grade 8 | unit 1 factoring
TRANSCRIPT
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STUDY GUIDE
GRADE 8 | UNIT 1
Factoring
Table of Contents
Introduction ......................................................................................................................................... 3
Test Your Prerequisite Skills ............................................................................................................. 4
Objectives ............................................................................................................................................ 5
Lesson 1: Factoring Polynomials with a Common Monomial Factor
- Warm Up! ................................................................................................................................. 5
- Learn about It! ........................................................................................................................ 6
- Let’s Practice! .......................................................................................................................... 7
- Check Your Understanding! ................................................................................................ 12
Lesson 2: Factoring the Difference of Two Squares
- Warm Up! ............................................................................................................................... 13
- Learn about It! ...................................................................................................................... 15
- Let’s Practice! ........................................................................................................................ 17
- Check Your Understanding! ................................................................................................ 22
Lesson 3: Factoring the Sum or Difference of Two Cubes
- Warm Up! ............................................................................................................................... 23
- Learn about It! ...................................................................................................................... 24
- Let’s Practice! ........................................................................................................................ 25
- Check Your Understanding! ................................................................................................ 30
Lesson 4: Factoring Perfect Square Trinomials
- Warm Up! ............................................................................................................................... 31
- Learn about It! ...................................................................................................................... 32
- Let’s Practice! ........................................................................................................................ 34
- Check Your Understanding! ................................................................................................ 39
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Lesson 5: Factoring General Trinomials
- Warm Up! ............................................................................................................................... 40
- Learn about It! ...................................................................................................................... 41
- Let’s Practice! ........................................................................................................................ 42
- Check Your Understanding! ................................................................................................ 49
Challenge Yourself! .......................................................................................................................... 49
Performance Task ............................................................................................................................ 50
Wrap-up ............................................................................................................................................. 54
Key to Let’s Practice! ......................................................................................................................... 55
References ........................................................................................................................................ 56
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STUDY GUIDE
GRADE 8 | MATHEMATICS
UNIT 1
Factoring Mathematics relies on logic and creativity, and it is studied both for its theoretical and
practical applications. For some people, not just the
professionals, the pursuit to understand the essence of
mathematics lies in the study of patterns and relationships.
For grade 8 students, the pursuit to study mathematics starts
with the understanding of the concepts of polynomials.
For some, it is not outright clear when or where the application of the study polynomials
can be readily applied. However, even the simplest tasks or scenarios can be modeled
using polynomials.
Have you ever wondered how architects maximize and design a
certain floor plan of a house or a building? …or how an engineer
computes for the right mixture of cement and gravel to be used for
the foundations of skyscrapers and other infrastructures? …or simply
how a carpenter builds a cabinet or drawer using limited supplies?
In this unit, you will learn about the different factoring techniques that
will be useful in simplifying polynomials as well as their applications in the real world.
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Table of Contents
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Before you get started, answer the following items to help you assess your prior
knowledge and practice some skills that you will need in studying the lessons in this unit.
1. List all the positive integer factors of the given number.
a. 9 b. 16 c. 51
2. Perform the indicated operation.
a.
b.
c.
d.
e.
f.
3. Expand the following expressions using special product formulas.
a.
b.
c.
d.
4. Give the formulas for the following:
a. area of a rectangle
b. area of a square
c. area of a triangle
d. area of a circle
e. volume of a cube
f. volume of a rectangular prism
Computing the area and volume of two- and three-dimensional figures
Performing basic operations on polynomials
Finding special products
Test Your Prerequisite Skills
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At the end of this unit, you should be able to
factor completely different types of polynomials (polynomials with common
monomial factor, difference of two squares, sum and difference of two cubes,
perfect square trinomials, and general trinomials; and
solving problems involving factors of polynomials.
Something Common
Materials Needed: fishbowl, pen and paper
Instructions:
1. This activity may be played by the whole class.
2. Your teacher has prepared a fishbowl with rolled small pieces of papers having
monomials written on them.
3. Each one of you is to pick a piece of rolled paper without looking at it. You must
also not show the content of your paper to any of your classmates just yet.
4. After each of your classmates has taken his or her pick, each one of you may
open the rolled paper and take a look at the monomial you got.
5. Each one of you must then go around the classroom and find two other persons
with monomials that have a common factor (except 1) with your monomial. The
common factor may be numerical (numeral) or literal (variable) or a combination
of both. You are free to talk while in search for your partners that would form a
triad.
Lesson 1: Factoring Polynomials with a Common
Monomial Factor
Objectives
Warm Up!
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Examples of monomials with common factors:
and (Both have 3 as a common numerical factor.)
and (Both have as a common literal factor.)
and (Both have as a common factor.)
6. Once a triad is formed, the three must run to the teacher and show their
monomials for verification.
7. The first three triads who get verified by the teacher get a prize.
In factoring polynomials, the first factors taken out are the greatest common monomial
factors.
For example, let us factor .
One may opt to list down the common factors of both terms of the polynomial and select
the greatest factor. Nevertheless, the following steps may be helpful and easier to
perform.
Step 1: Find the GCF of the numerical coefficients and the GCF of the variables by
prime factorization.
Numerical coefficients: Variables:
6 = 3 × 2
12 = 3 × 2 × 2
ab = a ⋅ b
bc = b ⋅ c
GCF = 3 × 2 = 6 GCF = b
Learn about It!
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Step 2: Get the product of the GCFs for the numerical coefficients and the variables.
This will be the greatest common monomial factor of the polynomial.
⋅
Step 3: Factor out the greatest common monomial factor and divide each term by
this to find the other factor.
The other factor is .
Therefore, .
Example 1: Completely factor the polynomial .
Solution:
Step 1: Find the GCF of the numerical coefficients and the GCF of the variables by
prime factorization.
Definition 1.1: The greatest common monomial factor is the product
of the greatest common numerical factor and a second
component made up of the common variable factors,
each with the highest power common to each term.
Let’s Practice!
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Numerical coefficients: Variables:
45 = 3 × 3 × 5
36 = 3 × 3 × 4
a4 = a ⋅ a ⋅ a ⋅ a
a3 = a ⋅ a ⋅ a
GCF = 3 × 3 = 9 GCF = a ⋅ a ⋅ a = a3
Step 2: Get the product of the GCFs for the numerical coefficients and the variables.
This will be the greatest common monomial factor of the polynomial.
⋅
Step 3: Factor out the greatest common monomial factor and divide each term by
this to find the other factor.
The other factor is .
Therefore, .
Try It Yourself!
Completely factor the polynomial – .
Example 2: Find the greatest common monomial factor of to
factor it completely.
Solution:
Step 1: Find the GCF of the numerical coefficients and the GCF of the variables.
Besides prime factorization, you may also use continuous division.
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The GCF of the numerical coefficients is 6.
The GCF of the variables is .
Step 2: Get the product of the GCFs for the numerical coefficients and the variables.
This will be the greatest common monomial factor of the polynomial.
⋅
Step 3: Factor out the greatest common monomial factor and divide each term by
this to find the other factor.
The other factor is .
Therefore, ).
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Try It Yourself!
Completely factor the polynomial .
Example 3: Given that represents a positive integer, prove that it is
a composite number.
Solution: is composite if we can factor it.
Step 1: Find the GCF of the numerical coefficients and the GCF of the variables.
Besides prime factorization, you may also use continuous division.
The GCF of 75, 15, and 45 is 15.
The GCF of , , and is .
Step 2: Get the product of the GCFs for the numerical coefficients and the variables.
This will be the greatest common monomial factor of the polynomial.
⋅
Step 3: Factor out the greatest common monomial factor and divide each term by
this to find the other factor.
The other factor is .
Written in factored form, .
Since we have factored , it is a composite number.
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Try It Yourself!
Is the polynomial a prime or composite number?
Justify your answer.
Real-World Problems
Example 4: Mr. Santos plans to construct a circular dinner table with a square
centerpiece in the center. The radius of the table should be the same
measure as the side of the square centerpiece. Write an expression for the
remaining area of the table not covered by the centerpiece in terms of the
side of the square. Write your answer in factored form.
Solution:
Step 1: Draw a figure to illustrate the given problem.
Step 2: Note that we are looking for the area not covered by the centerpiece. Hence,
we use the formula for the area of the circle and that of the square.
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Since the radius should be the same measure as the side of the square, we
write
Step 3: Solving for the area not covered by the centerpiece, we have
Step 4: Rewriting the equation in factored form, we have
).
Therefore the area of the table not covered by the centerpiece is given by .
Try It Yourself!
If the table in Example 4 is in the form of a square having a circular mantle and the
radius of the mantle is equal to the side of the square , what would be the
expression for the area not covered by the mantle?
1. Factor the following expressions completely.
a.
b.
c.
d.
Check Your Understanding!
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2. Write an expression (in factored form) for the area of the shaded region in terms
of and .
A Tale of Two Squares
Materials Needed: colored papers, ruler, pencil, scissors, paper and pen,
cartolina, markers
Instructions:
1. Form groups of three.
2. Cut two square-shaped piece from the colored
papers. One square should be larger than the
other, and the squares must be of different colors.
Label the side of the bigger square and the side of
the smaller square .
Lesson 2: Factoring the Difference of Two Squares
Warm Up!
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3. Trace the smaller square onto the bigger square at the corner and cut along the
trace. With your groupmates, find an expression for the area of the remaining
figure in terms of and ?
4. Draw a horizontal line segment dividing the remaining figure into two rectangles as
shown and cut along this line.
5. Move the cut out region to the right as shown.
6. Find the expressions of the dimensions (width and length) of the rectangle in terms
of and .
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7. Find the expression for the area of the rectangle using the dimensions you
obtained in step 6. How does this compare to the area obtained in step 3?
8. Write your answers to the expressions required and your solutions on a cartolina
and present your work in class.
A constant is a perfect square if it is obtained by multiplying a number by itself.
Observe the following examples:
Number
(x)
Square
(x2)
Perfect
Square
1 12 = 1 1
2 22 = 4 4
3 32 = 9 9
5 52 = 25 25
10 102 = 100 100
A variable is a perfect square when its exponent is even, which is divisible by 2.
Number
(x)
Square
(x2)
Perfect
Square
a a2 a2
b2 (b2)2 = b4 b4
c3 (c3)2 = c6 c6
d5 (d5)2 = d10 d10
e10 (e10)2 = e20 e20
Learn about It!
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In Warm Up!, the area of the new figure in step 3, is in the form of a difference of two
perfect squares.
The difference of the squares of two numbers is equal to the product of their sum and
their difference as shown by the length and width in step 5 of the activity in Warm Up!.
That is,
Let us take the case of . What are its factors?
Check if the given involves difference of two squares:
It is a binomial.
The operation involved is subtraction.
is the square of , while is the square of .
Following the format above, the factors of are the sum and the difference of the
numbers being squared, and .
Thus, .
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Example 1: Factor
Solution:
Step 1: Check if there is a common monomial factor.
4x2 – 25 have no common monomial factor.
Step 2: Check if the given polynomial involves a difference of two squares.
Step 3: Identify the square root of each of the terms. The square root is the number
being multiplied by itself to obtain another number.
Step 4: Write the factors as the sum and the difference of the answers in step 3.
Let’s Practice!
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Try It Yourself!
Factor
Example 2: Factor .
Solution:
Step 1: Check if there is a common monomial factor.
The GCF of the numerical coefficients is 5 and the GCF of the variables is .
Therefore, the greatest common monomial factor is . We factor this out.
Step 2: Check if any of the factors involves a difference of two squares.
Step 3: Identify the square roots of each of the terms.
1 = 12
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Step 4: Write the factors from steps 1 and 3.
Thus, is factored as .
Try It Yourself!
Factor completely: .
Example 3: Simplify without using a calculator.
Solution:
Step 1: Check if there is a common monomial factor.
The terms of the given expression has no common monomial factor.
Step 2: Check if any of the factors involves a difference of two squares.
Notice that the given involves the difference of two squares since 22 and 21
are squared.
Step 3: Identify the square roots of each of the terms.
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Step 4: Write the factors from step 3.
Thus, is equal to .
Try It Yourself!
Simplify without using a calculator.
Real-World Problems
Example 4: The difference of the areas of two limited edition
square stamps is 128 cm2. One side of the bigger
stamp is thrice the length of one side of the
smaller. Find the lengths of the sides of the two
stamps.
Solution:
Step 1: Identify the given information.
Area of bigger square – Area of smaller square = 128 cm2.
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Step 2: Write the equation. Remember that the area of a square is equal to the
square of the length of its side.
Step 3: Solve for the value of s by factoring.
= 128
= 128 Square 3s.
128 Subtract s2 from 9s2.
= 0 Subtract 128 from both sides of the equation.
= 0 Factor out the greatest common monomial
factor, 8.
= 0 Divide both sides of the equation by 8.
= 0 Factor the difference of two squares.
Remember that a product can only be zero if one of the factors is zero. In this
case, either is zero or is zero.
or
The measurement of length cannot be a negative value. Thus,
The length of a side of the smaller stamp is 4 cm while the length of one side
of the larger stamp is 12 cm.
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Try It Yourself!
What will be the length of the sides of the two stamps in Example 4, if the
difference of their areas is 512 cm2?
1. Factor the following expressions completely:
a.
b. –
c. –
d.
2. Without raising any number to a power, evaluate the following:
a.
b.
c.
3. A photo is surrounded by a frame of uniform width. The length of the outer side of
the frame is 4 inches more than the length of a side of the photo. If the area
covered by the frame alone is 80 square inches, what is the length of a side of the
photo?
Check Your Understanding!
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Special Delivery!
Materials Needed: paper and pen, stopwatch or timer
Instructions:
1. This activity may be played by the entire class with the members of the class
divided into groups of five and a person assigned as timer and facilitator.
2. The facilitator will stand in front of the class and choose one expression to be
simplified from the given table below.
3. One representative from each group will move to the back of the classroom to
answer or give the product of the expressions flashed by the facilitator.
4. The members of each group are to take turns in answering.
5. The fastest representative to reach the facilitator with the correct answer will a
get a point.
6. The group with the highest score out of the 5 items in the table will be
considered the winner.
Questions
Lesson 3: Factoring the Sum or Difference of Two Cubes
Warm Up!
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Recall first what a perfect cube is.
A constant is a perfect cube if it is obtained by using a number as a factor three times.
Observe the following examples:
Number
(x)
Cube
(x3)
Perfect
Cube
1 13 = 1 1
3 33 = 9 27
5 53 = 25 125
8 83 = 512 512
10 103 = 1 000 1 000
A variable is a perfect cube when its exponent is divisible by 3.
Variable
(x)
Cube
(x3)
Perfect
Cube
a a3 a3
b2 (b2)3 = b6 b6
c3 (c3)3 = c9 c9
d5 (d5)3 = d15 d15
e10 (e10)3 = e30 e30
The expression given in Warm Up! result in either a sum or a difference of two cubes
which can be factored as
Learn about It!
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Let us take the case of . What are its factors?
Check if the given expression involves a sum or difference of two cubes:
It is a binomial.
The operation involved is either addition or subtraction. In this case, it is subtraction.
is the cube of , while is the cube of .
Following the format above for difference of two cubes, we have and . So,
Example 1: Find the factors of 8b3 + 1
Solution:
Step 1: Check if there is a common monomial factor.
8b3 and 1 have no common monomial factor.
Step 2: Check if the given polynomial involves the sum or the difference of two
cubes.
Let’s Practice!
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8b3 + 1 is a binomial
The operation involved is addition.
8b3 is the cube of , while is the cube of .
Step 3: Identify the cube root of each of the terms.
so
, so
Step 4: Form the factors using the formula with
and .
Therefore, the factors of are and .
Try It Yourself!
Find the factors of .
Example 2: Factor
Solution:
Step 1: Check if there is a common monomial factor.
)
Step 2: Check if any of the factors involves the sum or the difference of two cubes.
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is a binomial.
The operation involved is subtraction.
is the cube of , while is the cube of .
Step 3: Identify the cube root of each of the terms.
, so
, so
Step 4: Write the factors from steps 1 and 3.
Therefore,
Try It Yourself!
Factor completely: .
Example 3: Factor completely: .
Solution:
Step 1: Check if there is a common monomial factor.
and 1 have no common monomial factor.
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Step 2: Check if the given is a difference of two squares.
is the square of , and is the square of . Using ,
we have
Step 3: Check if any of the factors involves the sum or the difference of two cubes.
and are binomials
The operations involved are addition and subtraction.
is the cube of , while is the cube of .
Step 4: Identify the cube root of each of the terms.
, so
, so
Step 5: Write the factors from steps 1 and 3.
Using the formula for factoring the sum of two cubes, we have
Therefore, in factored form, .
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Try It Yourself!
Factor completely: .
Real-World Problems
Example 4: The volume of a Rubik’s cube with side n is equal to n3. Another Rubik’s cube
whose side measures 8 cm is placed on top of the first cube. If the sum of
their volumes is 1 843 cm3, how long is one side of the other cube?
Solution:
Step 1: Identify the given and illustrate the given problem.
Sum of the volumes = 1843 cm3.
Step 2: Write the equation. Remember that the volume of a cube is equal to the cube
of the length of one side.
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Step 3: Solve for the value of by factoring.
= 1 843
= 1 843 Evaluate .
= 0 Subtract 1 843 from both sides of
the equation.
= 0 Factor the difference of two cubes.
Remember that a product can only be zero if one of the factors is zero. In this
case, either or . But is no longer
factorable and definitely would not equal to zero for any positive value of n,
so we have
or .
Therefore, the length of one side of the bigger cube is 11 cm.
Try It Yourself!
What will be the length of a side of the bigger cube in Example 4, if the smaller cube
has a side whose length 5 cm and the sum of their volumes is 341 cm3?
1. Identify if the following mathematical statement is true or false:
.
Check Your Understanding!
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2. Factor the following expressions completely.
a.
b.
c.
d.
3. A wooden block is in the shape of a cube which is hollow in the inside. The hollow
space inside is also in the shape of a cube. The outside length of a side of the block is
four cm longer than a side of the cube-shaped hollow space inside. If the total volume
occupied by the wooden part of the block is 448 cm3, find the side length of the cube
and the side length of the cube-shaped hollow space inside.
Tile Four-mation
Materials Needed: cartolina, pen, and scissors
Instructions:
1. This activity may be done in groups of three.
2. Each group will be assigned a number.
3. You and your groupmates shall cut out from cartolinas the following:
4 big squares measuring 4” × 4”
8 rectangular tiles measuring 4” × 1”
16 small squares measuring 1” × 1”
Lesson 4: Factoring Perfect Square Trinomials
Warm Up!
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4. Each of the groups shall form the following for each round.
1 big square tile, 2 rectangular tiles, and 1 small square.
1 big square tile, 4 rectangular tiles, and 4 small squares.
1 big square tile, 6 rectangular tiles, and 9 small squares.
1 big square tile, 8 rectangular tiles, and 16 small squares.
4 big square tiles, 4 rectangular tiles, and 1 small square.
4 big square tiles, 8 rectangular tiles, and 4 small squares.
5. Once your group is done forming a square with the indicated pieces, shout out
your group number.
6. The teacher shall then verify if a square was formed and the pieces are correct.
7. The group that is first to get the pieces right shall receive a point.
8. The group with the most number of points after 6 rounds wins.
In Warm Up!, you were able to create squares of varying
dimensions using the tiles. Consider the square formed using 1
big square tile, 8 rectangular tiles, and 16 small squares tiles. If
the side of the 4” × 4” square is , the shorter side of the 4” × 1”
rectangle is 1 unit, and the side of the 1” × 1” square is 1 unit, the
area covered by the square can be modeled by the polynomial:
. Can you try to find the measure of one of its sides?
To solve this kind of problem, remember that the area of a square is equal to the
square of the length of its side.
So, if the length of one side of a square is x, then the area is x2. Similarly, if the length
is , then the area is . Moreover, if the length is a – b, then the
area is .
Learn about It!
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Such expression for the area of a square is called a perfect square. Moreover, since the
square of a + b results in a polynomial with three terms, it is called a perfect square
trinomial.
In the case of the square formed by 1 big square tile, 8 rectangular tiles, and 16 small
square tiles, the side is of length . That means the area is .
Thus, equating the two areas, we have and found a way to factor
the perfect square trinomial .
Generally for a perfect square trinomial , by working backwards, we have
Definition 4.1: A perfect square trinomial is an algebraic
expression that can be written in the form
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Note that the first and last terms are squares of and respectively (which should always
be positive), and the middle term is positive or negative twice the product of and .
Hence, in the factored form, the operation involved depends on the sign of the middle
term.
Let us check if the given area (in square meters) in the problem, . Does it
follow the pattern for a perfect square trinomial?
In , observe that and 16 = (4)2. To check if it is a perfect square
trinomial, the middle term must be equal to twice the product of and .
Since (the middle term), the given expression for the area is a perfect square
trinomial. Factoring the expression, we have
.
Hence, we also find by factoring that the length of one side of the square is meters.
Example 1: Write as the square of a binomial.
Solution:
Step 1: Check if there is a common monomial factor.
has no common monomial factor.
Step 2: Identify if the given polynomial is a perfect square trinomial.
Let’s Practice!
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The first and last terms are both perfect squares.
and
The middle term is negative two times the product of the square roots of
the first and last terms.
– –
Step 3: Use the square root of the first term of the trinomial as the first term of the
factor and the square root of the last term of the trinomial as the second
term of the factor. Square the binomial formed. (Note that the operation
involved in the factor depends on the sign of the middle term.)
and
Hence,
Try It Yourself!
Write 4 as the square of a binomial.
Example 2: Factor completely: .
Solution:
Step 1: Check if there is a common monomial factor.
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Step 2: Identify if the trinomial factor is a perfect square.
The first and last terms are both perfect squares.
and
The middle term is twice the product of the square roots of the first and
last terms.
Step 3: Use the square root of the first term of the trinomial as the first term of the
factor; use the square root of the last term of the trinomial as the second
term of the factor. Square the binomial formed.
Note that the middle term is positive (addition) so the operation to be used
in the factor is addition.
and
2
Hence, .
Try It Yourself!
Factor completely:
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Example 3: The square of a number is .
What is the number if ?
Solution:
Step 1: List down the given information.
Square of the number
Step 2: Find the square root of by factoring.
We first check if is a perfect square trinomial.
Notice that
may be taken as the first term and is the square of
may be taken as the last term and is the square of 2
may be taken as the middle term and is twice the product of
and 2
Therefore, is in the form of where
and . Following the format for the factors of a perfect square trinomial, we
have
Hence, the number is equivalent to .
Step 3: Substitute 9 for n.
Therefore, the number is 14.
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Try It Yourself!
How long is one side of a square whose area is cm2?
Real-World Problems
Example 4: Mang Berting is planting palay on a square
piece of land. The land area is given by the
expression square meters.
What is the length of the side of the land if
?
Solution:
Step 1: List down the given information.
Area of the square piece of land
Step 2: Find the square root of by factoring.
is a perfect square trinomial in the form with
and because
is a perfect square; it is the square of .
is a perfect square; it is the square of .
is equal to .
Following the formula for factoring a perfect square trinomial, we have
Hence, the side of the square is equivalent to .
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Step 3: Substitute the value of .
Therefore, the measure of the side of the square is 6 m.
Try It Yourself!
The area of a square coaster is given by the expression cm2. What is
the length of a side of the coaster if and ?
1. Factor completely.
a.
b.
c.
2. Complete each expression to form a perfect square trinomial.
a.
b.
c.
3. A wall clock has a shape of a square. Its area is given by the algebraic expression
cm2. Find the length of a side of the clock if .
Check Your Understanding!
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Cards on the Table
Materials Needed: flaglet for each group, standard deck of cards (only the
spade and heart suits are needed)
Instructions:
1. This activity may be played by the whole class. One of your classmates shall
assume the role of game master. Divide yourselves in groups of five.
2. The game master shall take hold of the cards and shuffle them.
3. Each card shall be assigned an integer:
A = 0 7 = 7 A = 0 7 = –7
1 = 1 8 = 8 1 = –1 8 = –8
2 = 2 9 = 9 2 = –2 9 = –9
3 = 3 10 = 10 3 = –3 10 = –10
4 = 4 J = 11 4 = –4 J = –11
5 = 5 Q = 12 5 = –5 Q = –12
6 = 6 K = 13 6 = –6 K = –13
4. The game master shall then pick two cards at random, remember them, and have
them face down on the table.
5. Using the table above, the game master shall then compute the sum and the
product of the corresponding integers of the cards and tell these to the class.
Lesson 5: Factoring General Trinomials
Warm Up!
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6. The groups are then supposed to try to correctly guess the card as fast they can.
7. Once a group has the answers, they should raise their flaglet to be recognized
by the game master.
8. The group that correctly guesses the two cards (with the correct number and
suit) gets a point.
9. The group that gets the most points wins.
Suppose the product of two numbers is . What are the numbers?
To factor out a general trinomial, you can use the technique called the AC method, which
is basically the “inverse” of the FOIL method.
First, identify the coefficients and of the trinomial in the form , and then
find their product.
Then find the factors of that add up to the middle term’s coefficient, . In this case,
.
Factors of 6 Sum
1, 6 7
2, 3 5
The factors of 6 that have a sum of 5 are 2 and 3.
Next, rewrite the trinomial by expanding the middle term, , into :
Learn about It!
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Regroup the polynomial into two sets of binomials. Factor each binomial using their
greatest common factor. Then we factor the common binomial factor from each set to
form the two factors.
=
Thus, written in factored form, .
Example 1: Factor completely: .
Solution:
Step 1: Check if there is a common monomial factor and/or if the given trinomial is a
perfect square. If so, factor accordingly.
The terms of have no common monomial factor.
is not a perfect square trinomial.
Step 2: Find .
Given , and .
Let’s Practice!
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Step 3: Find the factors of 10 whose sum is the coefficient of the middle term, 7.
Factors of 10 Sum
1, 10 11
2, 5 7
Note: When the coefficients of the middle and last terms are both positive,
the factors of must be both positive as well.
Step 4: Rewrite the middle term of the original trinomial using the factors obtained
in step 3.
Step 5: Regroup the resulting polynomial and factor each group using their greatest
common factor. Then factor out the common binomial factor from set.
=
Therefore,
Try It Yourself!
Factor .
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Example 2: Factor completely: .
Solution:
Step 1: Check if there is a common monomial factor and/or if the given trinomial is a
perfect square. If so, factor accordingly.
The trinomial factor is not a perfect square.
Step 2: For the trinomial , find .
Given , and .
Step 3: Find the factors of –28 whose sum is the coefficient of the middle term, 3.
Note: When the last term is negative, one of the factors of must be
positive while the other must be negative.
Factors of –28 Sum
1, –28 –27
–1, 28 27
2, –14 –12
–2, 14 12
4, –7 –3
–4, 7 3
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Step 4: Rewrite the middle term of the original trinomial using the factors obtained
in step 3.
Step 5: Regroup the resulting polynomial and factor each group using their greatest
common factor. Then factor out the common binomial factor from each set.
=
= –
Therefore,
Try It Yourself!
Find the factors of .
Example 3: The product of two positive integers is in the form . Without
evaluating the given expression itself, give two such integers if .
Solution: To get the numbers, we can find the factors of .
Step 1: Check if there is a common monomial factor and/or if the given trinomial is a
perfect square. If so, factor accordingly.
The terms of has no common monomial factor.
is not a perfect square trinomial.
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Step 2: Find .
Given , and .
Step 3: Find the factors of 12 whose sum is the coefficient of the middle term, –8.
Note: When the last term is positive but the middle term is negative, the
factors of must be both negative.
Step 4: Rewrite the middle term of the original trinomial using the factors obtained
in step 3.
Step 5: Regroup the resulting polynomial and factor each group using their greatest
common factor. Then factor out the common binomial factor from each set.
Step 6: Substitute x = 31 to find the values of the missing numbers.
Therefore, two such integers are 25 and 29.
Factors of –28 Sum
–1, –12 –13
–2, –6 –8
–3, –4 –7
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Try It Yourself!
The product of two positive integers is in the form . Without evaluating
the given expression itself, give two such integers if
Real-World Problems
Example 4: The floor area of a chain of boutiques is given by square
meters. Without evaluating the given expression itself, find its dimensions if
the length is , and .
Solution:
Step 1: Check if there is a common monomial factor and/or if the given trinomial is a
perfect square. If so, factor accordingly.
has no common monomial factor.
Also it is not a perfect square.
Step 2: To factor , find .
written in standard form is . Thus, and .
Step 3: Find the factors of 75 whose sum is the coefficient of the middle term, 28.
Factors of 75 Sum
1, 75 76
–1, –75 –76
3, 25 28
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Step 4: Rewrite the middle term of the original trinomial using the factors obtained
in step 3.
Step 5: Regroup the resulting polynomial and factor each group using their greatest
common factor. Then factor out the common binomial factor from each set.
Step 6: Evaluate the length and the width using .
Since the length is , its width would be . Finally, if ,
then the length is 27 m, while the width is 5m.
Try It Yourself!
What will be the dimensions of the floor area of the chain of boutiques in Example 4 if
the area is square meters, the length is , and ? Compute for the
required dimensions without evaluating the given expression itself.
–3, –25 –28
5, 15 20
-5, -15 -18
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1. Use a table to factor each of the following trinomials.
a.
b.
c.
d.
e.
2. Find all values of for which the given trinomials can be factored.
a.
b.
c.
3. Without evaluating the expression for the area, find the dimensions of a
smartphone if its area is given by , its length is and .
1. Provide an explanation for errors in factoring of the given polynomials below.
a.
b.
c. is prime (i.e. it is not factorable).
2. Is the GCF of any expression always a monomial? Give an example that supports
your answer.
3. Relate the concepts in specials products to the factoring techniques that you have
studied in this unit. Provide explanations on their relationship.
Challenge Yourself!
Check Your Understanding!
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(This activity will showcase your learning in this unit. You and two other teammates will assume the role of
packaging specialists hired by a cosmetics company.)
The company is launching their new products, and as the head of a team hired by the
company, you are tapped to provide your expertise in formulating and answering
inquiries regarding the packaging of the company’s new products. You will present the
models and explain your computations to the chief executive officer (CEO) of the company
and to the head of operations and logistics department.
Specifically, you and your team are to make different prismatic (in the form of a prism)
bundles by stacking products of different sizes.
The products are packaged in boxes with the following dimensions:
The first part of the task is purely computational. In this part, you are to answer some
inquiries about the dimensions of the bundles for specific. The solutions shall not yet use
the construction of the actual boxes as well as diagrams since they may be solved purely
by operations on polynomials and factoring. You are to answer all inquiries for all of
the following bundles:
Performance Task
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Bundle 1: Form a prismatic bundle by stacking 1 blue box, 2 green boxes and 1 red box.
a) Can you compute for the total base area covered by if the height of the
bundle is cm?
b) Can you provide its length and width in terms of and ?
c) If cm and cm, provide the total base area covered as well as
the length and width.
Bundle 2: Form a prismatic bundle by stacking 2 blue boxes and 4 green boxes.
a) Can you compute for the total base area covered by if the height of the
bundle is cm?
b) Can you provide its length and width in terms of and ?
c) If cm and cm, provide the total base area covered as well as
the length and width.
Bundle 3: Form a prismatic bundle with a volume equal to .
a) What are the dimensions (length, width, height) of this prismatic bundle in
terms of and ?
b) If cm and cm, compute for the length, width, and height of the
bundle.
c) What products will fit into this bundle and what are their dimensions?
Bundle 4: Form a prismatic bundle with a volume equal to .
a) What are the dimensions (length, width, height) of this prismatic bundle in
terms of and ?
b) If cm and cm, compute for the length, width, and height of
the bundle.
c) What products will fit into this bundle and what are their dimensions?
After accomplishing the computational part of task, the second part of the task is to create
the model of a bundle. Your team is to create actual models of these boxes placed
stacked to form one of these prismatic bundles. You shall choose to model only one (1)
of the bundles stated previously. The aim of the actual model is to confirm if your
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STUDY GUIDE
computations for the dimensions asked in the inquiries agree with the boxes in your
prismatic bundle models. You are free to use any material and to create your own
patterns and designs in making the boxes.
The third part of the task is the presentation of your computations and models to the
class. You may refer to the given format below as a guide for your presentation.
I. Product Name
Project Leader
Members
Date Submitted
II. Computations and Explanations
(State each problem and present your complete and detailed solutions for each
problem. Do not forget to specify the factoring concept or formula you used in solving
the problem.)
III. Prismatic Bundle Model
(Indicate the bundle you chose to model. Present a diagram of the chosen bundle with
dimensions. Present to the class the actual stacking of the boxes to form the prismatic
bundle.)
The presentation will be evaluated according to the following: explanation of the proposal,
accuracy of computations, and appropriateness of the design and model.
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Performance Task Rubric
Criteria
Below
Expectation
(0–49%)
Needs
Improvement
(50–74%)
Successful
Performance
(75–99%)
Exemplary
Performance
(99+%)
Explanation of
the Design
Proposal
Explanations and
presentation of
the layout is
difficult to
understand and
is missing several
components.
Explanations and
presentation of
the layout is a
little difficult to
understand but
includes critical
components.
Explanations and
presentation of
the layout is
clear.
Explanations and
presentation of
the layout is
detailed and clear.
Accuracy of
Computations
The
computations
done are
erroneous and
do not show wise
use of the
concepts of
factoring.
The
computations
done are
erroneous and
show little use of
the concepts of
factoring.
The
computations
done are
accurate and
shows moderate
use of the
concepts of
factoring.
The computations
done are accurate
and show an
extensive use of
the concepts of
factoring.
Appropriateness
of the Designs
The model is not
useful in
understanding
the design
proposal.
The model is
somewhat useful
in understanding
the design
proposal.
The model is well-
crafted and
useful for
understanding
the design
proposal. It
showcases the
desired layout.
The model is well-
crafted and useful
for understanding
the design
proposal. It
showcases the
desired layout and
is accurately done.
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Key Concept Description
Greatest Common
Monomial Factor
The greatest common monomial factor is the product of the GCF
of the numerical coefficients and the GCF of the variables.
To factor an expression using the greatest common monomial
factor, follow these steps:
Step 1: Factor out the greatest common monomial factor.
Step 2: Divide each term of the expression by the greatest
comomon monomial factor to get the other factor.
Note: Finding the greatest common monomial factor is the first
step to be done in factoring any expression.
Difference of Two
Squares
Sum and Difference
of Two Cubes
Perfect Square
Trinomial
General Trinomial
To find the factors of a trinomial in the form , follow
these steps:
Step 1: Find .
Step 2: Find factors of whose sum is .
Step 3: Rewrite the middle term using the values found in
Step 2.
Step 4: Regroup the terms and take greatest common
monomial factor in each group.
Step 5: Factor out the common binomial factor from each
group to find the factors.
Wrap-up
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Lesson 1
1.
2.
3. The given polynomial is a composite number since it can be factored into
.
4. )
Lesson 2
1.
2.
3. 199
4. The length of one side of the small stamp is 8 cm while the length of one side of the
big stamp is 24 cm.
Lesson 3
1.
2. –
3.
4. The length of a side of the bigger cube is 6 cm.
Lesson 4
1.
2.
3. cm
4. The measure of the side of the square is 8 cm.
Lesson 5
1.
2.
Key to Let’s Practice!
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3. The two numbers are 19 and 22.
4. If , then the length is 8 m, while the width is 7 m.
Baron, Lorraine, et. al. Math Makes Sense 8. Pearson Education Canada, 2008.
Davison, David M., et al. Pre-Algebra. Philippines: Pearson Education, Inc., 2005.
Maths is Fun. “Algebra”. Accessed January 10, 2018.
http://www.mathsisfun.com/algebra/factoring.html
McCune, Sandra Luna and Clark, William D. Easy Algebra Step-by-Step. McGraw Hill
Professional, 2011.
McGraw-Hill Education. Glencoe Math Volume 1. McGraw-Hill Professional, 2013.
References