final p1 skema mt pat f4 2013

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  • 8/11/2019 Final p1 Skema Mt Pat f4 2013

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    SULIT

    3472/1

    Additional

    Mathematics

    Paper 1Oktober

    2013

    BAHAGIAN PENGURUSANSEKOLAH BERASRAMA PENUH

    DAN SEKOLAH KECEMERLNGAN

    KEMENTERIAN PELAJARAN MALAYSIA

    PEPERIKSAAN AKHIR TAHUN

    TINGKATAN 4

    2013

    ADDITIONAL MATHEMATICS

    Paper 1

    MARKING SCHEME

    This marking scheme consists of 6 printed pages

    KEMENTERIAN PENDIDIKAN MALAYSIA

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    MARKING SCHEME

    Question Answers Mark

    1

    (a) 12 and 15

    (b) { 5 , 9 , 13 }

    1

    1

    2

    (a)2

    3

    (b)1

    , 13

    x x

    1

    3 2x

    x

    1

    2

    B1

    3

    a) 7

    (b) 37

    1 3( )5

    xf x

    or (8)f k

    1

    2

    B1

    4

    m= 5 and n=36

    m= 5 or n= 36

    2 ( ) 6(6 m) mg x x

    3

    B2

    B1

    5

    23 7 6 0x x

    ( 3)(3 2)x x or SOR = - 3 + 2/3 or POR = (-3)(2/3)

    2

    B1

    6

    8k and 4k

    0)9)(1(4)2( 2 k

    09)2(2 xkx or 0292 xkxx

    3

    B2

    B1

    7

    2p and 4q

    2p or 4q

    6)4(3 pPOR or )1(43 qpSOR

    3

    B2

    B1

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    3

    8

    (a) 1m

    3

    2

    4

    2

    44

    22

    2 xx

    (b)

    Correct shape

    2

    B1

    2

    B1

    9

    4x , 1x

    )1)(4( xx or

    0862 2 xx

    3

    B2

    B1

    10

    a)

    a > 0

    b) 3b

    c)

    4c

    1

    1

    1

    4

    )(xf

    x O

    3 -

    )1,2(

    1

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    4

    11

    5x

    522 x

    4

    1)816(2 x

    )2(2)2(2 34 xx

    4

    B3

    B2

    B1

    12

    3qp

    0log 33 q

    p

    27log

    log

    3

    3 p

    3

    B2

    B1

    13

    4

    1x

    3241

    x

    x

    x

    x41log2

    3

    B2

    B1

    14

    a) 2h

    b)3

    1k

    kh

    6

    1

    2

    B1

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    15

    a) 12 xy

    )2(25 xy or equivalent

    b) )4,2(

    822 xx or equivalent

    2

    B1

    2

    B1

    16

    0172127655 22 yxyx

    22 )2()2(3 yx = 22 )6()5(2 yx

    3PA= 2PB

    3

    B2

    B1

    17

    (a) x= 8

    (b) x = 12

    (c ) x= 2

    1397

    )(3)3(2)9(1)7(0

    x

    x

    1

    1

    2

    B1

    18

    5

    13 - 8

    3, 8 , 8, 9 , 11 , 13 , 15 or Q1= 8 or Q3=13

    3

    B2

    B1

    19

    21625 mp

    22 168

    200mp

    8@2002 xx

    3

    2

    B1

    20

    r = 6.5 cm

    31.2 = r(4.8)

    484.12

    3

    B2

    B1

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    21

    a) 5

    0.83336

    or

    56

    (b) 27

    6+6+5+10 or

    6

    512RQ

    2

    B1

    2

    B1

    22

    (a)

    0.9274 rad

    53.13o

    (b)5.593 cm2

    2

    1(5)2(0.9274) -

    2

    1x 3 x 4

    2

    B1

    2

    B1

    23

    24

    )2(12)2(12)2( 2 f

    xxxf 1212)( 2

    3

    B2

    B1

    24

    (a) 3125.0

    310 xdx

    dy

    (b) 0.3109

    )01.0(410

    3

    2

    B1

    2

    B1

    25

    -204.8cm3s-1

    )2.0()16(4 2dt

    dV

    24 rdr

    dV

    3

    B2

    B1

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