genetic mapping in a three-point test cross
DESCRIPTION
Genetic Mapping in a Three-Point Test Cross. sc x ec 12 14 14 16 56/1008 x 100 = 5.6 mu. ec vg235ec +243 ec vg016ec + 014 + +241+ vg233 + + 014 + vg012 506502. sc vg235sc +243 sc vg012sc + 014 + +241+ vg233 + + 014 + vg016 - PowerPoint PPT PresentationTRANSCRIPT
Genetic Mapping in a Three-Point Test Cross
sc x ec
12
14
14
16
56/1008 x 100 = 5.6 mu
ec vg 235 ec +243
ec vg 016 ec + 014
+ + 241 + vg233
+ + 014 + vg012
506 502
sc vg 235 sc +243
sc vg 012 sc + 014
+ + 241 + vg233
+ + 014 + vg016
502 506
--|-----------------------------------------------|---
sc 5.5 mu ec
--------------------------|-------------------------
vg
sc x ec
25
29
54/982 x 100 = 5.5 mu
ec x cv
44
37
81/982 x 100 = 8.2 mu
sc x cv
25
44
29
37
135/982 x 100 = 13.7 mu
--|-----------------------------------------------|---
sc 5.5 mu ec
--|-----------------------------------------------|---
cv 8.2 mu ec
--|-----------------------------------------------|---
sc 13.7 mu cv
5.5 mu ec 8.2 mu
--|-----------------|-----------------------------|---
sc 13.7 mu cv
cv x ct
45
03
40
05
93/1448 x 100 = 6.4 mu
ct x v
89
05
94
03
191/1448 x 100 = 13.2 mu
cv x v
45
89
40
94
268/1448 x 100 = 18.5 mu
--|-----------------------------------------------|---
cv 6.4 mu ct
--|-----------------------------------------------|---
ct 13.2 mu v
--|-----------------------------------------------|---
cv 18.5 mu v
6.4 mu ct 13.2 mu
--|-------------|--------------------------------|---
cv 18.5 mu v
6.4 + 13.2 = 18.5
6.4 + 13.2 = 19.6DOUBLE
CROSSOVERS!
/
cv x v
45
89
40
94
16 (5 + 3 = 8 X 2= 16)
284/1448 x 100 = 19.6 mu
6.4 mu ct 13.2 mu
--|-------------|--------------------------------|---
cv 19.6 mu v