exponential functions and their graphs, logs and natural logs, rational functions and their graphs
TRANSCRIPT
Exponential Functions and Their Graphs, Logs and Natural Logs, Rational
Functions and their Graphs
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The exponential function f with base a is defined by
f(x) = ax
where a > 0, a 1, and x is any real number.
For instance,
f(x) = 3x and g(x) = 0.5x
are exponential functions.
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The Graph of f(x) = ax, a > 1
y
x(0, 1)
Domain: (–, )
Range: (0, )
Horizontal Asymptote y = 0
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The Graph of f(x) = ax, 0 < a <1
y
x
(0, 1)
Domain: (–, )
Range: (0, )
Horizontal Asymptote y = 0
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Example: Sketch the graph of f(x) = 2x.
x
x f(x) (x, f(x))
-2 ¼ (-2, ¼)
-1 ½ (-1, ½)
0 1 (0, 1)
1 2 (1, 2)
2 4 (2, 4)
y
2–2
2
4
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Example: Sketch the graph of g(x) = 2x – 1. State the domain and range.
x
yThe graph of this function is a vertical translation of the graph of f(x) = 2x
down one unit .
f(x) = 2x
y = –1 Domain: (–, )
Range: (–1, )
2
4
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Example: Sketch the graph of g(x) = 2-x. State the domain and range.
x
yThe graph of this function is a reflection the graph of f(x) = 2x in the y-axis.
f(x) = 2x
Domain: (–, )
Range: (0, ) 2–2
4
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The irrational number e, where
e 2.718281828…
is used in applications involving growth and decay.
Using techniques of calculus, it can be shown that
ne
n
n
as 1
1
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The Graph of f(x) = ex
y
x2 –2
2
4
6
x f(x)
-2 0.14
-1 0.38
0 1
1 2.72
2 7.39
Properties of Logarithmic FunctionsIf b, M, and N are positive real numbers, b 1, and p and x are real numbers, then: Log15 1 = 0
Log10 10 = 1
Log5 5x = x
3log x = x 3
150 = 1
101 = 10
5x = 5x
Graph and find the domain of the following functions.
y = ln x
x y
-2-101234
.5
cannot takethe ln of a (-) number or 0
0ln 2 = .693ln 3 = 1.098ln 4 = 1.386
ln .5 = -.693
D: x > 0
Graph y = 2x
x y
-2-1012
2-2 =4
1
2-1 =2
1
124
The graph of y = log2 x is the inverse of y = 2x.
y = x
The domain of y = b +/- loga (bx + c), a > 1 consistsof all x such that bx + c > 0, and the V.A. occurs whenbx + c = 0. The x-intercept occurs when bx + c = 1.
Ex. Find all of the above for y = log3 (x – 2). Sketch.
D: x – 2 > 0
D: x > 2
V.A. @ x = 2
x-int. x – 2 = 1
x = 3
(3,0)
3.6: Rational Functions and Their Graphs
Strategy for Graphing a Rational FunctionStrategy for Graphing a Rational FunctionSuppose that
where p(x) and q(x) are polynomial functions with no common factors.
1. Determine whether the graph of f has symmetry. f (x) f (x): y-axis symmetry f (x) f (x): origin symmetry
2. Find the y-intercept (if there is one) by evaluating f (0).3. Find the x-intercepts (if there are any) by solving the equation p(x) 0. 4. Find any vertical asymptote(s) by solving the equation q (x) 0.5. Find the horizontal asymptote (if there is one) using the rule for determining the
horizontal asymptote of a rational function.6. Plot at least one point between and beyond each x-intercept and vertical asymptote.7. Use the information obtained previously to graph the function between and beyond
the vertical asymptotes.
Strategy for Graphing a Rational FunctionStrategy for Graphing a Rational FunctionSuppose that
where p(x) and q(x) are polynomial functions with no common factors.
1. Determine whether the graph of f has symmetry. f (x) f (x): y-axis symmetry f (x) f (x): origin symmetry
2. Find the y-intercept (if there is one) by evaluating f (0).3. Find the x-intercepts (if there are any) by solving the equation p(x) 0. 4. Find any vertical asymptote(s) by solving the equation q (x) 0.5. Find the horizontal asymptote (if there is one) using the rule for determining the
horizontal asymptote of a rational function.6. Plot at least one point between and beyond each x-intercept and vertical asymptote.7. Use the information obtained previously to graph the function between and beyond
the vertical asymptotes.
( )( )
( )p x
f xq x
EXAMPLE: Graphing a Rational Function
Step 4 Find the vertical asymptotes: Set q(x) 0.x2 4 0 Set the denominator equal to zero.
x2 4 x 2Vertical asymptotes: x 2 and x 2.
Solution
moremore
2
2
3Graph: ( ) .4
xf xx
Step 3 Find the x-intercept: 3x2 0, so x 0: x-intercept is 0.
Step 1 Determine symmetry: f (x) f
(x):
Symmetric with respect to the y-axis.
2 2
2 2
3 344
x xxx
Step 2 Find the y-intercept: f (0) 0: y-intercept is 0.
2
2
3 0 00 4 4
3.6: Rational Functions and Their Graphs
EXAMPLE: Graphing a Rational Function
Solution
The figure shows these points, the y-intercept, the x-intercept, and the asymptotes.
x 3 1 1 3 4
f(x) 1 1 4
moremore
2
2
3Graph: ( ) .4
xf xx
Step 6 Plot points between and beyond the x-intercept and the vertical asymptotes. With an x-intercept at 0 and vertical asymptotes at x 2 and x 2, we evaluate the function at 3, 1, 1, 3, and 4.
Step 5 Find the horizontal asymptote: y 3/1 3.
2
2
34
xx
275
275
-5 -4 -3 -2 -1 1 2 3 4 5
7
6
5
4
3
1
2
-1
-2
-3
Vertical asymptote: x = 2
Vertical asymptote: x = 2
Vertical asymptote: x = -2
Vertical asymptote: x = -2
Horizontal asymptote: y = 3
Horizontal asymptote: y = 3
x-intercept and y-intercept
x-intercept and y-intercept
3.6: Rational Functions and Their Graphs