100 80 180
Number of female visitors on Tuesday = 50 + 1/5th of 50 = 50
+ 10 = 60
Number of male visitors on Tuesday = (11/6) × 60 = 110
Hence, the total number of visitors on Tuesday = 60 + 110 =
170.
❖ Neon Approach (Thought Process):
Aryan Ratio :
⇒ 4 × 30 × 5 6 17
12 5 6 = 170
❖ Neon Approach (Thought Process):
m : f
11 : 6 = 17
Answer will be multiple of 17
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29. (d)
Day Male Female Total
Friday 40 60 100
Saturday 70 50 120
Sunday 100 80 180
The total number of male visitors on the given 3 days together
= 40 + 70 + 100 = 210.
30. (d)
Day Male Female Total
Friday 40 60 100
Saturday 70 50 120
Sunday 100 80 180
Let cost of 1 adult’s ticket = Rs. 2x, then cost of 1 child’s ticket =
Rs. X
(35% of 120)× 2x + (65% of 120) × x = 8100
⇒ 84x + 78x = 8100
⇒ x = 8100/162 = 50
Hence, cost of 1 adult’s ticket = Rs. 2x = 2× Rs. 50 = Rs.100.
31.
32. (e)
Day Male Female Total
Friday 40 60 100
Saturday 70 50 120
Sunday 100 80 180
Required percentage = (60/80) × 100 = 75%.
33. (a)
Required average = (190 + 150 + 200) ÷ 3 = 540 ÷ 3 = 180
34. (b)
Required ratio = 50 + 70: 200 = 120: 200 = 3: 5
35. (a)
Number of females in town B whose ages are below and equals
to 40 years = 210 × 0.60 = 126
Number of females in town D whose ages are below and equals
to 40 years = 200 × 0.40 = 80
Required difference = 126 – 80 = 46
36. (d)
Required percentage = 200 190
200
−× 100 = 5%
37. (a)
Total males and females in town E = 1.10 × 240 = 264
Number of males and females whose ages are above 40 years =
1.20 × 110 = 132
Required answer = 264 – 132 = 132
38. (b)
A B C
Veg 72 60 63
Non-Veg 56 80 45
Required total amount = 60 × 200 + 80 × 300 = 12000 + 24000
= 36000
39. (a)
Required ratio =72+63
80+ 45=
135 27=
125 25
❖ Neon Approach (Thought Process):
M : F
Friday 2 : 3 = 5
Saturday 7 : 5 = 12 ÷ 2
Sunday 5 : 4 = 9
the percentage of male
[2+3.5+5]×5 = 52.5%
Total male = 4×52.5 = 210
❖ Neon Approach (Thought Process):
Adult : Children
No. of person 7 : 13 = 20
Price of Ticket 2 : 1 = 3
Total amount 14 : 13 = 27
Total person on Saturday = 30% of 400 = 120
That is 6 time of 20
Aryan Ratio :
Price of Adult = 8100
27×6× 2 = 100
❖ Neon Approach (Thought Process):
360
100× 45 = 162
❖ Neon Approach (Thought Process):
Friday : Saturday
Female 3 : 4
⇒ 3
4× 100 = 75%
❖ Neon Approach (Thought Process):
Total male and female in A, C, D (below or equal to
the 40 year)
= 190 + 150 + 200 total excess (40+50 = 90)
Required Average = 150 + 90
3= 180
❖ Neon Approach (Thought Process):
210 × 60% - 200 × 40%
= 46 (Apply digit sum) (unit digit)
❖ Neon Approach (Thought Process):
Number of those male and female in town E whose
ages are below or equal to 40
= 240 ×11
10- 110 ×
6
5
= 132 (Answer will be multiple of 11) only (a) option
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40. (e)
Required ratio = 72+60+63
3= 65
41. (b)
Required ratio = 135
125× 100 =
27
25× 100 = 108%
42. (a)
Required sum = 4
3× 60 +
7
4× 56 = 80 + 98 = 178
38-42.
38.
39.
40.
41.
42.
❖ Neon Approach (Thought Process):
V. Pizza : N.V. Pizza
A 9 : 7 = 16 × 2 = 32 × 4
B 3 : 4 = 7 × 5 = 35 268
C 7 : 5 = 12 ---×9--------108
A : B
Veg Pizza 6 : 5
❖ Neon Approach (Thought Process):
B V : N
Pizza 3 : 4
Cost 2 : 3
Total 6 : 12 = 18
(Answer will be multiple of a only (b) option)
❖ Neon Approach (Thought Process):
(A+C) veg Pizza : (B+C) Non Veg Pizza
9×2×4+7×9 : 4×5×4+5×9
135 : 125
27 : 25
❖ Neon Approach (Thought Process):
Average = 135 + 650 =195
3= 65
❖ Neon Approach (Thought Process):
Receive Percentage =27
25× 100 = 108%
❖ Neon Approach (Thought Process):
Total sum = 60 ×4
3+ 56 ×
7
4= 178