áfu« bjhlnth« - padasalai 11th studymaterials · 2017. 10. 15. · (iii) to order with us. s....

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www.surabooks.com áfu« bjhLnth« ntâÆaš òâa 11- « tF¥ò Ruh g¥Ënfõ‹° br‹id. òâa ghl¤â£l« 2017-18 ‹go jahÇ¡f¥g£LŸsJ. 2017-18 M©L¡fhd ghlüšfË‹ ntâÆaš 2 k‰W« 3 kâ¥bg© Édh-ÉilfŸ, ghlthÇahf¤ ju¥g£LŸsd. x›bthU ghl¤â‰F« K¡»a Édh ÉilfŸ. 2018 bghJ¤nj®î¡F ga‹jU« tifÆš jahÇ¡f¥g£LŸsJ. áw¥g«r§fŸ lh®bf£ kâ¥bg© Édh-Éil 2 & 3 This material only for sample [email protected] Ph:9600175757/8124201001 www.Padasalai.Net www.TrbTnpsc.com http://www.trbtnpsc.com/2017/06/latest-11th-study-materials-tamil-medium-english-medium.html www.Padasalai.Net

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Page 1: áfu« bjhLnth« - Padasalai 11th Studymaterials · 2017. 10. 15. · (iii) TO ORDER WITH US. S. CHOOLS and TEACHERS: We are grateful for your support and patronage to ‘SURA . PUBLICATIONS’

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s.comáfu« bjhLnth«

ntâÆaš

òâa

11- « tF¥ò

Ruh g¥Ënfõ‹°

br‹id.

òâa ghl¤â£l« 2017-18 ‹go jahÇ¡f¥g£LŸsJ.

2017-18 M©L¡fhd ghlüšfË‹ ntâÆaš 2 k‰W« 3 kâ¥bg©

Édh-ÉilfŸ, ghlthÇahf¤ ju¥g£LŸsd.

x›bthU ghl¤â‰F« K¡»a Édh ÉilfŸ.

2018 bghJ¤nj®î¡F ga‹jU« tifÆš jahÇ¡f¥g£LŸsJ.

áw¥g«r§fŸ

lh®bf£

kâ¥bg©

Édh-Éil2 & 3

This material only for sample

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www.Padasalai.Net

NIRANJANA
Stamp
Page 2: áfu« bjhLnth« - Padasalai 11th Studymaterials · 2017. 10. 15. · (iii) TO ORDER WITH US. S. CHOOLS and TEACHERS: We are grateful for your support and patronage to ‘SURA . PUBLICATIONS’

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(ii)

2017 - 18 gâ¥ò

© btËp£lhs®fŸ

ISBN : 978-93-81650-66-0 F¿p£L v© : SG188

jiyik mYtyf«:

1620, `n#’ ãsh¡,

16-MtJ ãujhd rhiy,

m©zh ef®, br‹id-600 040. : 044-26162173, 26161099. : 81242 01000/ 81243 01000

Fax : (91) 44-26162173e-mail : orders @surabooks.comwebsite : www.surabooks.com

RuhÉ‹ jÄœ ciuüš

Sura’s English Guide

Sura’s Mathematics (EM / TM)

Sura’s Physics (EM / TM)

Sura’s Chemistry (EM / TM)

Sura’s Biology (EM / TM)

Sura’s Computer Sciene (EM / TM)

Sura’s Economics (EM)

Sura’s Commerce (EM)

Sura’s Accountancy (EM)

Sura’s Business Maths (EM)

Sura’s Sigaram Thoduvom (EM/TM) for all subjects

Also available for Std. - XII Guides and Previous Year Question Banks

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(iii)

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(iv)

bghUsl¡f«

bjhFâ - IntâÆaš

1. ntâÆaš fz¡ÑLfŸ ..............................................1 - 9

2. cnyhfÉaš g‰¿a bghJthd F¿¥òfŸ .......10 - 16

3. mQ mik¥ò - I ........................................................16 - 25

4. jÅk§fistif¥gL¤Jjš-I ..........................26 - 34

5. bjhFâ 1 s-bjhFâ jÅk§fŸ............................ 34 - 42

6. bjhFâ 2 s-bjhFâ jÅk§fŸ ........................... 43 - 47

7. p -bjhFâ jÅk§fŸ ............................................. 48 - 52

ïa‰ãaš ntâÆaš

8. âl Ãiyik - I ..............................................................54 - 59

9. thí Ãiyik - I .............................................................59 - 65

bjhFâ - IIïa‰ãaš ntâÆaš

10. ntâ¥ãiz¥ò - I ............................................................65 - 75

11. bjhifrh® g©òfŸ ....................................................75 - 81

12. bt¥g ïa¡fÉaš - I ....................................................81 - 86

13. ntâ¢rkÃiy - I ............................................................ 87 - 91

14. ntâ ÉidntfÉaš - I .............................................. 91 - 95

fÇk ntâÆaš

15. fÇk ntâÆaÈ‹ mo¥gil¡ bfhŸiffŸ .......96 - 102

16. fÇk¢nr®k§fis¤öŒik¥gL¤Jjš ............. 103 -105

17. jÅk§fis¡ f©l¿jY« msÉLjY« ......... 106 - 108

18. iA£nuh fh®g‹fŸ ................................................. 108 - 115

19. mnuhnk£o¡ iA£nuhfh®g‹fŸ ........................ 116 - 119

20. fÇk Ahy#‹ nr®k§fŸ........................................ 119 - 124

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ntâÆaš

11 M« tF¥ò

ghl«-1

ntâÆaš fz¡ÑLfŸ

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. khWg£l nr®k§fŸ xU _y¡TW thŒgh£oid bg‰¿U¡f

Koíkh? ckJ ÉilÆid ïU vL¤J¡fh£LfSl‹

És¡Ff.

(i) Koí«, m¢nr®k§fŸ kh‰¿a§fŸ vd¥gL«.

(ii) v.fh: - C3H6O ïªj _y¡TW thŒgh£il bg‰WŸs

nr®k§fŸ,

CH3- CO - C H3 - má£nlh‹

CH3- CH2 - CHO - ònuh¥gdhšoiAL

2. xU nt⢠rk‹gh£o‰FÇa K¡»a njitfŸ v‹d?

(i) rk‹ brŒa¡Toajhf ïU¡f nt©L«

(ii) _y¡TW ÃiyÆš ïU¡f nt©L«.

3. Ñœ¡fhQ« rk‹ghLfis rk‹ brŒ.

(i) Fe + H2O Æ Fe3O4 + H2

(ii) Fe2(SO4)3 +NH3 +H2O Æ Fe(OH)3 + (NH4)2SO4

(iii) KMnO4 + H2SO4 Æ K2SO4 + MnSO4 + H2O

+ O2 + Fe2(SO4)3 + FeSO4

(iv) K2Cr2O7 + H2SO4 + H2S Æ K2SO4 + Cr2(SO4)3 + H2O + O2 + S

[ 1 ]

This material only for sample

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2 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

(i) 3Fe + 4H2O → Fe3O4 + 4H2.

(ii) Fe2(SO4)3 + 6NH3 + 6H2O → 2Fe(OH)3 + 3(NH4)2 SO4

(iii) 4KMnO4+ 6H2SO4→ 2K2SO4 + 4MnSO4 + 6H2O + 5O2

(iv) 2K2Cr2O7+ 8H2SO4→ 2K2SO4 + 2Cr2 (SO4)3 + 8H2O+ 3O2

K¡»a Édh¡fŸ

1. _y¡TW thŒgh£L vil v‹whš v‹d?

xU nr®k¤â‹ _y¡TW thŒgh£oš fhz¥gL« mid¤J

mQ¡fË‹, mQÃiwfË‹ T£L¤bjhifna m¢nr®k¤â‹

_y¡TW thŒgh£L vil vd¥gL«.

2. NaCl -‹ thŒghL vil k‰W« mQ vil v‹d?

NaCl-‹ thŒgh£L vil 58.44 amu

NaCl-‹ mQ vil 22.99 amu

3. mtnf£nuh v© (NA) v‹gbj‹d? mt‰¿‹ kâ¥ò ahJ?

12 » (fh®g‹ - 12) š fhQ« mQ¡fË‹ v©Â¡ifna

mtnf£nuh v© MF«.

mtnf£nuh v© kâ¥ò = 6.0221367×1023

4. xU nkhš v‹gJ v‹d?

fh®g‹ - 12 Inrhnlh¥ãš, 12 » ÃiwÆš fhz¥gL« fh®g‹

mQ¡fË‹ v©Â¡if¡F rkkhd msî Mjhu¤ JfŸfis

bfh©LŸs bghUË‹ Ãiwna xU nkhš vd¥gL«.

5. xU nkhš bjhl® vij bghW¤J ga‹gL¤j¥gL»wJ?

maÅ bghU£fS¡F m¥bghUË‹ thŒghL myF

v©Â¡ifia bghW¤J nkhš bjhl® ga‹gL¤j¥gL»wJ.

v.fh: xU nkhš nrhoa« fh®gnd£oš (Na2CO3)6.023×1023‹

myFfŸ cŸsd.

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6 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. xU ntâ¢rk‹ghL jU« brŒâfŸ ahit?

(i) nt⢠rk‹ghL g©ò rh®ªJ«, msî rh®ªJ«

K¡»a¤Jt« bg‰¿U¡F«.

(ii) xU rk‹ghL ÉidbghU£fË‹ ÉisbghU£fË‹

bga®fis F¿¥ãL»wJ.

(iii) ntâÉidÆš <LgL« ÉidbghU£fŸ, Éis¥

bghUË‹ _y¡TW v©Â¡ifia bjÇÉ¡»wJ.

K¡»a Édh¡fŸ

1. ZnI2 jÅk§fË‹ neuo Éidahš bgw¥gL« nr®k«,

0.0654 nkhš ZnI2 c©lhtij ntâÆayhs® f©l¿ªj

Ãiw ahJ?

ZnI2 nkhyh® Ãiw 319»/nkhš

(thŒghL Ãiw 319amu)

ïªj kâ¥ò Zn k‰W« I2 mQ vilia¡ nr®¤J¥ bgw¥g£lJ

0.0654 nkhš ZnI2 × 319 ZnI2 20.9 ZnI2

1 ZnI2g=

»

nkhš

2. É»j thŒ¥gh£o‰F« _y¡TW thŒ¥gh£o‰F« cŸs

bjhl®ãid¡ TW.

xU nr®k¤â‹ _y¡TW thŒ¥ghL v‹gJ mj‹ RU¡»a

É»j thŒ¥gh£o‹ bgU¡F¤ bjhifahF«.

_¡TW thŒghL É»j« = n × É»j thŒghL

n = _y¡TW thŒgh£L Ãiw

É»j thŒgh£L Ãiw

v-fh. bg‹ÓÅ‹ É»j thŒghL = CH

bg‹ÓÅ‹ _y¡TW thŒghL = 6 (CH) = C6 H6

This material only for sample

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 7

3. by£ (II) Fnuhbk£ jahǤj nghJ 45.6 » PbCrO4 »il¤jJ.

ïâš fhQ« PbCrO4 nkhšfË‹ v©Â¡ifia f©l¿.

PbCrO4 ‹ nkhyh® Ãiw 323 / nkhš

vdnt 4 44

4

45.6 PbCrO PbCrO 0.141 PbCrO323 PbCrO

×=

» nkhšnkhš

»

4. nrhoa¤â‹ mQ vil v‹d? k‰W« NaCl ‹ thŒgh£o‹

vil v‹d?

(i) 22.99 amu

(ii) thŒghL vil = 58.44 amu

5. FnshÇ‹ mQ vil = 35.45 amu Fnshnuhgh®« (CHCl3)

ït‰¿‹ thŒgh£L vilÆid f©l¿f.

1 × AW of C = 12.0 amu

1 × AW of H = 1.0 amu

3 × AW of Cl = 3 ×35.45 = 106.4 amu

CHCl3-‹ thŒgh£L vil = 119.4 amu

6. fh®gÅ‹ F¿pL k‰W« mntfh£nuh v©iz

F¿¥ãLf?

(i) (NA) fh®gÅ‹ F¿pL

(ii) 12» - mQ¡fË‹ v©Â¡ifna mtfh£nuh v©.

(iii) rÛg¤âa msåLfŸ ïªj v© kâ¥ò 6.0221367×1023

v‹w kâ¥ig jªjhš 6.023×1023 v‹W F¿¡f¥gL»wJ.

7. CO2É‹ _y¡TW Ãiw v‹d?

(i) 44g mol–1

(ii) 44g CO2š 6.023×1023 _y¡TWfŸ cŸsd.

(iii) STP-š 2.24×10–2m3CO26.023×1023

This material only for sample

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10 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

ghl« - 2

cnyhfÉaš g‰¿a bghJthd F¿¥òfŸ

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. jFªj vL¤J¡fh£Ll‹ fÅk¤ijí«, jhJití«

ntWgL¤â¡ fh£Lf.

• fÅk§fŸ • jhJ¡fŸ

(i) v š y h f Å k § f S «

jhJ¡fŸ ïšiy. v.fh.

gh¡i[£, »Çnahiy£

v š y h j h J ¡ f S «

fÅk§fshF«.

(ii) òÉÆ‹ nk‰gu¥ãš, nr®k

ÃiyÆš fhz¥gL«

cnyhf§fŸ fÅk§fŸ

vd¥gL«.

xU fÅk¤âš cŸs cnyhf«

y h g f u k h d K i w Æ š

ãǤbjL¡f¥g£lhš mit

cnyhf¤ jhJ vd¥gL»wJ.

2. flšÚ® _y¤âÈUªJ »il¡F« jÅk§fŸ ahit?

Na, Mg, Cl2 k‰W« Br2 M»a eh‹F jÅk§fS«, x‰iw

mQ¡fË‹ maÅfŸ (Na+, Mg2+, Cl– Br–) bfh©l

rK¤âu§fËY« c¥ò ÚÇYÄUªJ ãǤbjL¡f¥gL»‹wd.

3. jhJit ml®ã¡F« gšntW KiwfŸ ahit?

(i) òÉ <®¥ò Kiw.

(ii) Eiu kâ¥ò Kiw.

(iii) Ä‹fhªj ãÇ¥ò Kiw.

(iv) ntâÆaš Kiw.

4. òÉ <®¥ò KiwÆš ãǤjš v‹whš v‹d?

(i) ösh¡f¥g£l jhJit rÇthd js¤âš it¤J

ntfkhf XL« ÚÇš fGt¥gL»wJ. nyrhd khR¡fŸ

mo¤Jbršy¥g£L fdkhd jhJ moÆš j§F»wJ.

(ii) nAkil£, btŸça¡fhš ngh‹w fdkhd M¡i[L

òÉ <®¥ò KiwÆš ãǤbjL¡f¥gL»wJ.

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 11

5. Eiu Äj¥ò KiwÆš ml®ã¡f¥gL« jhJ¡fË‹

bga®fis¡ F¿¥ãLf.

Eiu Äj¥ò KiwÆš ͧ¡ ãsh©£ (ZnS) k‰W« fh¥g® igiu£°

(CuFeS2) ngh‹w ršigL jhJ¡fŸ ml®ã¡f¥gL»‹wd.

6. cnyhfÉaš Kiwia tiuaW.

(i) cnyhf§fŸ mt‰¿‹ jhJ¡fËÈUªJ xL¡fš

KiwÆš ãǤbjL¡f¥gL»‹wd.

(ii) cnyhf§fË‹ j‹ik¡F V‰g, mt‰iw ãǤjš,

tW¤jš, cU¡» ãǤjš, öŒikah¡Fjš ngh‹w

KiwfS¡F c£gL¤â mt‰¿Å‹W cnyhf¤ij

ãǤbjL¡F« Kiw cnyhfÉaš MF«.

7. cnyhfÉaÈš ga‹gL« K¡»a KiwfŸ v‹d?

(i) jhJ¡fËš ïUªJ cnyhf¤ij¥ ãǤbjL¤jš.

(ii) khR¡fËSŸs cnyhf¤ij öŒik¥gL¤Jjš.

(iii) g©glhj cnyhf¤ij Û©L« öŒik¥gL¤Jjš.

8. fh‰¿šyh NHÈš tW¤jš v‹whš v‹d? v.fh. jUf.

fh®gnd£ (m) Únu‰w« milªj jhJ¡fis, fh‰¿šyh

NHÈš, mj‹ cUF Ãiyia Él Fiwªj bt¥gÃiyÆš

Nlh¡» tW¤J cnyhf M¡i[LfŸ bgW« Kiw fh‰¿šyh

NœÃiyÆš tW¤jš vd¥gL«.

v.fh : R©zh«ò¡ fš

Ènkhid£

CaCO CaO CO3 2∆ → ↑+

2 3 32 3 2 2 3 2Fe O H O Fe O H O→ + ↑

9. ne®Ä‹thŒ khR v‹whš v‹d?

Ä‹dh‰gF¥ã‹ nghJ, fiuahj khR¡fŸ Ä‹gFËÆš

fiuí« mšyJ fiurÈ‹ moÆš ne®Ä‹thŒ khR¡fshf¤

j§F»wJ. ï›thW goí« khR¡fŸ ne®Ä‹thŒ¤JfŸ

vd¥gL»wJ.

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12 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

10. Ñœ¡f©lt‰iw¥ g‰¿ v‹d m¿thŒ,

i) tW¤jš ii) cU¡»¥ ãǤjš

(i) tW¤jš : jhJit mj‹ cnyhf

M¡i[lhf (M¡Ì#nd‰w«)

kh‰w« Kiwna tW¤jš MF«.

(ii) cU¡»¥ ãǤjš : cnyhf M¡i[il, cnyhfkhf

kh‰W« xL¡f Éidna

cU¡»ãǤjš vd¥gL«.

K¡»a Édh¡fŸ

1. nr®ªj ÃiyÆš fhz¥gL« cnyhf§fŸ ahit?

M¡i[LfŸ – Mg, Cu, Zn, Al, Mn, Fe

gh°ng£LfŸ – Ca, Pb, Fe.

ršng£LfŸ – Fe, Cu, Pb, Hg

2. òÉ <®¥ò KiwÆš ãǤbjL¡f¥gL« jhJ¡fŸ vit?

nAkil£, btŸça¡fhš (xU btŸça¤ jhJ) ïit

ïu©L« fdkhd M¡i[L MF«.

3. ntâaš KiwÆš ãÇ¡f¥gL« jhJ vJ? ï«KiwÆ‹

áw¥ò v‹d?

mYÄÅa« jhJ - gh¡ir£ (Al2 O3)

jhJ Äf¤öŒikahf ïU¡f nt©LbkÅš ntâÆaš Kiw

ã‹g‰w¥gL»wJ.

4. kh£o vd¥gLtJ v‹d?

cUfhj khRthd FeO, FeSiO3 (frL) Mf kh‰w¥g£L

Ú¡f¥gL»‹wJ. ïitna kh£o vd¥gL«.

FeO + SiO2 → FeSiO3

khR - ïs¡» - frL

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 13

5. Ä‹dh‰ gF¥ò KiwÆš öŒikah¡f¥gL« cnyhf§fŸ

ahit?

Cu, Ag, Pb. Au. Ni. Zn

6. Fiw fl¤âfŸ v‹gbj‹d? cjhuz« bfhL.

khR¡fŸ ïU¡F« nghJ xU bghUË‹ cUF Ãiy Fiwí«

v‹gnj Fiwfl¤âÆ‹ j¤Jt« MF«.

(áÈf‹, blšÿÇa«, b#®khÅa«) ï«Kiw Äfî« öŒikahd

cnyhf«, jahÇ¡f ifahs¥gL»‹wJ.

7. v~F ïU«ò v‹gbj‹d?

v~F ïU«ò v‹gJ 0.15% - 1.5% fh®g‹ fyªj fh®g‹ ïU«ò

fyit MF«.

8. kh‰¿ Kiw f©l¿ªjt® ah®? vªj M©L vªj njr¤ij

rh®ªjt®?

bA‹¿ bgák®

1856

炙yhªJ.

9. Ä‹dh‰gF¥ò KiwÆš JhŒikgL¤â bgw¥gL«

cnyhf§fŸ ahit?

(i) Cu, Ag, Pb, Au

(ii) Ni, Sn, Zn

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. bgák® KiwÆ‹ j¤Jt« v‹d?

ï«KiwÆš kh‰¿ vd¥gL« Ô¡fËk© ór¥g£l

bfhŸfy¤âš 2 tËk©ly mG¤j¤âš it¡f¥g£LŸs

th®¥ò ïU«ãš FË® fh‰W Cj¥gL« nghJ khR¡fŸ

M¡á#nd‰w« brŒa¥gLtnjhlšyhkš th®¥ò ïU«ò v~fhf

kh‰w¥gL»‹wJ.

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14 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

2. Ä‹dh‰gF¥ò KiwÆš öŒik¥ gL¤jš v‹whš v‹d?

vL¤J¡fh£L jUf.

(i) khRŸs cnyhf¤ j©L ne®Ä‹thahfî«, cnyhf¤â‹

bkšÈa jfL vâ®Ä‹thahf brašg£L, cnyhf

fiuriy Ä‹gFËahf vL¤J¡bfhŸs¥gL»wJ. ïj‹

tÊahf Ä‹rhu¤ij brY¤J« nghJ ne®Ä‹thÆš

cŸs öa cnyhf« vâ®Ä‹thÆš go»wJ.

(ii) fiuahj khR¡fŸ Ä‹gFËÆš fiu»wJ.

v.fh : jhÄu«, nfhš£, ášt®

K¡»a Édh¡fŸ

1. jhJit ml®ã¡F« _‹W Kiwfis vGJf.

(i) òÉ <®¥ò Kiw

(ii) Eiu Äj¥ò Kiw

(iii) Ä‹fhªj¥ ãÇ¥ò Kiw

2. cnyhfÉaš ga‹gL« _‹W Kiwfis vGJf.

(i) khRŸs cnyhf¤ij JhŒikgL¤Jjš.

(ii) jhJÉš ïUªJ cnyhf¤ij ãǤbjL¤jš.

(iii) cnyhf¡ fyitfis jahǤjš.

3. ïs¡» v‹whš v‹d?

(i) jhJÉš ïUªJ cnyhf¤ij cU¡» ãǤjš,

(ii) cU¡» ãǪJŸs nghJ khRit frlhf kh‰w

nr®¡fgL« ntâ¥bghUŸ ïs¡».

4. ônuÅa« k‰W« bk¡Üáa¤â‹ K¡»a jhJ ahJ?

(i) ínuÅa« - ã£á ãs©o

(ii) bk¤Üáa«« - nlhyik£

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16 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

10. kh©£ KiwÆš áfiy ãǤbjL¡F« Kiwia ÉtÇ?

(i) khRŸs Ni cnyhf«, CO cl‹ bt¥g¥gL¤j¥gL»wJ.

(i) »il¤j áfš fh®gidš áij¡f¥g£L™öaáfš

cnyhfK«, CO c« bgw¥gL»wJ.

Ni + 4CO Ni(CO)4 Ni + 4CO

ghl« - 3

mQ mik¥ò - I2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. vy¡£uh‹, ònuh£lh‹ k‰W« Ãô£uh‹fŸ ÛJŸs

Ä‹}£l« v‹d?

(i) vy¡£uhÅ‹ Ä‹}£l« - vâ®Ä‹ Rik. (–ve)

(ii) ònuh£lhÅ‹ Ä‹}£l« - ne®Ä‹ Rik (+ve)

(iii) Ãô£uh‹ Ä‹}£l« ïšiy, Ä‹Rika‰wJ

(eLÃiyahdJ)

2. mQ v© v‹whš v‹d?

(i) xU mQÉš ïU¡F« ne®Ä‹RikfË‹ v©Â¡ifia

mQ v© vd¥gL«.

(ii) xU mQÉš cŸs ònuh£lh‹ (m) vy¡£uhÅ‹

v©Â¡ifna mªj mQÉ‹ mQ v© vd¥gL«.

3. X® M®ã£lhš mâfg£r« v¤jid vy¡£uh‹fŸ ïU¡f

ïaY«?

X® M®ã£lhÈš mâfg£r« ïu©L vy¡£uh‹fŸ ïl«bgW«.

4. ïu©lhtJ R‰W tisa ghijÆš fhQ«

M®ã£lhšfË‹ v©Â¡if v‹d? mit v›thW

F¿¥ãl¥gL»‹wd?

(i) ïu©lhtJ t£l¥ghijÆš ïu©L Éjkhd

M®ã£lhšfŸ ïU¡F«.

(ii) mit 2s k‰W« 2px., 2py , 2pz.. v‹W ãÇ»‹wd.

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22 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

K¡»a Édh¡fŸ

1. mQ khâÇ bfhŸif ahuhš, vªj M©L

f©Lão¡f¥g£lJ?

r® n#. n#. jh«r‹ ; 1904

2. mQ¡ bfhŸifia njh‰Wɤjt® ah®? ït® fU¤J

ahJ?

#h‹ lhšl‹ 1808

všyh¥ bghU£fS« Äf E©Âa JfŸfsh»a mQ¡fshš

M¡f¥g£litahF«.

3. ájU« nrhjidia el¤âat® ah®? fhuz« ahJ?

%j®ngh®L (1911)

vy¡£uh‹ k‰W« ònuh£lh‹fŸ v›thW mikªJŸsd

v‹gij m¿tj‰fhf.

4. Fth©l¡ bfhŸifia rh®ªJ mQ khâÇ¡ bfhŸifia

kh‰¿ mik¤jt® ah®? fhuz« ahJ?

Úš°ngh® (1913)

%j®ngh®o‹ mQ khâÇÆ‹ FiwghLfis fistj‰fhf.

5. Fth©l« v© v‹gJ v‹d? v¤jid tif¥gL«?

xU mQÉš fhQ« vy¡£uhid F¿¥ãl njit¥gL«

F¿¥òfns Fth©l« v©fshF«.

mit 4 tif¥gL«.

6. Fth©l v©fË‹ tiffŸ ahit?

(i) Kj‹ik Fth©l« v© (n)

(ii) nfhz cªj« (m) Jiz Fth©l« v© (l)

(iii) fhªj Fth©l« v© (m)

(iv) j‰RH‰á Fth©l« v© (s)

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 23

7. FnuhÄa¤â‹ vâ®gh®¡F« vy¡£uh‹ mik¥ãid jUf?

1s2, 2s2, 2p6, 3s2, 3p6, 3d4, 4s2

8. fh¥gÇš fhz¥gL« vy¡£uh‹ mik¥ãid jUf?

1s2, 2s2, 2p6, 3s2, 3p6, 4s10, 4s1

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. xU jÅk¤â‹ mQ Ãiw 24. mj‹ mQ v© 12. v›thW

ïªj mQ mik¥ò cŸsJ?

(i) mQ v© 12 v‹gâš ïUªJ ïªj mQÉš 12

ònuh£lh‹fŸ k‰W« 12 vy¡£uh‹fŸ cŸsd v‹gJ

bjËth»wJ. Ãiw v©, 24 vÅš c£fU¤JfŸfŸ = 24

MF«.

ònuh£lh‹fŸ + Ãô£uh‹fŸ = 24 MF«

Ãô£uh‹fË‹ v©Â¡if = 24 –12 = 12

(ii) ïªj mQ mik¥ãš 12 ònuh£lh‹fŸ

12 vy¡£uh‹fŸ

12 Ãô£uh‹fŸ cŸsd.

2. xU d- Jiz¡ T£oš v¤jid vy¡£uh‹fŸ s + ½ kâ¥ig¥ bg‰WŸsd?

(i) d M®¥ã£lhÈš 5 Jiz¡ TLfŸ cŸsd

(ii) Jiz¡ T£oš ïu©L vy¡£uh‹fŸ cŸsd.

(iii) RH‰á Fth©l« v©fË‹ kâ¥òŸs + ½ mšyJ –½

(iv) d Jiz¡ T£oš 5 vy¡£uh‹fŸ s = + ½ kâ¥ãid¥

bg‰¿U¡F«.

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24 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

K¡»a Édh¡fŸ

1. %j®ngh®o‹ mQÉ‹ c£fU khâÇ bfhŸifia

És¡Ff.

(i) X® mQÉ‹, ika¥gFâ E©Âa ne®Ä‹Dh£lKila

c£fU cŸsJ.

(ii) c£fUÉ‹ ne®Ä‹Dh£l¤â‰F ònuh£lh‹fŸ fhuz«

MF«. eLÃiy¤ JfŸfŸ Ãô£uh‹fŸ MF«.

(iii) c£fUÉš cŸs ònuh£lh‹, Ãô£uh‹, ïitahî«

x£Lbkh¤jkhf c£fU¤ JfŸfŸ (Nucleons) vd

miH¡f¥gL»‹wd.

(iv) c£fU¤ JfË‹ bkh¤j v©Â¡ifna mQÉ‹ Ãiw

v©zhF«. (A)

2. Úš° nghÇ‹ kh‰¿aik¡f¥g£l mQ khâÇ¡

bfhŸifÆ‹ nfh£ghLfŸ ahit?

(i) M®ã£fËš k£Lnk vy¡£uh‹fŸ c£fUit¢ R‰¿

tU»‹wd ïit M‰wš k£l§fŸ vd¥gL»‹wd.

(ii) nfhz cªj« h/2π v‹w kl§»š mika¥bg‰w

vy¡£uh‹fis V‰F« M®ã£fŸ (tisaghijfŸ)

k£L« V‰f¥gL« M®ã£fŸ MF«. ïâš h v‹gJ ãsh§

kh¿È.

(iii) mvr = nh/ 2π ï§F n = 1,2,3,4.............

vy¡£uhÅ‹ nfhz cªj«, Fth©l« kâ¥òfis

bfh©ljhF«.

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26 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

ghl« - 4

jÅk§fis tif¥gL¤Jjš - I2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. F, Cl, Br k‰W« I M»at‰iw vy¡£uh‹ ft® v‹jhšãÆ‹

VWtÇirÆš vGJ.

1 < F< Br < Cl v‹w tÇirÆš ïU¡F«.

2. mQ v©fŸ 6 Kjš 14 tiu cŸs jÅk§fË‹ vy¡£uh‹

mik¥ig vGJf. mit jÅk tÇir m£ltizÆš vªj

bjhFâia¢ rh®ªjit vd¡ f©Lão.

mQ

jÅk¤â‹

bga®

vy¡£uh‹

mik¥òbjhFâ

6 fh®g‹ 1s2, 2s2, 2p2 14(IV-A)14 áÈf‹ 1s2, 2s2, 2p6, 3s2, 3p2 14(IV-A)

3. Ñœ¡f©l vªj vy¡£uh‹ mik¥ò Äf¡ Fiwªj

maÅah¡F« v‹jhšãia bg‰WŸsJ.

(a) 1s2, 2s2, 2p6 ; (b) 1s2, 2s2, 2p6 ; (c) 1s2, 2s2, 2p2, 3s2.

vy¡£uh‹ mik¥ò 1s2, 2s2, 2p6, 3s2 Äf¡ Fiwªj maÅ M¡F«

v‹jhšãia bg‰WŸsJ.

4. òâa Mt®¤jd Éâia¡ TW.

òâa Mt®¤jd Éâ¥go, jÅk§fË‹ ïa‰ãaš k‰W«

ntâÆaš g©òfŸ mt‰¿‹ mQ v©fis mo¥gilahf

bfh©ljhF«.

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 27

5. kªj thí¡fŸ ó{Ía vy¡£uh‹ ft® v‹jhšãia

bg‰WŸsij És¡Ff.

kªj thí¡fËš btËT£oYŸs s M®ã£lhY« p M®ã£lhY«

KGikahf Ãu¥g¥g£LŸsd. (ns2, np6) mit vy¡£uhid

bgWtnjh ïH¥gnjh ïayhJ. vdnt kªjthí¡fŸ ó{a

vy¡£uh‹ ft® v‹jhšãia bg‰WŸsd.

6. Ñœ¡f©lt‰¿š vªj n#ho jÅk§fŸ Fiwªj

maÅah¡F« v‹jhšãia bg‰WŸsd.

(a) Cl mšyJ F (b) Cl mšyJ S

(c) K mšyJ Ar (d) Kr mšyJ Xe

(a) Cl (b) S (c) K (d) Xe M»ait Fiwªj Kjš maÅ M¡F«

v‹jhšãia bg‰WŸsd.

7. VjhtJ ïu©L ïilÃiy¤ jÅk§fisí«, ïu©L

cŸ ïilÃiy¤ jÅk§fisí« vGJf.

(i) ïilÃiy¤ jÅk§fŸ - áfš k‰W« jhÄu«

(ii) cŸ ïilÃiy¤ jÅk§fŸ - ínuÅa« k‰W« njhÇa«

8. Ñœ¡f©lt‰iw mQ¥ gUk‹fË‹ VW tÇirÆš

vGJf.

(a) Li, Na k‰W« K ;

(b) C, N k‰W« O ;

(c) Ca, Sr k‰W« Ba

(a) Li < Na < K b) O < N < C c) Ca < Sr < Ba

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28 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

9. jÅk tÇir m£ltizÆš cŸs bt›ntW bjhFâfŸ

ahit? x›bthU bjhFâ¡F« cŸs bghJthd

vy¡£uh‹ mik¥ig vGJf.

bjhFâÆ‹ bga® vy¡£uh‹ mik¥ò

s bjhFâ jÅk§fŸ ns1–2

p bjhFâ jÅk§fŸ ns2 np1–6

d bjhFâ jÅk§fŸ (n–1)d1–10 ns1–2

f bjhFâ jÅk§fŸ (n–2)f 1–14 (n–1) d 0–1 ns2

10. 3d10 4s2 vy¡£uh‹ mik¥ò bfh©l jÅk« vªj

bjhFâia¢ rh®ªjJ?

3d10 4s2 vy¡£uh‹ mik¥ò bfh©l jÅk«, jÅk tÇir

m£ltizÆš d - bjhFâia¢ rh®ªjJ.

11. òqÇ‹ k‰W« FnshÇ‹ M»at‰¿š vJ mâf

vy¡£uh‹ ft® v‹jhšãia cilaJ?

(i) �EF < ECl (EF = 322 kJ mol–1, ECl = 349 kJ mol–1)

(ii) �F -¡F Fiwªj kâ¥ã‰F fhuz« vy£uh‹ - vy¡£uh‹

Éy¡F Éir.

(iii) 2p �M®ã£lhÈš f£lik¥ò MF«.

12. d- bjhFâ jÅk§fŸ V‹ ïilÃiy¤ jÅk§fŸ vd

miH¡f¥gL»‹wd.

Éidâw‹ Ä¡f s - bjhFâ jÅk§fS¡F«, Fiwªj

Éidâw‹ bfh©l p - bjhFâ jÅk§fS¡F ïilna

ghykhf És§Ftjhš ïit ïilÃiy¤ jÅk§fŸ vd

miH¡f¥gL»‹wd.

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 29

13. bk©lä¥ jÅk§fis vªj g©ã‹ mo¥gilÆš

tÇir¥gL¤âdh®?

bk©lä¥ jÅk§fis mt‰¿‹ mQ ÃiwÆ‹ VW tÇir

mo¥gilÆš tÇir¥gL¤âdh®.

14. Li, K, Ca, S k‰W« Kr M»at‰¿š vJ mâf Kjš

maÅah¡F« M‰wiyí«, Fiwªj Kjš maÅah¡F«

M‰wiyí« bg‰WŸsJ?

(i) bgh£lháa« jh‹ Äf¡ Fiwªj Kjš maÅah¡F«

M‰wiy¥ bg‰¿U¡F«.

(ii) »Ç¥lh‹ mâf Kjš maÅ M¡F« M‰wiy¥ bg‰¿U¡F«.

K¡»a Édh¡fŸ

1. K«ikfŸ v‹gbj‹d? cjhuz« bfhL.

x¤j g©òila _‹W jÅk§fŸ bfh©l bjhFâ K«ikfŸ

vd¥gL«.

c.«:- Ȥâa«, nrhoa« k‰W« bgh£lháa«.

2. K«ikfŸ vªj M©L ahuhš tif¥gL¤j¥g£lJ?

K«ik¡F c.«. jUf.

1829, nlhgÇ‹d®

c.«:- Ȥâa«, nrhoa« , bgh£lháa«.

3. Ãôy©o‹ v£lhtJ Éâia tiuaW.

jÅk§fis, mQÃiwfË‹ VW tÇirÆš tÇir¥gL¤J«

nghJ, v£lhtJ jÅk« KjyhtJ jÅk¤â‹ g©òfis

x¤J ïU¡F«.

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32 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. V‹ xnu bjhFâÆš cŸs jÅk§fŸ x¤j¥ g©òfis¥

bg‰WŸsd?

(i) xU bjhFâÆš cŸs jÅk§fË‹ xnu vy¡£uh‹

mik¥ig bg‰WŸsd.

(ii) nkY« mt‰¿š btË¡TL M®ã£lhÈš rk

v©Â¡ifÆš vy¡£uh‹fisí«, xnu g©òfisí«

bg‰WŸsd.

(iii) v.fh. bjhFâ 1š cŸs jÅk§fŸ mid¤J« ns1 v‹w

btËT£L vy¡£uh‹ mik¥ig bg‰WŸsjhš x¤j

g©ig bfh©LŸsJ.

2. ie£u#dhdJ M¡á#id Él mâf IE bg‰WŸsij

És¡F.

(i) �8O(1s2 2s2 2px2 2py

1 2pz1) vËâš xU vy¡£uhid ïHªJ

Ãiyahd vy¡£uh‹ mik¥ig¥ bgWtjhš Fiwªj IE

bg‰¿U¡F«.

(ii) �7N(1s2 2s2 2px2 2py

1 2pz1) mâf Ãiy¤j‹ik bg‰Wšy-

jhš, vy¡£uhid Ú¡FtJ fod«.

�(iii) ï¡fhuz¤jhš ie£u#‹ M¡á#id Él mâf IE

bg‰WŸsJ.

K¡»a Édh¡fŸ

1. nlhgÇ‹ K«ik Éâia TWf?

_‹W jÅk§fŸ mt‰¿‹ mQÃiwÆ‹ VWtÇirÆš

tÇir¥gL¤j¥go‹ eLÉš cŸs jÅk¤â‹ mQ

ÃiwahdJ k‰w ïu©L jÅk§fË‹ mQ ÃiwfË‹

ïa‰fÂj ruhrÇahf ïU¡F«.

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 33

jÅk§fŸ mQÃiw

Li 7Na 23K 39

2. jÅk tÇir m£ltizÆš iA£u#Å‹ ïl« v‹d?

(i) áw¥ò jFâíilajhŒ, iA£u#‹ jÅk tÇir

m£ltizÆš nkš gFâaš it¡f¥g£LŸsJ.

(ii) iA£u#‹ jŤj 1s vy¡£uhid¥ bg‰WŸsJ.

(iii) iA£u#‹ fhu cnyhf§fis¥ nghyî«, X® vy¡£uhid

th§» bfh©L kªj thíÉ‹ mik¥ãid bgWtjhš

Ahy#‹fis¥ nghyî« brašgL»‹wJ.

(iv) ï¢áw¥ghd fhuzkhf m£ltizÆš nk‰òw¤âš

iA£u#‹ it¡f¥g£LŸsJ.

3. rhjhuz jÅk¤â‰F« ïilÃiy¤ jÅk¤â‰F« cŸs

ntWghL ahJ?

rhjhuz jÅk§fŸ ïilÃiy¤ jÅk§fŸ

mnyhf§fS«, cnyhf§fS«

cilait

cnyhf§fshF«

Éidô¡»ahf

brašgLtâšiy

Éidô¡»ahf¢

brašgL«

mizî¢ nr®k¤ij

cUth¡Ftâšiy

ïit mizî¢

nr®k¤ij cUth¡F«

Ãwk‰w nr®k¤ij

cUth¡F»wJ

bghJthf ÃwKŸs

nr®k§fis cUth¡F«

4. m¿Éaš m¿P®fË‹ bgaÇid¡ bfh©l VnjD«

_‹W bjhF¥ò jÅk§fË‹ bgaÇid vGJf.

(i) bg®Äa« - Fm (Z = 100)

(ii) bk©läÉa« - Md (Z = 101)

(iii) yhu‹áa« - Lr (Z = 103)

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34 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

5. âiu Éisî v‹whš v‹d?

mâf v©Â¡if, vy¡£uh‹fis¡ bfh©l mQ¡fËš,

c£TL vy¡£uh‹fs, btËT£L vy¡£uh‹fS¡F«,

mQ c£fUɉF« ïilna xU âiu nghš brašgL»wJ.

ïjdhš btËT£L vy¡£uh‹fŸ c£fUit neh¡»

<®¡f¥gLtâšiy. c£TL vy¡£uh‹fË‹ ïªj kiwªj

Éisit âiu Éisî v‹»nwh«.

ghl« - 5

bjhFâ 1s - bjhFâ jÅk§fŸ

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. Inrhnlh¥òfŸ v‹whš v‹d? iA£u#Å‹

Inrhnlh¥òfis¡ F¿¥ãL.

Inrhnlh¥òfŸ v‹gJ xnu mQ v©fisí« bt›ntW Ãiw

v©fisí« bfh©l jÅk¤â‹ mQ¡fŸ MF«.

iAou#Å‹ Inrhnlh¥òfŸ

ònuh£oa« (m) rhjhuz iA£u#‹ 11H

oô£oÇa« (m) fd iA£u#‹ 12 D

oÇ£oa« (m) fâÇa¡f iA£u#‹ 13T

2. oÇ£oa¤ij g‰¿ áW F¿¥ò tiuf.

(i) Ãiw v© 3 mQ v©.1

(ii) xU ònuh£lh‹ xU vy¡£uh‹ ïu©L Ãô£uhiz

bg‰WŸsJ.

(iii) fâÇa¡f g©ò cilaJ

(iv) miu Mí£fhy« Rkh® 12.3 M©LfŸ.

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3. v›thW oô£oÇa« ie£u#Dl‹ Éid òÇ»wJ?

Éidô¡» K‹ÅiyÆš oô£Ça« ie£u#Dl‹ ÉidòǪJ

ie£u#‹ Oô£oiuL c©lh»wJ. ïJ fd m«nkhÅah (m)

oô£onuh m«nkhÅah v‹W« miH¡f¥gL»wJ.

3D2 + N2 → 2ND3

4. oô£oÇa« v›thW cnyhf§fSl‹ Éid òÇ»wJ?

oô£oÇa« mâf bt¥gÃiyÆš (633 K) fhu cnyhf§fSl‹

ÉidòǪJ oô£oidLfis c©lh¡F»wJ.

2Na + D2 → 2NaD

5. oÇ£oa« v›thW jahÇ¡f¥gL»wJ?

Ȥâa¤ij bkJthf¢ bršY« Ãô£uh‹id bfh©L

jh¡Ftjhš, 1T3 »il¡»wJ.

3Li6 → 0n1 → 1T

3 + 2He4

6. v›thW fdÚ® cnyhf§fSl‹ ÉidòÇ»wJ?

D2O cnyhf§fSl‹ Äf bkJthf Éid¥g£L fd

iA£u#id btËna‰W»wJ.

2Na + 2D2O → 2NaOD + D2

nrhoa« oô£ouh¡i[L

Ca + 2D2O → 2Ca(OD)2 + D2

fhšáa« oô£ouh¡i[L

7. iA£u#‹ bguh¡irL MŒtf¤âš v›thW

jahÇ¡f¥gL»wJ?

Ú®¤j fªjf mÄy¤ij nrhoa« bguh¡i[L ÛJ

Éid¥gL¤Jtj‹ _y« H2O2 MŒtf¤âš jahÇ¡f¥gL»wJ.

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36 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

(fz¡»l¥g£l Na2O2 20% gÅ¡f£o fyªj fªjf mÄy¤âš

nr®¡f¥gL»wJ.)

Na2O2 + H2SO4 → Na2SO4 + H2O2

ï«KiwÆš 30% H2O2 fiurš »il¡»wJ.

8. iA£u#‹ bguh¡iro‹ xL¡f¥ g©ig¥ g‰¿ vGJf.

iA£u#‹ bguh¡i[L xU áwªj M¡Ì#‹ xL¡».

ïJ ášt® M¡i[Ll‹ Éid òǪJ mjid áštuhf

xL¡F»wJ.

Ag2O + H2O2→ 2Ag + H2O + O2

9. H2O2 ï‹ ïU K¡»a ga‹fis vGJf.

(i) uh¡bf£LfËš vÇbghUshfî«

(ii) f«ãË, g£L ngh‹w ÄUJthd bghU£fis btS¡f.

(iii) »UÄ eháÅahf ga‹gL»wJ.

10. fhu cnyhf§fŸ V‹ Fiwªj cUFÃiyaí«,

bfhâÃiyí« bfh©LŸsd?

(i) â©k ÃiyÆš tY¡Fiwªj ãiz¥ig bg‰¿U¥gjhš

Fiwthd cUF Ãiyiaí« bfhâ Ãiyiaí«

bg‰WŸsd.

(ii) ïizâw‹ vy¡£uh‹fŸ x‹W ïU¥gJ«, mt‰¿‹

mQ Mu« bgÇajhf ïU¥gJ« MF«.

11. V‹ fhu cnyhf§fŸ tÈik ÄFªj ne®Ä‹ jÅikia¥

bg‰WŸsd?

fhu cnyhf§fŸ Fiwªj maÅah¡F« M‰wš bg‰¿U¥gjhš

mit vËjhf X® vy¡£uhid ïHªJ, x‰iw ne®Ä‹

maÅia njh‰WÉ¡»‹wd.

M → M+ + 1e– vdnt ïit tÈik ÄFªj ne®Ä‹

j‹ikíilaitahF«.

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 37

K¡»a Édh¡fŸ

1. xË Ä‹ Éisî - tiuaW?

fhu cnyhf§fŸ ne®Ä‹ Rik cilait. ï› cnyhf§fŸ

xËÆ‹ ghijÆš it¤J xËô£l¥g£lhš, vy¡£uhid

btˤjŸS«, ï›ÉisthdJ xË Ä‹ Éisî.

2. Ȥâa¤â‹ ga‹fŸ ahit?

(i) Ȥâa« nr®k§fŸ, f©zho k£gh©l§fŸ jahÇ¡fî«

(ii) cnyhf fyit bgUksÉš jahÇ¡fî«, k‰W«

(iii) LiAlH4 xL¡»ahfî« ga‹gL»wJ.

3. oÇ£oÇa¤â‹ g©òfŸ ahit?

(i) oÇ£oÇa¤â‹ miu Mí£fhy« 12.4 M©LfŸ

(ii) fâÇa¡f¤ j‹ik cila jÅk«.

(iii) β fâ®fis cÄœªJ ëÈa« - 3 Mf áij»wJ.

1T3 → 2He3 + –1e

0

4. oô£oÇa¤ij v›thW bgwyh«?

fdÚiu nrhoa« brŠNlh¡f¥g£l l§°l‹ _y« áij¤J

(m) nrhoa« fh®gnd£Ll‹ Ä‹dh‰ gF¤njh oô£oÇa¤ij

bgwyh«.

2D2O Ä‹dh‰ gF¤jš

oô£oÇa« 2D2 + O2

2D2O + 2Na2 → 2NaOD + D2 nrhoa« oô£uh¡i[L

5. Ȥâa¤â‹ g©òfŸ ahit?

Ȥâa«, bt©ik ÃwKila cnyhf«, Äfî« nyrdhJ k‰w

cnyhf§fSl‹ nr®ªJ cnyhf¡ fyití«, ur¡ fyitiaí«

c©Lg©Q«, <uKŸs fh‰whš clnd M¡á#nd‰w«

mil»wJ. Ȥâa« åÇaÄ¡f ne®Ä‹j‹ikíŸs cnyhf«.

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40 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. oô£oÇa¤â‹ ga‹fŸ ahit?

(i) ntâÉidfË‹ tÊKiwia m¿í« Rtl¿thdhfî«

(ii) bra‰if fâÇa¡f¤ij V‰gL¤jî« k‰W«

(iii) k£L¥gL¤âahf mQ ciyfËš ga‹gL»wJ.

2. ghuh iA£u#id v›thW M®¤njh iA£u#dhf

kh‰WthŒ?

(i) ãsh£od« ma®‹ ngh‹w Éidntf kh‰¿fSl‹

nrU« nghJ

(ii) Ä‹ ghŒ¢riy c£brY¤J« nghJ

(iii) 800º C nkš cŸs bt¥gÃiy¡F Nnl‰W« nghJ

(iv) O2, NO, NO2 ngh‹w ghuh fhªj j‹ikíŸs _y¡

TWfSl‹ nr®¡F«nghJ.

(v) ãwÉ Ãiy iA£u#‹ (m) mQ Ãiy iA£u#ndhL

nr®¡F« nghJ.

3. iA£u#‹ bguh¡irL fiurš v›thW ml®ã¡f¥

gL»wJ?

(i) iA£u#‹ bguh¡irL fiurÈš cŸs khR¡fŸ fÇk¥

bghU£fSl‹, cnyhf maÅfS«, mJ bto¤J¢

áijîWtij ö©lyh«.

(ii) Ú®¤bjh£oÆš it¡f¥g£l fiurš ftdkhf

Fiwªj mG¤j¤âš ãÇ¥ò¡ fy‹fis ga‹gL¤â

MÉah¡f¥gL»wJ.

(iii) Fiwªj mG¤j¤âš 330 K¡F« Fiwthd bt¥gÃiyÆš

fhŒ¢r¥g£l fiurÈš 90% fiurš »il¤jã‹,

gofkh¡f¥gL»wJ.

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 41

K¡»a Édh¡fŸ

1. nrhoa¤â‹ ga‹fŸ ahit?

(i) nrhoa« ur¡fyit xL¡»ahf¥ ga‹gL»wJ.

(ii) fÇk ntâÆaÈš Éid fhuÂahfî«, k‰W«

(iii) bra‰if u¥g® jahǥ㚠Éidô¡»ahf ga‹gL»wJ.

2. bls‹ KiwÆš, nrhoa« jahÇ¥ãiz RU¡fkhf

És¡Ff.

cU»a nrhoa« Fnshiuil Ä‹dh‰gF¥ò brŒJ nrhoa«

bgUksÉš jahÇ¡f¥gL»wJ. bls‹ Ä‹dh‰ gF¥ò fy«

ma®‹ bg£o mik¥òilaJ. fh®gidš ne®Ä‹thahfî«,

ïU«ò vâ®Ä‹thŒ, ït‰¿‰F eLnt jL¥ò Rt®

mik¥òŸsJ. Ä‹dh‰gF¡F« btËah»wJ. vâ® Ä‹thÆš

nrhoa« f«ã¡FŸ j§F»wJ.

cU»a nrhoa¤â‹ msî mâfÇ¡F« nghJ mJ tʪJ

bfhŸfy¤âDŸ ÉG»wJ.

2NaCl → 2Na + Cl2

3. oô£Ça¤â‹ gâä£L Éidfis ÉtÇ.

oô£Ça« mQ iA£u#D¡F¥ gâyhf gâäL brŒa¥gL»wJ.

NH3, CH4 k‰W« H2O, ca®bt¥gÃiyÆš oô£Ça« KGtJkhf

gâäL brŒa¥gL»wJ.

H2 + D2 � ⇀�↽ �� 2HD

2NH3 + 3D2 � ⇀�↽ �� 2ND3 + 3H2

H2O + D2 � ⇀�↽ �� D2O + H2

CH4 + 2D2 � ⇀�↽ �� CD4 + 2H2

C2H6 + 3D2 � ⇀�↽ �� C2H6 + 3H2

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ghl« - 6

bjhFâ 2s - bjhFâ jÅk§fŸ

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. MgCl2 fiurYl‹ NH4Cl k‰W« Ú®¤j mnkhÅah nr®¡F«

nghJ Mg(OH)2 åœgoî cUthtJ ïšiy. V‹?

(i) fiuâw‹ mâfkhf ïU¡»wJ.

(ii) á¿a mËÉš f£lik¥ò bg‰WŸsJ.

(iii) Mg(OH)2 , NH4Cl fiurÈš vËâš fiuªJ ÉL«.

2. M2+ maÅah¡F« M‰wš, M+ maÅah¡F« M‰wiy Él

r‰nw ca®ªJ fhz¥gL»wJ. V‹?

(i) fhuk© cnyhf§fËŸ ïu©lh« maÅ M¡F« M‰wš

bg‰¿UªjhY« M2+ maÅfis¤ jU»‹wd.

(ii) â©k ÃiyÆš Ú® fiurÈš mâf Únu‰w bt¥g¤ij

k‰W« mâf gof M‰wiy bg‰¿U¡»wJ.

(iii) fhuk© cnyhf§fŸ ïu©lhtJ vy¡£uhid Ú¡»,

kªjthí mik¥ig bgW»wJ.

3. fhuk© cnyhf§fË‹ fh®gnd£ k‰W« iA£uh¡i[L

fË‹ Ãiy¥ò j‹ikia¡ bfh©L mL¡Ff.

fhuk© cnyhf§fË‹ mQ v© mâfǤjhš mt‰¿‹

fh®gnd£ k‰W« iA£uh¡i[LfË‹ Ãiy¥ò¤ j‹ik

mâfÇ¡F«.

fh®gnd£ Ãiy¥ò¤j‹ik VWtÇirÆš

BeCO3 < MgCO3 < CaCO3 < SrCO3 < BaCO3

iA£uh¡i[LfË‹ Ãiy¥ò¤j‹ik

Be(OH)2 < Mg(OH)2 < Ca(OH)2 < Sr(OH)2 < Ba(OH)2

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44 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

4. V‹ bgÇÈa« AhiyL fh‰Wl‹ òif»wJ?

bgÇÈa« AhiyL Ú®¡fh‰Wl‹ vËâš Ú®¡fh‰Wl‹

ÉidòǪJ HCl òifia ju¡ToaJ. bgÇÈa« AhiyL

rf¥ãiz¥ò j‹ik bfh©LŸsjhš vËâš Únu‰w« bg‰W

HCl I¤ jU«.

BeCl2 + 2H2O → 2Be(OH)2 + 2HCl

5. fhuk© cnyhf§fË‹ khndh M¡i[LfŸ Äfî«

Ãiy¥ò¤ j‹ik cilaJ V‹?

(i) fhuk© cnyhf§fË‹ khndh M¡i[LfŸ Äfî«

Ãiy¥ò¤ j‹ik bgw¡ fhuz«, maÅfS¡»ilna

fhz¥gL« mâf msî <®¥ò Éirna MF«.

(ii) M2+ k‰W« O2– M»a maÅfËilna cŸs <®¥ò Éir

mâfÇ¥gjhš, gof¡TL M‰wY« mâfÇ¡»wJ.

(iii) ïjdhš Ãiy¥ò¤j‹ik mâfkhf cŸsJ.

6. BeÆš ïUªJ Ba tiu ïu©lh« bjhFâ jÅk

M¡i[LfË‹ fhu tÈik mâfÇ¡»wJ V‹?

(i) ne®Ä‹j‹ik nkš ïUªJ ÑHhf bršY« nghJ

mâfÇ¡»wJ.

(ii) jÅk§fË‹ vy¡£uh‹fŸ ïH¡f¥gL« j‹ik

mâfÇ¡»wJ.

(iii) mQÉ‹ cUt msî«, JUt M‰wY« mâfÇ¡»wJ

ïjdhš jÅk M¡i[LfË‹ fhu tÈik mâfÇ¡»wJ.

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K¡»a Édh¡fŸ

1. bk¡Üáa¤â‹ ga‹fŸ ahit?

(i) nghuh‹, áÈ¡f‹ jahÇ¥òfËš xL¡»ahfî«, k‰W«

(ii) cl‹ xË òif¥gl¤ bjhÊš, k¤jh¥ò¤ bjhÊš k‰W«

g£lhR bjhÊÈš ga‹gL¤j¥gL»wJ.

2. Í¥r« g‰¿ F¿¥ò tiuf. ga‹fŸ ïu©il F¿¥ãLf.

Úu‰w CaSO4 Mfî«, Í¥r« CaSO4, 2H2O Mfî« »il¡»wJ.

Ú®¤j ršãôÇ¡ mÄy¤ij fhšáa« c¥òl‹ nr®¤J ï¢

nr®k« bgw¥gL»wJ.

CaCO3 + H2SO4 CaSO4 + H2O + CO2

ga‹fŸ :

(i) ãsh°l® rhªJ jahÇ¡fî« k‰W«

(ii) ábk©£ ïWFtij jL¥gj‰F ga‹gL»wJ.

3. ÚUl‹ Mg v›thW ÉidòÇ»wJ?

FË®ªj ÚUl‹ Mg ÉidòÇtâšiy, ÚuhÉíl‹

bt¥g¥gL¤J« nghJ ãufhrkhf vǪJ bk¡Üáa

M¡i[ilí«, iA£u#idí« jU»wJ.

Mg + H2O → MgO + H2 ÚuhÉ

4. v¥r« c¥ò v‹gJ ahJ? mj‹ ga‹ ahJ?

Úu‰w bk¡Üáa« ršng£ MgSO4, 7H2O v¥r« c¥ò v‹W

miH¡f¥gL»wJ.

ga‹fŸ :

(i) kyÄs¡»ahfî«,

(ii) rha« k‰W« njhš gjÅL« KiwfËY«, gŠR

bghU£fis rÇah¡fî«

(iii) ãsh£od« fyªj Éidntf kh‰¿ahfî« ga‹gL»wJ.

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46 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. 2 M« bjhFâ jÅk§fË‹ M¡i[LfŸ mâf cUF

Ãiyaia cilaJ V‹?

(i) M¡Ì#nd‰w v© +2 k‰W«

(ii) mU»š cŸs kªj thí¡fË‹ mik¥ig bgW»wJ.

(iii) ãiz¥ò vy¡£uhÅ‹ v©Â¡if ïUkl§F vdnt

(iv) cUF Ãiyaí« mâf«.

2. ïu©lh« bjhFâ cnyhf§fËš M3+ maÅ cUthtj‰F

njitahd maÅah¡F« M‰wš mâfÇ¡»wJ. V‹?

(i) ïu©lh« bjhFâ bghJthd vy¡£uh‹ mik¥ò ns2

(ii) btË¡T£oš cŸs 2 vy¡£uh‹fis ïHªJ

kªjthíÉ‹ Ãiy¤j‹ikia bgW»wJ.

(iii) M2+ maÅfË‹ Ãiy¤j‹ik mâf«.

(iv) M2+ maÅš ïUªJ nkY« xU vy¡£uhid Ú¡FtJ

fod«.

(v) Mfnt mâf maÅ M¡F« M‰wš njit¥gL»wJ.

3. fhu cnyhf§fis¡ fh£oY« ïu©lh« bjhFâ

jÅk§fŸ Fiwªj cnyhf¤ j‹ikíilaJ. V‹?

(i) fhu cnyhf§fŸ X® vy¡£uhid ïHªJ (s1) maÅah»wJ Mdhš

(ii) fhu k© cnyhf§fŸ ïizâw‹ T£oYŸs ïu©L

vy¡£uhid mf‰¿ kªjthí mik¥ò milí«.

(iii) ïu©L ïizâw‹ maÅ c¥ig jU»‹wd.

(iv) nk‰f©l fhuz¤jhš Kjš bjhFâ jÅk maÅ

c¥òfis¡ fh£oY« Fiwªj fhu¤j‹ikíilad.

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 47

4. bgÇÈa« AhiyLfŸ rf¥ãiz¥ò¤ j‹ikí«

bk¡Üáa« AhiyLfŸ maŤ j‹ikí« bfh©LŸsJ

V‹?

(i) bgÇÈa« bk¡Üáa¤ij Él cUÉš á¿aJ.

(ii) mâf vy¡£uh‹ ft® M‰wš cilaJ.

(iii) Ahy#‹fSl‹ vy¡£uhid¥ g»®ªJ bfh©L rf¥

ãiz¥ig V‰gL¤â¡ bfhŸ»wJ. Mdhš Mg Fiwªj

maÅ M¡F« M‰wš, bgÇa cUt msî M»a

fhuz§fËdhš Ahy#‹fnshL ïizªJ maŤ

j‹ikíila bk¡Üáa« Ahiyil¤ jU»wJ.

K¡»a Édh¡fŸ

1. bk¡Üáa¤â‹ jhJ¡fŸ ahit?

(i) bk¡dir£ MgCO3

(ii) v¥r« c¥ò MgSO4, 7H2O

(iii) nlhyik£ MgCO3, CaCO3

(iv) fh®diy£ MgCl2 KCl, 6H2O

2. CO2 k‰W«, ÚUl‹ bk¡Üá¤â‹ Éid ahJ?

(i) CO2 cl‹ Éid : CO2 NœÃiyÆš bjhl®ªJ vÇí«

g©ãid bg‰WŸsJ.

2Mg + CO2 2MgO + C

(ii) ÚUl‹ Éid : ÚuhÉíl‹ bt¥g¥gL¤J« nghJ

ãufhrkhf vǪJ bk¡Üáa« M¡i[ilí«,

iA£u#idí« jU»wJ.

Mg + H2O2 MgO + H2 ÚuhÉ

3. ghß° rhªJ v‹gJ v‹d? mj‹ ga‹ahJ?

Í¥r« c¥ãid Rkh® 393K bt¥gÃiyÆš NLgL¤J« nghJ

xU _y¡TW Í¥r« 1½ _y¡TW Úiu ïHªJ CaSO4, ½H2O

vd¥gL« ghß° rhªJ »il¡»wJ.

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48 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

ghl« - 7

p - bjhFâ jÅk§fŸ

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. p - bjhFâ jÅk§fŸ Fiw M¡á#nd‰w Ãiy

Ãiy¥gL¤Jtâ‹ fhuz§fis¡ TWf.

(i) bjhFâ nkÈUªJ ÑnH bršy ‘s’ M®ã£lhÈš cŸs

ïu©L vy¡£uh‹ ÉidÆš <LglhJ.

(ii) ‘p’ M®ã£lhÈš cŸs vy¡£uh‹ ÉidÆš <LgL»wJ.

(iii) ïJ kªj n#ho Éisî vd¥gL»wJ.

2. nghuh‹ oiu òqiuo‹ vy¡£uh‹ V‰ò g©ãid rh‹W

fh£o És¡F.

(i) nghuh‹ oiu òqiuL mnkhÅahÉš cŸs ie£u#‹

mQÉÈUªJ xU n#ho vy¡£uh‹ bg‰W ÿÆ°

mÄykhf brašgL»wJ.

(ii) mnkhÅah ÿÆ° fhukhf brašgL»wJ.

F H

F B N H

F H

− ← −

ÿÆ° mÄy« ÿÆ° fhu«

3. III bjhFâÆš x‹W k‰W« K«ik ïizâw‹fŸ cŸs

jÅk§fS¡F x›bthU rh‹W jUf.

(i) jhÈa«.

(ii) nghuh‹ (m) mYÄÅa«

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 51

12. ënkhFnshã‹, knahFnshãÅš fhQ« cnyhf

maÅfis¡ T¿ mj‹ brašâw‹fis És¡F.

át¥ò u¤j bršfËš fhQ« ënkhFnshã‹ (Hb) ma®‹

cŸs mizî¢ nr®kkhF«. ïJnt, EiupuÈUªJ,

cl«ã‹ všyh ghf§fS¡F« M¡Ì#id¢ RkªJ bršy¡

fhuzkh»wJ.

(i) knahFnshã‹ (Mb) jir âR¡fËš cŸsJ.

(ii) M¡Ì#id nrĤJ it¡F« miz ngh‹wJ.

(iii) jir bršfS¡F M¡Ì#id Rk¡F« brašâw‹

cilaJ.

K¡»a Édh¡fŸ

1. nghuh‹, mÄy§fSl‹ Éidia F¿¥ãLf.

gofk‰w nghuh‹ ml® H2SO4 k‰W« HNO3 fiuªJ nghÇ¡

mÄykhf khW»wJ.

B + 3HNO3 → H3BO3 + 3NO2

2B + 3H2SO4 → 2H3BO3 + 3SO2

2. nghuh‹ v›thW xL¡F»ahf brašgL»wJ?

(i) nghuh‹ xU tÈa xL¡»

(ii) fh®g‹il M¡iril, fh®gdhfî«, áÈfhit

áÈ¡fdhfî« nghuh‹ xL¡»wJ.

3CO2 + 4B → 2B2O3 + 3C

3SiO2 + 4B → 2B2O3 + 3Si

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52 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. XnrhÅ‹ VnjD« _‹W ga‹fis¡ TWf.

(i) »UÄ eháÅ, k‰W« ó¢á bfhšÈahf ga‹gL»wJ.

(ii) khî, °lh®¢, jªj« k‰W« v©bzŒ ït‰iw

btS¥gj‰F« ga‹gL»wJ.

(iii) bra‰ifg£L k‰W« Nl« bjhF¥gâY« ga‹gL»wJ.

K¡»a Édh¡fŸ

1. ~òšbyÇ‹fŸ v‹gJ v‹d?

(i) Ç¢r®£ °khÈ k‰W« uhg®£ f®š v‹gtuhš f©l¿a¥g£l

fh®gÅ‹ òâa òw nt‰Wik ïiaò ~òšbyÇ‹fŸ

MF«.

(ii) 60 fh®g‹ mQití« 32 g¡f§fisí« bfh©l ïjid

“g¡»ghš” vd¥ bgaÇ£ld®.

(iii) nfhstoÉš mikªj fh®g‹ _y¡TWfË‹ bjhFâ

~òšbyÇ‹fŸ v‹W miH¡f¥gL»wJ.

(iv) ïit mâ ÔÉu fl¤J« g©òfis bg‰WŸsJ.

2. ilak©o‹ (itu«) mik¥ig ÉtÇ?

(i) itu¤â‹ x›bthU mQî« rftY ãiz¥òfshš

ãiz¡f¥g£L KoÉš Äf¥bgÇa _y¡Twhf

c©lh»wJ.

(ii) x›bthU fh®g‹ mQî« mL¤J cŸs eh‹F

fh®g‹ mQ¡fSl‹ ïizªJ eh‹Kf¤â‹ eh‹F

_iyfis neh¡» rftY¥ ãiz¥ãš cŸsJ.

(iii) C-C ãiz¥òfŸ Äfî« tÈikahdit. vdnt jh‹

iA¥gof« fod¤j‹ik cŸsjhf ïU¡»wJ.

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 53

3. nAg® KiwÆš m«nkhÅah v›thW jahÇ¡f¥gL»wJ?

1 : 3 v‹w É»j¤âš cŸs ie£u#‹ k‰W« iA£u#‹

fyitia ca® mG¤j¤âš (200 – 900atm) 770K bt¥gÃiyÆš,

ïU«ò¤öŸ Éidntf kh‰¿ k‰W« khÈ¥od« Éidntf

kh‰¿ C¡»Æ‹ K‹ÅiyÆš brY¤â mnkhÅah

jahÇ¡f¥gL»wJ.

N2 + 3H2 � ⇀�↽ �� 2NH3

4. nghuh¡Ì‹ g©òfis ÉtÇ?

(i) nghuh¡° mj‹ cUFÃiy¡F nkš bt¥g¥gL¤J«

bghGJ gof Ú® _y¡TWfŸ btËna¿ Ãwk‰w

f©zho ngh‹w bghUis¤ jU»wJ.

(ii) ï¢ nr®k« áijªJ nrhoa« bklhnghnu£ k‰W« nghuh‹

(III) M¡i[lhfî« khW»wJ.

(iii) Na B O .10H O Na B O +10H O

Na B O 2NaBO + B O2 4 7 2 2 4 7 2

2 4 7 2 2 3

5. fh®g‹ bjhFâ jÅk§fŸ vit?

jÅk« mQ v© vy£uh‹ mik¥ò

fh®g‹ 6 [He] 2s2 2p2

áÈf‹ 14 [Ne] 3s2 3p2

b#®khÅa« 32 [Ar] 3d104s2 4p2

o‹ 50 [Kr] 4d10 5s2 5p2

by£ 82 [Xe] 4f14 5d10 6s2 6p2

jÅk tÇir m£ltizÆš 14M« bjhFâÆš ml§»íŸsd.

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54 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

ghl« - 8

âl Ãiyik - I 2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. gof§fËš beU¡fkhd bghâªJŸs mik¥òfis

îzÆ¡F« gofŸ ahit?

(i) RU¡f ïayh¤ j‹ik, f£oW¡f« k‰W« mG¤j«.

(ii) gUk msî Fiwí« j‹ik ïšyhik,

2. gof toik¥ãaÈš ‘myF¡ TL’ v‹whš v‹d?

gof âl¥bghUŸ (m) gof¤âš cŸs Äf¢á¿a Û©L«

Û©L« njh‹w¡ Toa K¥gÇkhz totoik¥ò my¡TL

vd¥gL«.

3. fd¢rJu myF¡ TLfË‹ v©Â¡if v‹d?

mitahtd?

_‹W, mit

(i) vËa fd¢rJu«

(ii) bghUŸ ika fd¢rJu«

(iii) Kf¥ò ika fd¢rJu«

4. Äšy® F¿fh£ofŸ v‹whš v‹d?

å° F¿fh£ofË‹ jiyÑœ kâ¥òfis á¿a bghJ

v©zhš bgU¡» »il¡F« KG v© É»j§fns js¤â‹

Äšy® F¿fh£ofŸ vd¥gL«.

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56 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

K¡»a Édh¡fŸ

1. òwbtË m¡ nfhit v‹whš v‹d?

K¥gÇkhz¤âš mQ¡fË‹ _y¡TWfŸ (m) maÅfŸ

bt›ntW ïl§fËš m›thW xG§fik¡f¥g£LŸsd

v‹gij fh£L« tÇir, tÇirahd òŸËfns òwbtË

m¡nfhit vd¥gL«.

2. mizî v© v‹gJ v‹d?

X® myF T£oš cŸs xU mQit¢ R‰¿ beU§»

mikªJŸs mQ¡fË‹ v©Â¡if mj‹ mizî v©

vd¥gL«.

3. mQ Mu« v‹gij tiuaW?

xU gof¤âš cŸs mL¤jL¤j ïu©L mQ¡fS¡F

ïil¥g£l öu¤âš ghâasî mQ Mu« vd¥gL«.

3 kâ¥bg©fŸ

K¡»a Édh¡fŸ

1. xU js¤âš Äšy® F¿fh£ofis bgWtj‰fhd KiwfŸ

ahit?

(i) _‹W tÇir m£ltizÆ‹ nkš gFâÆš myF¡ TL

kâ¥òfis vGJf.

(ii) js¤â‹ bt£L¤J©L kâ¥òfis vGJf.

(iii) kâ¥òfË‹ jiyÑÊia vGj nt©L«.

(iv) á¿a bghJ v©zhš bgU¡» h, k, l, kâ¥òfis bgWf.

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2. bt£L¤ J©LfŸ tiuaW

(i) xU myFT£o‹ a, b k‰W« c M»a _‹W g¡f§fŸ

bt£L¤J©LfŸ vd¥gL«.

(ii) z

y

x

αßa

c

by

gof m¢R¡fŸ : ox,oy,oz

Kf¥ònfhz§fŸ : α, β,γ

bt£L¤J©LfŸ : a,b,c

(iii) my¡TlhdJ a b k‰W« c M»a Ús§fshY« α, β k‰W«

γ M»a nfhz§fshY« tiuaW¡f¥gL»‹wd.

3. miwbt¥gÃiyÆš,nghnyhÅa« vËa fd¢rJukhf

gofkh»wJ. mj‹ mQ Ãiw 20g mol–1 k‰W« a = 3.3Å vÅš nghnyhÅa¤â‹ ml®¤âia fz¡»Lf.

vËa fd¢rJu¤â‹ 8 _iyfËY« 8 mQ¡fŸ cŸsd.

vdnt n = 8 × 18

fd msî = V = a3 = (3,36A)3

ml®¤â, p =nMm

=(1) × (209g mol–1)

No (6.023 × 1023 mol–1 (3.36 × 10–8 cm)= 9.15g mol–3 cm3

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6. mQ mšyJ maÅahdJ bgW« eh‹F tifahd

T£lik¥ò¤ j‹ikia vGJf

(i) bghUŸika« : g»®ªJ bfhŸs¥gLtâšiy.

(ii) Kf¥ò : ïu©L myF¡TLfŸ g»®ªJ bfhŸ»‹wd.

(iii) ÉË«ò : eh‹F myF¡TLfŸ g»®ªJ bfhŸ»‹wd.

(iv) _iy : v£L myF¡TLfŸ g»®ªJ bfhŸ»‹wd.

ghl« - 9

thí Ãiyik - I 2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. ghÆš ÉâÆ‹ fÂj És¡f¤ij vGJf.

P α 1V

PV = kh¿È (khwhj bt¥gÃiy T)

bt¥gÃiy T, thíÉ‹ fdmsî V1 cŸs nghJ mG¤j« P1 Mfî«, mnj bt¥gÃiyÆš thíÉ‹ fd msî V2 Mfî«

mj‹ mG¤j« P2 Mfî« ïUªjhš ï›Éâ¥go

P1V1 = P2V2 = kh¿È

2. 3 nkhšfŸ A thí k‰W« 5 nkhšfŸ B thí M»ait

fy¡f¥gL»wJ. 25∞C k‰W« 1atm mG¤j¤âš mt‰¿‹

gFâ mG¤j§fis x¥ãL.

thí A Æ‹ gFâ mG¤j«

pA = 38 × 1 =

38 tË (m) 0.375 tË

thí B Æ‹ gFâ mG¤j«

pB = 58

× 1 = 58

tË(m) 0.625 tË

thí B thí A it¡ fh£oY« mâf gFâ mG¤j« bg‰WŸsJ.

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3. th©l®thš° rk‹gh£oYŸs mG¤j¤ âU¤j« k‰W«

fd msî âU¤j« M»at‰iw vGJf.

fd msî âU¤j« = b = 4n Vm.

mG¤j¤ âU¤j« = P + P′ = P +

aV2

4. xU ešÈašò thí bt‰¿l¤â‰F¢ bršY« nghJ mj‹

ïa¡f M‰wš khWtâšiy. És¡Ff.

xU ešÈašò thí mG¤j¥g£L xU bfhŸfy¤âÈUªJ

btËna‰w¥gL« nghJ ïa¡f M‰wÈš vªj khWghL«

V‰glhJ. VbdÅš ÉÇtiljš ÃiykhW bt¥gÃiyÆš

V‰gL»wJ.

5. mG¤j¥g£l ïašò thí x‹¿id Jthu« tÊahf

bt¥g« khwh¢ brašKiwÆš ÉÇtila¢ brŒí« nghJ

bt¥gÃiyÆš V‰gL« kh‰w« v‹d?

bt¥gÃiy Fiw»wJ.

xU thíit Fiwªj mG¤j¥ gFâ¡F brY¤J« nghJ mj‹

_y¡TW cldoahf »il¥g£l Éir¡F vâuhf Éy»¢

brš»wJ. ÉÇtilí« nghJ M‰wš ïHªJ ntiyia¢

brŒ»‹wd.

6. thíÉ‹ msÉl¡ Toa g©òfŸ ahit?

fdmsî (V)

mG¤j« (P)

bt¥gÃiy (T) k‰W« nkhšfË‹ v©Â¡if (n).

7. ešÈašò thí Éâ¥go 500 K k‰W« 600 atm-š ie£u#Å‹

nkhyh® fd msî v‹d?

PV = nRT

PV = RT xU nkhš ie£u#D¡F.

V = RTP

=0 0821

600. × 500

= 0.0684 È£l®fŸ.

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8. thíkh¿È R-‹ kâ¥òfis fnyhÇ k‰W« éš myFfis

vGJ.

R = 8.314 éš K–1 nkhš–1

R = 1.987 fnyhÇ K–1 nkhš–1

9. th©l®thš° kh¿ÈfËš ‘a’ k‰W« ‘b’ M»at‰¿‹

myFfis vGJf.

‘a’ ‹ myF = tËk©ly« È£l®2 nkhš–2

‘b’ ‹ myF = È£l® nkhš–1

10. #]š-jh«r‹ Éisit És¡Ff.

xU thíit mâf mG¤j gFâÆš ïUªJ Fiwªj mG¤j

gFâ¡F ÉÇtila¢ brŒí« nghJ mj‹ bt¥gÃiy FiwtJ

#]š jh«r‹ Éisî vd¥gL«.

11. vâ®khW bt¥gÃiy v‹whš v‹d?

xU F¿¥ã£l bt¥gÃiy¡F Ñœ xU thíit bt¥gkhwh¢

brašKiwÆš Fiwªj mG¤j¥ gFâ¡F JistÊahf

ÉÇtila¢ brŒí« nghJ bt¥gÃiy FiwtJ vâ®khW

bt¥gÃiy (Ti) vd¥gL«.

TRiab

=2

K¡»a Édh¡fŸ

1. ïašò thí¡fŸ v‹gd ahit?

rhjhuz bt¥gÃiyfËY« mG¤j¤âY« thí ÉâfŸ k‰W«

PV = nRT ¡F c£glhj thí¡fŸ ïašò thí¡fŸ vd¥gL«.

2. ÃiykhW mG¤j« tiuaW.

ÃiykhW bt¥gÃiyÆš, xU nkhš thíit âutkh¡f¤

njit¥gL« Äf¡ Fiwªj mG¤j« ÃiykhW mG¤j«

vd¥gL«.

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3. thí¡fis âutkh¡F« KiwfŸ ahit?

(i) È©nl Kiw

(ii) »shL Kiw

(iii) khwh bt¥g fhªj Ú¡f Kiw.

4. xU thíit âutkh¡f njit¥gL« ÃgªjidfŸ ahit?

(i) Fiwªj bt¥gÃiy

(ii) mâf mG¤j«.

5. rk bt¥gÃiy¡ nfhL v‹whš v‹d?

khwhj bt¥gÃiyÆš thíÉ‹ fd msit mâfÇ¡F«

nghJ mG¤j« Fiwí«. ïjid¡ fh£L« tiunfhLfŸ rk

bt¥gÃiy¡ nfhLfŸ vd¥gL«.

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. rh®y° Éâ k‰W« ghÆš Éâ M»at‰iw tiuaW¡f.

rh®y° Éâ : khwhj mG¤j¤âš xU F¿¥ã£l ÃiwíŸs

thíÉ‹ fdmsî (V) mj‹ jÅ bt¥g

Ãiy¡F (T) ne® É»j¤âš ïU¡F«.

V α T (or) VT

= kh¿È

mnj ngh‹W khwhj fd msÉš xU F¿¥ã£l ÃiwíŸs

thíÉ‹ mG¤j« (P) mj‹ jÅ bt¥g Ãiy¡F ne® É»j¤âš

ïU¡F«.

P α T (or) PT

= kh¿È

ghÆš Éâ : khwhj bt¥gÃiyÆš xU F¿¥ã£l ÃiwíŸs

thíÉ‹ mG¤j« (P) mj‹ fd msî« (V) vâ®

É»j¤ bjhl®ig bg‰WŸsd.

P α 1V

(khwhj bt¥g ÃiyÆš) (or) PV = kh¿È

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K¡»a Édh¡fŸ

1. »uAhÄ‹ thí Éuîjš Éâia És¡Ff.

xnu bt¥g« k‰W« mG¤j ÃiyfËš thí¡fË‹ Éuîjš

åjkhdJ mt‰¿‹ _y¡TW ÃiwÆ‹ t®¡f _y¤â‰F

vâ® É»j¤âÈU¡F«.

fÂjKiw¥go ï›Éâ rr1

2

2

1=

MM

r1, r2 v‹gJ thí 1 k‰W« 2-‹ Éuîjš åjkhF«.

M1 k‰W« M

2 _y¡TW ÃiwahF«.

2. iA£u#‹ FnshiuL thíɉfhd th©l® thš°

khwÈfŸ a = 3.67 atm lit-2 k‰W« b = 40.8ml mol-1 MF«.

ÃiykhW bt¥g« k‰W« ÃiykhW mG¤j¤âid

fz¡»Lf.

(i) TR

K Ccab

= =×

× ×= = °

827

8 3 6727 0 0821 0 0408

324 7 51 7.. .

. .

(ii) P atmcab

= =×

=27

3 6727 0 0408

81 62 2.

( . ).

3. thí¡fis âutkh¡f njitahd ÃgªjidfŸ _‹¿id

vGJ.

(i) vâ® khW bt¥g Ãiy¡F c£gL¤â FW¡Fjš.

(ii) #]š jh«r‹ Éisî¡F c£gL¤Jjš.

(iii) bt¥g khwh¢ brašKiwÆš fhªj j‹ikia ïH¤jš.

v.fh.

NH3, Cl2, SO2 k‰W« CO2 thí¡fË‹ Tc kâ¥òŸs miw

bt¥gÃiy¡F x¤J ïU¥gjhš, mG¤j¤ij Tc kâ¥ãš

mâfÇ¥gj‹ _y« âutkh¡fyh«.

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4. xU thíthdJ M¡Ì#‹ Éuîjš åj¤âš ghâia

bg‰¿Uªjhš, mj‹_y¡TW Ãiwia fz¡»Lf.

»uAhÄ‹ Éâ¥go

rr

i1

2

12=

MM 1

32M

1

2 1 = rr

i1

2

12=

MM 1

32M

1

2 1

rr

i1

2

12=

MM 1

32M

1

2 1 =

rr

i1

2

12=

MM 1

32M

1

2 1

ïUg¡fK« t®¡f¥gL¤j,

12

+ 32M

(or) 14

= 32M

2

1 1

=

12

+ 32M

(or) 14

= 32M

2

1 1

(m) 12

+ 32M

(or) 14

= 32M

2

1 1

M1 = 128

thí _y¡TW Ãiw = 128 MF«. (M1)

ghl« - 10

ntâ¥ãiz¥ò

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. NaCl, MgCl2 k‰W« AlCl2 I rf¥ ãiz¥ò¤ j‹ikÆ‹

VWtÇirÆš vGJ.

ne®Ä‹ maÅÆ‹ M¡á#nd‰w v© mâfkhf ïUªjhš

vâ®Ä‹ maÅ KidîWtJ« mâfkhF«.

NaCl < MgCl2 < AlCl32. ã‹tUtdt‰¿š σ k‰W« π ãiz¥òfis vGJ.

CH3 – CH3 , CH2 = CH2 , CH ≡ CH

(i) CH3 – CH3

H H | |

H C C H | | H H

σ σσ σ

σσ

σ 7σ ãiz¥òfŸ

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(ii) CH2 = CH2 H H

C C H H

σ σ

σ

πσ σ

5 (σ) á¡kh ãiz¥òfŸ

1 (π) ig ãiz¥ò

(iii) HC ≡ C – H π

π

σ σσH C C H 3 σ á¡kh ãiz¥òfŸ

2 π ig ãiz¥òfŸ

3. Na+, Ca+2, Mg+2 k‰W« Al+3 M»at‰¿š vJ mâf

KidîW¤J« âw‹ bfh©lJ?

ne®Ä‹ maÅÆ‹ Ä‹}£l« mâfǤjhš mªj maÅÆ‹

KidîW¤J« âw‹ mâfkhf ïU¡F« vdnt A13+ maÅ

KidîW¤J« âw‹ mâf« cilaJ.

4. BeCl2 ‹ totik¥ò v‹d?

BeCl2 ne®nfh£L totik¥ò cilaJ. Be mj‹ ïU sp

ïdfy¥ig¥ ga‹gL¤â Be–Cl ãiz¥ig V‰gL¤J»wJ.

mj‹ ãiz¥ò nfhz« 180°180°

: Cl Be Cl :

5. maÅ¥ ãiz¥ò k‰W« rf¥ãiz¥ò M»at‰¿‰

»ilnaahd ntWghLfis vGJ.

maÅ¥ãiz¥ò rf¥ãiz¥ò

i) tYthdJ tYt‰wJ

ii) âir¥ g©ò »ilahJ âir¥ g©ò c©L

iii) M®ã£lhšfŸ jGtš

ïšiy

M®ã£lhš jGtš

c©L

6. CCl4 ÚÇš fiuahJ. Mdhš NaCl fiua¡ ToaJ V‹?

(i) CCl4 Kidt‰w rf¥ãiz¥ò nr®k«.

(ii) cUt msî bgÇaJ, Ú® _y¡TWfshš

<®¡f¥gLtâšiy.

(iii) NaCl KidîW« maÅ¢ nr®k« vdnt ÚÇš maÅí‰W

fiu»wJ.

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7. CH4, H2O k‰W« NH3 š cŸs ïd¡fy¥ò sp3 MF«.

Mdhš ãiz¥ò¡ nfhz« mt‰¿‰»ilna ntWgLtij

És¡Ff.

(i) CH4, H2O k‰W« NH3 cŸs jŤj n#ho vy¡£uh‹fŸ,

ãiz¥ò n#ho vy¡£uh‹fË‹ Éy¡f« fhuzkhf,

ãiz¥ò¡ nfhz« ntWgL»wJ.

(ii) CH4 Û¤njÅš eh‹F ãiz¥ò n#ho vy¡£uh‹¡s

cŸsd. x‹iwbah‹W Éy¡» eh‹K» toÉš109° 28′ v‹w ãiz¥ò nfhz¤Jl‹ mik»wJ.

(iii) NH3 Æš _‹W ãiz¥ò n#ho vy¡£uh‹fS« xU

jŤj n#ho vy¡£uh‹fS« cŸsJ.

(iv) jŤj n#ho vy¡£uh‹fŸ mâf ïl¤ij M¡»uÄ¥ò

brŒtjhš Éy¡F Éir mâfÇ¡»wJ. ïjdhš

H – N – H ãiz¥ò¡ nfhz« 190° 28′ ÈUªJ 107° ¡F

Fiw»wJ.

(v) H2O ÚÇš ïu©L ãiz¥ò n#ho vy¡£uh‹fS«,

ïu©L jŤj n#ho vy¡£uh‹fS« cŸsd. jŤj

n#ho vy¡£uh‹fŸ Äf mâf msÉš x‹iwbah‹W

Éy¡Ftjhš ãiz¥ò¡ nfhz« FiwªJ 104° Mf

mik»wJ.

8. BF3 k‰W« NH3 M»at‰¿‰»ilna <jš ãiz¥ò

cUthtij És¡Ff.

(i) NH3 _y¡TW, xU n#ho vy¡£uhid BF3 ¡F

bfhL¡»wJ.

(ii) BF3 xU vy¡£uhid Fiw nr®kkhf ïU¥gjhš bt‰W

M®ã£lhš xU n#ho vy¡£uhid V‰W¡bfhŸ»wJ.

ïjdhš V‰gL« ãiz¥ò <jš rf¥ãiz¥ò vd¥gL«.

H H | |

H N B F | | H F

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K¡»a Édh¡fŸ

1. Ú® _y¡T¿š cŸs M¡Ì#‹ mQÉ‹ ïd¡fy¥ò

v‹d?

1s2, 2s2, 2px2 2py

1 2pz1

M¡Ì#‹ vy¡£uh‹ ïašò Ãiy

↑ ↓ ↑ ↓↑ ↓ ↑ 1s2 2px22s2 2py

1↑

2pz1

Ú® _y¡T¿š cŸs M¡Ì#‹ mQÉ‹ ïd¡fy¥ò sp3

ïd¡fy¥ghF«.

2. gof¡ TL M‰wš v‹whš v‹d?

xU nkhš â©k maÅ¢ nr®k¤ij KGtJkhf thíÃiy

maÅfshf ãÇ¥gj‰F njit¥gL« M‰wyhF«. ïJ v¥nghJ

ne®F¿ia bg‰¿U¡F«.

3. nt⥠ãiz¥ò v‹whš v‹d?

ïu©L mšyJ mj‰F nk‰g£l mQ¡fŸ gšntW

ÉirfËdhš ãizªJŸsijna ntâ¥ãiz¥ò v‹»nwh«.

4. ng#h‹ Éâia TW?

xU _y¡T¿š cŸs vâ®Ä‹ maÅfË‹ KidîW¤J«

âw‹ mâfkhf ïU¥gjhš rf¥ãiz¥ò j‹ikí« mâfkhf

ïU¡F«.

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3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. ã‹tUtdt‰¿‹ ÿÆ° òŸË totik¥ig vGJf.

S, S2–, P, P3–, Na, Na+, Al, Al3+

(i) S (1s2 2s2 2p6 3s2 3p4)

x x

x x

x xS

(ii)

S2– x x

x x

x x 2−

x xS

(iii) P(1s2 2s2 3s2 3p5)

x x x

x

x P

(vi)

P3– x x

x x

x x 3−

x xP

(v) Na (1s2 2s2 2p6 3s1) (vi) Na+

Na[Na]+

(1s2 2s2 2p6)

• •+

• •Na•

•••

(vii) Al (1s2 2s2 2p2 3s2 3p1) (viii) Al3+

Al ..[Al]3+

(1s2 2s2 2p6)• •

+ 3

• •Al•

•••

2. ïizâw‹ ãiz¥ò¡ bfhŸifÆ‹ K¡»akhf áw¥ò¥

g©òfis vGJf.

(i) ïu©L mQ¡fŸ KoÉšyh¤ bjhiyÉš cŸs nghJ mt‰¿‰»ilna v¤jifa ïilpL« ïšiy.

(ii) <®¥ò Éir Éy¡F Éiria Él mâfkhf ïU¡F« tiu mik¥ãš Ãiy M‰wš FiwªJ bfh©nl tªJ ó{Ía¤ij milí«.

(iii) x‰iw ãiz¥ò cUthF« nghJ M‰wš btËÆl¥gLtjhš Ãiy M‰wš Fiw»wJ.

(iv) ïu©L mQ¡fŸ x‹iwbah‹W beU§» tU« nghJ mt‰¿‰»ilnaahd mQ¡fS¡»il¥g£l bjhiyî FiwªJ bfh©nl tU«.

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3. clÅirî v‹whš v‹d? CO2 k‰W« CO32 –‹ bt›ntW

clÅirî totik¥òfis vGJf.

(i) xU _y¡T¿‹ tot mik¥ig xnu M‰wš, xnu

ïl¤âš cŸs mQ¡fŸ ãiz¥ò k‰W« ãiz¥ãš

<Lglhj n#ho vy¡£uh‹fŸ bfh©L x‹W¡F nk‰g£l

totik¥òfŸ _y« És¡fyh«. ïjid clÅirî

v‹»nwh«.

(ii) CO2

(−) (+) (+) (−)..

.... ... . . .

. . . .. .. .

O C O O C O O C O

(iii) CO32– ‹ clÅirî mik¥òfŸ :

(−)

(−) (−) (−) (−)

(−).. .. .. .. .. ... . . .

O OO

.. ... .O .. . .O .. . .O.. ..

... .O.. ... .

C C C

.. . .OO

K¡»a Édh¡fŸ

1. ïu©L vy¡£uh‹ gÇkh‰w« miltjhš MgO cUthtij

És¡Ff?

(i) [ ] [ ]

2

23Mg Mg 2

NesNe

e e− + −+→ïH¤jš

(ii) [ ] [ ]

22 62 5 2 2 [ ]2 2

O + 2 Os p NeNes pHe

ee− −−→V‰wš

(m)

(iii) 2 2 2 2M O MgO M Og g+ − + −→ÃiyÄ‹(m)

<®¥ò Éir

MgOš cŸs ãiz¥ò maÅ¥ ãiz¥ò MF«.

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 73

2. ngh#‹ ÉâahJ? ngh#Å‹ ne® Ä‹ maÅÆ‹

bghJthd KidîW¤ âwÅ‹ tÇiria vGJf.

(i) xU _y¡T¿š cŸs vâ®Ä‹ maÅfË‹ KidîW«

âw‹ mâfkhf ïUªjhš rf¥ãiz¥ò¤ j‹ikí«

mâfkhf ïU¡F«. ïJ ngh#‹ Éâ.

(ii) bghJthd Kid mG¤J« âw‹ tÇir

Li > Na+ > K+ > Rb+ > Cs+

(iii) ~rf¥ãiz¥ò j‹ik

LiCl > NaCl >KCl > RbCl > CsCl.

3. Nacl‹ gof TL v©jhšãia gh®‹-nAg® R‰W _y«

És¡Ff

(i) Na+(s)

12 Cl(g) NaCl(s)

nk‰f©l ÉidÆ‹ â£l v‹jhšã kh‰w« - 411.3kJmol–1

(ii) Na(s)

Na(g)

Na+(g)

NaCl(s)

∆H5

∆H4°

∆H2°∆H1°

∆Hf°

∆H3°

Cl−(g)

Cl(g)

½ Cl2(g)

(gj§fkhjš) (áijî)

(maÅah¡F« M‰wš)

(vy¡£uh‹ eh£l«)

(iii) ÉidgL bghUŸfŸ jÅkÃiyÆY« ÉidÉis

bghU£fŸ âlÃiyÆš ïU¥gjhš ÉidÆ‹ bkh¤j

v‹jhšã kh‰wkhdJ NaCl cUthjÈ‹ v‹jhšãahF«.

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(i) (g) ( )

2 6 1 2 62 2 3 2 2

Na N gs p s s p

a e+ −→ +maÅahjšnrhoa«ne®Ä‹maÅ

(ii) ( ) 2 63 32 53 3

Cl Clgs ps p

e− −+ →vy¡£uh‹ ft®jšFnshiuL vâ®Ä‹ maÅ

(iii) Na NaClCl+ + →ÃiyÄ‹

<®¥ò Éirnrhoa« maÅ FnshiuL maÅ maÅ¢ nr®k«

ghl« - 11

bjhifrh® g©òfŸ

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. bjhifrh® g©òfŸ ahit?

fiurÈ‹ g©òfŸ, mâš fiuªJŸs JfŸfË‹

v©Â¡ifia bghU¤J mika¡ToajhŒ ïU¥ã‹ mit

bjhif rh® g©ghF«.

(i) MÉ mG¤j« Fiwî ∆p

(ii) bfhâÃiy ca®î ∆Tb

(iii) ciwÃiy¤ jhœî ∆Tf

(iv) r›ñL gutš mG¤j« π

2. x¥ò MÉ mG¤j¡ Fiwit tiuaW.

MÉ mG¤j¡ FiwɉF«, öŒikahd fiu¥ghÅ‹ MÉ

mG¤j¤â‰F« cŸs É»jnk x¥ò MÉ mG¤j¡ Fiwî

vd¥gL«.

fiu bghUË‹ x¥ò MÉ mG¤j¡ Fiwî = p p

p° −

°

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76 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

3. nkhyhš bfhâÃiy ca®î v‹whš v‹d?mrhjhuz

fiubghUŸfŸ ahit?

1 nkhš msîŸs fiubghUŸ 1 Kg msîŸs fiu¥ghÅš

fiu¡f¥g£L »il¡F« nkhyhš fiurÈ‹ bfhâÃiy

ca®nt nkhyhš bfhâÃiy ca®î vd¥gL«.

fiu¥ghÅš Ä‹ gFËia¥ ngh‹W ãÇif milí«

fiubghUŸfŸ mrhjhuz fiubghUŸfŸ MF«. c.«: NaCl

4. vËâš MÉahfhj fiubghUis nr®¥gjhš fiurÈ‹

bfhâÃiy ca®tJ V‹?

xU fiurÈ‹ MÉ mG¤j« tË k©ly mG¤j¤â‰F

rkkhF« nghJ mJ bfhâÃiy milí« vËâš MÉ Mfhj

fiubghUis nr®¥gjhš, fiurÈ‹ MÉ mG¤j« Fiw»wJ.

vdnt bfhâÃiy caU»wJ.

5. thfd§fËš vËâš MÉahF« iA£nuh fh®g‹fis

vÇbghUshf¥ ga‹gL¤Jtâšiy. V‹?

(i) MÉahF« iA£nuhfh®g‹fŸ vËâš MÉah»

ÉLtjhš, cuhŒî Fiw¡f¥g£L, ntf¤ij¡

f£L¥gL¤Jtâš jil V‰gL»wJ.

(ii) vdnt vËâš MÉahfhj iA£nuhfh®g‹fis

thfd§fËš vÇbghUshf ga‹gL¤j nt©L«.

6. InrhnlhÅ¡ fiuršfŸ v‹whš v‹d?

bt›ntW nr®k§fis¡ bfh©L ïU fiuršfŸ xnu

bt¥gÃiyÆš rkkhd r›ñL gutš mG¤j¤ij bg‰¿Uªjhš

m¡fiurš InrhlhÅ¡ fiuršfŸ vd¥gL«.

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 77

7. xU Ä‹ gF bghUË‹ bjhifrh® g©ig f©l¿tj‹

_y« mj‹ ãÇif åj¤ij m¿í« tÊia És¡Ff.

(i) fiubghUŸ fiu¥ghÅš Ä‹gFËia¥ ngh‹W ãÇif

mil»wJ.

(ii) fiurÈ‹ JfŸ v©Â¡if mâfÇ¡»wJ. ïªj

ÉisÉdhš bjhifrh® g©òfŸ msÉl¥gL« nghJ

mâfÇ¡»wJ.

th‹£A~¥ fhu i =msÉl¥gL« bjhif rh® g©ò

rhjhuz bjhif rh® g©ò

bjhifrh® g©ò _y¡TW Ãiw¡F vâ® É»j«

i = rhjhuz _y¡TW vil

msÉl¥gL« _y¡TW vil

ãÇif É»j« αãÇifailjš

α =−−in

11

K¡»a Édh¡fŸ

1. nkhyhš bfhâÃiy V‰w kh¿È v‹whš v‹d?

xU nkhyhš fiurš bg‰WŸs bfhâÃiy ca®nt nkhyhš

bfhâÃiy V‰w kh¿È vd¥gL«.

∆Tb = Kb m

m = 1 Mf, ïU¡F«nghJ ∆Tb = Kb

2. Ú®k¤â‹ ciw Ãiy v‹whš v‹d?

XU F¿¥ã£l bt¥gÃiyÆš xU nr®k¤â‹ â©k« k‰W«

âut ÃiyikfË‹ MÉaG¤j« rkkhf ïUªjhš mªj

bt¥gÃiy ciwÃiy vd¥gL«.

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3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. ciwÃiy¤ jhœî xU bjhifrh® g©ò v‹gij ÃWîf.

öa fiu¥ghÅ‹ ciwÃiy = To.

fiurÈ‹ ciwÃiy = T

T < To

vdnt ciwÃiy¤ jhœî = To – T = ∆Tf

∆Tf α m (m = nkhyhÈ£o)

∆Tf = Kf . m (Kf = nkhyhš ciwÃiy¤ jhœî kh¿È)

xU nkhš fiubghUŸ 1000 »uh« fiu¥ghÅš fiuªJŸs

fiurÈš ciwÃiy¤ jhœî, nkhyhš ciwÃiy¤ jhœî

kh¿È vd¥gL«.

Ú®¤j fiurÈ‹ ciwÃiy¤ jhœthdJ bfhL¡f¥g£l

fiu¥ghÅš fiuªJŸs fiu¥bghUË‹ nkhšfË‹

v©Â¡if¡F ne®É»j¤âš ïU¡F«. nkY« ∆Tf MdJ

fiubghUË‹ j‹ikia¥ bghW¤J miktâšiy. vdnt

ciwÃiy¤ jhœî xU bjhifrh® g©ghf¡ fUj¥gL»wJ.

2. r›ñL gutš k‰W« r›ñL gutš mG¤j« M»at‰iw

És¡Ff.

(i) Ú®¤j fiu¢rš (m) öa fiu¥ghÅYŸs fiu¥gh‹

_y¡TWfŸ xU TW òfÉL« tÊna br¿î mâfkhd

fiu¢rY¡F brštJ r›ñL gutš vd¥gL«.

(ii) á¿jsî mG¤j¤ij brY¤â fiu¥gh‹ _y¡TWfŸ

xU TW òfÉL« r›É‹ tÊna fiurš gFâ¡F

brštij jL¡fyh«. ï›thW fiu¥gh‹ brštij

jL¤J ÃW¤j¡ Toa mG¤jkhdJ r›ñL gutš

mG¤j« vd¥gL«.

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3. bg®¡FÈ Ah®£È KiwÆ‹ nk‹ikfŸ ahit?

(i) r›ñL gutš mG¤j« neuoahf msÉl¥gL»wJ.

(ii) fiurÈ‹ br¿î khWtâšiy.

(iii) btË mG¤j¤jhš r›ñL gutš mG¤j« rk‹

brŒa¥gLtjhš xU TW òfÉL« r›î Fiwªj msî

Û£á¡F c£gL¤j¥gL»wJ.

K¡»a Édh¡fŸ

1. bjhifrh® g©òfË‹ K¡»a neh¡f« ahJ?

(i) Ú®¤j fiurÈš fiuªJŸs MÉahfhj fiubghUË‹

_y¡TW Ãiwia îzƤjny MF«.

(ii) bjhifrh® g©òfŸ ã‹tUkhW

�� MÉ mG¤j¡ Fiwî (Δp)

�� bfhâ Ãiy ca®î (ΔTb)

�� ciwÃiy¤ jhœî (ΔTf)

�� r›ñL gutš mG¤j« (π)

2. x¥ò MÉ mG¤j¡ FiwÉid uîy£ ÉâÆ‹ fÂjÉaš

KiwÆš TW.

x¥ò MÉ mG¤j¡ Fiwî v‹gJ MÉ mG¤j¡ FiwɉF«

Jha fiu¥ghÅ‹ MÉ mG¤j¤â‰F« cŸs É»jkhF«.

(i) vdnt, x¥ò MÉaG¤j Fiwî

p pp

ppo

° − =°

p = p° X1 vÅš p p

pp p

p° −

°=

° −°

X1

(ii) pp

° −( )°

= − = { + = }11 11

1 2 1 2X

X X X X

(iii) ∴ p p

p° −

°× = X2 ïªj rk‹ghL uîy£ ÉâÆ‹ fÂjÉaš

KiwahF«.

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80 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

3. 3 »uh« fiubghUis 20 »uh« ÚÇš fiu¤J »il¡F«

fiurÈ‹ ciwÃiy v‹d?

Jha ÚÇ‹ ciwÃiy 273K ÚÇ‹ Kf=1.86k kgmol-1

fiubghUË‹ nkhš vil = 300 »uh«/nkhš.

(i) T T K

WM W

° − =

=

f m

m 2

2 1

(ii)

T T K

×

° − =× ×

×=

3300 20

1000

1 86 3 1000300 20

0 93. .

(iii) T = 273K – 0.93K = 272.07K

4. Ñœ¡f©lt‰¿‹ nkhyhš bfhâÃiy V‰w kh¿ÈÆ‹

kâ¥òfis jUf.

t.v© fiu¥gh‹bfhâÃiy

(K) Kb(K.Kg.mole–1)

(i) Ú® 373.00 0.52

(ii) bg‹Ó‹ 353.10 2.57

(iii) bk¤jdhš 337.51 0.81

(iv) v¤jdhš 351.33 1.20

(v) Fnshnuhgh®« 334.20 3.88

(vi) má£nlh‹ 329.15 1.72

5. ciwÃiy¤ jhœÉÈUªJ X® fiurÈ‹ _y¡TW

vilia v›thW îzÆ¥ghŒ?

(i) ΔTf = Kf . m m v‹gJ nkhyhÈ£o.

2 22

1 2

WW Mnm n= =k‰W«

W1 = fiu¥ghÅ‹ vil »nyh»uhÄš

M2 = fiubghUË‹ _y¡TW vil

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∴ m =W

M W2

2 1

∴ ∆T = KW

M W2

2 1f f

M =K WT W

K. mol gK.2

2

1

1f

f

kgkg

⋅−

M =KT

.WW

gmol22

1

1f

f∆−

vdnt fiubghUË‹ _y¡TW vilia fz¡»lyh«.

ghl« - 12

bt¥g ïa¡fÉaš - I 2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. vÇâš v‹jhšãia îzÆ¡F« fUÉÆ‹ bgaiu vGJ.

gh« fnyhÇ Û£l®

2. M‰wiy M¡fî«, mÊ¡fî« Koí«. ï¡T‰W rÇah

mšyJ jtwh vd¡TW.

jtW. VbdÅš bt¥g ïa¡fÉaÈš Kjš Éâ¥go, “M‰wš

xU tifÆš ïUªJ k‰bwhU tif¡F kh‰w¡ ToaJ.

Mdhš M‰wiy M¡fnth mšyJ mÊ¡fnth KoahJ”.

3. bt¥g ïa¡fÉaÈ‹ ó{Ía Éâia tiuaW.

bt›ntW bt¥gÃiyÆš cŸs ïu©L mik¥òfŸ _‹whtJ

mik¥òl‹ rkÃiyÆš ïUªjhš mit mid¤J« x‹nwhL

x‹W bt¥g rkÃiyia bg‰¿U¡F«.

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82 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

4. DU k‰W« DH ¡F cŸs bjhl®ig tUÉ.

(i) khwhj mG¤j¤âš bjhl¡f Ãiy¥ g©òfŸ - H1, U1, V1 k‰W« P. ïWâÃiy¥ g©òfŸ H2, U2, V2 k‰W« P.

(ii) ∆H = (H2–H1) = (U2–U1) + P (V2–V1)

∆H = ∆U + P ∆V

5. bt¥gkhwh¢ braš Kiwia tiuaW.

mik¥ã‰F« R‰Wòw¤â‰FÄilna bt¥g gÇkh‰w« ïšyhkš

Ãfœ¤j¥gL« brašKiwahF«.

6. bt¥g ïa¡fÉaÈ‹ Kjš Éâia tiuaW.

M‰wš xU tifÆÈUªJ k‰bwhU tif¡F kh‰w¡ ToaJ.

Mdhš M‰wiy M¡fnth mšyJ mÊ¡fnth KoahJ.

K¡»a Édh¡fŸ

1. M‰wš v‹gJ ahJ? áy tif M‰wšfis TW.

ntiy brŒtj‰fhd âw‹, M‰wš vd¥gL»wJ.

(i) Ä‹dh‰wš

(ii) ntâ M‰wš

(iii) bt¥g M‰wš

(iv) ïaªâu M‰wš

(v) NÇa M‰wš vd gytif¥gL«.

2. mik¥ò v‹whš v‹d?

MŒî¡F vL¤J¡bfhŸs¥gL« m©l¤â‹ xU F¿¥ã£l

gFâ mik¥ò vd¥gL«.

3. R‰W¥òw« v‹whš v‹d?

MŒÉ‰F c£gL¤j¥g£l gFâ jÉu vŠáíŸs m©l¤âš

ãw gFâfŸ R‰W¥òw« vd¥gL«.

4. jŤj mik¥ò v‹whš v‹d?

X® mik¥ã‰F«, R‰Wòw¤â‰F« ïilna bghU©ik k‰W«

M‰wš gÇkh‰w« ÃfHhkš ïUªjhš mJ jŤj mik¥ò

vd¥gL«.

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5. _oa mik¥ò v‹whš v‹d?

X® mik¥ãš mik¥ã‰F«, R‰Wòw¤â‰F« ïilna M‰wš

k£L« gÇkh‰w« milªjhš mJ _oa mik¥ò vd¥gL«.

6. xU ÉidÆš xU nkhY¡F btËÉl¥gL« bt¥g« ahJ?

483.7 kJ ≡ 2 nkhšfŸ.

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. bt¥g« cÄœ braš Kiw k‰W« bt¥g« bfhŸ brašKiw

M»at‰¿‰»ilnaahd ntWghLfis vGJf.

bt¥g« cÄœ brašKiw bt¥g« bfhŸ brašKiw

(i) bjhl¡f ÃiyÆÈUªJ

ïWâ Ãiy¡F khW«

xU brašKiwÆ‹

nghJ bt¥g« cÄH¥

gL»wJ.

bjhl¡f ÃiyÆÈUªJ

ïWâ Ãiy¡F khW« nghJ

bt¥g« c¿Šr¥gL»wJ.

(ii) mik¥ã‹ ïWâ

ÃiyahdJ bjhl¡f

Ãiyia Él Fiwªj

M‰wiy bg‰¿U¡F«.

mâf M‰wš

mik¥ò bt¥gkhf

btËÉL»wJ.

∆H = –Ve

mik¥ã‹ ïWâ

ÃiyahdJ bjhl¡f

ÃiyiaÉl mâf

M‰wš bg‰¿U¡F«.

mâf M‰wiy bt¥gkhf

mik¥ò R‰Wòw¤âÈUªJ

c¿ŠR»wJ.

∆H = +Ve(iii) bt¥g¤â‹ cÄœ

ïa‰ãaš kh‰w¤â‹ nghJ bt¥g« vL¡f¥ gL»wJ. âut« ciw ÃiyÆš â©kkhtJ bt¥g cÄœ brašKiwahF«. ∆E = –Ve

bghJthf X® ïa‰ãaš kh‰w¤â‹ nghJ, bt¥g¤âdhš xU â©k« cUFtJ bt¥g« bfhŸ braš KiwahF«.∆E = +Ve

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K¡»a Édh¡fŸ

1. mik¥ã‹ bghU©ik g©òfŸ v‹whš v‹d? mj‹

tiffŸ ahit?

(i) mG¤j« fdmsî, bt¥g« ml®¤â, gu¥ò ïGÉir

Éyfš v©, Ãw« ngh‹w g©òfŸ mik¥ã‹ ÃiyÆš

bghU¤J ïU¥gjhš mit bghU©ik¥ g©òfŸ

vd¥gL«.

(ii) ïu©L tif¥gL«,

(iii) bghU©ik rh® g©òfŸ

bghU©ik rhuh g©òfŸ (m) mf¥g©òfŸ.

2. Ûsh¢ braš Kiw v‹whš v‹d? v.fh.jUf.

(i) R‰W¥òw¤âš xU Ãiyahd kh‰w¤ij V‰gL¤jhkš

mik¥ãid Û©L« bjhl¡f Ãiy¡F bfh©L tu

ïayhj brašKiw Ûsh¢ brašKiwahF«.

(ii) KJikailtJ xU Ûsh¢ brašKiwahF«.

(iii) mUÉÆš ïUªJ Ú® bfh£LtJ.

3. ÛŸk‰W« Ûsh¢ brašKiwfË‹ x¥ÕLKiw¤ jUf.

t.

v©ÛŸ brašKiw Ûsh¢ brašKiw

(i) K‹ndh¡F (m) ã‹

neh¡F âirÆš ÃfG«.

xnu âirÆš k£L« ÃfG«.

(ii) brašKiw gy á¿a

gofËš Ãfœ¤j¥gL»wJ.

tiuaW¡f¥g£l Éir

njit¥gL»wJ.

(iii) x›bthU goÆY«

mik¥ò R‰W¥òw¤Jl‹

rk ÃiyÆš ïU¡F«.

ï«kh‰w¤â‹nghJ

mik¥ã‰F«

R‰W¥òw¤â‰F« rk Ãiy

VJ« ïšiy.

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4. gšntW tif ntiyfËš VnjD« _‹iw vGJf?

(i) òÉ<®¥ò ntiy: òÉ<®¥ò Éir¡F vâuhf xU bghUis

F¿¥ã£l cau¤â‰F nkny ca®¤J« nghJ òÉ<®¥ò

ntiy brŒa¥gL«.

‘m’ Ãiwbfh©l bghUis òÉ<®¥ò KL¡f¤â‰F

vâuhf ‘h’ cau¤â‰F ca®¤J« nghJ ‘mgh’ ntiy

brŒa¥gL»wJ.

(ii) Ä‹rhu ntiy: Ä‹òy« bg‰w xU bghUŸ Ä‹ mG¤j¥

gFâÆš ïUªJ k‰bwhU Ä‹ mG¤j« gFâ¡F ïl«

bgaU« nghJ Ä‹rhu ntiy brŒa¥gL»wJ.

(iii) vªâuÉaš ntiy: xU mik¥ã‹ mG¤j¤ij

Fiw¤jhnyh (m) mâfǤjhnyh mj‹ fd msÉš

V‰gL« kh‰w« vªâuÉaš ntiy MF«.

5. mf M‰wš v‹whš v‹d? mt‰¿‹ g©òfŸ ïu©il

F¿¥ãLf?

(i) mf M‰wš (U) v‹gJ bt¥g ïa¡fÉaÈ‹ mik¥ã‹

M‰wš MF«.

(ii) ïa¡f M‰wš k‰W« Ãiy M‰wš M»ait nr®ªjnj

mf M‰wš MF«.

(iii) g©òfŸ : M‰wš v‹gJ bghUik rh® g©ghF«.

(iv) U xU tÊ¢ rh®¥ò bfh©ljšy,

SI my»š M‰wÈ‹ myFfŸ éšfŸ ‘J’ (m) kJ MF«.

(v) U xU tÊ¢ rh®¥ò bfh©ljšy. bjhl¡f, ïWâ

Ãiyfis¥ bghW¤J khWtâšiy.

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ghl« - 13

ntâ¢rkÃiy - I 2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. Ãiwjh¡f Éâia tiuaW.

khwh bt¥gÃiyÆš xU ntâÉidÆ‹ ÉidntfkhdJ

ÉidgL bghUŸfË‹ »s®î ÃiwfË‹ bgU¡F¤

bjhif¡F ne® É»j¤âš ïU¡F«.

2. PCl5(g) � ⇀�↽ �� PCl3(g) + Cl2(g) v‹w Éid¡F Kp ‹ kâ¥ig

vGJf.

PCl5(g) � ⇀�↽ �� PCl3(g) + Cl2(g)

K .

pCl

Cl=

p pp

P Cl

P

3 2

5

K . p =

−x

x

2

21P (x - ãÇif åj«)

3. ÛshÉid¡F cjhuz« bfhL.

(i) Éid xnu âirÆš k£L« eilbg‰W Kotila¡ToaJ

Ûsh ÉidfŸ vd¥gL«.

(ii) fh®g‹ fh‰¿š vǪJ fh®g‹il M¡i[il¤ jUtJ

xU Ûsh ÉidahF«. C(g) + O2(g) → CO2

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K¡»a Édh¡fŸ

1. ÛŸ Éid v‹gJ ahJ?

xU ÉidahdJ K‹ndh¡F k‰W« ã‹ndh¡F âirfËš

xnu neu¤âš Ãfœªjhš mJ ÛŸ Éid vd¥gL«.

ÛŸ Éid ã‹tUkhW F¿¡f¥gL»wJ.

H2 + I2 K

Kf

r� ⇀���↽ ���� 2 HI

2. rkÃiyia Jt¡F« tÊKiw v.fh. cl‹ jUf.

xU ÛŸ ÉidÆ‹ rk Ãiyia ÉidgL bghUŸfË‹

tÊahf mšyJ ÉidÉis bghUŸfË‹ tÊahfnth

Jt¡fyh«.

vL¤J¡fh£lhf:- H2(g) + I2(g) � ⇀�↽ �� 2HI(g) rkÃiy H2 k‰W« I2 tÊahf (or) HI tÊahfnth Jt¡fyh«.

3. ntâ rkÃiy v¡fhuÂfis rh®ªJŸsJ?

(i) bt¥gÃiy

(ii) mG¤j«

(iii) rkÃiy br¿î

4. ãÇif åj« v‹whš v‹d?

ãÇif rkÃiyÆš, ãÇifailªj _y¡TWfË‹

v©Â¡if¡F«, bkh¤j _y¡TWfS¡F« cŸs

É»jkhdJ ãÇif åj« (x) vd¥gL«.

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3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. Dn = 0, Dn = 1 k‰W« Dn = 2 M»a kâ¥òfS¡F Kp k‰W« Kc -¡F ïilnaíŸs bjhl®ig vGJf.

Kp = Kc RT∆ng

(i) ∆n = 0 vÅš

Kp = Kc [∴(RT)º = 1]

(ii) ∆n = 1 vÅš Kp = Kc RT

(iii) ∆n = 2 vÅš

Kp = Kc (RT)2

2. rkÃiy br¿îfŸ khwhkš ïU¥gj‰fhd fhuz¤ij

vGJf.

(i) khwh bt¥gÃiyÆš _oa fy¤âš ntâ¢rkÃiy

cUthF« nghJ _y¡TWfŸ Éid¥g£L ÉidÉis

_y¡TWfis jU»‹wd.

(ii) ÉidÉis _y¡TWfŸ mnj ntf¤âš Éid¥g£L

ÉidgL _y¡T¿id jU»‹wd.

(iii) ntârkÃiyÆš K‹ndh¡F, ã‹ndh¡F ÉidÆ‹

ntf« rkkhf ïU¥gjhš rkÃiy br¿îfŸ

khwhâU¡»‹wd.

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K¡»a Édh¡fŸ

1. gygo¤jhd rkÃiy v‹whš v‹d? c.« jUf?

xU nt⢠rkÃiyÆš ÉidgL k‰W« ÉidÉis

bghUŸfŸ bt›ntW ÃiyikfËš ïUªjhš mJ gy

go¤jhd rkÃiy vd¥gL«.

v.fh.: CaCO3(s) � ⇀�↽ �� CaO(s) + CO2(g)

3Fe(s) + 4H2 O(g) � ⇀�↽ �� Fe3 O4(s)+ 4H2(g)

2. ÛŸ Éid v‹whš v‹d?

(i) xU ÉidahdJ K‹ndh¡» k‰W« ã‹ndh¡»

âirfËš xnu neu¤âš Ãfœªjhš mJ ÛŸ Éiz

vd¥gL«.

(ii) K

K

A + B C + D -

C + B A + B -

f

r

ã‹ndh¡FÉid

ÛŸÉid ã‹tUkhW

vGj¥gL»wJ.

A + B C + DK

Kf

r� ⇀���↽ ����

(iii) ÛŸÉid¡F v.fh

2 2 2 2

5 3 2

3

NO N O

PC PC C

C CO

g g

g g

g

l l l

a

( ) ( )

( ) ( )

( )

+

� ⇀�↽ ��� ⇀�↽ ��� ⇀�↽ �� CC O COa s g( ) ( )+ 2

4. Ú®kÃiy rkÃiyfŸ v‹gJ v‹d? v.fh. jUf

nt⢠rkÃiyÆš ÉidgL k‰W« Éid Éis bghU£fŸ

Ú®kÃiyÆš ïUªjhš mj‰F Ú®k Ãiyik rkÃiy vd¥gL«.

v.fh.

CH3COOH(1) + C2 H5 OH

CH3 COOC2H5(1) + H2O(1)

thí Ãiyik k‰W« Ú®k Ãiyik rkÃiyfŸ xU go¤jhd

rkÃiyfŸ vd¥gL«.

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ghl« - 14

ntâ ÉidntfÉaš - I 2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. miu thœî neu« v‹gij tiuaW.

miu thœî neu« v‹gJ ÉidgL bghUŸfË‹ bjhl¡f¢

br¿î ghâahf Fiwtj‰F vL¤J¡ bfhŸS« neu« MF«.

t1/2 = 0 6932.K

2. _y¡TW v© v‹whš v‹d?

xU ntâÉidÆ‹ vËa goÆš <Lgl¡Ta mQ¡fŸ (m)

_y¡T¿‹ v©Â¡if _y¡TW v© vd¥gL«.

3. Éidntf¤ij îzÆ¡F« go v‹whš v‹d?

(i) áy ntâÉidfŸ x‹W¡F nk‰g£l gofËš ÃfH¡Toa

ÉidfshF«.

(ii) bkJthf ÃfG« ÉidÆ‹ Éidntf¤ij nrhjid

_y« f©l¿ayh«.

vdnt xU ÉidÆš bkJthf Éid ÃfG« gona mj‹

Éidntf¤ij îzÆ¡F«go v‹g®.

4. Éid tifia rh®ªâU¡F« fhuÂfŸ ahit?

Éidtif rh®ªâU¡F« fhuÂfŸ mG¤j«, bt¥gÃiy

k‰W« br¿î M»aitahF«.

5. pA + qB Æ lC + mD v‹w Éid¡fhd Éidntf Éâia

vGJf.

ÉidÆ‹ ntfkhdJ ÉidgL bghUŸfË‹ bjhl¡f¢

br¿îfË‹ bgU¡F¤ bjhif¡F ne®É»j¤âš ïU¡F«.

pA + qB Æ lC + mD

Éidntf ÉâÆ‹go, Éidntf« α [A]p , [B]q

Éidntf« = k [A]p . [B]q

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92 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

6. ÉidÆ‹ Éid ntf¤ij tiuaW.

xuyF neu¤âš ÉidgL bghUŸfŸ (m) ÉidÉis

bghUË‹ br¿Éš V‰gl¡Toa kh‰w« ÉidÆ‹ Éid

ntf« vd¥gL«.

A + B → C + D

Éidntf« =br¿Éš V‰gL« kh‰w«

vL¤J¡ bfhŸs« neu«

=− [ ] =

− [ ] =+ [ ] =

+ [ ]ddt

ddt

ddt

ddt

A B C D

K¡»a Édh¡fŸ

1. ã‹dtif v‹whš v‹d?

ÉidÆ‹ ntf«, ã‹d br¿it bghW¤J mikí« m›Éid

ã‹dtif Éid vd¥gL«. v.fh. má£lhšoiAL

bt¥g¤jhš áijtilí« ÉidÆ‹ tif 1.5 vd

f©l¿a¥g£LŸsJ.

2. ÉidÆ‹ Éidtifia îzÆ¡F« Kiwia vGJ?

(i) tifbfG Kiw

(ii) bjhifÆlš Kiw

(iii) miuthϔ neu Kiw

(iv) M°thšo‹ jŤJ ãÇjš Kiw

3. Kjš tif Éid¡fhd Éidntf rk‹gh£il vGJf.

A → ÉidÉis bghU£fŸ

Éidntf« α [A]

Éidntf« = k [A]

kt t

=−∞

2 303 12

. log VV V

Éeho–1

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3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. Éidntf¤ij ghâ¡F« fhuÂfŸ ahit?

(i) ÉidgL bghUŸfŸ k‰W« ÉidÉis bghUŸfË‹

j‹ik.

(ii) ÉidgL bghUË‹ br¿î

(iii) Éidô¡»

(iv) mik¥ã‹ bt¥gÃiy

(v) fâ®å¢R

(vi) Éisah£L bghUŸfË‹ br¿î

K¡»a Édh¡fŸ

1. ó{Ía tif Éid v‹whš v‹d?

xU ntâÉidÆš ÉidÆ‹ ntf« ÉidgL« bghUŸfË‹

br¿îfis¢ rh®ªâU¡fÉšiybaÅš mJ ó{a tif

Éid vd¥gL«.

Éid ntf ÉâahdJ,

k =A A

to t[ ] − [ ]

ó{Ía tif Éid¡F v.fh.: H2(g) + Cl2(g) hν� ⇀��↽ ��� 2HCl(g)

2. 2A Æ ÉidÉis bghUŸfŸ v‹w ïu©lh« tif

Éid¡fhd Éidntf¢ rk‹gh£il vGJf.

2A → ÉidÉisbghUŸ

Éidntf« = k [A]2

kt

= [ ] − [ ]

1 1 1A At o

(mšyJ)

kt

xa a x

=−

1( )

È£l® nkhš–1 Éeho–1

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ghl« - 15

fÇk ntâÆaÈ‹ mo¥gil¡ bfhŸiffŸ

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. gâä£L ÉidfŸ.

fh®gDl‹ ïiz¡f¥g£LŸs xU mQ bjhFâ Ú¡f¥g£L,

ntW xU mQ mšyJ bjhFâ m›Él¤ij milªJ

fh®gDl‹ ãiz¥ò V‰gLkhÆ‹ m›Éid gâä£L

ÉidahF«.

v.fh.: CH3Cl + KOH →Ú® CH3 OH + KCl

2. T£LÉidfŸ.

ïu©L _y¡TWfŸ To xnu nr®k¤ij jU« Éid T£L

Éid vd¥gL«.

v.fh.: CH + H CH

CH Cl CH Cl

2 3

2 2

3. Ú¡f ÉidfŸ.

xU _y¡TWÈUªJ xU mQî« (m) xU bjhFâí« (m)

ïu©L bjhFâfŸ Ú¡f« mil»‹wd. ï›Éid Ú¡f

Éid vd¥gL«. ïJ T£L ÉidÆ‹ vâ®g¡f ÉidahF«.

v.fh.: CH3CH2 Br KOH→MšfAhš

fiuªj CH2 = CH2 + KBr + H2O

v¤âä ònuhikL

4. gygoah¡fš ÉidfŸ.

ïu©L¡F nk‰g£l _y¡TWfŸ T£L ÉidÆš <Lg£L

xU bgÇa _y¡Tiw c©lh¡F« Éid gygoah¡fš

ÉidahF«.

v.fh.: nCH2 = CH2 473

1000K

atm → [CH2 – CH2]n

v¤âä‹ (xUgo) ghȤԋ (gygo)

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K¡»a Édh¡fŸ

1. bra‰if KiwÆš ôÇahit jahǤjt® ah®? v›thW?

nAhy® (1828).

m«nkhÅa« rand£il RLgL¤â MŒt¤âš ôÇahit

jahǤjh®.

NH4CNO ∆ → NH2CONH2

mnkhÅa« rand£ ôÇah

2. fh®gh¡áÈ¡ mÄy« v‹whš v‹d?

fÇk nr®k§fËš - COOH Éid bjhFâ ïUªjhš mit

fh®gh¡áÈ¡ mÄy§fŸ vd¥gL»wJ.

v.fh.: CH3 – COOH má£o¡ mÄy«

ïu©L -COOH bjhFâia cilait ilfh®gh¡áÈ¡

mÄy§fŸ vd¥gL«

COOH

COOH CH2

COOH

COOHM¡ÌÈ¡ mÄy« bknyhÅ¡ mÄy«

3. CH2 = CH2 ït‰¿‹ IUPAC bga® v‹d?

v¤â‹

4. CH3 – CH2 – Br ït‰¿‹ IUPAC bga® ahJ?

ònuhnkh <¤nj‹

5. CH3 – CH2 – OH ït‰¿‹ IUPAC k‰W« gH¡f¥ bga®

v‹d?

gH¡f¥ bga® – v¤âš MšfAhš

IUPAC – v¤jdhš

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98 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. Óuhd k‰W« Óu‰w ãs¤jš.

(i) xU ãiz¥ò ãs¡F« nghJ, x›bthU mQÉlK«

ãiz¡F« vy¡£uh‹ ïu£ilÆš cŸs xU vy¡£uh‹

Él¥gL»wJ ïJ Óuhd ãs¥ò v‹W bga®.

• • CH3 – CH3 → CH3 + CH3

ii) ãiz¥ò ãs¡f¥gL« nghJ ãiz¡F« vy¡£uh‹

ïu£il ïu©oš VnjD« xU mQÉlnk Él¥gL»wJ.

ïij Óu‰w ãs¥ò v‹»nwh«.

CH3 – Cl → CH3+ + Cl–

2. V‰w ïw¡f ÉidfŸ.

Ú®¤j fiurš xU Äjkhd V‰¿, ïJ C = C ãiz¥ãš x‹iw

ãs¡»wJ.

v.fh.: CH

CH

2

2

+ H2O + [O] KMnO4→fhu« fyªj

CH OH

CH OH

2

2

v¤âä‹ v¤âä‹ »is¡fhš

(ii) MšoiAL mšyJ Ñ£nlh‹fŸ ml® HCl K‹ÅiyÆš

iA£nuh fh®g‹fshf xL¡fkil»‹wd.

C6H5COCH3 Zn/HgHCl→ C6H5 – CH2 CH3

má£nlh~Õndh‹ v¤âš bg‹Ó‹

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K¡»a Édh¡fŸ

1. gš ïd tisa nr®k« v‹gJ v‹d? c.« jUf

(i) tisa nr®k§fË‹ fh®g‹ mQ¡fnshL ntW tif

mQ¡fsh»a ie£u#‹, M¡Ì#‹ fªjf« mika

bg‰whš mit gš ïd tisa nr®k« MF«.

(ii) H-C

H-CN

C-H

C-H

HNH

ã®nuhš

(iii) H-C

H-CO

C-H

C-H

O

jah~Õ‹2. fÇk ntâÆaÈ‹ áw¥ãašòfŸ _‹iw¡ F¿¥ãLf

(i) bghJthf g‰¿ vÇí« j‹ik bfh©lit.

(ii) rf¥ãiz¥ãid cilait.

(iii) Fiwªj cUFÃiy, bfhâÃiy cilait.

(iv) ïit kh‰¿a¥ g©ãid bg‰¿U¡»‹wd.

3. gotÇir nr®k§fË‹ áw¥ãašòfŸ _‹iw¡ F¿¥ãLf?

(i) xnu tifadh Éid¤bjhFâfisí«, jÅk§fisí«

bfh©oU¡F«.

(ii) x¤j ntâ ÉidfËš <LgL»‹wd.

(iii) tÇirÆš cŸs mL¤jL¤jit, xU CH2 bjhFâÆš

ntWgL»‹wd.

4. Ñœf©lt‰¿‹ IUPAC bga® v‹d?

(i) CH3– OH

(ii) CH3– CH2– OH

(iii) CH3– CH2– CH2– OH

(i) bk¤jdhš

(ii) v¤jdhš

(iii) 1 - òu¥gdhš

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ghl« - 16

fÇk¢ nr®k§fis¤ öŒikgL¤Jjš

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. gofkh¡fš KiwÆš nk‰bfhŸs¥gL« bt›ntW gofŸ

ahit?

(i) â©k¥ bghUis rÇahd fiu¥ghÅš fiu¤J fiuriy

jahǤjš.

(ii) Nlhd fiuriy tof£Ljš.

(iii) toÚiu FËu it¤J gofkh¡fš.

(iv) gof§fis ãǤbjL¤J cyu it¤jš.

2. ÚuhÉahš fhŒ¢á to¤jš - tiuaW.

(i) ÚÇš fiuahj â©k« k‰W« âut fÇk¢ nr®k§fis

ÚuhÉ _y« fhŒ¢á to¤J öa fÇk¢ nr®k« bgW«

Kiw ÚuhÉahš fhŒ¢á to¤jš vd¥gL«.

(ii) ÚuhÉ bt¥gÃiyÆš áijîwhkš ïU¡F« nr®k§fis

öŒik¥gL¤j ï«Kiw ga‹gL»wJ.

3. fhŒ¢á to¤jÈ‹ tiffŸ ahit?

(i) vËa fhŒ¢á to¤jš

(ii) ã‹d¡ fhŒ¢á to¤jš

(iii) ÚuhÉahš fhŒ¢á to¤jš

(iv) Fiwªj mG¤j¤âš fhŒ¢á to¤jš

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4. Fiwªj mG¤j¤âš fhŒ¢á to¤jÈ‹ e‹ikfŸ

ahit?

(i) tË k©ly mG¤j¤âš fhŒ¢á to¡F« nghJ ïašò

ÃiyÆš áijîW« nr®k« öŒikah¡f¥gL»wJ.

(ii) nr®k§fŸ ÉiuÆš bfhâÃiyia milªJ ÉLtjhš

vÇbghUŸ mâf« åzhtâšiy.

K¡»a Édh¡fŸ

1. thiy to¤jš KiwÆš ãǤbjL¡f¥L« nr®k¤â‰F

cjhuz« jUf.

(i) ie£nuh bg‹Ó‹ (bfh.Ã.484k) k‰W«

bg‹Ó‹ (bfh.Ã.354k),

(ii) il v¤âš <j® (bfh.Ã.308k) k‰W«

v¤âš MšfAhš (bfh.Ã.351k)

2. efU« Ãiyik v‹gJ ahJ?

efU« Ãiyik v‹gJ Ñœ ïUªJ nkš neh¡» efU« xU

fiurš mšyJ fiuršfË‹ fyitahF«.

3. gj§fkh¡fš v‹whš v‹d? c.«. jUf.

â©k¥ bghU£fis NLgL¤J« nghJ â©k ÃiyÆš

cUfhkš neuoahf MÉÃiy¡F khWtJ MÉia FËu¢

brŒjhš â©k¥ bghUŸ Û©L« bgw¥gL»wJ. ï«Kiw¡F

gj§fkhjš v‹W bga®. (c.«.: eh¥jÈ‹, f‰óu«).

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104 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. tojhŸ gu¥bgh£L t©z ãÇifÆ‹ tiffŸ ahit?

(i) VWKf tojhŸ gu¥bgh£L t©z¥ ãÇif Kiw

(ii) ïw§F Kf tojhŸ gu¥bgh£L t©z¥ ãÇif Kiw

(iii) t£l tojhŸ t©z¥ ãÇif Kiw

K¡»a Édh¡fŸ

1. fÇk¢ nr®k§fis öŒik gL¤J« gšntW KiwfŸ

ahit?

(i) gofkh¡fš

(ii) ã‹d¥ gofkh¡fš

(iii) gj§fkh¡fš

(iv) thiy to¤jš

(v) fiu¥gh‹ bfh©L rhW ïw¡Fjš

(vi) t©z¥ ãÇif Kiw

2. ÚuhÉahš fhŒ¢á to¤jš KiwÆš öŒikgL¤j¥gL«

nr®k« bg‰¿U¡F« g©òfŸ ahJ?

(i) ÚuhÉ bt¥gÃiy áijîwhkš ïU¡f nt©L«.

(ii) 373K-š ï¢ nr®k§fŸ ca® MÉ mG¤j¤âid

bg‰¿U¡f nt©L«.

(iii) ÚÇš fiuahj j‹ik bg‰¿U¡f nt©L«.

This material only for sample

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3. ÚÇa fiurÈš ïUªJ fÇk¢ nr®k§fŸ v›thW

ãǤbjL¡f¥gL»wJ?

(i) Jha nr®k« fhŒ¢á to¤jš _y« fÇkfiu¥ghÅš

ïUªJ ãǤbjL¡f¥gL»wJ.

(ii) ãÇòdiy ga‹gL¤â, fiu¥ghÅš cŸs fÅk¢nr®k«

ãÇ¡f¥gL»wJ. khR¡fŸ ÚÇnyna j§»ÉL»wJ.

(iii) fÇk nr®k« cŸs ÚÇa fiuriy jFªj fÇk

fiu¥ghDl‹ nr®ªJ e‹F FY¡»dhš, ÚÇš ïUªJ

ãÇif milªJ mjhtJ fÇk k‰W« ÚÇa mL¡Ffshf

ãÇ»wJ.

ghl« - 17

jÅk§fis¡ f©l¿jY« msÉLjY«

2 kâ¥bg©fŸ

K¡»a Édh¡fŸ

1. fÇk¢ nr®k¤âš cŸs fªjf«, k‰W« ršgiu v›thW

f©l¿ayh«?

byáf‹° toÚUl‹ nrhoa« ie£nuhò%irL nr®¡F«

nghJ Cjh Ãw¤ij bfhL¡»wJ. vdnt ïâš ršg® cŸsJ

vd f©l¿ayh«.

Na2S + Na2 [Fe(CN)5 NO] Na2 [Fe(CN)5 NOS]nrhoa« ie£nuh ò%irL CjhÃw«

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2. Ahy#‹fis f©l¿í« nrhjidia És¡Ff?

(i) nrhoa« cU¡F¢rh¿š Ahy#‹fŸ nrhoa« Ahiylhf

cŸsJ. Na + X NaX

(ii) nrhjid cU¡F¢ rhW Ú®¤j HNO3 bfh©L

mÄy¤j‹ikah¡f¥g£L, ã‹ ášt® ie£nu£ fiurš

nr®¡f¥gL»wJ. åœgoî c©lhtjhš Ahy#‹fŸ

ïU¥gij¡ cz®¤J»wJ.

NaX + AgNO3 → AgX ↓ + NaNO3

3. jÅk§fis f©l¿a ga‹gL¤j¥gL« rhW vJ?

nrhoa« cU¡F¢ rhW

4. ršgiu nrhoa¤Jl‹ Nnl‰W« nghJ Ãfœtbj‹d?

nrhoa¤Jl‹ Nnl‰W« nghJ ršigil¡ bfhL¡»wJ.

2Na + S → Na2S

3 kâ¥bg©fŸ

K¡»a Édh¡fŸ

1. fh®g‹ v›thW f©l¿a¥gL»wJ?

fÇk¢ nr®k¤âš cŸs fh®g‹ fh¥g® (II) M¡i[L cl‹

Éidg£L fh®g‹il M¡i[lhf khW»wJ. ïJ bj˪j

R©zh«ò Úiu ghš nghš kh‰W»wJ.

C + 2CuO CO2 + 2 Cu

Ca (OH)2 + CO2 CaCO3 + H2O

This material only for sample

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ghl« - 18

iA£nuh fh®g‹fŸ

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. iA£nuhnghnuhnd‰w« v‹whš v‹d?

MšÑ‹fŸ ilnghnuDl‹ ÉidòǪJ oiu-Mš¡ifš

nghnu‹fis jU»wJ. ïJ fhu§fyªj iA£u#‹

bguh¡i[oš V‰w« milªJ Kj‹ik MšfAhiy¤ jU«.

ïJ iA£nuh nghnuhnd‰w« MF«.

3CH2 = CH2 + (BH3)2 2(CH3 - CH2)3Bv¤âä‹ ilnghnu‹ oiuv¤âš nghnu‹

( )CH CH B H O CH CH OH2 22 2

3 32 − → − v¤jdhš

2. Xnrh‹ gF¥ò v‹whš v‹d?

Mš¡Ñ‹ (or) Mš¡if‹ cl‹ Xnrh‹ nr®¡if ÉidòÇjš

Xnrh‹ gF¥ò vd¥gL«.

CH2= CH2+ O3

CH2COOH /H2O

CH2

H2O2 + 2HCHO

O

O O ozonideZn

CH2

XnrhidL gh®khšoiAL

3. É£o¡ Éid v‹whš v‹d?

oiu¥ Õidš gh°nghÅa« ÆiyLl‹ MšoiAL

(m) Ñ£nlh‹, tidòǪJ MšÑ‹ k‰W« oiu¥Õidš

gh°nghÅa« M¡i[il c©lh¡FtJ, É£o¡ ntâÉid

vd¥gL«.

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R1

C = 0 +

R2

− P+Ph3

C − R3

R4

+ Ph3 P = 0R1 R3

C = C

R2 R4

4. gygoah¡fš Éid v‹whš v‹d?

mâf v©Â¡ifÆš vËa _y¡TWfŸ (khndhk®) ïizªJ xnu xU Ú©l r§»È¤bjhliu (ghÈk®) c©lh¡F« Éidia gygoah¡fš Éid v‹»wh«.

n CH2 = CH2 O2 ,∆ →

mâf mG¤j«(– CH2– CH2)n

v¤âä‹ ghȤâ‹

5. v¤âäid v›thW Únu‰w ÉidÆš <LgL¤JthŒ?

tÈik Ä¡f mÄy C¡» K‹ÅiyÆš, Ú® v¤âäDl‹

T£L ÉidÆš <Lg£L v¤âš MšfAhiy jU»wJ.

CH2 = CH2 + H2O H+ → CH3 CH2 OH

v¤âä‹ v¤âš MšfAhš

gh®Ä¡ mÄy«

6. brŠN£L ÃiyÆYŸs FHhŒ tÊna má£oÈid

brY¤âdhš V‰gLtJ v‹d?

má£oÈid mâf mG¤j¤âš brŠN£L ÃiyÆš cŸs

FHhŒ tÊna brY¤âdhš gygoah¡fš ÃfœªJ bg‹Óid¤

jU»wJ.

3CH CH C H6 6 ≡ →brŠN£L FHhŒ

Ãiy mG¤j«

bg‹Ó‹

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K¡»a Édh¡fŸ

1. td°gâ, beŒ v›thW jhaÇ¡f¥gL»wJ?

Ãiwîwh czî v©bzŒfis 300°C bt¥gÃiyÆš áfš

C¡» K‹ÅiyÆš iA£u#nd‰w« brŒJ td°gâ beŒ

jhaÇ¡f¥gL»wJ.

2. òu¥igid brŠNlhd FHhÆš brY¤âdhš

Ãfœtbj‹d?

òu¥igid mG¤j¤âš brŠNlhd FHhÆš brY¤âdhš

gygoah¡fš ÃfœªJ, bká£oä‹, Éid»‹wJ.

3CH3 – C = CH →brŠN£L Ãiy

FHhŒ mG¤j«

CH3

CH3CH3

òu¥ig‹

3. iA£nuh fh®g‹fŸ v›thW tif¥gL¤j¥gL»‹wd?

(i) mÈ~gho¡ iA£nuhfh®g‹fŸ

(ii) mnuhnk£o¡ iA£nuhfh®g‹fŸ

mÈ~gho¡ iA£nuhfh®g‹fŸ nkY« Ãiwî‰wit

(Mšnf‹fŸ) v‹W«, Ãiwîwhjhit (MšÑ‹fŸ,

Mšif‹fŸ) vdî«, mÈir¡Ë¡ (tisa Mšnf‹fŸ)

vdî« gF¡f¥g£LŸsd.

4. C®£° Éid v‹whš v‹d?

<jÇš fiu¡f¥g£l Mš¡ifš AhiyL nrhoa«

cnyhf¤Jl‹ ÉidòǪJ ca® Mšnf‹fis¤ jUtJ

C®£° ÉidahF«.

CH3 – CH2Br + 2Na + Br – CH2 – CH3 →<j® CH3 – CH2 – CH2 – CH3 + 2NaBrv¤âš ònuhikL n - ãô£nl‹

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5. ïuhnd áfš v›thW jahÇ¡f¥gL»wJ?

Ni – Al cnyhf fyitÆš ïUªJ mYÄÅa¤ij nrhoa«

iA£uh¡irL bfh©L Ú¡Ftj‹ _y« uhnd áfš, Ú¡»

jahÇ¡f¥gL»wJ.

6. fh®gh¡áš Ú¡f Éid v‹whš v‹d? c.«. jUf.

fh®gh¡áÈ mÄy¤â‹ nrhoa c¥ãÈUªJ fh®g‹il

M¡i[il, nrhlh R©zh«ã‹ cjÉahš Ú¡FtJ

fh®gh¡áš Ú¡f Éid vd¥gL«

CH3CH2COONa + NaOH CaO∆ → CH3 – CH3 + Na2 CO3

nrhoa« ònuhãnahnd£ <¤nj‹

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. Mšnf‹fË‹ VnjD« IªJ nt⥠g©òfis¤ bjÇÉ.

Mšnf‹fis xË, bt¥g«, C¡»ia¥ ga‹gL¤â

FnshÇnd‰w«, ònuhÄnd‰w« brŒayh«.

CH4 + Cl2 uv CH3Cl + HCl

CH3Cl + Cl2 uv CH2Cl2 + HCl

CH3Cl2 + Cl2 uv CHCl3 + HCl

CHCl3 +Cl2 uv CCl4 + HCl

bk¤âš FnshiuL

bk¤âä‹ FnshiuL

Fnshnuhgh®«

fh®g‹ bl£uhFnshiuL

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ie£nuh V‰w« :

(i) Mšnf‹fis ie£nuh V‰w« brŒjš 150– 475°C š

Ãfœ¤j¥gL»wJ.

(ii) ï›ÉidÆš Äf¢ á¡fyhd fyitna Éis»wJ.

ï›Éidí« jÅ cW¥ò tÊÆš eilbgW»wJ.

CH3CH2CH3 CH3CH2CH2NO2+ CH3– CH – CH3+ CH3NO2+ CH3CH2NO2HNO400°C

NO2

M¡á#nd‰w« :

Mšnf‹fŸ vËâš mâfsî fh‰¿š g‰¿ vǪJ

CO2, H2O I¤ jU»‹wd.

CH4 + 2O2 CO2 + H2O

mnuhnk£o¡ nr®kkh¡fš

MW mšyJ mj‰F nkš fh®g‹ mQ¡fis¡ bfh©l

Mšnf‹fŸ, FnuhÄa«, tdoa«, khÈ¥od« M¡irnlhL

ïizªJ bt¥g¥gL¤j¥g£l mYÄÅa« ÛJ brY¤j¥gL«

nghJ iA£u#‹ Ú§F« tisakh¡fš Éid ÃfœªJ

mnuhnk£o¡ nr®k§fŸ c©lh»‹wd.

CH3 (CH2)4 CH3 + 3H2

Cr2 O3/ Al2O3

500° C, 10 − 20 atm

2. Mšnf‹fË‹ bghJthd jahÇ¡F« Kiwfis¤ bjÇÉ.

(i) Mšifš AhiyLfis Zn/HCl bfh©L xL¡f«

brŒJ Mšnf‹fis jahÇ¡fyh«.

CH3 CH2 Br + 2[H] Zn/HCl CH3CH3 + HBr

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(ii) c®£°Éid : <jÇš fiu¡f¥g£l MšifšAhiyL

nrhoa« cnyhf¤Jl‹ ÉidòǪJ Mšnf‹

c©lh»wJ.

CH3CH2Br + 2Na + Br CH2CH <j® CH3CH2 CH2CH3+2Na Br

(iii) »Ç¡dh‹L fhuÂia ga‹gL¤Jjš : »Ç¡dh®L

fhuÂíl‹ Ú®¤j mÄy« (m) Ú® M»at‰Wl‹

ÉidòǪJ Mšnf‹fis bfhL¡»wJ.

CH3CH2Br + Mg <j® CH3CH2 Mg Br

CH3CH2MgBr + H2O CH3CH3 + Mg

Br

OH(iv) nfhšã‹ Ä‹dh‰ gF¥ò Kiw : fh®gh¡ÌÈ¡

mÄy§fË‹ nrhoa« (m) bgh£lháa« c¥òfË‹

br¿ªj fiuriy Ä‹dh‰ gF¤jš brŒtj‹ _y«

ca®gotÇir iA£nuh fh®g‹fË‹ nr®ªj fyit

»il¡F«.

2CH3COOK 2CH3 COO– + 2K+

ne®Ä‹ KidÆš

2CH3COO– CH3 – CH3

+ 2 CO2↑ <¤nj‹

3. má£oÈDl‹ xnrh‹ Éidia vGJf.

má£oä‹ XnrhDl‹ To Xnrhidil¤ jU»wJ. ïij

Úuh‰gF¤jhš »isah¡rhš k‰W« gh®Ä¡ mÄy¤ij

jU»wJ.

CH = CH + O3H→

O

C C

OO

HH →CHO

CHO

+ H2O2 → 2HCOOHmá£oä‹

xnrhidL »isah¡rhš

This material only for sample

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K¡»a Édh¡fŸ

1. jhŒ iA£u#‹ fh®g‹ v‹gJ v‹d? v.fh. jUf

(i) nr®k¤âš vJ mâf beoa fh®g‹ bjhl® mik¥ig¡

bfh©lnjh mJnt jhŒ iA£nuh fh®g‹ vd¥gL«.

(ii) 2 1

CH2 CH3

CH3 CH2 CH2 CH CH3

6 5 4 3 bf¡nf‹

2. Mšnf‹fËš VnjD« ïu©L ntâ¥g©òfis¤ jUf?

M¡á#nd‰w« :

KMnO4 ngh‹w·V‰¿fŸ Inrhãô£nlid, _Éiz ãíilš

MšfAhš

(CH3)3 CH = [0] KMnO4 → (CH3)3COH

khÈ¥od« oiu M¡irL Û¤njid ~gh®khšoiAL Mf

V‰w« brŒ»wJ.

CH4 + O2 MoO3 → HCHO + H2O

ie£nuhV‰w« :

Mšnf‹fis ie£nuh V‰w« brŒjš 150 – 475°C š

Ãfœ¤j¥gL»wJ. ï›ÉidÆš Äf¢ á¡fyhd fyitna

Éid»wJ. ï›Éidí« jÅ cW¥ò tÊÆš eilbgW»wJ.

CH3CH2CH3 CH3CH2CH2NO2+ CH3– CH – CH3+ CH3NO2+ CH3CH2NO2HNO400°C

NO2

This material only for sample

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ghl« - 19

mnuhnk£o¡ iA£nuhfh®g‹fŸ

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. mnuhnk£o¡ j‹ikia tiuaW?

x‹W (m) mj‰F mâfkhd bg‹Ó‹ tisa§fis¡

bfh©l nr®k§fŸ bg‰¿U¡F« j‹ik mnuhnk£o¡ j‹ik

vd¥gL«.

2. åÇa¥gL¤J« bjhFâfis És¡Ff?

bg‹Óid Él mâf Éid ntf¤ij V‰gL¤J« bjhFâfŸ

åÇa« C£L« bjhFâfŸ MF«.

K¡»a Édh¡fŸ

1. gštisa mnuhnk£o¡ iA£nuh fh®g‹fŸ v‹gJ

v‹d?

ïu©L mšyJ mj‰F mâfkhd mnuhnk£o¡ tisa§fŸ

ïiz¡f¥g£LŸsd. ïu©L mL¤jL¤j fh®g‹ mQ¡fŸ

mnuhnk£o¡ tisa§fshš g»®ªJ bfhŸs¥gL»‹wd.

ït‰¿š áy ò‰WnehŒ fhuÂfsh«.

eh¥jä‹ ãndh¤jÇ‹ Mªjuá‹

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2. ~¥uÆlš-»uh¥£ Éidia És¡Ff?

bg‹ÓÅÈUªJ blhYÉ‹

C6H6 + CH3Cl 3AlCl

Úu‰w C6H5 CH3+ HCl

blhYÉ‹

3. C®£° ã£o¡ Éidia És¡Ff?

AhiyL, Mšifš AhiyLfË‹ fyitíl‹ nrhoa«

cnyhf« Éid¥g£L bg‹Ó‹ tÊ¢ nr®k§fŸ »il¡»‹wd.

C6H5 Br + 2Na + BrCH3→ C6H5CH3+ 2NaBrònuhnkh bk¤âš blhYÉ‹bg‹Ó‹ ònuhikL

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. bg‹Ó‹ Éahghu ßâÆš v›thW jahÇ¡f¥gL»wJ?

bg£nuhÈa¤ij ã‹d¡fhŒ¢á to¤jÈ‹ nghJ »il¡F«

eh¥jhit, mYÄdhîl‹ Toa ãsh£od« C¡»Æ‹

ÛJ brY¤âdhš bg‹Ó‹, blhYÉ‹ k‰W« gotÇir

nr®k§fŸ »il¡»‹wd. ï¡fyitÆÈUªJ bg‹r

fiu¥gh‹ rhW vL¤jš k‰W« ã‹d¡ fhŒ¢á to¤jš _y«

ãǤbjL¡f¥gL»wJ.

2. Ñœ¡f©l kh‰w§fis És¡Ff.

(i) bg‹ÓÅÈUªJ blhYÉ‹

(ii) ÕdhÈUªJ bg‹Ó‹

(iii) nrhoa« bg‹nrhna£oÈUªJ bg‹Ó‹

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(i) bg‹ÓÅÈUªJ blhYÉ‹:

6 6 3 6 5 33

C H CH Cl C H CH HClAlCl

+ → +Úu‰w

bg‹Ó‹ blhYÉ‹

cy® mYÄÅa« FnshiuL cl‹ bg‹Ó‹ MšifšAhiyL

cl‹ Éidg£L Mšifš bg‹Ó‹ »il¡»wJ.

(ii) ~ÕdhÈUªJ bg‹Ó‹:

C6H5OH 2CH3 C6H6 +ZnO ~Õdhš bg‹Ó‹

(iii) nrhoa« bg‹nrhna£oÈUªJ bg‹Ó‹:

C6H5COONa C6H6 + Na2CO3 bg‹Ó‹

K¡»a Édh¡fŸ

1. bg‹Ó‹ F¿¥ò tiuf?

(i) bg‹Óid Kj‹KjÈš ãǤjt® ~ghunl (1825)

(ii) Ãy¡fÇ jhÇY« bg‹Ó‹ ïU¥gij f©l¿ªjt®

Ah¥kh‹ (1845)

(iii) mnuhnk£o¡ nr®k tÇirÆš Kjš nr®k« bg‹Ó‹

(iv) nrhjid¢ rhiyÆš mnuhnk£o¡ mÄy§fshd

fh®gh¡áš bjhFâ Ú¡f ÃiyÆš bg‹Óid bgwyh«.

(v) bg‹Ó‹ _y¡TW thŒghL C6H6

COOH

CaO CaO

COOH

COOHNaOH NaOH

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ghl« - 20

fÇk Ahy#‹ nr®k§fŸ

2 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. ÿÆ° mÄy§fŸ v‹whš v‹d?

xU n#ho vy¡£uh‹fŸ FiwghL cŸs _y¡TWfŸ ÿÆ°

mÄy§fŸ vd¥gL»‹wd. ïit ïu©L vy¡£uh‹fis

V‰W¡ bfhŸs¡Toait.

v.fh:- BF3, AlCl3, Ag+, Na+

2. vy¡£uh‹ ft® nr®¥ò Éid v‹whš v‹d?

vy¡£uh‹fŸ mâf« cŸs ïl¤ij neh¡» vy¡£uh‹

Fiwthf cŸs fhuÂfns nrU« Éid vy¡£uh‹ ft®

nr®¥ò Éid vd¥gL«.

3. A‹°il¡f® Éid v‹whš v‹d?

fh®g‹ bl£uhFnshiuL _y¤âš ášt® fh®gh¡Ìny£LfŸ

FnshÇ‹ mšyJ ònuhÄ‹ M»at‰whš áijî‰W Mšifš

AhiyLfŸ bgw¥gL»‹wd.

CH3CH2 COOAg + Br2 → CH3CH2 Br + CO2 +AgBr

4. Rth®° Éid v‹whš v‹d?

Mšifš òqiuLfŸ, Mšifš FnshiuL (mšyJ)

ònuhikLfSl‹ AgF (mšyJ) SbF3 ngh‹w cnyhf

òqiuLfnshL nr®ªJ bgw¥gL»‹wd. ïJnt Rth®l°

Éid vd¥gL»wJ.

CH3CH2Br + AgF → CH3CH2 F + AgBr

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K¡»a Édh¡fŸ

1. miuš AhiyLfË‹ ga‹fŸ ahit?

(i) Fnshnuh bg‹Ó‹, k‰W« Õdhš jhaÇ¡fî«

(ii) mnrh k‰W« rš~g® rha§fŸ jhaÇ¡fî«

(iii) DDT, BHC ngh‹w ó¢á bfhšÈ jahÇ¡f¥ ga‹gL»wJ.

2. ~ã£o¡ Éidia És¡Ff?

Mšifš AhiyLfŸ ïšyhj nghJ miurš AhiyLfŸ

<j® fiurÈš nrhoa¤Jl‹ brašg£L ïU bg‹Ó‹

tisa§fŸ ãiz¡f¥g£l ïu£il miurš (biaryl) nr®k§fis¤ jU»‹wd.

C6H5 Br + 2Na + C6H5 Br →<j® C6H5 –C6H5+ 2NaBr

ig~Õidš

3. miurš AhiyLfŸ v‹gJ v‹d?

X® mnuhnk£o¡ tisa¤âš xU iA£u#‹ mQɉF gâyhf

Ahy#‹ mQ gâäL brŒa¥g£oUªjhš m¢nr®k¤â‰F

miuš AhiyLfŸ v‹W bga®.

v.fh.

Cl

Fnshnuhbg‹Ó‹

4. m® Mšifš AhiyL v‹whš v‹d?

X® mnuhnk£o¡ fh®gÅ‹ g¡f¤bjhlÇš cŸs fh®g‹

mQîl‹ Ahy#‹ mQ ãiz¡f¥g£oUªjhš

m¢nr®k¤â‰F m® Mšifš AhiyL (ar alkyl halide) v‹W

bga®.

CH2Cl

bg‹irš FnshiuL

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5. Mšnf‹fŸ jhaÇ¡F« Kiw x‹iw És¡Ff.

bk¤âš k¡Üáa« mnahilL ÚUl‹ mšyJ MšfAhYl‹

ïu£il¢ áijî¡F£g£L Mšnf‹fis cUth¡F»‹wd.

MgCH3 OH

I I+ HOH CH4 + Mg

Mg

CH3 OC2H5

I I

+ HOC2H5 CH4 + Mg

3 kâ¥bg©fŸ

ghl¥ ò¤jf Édh¡fŸ

1. ã‹bfš°o‹ Éid v‹gJ v‹d?

má£nlhÅš fiuªâU¡F« nrhoa« mnahilL fiurYl‹

rk Mšifš FnshiuL (m) ònuhikL nr®¡f¥g£L Mšifš

mnahilfŸ jahÇ¡f¥gL»‹wd. ï›ÉidÆš Mšifš

AhiyL k‰W« nrhoa« mnahilL M»at‰¿š cŸs

Ahy#‹fŸ gÇkh‰w« brŒa¥gL»‹wd.

RCl + NaI →mánlh‹ RI + NaCl

RBr + NaI →mánlh‹ RI + NaBr

This material only for sample

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RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£ 123

K¡»a Édh¡fŸ

1. DDT v›thW bgw¥gL»wJ?

(i) ml® ršòôÇ¡ mÄy K‹ÅiyÆš Fnshnuh bg‹Ó‹

oiuFnshnuh má£lhšoiALl‹ (Fnshuhš)

ÉidòǪJ p, p - ilFnshnuh il~Õidš oiu

Fnshnuh <¤nj‹ (DDT) bfhL¡»wJ.

(ii) ïJ xU áwªj ó¢á¡ bfhšÈ.

CCl3 CHO + 2conc.

H2SO4

DDT

Cl

Cl

Cl CCl3− CH

FnshušFnshnuhbg‹Ó‹

2. Ñœ¡fhQ« AhiyLfË‹ IUPAC bgaiu F¿¥ãLf?

(i) Br CH2 CH CH2 CH2 Cl

Cl

(ii) Cl

CH2 C CH CH3

Cl Br

(iii) Br

CH3 C CH CH CH3

CH3 Cl CH3

(i) 1 - ònuhnkh - 2,4 ilFnshnuh òô£nl‹

(ii) 2 - ònuhnkh - 3,3 ilFnshnuh òô£nl‹

(iii) 2 - ònuhnkh - 3, - Fnshnuh- 2, 4 - ilÛ¤ijš bg‹nl‹.

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124 RuhÉ‹ ntâÆaš 11 M« tF¥ò áfu« bjhLnth« lh®bf£

3. Ñœf©lt‰¿‹ bghJ¥ bg®fis F¿¥ãLf?

(i) CH3 CH CH2 Br

CH3

(ii) CH3 CH2 CHCl2 (iii) I

CH3 C CH3

I

(i) Inrhãô£ilšònuhikL

(ii) ònuhgä‹il FnshiuL

(iii) òu¥gä‹ il mnailL

4. Mšifš AhiyLfË‹ ïa‰ãaš g©òfŸ ahit?

(i) ÑœÃiy CH3Cl, CH3Br k‰W« CH3CH2Cl Mšifš

AhiyLfŸ thí¡fshF«.

(ii) CH3I k‰W« bgU«gh‹ikahd ca®Ãiy Mšifš

AhiyLfŸ ïÅa eWkd« cila Ú®k§fshF«.

(iii) mQ vil mâfÇ¡f bfhâÃiyí« mâfÇ¡F«.

5. Mšifš AhiyLfË‹ ga‹fŸ ahit?

(i) fiu¥gh‹fshfî«

(ii) kU¤Jt JiwÆš cz®î Ú¡»ahf

(iii) òiuÚ¡»ahfî«

(iv) Ôaiz¥ghdhfî« ga‹gL»wJ.

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