grade 12 pre-calculus mathematics [mpc40s] chapter 6
TRANSCRIPT
Grade 12 Pre-Calculus Mathematics
[MPC40S]
Chapter 6
Trigonometric Identities
Outcomes
T5, T6
12P.T.5. Solve, algebraically first and second degree trigonometric equations with the domain expressed in degrees and radians. 12P.T.6. Prove trigonometric identities, using
- Reciprocal identities - Quotient identities - Pythagorean identities - Sum or difference (restricted to sine, cosine, and tangent) - Double-angle identities (restricted to sine, oscine, and tangent.
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Chapter 6 β Homework
Section Page Questions
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Chapter 6: TRIGONOMETRIC IDENTITIES
6.1 β Reciprocal, Quotient, and Pythagorean Identities
An equation like sin π =1
2 is true for very few values of π, like π =
π
6 or π =
5π
6, or all
coterminal angles with those angles.
An identity like tan π₯ =sin π₯
cos π₯ is always true for all π β π (or nearly all).
Recall the following identities:
tan π₯ =sin π₯
cos π₯ csc π₯ =
1
sin π₯ sec π₯ =
1
cos π₯
cot π₯ =cos π₯
sin π₯ cot π₯ =
1
tan π₯
Non-permissible values are any values that result in a denominator equal to 0. Example #1
Determine the non-permissible values of the following identities, over the interval 0 β€ π₯ β€ 2π
a) cot π₯ =1
tan π₯
b) cot π₯
(tan π₯β1)(sin π₯)
T6
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Example #2
Verify that the equation sec π₯
tan π₯+cot π₯= sin π₯ is true for the following values of x.
a) π₯ = 60Β°
b) π₯ =3π
4
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c) State the non-permissible values of the above identity over the interval 0 β€ π₯ β€ 2π
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Pythagorean Identities From the unit circle, we know that cos π = π₯ and sin π = π¦. We also know that the equation of the unit circle is π₯2 + π¦2 = 1 Therefore, upon substitution, 1). _____________________________ Dividing Equation 1) by cos2ΞΈ results in:
sin2π
cos2π+
cos2π
cos2π=
1
cos2π β 2). _____________________________
Dividing Equation 1) by sin2ΞΈ results in:
sin2π
sin2π+
cos2π
sin2π=
1
sin2π β 3). _____________________________
We can manipulate these equations to create other equations. sin2π + cos2π = 1 tan2π + 1 = sec2π 1 + cot2π = csc2π
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Note: These identities are only true when the trigonometric functions are squared. (i.e. sin π + cos π β 1)
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Example #3
Simplify the following expressions completely.
a) tan π cos π
sec π cot π b)
cot π₯
csc π₯ cos π₯ c)
sec2π cos π
csc π
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Chapter 6: TRIGONOMETRIC IDENTITIES
6.3 β Proving Identities Part 1 To PROVE AN IDENTITY means to manipulate both sides of an equation independently until they are identical. Helpful Hints
β’ Rewrite all functions in terms of sin π and cos π
β’ Factor
β’ Multiply by a form of 1 (for example: sin ΞΈ
sin ΞΈ)
β’ Simplify
β’ Expand
β’ Multiply by the conjugate (1 + cos π₯ β 1 β cos π₯)
Things to Remember
β’ Identities are different from equations. Keep side separate!
β’ Use the correct variable (π, π₯, πΌ, π½, etc. )
β’ Left Hand Side = Right Hand Side (LHS = RHS)
β’ Show all of your work (marks are allocated for work shown)
β’ Do not invent new math. It is better to not arrive at the same answer than to make something up!
β’ Work vertically β
T6
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Example #1
Prove the following identities for all permissible values of the variable. a) (sin π₯)(sec π₯)(cot π₯) = 1
LHS RHS
b) cos2π₯
cot π₯= sin π₯ cos π₯
LHS RHS
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c) sec π₯
tan π₯+cot π₯= sin π₯
LHS RHS
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d) 1 β cos2π = cos2π tan2π
LHS RHS
e) sin πΌ
1βcos πΌ=
1+cos πΌ
sin πΌ
LHS RHS
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f) cos4π β sin4π = 1 β 2sin2π
LHS RHS
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Chapter 6: TRIGONOMETRIC IDENTITIES
6.2 β Sum, Difference, and Double-Angle Identities Along with the Pythagorean Identities, we have additional identities we can work with. They are the Sum and Difference Identities and the Double Angle Identities. Sum and Difference Identities sin(πΌ β π½) = sin πΌ cos π½ β cos πΌ sin π½ sin(πΌ + π½) = sin πΌ cos π½ + cos πΌ sin π½ cos(πΌ β π½) = cos πΌ cos π½ + sin πΌ sin π½ cos(πΌ + π½) = cos πΌ cos π½ β sin πΌ sin π½
tan(πΌ β π½) =tan πΌβtan π½
1+tan πΌ tan π½ tan(πΌ + π½) =
tan πΌ+tan π½
1βtan πΌ tan π½
Double Angle Identities sin 2πΌ = 2 sin πΌ cos πΌ
cos 2πΌ = cos2πΌβsin2πΌ
cos 2πΌ = 1 β 2sin2πΌ
cos 2πΌ = 2cos2πΌ β 1
tan 2πΌ =2 tan πΌ
1 β tan2πΌ
With the help of these identities, we can now we can find the coordinates of any point on the unit circle, provided it is a sum or difference of our special angels.
(π
3,
π
4,
π
6 family members)
T6
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Example #1
Simplify the following expressions and give the exact value.
a) cosπ
3cos
π
12+ sin
π
3sin
π
12
b) cos2(47Β°) + sin2(47Β°)
c) 1 β 2sin2 π
6
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We can use these formulas to determine the exact value of a trigonometric ratio that is not on the unit circle. Example #2
Determine the exact value of each expression below.
a) sin7π
12 b) cos 195Β°
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We can simplify expressions using identities. Example #3
Consider the expression 1βcos 2π
sin 2π
a) Determine the non-permissible values for this expression between [0, 2π]
b) Simplify the expression to one of the three primary trigonometry functions.
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Example #4
If 0 < π <π
2 and sin π =
3
5, determine the exact value of cos 2π.
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Example #5
If cos πΌ = β4
5 where
π
2β€ πΌ β€ π and cos π½ = β
12
13 where π β€ π½ β€
3π
2, determine the exact
value of cos(πΌ β π½).
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Chapter 6: TRIGONOMETRIC IDENTITIES
6.3 β Proving Identities Part 2 Example #1
Prove the following identities for all permissible values of the variable.
a) cot π β csc π =cos 2πβcos π
sin 2π+sin π
LHS RHS
T6
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b) 1βtan2π
1+tan2π= cos 2π
LHS RHS
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Chapter 6: TRIGONOMETRIC IDENTITIES
6.4 β Solving Trigonometric Equations Using Identities We will be solving trigonometric equations just like in the past, but now we need to make substitutions using trigonometric identities. Example #1
Solve the following trigonometric equation sin 2π = sin π over the interval [0, 2π] Example #2
Solve the following trigonometric equation over the interval [0, 2π). tan π₯ cos π₯ sin π₯ cot π₯ csc π₯ β 1 = 0
T5
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Example #3
a) Determine the non-permissible values of the following equation over the interval [0, 2π).
tan π = 2 sin π b) Solve the above trigonometric equation over the given interval
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Example #4
Solve the following trigonometric equations over the interval [0, 2π]. a) cos 2π₯ + 1 = cos π₯ b) 1 β cos2π₯ = 3 sin π₯ β 2
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c) 2 sin π₯ = 7 β 3 csc π₯