functional question foundation (algebra 5) for the week beginning …

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Functional Question Foundation (Algebra 5) For the week beginning ….

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Page 1: Functional Question Foundation (Algebra 5) For the week beginning …

Functional QuestionFoundation(Algebra 5)

For the week beginning ….

Page 2: Functional Question Foundation (Algebra 5) For the week beginning …

Coin£1 50 p 20 p 10 p 5 p 2 p 1 p

Number of coins2 1 2 0 1 3 1

(a)     The table shows the number and type of coins in Jack’s pocket.        How much money does Jack have? (2)

Coin £2 £1 50 p 20 p 10 p 5 p 2 p 1 p

Number of coins

               

(b)     Lucy buys two chocolate bars costing 65 p each.          She pays with a £5 note and receives the correct change.          She is given exactly five coins.          Complete the table to show what these coins could be. (3)(Total 5 marks) 

Page 3: Functional Question Foundation (Algebra 5) For the week beginning …

(a)     2 (+ 0.5 +) 0.4 (+ 0.05 +) 0.06 (+ 0.01)Allow one errorOr equivalent eg, 200 (+ 50 +) 40 (+ 5 +) 6 (+ 1) or 302This mark can be implied with cumulativeadditions seen eg, (£)2.90 or (£)2.95M1 – Method mark

(£) 3.02(p)Allow 302 pA1 - Accuracy marks are awarded when following on from a correct method(b)     5 – 1.30Or equivalentM1 – Method mark          (£)3.70A1 - Accuracy marks are awarded when following on from a correct method           £2, £1, 50 p, 2 × 10 p£2, 3 × 50 p, 20 p3 × £1, 50 p, 20 pMust be 5 coinsB1 Marks awarded independent of method

Page 4: Functional Question Foundation (Algebra 5) For the week beginning …

Common Mistakes – what did the examiners say?

Part (a) was a fairly straightforward question that was well done with about two-thirds of candidates gaining full marks. Some candidates failed to score full marks because they showed a correct method but made an error in their calculation.          Part (b) of this question assessed the functional elements of mathematics in a fairly straightforward way. Most candidates knew what they had to do and about 50% managed to find one of the correct combinations; only about 15% of candidates scored zero. A number of candidates often worked out the correct change but gave it in four coins rather than the five required. Some scored marks for the correct coins for the incorrect change.