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Geometry Unit VIII 10.5: Segments of Chords students will be finding the lengths of segments formed when chords

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Objective: students will be finding the lengths of segments formed when chords intersect. Geometry. Unit VIII 10.5: Segments of Chords. Q. C. A. D. B. 4. 4. 10. 5. 11. 7. y. 8. 18. 8. 15. Y+3. y. - PowerPoint PPT Presentation

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Page 1: Geometry

Geometry

Unit VIII10.5: Segments of Chords

Objective: students will be finding the lengths of segments formed when chords intersect.

Page 2: Geometry

In this section, we will be finding the lengths of segments formed when chords intersect. Theorem 10.5: If a diameter is perpendicular to a chord, then it bisects the chord and

its arc.

Example: In OQ, QBAC , AC = 8 and QD = 4. Find the radius of OQ. Example: In a circle of radius 10 inches, a chord is 5 inches from the center. Find the length of the chord as an exact answer.

Q

C

B

A D

Q

C

B

A D44

𝑐2=42+42

𝑐2=32𝑐=√32=4√2

105

102=52+π‘₯2

π‘₯2=75

π‘₯=√75=5√3h𝑙𝑒𝑛𝑔𝑑 π‘œπ‘“ h𝑐 π‘œπ‘Ÿπ‘‘=10 √3

Page 3: Geometry

Theorem 10.15: If two chords intersect inside a circle, then the product of the two

segments on one chord equals the product of the two segments on the

second chord.

Example: If AX = 7, XC = 8 and BX = 11, find XD.

Example: If AX = 8, XC = 15, BX = 18 and XD = y + 3, solve for y.

A X

D C

B

7

8

11

11𝑦=7βˆ—8

y

11𝑦=56𝑦=

5611

8

15

18

Y+3 18 𝑦=66

18 𝑦+54=120

18 (𝑦+3 )=8βˆ—15

𝑦=3.667

Page 4: Geometry

Example: The piece of pottery shown at the right was found at an archeological site. Determine the diameter of the original piece of pottery.

1.4 in 1.4 in 0.8 in

1.4βˆ—1.4=.8 𝑦

1.96=.8 𝑦

2.45=𝑦

π‘†π‘œ h𝑑 π‘’π‘‘π‘–π‘Žπ‘šπ‘’π‘‘π‘’π‘Ÿ π‘œπ‘“ h𝑑 π‘’π‘œπ‘Ÿπ‘”π‘–π‘›π‘Žπ‘™π‘π‘œπ‘‘ 𝑖𝑠 π‘’π‘žπ‘’π‘Žπ‘™π‘‘π‘œ2.45+.8=3.25 𝑖𝑛

y