force on a spring lab… the force applied to a spring and the amount of stretch in the spring are...
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![Page 1: Force on a spring lab… The force applied to a spring and the amount of stretch in the spring are directly proportional… F = ks F This relationship is known](https://reader035.vdocuments.us/reader035/viewer/2022071708/56649d6d5503460f94a4e083/html5/thumbnails/1.jpg)
Force on a spring lab…• The force applied to a spring and the amount of stretch
in the spring are directly proportional…
F = ks FThis relationship is known as Hooke’s Law
sSlope = spring constant, k – describes the stiffness of the spring
Area under line = stored Eel
½ bh = ½ (s)(F) = ½ (s)(ks) = ½ ks2
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Now, let’s look at Gravitational Potential Energy in a little more detail…
• Construct a free body diagram for a box being lifted at a constant speed and write a force equation.
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Now, let’s look at Gravitational Potential Energy in a little more detail…
• Construct a free body diagram for a box being lifted at a constant speed and write a force equation
F
Fg
Since speed is constant, F = 0…F – Fg = 0F – mg = 0F = mgSo, the lifting force is equal to the weight of the box throughout the entire lift.
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Gravitational Potential Energy
• In the spring lab we graphed Force vs. Stretch to inform us about stored energy. What would a graph of Force vs. Height look like for the case of lifting the box at constant speed?
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Gravitational Potential Energy
• In the spring lab we graphed Force vs. Stretch to inform us about stored energy. What would a graph of Force vs. Height look like for the case of lifting the box at constant speed?
F (N)
h (m)
mg
1 2 3 4
Constant force acting on object as it is lifted higher and higher.
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Gravitational Potential Energy
• What characteristic of our graph is getting larger the higher the object gets lifted?
F (N)
h (m)
mg
1 2 3 4
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Gravitational Potential Energy
• What characteristic of our graph is getting larger the higher the object gets lifted?
F (N)
h (m)
mg
1 2 3 4
AREA = Eg
Area = b x h = F x h= mgh
Eg = mgh
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Kinetic Energy• Consider a cart being pushed by a force across
a frictionless surface some distance x…
x
F F
Change in Energy will correspond to a force times a distance, therefore
Ek = F x= max ***Recall from studying motion
vf2 = 2ax + vi
2 OR…
ax = ½ vf2 - ½ vi
2
Ek = m(½ vf2 - ½ vi
2)
Ek = ½ mvf2 - ½ mvi
2 So, Ek = ½mv2
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Summarizing the Energy Equations
• Elastic Potential Eel = ½ ks2
• Gravitational Potential Eg = mgh
• Kintetic Ek = ½ mv2
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Using LOL diagrams to write equations
F
Consider our box once again being lifted by some force external to the system…
Initial Energy Flow Final
Ek Eg Eel Ek Eg Eel
BoxEarth
Working
Ek + Eg + Eel + W = Ek + Eg + Eel
W = mghf
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Sample Problem
Energy Flow Diagram
0
EK Eel
Initial Eg
0
Final EK Eg Eel Ediss
A moving cart hits a spring, traveling at 5.0 m/s at the time of contact. At the instant the cart is completely stopped, by how much is the spring compressed? (ignore friction)
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A closer look at Working• Something is working if it transfers energy
into or out of a system… W = E• W is positive when energy is added to a system• W is negative when energy is removed from a
system
Energy Flow Diagram
0
EK Eel
Initial Eg
0
Final EK Eg Eel Ediss
+W - W
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Working• In every case, when something is working, a force is
being exerted on an object as the object moves.
• Only forces acting parallel to the motion of the object are Forces acting in a direction parallel to displacement in order for energy transfer to occur.
W = F x
F F
x
F
FN
Fg
f
***In this example, FN and Fg would not change the energy of the system, F would add energy, f woul remove energy
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Sample Problem
Energy Flow Diagram
0
EK Eel
Initial Eg
0
Final EK Eg Eel Ediss
A person pushes a 1500 kg car from rest with a force of 500 N. If there was no friction, how fast would the car be moving after pushing for 10 m?
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Sample Problem
Energy Flow Diagram
0
EK Eel
Initial Eg
0
Final EK Eg Eel Ediss
A person pushes a 1500 kg car from rest with a force of 500 N. If the coefficient of friction between the car and road is 0.20, how fast would the car be moving after pushing for 10 m?
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Sample Problem
• A 30 g bullet is fired into ballistic gel. If the gel exerts a force of 50000 N to stop the bullet in a distance of 0.10 m, how fast was the bullet moving? Energy Flow
Diagram
0
EK Eel
InitialEg
0
FinalEK Eg Eel Ediss
Initial Final