Exercises on Associativity and Precedence rules:

1. Consider the comma operator: “, “

Given that

i=1;

What will be the values of i, sum after the execution of the statement:

++i, sum=sum+i;

2. Fill the value column using the declarations and initializations below:

int i, j, k=3; double x=3.3

Expression Equivalent expression

Value Inference Lessons learnt

i=1, j=2, ++k+i+1;

k!=1, ++x*2.5+3

3. Fill the value column using the declarations and initializations below:

char a= ‘a’, b =’b’; int i=1, j=2;

Expression Value

i==j? a-1 : b-1;

J%3 ==0?i+4:x

J%3?i+4:x

4. Fill the value column using the declarations and initializations below:

int a=1, b=2, c=3; double x=1.0;

Expression Value

a>b&&c<d

a < !b ||!!a

a+b < !c +b

a –x || b*c&&b/a

5. What does the following code fragment will print?

char c =’A’;

int i=5, j=10;

printf(“%d%d%dn”, !c, !!c, !!!c);

printf(“%d%d%dn”, -!i, !-i, ! –i – !j);

printf(“%d%d%dn”, !(6*j +i-c), !i-5, !j-10);

6. Check and analyze the output for the code below:

double x=1e+33, y=0.0001

printf(“%d%d%d\n”, c==’a’, c==’b’,c!=’c’);

printf(“%d\n”, c==’A’&& c< =’B’ || ‘c’);

printf(“%d\n”, 1!=!!c==!!!c);

printf(“%d\n”, x+y >x -y);

7. Check and analyze the output for the code below:

int a=0, b=0, x;

x=0&&(a=b=333);

printf(“%d%d%d\n”, a, b, x);

x=333||(a=++b);

printf(“%d%d%d\n”, a, b, x);

8. Fill the following table below, using precedence rules:

int i=1, j=2, k=3, m=4; double x=3.3

Expression Equivalent expression

Value Inference Lessons learnt

i+=j+k

J*=k=m+5;

9. Check and analyze the output for the code below:

int a, b, c=0;

a=++c;

b=c++;

printf(“%d%d%d\n”, a, b, ++c);

printf(“%d%d%d\n”, a, b, c ++);