final review

29
Significant Figures a.k.a.- sig figs

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Page 1: Final  Review

Significant Figures

a.k.a.- sig figs

Page 2: Final  Review

Significant Digits

• The certain digits and one estimated digit of each measurement are significant.

Remember! Every time you make a measurement, you record all of the certain digits and one estimated digit.

200.54 g

Page 3: Final  Review

Rules for Sig Figs

1) Non zeros are always significant.2) Zeros between non zeros are significant.3) Zeros at the end of significant digits following

a decimal point are significant.*They show precision in measurement.

4) Place keeper zeros are NOT significant.a) Zeros preceding significant digits.b) Zeros following significant digits without a

decimal point.

Page 4: Final  Review

Try These Examples

7.05940Final zero significant (follows decimal point)

6 significant digits0.00135

Leading zeros Not significant (place keepers)3 significant digits

20,400Final zeros Not significant (place keepers – no decimal)

3 significant digits

Page 5: Final  Review

Heat Calculations• Heat (q)

– Energy transferred from an object at a higher temperature to an object at a lower temperature. (heat lost = -heat gained)

– q = mcT

– q=mHfus

– q=mHvap

Page 6: Final  Review

Heat Calculations• A 10.0g sample of iron at 50.4oC is cooled to

25.0oC in 50.0g of water. Calculate the amount of heat lost by the iron.

ciron= 0.449 J/goC

• A 2.1g ice cube at –8.0oC melts completely and warms to 12.5oC. How much heat was required?

Hfus ice = 334 J/g

cice = 2.03 J/goC

cwater = 4.18J/goC

Page 7: Final  Review

soluble – a substance that dissolves in a solvent

insoluble – a substance that does not dissolve in a solvent

solvation – the process of surrounding solute particles with solvent particles to form a solution

Page 8: Final  Review

Solvation• When a solid solute is placed in a solvent, the

solvent particles completely surround the surface of the solid solute.

• If attractive forces between the solute particles and the solvent are greater than the attractive forces holding the the solute particles together, the solvent particles pull the solute particles apart and surround them.

Page 9: Final  Review

+

-

--

-+

+

-+

+

NaCl

Na =

Cl =

H2O

H =

O =

+

-+--+ +

-+-

- + -

+-+

-

+

-+ +

-++

-+

+- +

+

+

-+

+

Process of Solvation

Page 10: Final  Review

Water- Universal Solvent• Polar molecule

• Dipoles allow solvation of ions and polar molecules

Page 11: Final  Review

Factors that Affect the Rate of Solvation

1.Agitate the solution (stirring)

2. increase the temperature of solvent

3. increase the surface area of the solute

Page 12: Final  Review

SOLUBILITY – refers to the maximum amount of solute that will dissolve in a given amount of solvent (at a specified temperature and pressure)

saturated – a solution that contains the maximum amount of dissolved solute (for a given temp & pressure than a saturated solution)

unsaturated – a solution that contains less dissolved solute (for a given temp & pressure than a saturated solution)

Page 13: Final  Review

Units of Solubility

g of solute

100 g water

read these units as:

“grams of solute per 100 grams of water”

Page 14: Final  Review
Page 15: Final  Review

Here are some for you to try.

What mass of solute will dissolve in 100mL of water at the following temperatures. Also determine which of the three substances is most soluble in water at 15°C.

1. KNO3at 70°C

2. NaCl at 100°C

3. NH4Cl at 90°C  

Page 16: Final  Review

supersaturated – a solution that contains more dissolved solute than a saturated solution at the same temperature

- is above the solubility curve

solute will usually precipitate out of solution

Page 17: Final  Review

Radioactivity• There are two main types of radioactivity:

Natural and Induced

Page 18: Final  Review

Natural Radioactivity• Occurs in nature

• Usually large, unstable nuclei

• Occurs in three ways:

– Particle (alpha particle)

– Particle (beta particle)

– Ray (gamma ray)

Page 19: Final  Review

Alpha Decay

• A helium nucleus is released from the nucleus. ( )– The mass decreases by 4– The atomic number decreases by 2

(Because the He nucleus has 2p+ and 2no)

• Alpha radiation can be stopped by a piece of paper. Cannot penetrate skin. Not dangerous.

He4

2

Page 20: Final  Review

Alpha Decay Example

Notice that the uranium has changed into a new element, thorium.

HeThU 4

2

234

90

238

92

Page 21: Final  Review

Beta Decay

• An electron is released from the nucleus when a neutron becomes a proton.

• The mass is unaffected. (the mass of a neutron is roughly equal to the mass of a proton)

• The atomic number is increased by 1.

• Harder to stop and more dangerous.

e0

1

Page 22: Final  Review

Beta Decay Example

eNC 0

1

14

7

14

6

Notice that carbon has changed into nitrogen.

Page 23: Final  Review

Gamma Decay• Pure energy is released from the nucleus.

• The mass and atomic number are unaffected.

• Stopped by lead. The most harmful to living tissue.

Page 24: Final  Review

Gamma Decay Example

SrSr 87

38

87

38*

No new element formed. Gamma radiation (energy) released.

Page 25: Final  Review

Induced Radioactivity• Particles are slammed together to cause

transmutation of stable elements. (Nuclear Bombardment)

• Discovered by Rutherford in 1919.

Page 26: Final  Review

Uranium-238 Decay Series

Page 27: Final  Review

Average Atomic Mass(How the number ends up on the periodic table!!)

1st Mass of one isotope x % abundance

in decimal form (watch SIG FIGS!!)

2nd Do this for each isotope of that element

3rd Add all individual isotopes

together to get the average atomic

mass of the element.

Page 28: Final  Review

1. Calculate the average atomic mass of potassium using the following data:

Isotope Mass % abundance

Potassium-39 38.964 amu 93.12%

Potassium-41 40.962 amu 6.88 %

Potassium-39

38.964 amu

x 0.9312=

36.28 amu

Potassium-41

40.962 amu

x 0.0688 2.82 amu

=

+ Average atomic mass for K = 39.10

amu

Page 29: Final  Review

2. Calculate the average atomic mass of magnesium using the following data:

Isotope Mass % abundance

Magnesium-24 23.985 amu 78.70%

Magnesium-25 24.986 amu 10.13 %

Magnesium-26 25.983 amu 11.17 %

Magnesium-24

23.985 amu

x 0.7870=

18.88 amuMagnesium-

2524.986 amu

x 0.1013 2.531 amu

=

+

Average atomic mass for K = 24.31 amu

+

Magnesium-26

25.983 amu

x 0.1117=

2.902 amu