geometry ch 4-2 isosceles & equilateral triangles holt geometry warm up warm up lesson...
TRANSCRIPT
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Holt Geometry
Warm UpWarm Up
Lesson PresentationLesson PresentationLesson QuizLesson Quiz
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Warm Up
1. Find each angle measure.
True or False. If false explain.
2. Every equilateral triangle is isosceles.
3. Every isosceles triangle is equilateral.
60°; 60°; 60°
True
False; an isosceles triangle can have only two congruent sides.
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Prove theorems about isosceles and equilateral triangles.Apply properties of isosceles and equilateral triangles.
Objectives
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
12.0 Students find and use measures of sides and of interior and exterior angles of triangles and polygons to classify figures and solve problems.
15.0 Students use the Pythagorean theorem to determine distance and find missing lengths of sides of right triangles.
California Standards
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
legs of an isosceles trianglevertex anglebasebase angles
Vocabulary
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Geometry
CH 4-2 Isosceles & Equilateral TrianglesTri
an
gle
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Geometry
CH 4-2 Isosceles & Equilateral TrianglesTri
an
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Exte
rnal A
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Corollary: The measure of an exterior angle of a triangle is greater than the measure of either of its remote angles. 4 1 and 4 2m m m m
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Geometry
CH 4-2 Isosceles & Equilateral TrianglesTri
an
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An
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Sum
Thm
.
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
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Geometry
CH 4-2 Isosceles & Equilateral TrianglesTri
an
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Cla
ssifi
cati
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
A corollary is a theorem whose proof follows directly from another theorem. Here are two corollaries to the Triangle Sum Theorem.
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Recall that an isosceles triangle has at least two congruent sides. The congruent sides are called the legs.
The vertex angle is the angle formed by the legs. The side opposite the vertex angle is called the base, and the base angles are the two angles that have the base as a side.
3 is the vertex angle.
1 and 2 are the base angles.
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Geometry
CH 4-2 Isosceles & Equilateral TrianglesIs
osc
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s Tri
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
If , then B C.AB AC
If E F, then .DE DF
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
The bisector of the vertex angle of an isosceles triangle is the perpendicular bisector of the base.
Bisector of the Vertex
If and bisects C,
then and bisects .
AB BC BD AB
BD AC BD AC
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Find mF.
Example 1: Finding the Measure of an Angle
Thus mF = 79°
mF = mD = x° Isosc. ∆ Thm.
mF + mD + mA = 180 ∆ Sum Thm.
x + x + 22 = 180Substitute the given values.
2x = 158Simplify and subtract 22 from both sides.
x = 79 Divide both sides by 2.
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Find mG.
Example 2: Finding the Measure of an Angle
Thus mG = 22° + 44° = 66°.
mJ = mG Isosc. ∆ Thm.
(x + 44) = 3xSubstitute the given values.
44 = 2xSimplify x from both sides.
x = 22 Divide both sides by 2.
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
TEACH! Example 1
Find mH.mH = mG = x° Isosc. ∆ Thm.
mH + mG + mF = 180 ∆ Sum Thm.
x + x + 48 = 180Substitute the given values.
2x = 132Simplify and subtract 48 from both sides.
x = 66 Divide both sides by 2.
Thus mH = 66°
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
TEACH! Example 2
Find mN.
Thus mN = 6(8) = 48°.
mP = mN Isosc. ∆ Thm.
(8y – 16) = 6ySubstitute the given values.
2y = 16Subtract 6y and add 16 to both sides.
y = 8 Divide both sides by 2.
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Geometry
CH 4-2 Isosceles & Equilateral TrianglesEq
uila
tera
l Tri
an
gle
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
The following corollary and its converse show the connection between equilateral triangles and equiangular triangles.
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Geometry
CH 4-2 Isosceles & Equilateral TrianglesEq
uia
ng
ula
r Tri
an
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Ex. 3: Using Properties of Equilateral Triangles
Find the value of x.
∆LKM is equilateral.
(2x + 32) = 60 The measure of each of an equiangular ∆ is 60°.
2x = 28 Subtract 32 both sides.
x = 14 Divide both sides by 2.
Equilateral ∆ equiangular ∆
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Ex. 4: Using Properties of Equilateral Triangles
Find the value of y.
∆NPO is equiangular.
Equiangular ∆ equilateral ∆
5y – 6 = 4y + 12Definition of equilateral ∆.
y = 18 Subtract 4y and add 6 to both sides.
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
TEACH! Example 3
Find the value of JL.
∆JKL is equiangular.
Equiangular ∆ equilateral ∆
4t – 8 = 2t + 1 Definition of equilateral ∆.
2t = 9 Subtract 4y and add 6 to both sides.
t = 4.5 Divide both sides by 2.
Thus JL = 2(4.5) + 1 = 10.
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
A coordinate proof may be easier if you place one side of the triangle along the x-axis and locate a vertex at the origin or on the y-axis.
Remember!
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Prove that the segment joining the midpoints of two sides of an isosceles triangle is half the base.
Example 5: Using Coordinate Proof
Given: In isosceles ∆ABC, X is the mdpt. of AB, and Y is the mdpt. of BC.
Prove: XY = AC.12
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Proof:
Draw a diagram and place the coordinates as shown.
Example 5 Continued
By the Midpoint Formula, the coordinates of X are (a, b), and Y are (3a, b).
By the Distance Formula, XY = √4a2 = 2a, and AC = 4a.
Therefore XY = AC.12
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
TEACH! Example 5 The coordinates of isosceles ∆ABC are A(0, 2b), B(-2a, 0), and C(2a, 0). M is the midpoint of AB, N is the midpoint of AC, and Z(0, 0), .
Prove ∆MNZ is isosceles.
x
A(0, 2b)
B (–2a, 0) C (2a, 0)
y
M N
Z
Proof:
Draw a diagram and place the coordinates as shown.
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Check It Out! Example 6 Continued
By the Midpoint Formula, the coordinates. of M are (–a, b), the coordinates. of N are (a, b), and the coordinates of Z are (0, 0) . By the Distance Formula, MZ = NZ = √a2+b2 .
So MZ NZ and ∆MNZ is isosceles.
x
A(0, 2b)
B(–2a, 0) C(2a, 0)
y
M N
Z
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Lesson Quiz: Part I
Find each angle measure.
1. mR
2. mP
Find each value.
3. x 4. y
5. x
124°
28°
20 6
26°
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Geometry
CH 4-2 Isosceles & Equilateral Triangles
Lesson Quiz: Part II
6. The vertex angle of an isosceles triangle measures (a + 15)°, and one of the base angles measures 7a°. Find a and each angle measure.
a = 11; 26°; 77°; 77°